PHP - Open An External Url Without Displaying It To The User? :)
Hi guys
Do you guys know if possible to open an external URL without actually displaying this to the user? We have a service where we wish to open an external URL which triggers sending out an SMS to the user. However..we cannot display the url opened to the user as it shows our username etc with the sms provider. basically the url looks like this: https://www.smsprovider.com/username=OurUsername&password=******&smsMsg_to_send=blablablablabla Is it possible to "trigger" this URL without letting our users see it? Thanks in advance for any help you may provide Similar TutorialsHello! Looking for some advice regarding displaying content from my databases on my members websites via an iframe. Here's what I want to do; Members on my site are rated and reviewed, what I wanted to do was create a piece of code that they could embed on their website to show their reviews. My first instincts where to create an iframe and use the source to pass get variables to my server to identify the member and then use these in a query to select member reviews. Here is the code; For their site; Code: [Select] <iframe frameborder="0" height="250px" width="700px" scrolling="auto" src="http://www.mysite.co.uk/reviews.php?ID=9999&aKey=123456"></iframe> Passes the member ID and a unique access key for that member. The page on my site; (reviews.php) include_once $_SERVER['DOCUMENT_ROOT'] . // path to script files $ID=mysql_real_escape_string($_GET['ID']); $aKey=mysql_real_escape_string($_GET['aKey']); if(empty($aKey) || empty($ID)){ die("Key or ID not set,Selection Error"); exit;} $reviewresult = mysql_query("SELECT Name,Review,Date FROM Reviews WHERE ID='$ID' AND aKey='$aKey' Order by RAND() Limit 10"); //if there is at least one review if($reviewresult && mysql_num_rows($reviewresult) > 0) { while($review = mysql_fetch_array($reviewresult)) { // output reviews } } Are there any security risks with this script? Do you think it is the best method to accomplish what I want? Are there better alternatives? Any suggestions or room for improvement? Thanks! I have hardware setup to preform an action on camera when i enter a url into the address bar. Pretty much you will be able to feed tarantulas. I'd like to setup a button that my user can click that will active the url without being moved off of the current page. I can't figure out how to stop the browser from following the link to a blank page. It messes the whole thing up because the feeder only runs for a second and if you get sent to the blank page and have to navigate back the the live video feed page you could miss the feeding. Thanks for the help I'm working on a light use/kiosk system. I have apache2 and php5 installed on Ubuntu 10.04 and I have the browser open the localhost web page by default. I would like to include a link on this page to open oowriter (open office writer) for the end user on the machine. I've tried Code: [Select] exec('oowriter'); with no luck. I've also tried setting the DISPLAY value before the command like Code: [Select] exec('DISPLAY=:0 oowriter'); with no success. I don't mind have the www-data user in the sudoers file if I have to sudo the command or something, but is this possible to do?? I'm not having any luck at all! i want a code in php to check if user open this page I need help getting user comments from my database and displaying them in a format like you'd see in an online newspaper where each user's comments are displayed one after the other like this... Quote --------------------- By John Doe 8:30 p.m. on Sept 1, 2011 I really liked Debbie's article and encourage others to read it! --------------------- By Sally Peters 11:00 a.m. on Aug 30, 2011 I had the same thing happen to me!! --------------------- Here is the code I have on my "article.php" page below where I generate my Article... Code: [Select] // ********************** // Build Comments Query * // ********************** // Build query. $q = 'SELECT m.first_name, c.created_on, c.body, c.status FROM member AS m INNER JOIN comment AS c ON m.id = c.member_id WHERE article_id=?'; // Prepare statement. $stmt = mysqli_prepare($dbc, $q); // Bind variable. mysqli_stmt_bind_param($stmt, 'i', $articleID); // Execute query. mysqli_stmt_execute($stmt); // Store