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PHP - Array/subarray Mysql Insert
Hi,
I have an 2 arrays ( $match[1] and $match[2] ) with 50+ fields that i need to insert into a database, but im not getting how i could do it. Until now im trying with with the following code: Code: [Select] $sql="INSERT INTO is_trigger_reference (triggerName) VALUES ('$match[2][0]')"; mysql_query($sql) or die(mysql_error()); But when i check into the db table i only got: Code: [Select] triggername ( field name ) Array[0] ( data inserted) I know i can set a var to each array ( 40+ ) but i belive there's something more clean than that Thanks! Similar TutorialsI have a multidimensional array for a calendar application as shown below. The first level is an associative array for calendar dates, and the second is a numeric array for multiple events on each day. The third level holds the events. I know that I can extract a single event using the array indices, such as: echo $events['2010-11-24'][0]['event_date']; If I know the number of events for the date, I can extract them one-by-one by incrementing the array index. However, I never know how many events will be stored for any one day. I also know that I can extract all the data in the entire array using a foreach loop. But how can I extract only the data in a subarray? Array ( [2010-11-16] => Array ( => Array ( [event_date] => 2010-11-16 [title] => Board Meeting ) [1] => Array ( [event_date] => 2010-11-16 [title] => Second event ) ) [2010-11-24] => Array ( => Array ( [event_date] => 2010-11-24 [title] => New meeting ) ) ) Hello. I am editing a plugin that is grabbing a multidimensional array, then breaking it out into a foreach statement and doing stuff with the resulting data. What I am trying to do is edit the array before it gets to the foreach statement. I want to look and see if there is a key/value combination that exists, and if it does remove that entire subarray, then reform the array and pass it to a new variable. The current variable Code: [Select] $arrSlides returns several subarrays that look like something like this (I remove unimportant variables for the sake of brevity): Code: [Select] Array ( [0] => Array ( [slide_active] => 1 ) [1] => Array ( [slide_active] => 0 ) ) What I want to do is look and see if one of these subarrays contains the key slide_active with a value of 0. If it contains a value of zero, I want to dump the whole subarray altogether, then reform the multidimensional array back into the variable Code: [Select] $arrSlides. I have tried a few array functions but have not had any luck. Any suggestions? Thanks in advance, Jason I'm trying to insert array of posts categories into MySQL. I'm getting category IDs from drop down list.. ERR: Notice: Notice: Array to string conversion in C:\laragon\*********\includes\functions.php on line 477
Array
Array
(
[0] => Array
(
[0] => 4
[1] => 5
)
)
PHP
try {
$sql = "INSERT INTO posts_category_ids (post_id, category_id) VALUES";
$insertQuery = array();
$insertData = array();
foreach ($filter_category as $row) {
$insertQuery[] = '(?, ?)';
$insertData[] = $id;
$insertData[] = $row;
}
if (!empty($insertQuery)) {
$stmt = $this->conn->prepare($sql);
$stmt->execute($insertData); //477
}
}catch (Exception $e){
echo $e->getMessage();
}
}
hi guys so i have this add contacts page and the form is divided into 3 different froms 1) primary contact 2)spouse 3)child and the child form data is inserted as array into database because in the primary contact part of the form there is a "Children ?" with yes and no radio button and if yes a drop down list is enabled where if user chooses say 2 then there would be 2 child form that appears. and since theres 2 children then in the database a new row and data will be added accordingly.
image attached to be clearer.
