PHP - Php Menu "active" Button For Sub Navs
Hi,
First of all, this is not a spam. Someone with the username Pikachu2000 removed it thinking it was a spam so now I have to post it again. I really need you help fixing this problem. Anyway, I'm building a site where I used a "php include once" for the navigation menu. I was able to show the active pages when they don't have sub pages but I can't seem to show the active sub pages. I've been trying for days and nothing I try seems to work! I'm sure some people have asked this before but I can't find any forums that describe how to do this with sub navs rather then just the main nav buttons. The coding is below along with a link to one of the sub pages in the site I'm working on. The problem is with the sub pages under "Our Coffee Farm". Thanks for reading my post. Website Link: http://vanessajohodesigns.com/sarpa/the_farm/plantation.php before DOCTYPE: <?php $thisPage="The Plantation"; ?> after body tag: <?php include_once("../includes/nav.php");?> nav.php include once file: <div class="arrowsidemenu"> <div<?php if ($thisPage=="Home") echo " class=\"active\""; ?>> <a href="../index.php">Home</a></span></div> <div class="menuheaders"><a>Our Coffee Farm</a></div> <ul class="menucontents"> <li<?php if ($thisPage=="The Plantation") echo " class=\"active\""; ?>><a href="plantation.php">The Plantation</a></li> <li<?php if ($thisPage=="Blooming & Harvest") echo " class=\"active\""; ?>><a href="bloom_harvest.php">Blooming & Harvest</a></li> <li<?php if ($thisPage=="Coffee Processing") echo " class=\"active\""; ?>><a href="processing.php">Coffee Processing</a></li> </ul> <div<?php if ($thisPage=="About Us") echo " class=\"active\""; ?>> <a href="../about_us.php">About Us</a></div> <div<?php if ($thisPage=="Rainforest Alliance") echo " class=\"active\""; ?>> <a href="../rainforest_alliance.php">Rainforest Alliance</a></div> <div<?php if ($thisPage=="Social Commitment") echo " class=\"active\""; ?>> <a href="../social_commitment.php">Social Commitment</a></div> <div<?php if ($thisPage=="News & Events") echo " class=\"active\""; ?>> <a href="../news_events.php">News & Events</a></div> <div<?php if ($thisPage=="Web Cameras") echo " class=\"active\""; ?>> <a href="../webcams.php">Web Cameras</a></div> <div<?php if ($thisPage=="Photo Gallery") echo " class=\"active\""; ?>> <a href="../gallery.php">Photo Gallery</a></div> <div<?php if ($thisPage=="Contact Us") echo " class=\"active\""; ?>> <a href="../contact_us.php">Contact Us</a></div> <!--end .arrowsidemenu --></div> Similar TutorialsCan someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hello, I have 2 questions... 1. Do you know of any good and easy php breadcrumb solution? 2. I have recently learned how to use PHP to make a navigation Active based on what page I am on (see below). If I am on the "currentPage" "contact.php" it will show it active... But, what I also want to do is have the main nav active on a sub-nav page. Is it possible to have 2 or more page referenced? Something like ($currentPage == 'contact.php' AND 'contact_form.php') Where both pages would make the link appear active and highlighted. <ul> <li><a href="contact.php" <?php if ($currentPage == 'contact.php') {echo 'id="here"';} ?>>Contact</a></li> <li><a href="about.php" <?php if ($currentPage == 'about.php') {echo 'id="here"';} ?>>About Us</a></li> <li><a href="careers.php" <?php if ($currentPage == 'careers.php') {echo 'id="here"';} ?>>Careers</a></li> <li><a href="services.php" <?php if ($currentPage == 'services.php') {echo 'id="here"';} ?>>Services</a></li> <li><a href="index.php" <?php if ($currentPage == 'index.php') {echo 'id="here"';} ?>>Home</a></li> </ul> Thank you in advance for your help I have a menu on my site on each page, I want to put it in it's own menu.php file but i'm not sure how to set the class="active" for whatever page i'm on. Here is my code:<?php if ($url == $curpage) { $class = "active"; } else { $class = "in-active"; } ?> <ul id="top-navigation"> <li><a href="./" class="<? echo $class ?>">Homepage</a></li> <li><a href="?p=MM" class="<? echo $class ?>">Maintenance Mode</a></li> <li><a href="?p=UCP" class="<? echo $class ?>">User CP</a></li> <li><a href="?p=LYRICS" class="<? echo $class ?>">Lyrics</a></li> <li><a href="?p=SB1" class="<? echo $class ?>">Sidebar 1</a></li> <li><a href="?p=SB2" class="<? echo $class ?>">Sidebar2</a></li> <li><a href="?p=SHP" class="<? echo $class ?>">Site HomePage</a></li> <li><a href="?p=EDTpst" class="<? echo $class ?>">post.php</a></li> <li><a href="?p=EDTUCP" class="<? echo $class ?>">UCP.php</a></li> <li><a href="?p=EDTtimer" class="<? echo $class ?