result-set. mysqli_stmt_store_result($stmt); // **************************** // Check for Comments Record. * // **************************** if (mysqli_stmt_num_rows($stmt)>=1){ // Comment in Database. $commentExists = TRUE; // Bind result-set to variables. mysqli_stmt_bind_result($stmt, $firstName, $createdOn, $body, $status); // Fetch record. mysqli_stmt_fetch($stmt); } Is it correct that mysqli_stmt_store_result($stmt); stores the entire query results? Where does it do that? Some hidden MySQL object in memory? How do I get the query results into a format where I can iterate through each record and display it? Thanks, Debbie Hello, I'm trying to build a registration/login system. I managed to set it up but i need that for the user when he/she is logged in to display his own information and to manage to edit them, First i need to display them, because i seem to not be doing it.. i know it's easy in principal but i am really new at this... So here is my code: The login.php page Code: [Select] <?php include ('database_connection.php'); if (isset($_POST['formsubmitted'])) { // Initialize a session: session_start(); $error = array();//this aaray will store all error messages if (empty($_POST['e-mail'])) {//if the email supplied is empty $error[] = 'You forgot to enter your Email '; } else { if (preg_match("/^([a-zA-Z0-9])+([a-zA-Z0-9\._-])*@([a-zA-Z0-9_-])+([a-zA-Z0-9\._-]+)+$/", $_POST['e-mail'])) { $Email = $_POST['e-mail']; } else { $error[] = 'Your EMail Address is invalid '; } } if (empty($_POST['Password'])) { $error[] = 'Please Enter Your Password '; } else { $Password = $_POST['Password']; } if (empty($error))//if the array is empty , it means no error found { $query_check_credentials = "SELECT * FROM members WHERE (Email='$Email' AND password='$Password') AND Activation IS NULL"; $result_check_credentials = mysqli_query($dbc, $query_check_credentials); if(!$result_check_credentials){//If the QUery Failed echo 'Query Failed '; } if (@mysqli_num_rows($result_check_credentials) == 1)//if Query is successfull { // A match was made. $_SESSION = mysqli_fetch_array($result_check_credentials, MYSQLI_ASSOC);//Assign the result of this query to SESSION Global Variable header("Location: page.php"); }else { $msg_error= 'Either Your Account is inactive or Email address /Password is Incorrect'; } } else { echo '<div class="errormsgbox"> <ol>'; foreach ($error as $key => $values) { echo ' <li>'.$values.'</li>'; } echo '</ol></div>'; } if(isset($msg_error)){ echo '<div class="warning">'.$msg_error.' </div>'; } /// var_dump($error); mysqli_close($dbc); } // End of the main Submit conditional. ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Login Form</title> <style type="text/css"> body { font-family:"Lucida Grande", "Lucida Sans Unicode", Verdana, Arial, Helvetica, sans-serif; font-size:12px; } .registration_form { margin:0 auto; width:500px; padding:14px; } label { width: 10em; float: left; margin-right: 0.5em; display: block } .submit { float:right; } fieldset { background:#EBF4FB none repeat scroll 0 0; border:2px solid #B7DDF2; width: 500px; } legend { color: #fff; background: #80D3E2; border: 1px solid #781351; padding: 2px 6px } .elements { padding:10px; } p { border-bottom:1px solid #B7DDF2; color:#666666; font-size:11px; margin-bottom:20px; padding-bottom:10px; } a{ color:#0099FF; font-weight:bold; } /* Box Style */ .success, .warning, .errormsgbox, .validation { border: 1px solid; margin: 0 auto; padding:10px 5px 10px 60px; background-repeat: no-repeat; background-position: 10px center; font-weight:bold; width:450px; } .success { color: #4F8A10; background-color: #DFF2BF; background-image:url('images/success.png'); } .warning { color: #9F6000; background-color: #FEEFB3; background-image: url('images/warning.png'); } .errormsgbox { color: #D8000C; background-color: #FFBABA; background-image: url('images/error.png'); } .validation { color: #D63301; background-color: #FFCCBA; background-image: url('images/error.png'); } </style> </head> <body> <form action="login.php" method="post" class="registration_form"> <fieldset> <legend>Login Form </legend> <p>Enter Your username and Password Below </p> <div class="elements"> <label for="name">Email :</label> <input type="text" id="e-mail" name="e-mail" size="25" /> </div> <div