PHP - How To Check If A $byte_array Contains Data?
I have two questions regarding $byte_array.
1. Is there a general way to check if a $byte_array contains any data? 2. Is there a way to confirm if the $byte_array contains an actual PNG image? Similar TutorialsHey Folks! So, my brain is hurting now... I am making a little process to go through a table and if a row as one set of data, and the next row as the same data based on 3 fields then update a field in the current row. Here is a snippet of what I have been working on: <?php date_default_timezone_set('AUSTRALIA/BRISBANE'); $lasthour = (time() - 3600); $lastattack45 = (time() - 2820); $lasthalfhour = (time() - 1800); $lastfifteen = (time() - 900); $lastfhourhalf = (time() - 5400); $next15 = (time() + 900); $now = time(); mysql_connect($mysql_host, $mysql_user, $mysql_password) or die('Error connecting to mysql'); mysql_select_db($mysql_database); $result = mysql_query("SELECT feeder, attacker, defender, attacklandunix, smurfid, smurf, unixtime, record, leader FROM nation_incoming WHERE attacklandunix > $now && smurf <> 'smurfed' ") or die("SELECT Error: ".mysql_error()); while($row = mysql_fetch_array($result)){ $a[][feeder] = $row['feeder']; $a[][defender]= $row['defender']; $a[][landing]= $row['attacklandunix']; } foreach($a as $b){ //in here it is to compare the 'feeder' && 'defender' && 'attacklandunix' to the next row. IF the same combo exists, then update field 'leader' to "0". else update 'leader' to "1" } ?> How can/should I pull up the next row? Hi Guys, Im using the code below to display the value of checked checkboxes on form submission, however im also trying to pull the price from the database for each checked value. foreach ($_POST['check'] as $product) { echo $row['price'] . " " . $row['currency'] . " for " . $product . "<br />"; } Please could somebody point me in the right direction as to what id need to do. As iv only been able to get it to display the price of the first checked value. Thanks Hey Guys, I have got 3 chained select boxes working. Basically what you do is check for a region with the country, then once you pick a region, you select a club within that region. Once you have selected the club, you can then choose a team from within that club. Screenshot: Attchment As part of this chained select boxes's, a user can register. Although, the user has to FIRST check if the TEAM has already been registered in the database. I have taken a screenshot of my database, which shows the regions, clubs, and teams from the chained select boxes. What i want to do now is be able to check if a TEAM is already registered in the database. So as you can see in the database, the team 'NPOB, Senior As' has already been taken. Database Screenshot: Attachment *** How do i check if a user has been registered to one of the teams? And if there is not a registered user to that team, they can then register it. Here is my code: <?php include"database.php"; ?> <script type="text/javascript"> /* Triple Combo Script Credit By Philip M: http://www.codingforums.com/member.php?u=186 Visit http://javascriptkit.com for this and over 400+ other scripts */ var categories = []; categories["startList"] = ["Taranaki","Auckland"] // Regions + Clubs categories["Taranaki"] = ["NPOB","Tukapa"]; categories["Auckland"] = ["Marist","Takapuna"]; // Clubs + Teams within that Club categories["NPOB"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Tukapa"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Marist"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Takapuna"] = ["Senior As","Senior Bs","Colts U21s"]; var nLists = 3; // number of select lists in the set function fillSelect(currCat,currList){ var step = Number(currList.name.replace(/\D/g,"")); for (i=step; i<nLists+1; i++) { document.forms['tripleplay']['List'+i].length = 1; document.forms['tripleplay']['List'+i].selectedIndex = 0; } var nCat = categories[currCat]; for (each in nCat) { var nOption = document.createElement('option'); var nData = document.createTextNode(nCat[each]); nOption.setAttribute('value',nCat[each]); nOption.appendChild(nData); currList.appendChild(nOption); } } // function getValue(L3, L2, L1) { // alert("Your selection was:- \n" + L1 + "\n" + L2 + "\n" + L3); // } function init() { fillSelect('startList',document.forms['tripleplay']['List1']) } navigator.appName == "Microsoft Internet Explorer" ? attachEvent('onload', init, false) : addEventListener('load', init, false); </script> <form name="tripleplay" action="testingdropdown.php" method="post"> <select name='List1' onchange="fillSelect(this.value,this.form['List2'])"> <option selected>Choose Region</option> </select><br /><br /> <select name='List2' onchange="fillSelect(this.value,this.form['List3'])"> <option selected>Choose Club </option> </select><br /><br /> <select name='List3' onchange="getValue(this.value, this.form['List2'].value, this.form['List1'].value)"> <option selected >Choose Team </option> </select> <input type="submit" name="tripleplay" value="Register"> </form> <?php if (isset($_POST['tripleplay'])) { $region = addslashes(strip_tags($_POST['List1'])); $club = addslashes(strip_tags($_POST['List2'])); $team = addslashes(strip_tags($_POST['List3'])); $email = 'email'; $check = mysql_query("SELECT * FROM managers WHERE email='$email'"); if ($email == '') { echo "You can register that club"; } else { echo "Sorry that team has already been registered"; } } ?> Hi guys, I'm recent working on my php to add the row in mysql database. I need a bit of your help as I would like to know how to check the data in mysql database if it have added in mysql and then print it out without adding another same row? here's the current code: Code: [Select] <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbuser'); define('DB_PASSWORD', 'mydbpass'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $pass = clean($_GET['pass']); $login = clean($_GET['login']); $all = clean($_GET['all']); if($username == '' && $pass == ''){ // both are empty $errmsg_arr[] = 'Username and password are missing. You must enter both or the other one.'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $insert = array(); if(isset($_GET['user'])) { $insert[] = 'username = \'' . clean($_GET['user']) .'\''; } if(isset($_GET['pass'])) { $insert[] = 'pass = \'' . clean($_GET['pass']) . '\''; } if(isset($_GET['login'])) { $insert[] = 'LoggedUser = \'' . clean($_GET['login']) . '\''; } if(isset($_GET['all'])) { $insert[] = 'all = \'' . clean($_GET['all']) . '\''; } if (count($insert)>0) { $names = implode(',',$insert); if($username) { $qrytable1="SELECT username, LoggedUser FROM Online_Users WHERE username='$username'"; $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error()); while ($row = mysql_fetch_array($result1)) { echo "<p id='LoggedUser'>"; echo $row['LoggedUser'] . "</p>"; } } if($username && $login == '1') { $sql="INSERT INTO Online_Users (username, LoggedUser) VALUES ('$_GET[user]','$_GET[login]')"; $result = mysql_query($sql); if($result) { $qrytable1="SELECT username, LoggedUser FROM Online_Users WHERE username='$username'"; $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error()); while ($row = mysql_fetch_array($result1)) { echo "<p id='LoggedUser'>"; echo $row['LoggedUser'] . "</p>"; } } } elseif($username == 'all') { $names = implode(',',$insert); $result = mysql_query("SELECT * FROM Online_Users") or die('Error: ' . mysql_error()); $num_rows = mysql_num_rows($result); echo "There are $num_rows Users Online right now"; } } } ?