|
PHP - Looping Through Mysql Query Using Php
Apologies if this should be in the mysql forum but hopefully this is the correct one.
I am trying to extract the sum of a column from my database for each financial year, at the moment I am doing each year as a separate recordset but I am certain there must be a more automated way! The financial year is 1st April to 31st March each year and I need to create a variable which is a sum of each year, you'll see in my code below what I mean, any help gratefully appreciated as I am going to end up with decades of info in the db and am keen to get the code right now! The relevant recordsets are 2,5,7. db is readingID, date, reading The code and page does work fine, it's just long winded! Code: [Select] <?php mysql_select_db($database_wind, $wind); $query_Recordset1 = "SELECT readingID, date_format(date,'%d/%m/%Y') as date, reading FROM solar ORDER BY readingID DESC LIMIT 5"; $Recordset1 = mysql_query($query_Recordset1, $wind) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); mysql_select_db($database_wind, $wind); $query_Recordset2 = "SELECT SUM(reading) as year1total FROM `solar` WHERE date between '2010-04-01' and '2011-03-31'"; $Recordset2 = mysql_query($query_Recordset2, $wind) or die(mysql_error()); $row_Recordset2 = mysql_fetch_assoc($Recordset2); $totalRows_Recordset2 = mysql_num_rows($Recordset2); mysql_select_db($database_wind, $wind); $query_Recordset3 = "SELECT * FROM solar ORDER BY readingID DESC Limit 29"; $Recordset3 = mysql_query($query_Recordset3) or die(mysql_error()); mysql_select_db($database_wind, $wind); $query_Recordset4 = "SELECT readingID, YEAR(date) as yeardate, MONTHNAME(date) as monthdate, SUM(reading) as sumreading FROM `solar` Group by yeardate, monthdate Order by readingID ASC"; $Recordset4 = mysql_query($query_Recordset4) or die(mysql_error()); mysql_select_db($database_wind, $wind); $query_Recordset5 = "SELECT SUM(reading) as year2total FROM `solar` WHERE date between '2011-04-01' and '2012-03-31'"; $Recordset5 = mysql_query($query_Recordset5, $wind) or die(mysql_error()); $row_Recordset5 = mysql_fetch_assoc($Recordset5); $totalRows_Recordset5 = mysql_num_rows($Recordset5); mysql_select_db($database_wind, $wind); $query_Recordset6 = "SELECT datediff( Max(date), Min(date)) as DateDiff, Sum(reading) as LatestReading, date_format(MAX(date),'%d/%m/%Y') as LatestDate FROM solar"; $Recordset6 = mysql_query($query_Recordset6, $wind) or die(mysql_error()); $row_Recordset6 = mysql_fetch_assoc($Recordset6); $totalRows_Recordset6 = mysql_num_rows($Recordset6); mysql_select_db($database_wind, $wind); $query_Recordset7 = "SELECT SUM(reading) as year3total FROM `solar` WHERE date between '2012-04-01' and '2013-03-31'"; $Recordset7 = mysql_query($query_Recordset7, $wind) or die(mysql_error()); $row_Recordset7 = mysql_fetch_assoc($Recordset7); $totalRows_Recordset7 = mysql_num_rows($Recordset7); $average = (int)(($row_Recordset6['LatestReading'])/($row_Recordset6['DateDiff'])); $income1 = $row_Recordset2['year1total']*0.428; $income2 = $income1 + $row_Recordset5['year2total']*0.464; $income = $income2 + $row_Recordset7['year3total']*0.464; $saving = $row_Recordset2['year1total']*0.0675; $saving = $saving + $row_Recordset5['year2total']*0.0675; $saving = $saving + $row_Recordset7['year3total']*0.0675; ?> Similar TutorialsI am trying to loop through the array that I have created to check to see if any of the dates in the array match the date I am passing (which is todays date) and then asks the user to consider making another booking. This is what I have so far but I am not sure how to finish it off: Code: [Select] $table_id = 'booking'; $query = "SELECT * FROM booking WHERE bookingDate = 'newDate'"; $result = mysql_query($query); $loop = $end_Time - $start_Time; echo $loop; while($row = mysql_fetch_assoc($result)){ if ($startTime || $end_Time == 'booking.startTime'){ echo "choose another booking"; }{ echo "booking is ok"; } Hey guys. Just need some help on how I can add a query on row 2 if let's say a field is populated (Ex. spouse != null). Here is the code but having a hard time trying to put that 2nd row while it's looping. Any help would be appreciated. Thanks! $data = ''; while ( $row = mysql_fetch_row($export)) { $line = ''; foreach ( $row as $value ) { if ( ( !isset($value) ) OR ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace('"', '""', $value); $value = '="' . $value . '"' . "\t"; // ^ // Added an equal sign } $line .