PHP - Issue With Saving Uploaded Image Twice

Hi everyone, I have a script below, which uplads an image, however, the image name always starts with a capital letter, I want all letters to be small, how to adjust this please, thank you

 

$target_dir = "";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$target_file = "$get_current_user.jpg";


$uploadOk = 1;
$imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));


// Check if image file is a actual image

if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo ""; /// was File is an image
        $uploadOk = 1;
    } else {
        echo "File is not an image<br>";
        $uploadOk = 0;
    }
}


// Check file size

if ($_FILES["fileToUpload"]["size"] > 10000000) {
    echo "Sorry, this image is too large, please resize using Paint<br>";
    $uploadOk = 0;
}

// Allow certain file formats

if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg" && $imageFileType != "gif" ) {
    echo "Only JPG, JPEG, PNG & GIF files are allowed<br>";
    $uploadOk = 0;
}


// Check if $uploadOk is set to 0 by an error

if ($uploadOk == 0) {

    echo "There was an error<br>";


} else {


    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {

       echo "Uploaded successfully (You may need to clear Cache to see the new image)";
	   mysql_query("UPDATE user SET user_image = 'https://.../images/users/$get_current_user.jpg' WHERE user_name = '$get_current_user' ");

    } else {

        echo ""; /// was Select a suitable image, file not uploaded yet

    }

}

 

Hello

I have uploaded images from a server onto a website, they run through a mysql database (database holds the image file names). The problem I am having is resizing the images. Can anyone help?

Thank you in advance

GWG

Not sure if this is the right place to post this.

I have  PHP form that I use to upload a document, PDF or Word Doc, I would also like the form to create a thumbnail of the document when it is uploaded, is this possible?

Hi, I have a script that uploads an image to a directory and then saves the fill path to a field in a table for later use. The only problem is people are uploading huge images and then when I produce a catalogue of my listings it takes forever to load because the images are so big. What I am after is an add in script to create an ADDITIONAL image 100 x 75px, I don't really want to change my upload script. Any ideas? Thanks in advace.

Here is what I have:

Code: [Select]

<?php
$idir = "../fleet/";   // Path To Images Directory


if (isset ($_FILES['fupload'])){

//upload the image to tmp directory
$url = $_FILES['fupload']['name'];   // Set $url To Equal The Filename For Later Use 
if ($_FILES['fupload']['type'] == "image/jpg" || $_FILES['fupload']['type'] == "image/jpeg" || $_FILES['fupload']['type'] == "image/pjpeg") { 
$file_ext = strrchr($_FILES['fupload']['name'], '$account.');   // Get The File Extention In The Format Of , For Instance, .jpg, .gif or .php 
$copy = copy($_FILES['fupload']['tmp_name'], "$idir" . $_FILES['fupload']['name']);   // Move Image From Temporary Location To Perm  
}
}
$fleetimage1 = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']);

//then insert sql code below...
?>

Hey.

I'm just wondering what would be the most logical or most efficient way to save an image resource that has been constructed on say the www. to a subdirectory or on another webserver?

For eg

The script on www.example.com constructs an image using the GD library from image1.png and image2.png.
It has now got the final image resource for what's been constructed.

I now want to save this image onto images.example.com

How would you suggest?

Hey guys!
I have the following php code that grabs variables (and the browsed image) from Flash.


//FLASH VARIABLES
$Name = $_POST['Name'];
$itemNumber = $_POST['itemNumber'];
$filename = $_FILES['Filedata']['name'];
$filetmpname = $_FILES['Filedata']['tmp_name'];
$fileType = $_FILES["Filedata"]["type"];
$fileSizeMB = ($_FILES["Filedata"]["size"] / 1024 / 1000);


list($filename, $extension) = explode('.', basename($_FILES['Filedata']['name']));
$filename = $Name;
$target = $filename . $itemNumber . "." . $extension;


// Place file on server, into the images folder
move_uploaded_file($_FILES['Filedata']['tmp_name'], "images/".$target);



This works perfect, but what I want to change is the width and height of the uploaded image.
Any ideas/suggestions on how this could be done?

Thanks in advance!!
Cheers!

OK,

When the user fills the info in the form out it goes in the DB fine.  I can then array them on the "showroom page" fine.

When they upload a picture it goes into the /images/ folder fine.

Problem is... On each array on the showroom page I need the image they uploaded to be displayed.

Cant work it out.

Help would be GREAT!!!!!

hi to all.Im currently displaying the images from my upload directory but the image does not display.please help thanks

Hi

Basically I've built a CMS where by my clients can upload a number of images. On the success page I want to display the images they uploaded by file name.

