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PHP - Unique Submit Buttons Won't Post
I can't figure out why my $_POST['join'] isn't working. Does my form need to be inside my foreach?
Code: [Select] <?php if(is_admin($user_info['uid'], $info['companyid']) === false) { if (isset($_POST['join'])) { echo "works"; die(); } $companies = fetch_company_by_name($info['cname']); ?> <table class="feed pts pbl"> <?php foreach ($companies as $company) { ?> <tr class="mbm"> <td> <form method="post" id="ccreateform" class="man"> <input type="submit" name="join[<?php echo $company['companyid']; ?>]" value="Join" /> </form> </td> </tr> <?php } ?> </table> <?php } ?> Similar TutorialsI think I understand that there can only be one "submit" button on a page.
I want buttons for separate forms to not trigger the empty errors on the other forms...
How do you accomplish specific button actions?
I think I've tried it with javascript but you can do it with PHP right?
Thanks for any help.
Hi i'm making a new website based on PHP. I bumped on a problem now... The problem is that I have a loop where i get all records out of my sql database and get them into a form. Every record has a differend form with a button to. Every button then has a unique ID. Now i tried everyting i could think of to get the value out of a button when a button is clicked. But nothing worked... here is the part of the code where everything is for the form and the POST. Code: [Select] while($record = mysql_fetch_object($result)){ $id = $record->id; echo"<form action='home.php' method='post'>"; echo"<b>name:</b>".$record->name." <b>Price: </b>".$record->price.""; echo'<input type="hidden" name="id" value='.$id.'>'; echo"<input type='submit' value='Buy' /><br />"; echo"</form>"; } if($_POST) { $ID = intval($_POST['id']); $query1 = "SELECT price FROM items WHERE id = ".$ID.""; $result1 = mysql_query($query1); list($cost) = mysql_fetch_row($result1); $gold = getStat('gc',$userID); if($gold > $cost) { setStat('gc',$userID,($gold - $cost)); $queryw = "INSERT INTO users_inventory(item_id,user_id, quantity) VALUES ('".$ID."','".$userID."','1')"; $resultw = mysql_query($queryw); } else { echo"You can't afford this weapons."; } } The only thing that doesn't seem to work is this part Code: [Select] $ID = intval($_POST['id']); is always gives me this error: Notice: Undefined index: id in shop.php on line 26 Please help me out here i have no idea what to do from here on... Hi, Newbie! I need to generate a unique number and put it in a field called "intInstD" value ="123456" to send to Paypoint to initiate an order. They insist each order from my website has a unique number. Can anyone help with a bit of code that does this please? Much appreciated zzdave I was wondering if you can have a form that has different actions depending on what submit button is pressed. I have two button and with one I was to use <form action="<?php echo ( $_SERVER['PHP_SELF'] ); ?>" method="post"> and with the other I want to use <form action="preview.php" method="post"> I was to do this because I want to user to be able to preview their content before submitting. I want the preview page to use the post variables as the value of the input fields so the user doesn't have to input their data again. However because the form doesn't redirect the user to the preview page I have to save all the post variables as session variables. One submit button goes to my own login system.. the other goes to a billing system. I am having problems getting it to work probably because there are alot of if and else if statements. Or maybe I am just missing something. The problem is the line with blesta.. I take that if isset out and just start with if permission =1 then all is great but I need both of them to operate .. with one being sent to one place and the other to another one. the login file and my form has both input types ready to go within it.. I can declare the values I just need to know what I am doing wrong in the if statement. Code: [Select] <input type="image" name="blesta" id="BtnSubmit" src="images/cart.jpg" width="25" height="20" submit="Blesta"></td> <td><input name="login" type="image" class="vote" src="images/index19.jpg" submit="login"></td> Code: [Select] <? session_start(); $username = $_SESSION["username"]; ?