class="elements"> <label for="Password">Password:</label> <input type="password" id="Password" name="Password" size="25" /> </div> <div class="submit"> <input type="hidden" name="formsubmitted" value="TRUE" /> <input type="submit" value="Login" /> </div> </fieldset> </form> Go Back to <a href="#">Account Verification on sign up</a> </body> </html> This is the page's code where user is redirected after login Code: [Select] <?php ob_start(); session_start(); if(!isset($_SESSION['Username'])){ header("Location: login.php"); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Member Area </title> <style type="text/css"> .success { border: 1px solid; margin: 0 auto; padding:10px 5px 10px 60px; background-repeat: no-repeat; background-position: 10px center; font-weight:bold; width:450px; color: #4F8A10; background-color: #DFF2BF; background-image:url('images/success.png'); } </style> </head> <body> <div class="success">Welcome , <?php echo $_SESSION['Username'] ; ?></div> <? $b = time (); $date1 =date( "Y-m-d;h:i:s" , mktime(date("h")+6, date("i"), date("s"), date("m") , date("d"), date("Y"))); $str_time = "&receivedtimestamp="; $str_msg = "&msg=bkt"; $str_from = "from="; ?> <a href="http://testext.i-movo.com/api/receivesms.aspx?<?echo $str_from;?><?echo $_SESSION['phone'];?><?echo $str_time;?><?echo $date1;?><?echo $str_msg;?>">Get a Cupon</a> </br> <?php echo $_SESSION['Email'] ; ?> </br> <?php echo $_SESSION['phone'] ; ?> <p><strong>My Account</strong></p> <a href="myaccount.php">My Account</a><br> <a href="mysettings.php">Settings</a><br> <a href="logout.php">Logout </a> </body> </html> And finally the database structure is this one ... Code: [Select] CREATE TABLE IF NOT EXISTS `members` ( `Memberid` int(10) NOT NULL AUTO_INCREMENT, `Username` varchar(20) NOT NULL, `Email` varchar(50) NOT NULL, `Password` varchar(10) NOT NULL, `phone` varchar(25) NOT NULL, `Activation` varchar(60) DEFAULT NULL, PRIMARY KEY (`Memberid`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=30 ; Please help me with this because i'm going mad Hi all, I'm new to PHP and just looking for any advice anyone might have on the following problem I'm having. I have created a database and tables for registering and logging in users. Each record has three different User Types (or roles): 1, 2 and 3. Once the session has started, I would like to make certain menu items available to certain User Types. I suppose it is some sort of if...elseif statement such as: <?php if($UserType==1) echo {"<p>Menu1</p>"} elseif($UserType==2) echo {"<p>Menu2</p>"} elseif($UserType==3) echo {"<p>Menu3</p>"}; ?> Would anybody be able to point me in the right direction? I'd really appreciate any help at all. Hi, I got this code which is meant to display the login details of the person that is logged in, however it just displays the details of the last person in the mysql table. I have set up some test logins, so if I login as paul1 the details for paul3 are displayed...confused Anyway, here is the page which displays the details Code: [Select] <?php session_start(); // This checks to make sure the session variable is registered // WARNING: DO NOT DELETE THE FOLLOWING LINE OF TEXT if( isset($_SESSION['username']) && isset($_SESSION['sid'])) { // You are free to edit the following code to suit your requirements include_once("../../data/server.php"); include_once("../../lib/userdata.php"); // THIS BIT WORKS AND DISPLAYS THE USERNAME $data = mysql_query("SELECT * FROM members") or die(mysql_error()); while($info = mysql_fetch_array( $data )) { include("../../lib/userinfo.php"); //////////////////////////////////////////// WARNING: YOU SHOULD NOT EDIT ANYTHING ABOVE THIS LINE //////////////////////////////////////////////////////// ECHO <<<PAGE <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>$siteName</title> <link rel="stylesheet" href="../../userstylesheet.css" type="text/css" /> </head> <div id="page"> <img alt="" src="../../images/leftCurve" height="6" width="6" id="left" /> <img alt="" src="../../images/rightCurve.gif" height="6" width="6" id="right" /> <div id="pageName"> <h1>$siteName</h1> </div> <div id="pageNav"> <div id="sectionLinks"> <a href="profile.php?username=$username">My Profile</a> <a href="modify.php?username=$username">Personal Details</a> <a