>">timer.php</a></li> </ul> I want $curpage to be the only page I'm on not all of the pages. How would I do this would it be like $url = (isset($_GET['p']) ? $_GET['p'] : 'home'); $s1 = "main" ; $s2 = "MM" ; $s3 = "UCP" ; $s4 = "LYRICS" ; //cont. . . if ($url == $s1) { $class = "active"; } elseif ($url == $s2) { $class = "active"; } elseif ($url == $s3) { $class = "active"; } elseif ($url == $s4){ $class = "active"; } //cont. . . Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks Hi all I am new here and looking for some help, I am also not a PHP coder and learning as I go. My problem is this I have a script and have a header.php and global_header.tpl amongst all the other files that come in the script, I have a tabed navigation in global_header.tpl that I want to set to class="active" depending on what page is being viewed. I have spent all last night and all of today going through google and yahoo trying all diferent bits of code but absolutly nothing works. At the moment I have a file I made from some code found on google that I placed in its own .hph file named activetabs.php,I have included this in header.php using Code: [Select] include 'activetabs.php'; In activetabs.php I have Code: [Select] <?php if ($_SERVER["REQUEST_URI"] != '/browse.php') { $tab1 = 'none'; } else { $tab1 = 'active'; } $template->assign_vars(array( 'TAB1' => $tab1, )); ?> testing only but againe it wont work. If I change the above code to Code: [Select] <?php if ($_SERVER["REQUEST_URI"] == '/browse.php') { $tab1 = 'none'; } else { $tab1 = 'active'; } $template->assign_vars(array( 'TAB1' => $tab1, )); ?> the tab becomes active but stays active. Could any of you either show me how to get that code working or kindly provide me some working code. Thanks in advance cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; If you look at this form: kmkwebdevelopment.com/formtest/upload.php you will see that when you click on the "add another upload box" button, instead of it adding another upload box, it is submitting the form for some reason. Can anyone see where the error lies? Relevant snippet of code below: <?php //deafult number of upload boxes $upload_quant = 4; //if the user increased the number of boxes if(isset($_POST['increase_upload'])) { //increasing the number of upload boxes $upload_quant = $_POST['previous_upload'] + 1; } $upload_quantity = $_POST['previous_upload']; //getting all the names into an array $uplaoded_array = array(); for($i=0;$i<$upload_quantity;++$i) { $ii = $i+1; $upload_name = 'upload'.$ii; $get_upload_name = $_POST['$upload_name']; array_push($uplaoded_array,$get_upload_name); } ?> <form class="uploadform" action="<?php echo $_SERVER["PHP_SELF"] ?>" method="post" enctype="multipart/form-data" onSubmit="return CheckForm(this);"> <?php IsThereErrors("0", $_iserrors); ?> <input type="hidden" name="_referer" value="<?php echo $_referer ?>"> <input type="hidden" name="_next_page" value="1"> <p class="form_expert_style"><input name="URL" type="text" value=""/></p> <table> <tr> <td>First Name *</td> <td><input type='text' size='30' name='firstname' onBlur="FieldBlur(this.name+'_tooltip')" <?php mark_if_error("firstname", "") ?> value="<?php echo isset($_values["firstname"]) ? htmlspecialchars($_values["firstname"]) : "" ?>"></td> </tr> <tr> <td>Last Name *</td> <td><input type='text' size='30' name='lastname' onBlur="FieldBlur(this.name+'_tooltip')" <?php mark_if_error("lastname", "") ?> value="<?php echo isset($_values["lastname"]) ? htmlspecialchars($_values["lastname"]) : "" ?>"></td> </tr> <tr> <td>E-mail *</td> <td><input type='text' size='30' name='email' onblur="FieldBlur(this.name+'_tooltip')" <?php mark_if_error("email", "") ?> value="<?php echo isset($_values["email"]) ? htmlspecialchars($_values["email"]) : "" ?>"></td> </tr> <tr> <td>Company Number *</td> <td><input type='text' size='30' name='companynumber' onBlur="FieldBlur(this.name+'_tooltip')" <?php mark_if_error("companynumber", "") ?> value="<?php echo isset($_values["companynumber"]) ? htmlspecialchars($_values["companynumber"]) : "" ?>"></td> </tr> <?php for($i=0;$i<$upload_quant;++$i) { $ii = $i+1; $upload_name = 'upload'.$ii; echo <<<_END <tr> <td>Upload $ii</td> <td><input class="image" type='file' size='30' name='$upload_name'></td> </tr> _END; } echo <<<_END <tr> <td> <input type="hidden" value="$upload_quant" name = "previous_upload"/> <input type="submit" name="increase_upload" value="Add another upload box" /> </td> <tr> <td><input type="submit" name="SubmitBtn" onClick="CheckForm1();" value="SUBMIT" /></td> </tr> </table> </form> _END; } ?