> <html><body> <title>Login</title> <table width="100%" height="100%" border="0" cellpadding="0" cellspacing="0"> <tr> <td class="poptop" height="10"><img src="password/images/spacer.gif" width="3" height="3"><img src="logo.png" border="0"></td> </tr> <tr> <td class="hrz_line"><img src="password/images/spacer.gif" width="1" height="1"></td> </tr> <tr> <td style="background: #ffffff; padding: 5px" valign="middle"><h1 style="margin-top: 0; margin-bottom: 0">Welcome<br><br> Newest User: <font style="FONT-FAMILY: Verdana; FONT- SIZE: 7pt"><?php $connect = mysql_connect("localhost", "username", "pw") or die("Could not connect to database: " . mysql_error()); mysql_select_db("db", $connect) or die("Could not select database"); $query = "SELECT * FROM users ORDER BY created DESC LIMIT 1"; $result = mysql_query($query, $connect) or die ("QUERY FAILED: " . mysql_error()); $row = mysql_fetch_array($result,MYSQL_ASSOC);?> <?echo $row[username]; ?></td></h1></font> </tr> <tr> <td class="hrz_line"><img src="password/images/spacer.gif" width="1" height="1"></td> </tr> <tr> <td valign="top" style="padding: 1em" class="maincontent" height="90"> <META HTTP-EQUIV="expires" CONTENT="0"> <META HTTP-EQUIV="Pragma" CONTENT="no-cache"> <link rel="stylesheet" type="text/css" href="style.css"> <?php $connect = mysql_connect("localhost", "user", "pw") or die("Could not connect to database: " . mysql_error()); mysql_select_db("db", $connect) or die("Could not select database"); $login = $_POST["username"]; $password = $_POST["password"]; $field = ""; if (isset($_POST["username"]) and isset($_POST ["password"])) { if (is_numeric('$login')) { $field = "user_id"; } else { $field = "username"; } $query = sprintf ("SELECT * FROM users WHERE $field='$login' AND password='".md5 ($password)."'", mysql_real_escape_string($login), mysql_real_escape_string($password)); $result = mysql_query($query, $connect) or die ("QUERY FAILED: " . mysql_error()); if (mysql_num_rows($result) == 0) { if(session_is_registered("LoginFailed")) { if($_SESSION['LoginFailed'] > 3) { $user_query = mysql_query("SELECT * FROM users WHERE username = '$login'") or die("QUERY FAILED: " . mysql_error()); $user = mysql_query($user_query); $hostname = gethostbyaddr($_SERVER ['REMOTE_ADDR']); $password_cypt = md5($password); $date = date("YmdHis"); $IP = getenv("REMOTE_ADDR"); $browser = getenv("HTTP_USER_AGENT"); $handle = fopen("ban.txt", "a+"); //echo "sql: ".$query.""; //echo "Login Failed!"; $access_query = "INSERT INTO hacklog (date, username, hostname, ip_address, browser, refer, password) values ('$date', '$login', '$hostname', '$IP', '$browser', '$refer', '$password')" or die("QUERY FAILED: " . mysql_error()); $access = mysql_query($access_query) or die ("QUERY FAILED: " . mysql_error()); $browser = getenv("HTTP_USER_AGENT"); $hostname = gethostbyaddr($_SERVER ['REMOTE_ADDR']); $date = date("YmdHis"); $rest = substr(getenv('SCRIPT_NAME'), 1, -4); mail("email", "Hack Attack Alert", "Someone Is Attempting To Enter V.I.P\nThe username is: $login\nPassword is: $password\nIP is: $visitorip\nHostname is: $hostname\nBrowser Used is: $browser\nDate: $date\nFile: $rest", "From: email\n"); $browser = getenv("HTTP_USER_AGENT"); $date = date("YmdHis"); $hostname = gethostbyaddr($_SERVER ['REMOTE_ADDR']); $IP = getenv("REMOTE_ADDR"); $handle = fopen("ban.txt", "a+"); $date = date("m-d-Y H:i:s"); $somecontent = $IP.", ".$date. ", ".$browser.", ".