href="message.php?username=$username">Messages</a> <a href="../../logout.php?username=$username">Logout</a></div> </div> <div id="content"> <div class="feature"> <h2>Welcome $username </h2> <p>This is the demonstration home.html template. You are free to edit this or any of the other templates to suit your own needs. </p> <p>This is the first page your member will see once they have logged in. </p> <p>If you look at the code for this page, you will see that all HTML code is placed between the ***PAGE and PAGE; tags. Please note that the three * should be replaced with the < character. This format must be kept to ensure that the user variables work. Changing this format may result in errors being returned.</p> <p>You may call member information using the $ tag and the variable name eg $ firstname without the space, will show the members first name, such as $firstname</p> <p>For any information please visit our site http://www.membersitemaker.co.uk. User guides will be added shortly and the forum will soon be full of help. </p> </div> </div> <div id="information"> <a href="#">About Us</a> | <a href="#">Site Map</a> | <a href="#">Privacy Policy</a> | <a href="#">Contact Us</a> | ©2011 $siteName </div> </div> </body> </html> PAGE; } //////////////////////////////////////// WARNING: DO NOT DELETE ANYTHING BELOW THIS LINE ////////////////////////////////////////////////////////// } else { // This will redirect the user to the login page if the session variables do not exist header( "Location: ../../../login.html" ); } ?> And here is the code for userdata.php Code: [Select] <?php // Decode sitename function decode_variable(&$siteName) { $siteName = urldecode($siteName); $siteName = str_replace('%20',' ',$siteName); return $siteName; } decode_variable($siteName); // Connnect to MySQL database include_once("../../data/mysql.php"); $mysqlPassword = (base64_decode($mysqlpword)); $db = mysql_connect("$localhost", "$mysqlusername", "$mysqlPassword") or die ("Error connecting to database"); mysql_select_db("$dbname", $db) or die ("An error occured when connecting to database"); // Carry out MySQL query ?> and userinfo.php Code: [Select] <?php $username = $info['username']; $firstname = $info['firstname']; $lastname = $info['lastname']; $address = $info['address']; $town = $info['town']; $county = $info['county']; $postcode = $info['postcode']; $email = $info['email']; $birth_year = $info['birth_year']; $country = $info['country']; $telephone_number = $info['telephone_number']; $mobile_number = $info['mobile_number']; $nickname = $info['nickname']; As always, your help is much appreciated Paul i need to display the fullname and email of the logged in user. <?php session_start(); mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("db_register") or die(mysql_error()); $query = "SELECT` fullname`, `email` FROM `members` WHERE `username`='".$_SESSION['user']."' LIMIT 1"; if($doQuery = mysql_query($query)) { if(mysql_num_rows($doQuery)) { $user = mysql_fetch_assoc($doQuery); print_r($user); } else { echo 'No result returned for the query: '.$query; } } else { echo 'The following query failed: '.$query; } $id = $user['id']; $fullname = $user['fullname']; $email = $user['email']; } ?> <br> Fullname : <?php echo $fullname; ?> <br> Email : <? echo $email; ?> ?> HELP please . Hi all I have some code that displays the high scores for a game. Unfortunately, if a user has more than 1 high score in the table all scores for that user are displayed. I would like to only display the highest score per user. My Current Code Code: [Select] $sql_query = sprintf("SELECT * FROM `highscores` WHERE `gameID` = '106' ORDER BY `score` DESC"); //store the SQL query in the result variable $result = mysql_query($sql_query); if(mysql_num_rows($result)) { //output as long as there are still available fields while($row = mysql_fetch_row($result)) { echo ("$row[3] Scored :$row[5] <br>"); } } //if no fields exist else { echo "no values in the database"; } mysql_close($con); OutPut User1 300 User1 298 User 2 297 User1 296 User3 295 User2 290 I would like the output to be User1 300 User 2 297 User3 295 Any help is much appreciated I'm trying to open a URL using fopen() and I keep getting this error: Code: [Select] Failed to open stream: Permission deniedI can not work out what is wrong, it's not a firewall as far as I can tell. Not to say that this occurs in every php software out there, but I far too occasionally notice that the application is written with scattered php open and close tags, for instance