> </html> <?php Thanks I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 Hi, I have set up 2 php pages page 1 - add_entry2.php In this page I have a invoice table created where I can dynamically add/delete rows. This has a View Bill button which takes me to page 2- add_entry3.php In this page it shows up the rows added in page 1 in read only format, so if the user wants to modify the data that he/she entered then he must Click on <back> that i have provided in the page 2 which will direct him to page 1 Now the problem starts here on click of Back the dynamically added rows dissappear..which is frustrating..I know its something to do with my code..but can anyone help me fix it. One more thing is that i dont want to store the data into DB till the finalise button is clicked on page 2 so that means till page 2 is submitted nothing goes to DB from Page 1. I am able to retain values if I use the code Code: [Select] <form action="add_entry2.php" name="eval_edit" method="post" format="html"> i,e if I submit back to the same page and retrieve values form $_POST but If I use the code Code: [Select] <input type="button" value="Back" onClick="history.go(-1);return true;">to get back to add_entry2.ph it looses all the values. Is there any other way to code the BACK link retaining my $_POST values(Do you think $_SESSION would work in this case?) Hi. I have just one question (I have searched for an answer for this but have not been able to locate one): How do you go about changing the text on a "Submit Query" button to display simply "Submit"? Below is the current code for the page that displays said button. Thank-you in advance for any help or direction. <?php include 'connection.php'; $query = "SELECT * FROM people"; $result = mysql_query($query) or die(mysql_error()); while ($person = mysql_fetch_array($result)){ echo $person ['name']; echo $person ['descrip']; } ?> <H1>Add Your Review:</H1> <form action="create.php" method="post"> Subject <input type="text" name="inputName" value=""/> </br > Review <textarea cols="50" rows="4" name="inputDesc" value=""/></textarea> </br > <input type= "submit" name= "submit"/> </form> <html> <head></head> <body> <p>The current second is <span style='font-size:16px;font-weight:bold;color:red;position:absolute;right:25px;'><?php echo time(); ?></span> on this computer.</p> </body> </html> I am currently creating a form and I want to populate a drop down selection menu with data from two fields in a form. For example, I want it to pull the first and last name fields from a database to populate names in a drop down menu in a form. I want the form to submit to the email address of the person selected in the drop down. Is this possible to do? The email is already a field in the record of the person in the database. Can anyone give me some pointers or advice on how I should go about setting up the "Select" box drop down? I am not sure how to code it to do what I am wanting. Any links to relevant help would be appreciated too. Thanks in advance! I've searched but can't seem to find anything I can apply to this situation. Most of the resources are dedicated to dropdown menu's from the same table. I have two tables 'regions' and 'cities' and I am looking to create a menu that lists all the cities within a region then moves on to do the same for the rest of the regions in that state: State1 Region1 City1 City2 City3 Region2 City1 City2 City3 Region3 Etc My tables: States table: stateID, state Regions table: regionID, region, stateID Cities table: cityID, city, regionID I currently have two pages- select region, then select city... I'd like to consolidate to one step after choosing a state. I know I need a nested loop, (while?), and to count the results somehow to retrigger loop; also not sure how to handle two mySQL querries in the nested loop. I'm having trouble wrapping my mind around it. Thank you. I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this.. GoodDay "username", Blah Blah! how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE! This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=347922.0 Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? Hello all, I'm using sessions to store a username/password For example, I have the following at the top of all my source files: Code: [Select] <?php session_start(); if(!isset($_SESSION['myusername'])){ header("Location:login.php"); exit; } else { $username = $_SESSION['myusername']; $permissionLevel = $_SESSION['mypermissionlevel']; } ?> Now, I'd like to add a "Remember Me" checkbox so they can store their login info (securely!) so they don't have to log in all the time.... How do I do this? Thanks |