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PHP - Building Html Form From Mysql Table
Hi, I have this script which I would like to use to build an html form from a MySQL table.
The <input text................ writes successfully to file but none of the other form types are written to file when using the elseif command Also, I would like this script to carry out the file write foreach row in the table It seems complicated and i am not sure if I am going about it in the right way, but here goes Code: [Select] //// Create Forms from MySQL $result = mysql_query("SELECT * FROM forms"); while($row = mysql_fetch_assoc($result)){ $field_label = $row['field_label']; $column_name = $row['column_name']; $field_type = $row['field_type']; if ($row['field_type'] = 'Text') { $stringData = "$field_label<input type=text name=$column_name>\n"; fwrite($fh, $stringData); } elseif ($row['field_type'] = 'Text Area') { $stringData = "$field_label<input type=textarea name=$column_name></textarea>\n"; fwrite($fh, $stringData); } elseif ($row['field_type'] = 'Select Menu') { $stringData = "$field_label<select name=$column_name></select>\n"; fwrite($fh, $stringData); } elseif ($row['field_type'] = 'Checkbox') { $stringData = "$field_label<input type=checkbox name=$column_name></textarea>\n"; fwrite($fh, $stringData); } fclose($fh); As always, any help is much appreciated Similar Tutorialshello, I am trying to create a form that will log items. Say I have a list of fruits and I want to log the fruit and its color. I don't know how many fruits I have so I need the form to start with one row first then add rows after I hit enter. I then need to insert the fruits into mysql any ideas or links? anyone? Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero I know I'm doing it something right, but can someone tell me why only one table is showing up? Can you help me fix the issue? Heres my code: function showcoords() { echo"J3st3r's CoordVision"; $result=dbquery("SELECT alliance, region, coordx, coordy FROM ".DB_COORDFUSION.""); dbarray($result); $fields_num = mysql_num_fields($result); echo "<table border='1'>"; // printing table headers echo "<td>Alliance</td>"; echo "<td>Region</td>"; echo "<td>Coord</td>"; // printing table rows while($row = mysql_fetch_array($result)) { // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row AS $Cell) echo "<tr>"; echo "<td>".$row['alliance']."</td>\n"; echo "<td>".$row['region']."</td>\n"; echo "<td>".$row['coordx'].",".$row['coordy']."</td>\n"; echo "</tr>\n"; } echo "</table>"; mysql_free_result($result); } I have 2 rows inserted into my coords table. Just frustrated and ignorant to php. I'm a newbie and want to explore on the use of php.I want to create a transcript system but do not know how to go about it.please where should i start from? I have a table in my db with all my menus and submenues of my site, I'd like to show them in some kind of menu containing all of them each entry in db has the columns ID,NAME,TEXT,LEVEL,DEPENDENT level has a value of 1 or 2 depending if it's an item or a subitem dependent has a reference to the id of the section it belongs to Using dreamweaver I created two recordsets based on the level, they are called row_sections (only where level = 1) and row_subsections (only where level = 2) here is the code I tried to use: <?php do { ?> <p><a href="test.php?sec=<?php echo $row_sections['id'];?>"><?php echo $row_sections['name']; ?></a></p> //prints the section text <?php do { ?> <?php if($row_subsections['dependent'] == $row_sections['id']) { echo $row_subsections['name']."<br>"; //tries to print all subitems corresponding to the actual item } ?> <?php } while ($row_subsections = mysql_fetch_assoc($subsections)); ?> <?php } while ($row_sections = mysql_fetch_assoc($sections)); ?> Here's the output: Quote section 1 title subsection 1 subsection 2 section 2 title both section 1 and 2 should have two different subitems.. where is the problem? if I add the line <?php echo $row_sections['id']; ?> right before the second <?php do{ ?