The issue is the number of images can vary. They may upload 2 or 10 or 50 etc.

So far I've come up with this:

Code: [Select]
// number of files
$UN = 3; //I've set this to 3 for now, but this is passed from the upload page!

// server directories and directory names
$dir = '../properties';

$images = glob($dir.'/*.{jpg}', GLOB_BRACE); //formats to look for

$num_of_files = $UN; //number of images to display from number of uploaded files

foreach($images as $image)
{
$num_of_files--;

$newest_mtime = 0;
$image = 'BROKEN';
if ($handle = @opendir($dir)) {
while (false !== ($file = readdir($handle))) {
if (($file != '.') && ($file != '..')) {
$mtime = filemtime("$dir/$file");
if ($mtime > $newest_mtime) {
$newest_mtime = $mtime;
$image = "$file";
}
}
}
}

if($num_of_files > -1) //this made me laugh when I wrote it
echo $trimmed = ltrim($image, "../properties").'<br />'; //display images
else
break;
}
Without this piece of code:

Code: [Select]
$newest_mtime = 0;
$image = 'BROKEN';
if ($handle = @opendir($dir)) {
while (false !== ($file = readdir($handle))) {
if (($file != '.') && ($file != '..')) {
$mtime = filemtime("$dir/$file");
if ($mtime > $newest_mtime) {
$newest_mtime = $mtime;
$image = "$file";
}
}
}
}
It shows the first 3 files alphabetically. I want to view the last number of images added.

With the above code it simply shows the last image added 3 times!

So I need to get the time each image was added and then order by the newest added and limit to the number of images uploaded. Any suggestions please?

Kindest regards
Glynn

Hi All,

This is my first post on here. I'd really appreciate any help with this, it's driving me mad.

I'm trying to create a form to save a image into a mySQL database.

I have a website hosted by UK2.net which has a mysql db with a table called gallery(name (varchar 30), size (int), type varchar(30), thePic(mediumBlob)).

I have a form with this:

Code: [Select]
<td><p><label>Pic: </label></td><td><input name="userfile" type="file" id="userfile" /></td></p>
Which when submitted actions addImage.php. The code for this looks like this:

Code: [Select]
<?php


$fileName = $_FILES['userfile']['name'];
$tmpName  = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];

$fp      = fopen($tmpName, 'r');
$content = fread($fp, filesize($tmpName));
$content = addslashes($content);
fclose($fp);

if(!get_magic_quotes_gpc())
{
    $fileName = addslashes($fileName);
}

$con = mysql_connect("localhost", "userName", "password") or die(mysql_error()); 

mysql_select_db("dbName", $con) or die(mysql_error()); 

$query = "INSERT INTO gallery (name, size, type, thePic) ".
"VALUES ('$fileName', '$fileSize', '$fileType', '$content')";

if (!mysql_query($query,$con))
  {
  die('Error: ' . mysql_error());
  }

echo "<br>File $fileName uploaded<br>";


?>
I get the following error message:

Quote

Warning: fopen() [function.fopen]: Filename cannot be empty in /home/hiddenje/public_html/addImage.php on line 13


Does anyone know what this is about? I've been on out friend google and a lot of people seem to be pointing to permissions but I can't seem to apply it to my scenario and just can't get it to work. Im a developer by trade, but this is my first step into the...interesting world of PHP and mySQL.

Again, I'd appreciate any help with this. I'd love someone to talk me through exactly what I'm missing or doing wrong.

Thanks in advance.

I need help making the uploaded image file name, that's chosen to be uploaded, be displayed on the html page with the path /upload/ added to the beginning of the displayed file name like so:
../upload/test.png
Any help/improvements will be appreciated.

<html>
 <head>
  <title>PHP Test</title>
 </head>
  <body>
 <?php
 if ($form_submitted == 'yes') {
 $allowedExts = array("gif", "jpeg", "jpg", "png");
 $temp = explode(".", $_FILES["file"]["name"]);
 $extension = strtolower( end($temp) );
 if (  $_FILES["file"]["size"] < 200000
       && in_array($extension, $allowedExts) )
 {
     if ($_FILES["file"]["error"]!= 0)
     {
         echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
     } else {
         $length = 20;
         move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $newfilename );
         $file_location = '<a href="http://../upload/' . $newfilename . '">' . $newfilename . '</a>';
     }
 } else {
   echo "Invalid upload file";
 }
?>
<label for="file">Filename:</label>
<input type="file" name="file" id="file">
</body>
</html>

I am working on a simple gallery. I want to have an option to download full scale image without users having to right click and "save as". Using this code you get a image preview:

<a href="pictures/img-(1).jpg"><img src="thumbnails/img-(1).jpg"></a>

How can I modify it so when user clicks on thumbnail of image 1 it will prompt him to save the image instead of viewing it.