from2.jpg 24.15KB
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i got it inserted into database but in the specified field it says array: |child_name|dob|house_add1|mobile|office|email| inserted: |array|array-array-array|array|array|array|array| query:
"INSERT INTO child VALUES('','".$childsalutations." $childfname $childlname',' ".$cday."-".$cmonth."-$cyear ','$childline1','$childline2','$childm','$childoff','$childemail')"
in a stackoverflow question(not my own question) someone says: information stating arrays need to be split, before inserting into the table. does that mean something like this?:
$cday = ($_POST['cday']);
$cmonth = ($_POST['cmonth']);
$cyear = ($_POST['cyear']);
$childsalutations = ($_POST['child-salutations']);
$childfname = ($_POST['child-fname']);
$childlname = ($_POST['child-lname']);
$childline1 = ($_POST['child-line1']);
$childemail = ($_POST['child-email']);
$childm = ($_POST['child-mobile']);
$childoff = ($_POST['child-office']);
$info = array('c_name' => $childsalutation $childfname $childlname, 'c_dob' => $cday-$cmonth-$cyear, 'c_line1' => $childline1, 'c_mobile' => $childm, 'c_office' => $childoff, 'c_email' => $childemail)
just in case u wanted to c the html child form(warning its abit long,very!):
<table class="prime"> <tbody> <br> <tr><td style="font-size:20px;font-weight:bold">Child <span id="number"></span></td></tr> <tr> <td>Salutation :</td> <td><select name="child-salutations[]" id="child-salutations"> <option value="" disabled selected>Salutations</option> <option value="Datin">Datin</option> <option value="Datin Paduka">Datin Paduka</option> <option value="Dato Paduka">Dato Paduka</option> <option value="Dato'">Dato'</option> <option value="Dato' Seri">Dato' Seri</option> <option value="Datuk">Datuk</option> <option value="Datuk Seri">Datuk Seri</option> <option value="Dr.">Dr.</option> <option value="Haji">Haji</option> <option value="Hajjah">Hajjah</option> <option value="HM">HM</option> <option value="HRH">HRH</option> <option value="Miss">Miss</option> <option value="Mrs.">Mrs.</option> <option value="Mr.">Mr.</option> <option value="Pehin">Pehin</option> <option value="Professor">Professor</option> <option value="Raja">Raja</option> <option value="Tan Sri">Tan Sri</option> <option value="Tengku">Tengku</option> <option value="Tuanku">Tuanku</option> <option value="Tun">Tun</option> <option value="Tunku">Tunku</option> <option value="Ungku">Ungku</option> </select> </td> </tr> <tr><td colspan="2"><label class="label" style="color:Red">*If a person has many salutations, choose the highest form of salutation</label></td></tr> <tr><td>First Name :</td><td><input type="text" name="child-fname[]" id="child-fname" class="style" /></td> <td>Last Name :</td><td><input type="text" name="child-lname[]" id="child-lname" class="style" /></td></tr> <tr> <td>Date of Birth : </td> <td> <select name="cday[]"> <option value=""selected disabled>Day</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <select name="cmonth[]"> <option value="" selected disabled>Month</option> <option value="1">January</option> <option value="2">February</option> <option value="3">March</option> <option value="4">April</option> <option value="5">May</option> <option value="6">June</option> <option value="7">July</option> <option value="8">August</option> <option value="9">September</option> <option value="10">October</option> <option value="11">November</option> <option value="12">December</option> </select> Year : <input type="text" name="cyear[]" maxlength="4" size="4" class="year"> </td> </tr> <tr><td>Where do they live ?</td><td colspan="3"><input type="radio" name="living[]" id="living-me" class="living-me"/>With Me<input type="radio" name="living[]" id="living-other" class="living-other"/>With Other Parent<input type="radio" name="living[]" id="living-own" class="living-own"/>Own</td></tr> <tr><td>House Address</td></tr> <tr><td>Line 1 :</td><td><input type="text" name="child-line1[]" id="child-line1" size="20" class="style" /></td> <td>Mobile No :</td><td><input type="text" name="child-mobile[]" id="child-mobile" class="style" /></td></tr> <tr><td>Office No :</td><td><input type="text" name="child-office[]" id="child-office" class="style" /></td> <td>Email Address : </td><td><input type="email" name="child-email[]" id="email" class="style" /></td></tr> </tbody> </table> Hello, I have been at this for awhile now and cant seem to figure it out. I have 2 separate arrays like shown below and I am trying to insert each value into my database using one update query. I have tried a for loop inside each array, but only one column populates. I have tried breaking the values outside their for loop, etc, etc. Does anyone know a way this can be done? Code: [Select] //Cars $cars = array('ford', 'toyota', 'bmw'); //Places $places =arrray('Orlando','California','Texas'); foreach ($cars as $car){ foreach ($places as $place){ $place .=$place; } mysql_query("INSERT INTO vehicles (cars, places) VALUES ('" . $car. "', '" . $place . "'')"); } I have tried many ways of storing an array of data that comes from a multiple selection form into a mysql table, including serialization. I am currently trying to do it by forming a string, and using the string in the insert query, but keep getting errors, or just nothing happening. I am not sure what I am doing wrong. Code: [Select] $categoryString = array(); if ($categoryArray){ foreach ($categoryArray as $category){ $categoryString[] = $category.'<br />';} } $categoryquery= "INSERT INTO categoryname VALUES('$categoryString')"; mysql_query($categoryquery); Thank you for your time as always.