> it shows the corresponding ID for BOTH sections so I can't understand the problem... This topic has been moved to Application Design. http://www.phpfreaks.com/forums/index.php?topic=351877.0 There are two pieces to this- The HTML Form and the resulting php. I can't seem to make the leap, from the code to having the form produce the php page so others can view it until the form is again submitted overwriting the php, thus generating new content. The environment I am working in is limited to IIs 5.1 and php 5.2.17 without mySQL or other DB I'm new to php, this isn't homework,or commercialization, it's for children. I am thinking perhaps fwrite / fread but can't get my head around it. Code snipets below. Any help, please use portions of this code in hopes I can understand it Thanks Code snipet from Output.php Code: [Select] <?php $t1image = $_POST["t1image"]; $t1title = $_POST["t1title"]; $t1info = $_POST["t1info"]; $t2image = $_POST["t2image"]; $t2title = $_POST["t2title"]; $t2info = $_POST["t2info"]; ?> ... <tbody> <tr><!--Headers--> <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Animal</td> <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Image thumb<br> </td> <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Date<br> </td> <td style="vertical-align: top; text-align: center; background-color: rgb(204, 255, 255);">Information<br> </td> </tr> <tr> <td style="vertical-align: top; text-align: center;">Monkey </td> <td style="vertical-align: top; text-align: center;"><img src="<?php echo $t1image.'.gif'; ?>"><!--single image presented selected from radio buttons--> </td> <td style="vertical-align: top; text-align: center;"><?php echo date("m/d/Yh:i A"); ?><!--time stamp generated when submitted form populates all fields at once--> </td> <td style="vertical-align: top; text-align: center;"><a href="#monkey" rel="facebox"><?php echo $t1title ?></a><!--Link name provided by "Title 1", that links to hidden Div generated page with content from "Info1" field--> <div id="Monkey" style="display:none"> <?php echo $t1info; ?> </div> </td> </tr> <tr> <td style="vertical-align: top; text-align: center;">Cat<br> </td> <td style="vertical-align: top; text-align: center;"><img src="<?php echo $t2image.'.gif'?>"></td> <td style="vertical-align: top; text-align: center;"><?php echo date("m/d/Yh:i A"); ?></td> <td style="vertical-align: top; text-align: center;"><a href="#Cat" rel="facebox"><?php echo $t2title ?></a> <div id="Cat" style="display:none"> <?php echo $t2info; ?> </div> </td> </tr> <tr> This replicates several times down the page around 15-20 times ( t1### - t20###) Code Snipet from HTML Form Code: [Select] <form action="animals.php" method="post"> <div style="text-align: left;"><big style="font-family: Garamond; font-weight: bold; color: rgb(51, 51, 255);"><big><big><span>Monkey</span></big></big></big><br> <table style="text-align: left; width: 110px;" border="0" cellpadding="2" cellspacing="0"> <tbody><tr> <td style="vertical-align: top;">Image thumb<br> <input type="radio" name="t1image" value="No opinion" checked><img src="eh.gif" alt="Eh"> <input type="radio" name="t1image" value="Ok"><img src="ok.gif" alt="ok"> <input type="radio" name="t1image" value="Like"><img src="like.gif" alt="Like"> <input type="radio" name="t1image" value="Dont"><img src="dont.gif" alt="Don't Like"> <input type="radio" name="t1image" value="Hate"><img src="hate.gif" alt="Hate"> <input type="radio" name="t1image" value="Other"><img src="other.gif" alt="Other"> <br> Why Title:<input type="text" name="t1title" size="45" value="..."/></td> <td style="vertical-align: top;"> Explain:<br> <textarea name="t1info" cols=45 rows=3 value="..."></textarea> </td></tr></table> <br> <!