PHP - What's Wrong With This Join Query?

I am using two seperate queries to calculate a streak, but the queries must be grouped together to find the actual streak?

Query 1:

SELECT COUNT(matchID) as streak, clan1 FROM webs_cup_matches WHERE ladID='17' AND clan1='2630' AND score1 > score2 AND confirmscore='1' AND einspruch='0' GROUP BY clan1 ORDER BY streak DESC LIMIT 1
Query 2:
SELECT COUNT(matchID) as streak, clan2 FROM webs_cup_matches WHERE ladID='17' AND clan2='2630' AND score1 < score2 AND confirmscore='1' AND einspruch='0' GROUP BY clan2 ORDER BY streak DESC LIMIT 1

is it possible someone can join these queries together?

I was running this query and feel this is slowing down the server:

Code: [Select]
$agent_query=$this->db->query("
                       SELECT u.id,u.name,u.team_id,l.agent_id from users AS u,leads AS l WHERE u.id=l.agent_id AND u.team_id
                        IS NOT   NULL AND u.is_active='1'
ORDER BY u.name ASC
");
Is there a better way to write the above code.

It's been a while since I sat down to build some pages and teach myself php. So now that I've started back up, I'm at a loss for what I've done. I deleted a file, and have to rebuild from an old broken version:

I have a form that submits a query to the database, but the results pages is giving me this error:

Code: [Select]
Oops, my query failed. The query is:
SELECT COUNT 'descriptors'.* ,'plantae'.* FROM 'descriptors' LEFT JOIN 'plantae' ON ('descriptors'.'plant_id' = 'plantae'.'plant_name') WHERE 'leaf_shape' LIKE '%auriculate%' AND 'leaf_venation' LIKE '%%' AND 'leaf_margin' LIKE '%%'
The error is:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.* ,'plantae'.* FROM ' at line 2
But I'm not seeing what the syntax error is.

Here's the code:
Code: [Select]
<?php 
require ('connection.php');

$display = 2;
// it's intentionally only 2 for the moment

if (isset($_GET['np'])) {
   $num_pages = $_GET['np'];
} else { 
$data = "SELECT COUNT
                        'descriptors'.*
                        ,'plantae'.*
                    FROM
                        'descriptors'
                    LEFT JOIN
                        'plantae' ON ('descriptors'.'plant_id' = 'plantae'.'plant_name')
                    WHERE
                        'leaf_shape' LIKE '%$s1%'
                        AND 'leaf_venation' LIKE '%$s3%'
                        AND 'leaf_margin' LIKE '%$s4%'";
$result = mysql_query ($data);

if (!$result) {
    die("Oops, my query failed.  The query is: <br>$data<br>The error is:<br>".mysql_error());
}

$row = mysql_fetch_array($result, MYSQL_NUM);

$num_records = $row[0];

if ($num_records > $display) {
   $num_pages = ceil ($num_records/$display);
} else {
$num_pages = 1;
}
}
if (isset($_GET['s'])) {
   $start = $_GET['s'];
} else {
    $start = 0;
}

if(isset($_POST[submitted])) {
// Now collect all info into $item variable
$shape = $_POST['s1'];
$color = $_POST['s2'];
$vein = $_POST['s3'];
$margin = $_POST['s4'];




// This will take all info from database where row tutorial is $item and collects it into $data variable 

$data = mysql_query("SELECT
                        'descriptors'.*
                        ,'plantae'.*
                    FROM
                        'descriptors'
                    LEFT JOIN
                        'plantae' ON ('descriptors'.'plant_id' = 'plantae'.'plant_name')
                    WHERE
                        'leaf_shape` LIKE '%$s1%'
                        AND 'leaf_venation' LIKE '%$s3%'
                        AND 'leaf_margin' LIKE '%$s4%'
                    ORDER BY 'plantae'.'scientific_name` ASC LIMIT $start, $display");



//chs added this in... 
echo '<table align="center" cellspacing="0" cellpading-"5">
<tr>
<td align="left"><b></b></td>
<td align="left"><b></b></td>
<td align="left"><b>Leaf margin</b></td>
<td align="left"><b>Leaf venation</b></td>
</tr>
';
//end something chs added in 

// This creates a loop which will repeat itself until there are no more rows to select from the database. We getting the field names and storing them in the $row variable. This makes it easier to echo each field.

while($row = mysql_fetch_array($data)){
echo '<tr>
<td align="left"> <a href="link.php">View plant</a> &nbsp; &nbsp;</td>
<td align="left"> <a href="link.php">unknown link</a>&nbsp; &nbsp;</td>
<td align="left">' . $row['scientific_name'] . '</td>
<td align="left">' . $row['common_name'] . '</td>
<td align="left">' . $row['leaf_shape'] . '</td>
</tr>';
}
echo '</table>';
// row 95
}
if ($num_pages > 1) {
echo '<br /><p>';
$current_page = ($start/$display) + 1;
// row 100
if ($current_page != 1) {
echo '<a href="leafsearch2a.php?s=' . ($start - $display) . '&np=;' . $num_pages . '">Previous</a> ';
}

for ($i = 1; $i <= $num_pages; $i++) {
if($i != $current_page) {
echo '<a href="leafsearch2a.php?s=' . (($display * ($i - 1))) . '$np=' . $num_pages . '">' . $i . '</a>';
} else {
echo $i . ' ';
}
}


if ($current_page != $num_pages) {
 echo '<a href="leafsearch2a.php?s=' . ($start + $display) . '$np=' . $num_pages . '"> Next</a>';
}
} 
//added curly
?>

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=313679.0

Is there a cleaner way to do this?