<?php if(true) ?> <?php { ?> Blah blah blah, because it's true <?php } else { ?> because it's not true <?php } ?>To me, it is extremely irritating. Regardless, I see a lot of open source software written this way and I can't help but think that there must be some underlying reason for it. Magento, for example, is written exactly in this manner. The templates are infested with these opened and closed php snippets. Obscurity is not security so I'm ruling security reasons out. Maybe it is more efficient? -- But I couldn't understand why, if so. It seems like that would put more of a drag on the system itself causing php to start and stop parsing continually and excessively, then again, I'm no expert in the field of memory consumption and other operating system complexities. Honestly, in my opinion, it is stupid. i would never write a program that way.. HEREDOCs are much more useful and eye pleasing than that awful <?php { ?> I had the misfortune a few months ago when I purchased an invoicing/customer maintenance system that I didn't know was written for PHP 5.2 or something lower, one that allowed short tags; and thus short tags were used in the same manner as I've described. Is this just plain disorganization or is there some deep-seated inner lining advantage that I'm not aware of? I would appreciate your assistance, there are tons of login scripts and they work just fine. However I need my operators to login and then list their activities for the other operators who are logged in to see and if desired send their clients on the desired activity. I have the login working like a charm and the activities are listed just beautifully. How do I combine the two tables in the MySQL with PHP so the operator Logged in can only make changes to his listing but see the others. FIRST THE ONE script the member logges in here to the one table in MSQL: <?php session_start(); require_once('config.php'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } $login = clean($_POST['login']); $password = clean($_POST['password']); if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); if($result) { if(mysql_num_rows($result) == 1) { session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: member-index.php"); exit(); }else { header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?> ................................................. ................................ Now I need the person who logged in to the table above to be able to make multiple entries to the table below <? $ID=$_POST['ID']; $title=$_POST['title']; $cost=$_POST['cost']; $activity=$_POST['activity']; $ayear=$_POST['aday']; $aday=$_POST['ayear']; $seats=$_POST['special']; $special=$_POST['seats']; mysql_connect("xxxxxx", "xxx350234427", "========") or die(mysql_error()); mysql_select_db("xxxx") or die(mysql_error()); mysql_query("INSERT INTO `activity` VALUES ('ID','$title', '$cost','$activity', '$aday', '$ayear', '$special', '$seats')"); Print "Your information has been successfully added to the database!" ?> Click <a href="member-profile.php">HERE</a> to return to the main menu <?php ?> hi, i have made a website where people resgister their details of them and products. they have to enter the following details in form Name of company name of the product company address email id password mobile number contact and brief details about their company
user can then login with email id and pwd. now after login ..user will get a page where he can upload the photos of products images and their price, so now my question is that when he finishes uploading (|by clicking on upload button) the product images and price text box ..then on final uploaded webspage it should show all other things which he registerd before (company name , mobile number etc) along with images and price...hence the main question that user does not need to enter mobile and address while uploading images and filling proce ..but on the final page it should show mobile and address along with price and images..as user is not going to enter mobile and address again and again as he will have multiple products to upload.