--Next--> How do I get the Form data to save to the php page for others to view? Hi all, I'm new to php/myslq and I'm going crazy trying to figure this one out I'm building a personal calendar and I want to display the data into a HTML table. Code: [Select] //query the database $query = "SELECT * FROM tbl_events WHERE event_day=$day AND event_month=$month AND event_year=$year"; $query = mysql_query($query); //build the table echo '<table>'; for ($y = 0; $y < 6; $y++){ echo '<tr><td>'; //insert the data here echo '</td></tr>'; } echo '</table>'; When I store the events into the database, I assign a slot for each one depending on the hour. I don't want to use more than 6 events daily, hence the for loop. The problem I have is how to I insert the data into the designed <td>? In a particular day I could have only 2 events: event 1 - slot 2, event 2 - slot 6. I want to be able to enter each event into its own cell I hope I'm making myself clear enough. Sorry for any English mistakes if any. Thank you Windows 7, Apache 2.2.21 / PHP 5.3.5. What does the below error mean? I am new and fighting through this particular piece of code. Thank you in advance for your help. Warning: mysql() expects parameter 3 to be resource, string given in C:\website\do_createtable.php on line 3 <? $db_name="booster"; $connection=mysql("localhost", "USERNAME", "PASSWORD") or die (mysql_error()); $db=mysql_select_db($db_name, $connection) or die (mysql_error()); $sql="CREATE TABLE $_POST[table_name] ("; for ($i=0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] != "") { $sql .= " (".$_POST[field_length][$i]."),"; } else { $sql .= ","; } } $sql=substr($sql,0,-1); $sql .= ")"; $result=mysql_query($sql,$connection) or die (mysql_error()); if ($result) { $msg="<P>".$_POST[table_name]." has been created!</P>"; } ?> <HTML> <HEAD> <TITLE>Create a Database Table: Step 3</TITLE> </HEAD> <BODY> <h1>Adding table to <? echo "$db_name"; ?>....</h1> <? echo "$msg"; ?> </BODY> </HTML> Hi everyone. I've two MySQL tables (tbl_csv_input & tbl_qn_types). Table Details: 1. tbl_csv_input (qid, qname, qn_answer, qn_type) Primary Key = qid; Foreign Key = qn_type ref tbl_qn_types qn_type_id 2. tbl_qn_types (qn_type_id, qn_type_name, notes) Primary Key = qn_type_id Sample Data: tbl_csv_input 1 ; Ferrari is the fastest car? ; Yes||No ; T1 2 ; Which below features would you like to have in you... ; Navigator||Airbag||Seat Belt||Camera & Sensors ; T1 3 ; Which model would you prefer? ; CX||MX||SX||LX ; T2 4 ; Comments ; ; T3 tbl_qn_types T1; checkbox; This qn type is used for yes/no T2; radio; Multiple options but only one is correct T3; text area; Users enter input like comments The whole idea is to have a questionnaire displayed in a HTML table depending upon the question types (T1, T2, T3) In simple terms: You have a question and below it there are options. Some questions have check boxes and some have radio buttons and some have text areas. The problem I'm facing is with the column: qn_answer; and column = qn_type. I'm unable to make a loop inside a table which is already in a loop. Please see the attached files (which has the code I've written). TIA. [attachment deleted by admin] I am having so much trouble with this. I want to create a html table that looks like this: Code: [Select] <table id="datatable"> <thead> <tr> <th></th> <th>test</th> <th>test 2</th> </tr> </thead> <tbody> <tr> <th>2011-03-17</th><td>1</td><td>0</td> </tr> <tr> <th>2011-03-18</th><td>3</td><td>2</td> </tr> <tr> <th>2011-03-19</th><td>1</td><td>0</td> </tr> </tbody> </table> out of this mysql result: opens | name | date 1 | test | 2011-03-17 3 | test | 2011-03-18 2 | test 2 | 2011-03-18 1 | test 2 | 2011-03-19 Here is my mysql code: Code: [Select] SELECT count( o.campaign_id ) AS opens, c.name, date(o.created_at) as date FROM opens o LEFT JOIN campaigns c ON c.id = o.campaign_id WHERE (o.created_at between '2011-03-17 00:00:00' and '2011-03-19 23:59:59') GROUP BY date,c.name I also attached a sql dump of my database. So I have a jobs database with the following columns: id, jobtext, jobdate, and id. This is how it looks right now: http://prahan.com/jobs/display.html.php I have another table called author. In the authorid column in need the results of this query, SELECT name FROM author WHERE id = (SELECT authorid FROM job) , to be displayed for each row. I also want to be able to customize the header title for each column. Thanks in advance! I was wondering how does one go about showing results from SELECT query in columns in a html table. I have a list of products in