= $value; } $data .= trim($line)."\n"; } $data = str_replace("\r", "", $data); // return message if query returns no data if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } // setup headers with no caching header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=data.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; } else { Sorry, I originally posted part of this in MYSQL Help, but I was advised to post it here. I'm hoping someone can help me out. I have 2 tables. "categories" and "subcats" (sub categories). I used a JOIN query for both.. Code: [Select] SELECT categories.*, subcats.* FROM categories JOIN subcats on (categories.cat_id = subcats.cat_id) ORDER BY cat_name Then I used a while loop to echo all the categories from the "categories" table and their respective sub-categories from the "subcats" table. $sql = "SELECT categories.*, subcats.* FROM categories JOIN subcats on (categories.cat_id = subcats.cat_id) ORDER BY cat_name"; $cats_result = $connection->query($sql) or die(mysqli_error($connection)); while ($row = $cats_result->fetch_assoc()) { $cat_id = $row['cat_id']; $cat_name = $row['cat_name']; $subcat_name = $row['subcat_name']; //should output all categories once and nest their subcategories echo "<strong>".$cat_name."</strong>"; echo "<br />"; echo $subcat_name; echo "<br />"; } No MYSQL errors but unfortunately I get this output.. Technology Computers Technology Gadgets Technology Robots Health Fitness Health Diet What sort of code can use in the loop to echo categories just once instead of multiple times for each topic?
So I have a database that is structured like this: https://imgur.com/a/DdyTqiE
I would like to loop through this table, and get a count of how many were 'is_no_show' and 'is_cancelled' per (unique) category with respect to 'scheduled_student_services.' How would I approach this? I know I probably need to do two loops but I'm not sure the PHP syntax for this. Any suggestions or tips would be helpful. Thank you for your time! Hi all I have 2 tables: 1. is a tables full of images that have an id, a src and a title (images_table). 2. table is a list of records with an id, a description and an images_id (records_table) What I'm looking to do is: Loop through the records in the records_table and find the description, the description is something like this 'Welcome to Kansas'. Then, I want to loop through the images_table and find the associated image of Kansas, based on a MySQL LIKE statement. This is because the images_table has a title of 'Kansas', for example. Once this has been done, I then need to insert the id of Kansas into the images_id in the records_table a possible MySQL UPDATE. Has anyone got an idea how I could do this? Thanks Here is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate. What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop. It doesn't matter if I get to the next page using a header redirect or a form submit. I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. Any ideas? Query whats wrong with this query? $queryreg = mysql_query("UPDATE application SET employer = '$employer' AND eaddy = '$employer_address' AND ecity = '$employer_city' AND estate = '$employer_state' and ezip = '$employer_zip' AND supervisor = '$employer_supervisor' WHERE appID = '$appID'") or die(mysql_error()); I can't figure it out. Hi
I need a sql query help from you guys.
It is a sql query for get all upline referrer details from database for particular person
when new person register his details are storing in wp_members_tbl with uername, password, firstname, lastname, email, phone, address, referrer etc.
Below the query is for user
$wp_aff_members_db = $wpdb->get_row("SELECT * FROM $members_table_name WHERE refid = '".$_SESSION['user_id']."'", OBJECT);
And below the query is for this user's upline referrer
$wp_aff_members_db = $wpdb->get_row("SELECT * FROM $members_table_name WHERE refid = '$referrer'", OBJECT);
Now i need the query for find and get this referrer's upline referrer.