$hostname.""; fwrite($handle, $somecontent . " "); fclose($handle); echo "$IP Is Now Banned. Follow Instructions On Next Screen."; print "<META HTTP-EQUIV=\"Refresh\" target= \"info\" Content=\"1; URL=ban.php\">"; exit(); } else { $_SESSION['LoginFailed'] = $_SESSION ['LoginFailed'] + 1; print "<p><strong>Now " . $_SESSION ['LoginFailed'] . " out of 4 Attempts Used</strong></p>\n"; print "<META HTTP-EQUIV=\"Refresh\" Content=\"1; URL=error.php?msg=pass\">"; exit(); } } else { $_SESSION['LoginFailed'] = 1; print "<p><strong>You have used " . $_SESSION ['LoginFailed'] . " out of 4 trys</strong></p> \n"; print "<META HTTP-EQUIV=\"Refresh\" Content=\"1; URL=error.php?msg=pass\">"; exit(); } print "<META HTTP-EQUIV=\"Refresh\" Content=\"1; URL=error.php?msg=pass\">"; exit(); } else { $date = date("YmdHis"); $session = md5($date); $password_cypt = md5($password); $row = mysql_fetch_array($result,MYSQL_ASSOC); $hostname = gethostbyaddr($_SERVER ['REMOTE_ADDR']); $IP = getenv("REMOTE_ADDR"); $browser = getenv("HTTP_USER_AGENT"); $_SESSION["logged"] = "1"; $_SESSION["id"] = $row["user_id"]; $_SESSION["username"] = $row["username"]; $_SESSION["firstname"] = $row["firstname"]; $_SESSION["lastname"] = $row["lastname"]; $_SESSION["email"] = $row["email"]; $_SESSION["created"] = $row["created"]; $_SESSION["last_access"] = $row["last_access"]; $_SESSION["pw"] = $row["pw"]; $_SESSION["permission"] = $row["permission"]; $_SESSION["count"] = $row["count"]; $_SESSION["photo"] = $row["photo"]; $_SESSION["session_id"] = $row["session_id"]; //echo "sql: ".$query."<br>"; //echo "Login success: username: ".$_SESSION ["username"]; //Find Last Access $dd = substr($_SESSION[last_access],6,2); $mm = substr($_SESSION[last_access],4,2); $yyy = substr($_SESSION[last_access],0,4); $HH = substr($_SESSION[last_access],8,2); $MM = substr($_SESSION[last_access],10,2); $SS = substr($_SESSION[last_access],12,2); $access2 = "$mm-$dd-$yyy $HH:$MM:$SS"; $username = $_SESSION["username"]; $access = "$access2"; $login_message = "<p><br> Login Successful.<br><br> [$username] , Last Visited MalenTek On: [$access]<br>Loading Please Wait..<img src=password/images/ajax-loader.gif border=0></p>\n"; if (isset($_POST['blesta']) { print "You are being redirected to your Billing Account"; print "<META HTTP-EQUIV=\"Refresh\" Content= \"10; URL=/cart/u-main.php">"; } else if ($_SESSION[permission] == "1") { $connect = mysql_connect("localhost", "user", "pw") or die("Could not connect to database: " . mysql_error()); mysql_select_db("db", $connect) or die("Could not select database"); mysql_query("UPDATE users SET last_access = $date WHERE username = '$username'")or die("QUERY FAILED: " . mysql_error()); include ("file.php"); print "$login_message"; print "<META HTTP-EQUIV=\"Refresh\" Content=\"10; URL=password/admin.php\">"; } else if ($_SESSION[permission] == "0") { $connect = mysql_connect("localhost", "user", "pw") or die("Could not connect to database: " . mysql_error()); mysql_select_db("db", $connect) or die("Could not select database"); mysql_query("UPDATE users SET last_access = $date WHERE username = '$username'")or die("QUERY FAILED: " . mysql_error()); include ("file.php"); print "$login_message"; print "<META HTTP-EQUIV=\"Refresh\" Content=\"10; URL=members.php/">"; } else if ($_SESSION[permission] == "2") { mysql_query("UPDATE users SET last_access = $date WHERE username = '$username'")or die("QUERY FAILED: " . mysql_error()); include ("ban.php"); print "$login_message"; print "<META HTTP-EQUIV=\"Refresh\" Content=\"10; URL=index.php\">"; } //} } } ?