Actually, what i want to do is to use the email to fetch the $email,$password and $randomnumber from database after Hi, so far I have managed to set up a somewhat basic login website with a mysql database backend. Once they have logged on they go to a "main menu" page. What I need to define is that user A sees button A but only that button, etc. (Then of course that same rule would have to apply if they tried to directly go to the page, but I am guessing I can do that in the same way that I currently do to force a login). If anyone has any tutorials or sample code I would much appreciate it. Thanks, Hi guys, I am trying to put together a little system that allows users to log onto my website and access there own personal page. I am creating each page myself and uploading content specific to them which cannot be viewed by anyone else. I have got the system to work up as far as: 1/ The user logs in 2/ Once logged in they are re-directed to their own page using 'theirusername.php' Thats all good and working how I need it too. The problem I have is this. If I log onto the website using USER A details - I get taken to USER A's page like I should but - If I then go to my browser and type in USERBdetails.php I can then access USER B's page. This cannot happen!! I need for USER A not to be able to access USER B profile - there is obviously no point in the login otherwise! If you are not logged in you obviously cannot access any secure page. That much is working! Please find below the code I am using: LOGIN <?php session_start(); function dbconnect() { $link = mysql_connect("localhost", "username", "password") or die ("Error: ".mysql_error()); } ?> <?php if(isset($_SESSION['loggedin'])) { header("Location:" . strtolower($username) . ".php"); if(isset($_POST['submit'])) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $mysql = mysql_query("SELECT * FROM clients WHERE username = '{$username}' AND password = '{$password}'"); if(mysql_num_rows($mysql) < 1) { die("Password or Username incorrect! Please <a href='login.php'>click here</a> to try again"); } $_SESSION['loggedin'] = "YES"; $_SESSION['username'] = $username; $_SESSION['name'] header("Location:" . strtolower($username) . ".php"); } ?> HEADER ON EACH PHP PAGE <?php session_start(); if(!isset($_SESSION['loggedin'])) { die(Access to this page is restricted without a valid username and password); ?> --------------------------------------------------- Am I right in thinking it is something to do with the "loggedin" part? The system I have here is adapted from a normal login system I have been using for years. The original just checks the details and then does a 'session start'. This one obviously has to re-direct to a user specific page. To do this I used the <<header("Location:" . strtolower($username) . ".php");>> line to redirect to a page such as "usera.php" or "userb.php" Any help would be greatly appreciated! Ta Hi, I am getting frustrated beyond belief at the moment with trying to get a very simple script to run, I am using PHP 5.3.3 and MySQL 5.1 on a Win2k8 server with IIS7.5. Basically my script is connecting to a local database, running a single select query, returning those rows and building up a string from them. The problem is that I am receiving complete BS responses from PHP that the access is denied for the user being specified. This is complete rubbish since the user can connect via mysql, sqlyog, ASP.NET MVC without issue but for some bizarre reason it is not working via PHP. The code for the script is here : Code: [Select] <?php $mysql = mysql_connect('127.0.0.1:3306', 'myuser', 'mypass', 'mydatabase'); if (!$mysql) { die(mysql_error()); $content = "<nobr></nobr>"; } else { $result = mysql_query('SELECT * FROM tblEventGroup'); $content = "<nobr>"; if ($result) { while($row = mysql_fetch_assoc($result)) { $content .= "<span>"; $content .= $row['GroupName']; $content .= "</span>"; $content .= "<a href=\"../Event/EventSearch?groupid="; $content .= $row['GroupId']; $content .= "\" target=\"_blank\">Book here</a> "; } } mysql_close($mysql); $content .= "</nobr>"; } ?> I cannot for the life of me understand what the problem is, the return error is Access denied for user 'myuser'@'localhost' (using password: YES) Hallo everybody,
the user is in the table, but i get error (user not found!).
thank you very much for your help
Rafal
<!DOCTYPE html> <html> <head> <title>index</title> <meta http-EQUIV="CONTENT-LANGUAGE" content="en"> <?php SESSION_START(); include("abc.php"); $link2 = mysqli_connect("$hoster", "$nameuser", "$password", "$basedata") or die ("connection error" . mysqli_error($link2)); $email = $_POST["inp_email"]; $pwd = $_POST["inp_pwd"]; if($email && $pwd) { $chkuser = mysqli_query("SELECT email FROM $table2 WHERE email = '$email' "); $chkuserare = mysqli_num_rows($chkuser); if ($chkuserare !=0) { $chkpwd = mysqli_query("SELECT pwd FROM $table2 WHERE email = '$email'"); $pwddb = mysqli_fetch_assoc($chkpwd); if (md5($pwd) != $pwddb["pwd"]) { echo "Password is wrong!"; } else { $_SESSION['username'] = $email; header ('Location:list.php'); } } else { echo "user not found!"; } } else { echo "enter your Email and Password!"; } mysqli_close($link2); ?> </head> <body style="font-family: arial;margin: 10; padding: 0" bgcolor="silver"> <font color="black"> <br> <form action="index.php" method="post"> <b>Login</b><br><br> <table width="100%"> <tr><td> Email:<br><input type="text" name="inp_email" style="width:98%; padding: 4px;"><br> Password:<br><input type="password" name="inp_pwd" style="width:98%; padding: 4px;"><br> <br> <input type="submit" name="submit" value="Login" style="width:100%; padding: 4px;"> </td></tr> </table> </form> </font> </body> </html> |