An affiliate marketer refers some products which are stored in a simple array. $all_items_sold = '{"7777":{"item":"hammer","price":"4.99"},"8888":{"item":"nail","price":"1.99"},"9999":{"item":"apple","price":"2.00"}}';
$referred_by_Affiliate = array('1234','8888','7777');
So, out of all the 3 items that sold, only 2 of them were referred by the affiliate marketer.
Currently I do this:
Is there a "best practices" way to accomplish this?
Thank you. I am simply trying to insert a value generated from an array in a while loop, but it seems the value is not global and I can't pass it as I like. I did some research on this, but could not find an answer that solved my issue... Here is my select box code which is working perfect: <select name="city"> <?php $sql = "SELECT id, city_name FROM cities ". "ORDER BY city_name"; $results_set = (mysqli_query($cxn, $sql)) or die("Was not able to produce the result set!"); while($row = mysqli_fetch_array($results_set)) { echo "<option value=$row[id]>$row[city_name]</option>"; } ?> </select> Are any variables defined in a while loop global to the while loop only? Here is my SQL which you can see my $row[id] being passed thru field city_id... The value is being generated as supposed to based on value like: value="1", value="2" etc.. for the select options for each city name. So the values are there... But I CANNOT get that numerical id to pass to the database when submitting my form. Any ideas for a workaround to get this value passing as normal? if (isset($_POST['addPosting'])) { $query = "INSERT INTO Postings (id, city_id, title, description) VALUES ('','$row[id]','$_POST[title]','$_POST[description]')"; Hi again all, Why does the foreach loop im doing, put the array values from collection, into seperate table rows rather than 1 row per whole array? <?php class registration{ public $fields = array("username", "email", "password"); public $data = array(); public $table = "users"; public $dateTime = ""; public $datePos = 0; public $dateEntryName = "date"; public $connection; function timeStamp(){ return($this->dateTime = date("Y-m-d H:i:s")); } function insertRow($collection){ //HERE foreach($this->fields as $row => $value){ mysql_query("INSERT INTO $this->table ($value) VALUES ('$collection[$row]')"); } mysql_close($this->connection->connectData); } function validateFields(){ $this->connection = new connection(); $this->connection->connect(); foreach($this->fields as $key => $value){ array_push($this->data, $_POST[$this->fields[$key]]); } $this->dateTime = $this->timeStamp(); array_unshift($this->data, $this->dateTime); array_unshift($this->fields, $this->dateEntryName); foreach($this->data as $value){ echo "$value"; } $this->insertRow($this->data); } } $registration = new registration(); $registration->validateFields(); ?> I end up with 3 rows row 1: username row 2: email row 3 : password rather than row 1:username email password. Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; I need a help in the following : I have an admin page from where the admin attaches an gif image.This attached image should be shown to the user as a scrolling image. The code for the scrolling image is done through javascript. So my actual problem is getting the name of the attached gif image to the javascript array which is used for scrolling horizontally. I have an array $array_1 Code: [Select] ARRAY( [0] => info 1 [1] => info 2 [2] => info 3 ) and I have another array $array_2 Code: [Select] ARRAY( [0] =>thank you and welcome to what ever [1] =>the info you added * thanks for entering your info ) I want to loop though the first array and place the values into the [1] of the second array. But the tricky thing is I want it to insert were the * is. Code: [Select] foreach ($array_1 as $key => $val) { //not sure about this insert into ($array_2[1],after *, $val); } any help would be awesome. Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks Hi people I am new to php and I need your help.