> </td> </tr> <tr> <td class="hrz_line"><img src="images/spacer.gif" width="1" height="1"></td> </tr> <tr> <td height="20" class="popbot"><a href="mailto:email Errors">Report Errors</a></td> </tr> </table> </body> </html> I'm new to PHP and attempting to set up my first interactive site that is a basic survey for little kids to take. There's a picture shown to them and two submit buttons below the pic, one reads YES and the other NO to register whether they've participated in the activity before or not. Since the only thing that changes on the page after the selection is made is the photo for the next question/activity, I'd like to be able to use the two buttons to both send their choice to a database (Yes=1 and No=2) and also increment a counter so I can update the picture on the page as they progress through the survey. All the information I've searched/read so far on submit buttons and multiple page surveys doesn't use the actual button itself as data but it's used to submit information gathered elsewhere on the page to another php page for processing via the Action attribute, so I'm wondering if what I want can be done. I'm leaving the Action attribute blank for each button as I want to stay on the same page and attempting to use an incremental counter to update the picture on the page in order to "step" through the survey each time one of the two buttons is clicked, but not having any luck and would appreciate suggestions or points in the right direction on the best way to do this. Apologies in advance if this seems like a basic question, and thanks for any suggestions you can offer. Hi everyone, I have a gateway and I can submit 200 max at one time using POST. I need to send around 200,000 at a time. So, in a nut shell, I need to submit 1,000 POST without actually refreshing my page. How can I do that ? Becuz once I submit a POST, the page on my browser goes to the gateway page rather than staying on the current page. So, what I need is something like click one button do 1,000 POST and send around 200,000. Looking forward to receiving any input on this. Thanks all. Regards So I have created an online test . I have the results from the form submitted to my email. It is working great but the only problem is that when a question is left unanswered, the radio button doesn't have a result. What i want it to do is when a question is left unanswered, the email should look like this (Question) 1_01: True 1_02: Unanswered 1_03: False 1_04: Unanswered 1_05: True Right now it looks like this: (Question) 1_01: True 1_03: False 1_05: True I can't make the radio button required because it is a timed test where you have to work fast, so unanswered questions are going to happen. How do I make it so that unanswered radio buttons submit the value "unanswered" in the E-mail? I have a mysql table which will store users email addresses (each is unique and is the primary field) and a timestamp. I have added another column called `'unique_code' (varchar(64), utf8_unicode_ci)`. What I would very much appreciate assistance with is; a) Generating a 5 digit alphanumeric code, ie: 5ABH6 b) Check all rows the 'unique_code' column to ensure it is unique, otherwise re-generate and check again c) Insert the uniquely generated 5 digit alphanumeric code into `'unique_code'` column, corresponding to the email address just entered. d) display the code on screen. What code must I put and where? **My current php is as follows:** Code: [Select] require "includes/connect.php"; $msg = ''; if($_POST['email']){ // Requested with AJAX: $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'); try{ if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){ throw new Exception('Invalid Email!'); } $mysqli->query("INSERT INTO coming_soon_emails SET email='".$mysqli->real_escape_string($_POST['email'])."'"); if($mysqli->affected_rows != 1){ throw new Exception('You are already on the notification list.'); } if($ajax){ die('{"status":1}'); } $msg = "Thank you!"; } catch (Exception $e){ if($ajax){ die(json_encode(array('error'=>$e->getMessage()))); } $msg = $e->getMessage(); } } Hello I am working in moodle and its code base is in PHP. I am a novice to moodle as well as PHP and not quite familiar with PHP syntax. Right now I have built a Web page in moodle, and its view.php file I need to implement a fuctionality on click of a button. On click of submit button, I am trying to implement a functionality and I have written the code for that under if(isset($_POST['submit])) { ...my code...