> hi guys, in my form i need to insert an ID which is 5 digits number only. can anyone please tell me how can i check this before i insert? and also i need to check existing ID in my database. Hello. I want to check if an e-mail address is stored into a database. I've found this type of code: Code: [Select] function verifmail($email) { db_connect(); if (mysql_num_rows(mysql_query("SELECT email FROM users WHERE email='$email';"))) { return 1; } else { return 0; } } Is it correct ? Is there any other way? Hi, I have multiple table Table -1 order_no name 1 raj table -2 order_no name 1 raj table 3 order_no name 1 raj table 4 order_no name 1 raj table 5 order_no name 1 raj I want a query to check if the id (one) is present in all tables or not, i create this. select order_no from prepress, press, postpress, qc, binding, dispatch where order_no=prepress.order_no AND order_no=press.order_no AND order_no=postpress.order_no AND order_no=qc.order_no AND order_no=binding.order_no AND order_no=dispatch.order_no but the ambiguous error for order_no. how to achieve this can anyone suggest me? thanks hi all, I have an array(1,2,3,4) and i make a form and make checkboxes for this array and user selects 2,3 and 4 when user submit form then i save it in table by making selected check boxes and converting selected values into bitwise equivalent value like this foreach($data['meal_types'] as $v){ $mealTypeBits += pow(2,$v-1); } Now when i have to show user his selected data how will i compare table bitwise saved record with array(1,2,3,4) to get the values that he checked while saving. //database create table mydata ( id int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT, fname varchar(20), phoneno int(12) NOT NULL /*......*/ ); //class my data php <?php include('connect.php'); class InsertMydata { public function insertnow($fname, $phoneno) { $connect = new Connect; $insrt = $db -> prepare('INSERT INTO mydata (fname, phoneno) VALUES (?,?)'); $insrt -> execute(array($fname, $phoneno)); } } ?> //insernow validate form <?php include('../classs/mydata.php'); //Declare data and error arrays $errors = []; $mydara = []; if(!preg_match('/^[a-zA-Z]{4,15}$/', $_POST['fname'])) { $errors['fname'] = 'Enter full name!'; } //this block not working even the phone exist $connect = new Connect; $phoneno = $_POST['phoneno']; $checkiexist = $connect -> prepare('SELECT * FROM mydata WHERE phoneno = ?'); $checkiexist -> execute([$phoneno]); if($checkiexist->rowCount() > 0) { $errors['phonenoexist'] = 'Try another phone number!'; } if(!empty($errors)){ $data['success'] = false; $data['errors'] = $errors; }else{ $data['success'] = true; $data['message'] = 'success message!'; $mydata = new InsertMydata; $mydata -> insertnow($fname, $phoneno); } echo json_encode($data); ?> //my ajax $("#insertbtn").click( function(e) { var fname = $('#fname').val(), phoneno = $('#phoneno').val(), $.ajax({ url: 'insertnow.php', type: 'POST', data: {fname:fname, phoneno:phoneno}, dataType: "JSON", encode: true, }).done( function (data) { if (data.success == false) { if (data.errors.fname) { $('#fname').append('<p class="text-danger">' + data.errors.fname + '</p>'); } if (data.errors.phonenoexist) { $('.card-header').append('<div class="alert alert-info alert-dismissible" role="alert"> <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.errors.phonenoexist+'</div>'); } } else { $('.card-header').append('<div class="alert alert-success alert-dismissible" role="alert"><button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.message+'</div>'); } }); e.preventDefault(); }); //the problem is, the code insert data even if the phone exist why? the problem is, the code insert data even if the phone exist why? Edited April 8 by mahendaHi guys, im inserting data into the table using drop-down list & multi select list,well it works very well. but i need to make sure i should not insert same StudentID & CourseID twice. here my code for you could anyone tell me pls where should i write code to check existing data? <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("uni", $con)or trigger_error('MySQL error: ' . mysql_error()); $result = mysql_query("SELECT * FROM student") or trigger_error('MySQL error: ' . mysql_error()); echo '<select name="sid">'; while($row = mysql_fetch_array($result)) { echo '<option value="' . $row['StudentID'] . '">' . $row['StudentName'] . '</option>'; } echo '</select>'; // ---------------- ?