I am usig libchart and want to make the bars colored based on value:
Original code:
$this->setBarColor(array( new Color(42, 71, 1), )); I want to make something like this: $this->setBarColor(array( if ( ( condition1 )) new Color(42, 171, 1), if ( ( condition2 )) new Color(42, 71, 1), if ( ( condition3 )) new Color(42, 71, 211), )); I do not know php syntax yet, so how can I do this? Thank you, Alex I need help badly! What I want to do is insert into database the value from the selected radio group buttons.. All of them. There are 10 radio groups total (they can be less, but not more). Thanks! Code: [Select] <?php require_once('Connections/strana.php'); mysql_select_db($database_strana, $strana); ?> <link href="css/styles.css" rel="stylesheet" type="text/css" /> <table width="100%" height="100%" style="margin-left:auto;margin-right:auto;" border="0"> <tr> <td align="center"> <form action="" method="post" enctype="multipart/form-data" name="form1"> <table> <?php $tema = mysql_query("SELECT * from prasanja where tip=2")or die(mysql_error()); function odgovor1($string) { $string1 = explode("/", $string); echo $string1[0]; } function odgovor2($string) { $string1 = explode("/", $string); echo $string1[1]; } while ($row=mysql_fetch_array($tema)) { $id=$row['prasanje_id']; $prasanje=$row['prasanje_tekst']; $tekst=$row['odgovor']; ?> <tr> <td> </td> </tr> <tr> <td class="formaP"> <?php echo $prasanje?> </td> </tr> <tr> <td class="formaO"> <p> <label> <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor1($tekst) ?>" /> <?php odgovor1($tekst) ?></label> <br /> <label> <input type="radio" name="Group<?php echo $id?>" value="<?php odgovor2($tekst) ?>" /> <?php odgovor2($tekst) ?></label> <br /> </p></td> </tr> <tr> <td> <br /> </td> </tr> <?php } ?> </table> <input align="left"type="submit" name="submit" value="Внеси" > </form> </td> </tr> </table> prasanje = question tekst/odgovor = answer The answer table: id - primary question_id - the questions ID whose answer is selected in the radio group user_id - cookie takes care of this answer - the value from radio group date - automatic I have this code: <?php $con = mysql_connect("localhost","hhh","hhh"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("hhh", $con); // -------------------- // Avatar insert check // -------------------- session_start(); $name = $_POST[name]; $group = $_POST[group]; $age = $_POST[age]; $usernameid = $_SESSION[id]; $result = mysql_query("SELECT * FROM avatars WHERE name='$_POST[name]'"); $num = mysql_numrows($result); if ($num == 0) { mysql_query("INSERT INTO avatars (id, usernameid, name, group, age, xp) VALUES ('', '$usernameid', '$name', '$group', '$age', '0')"); header( 'Location: me/' ) ; } else echo 'Sorry, please pick a new name'; ?> And it does everything but put the data into the datebase. If I add a session befor and after '$request' they both run, but the sql doesn't. No error returns, if just redirects to the other page. Any help? Hi guys I have a registration form working fine, my database is as below: userid username password repeatpassword I have added another column which is "name", users can update their profile once they have logged in so I have created updateprofile.php and when I login-->go to update profile and insert my name nothing adds to mysql name column this is my code below: <?php include ("global.php"); //username session $_SESSION['username']=='$username'; $username=$_SESSION['username']; //welcome messaage echo "Welcome, " .$_SESSION['username']."!<p>"; if ($_POST['register']) { //get form data $name = addslashes(strip_tags($_POST['name'])); $update = mysql_query("INSERT INTO users (name) VALUES ('$_POST[name]') WHERE username='$username'"); } ?> <form action='updateprofile.php' method='POST'> Company Name:<br /> <input type='text' name='name'><p /> <input type='submit' name='register' value='Register'> </form> can you please tell me where in this code is wrong? Im new in php so please excuse me if I have silly mistakes. thanks in advance well this is truely embarrising...i have a insert statement which works within phpmyadmin but when using mysqli_query it returns a error.
INSERT INTO users (username, timestamp) VALUES ('test', UTC_TIMESTAMP())
Unknown column 'timestamp' in 'field list'
i've been playing about with this for a few hours now ...tried changing the column name (timestamp), adding ` around column names as well as table name.
the column exists which is the strangest part, and ive even checked there is no space after the column name in the db.
whats going on please?
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