a table, and would like to show them on the page in 4 columns. I have done many searches on google to try and find the sulution, but the majority of what im finding instead is about displaying a table from phpmyadmin as a table in html. If its a large operation to do this, I would be very happy if someone could poiint me in the direction of a tutorial maybe. Here is the code I have so far to display the products, but for some reason, it only show 1 row instead of all the rows from my table. Code: [Select] <?php $dbhost = "localhost"; $dbuser = "user"; $dbpass = "pass"; $dbname = "dbname"; mysql_connect ($dbhost, $dbuser, $dbpass)or die("Could not connect: ".mysql_error()); mysql_select_db($dbname) or die(mysql_error()); $result = mysql_query("SELECT * FROM mcproducts"); while($row = mysql_fetch_array($result)) { $products_local_id = $row['products_local_id']; $productname = $row['product_name']; $thumburl = $row['image_from_url']; $productlink = $row['product_local_url']; $thumbnail = $row['product_image_small']; $currencysymbol = $row['product_currency']; $price = $row['product_price']; $flagicon = $row['product_country_from']; } ?> <html> <head> <link href="style/stylesheet.css" rel="stylesheet" type="text/css" /> </head> <body> <div class="displaybox"> <div class="productimage"> <a href="<?php echo $productlink; ?><?php echo $products_local_id; ?>"><img src="<?php echo $thumburl; ?><?php echo $thumbnail ?>" width="150" height="150"></a> </div> <div class="productdescription"> <div class="pro_name"> <a href="<?php echo $productlink ?><?php echo $products_local_id; ?>"><?php echo $productname; ?></a> </div> <div class="pro_description"> </div> <?php if ($flagicon=="Ireland") { $flagicon = "<img src=\"flags/ireland.jpg\">"; } elseif ($flagicon=="UK") { $flagicon = "<img src=\"flags/uk.jpg\">"; } else echo ""; ?> <div class="pro_description"><?php echo $flagicon; ?><?php echo $currencysymbol ?> <?php echo $price ?></div> </div> </div> </body> </html> Many thanks, DB
Hello, I have the problem that only one user is displayed in the table
require('connection/db1.php');
// Teilnehmerliste
$query = 'SELECT * FROM convoy_part WHERE user_convoy= :I';
$start = $bdd->prepare($query);
$start->execute(array(':I' => $_GET['id']));
//fetch
$result2 = $start->fetch();
// Zählung der Datensätze
$count = $start->rowCount();
<table class="table">
<thead>
<tr>
<th scope="col">User</th>
<th scope="col">Datum</th>
<th scope="col"><a class="btn btn-primary" href="convoy_user.php?id=<?php echo $result['id']; ?>&action=part" role="button">Teilnehmen</a></th>
</tr>
</thead>
<tbody>
<tr>
<th scope="row"><?php echo $result2['name']; ?></th>
<td><?php echo $result2['date']; ?></td>
</tr>
</tbody>
</table>
Hi, I am extracting data from a mysql db to then edit and update back into the db and use below to list items first - Code: [Select] <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); $sql="SELECT * FROM properties"; $result=mysql_query($sql); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td> <table width="400" border="1" cellspacing="0" cellpadding="3"> <tr> <td colspan="4"><strong>List data from mysql </strong> </td> </tr> <tr> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Lastname</strong></td> <td align="center"><strong>Email</strong></td> <td align="center"><strong>Update</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td><? echo $rows['Property_Rating']; ?></td> <td align="center"><a href="update.php?id=<? echo $rows['ID']; ?>">update</a></td> </tr> <?php } ?> </table> </td> </tr> </table> <?php mysql_close(); ?> I then go next page where I show data and allow editing - <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); // get value of id that sent from address bar $id=$_GET['id']; // Retrieve data from database $sql="SELECT * FROM properties WHERE id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="update_ac.