Please help me with a solution
Regards
Edited by rajasekaran1965, 23 October 2014 - 10:09 AM. Hi Guys, I have been having problems with a piece of PHP and mysql. I was wondering if you could help me out? The error is = Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /customers/klueless.net/klueless.net/httpd.www/daisysite/home.php on line 120 Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /customers/klueless.net/klueless.net/httpd.www/daisysite/home.php on line 122 And this is the code which goes with these errors = Code: [Select] $msgquery = "SELECT * FROM spotty_messages WHERE (id_receiver = '" . $userid . "') AND read = '0'"; $messageres = mysql_query($msgquery); $messrow = mysql_fetch_array($messageres); $messagecount = mysql_num_rows($messageres); I have 2 tables (see code below) (1) "tbl_users" has all users info, including "user_alias" (VARCHAR) and "user_id" (INT and PRIMARY KEY) (2) "tbl_projects" has all project info, including "project_client" (INT) which i linked to "user_id" from "tbl_users" and displays "user_alias" Code: [Select] CREATE TABLE `tbl_users` ( `user_id` int(11) NOT NULL auto_increment, `user_first` varchar(25) NOT NULL, `user_last` varchar(25) NOT NULL, `user_email` varchar(35) NOT NULL, `user_pw` varchar(12) NOT NULL, `user_role` int(1) NOT NULL, `user_alias` varchar(35) NOT NULL, PRIMARY KEY (`user_id`) ) CREATE TABLE `tbl_projects` ( `project_id` int(11) NOT NULL auto_increment, `project_client` int(1) NOT NULL, PRIMARY KEY (`project_id`) ) So... I managed to display all users and all projects but I want to show all users with ONLY their projects assigned. I mean, when I click on a user, I want to see his or hers contact info and all the projects that specific user is linked to. For instance, i might have project 1, project 2, project 3 and project 4. Project 1, 2 and 4 are linked to user 1 so when i click on user 1 i see projects 1, 2 and 3 (not 4). Code: [Select] <?php require_once('config.php'); mysql_select_db($database, $makeconnection); //this displays all projects $sql_get_projects="SELECT * FROM tbl_projects ORDER BY project_id ASC"; $get_projects = mysql_query($sql_get_projects, $makeconnection) or die(mysql_error()); $row_get_roles = mysql_fetch_assoc($get_projects); $totalRows_get_projects = mysql_num_rows($get_projects); //this displays all users $sql_find_users = "SELECT * FROM tbl_users WHERE user_id = $user_id"; $find_users = mysql_query($sql_find_users, $makeconnection) or die(mysql_error()); $row_get_users = mysql_fetch_assoc($find_users); $totalRows = mysql_num_rows($find_users); ?> Any help would be great!! Hi there, I am executing this query in the code below, it executes as I want it except when it gets the title, it doesnt get the title for that row it just gets it from the first row in the table... if that makes sense... what is going on? Code: [Select] <?php require'styles/top.php'; ?> <br> <center><table border='0' width='100%' style='text-align:center; font-weight:bold;'> <tr> <td width='33%'>Subject</td> <td width='33%'>From</td> <td width='33%'>Date</td> </tr> </table></center> <br> <?php $query = mysql_query("SELECT * FROM messages WHERE to_user='$username' ORDER BY message_id DESC") or trigger_error('Error: ' . mysql_error()); $numrows = mysql_num_rows($query); if ($numrows > 0){ while ($row = mysql_fetch_assoc($query)){ $id = $row['message_id']; $from = $row['from_user']; $to = $row['to_user']; $title - $row['message_title']; $content = nl2br($row['message_content']); $date = $row['date']; echo"<center><table border='0' width='100%' style='text-align:center; font-weight:bold;'> <tr> <td width='33%'>$title</td> <td width='33%'>$from</td> <td width='33%'>$date</td> </tr> </table></center> <br>"; } } else echo ''; ?> </div> <div id='left'> </div> <div id='right'> </div> Hello... First I should explain what is wrong. I have a database with a table called subs... Within this table I have a unique field called ID, then a fields called member, date(unix timestamp) amount, month, year... HOWEVER for each month and year there is several entries all with different date stamps. How can I extract the entry with the most recent date??? However there is a catch. I want to view payments made since a certain date but only one per month... Below is my code... I thnk I need to add or change something slightly but i am fairly new to PHP and am totally stuck... MANY THANKS IN ADVANCE!!! Code: [Select] [php]$query="SELECT * FROM records WHERE section='B' OR section='C' OR section='S' order by section, surname"; $result=mysql_query($query); for ($row=0;$row<mysql_num_rows($result);$row++){ $forename=mysql_result($result,$row,'forename'); $surname=mysql_result($result,$row,'surname'); $id=mysql_result($result,$row,'id'); $ref="19nx".