Thanks

could someone help in how to resize a uploaded image size, say if someone is uploading a 1mb photo to my server, i wish for it to become 100kb and also resize its width and height?

here is my code

Code: [Select]
//////////////////////////////////////uploader
else if($action=="uploader")
{



echo "Upload your picture and copy the link <br/>after uploading to user it at gallery.<br/><br/>";

echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php?action=uploaded&amp;sid=$sid\">";
echo "Choose Pictu <br />";
echo "<input name=\"uploaded\" type=\"file\" /><br /><br />";
echo "<input type=\"submit\" value=\"Upload\" />";
echo "</form><br/>";


echo "<p align=\"center\">";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}


//////////////////////////////////////uploader
else if($action=="uploaded")
{



$blacklist = array(".php", ".php.jpg", ".php.jpeg", ".php.gif", ".php.png", ".phtml", ".php3", ".php4");
foreach ($blacklist as $item) {
if(preg_match("/$item\$/i", $_FILES['uploaded']['name'])) {
echo "<p align=\"center\">";
echo "Oops sorry we do not allow those files.<br/>";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
exit;
}
}

$target = "../images/";
$target = $target . basename( $_FILES['uploaded']['name']) ;
$ok=1;

if (file_exists("../images/" . $_FILES["uploaded"]["name"]))
      {
echo "<p align=\"center\">";
      echo $_FILES["file"]["name"] . "Oops file name already exists<br/> kindly rename your picture and upload again. <br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";   
 }else{

//This is our size condition
if ($uploaded_size > 25600){

echo "Your file is too large. We have a 25kb limit.<br/>";
$ok=0;
}

$types = array('image/jpeg', 'image/gif', 'image/png');

if (in_array($_FILES['uploaded']['type'], $types)) {
// file is okay continue
} else {
$ok=0;
}


//Here we check that $ok was not set to 0 by an error
if ($ok==0){
echo "<p align=\"center\">";
Echo "Sorry your file was not uploaded.<br/> It may be the wrong filetype. <br/>We only allow JPG, GIF, and PNG filetypes.<br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}

//If everything is ok we try to upload it
else{
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){
echo "<p align=\"center\">";

echo "The file ". basename( $_FILES['uploadedfile']['name']). " Picture uploaded successfully.<br/><br/><b>$target <br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}
else{
echo "<p align=\"center\">";

echo "Sorry, there was a problem uploading your file.<br/>";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}
}
}
}

Hello, currently, I got myself a site where you have your own profile and your own 'profile image'. I allow people to upload their own image, and checking my folder, it indeed uploads it correctly.

Now the issue starts when you try to delete your image, again - when deleted the image is deleted in the folder.. However, when then uploading a NEW image, it simply displays the old one (While the new one is actually in the folder!?)

I figured that if you would close the website, and then load it again - it works correctly (figured this means the old image is still loaded in your temp files or something?) Now I was wondering if you could actually somehow *force* the user to re-download this image when you upload a new one.

Thanks for your time!

i have a code that generates a random code and displays it as an image. But the problem the image can be displayed only if it is called before any other output. How do i run it so that it can be displayed after any output..


Code: [Select]

<?
//Security Word for the form

$codelenght = 10;
while($newcode_length < $codelenght) {
$x=1;
$y=3;
$part = rand($x,$y);
if($part==1){$a=48;$b=57;}  // Numbers
if($part==2){$a=65;$b=90;}  // UpperCase
if($part==3){$a=97;$b=122;} // LowerCase
$code_part=chr(rand($a,$b));
$newcode_length = $newcode_length + 1;
$newcode = $newcode.$code_part;
}

header('Content-Type: image/png');
$im = imagecreatetruecolor(200, 40);
$white = imagecolorallocate($im, 255, 255, 255);
$grey = imagecolorallocate($im, 128, 128, 128);
$blue = imagecolorallocate($im, 0, 0, 238);
$black = imagecolorallocate($im, 0, 0, 0);
imagefilledrectangle($im, 1, 1, 200, 40, $white);
$font = '/home/vhosts/master_files/advertising/fonts/arialbd.ttf';
imagettftext($im, 12, 0, 10, 18, $blue, $font, $newcode);
imagepng($im);
imagedestroy($im);

?>