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="3"><strong>Update data in mysql</strong> </td> </tr> <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><strong>Property_Name</strong></td> <td align="center"><strong>roperty_Rating</strong></td> <td align="center"><strong>Property_Address</strong></td> </tr> <tr> <td> </td> <td align="center"><input name="Property_Rating" type="text" id="Property_Rating" value="<? echo $rows['Property_Rating']; ?>"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> <? // close connection mysql_close(); ?> And then the update page - <?php // Connect to server and select database. mysql_connect('localhost', 'xxxxxxxxx', 'xxxxxxxxxxxxx') or die("Error: ".mysql_error()); mysql_select_db("xxxxxxxxx"); // update data in mysql database $sql="UPDATE properties SET Property_Name='$Property_Name' WHERE id='$id'"; $result=mysql_query($sql); // if successfully updated. if($result){ echo "Successful"; } else { echo "ERROR"; } ?> Everything seems ok but when I edit the data and submit I get the success message but data not changed in db. Any ideas? Thanks. MOD EDIT: code tags added. hello i have a db with name which populates a form dropdown list there are various variables like this in the form. the user selects their choices and then submits the form to a new db table at the moment it does not capture the dropdown data to the insert sql help please here is the code: =============================== <?php include ('connect.php'); // Insert any new image into database if(isset($_POST['xsubmit']) && $_FILES['imagefile']['name'] != "") { $fileName = $_FILES['imagefile']['name']; $fileSize = $_FILES['imagefile']['size']; $fileType = $_FILES['imagefile']['type']; $content = addslashes (file_get_contents($_FILES['imagefile']['tmp_name'])); $jeweltype = $_POST['jeweltype']; $jewelsize = $_POST['jewelsize_in']; $jewelcolour = $_POST['jewelcolour_in']; $jewelmaterial = $_POST['jewelmaterial_in']; $jewelgender = $_POST['jewelgender_in']; if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } // Checking file size if ($fileSize < 150000) { mysql_query ("INSERT into jewel_images (name,size,type,content,jeweltype,jewelsize,jewelcolour,jewelmaterial,jewelgender) " . "values ('$fileName','$fileSize','$fileType','$content','$jeweltype','$jewelsize','$jewelcolour','$jewelmaterial','$jewelgender')"); } else { $err = "The Image file to too large!"; } } // Find out about latest image $gotten = mysql_query("select * from jewel_images order by row_id desc"); $row = mysql_fetch_assoc($gotten); $bytes = $row['content']; // If this is the image request, send out the image if ($_REQUEST['pic'] == 1) { header("Content-type: $row[type];"); print $bytes; } ?> <html> <head> <title>Upload an image to a database</title> </head> <body> <font color="#FF3333"><?php echo $err ?></font> <table> <form name="Upload" enctype="multipart/form-data" method="post"> <tr> <td>Upload <input type="file" name="imagefile"><br /> Jewelery Type: <select> <?php $sql="SELECT jeweltype FROM jeweltypes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jeweltype" ><?php echo $data['jeweltype'] ?></option> <?php } ?> </select> <br /> Jewelery Size: <select> <?php $sql="SELECT jewelsize FROM jewelsizes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelsize" ><?php echo $data['jewelsize'] ?></option> <?php } ?> </select> <br /> Jewelery Colour: <select> <?php $sql="SELECT jewelcolour FROM jewelcolours"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelcolour_in" ><?php echo $data['jewelcolour'] ?></option> <?php } ?> </select> <br /> Jewelery Material: <select> <?php $sql="SELECT jewelmaterial FROM jewelmaterials"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelmaterial_in" ><?php echo $data['jewelmaterial'] ?></option> <?php } ?> </select> <br /> Jewelery Gender: <select> <?php $sql="SELECT jewelgender FROM jewelgenders"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelgender_in" ><?php echo $data['jewelgender'] ?></option> <?php } ?