> </div> <div class="style41" id="Layer7"> <?php $result = mysql_query("SELECT * FROM course") or trigger_error('MySQL error: ' . mysql_error()); echo '<select name ="cid[]" multiple="multiple" size="10">'; while($row = mysql_fetch_array($result)) { echo '<option value="' . $row['CourseID'] . '">' . $row['CourseName'] . '</option>'; } echo '</select>'; mysql_close($con); ?> ------------------------------------ <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("uni", $con)or trigger_error('MySQL error: ' . mysql_error()); if (!empty($_POST['sid']) && !empty($_POST['cid'])) { $ct = 0; $student = $_POST['sid']; foreach ($_POST['cid'] as $key => $course) { $sql = "INSERT INTO take (StudentID, CourseID) VALUES('".mysql_real_escape_string($student)."', '".mysql_real_escape_string($course)."')"; $query = mysql_query($sql) or trigger_error('MySQL error: ' . mysql_error()); if (mysql_affected_rows() > 0){$ct++;} } echo $ct . ' rows added.'; } mysql_close($con); ?> Hi guys Can someone help me about this: The php code can be revise username and password with CURL then check database and if username & password is correct return true else false. Thanks Hey! I have it so users can submit info to my site. They have to check some check boxes and radio buttons. I want them to be able to edit this information, so I want to have the data pulled from the MySQL database and have the correct radio button selected (and the text bolded). So I'm thinking some sort of array to check for each value in the database... but I don't really know. There are a few groups of radio boxes and check boxes but here is an example of one. Code: [Select] <input type="radio" name="stage" value="Stage 1" /> Stage 1 <input type="radio" name="stage" value="Stage 2" /> Stage 2 <input type="radio" name="stage" value="Stage 3" /> Stage 3 The information is pulled from the database like this: Code: [Select] $res=mysql_query("SELECT * FROM ACTIVE WHERE INDEX_ID=$id"); if(mysql_num_rows($res)==0) echo "There is no data in the table <br /> <br />"; else { for($i=0;$i<mysql_num_rows($res);$i++) { $row=mysql_fetch_assoc($res); } } So when I pull information (lets say I want to echo it) it'd look like this: Code: [Select] $row[STAGE] The value for the stage selection can only be Stage 1, Stage 2 or Stage 3 so I need it to be selected when the page loads. Thanks! Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.
<?php $con = mysqli_connect("localhost","user","password","part_inventory"); // Check connection if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } else { $result = mysqli_query($con, "SELECT * FROM amp20 "); $amp20ptid = $_POST['amp20ptid']; // escape variables for security $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']); mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'"); if (!mysqli_query($con, $amp20ptid)); { die('Could not delete data: ' . mysqli_error($con)); } echo "Part has been deleted to the database!!!\n"; mysqli_close($con); } ?> Scenario :
I would like to open the main program window and at the same time, if a condition is met, open a second - popup window to alert the user of previous information stored in the database.
This is an easy exercise if I use a hyperlink to open th second (popup) window but this is not the process required .
Can someone point me in the right direction ?