} Also while creating the form I have set the attributes as follows: echo "<form method='post' action='" . $_SERVER['PHP_SELF']."?inpopup=". $_GET['inpopup']."&id=" . $_GET['id'] . "'>"; But irrespective of whether or not I click the button, whenevr the page loads for the first time, it perform the code written in IF loop as well. So Am i going wrong in implementing a functionality on click of button in PHP or is it something related to moodle, if anyone knows? Any help or suggestions would be appreciated. As I am stuck with this logic since last three days. Regards hi guys i have a problem my mail dosent send if some data is entered in the textbox. if data is there it says page not found. If no data and i say submit it submits the same page and a blank email is sent. the form is used in the middle of the entire page. <form name="enquiry" action="<?php echo get_bloginfo('wpurl') .'/home/' ?>" method="POST" id="enquiry" > <div id="registerrow"> <div id="texttitle">Naam:</div> <input type="text" class="textboxdiv" name="name" id="name"> </div> <div id="registerrow"> <div id="texttitle">Email:</div> <input type="text" class="textboxdiv" name="email" id="email"> </div> <div id="registerrow"> <div id="texttitle">Telefoonnr.:</div> <input type="text" class="textboxdiv" name="phone" id="phone"> </div> <div id="registerrow"> <div id="texttitle">KvK nr.:</div> <input type="text" class="textboxdiv" name="kvknr" id="kvknr"> </div> <input name="Submit" type="submit" id="btnregister" /> </form> <?php include_once('mail_class.php'); require_once('mail_class.php'); if ($_POST['Submit']){ $name = $_POST['name']; $phone = $_POST['phone']; $msga = $_POST['kvknr']; $to = "nrocks@gmail.com"; $subject = "Enquiry for infosites"; $mailmsg = "<table width='772' border='2' cellpadding='0' bordercolor='#0099FF'>"; $mailmsg .= "<tr bgcolor='#0099FF'>"; $mailmsg .= "<td height='34' colspan='2' bgcolor='#91C8FF'><p align='center' style='font-family: Georgia, 'Times New Roman', Times, serif; font-size: 14pt;font-weight: bold;'><strong>Enquiry Form</strong></p></td>"; $mailmsg .= "</tr>"; $mailmsg .= "<tr>"; $mailmsg .= "<td height='38'><span style='font-family: Georgia, 'Times New Roman', Times, serif; font-weight: bold'><strong>Name:</strong></span></td>"; $mailmsg .= "<td height='38' > $name </td>"; $mailmsg .= "</tr>"; $mailmsg .= "<tr>"; $mailmsg .= "<td height='38'><span style='font-family: Georgia, 'Times New Roman', Times, serif; font-weight: bold'><strong>Phone No:</strong></span></td>"; $mailmsg .= "<td height='38' > $phone </td>"; $mailmsg .= "</tr>"; $mailmsg .= "<tr>"; $mailmsg .= "<td height='43'><span style='font-family: Georgia, 'Times New Roman', Times, serif; font-weight: bold'><strong>Enquiry For:</strong></span></td>"; $mailmsg .= "<td height='43'><span style='font-family: Georgia, 'Times New Roman', Times, serif; font-weight: bold'> $enquiry </span></td>"; $mailmsg .= "</tr>"; $mailmsg .= "<tr bgcolor='#0099FF'>"; $mailmsg .="<td height='35' colspan='2' bgcolor='#91C8FF'><p align='center' class='style1'> </p></td>"; $mailmsg .="</tr>"; $mailmsg .="</table>"; $headers = "From: ".$_POST['email']."\r\n"; $headers .= "MIME-Version: 1.0\r\n"; $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n"; if (mail($to , $subject , $mailmsg, $headers)) { echo 'Mail Send Succesfully'; } else { echo 'Mail was not send, Try again'; } } ?> </div> thanks Alright, so I play a browser game called Politics and War. I run an alliance that has 74 members. In that alliance we offer a bank service for all our members, but I - being the leader - am the only one who can access the bank. I have been building a site that works with the game API to gather data for members and create a dashboard. One of the features I am trying to build is allowing them to withdraw from their account instantly.