> </select> <br /> <input type="submit" name="xsubmit" value="Upload"> </td> </tr> <tr> <td>Latest Image</td> </tr> <tr> <td><img src="?pic=1"></td> </tr> </form> </table> </body> </html> Need a little help with this code. I'm running Apache 2.21 / PHP 5.3.5 on Windows. This is a V6 application. I am running Windows 7. I am new, and trying to learn. What am I doing wrong in line 8 with the 'if' statement? The idea is to create a table in mySQL using a form interface. Thank you in advance. Parse error: syntax error, unexpected '{' in C:\website\do_createtable.php on line 8 <? $db_name="booster"; $connection=mysql("localhost", "user", "password") or die (mysql_error()); $db=mysql_select_db($db_name, $connection) or die (mysql_error()); $sql="CREATE TABLE $_POST[table_name] ("; for ($i=0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] != "" { $sql .= " (".$_POST[field_length][$i]."),"; } else { $sql .= ","; } } $sql=substr($sql,0,-1); $sql .= ")"; I'm not sure if my problem is with the PHP, MySQL, HTML, or all of the above, but I've used a tutorial from ScriptPlayground (http://scriptplayground.com/tutorials/php/Printing-a-MySQL-table-to-a-dynamic-HTML-table-with-PHP/) to print a table to HTML. My problem isn't that I couldn't get it to work, as you can see from my site, http://dollapal.com/offerlist.php I've used the code on my site, trying to display a list of offers, with links to each, but I actually have two questions: Is there a way to EXCLUDE columns of the table? I would rather not show the 'id' or 'points' columns, since they don't offer any worth to the user. I would also need to hopefully add a dollar sign before the 'pay' quantities if possible. I would also like use the 'title' field as a hyperlink to the URL listed in the 'URL' field, instead of simply printing the URL. Are there any simple ways to do this and not have it look terrible? I have included a copy of the script that I'm working with so far. Thank you in advance! Hello I have an array with data from `mysql` that I would like to output it in a table using twig. The image is an example of want i want to achieve but without any luck. `print_r` of the array data Array ( [Administrator] => Array ( [0] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-View [PermissionId] => 1 ) [1] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-Edit [PermissionId] => 2 ) [2] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-Delete [PermissionId] => 3 ) ) [Moderator] => Array ( [0] => Array ( [RoleName] => Moderator [PermissionName] => Catalog-View [PermissionId] => 1 ) ) ) The `HTML` code:
<table>
<tr>
<thead>
<th>Controller - Action</th>
{% for permission in permissions %}
{% for item in permission %}
<th>{{item.RoleName}}</th>
{% endfor %}
{% endfor %}
</thead>
</tr>
{% for permission in permissions %}
{% for item in permission %}
<tr>
<td>{{item.PermissionName}}</td>
<td>{{item.PermissionId}}</td>
</tr>
{% endfor %}
{% endfor %}
</table>
OUTPUT: <table> <tbody> <tr></tr> </tbody> <thead> <tr> <th>Controller - Action</th> <th>Administrator</th> <th>Administrator</th> <th>Administrator</th> <th>Moderator</th> </tr> </thead> <tbody> <tr> <td>Catalog-View</td> <td>1</td> </tr> <tr> <td>Catalog-Edit</td> <td>2</td> </tr> <tr> <td>Catalog-Delete</td> <td>3</td> </tr> <tr> <td>Catalog-View</td> <td>1</td> </tr> </tbody> </table> Later Edit MySQL Query: SELECT t3.PermissionName, t1.PermissionId, t2.RoleName FROM tbl_user_role_perm AS t1 INNER JOIN tbl_user_roles AS t2 ON t1.RoleId = t2.RoleId INNER JOIN tbl_user_permissions AS t3 ON t1.PermissionId = t3.PermissionId MySQL Dump: -- Dumping structure for table tbl_user_permissions CREATE TABLE IF NOT EXISTS `tbl_user_permissions` ( `PermissionId` int(11) NOT NULL AUTO_INCREMENT, `PermissionName` varchar(50) NOT NULL, `PermissionDescription` varchar(100) NOT NULL, PRIMARY KEY (`PermissionId`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1; -- Dumping data for table tbl_user_permissions: ~2 rows (approximately) DELETE FROM `tbl_user_permissions`; /*!40000 ALTER TABLE `tbl_user_permissions` DISABLE KEYS */; INSERT INTO `tbl_user_permissions` (`PermissionId`, `PermissionName`, `PermissionDescription`) VALUES (1, 'Catalog->View', 'View Catalog Method'), (2, 'Catalog->Edit', 'Edit Catalog Method'), (3, 'Catalog->Delete', 'Delete Catalog Method'); /*!40000 ALTER TABLE `tbl_user_permissions` ENABLE KEYS */; -- Dumping structure for table tbl_user_role CREATE TABLE IF