Cheers and thanks
Am new here - looks like a great foru! I would sincerely appreciate any help anyone can give me. I have been trying to solve my problem for hours and I am not having any luck, so I thought I would post and see if anyone can help. I am very stuck and am not making much progress on this project, and I am certain the answer is very simple. I am constructing a form to collect data for a specialized purpose. The form and program actually work for its intended function, but I am trying to enhance the user experience by preventing customers from having to reenter all of their data should there be a problem with any of the data submitted. I have been able to do that with the contact form portion, but what I am having trouble with is the portion which has as many as 400 possible entries. So, in a nutshell, if the customers contact data is incomplete or in error, the form will ask them to return to the page and correct things. The previous data entered has been saved in the session and the input value will equal the previous entry. i.e. <tr> <td align="right" class="infoBox"><?php echo ENTRY_EMAIL_ADDRESS; ?></td> <td align=left><?php echo "<input type=text name='cemail' value=\"$cemail\" size=35 maxlength=35>" ?></td> </tr> Works perfectly, all well and good there. On the other 400 more or less entries, I am having a difficult time tweaking the string concatenation to work to achieve similar results. There are 4 columns each with $points entries asking for a dimension in either feet or inches. The <input name=> is one of ptaf,ptai,ptbf,ptbi, appended programatically with the corresponding row number or data point. i.e. "ptaf1", "ptai1", etc... This is produced by the example below and works perfectly also. <?php { $points=100; $i=1; while ($i <= $points) {echo ' <tr><td align="center" width="6"><b> ' .$i . '</b></td> <td align="right" NOWRAP>A' .$i . ' (ft) <input type="text" name="ptaf'.$i.'" size=4 maxlength=3> </td> <td align="right" NOWRAP>A' .$i . ' (in) <input type="text" name="ptai'.$i.'" size=4 maxlength=4> </td> <td align="right" NOWRAP>B' .$i . ' (ft) <input type="text" name="ptbf'.$i.'" size=4 maxlength=3> </td> <td align="right" NOWRAP>B' .$i . ' (in) <input type="text" name="ptbi'.$i.'" size=4 maxlength=4> </td> '; $i++; } } ?> I am trying to add <input value=$ptai.$i> for each field but as I mentioned I am not having any luck. It seems as if I have tried every combination imagineable, but still no luck. My head is spinning! The closest I seem to have gotten was with this: <td align="right" NOWRAP>A' .$i . ' (ft) <input type="text" size=6 maxlength=3 name="ptaf'.$i.'" value="' . "$ptaf" . $i . '" ></td> But line 17 for example returns this: <input type="text" value="17" name="ptaf17" maxlength="3" size="6"> To recap, I am trying to have the value set to whatever the customer may have entered previously. Again, I would most appreciate any help anyone can give me. If you need clarification on anything please let me know. Thanks AJ Hello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php while($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo ' <tr> <td>'.$row["id"].'</td> '; while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) { echo ' <td>'.$row1["email"].'</td> '; } if($row["validity"] == 1) { echo '<td>'.$row["validity"].' month</td>'; }else{ echo '<td>'.$row["validity"].' months</td>'; } echo ' <td>'.$row["valid_from"].'</td> <td>'.$row["valid_to"].'</td> </tr>'; } ?>
Thank you. I have two tables. Table Name:Users Fields: User_name user_email user_level pwd 2.Reference Fields: refid username origin destination user_name in the users table and the username field in reference fields are common fields. There is user order form.whenever an user places an order, refid field in reference table will be updated.So the user will be provided with an refid Steps: 1.User needs to log in with a valid user id and pwd 2.Once logged in, there will be search, where the user will input the refid which has been provided to him during the time of order placement. 3.Now User is able to view all the details for any refid 3.Up to this we have completed. Query: Now we need to retrieve the details based on the user logged in. For eg: user 'USER A' has been provided with the referenceid '1234' during the time of order placement user 'USER B' has been provided with the referenceid '2468' during the time of order placement When the userA login and enter the refid as '2468' he should not get any details.He should get details only for the reference ids which is assigned to him. <?php session_start(); if (!$_SESSION["user_name"]) { // User not logged in, redirect to login page Header("Location: login.php"); } $con = mysql_connect('localhost','root',''); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("login", $con); $user_name = $_POST['user_name']; $refid = $_POST['refid']; $query = "SELECT * from reference,users WHERE reference.username=users.user_name AND reference.refid='$refid' AND "; $result = mysql_query($query) or trigger_error('MySQL encountered a problem<br />Error: ' . mysql_error() . '<br />Query: ' . $query); while($row = mysql_fetch_array($result)) { echo $row['refid']; echo $row['origin']; echo $row['dest']; echo $row['date']; echo $row['exdate']; echo $row['username']; } echo "<p><a href=\"logout.php\">Click here to logout!</a></p>"; ?> <html> <form method="post" action="final.php"> Ref Id:<input type="text" name="refid"> <input type="submit" value="submit" name="submit"> </html> Here's the code that deals with the client side:
<?php session_start(); if(!isset($_SESSION['Logged_in'])){ header("Location: /page.php?page=login"); } ?> <!DOCTYPE Html> <html> <head> <!--Connections made and head included--> <?php require_once("../INC/head.php"); ?> <?php require_once("../Scripts/DB/connect.php"); ?> <!--Asynchronously Return User Names--> <script> $(document).ready(function(){ function search(){ var textboxvalue = $('input[name=search]').val(); $.ajax( { type: "GET", url: 'search.php', data: {Search: textboxvalue}, success: function(result) { $("#results").html(result); } }); }; </script> </head> <body> <div id="header-wrapper"> <?php include_once("../INC/nav2.php"); ?> </div> <div id="content"> <h1 style="color: red; text-align: center;">Member Directory</h1> <form onsubmit="search()"> <label for="search">Search for User:</label> <input type="text" size="70px" id="search" name="search"> </form> <a href="index.php?do=">Show All Users</a>|<a href="index.php?do=ONLINE">Show All Online Users</a> <div id="results"> <!--Results will be returned HERE!--> </div>search.php <?php //testing if data is sent ok echo "<h1>Hello</h1><br>" . $_GET['search']; ?>This is the link I get after sending foo. http://www.family-li...php?&search=foo Is that mean it was sent, but I'm not processing it correctly? I'm new to the whole AJAX thing. Hi, after banging my head against the wall for a while thinking this would be a simple task, I'm discovering that this is more complicated than I thought. Basically what I have is a link table linking together source_id and subject_id. For each subject there are multiple sources associated with each. I had created a basic listing of sources by subject... no problem. I now need a way of having a form to create an ordered list in a user-specified way. In other words, I can currently order by id or alphabetically (subject name lives on a different table), but I need the option of choosing the order in which they display. I added another row to this table called order_by. No problem again, and I can manage all of this in the database, however I want to create a basic form where I can view sources by subject and then enter a number that I can use for sorting. I started off looping through each of the entries and the database (with a where), and creating a foreach like so (with the subject_id being grabbed via GET from the URL on a previous script) Code: [Select] while($row = mysqli_fetch_array($rs)) { //update row order if (isset($_POST['submit'])) { //get variables, and assign order $subject_id = $_GET['subject_id']; $order_by = $_POST['order_by']; $source_id = $row['source_id']; //echo 'Order by entered as ' . $order_by . '<br />'; foreach ($_POST['order_by'] as $order_by) { $qorder = "UPDATE source_subject set order_by = '$order_by' WHERE source_id = '$source_id' AND subject_id = '$subject_id'"; mysqli_query($dbc, $qorder) or die ('could not insert order'); // echo $subject_id . ', ' . $order_by . ', ' . $source_id; // echo '<br />'; } } else { $subject_id = $_GET['subject_id']; $order_by = $row['order_by']; $source_id = $row['source_id']; } And have the line in the form like so: Code: [Select] echo '<input type="text" id="order_by" name="order_by[]" size="1" value="'. $order_by .'"/> (yes I know I didn't escape the input field... it's all stored in an htaccess protected directory; I will clean it up later once I get it to work) This, of course, results in every source_id getting the same "order_by" no matter what I put into each field. I'm thinking that I need to do some sort of foreach where I go through foreach source_id and have it update the "order_by" field for each one, but I must admit I'm not sure how to go about this (the flaws of being self-taught I suppose; I don't have anyone to go to on this). I'm hoping someone here can help? Thanks a ton in advance Say there is a complex opt in process where people start to enter their data but certain questions stop them where they close out of the page. They already entered their data and I feel there is a way to grab it and post it to mysql even though they do not click submit.
How would this be done?
A super simple example (proof of concept) or a link to a tutorial would be very useful.
Edited by brentman, 23 September 2014 - 10:42 AM. |