$id.substr($forename,0,2).substr($surname,0,2); $section=mysql_result($result,$row,'section'); $giftAid=mysql_result($result,$row,'giftAid'); if ($giftAid>1){$day=date('d',$giftAid);$month=date('m',$giftAid);$year=date('y',$giftAid);}else{$day="";$month="";$year="";} $giftAidName=mysql_result($result,$row,'giftAidName'); $giftAidComment=mysql_result($result,$row,'giftAidComment'); $subdate=mktime(0,0,0,$submonth,$subday,$subyear); $query="SELECT * FROM subs WHERE member='$id' AND date>$subdate Order BY id DESC"; $subResult=mysql_query($query); $subs=""; for($ss=0;$ss<mysql_num_rows($subResult);$ss++){ $amount=mysql_result($subResult,$ss,'amount'); if ($amount==""){$amount='25';} $date=date("M/Y",mysql_result($subResult,$ss,'date')); $subs=$subs."<a title='$date' alt='$date'>$amount</a>,"; }[/php] This outputs a line of results which is right except it shows 2 or 3 for april, 3 or 4 for may anthoer 2 or 3 for june etc... I hope someone gets my drift! I am creating a site that has to display 36 images on the screen. The image name is stored in the database. My problem is if I have less than 36 images stored I need to display a default image. here is my current query $sql="SELECT col_image, col_url from tbl_images WHERE col_active='1' and col_bigimage='0' ORDER BY RAND() limit 36"; so If I only have 20 active images. I need to display 16 default images. I hope this makes sense. Bill hi dudes how do i write a mysql query with 3 columns, where the first column is 'year', the second is 'month' (integer) and the third is 'day' (integer), ordered by desc, but with an extra quirk, where if any of the three columns is zero (which means there is no data for that date column - assume i have a year and a month, but no day)? my code looks like the following Code: [Select] ORDER BY exhib_date_year DESC, exhib_date_month DESC, exhib_date_day DESC Hi All, Wondered if someone could help me out with a sql query that I am having difficulty with? My database consists of 3 tables, clients, video, category. The video table stores the primary key value of the clients table and the category table as a foreign key. What I am trying to achieve is return all the videos that are associated to a particular client and group them under the relevant category. If there are now videos that match the category then I do not want to display the category. Here is my code so far: Code: [Select] <?php $sql = "SELECT category.cat_id, category.name AS catname FROM category"; $result = mysql_query($sql) or die (mysql_error()); while($categoryrow = mysql_fetch_assoc($result)) { ?> </p> <div class="themeheader"><h5><?php echo $categoryrow['catname']; ?></h5></div> <Br /> <?php $vsql = "SELECT video.video_id, video.title, video.description, video.thumbnail FROM video WHERE video.cat_id = '" . $categoryrow['cat_id'] . "' AND video.client_id = $customerid ORDER BY video.video_id DESC"; $vresult = mysql_query($vsql) or die (mysql_error()); ?> <div class="videos"> <ul> <?php while($videorow = mysql_fetch_assoc($vresult)) { ?> <li id="categoryList"><a href="film-details.php?video_id=<?php echo $videorow['video_id']; ?>"><img src="+_1m4g35/<?php echo $videorow['thumbnail']; ?>" alt="<?php echo $videorow['title']; ?>" title="<?php echo $videorow['title']; ?>" width="291" height="142" border="0" /></a> <h2><?php echo $videorow['title']; ?></h2> <p><?php $limit = 100; if (strlen($videorow['description']) > $limit) $description = substr($videorow['description'], 0, strrpos(substr($videorow['description'], 0, $limit), ' ')) . '... <a href="film-details.php?video_id='.$videorow['video_id'].'">read more</a>'; echo $description; ?> </p> <?php } //end video loop?> </ul> <br class="clearfloat" /> </div> <?php } //end category loop ?> </div> The above code is the closest I have got but it still outputs the categories even when there are no videos that match the category id and the client id. Any help in the right direction gratefully received as I am gradually going insane! Hello! First post. I am trying to code out a news website (kinda) I can't seem to fetch the news articles out of SQL. What am I doing wrong? (start is fetched by $_REQUEST. Assume it is 1) $end=$start+5; $stories = mysql_query("SELECT * FROM 'stories' DESC ORDER BY id LIMIT $start, $end"); $num = mysql_num_rows($stories); print $num; |
|||||||