So, what I need: To be able to submit a POST request to login to the site (specifically on this page --> https://politicsandwar.com/login) with my username and password, but then I need to keep the session active and navigate to a different page (the alliance bank page). On that page I first need to scrape a value from a hidden input (token) and then I need to submit a POST request to this same page while still being logged in.
I am not asking someone to do it for me, but rather someone to help me know how to go about this. I have never submitted post requests with PHP, but I have used PHP cURL in the past. I also have made POST requests with JS, but never PHP.
Thank you so much for anyone that is able to help! hi i need help on posting multiple inputs in a single button...while using mysql_fetch_array here is my codes: <? $re6 = mysql_query('select username from users where course = "BSIT" and yearlevel = "FOURTH"'); ?> <br /> <h1>Post Grade</h1> <h1>IT, Fourth Year</h1> <br />Please fill the following form to send The Grade<br /> <? $n = 0; while($row = mysql_fetch_row($re6)) { echo'<form action="grade_post.php" method="post">'; echo'Recipient<span class="small">(Username)</span><input type="text" value="'.$row['username'].'" readonly="readonly" id="recip" name="recip[' . $n . ']" />'; echo'Subject<input type="text" value="'.htmlentities($otitle, ENT_QUOTES, 'UTF-8').'" id="title" name="title[' . $n . ']" />'; echo'<input type="hidden" value="FOURTH" id="year" name="year[' . $n . ']" />'; echo'<input type="hidden" value="FIRST" id="sem" name="sem[' . $n . ']" />'; echo'Grade<input type="text" id="message" name="message[' . $n . ']" ><br />'; ++$n; } ?> i get all my recipients in every input type, but when i tried to post it in my database not all of them are posted rather only one of them are posted in my database ...what i want to happen is that all of my recipients in every input type will be posted in my database with different ids'...help pls... Hello. I hope one of the PHP/HTML gurus here can help me. I have a web page that has been altered a bit to add some Google Analytics stuff and I've moved it to a 2nd directory. The original one works fine, the 2nd one won't post the form when I click the submit button. 1st URL https://www.theneutralizer.info/neutralizer 2nd URL: https://www.theneutralizer.info/neutralizer2 I have changed the action property to the correct script, and it does exist. But the problem is when clicking the button nothing happens. Anyone have any ideas? I can send the PHP code if needed, but since it's HTML output, it should work the way it is displayed in the browser. David Hey Guys. I am working with a form that shows the grand total on the checkout page. The value of the grand total is inside a hidden field. When click on submit, the _POST array doesn't get back the last value of the grand total. I need to hit the button twice to get the last value. The weird thing is when I echo the value of the grand total it display the latest value, but not with the POST array
For example. If the grand total is $10.00 and I click on submit. It will show the POST['grand_total'] as empty. If I click on submit again it will show the grand total of $10.00.
Below is my code that I am working with. Any help would be really appreciated.
if(isset($_POST['submit'])) {
/* Doesn't show if i put it after if($_POST['submit'] */
if(isset($_POST['grand_total'])) {
echo $_POST['grand_total'];
}
}
//A bunch of other html/php code. Another class calculates the subtotal assigns it the variable $subtotal
$cart_totals = new cartTotals($subtotal, $discounted_amount,$post_values->tip); // Cart class is shown below
/* Doesn't show if i put it before if($_POST['submit'] */
if(isset($_POST['grand_total'])) {
echo $_POST['grand_total'];
}
echo "<input name='grand_total' type='hidden' value='$cart_totals->grand_total' />"; // Shows the grand total after second from submission
echo "$cart_totals->grand_total"; // Shows grand total after the first submission
Cart Totals Class
class cartTotals {
public $subtotal;
public $sales_tax;
public $tip;
public $grand_total;
public $discount_amount;
public $href_page;
public $invalidCouponMessage;
const TEST_ENVIORMENT = FALSE;
/**
* [ Function gets constructed in the order summary where the [$discount_amount= ""] arg does need to be passed.
* But does get passed in when called on the checkout.php page. Therefore we set the default value to an empty string.]