$query = "SELECT branches.Language FROM eua_users, branches WHERE eua_users.AssignedBranch = branches.country" ;
include("dbconnectlocal.php") ;
$result = mysql_query($query) ;

$row = mysql_fetch_object($result) ;

$usrlang = $row->Language ;

$query = "SELECT UserName, Email FROM eua_users WHERE UserName = '$user'" ;
include("dbconnectlocal.php") ;
$result = mysql_query($query) or die(mysql_error());

$row = mysql_fetch_object($result) ;

$branchmail = $row->Email ;

$query = "SELECT $usrlang FROM autoreplies WHERE ReplyID = '0'" ;
include("dbconnectlocal.php") ;
$result = mysql_query($query) or die(mysql_error()) ;

$row = mysql_fetch_object($result) ;

$message = $row->$usrlang ;

$query = "SELECT $usrlang FROM autoreplies WHERE ReplyID = '1'" ;
include("dbconnectlocal.php") ;
$result = mysql_query($query) or die(mysql_error()) ;

$row = mysql_fetch_object($result) ;

$url = $row->$usrlang ;

$query = "SELECT $usrlang FROM autoreplies WHERE ReplyID = '2'" ;
include("dbconnectlocal.php") ;
$result = mysql_query($query) or die(mysql_error()) ;

$row = mysql_fetch_object($result) ;

$subject = $row->$usrlang ;

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=342696.0

I am querying...

$sql  = "SELECT `messages_inbox`.`message_id`, `users`.`firstname`, `users`.`lastname`, `users`.`username` AS `from`, '${user_info['username']}' AS `to`, `subject`, LENGTH(`files`) AS `len`, 'inbox' AS `box`, DATE_FORMAT(`messages_inbox`.`time` ,'%T %D-%M-%Y') AS `time` ";
   
$sql .= "FROM `messages_inbox` INNER JOIN `users` ON `messages_inbox`.`from_id` = `users`.`id` WHERE `to_id` = ${user_info['uid']} AND `messages_inbox`.`deleted` = 0 ORDER BY `messages_inbox`.`message_id` DESC";

and I am trying to output

$displayName = ucwords("${message['firstname']} ${message['lastname']}");

by using

$messages = pm_fetch_all($_GET['box']);

I know my fetch works but for some reason firstname and lastname are only returning the logged in users first name and last name, not the person who sent the message.

hi,

$q = "SELECT `users.id`, `users.username`, `users.firstname`, `users.lastname`, `users.accounttype`, `companies.companyid`, `companies.companyname`, `companies.companyoccupation`, `companies.country`, `companies.state`, `companies.city`, `companies.industry` FROM `users`, `companies` WHERE `users.id` = `companies.companyid`";

Error: Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in /home/www-data/mysite.com/fresh.php on line 25

$sql_form_union = mysql_query("SELECT id, base FROM Match_1v1 WHERE show_id='$show_id' ORDER BY ordered UNION SELECT id, base FROM Segment_1 WHERE show_id='$show_id' ORDER BY ordered");

while ($form_union = mysql_fetch_array($sql_form_union)){

}

My variable `users`.`id` isn't being passed through correctly.


$ms = 'SELECT `messages_inbox`.`from_id`, `messages_inbox`.`subject`, `messages_inbox`.`body`, `messages_inbox`.`files`, `messages_inbox`.`inbox` AS `box`';
$ms.= 'SELECT LEFT `users`.`firstname`, `users`.`lastname`';
$ms.= 'SELECT FROM `messages_inbox` INNER JOIN `users` ON `messages_inbox`.`from_id` = `users`.`id`' or die(mysql(error)); 

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=326252.0

Hey guys,

I have a problem that I find rather strange, but maybe that's just me. I want to output a list of news that is stored in a MySQL database. I have coded paging ($start in the example below), but below I have narrowed my code down and removed code that is not related to the problem. The problem is that my script does not output the first row. That is, if I limit the query below from 0 to the next 10 (LIMIT 0, 10), the result will start at row 2. The same happens if $start is 10; news 12 will be the first one rather than 11. I have tried to put the numbers directly into the SQL query instead of $start, but with the same result. I have tested the query in phpMyAdmin, and the query works fine there. But for some reason, why PHP script does not output the first result. I guess I have made some silly mistake, but at the moment, I do not see it. 


<?php

// Connect to MySQL & select db

$start = 0;

$result = mysql_query("SELECT * FROM Content ORDER BY Time ASC LIMIT $start, 10");

if ($result) {
if (mysql_num_rows($result) > 0) {
$row = mysql_fetch_assoc($result);

while ($row = mysql_fetch_array($result)) {
echo '<div class="someClass">' . $row['title'] . '</div>';
}
}
}

?>

Thanks in advance!

ive looked at this for a while now and im not sure whats wrong, the error occured when i entered $cat and catagory into it, without that the query works perfectly fine, any help appreciated.
<?php
INSERT INTO newnotes (uid, name, catagory, location) VALUES ('1', 'test', '1001 Laws - Polceing', '/home/mikeh/public_html/uzEr Upl0ds/Alyssa O'Leary.doc')
 
the <php tag is only to give color and make it less dull the query is from a die($query) statment

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=347365.0