NOT EXISTS `tbl_user_role` ( `UserRoleId` int(10) NOT NULL AUTO_INCREMENT, `UserId` int(10) NOT NULL, `RoleId` int(10) unsigned NOT NULL, PRIMARY KEY (`UserRoleId`), KEY `FK_tbl_user_role_tbl_user_roles` (`RoleId`), KEY `UserId` (`UserId`) ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1; -- Dumping data for table tbl_user_role: ~2 rows (approximately) DELETE FROM `tbl_user_role`; /*!40000 ALTER TABLE `tbl_user_role` DISABLE KEYS */; INSERT INTO `tbl_user_role` (`UserRoleId`, `UserId`, `RoleId`) VALUES (1, 13, 22), (2, 14, 22); /*!40000 ALTER TABLE `tbl_user_role` ENABLE KEYS */; -- Dumping structure for table tbl_user_roles CREATE TABLE IF NOT EXISTS `tbl_user_roles` ( `RoleId` int(10) unsigned NOT NULL AUTO_INCREMENT, `RoleName` varchar(50) NOT NULL, `CreatedDate` datetime NOT NULL, `ModifiedDate` datetime DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP, PRIMARY KEY (`RoleId`) ) ENGINE=InnoDB AUTO_INCREMENT=29 DEFAULT CHARSET=utf8; -- Dumping data for table tbl_user_roles: ~7 rows (approximately) DELETE FROM `tbl_user_roles`; /*!40000 ALTER TABLE `tbl_user_roles` DISABLE KEYS */; INSERT INTO `tbl_user_roles` (`RoleId`, `RoleName`, `CreatedDate`, `ModifiedDate`) VALUES (22, 'Administrator', '2014-10-28 09:53:08', NULL), (23, 'Moderator', '2014-10-28 09:53:13', NULL), (24, 'Admin', '2014-10-28 12:22:05', '2014-10-28 12:22:06'), (25, 'User', '2014-10-29 15:10:36', '2014-10-29 15:10:37'), (26, 'SuperUser', '2014-10-29 15:10:45', '2014-10-29 15:10:46'), (27, 'Accountant', '2014-10-29 15:10:53', '2014-10-29 15:10:54'), (28, 'God', '2014-10-29 15:11:02', '2014-10-29 15:11:02'); /*!40000 ALTER TABLE `tbl_user_roles` ENABLE KEYS */; -- Dumping structure for table tbl_user_role_perm CREATE TABLE IF NOT EXISTS `tbl_user_role_perm` ( `RoleId` int(10) unsigned NOT NULL, `PermissionId` int(10) unsigned NOT NULL, KEY `RoleId` (`RoleId`), KEY `PermissionId` (`PermissionId`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; -- Dumping data for table tbl_user_role_perm: ~3 rows (approximately) DELETE FROM `tbl_user_role_perm`; /*!40000 ALTER TABLE `tbl_user_role_perm` DISABLE KEYS */; INSERT INTO `tbl_user_role_perm` (`RoleId`, `PermissionId`) VALUES (22, 2), (22, 1), (23, 1), (22, 3); /*!40000 ALTER TABLE `tbl_user_role_perm` ENABLE KEYS */; /*!40101 SET SQL_MODE=IFNULL(@OLD_SQL_MODE, '') */; /*!40014 SET FOREIGN_KEY_CHECKS=IF(@OLD_FOREIGN_KEY_CHECKS IS NULL, 1, @OLD_FOREIGN_KEY_CHECKS) */; /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;Can you help me to make the coding required so that the correct column have the correct permissions? thank you in advance. I have the following code that searches my database and displays results in a table: $fields = array("field1", "field2", "field3") $cols = implode (', ', $fields); $result= mysql_query (" SELECT $cols FROM tablename WHERE ................... "); if (!$result) {die('Could not search database: ' . mysql_error());} if($result) { if(mysql_num_rows($result) == 0) { return "Sorry. No records found in the database"; } else { $table = "<table border='1' cellpadding='5' cellspacing='5'>"; while($arr = mysql_fetch_array($result, MYSQL_ASSOC)) { $table .= "\t\t<tr>\n"; foreach ($arr as $val_col) { $table .= "\t\t\t".'<td>'.$val_col.'</td>'."\n"; } $table .= "\t\t</tr>\n"; } $table .= "</table>"; echo $table; } mysql_free_result($result); } As you can see each of the MySQL table fields specified by $fields is displayed in a new column in the html table. I want to change this so that e.g. "field3" is displayed in a new row instead. So, instead of the html table looking like: | "field1-result1" | "field2-result1" | "field3-result1" | | "field1-result2" | "field2-result2" | "field3-result2" | | "field1-result3" | "field2-result3" | "field3-result3" | I want it to look like: | "field1-result1" | "field2-result1" | | "field3-result1" | | | "field1-result2" | "field2-result2" | | "field3-result2" | | | "field1-result3" | "field2-result3" | | "field3-result3" | | I guess this is quite straightforward, but I can't work it out! Pls help! Thanks. |
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