* @param [float] $subtotal [subtotal get passed in from the parent class coreCartFunction]
* @param string $discount_amount [The class checkCouponCode calculates this discount amount based on the
* subtotal and the discount amount. It gets instantiated on the clients side and passed is this construction function.
* This is all done on the checkout page.]
*/
/*The way the construct function works is by invoking all the methods the passed arguments
When the methods get invoked the do all the work and set the properties its values. The properties then get echoed out
on the client side. */
function __construct($subtotal="", $discount_amount= "", $tip=""){
$this->subTotal($subtotal, $discount_amount);//SubTotal method takes the discount amount and subtracts it from the subtotal.
$this->salesTax($subtotal, $discount_amount);
$this->tip = $tip;
$this->grandTotal();
}
private function subTotal($subtotal,$discount_amount) {
$rounded_subtotal = round($subtotal-$discount_amount,2);
$money_format_subtotal = money_format('%i',$rounded_subtotal);
$this->subtotal = $money_format_subtotal;
}
private function salesTax($subtotal, $discount_amount =""){
$sales_tax = (STORE_SALES_TAX)?(float)STORE_SALES_TAX:8.875;
$sales_tax =(($this->subtotal)*$sales_tax)/100;
$sales_tax = round($sales_tax,2);
$this->sales_tax = $sales_tax;
}
public function Tip() {
//global $post_values;
//$last_tip_selected = $post_values->tip > 0 ? $post_values->tip : "" ;
$tip_output = "<select id='tip' name='tip'>";
for($tip=0.00; $tip<=11.75; $tip+=0.25){
if( $tip == "2") {$selected = " selected";} else {$selected ="";}
$formatted_tip = money_format('%i',$tip);
$tip_output .= "<option {$selected} id='selected_tip' value='$formatted_tip'>"."$".$formatted_tip ."</option>".PHP_EOL;
}
$tip_output .= "</select>";
return $tip_output;
}
private function grandTotal(){
$grand_total = round($this->sales_tax+$this->subtotal+$this->tip,2);
$grand_total_formatted = money_format('%i',$grand_total);
$this->grand_total = $grand_total_formatted;
}
Say I have an "Entries" table. I want to submit same multiple entries using a form submission. And If I have other queries submitted in the same form, I want those quarries to be submitted only once. Is that possible to do? Here's my code.
if(isset($_POST['submit'])) {
$entries = 10;
$id = 55;
$name = 'Smith';
$insert = $db->prepare("INSERT INTO entries(id, name) VALUES(:id, :name)");
$insert->bindParam(':id', $id);
$insert->bindParam(':name', $name);
$result_insert = $insert->execute();
if($result_insert == false) {
echo 'Fail';
} else {
echo 'Success';
}
}
?>
<form action="" method="post">
<input type="submit" name="submit" value="SUBMIT" />
</form>
Edited January 13, 2019 by imgrooot Hi. Pretty straight forward I guess but as the name suggests am a newbie. I have a form that requires the user to enter certain parameters. If the values are blank it submits to itself and loads the error messages. What I want to do is create PHP code that submits the form to a different url. What I thought was create two forms (the second with hidden fields replicating the first form), each form having a different url in the action"" code. What I cant work out is the PHP IF ELSE code to submit form 2 if Form1 is is validated correctly. This is the PHP code relevant to the form validation. Help? <?php //If form was submitted if ($_POST['submitted']==1) { $errormsg = ""; //Initialize errors if ($_POST[width]){ $title = $_POST[width]; //If title was entered } else{ $errormsg = "Please enter width"; } if ($_POST[drop]){ $textentry = $_POST[drop]; //If comment was entered } else{ if ($errormsg){ //If there is already an error, add next error $errormsg = $errormsg . " & content"; }else{ $errormsg = "Please enter drop"; } } } if ($errormsg){ //If any errors display them echo "<div class=\"box red\">$errormsg</div>"; } //If all fields present if ($title && $textentry){ //Do something echo 'THIS IS WHERE I WANT THE CODE TO SUBMIT FORM 2 or SUBMIT FORM 1 TO A DIFFERENT URL'; } ?> |
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