PHP - Urls In Switch Function

So, I'm working on making my code a little prettier.
Previously, if I wanted to do 3 different things, I would create 3 different php pages for those three different things.

For Example:
<form action="user_add.php">
<form action="user_edit.php">
<form action="user_delete.php">
This would usually be 6 different pages. (3 "gui" pages and 3 php pages that performed specific actions)

So, I've decided to create 1 specific page called "actions.php"
Using a switch.case variable named $request
This will allow me to achieve the following:
<form action="actions.php?request=userAdd">
<form action="actions.php?request=userEdit">
<form action="actions.php?request=userDelete">

My actions page looks like this:
Code: [Select]
<?php
include("connectDB.php");
$request=$_GET['request'];

switch ($request)
{
case "userDelete":
echo "delete";
break;
case "userEdit":
echo "edit";
break;
case "userAdd":
echo "add";
break;
}
?>

Now, assume I access the page that allows me to add a new user. The form action would look like this: <form action=actions.php?request=userAdd>
When I click on the submit button, I would see the words "add" on the page. Perfect, good job, yay me.

Now, assume I add the following code block into the "userAdd" case
Code: [Select]
<?php
...
case "userAdd":
// Get values from form
$username=$_POST['username'];
$password=$_POST['password'];
$email=$_POST['email'];

// Insert data into mysql
$sql="INSERT INTO $tbl_users(username, password, email)VALUES('$username', '$password', '$email')";
$result=mysql_query($sql);

// if successfully insert data into database, displays message "Successful".
if($result)
{ echo "Successful"; }
else 
{ echo "ERROR"; }

echo $previous_page;
break;
?>This works perfectly. Good job, yay me!

Now assume I change the case block to look like this:
Code: [Select]
<?php
...
case "userAdd":
adduser();
break;
}

function adduser()
{
// Get values from form
$username=$_POST['username'];
$password=$_POST['password'];
$email=$_POST['email'];

// Insert data into mysql
$sql="INSERT INTO $tbl_users(username, password, email)VALUES('$username', '$password', '$email')";
$result=mysql_query($sql);

// if successfully insert data into database, displays message "Successful".
if($result)
{ echo "Successful"; }
else 
{ echo "ERROR"; }

echo $previous_page;
}
?>This doesn't work. WHY? If I change the adduser() function to echo "hello world"; I would see "hello world", but when I attempt to copy and paste the block of code (that works in the switch case statement) into the function, it stops working. (It prints nothing)

Now, I don't even know if this is the correct place to put this. Last time I had a mysql database error and my thread was moved here, even though I knew it wasn't a php error. So, if this is the wrong section, I apologize - but I assume it falls under both a mysql and php problem.

This is the error that I am getting...
Quote

<br /> <b>Fatal error</b>: Call to undefined function readChatOnload() in <b>C:\server\xampp\htdocs\php\chat\readChat.php</b> on line <b>18</b><br />



And this is my php file...

if(isset($_POST['function']))
{
$function = $_POST['function'];
switch($function)
{
case 'readNamesOnload': 
readNamesOnload();
break;

case 'readNamesLoop':
readNamesLoop(); 
break;

case 'readChatOnload':
readChatOnload(); 
break;

case 'readChatLoop': 
readChatLoop(); 
break;
}


//READ NAMES ONLOAD
function readNamesOnload()
{
die('readNamesOnload');
}

//READ NAMES LOOP
function readNamesLoop()
{
die('readNamesLoop');
}

//READ CHAT ONLOAD
function readChatOnload()
{
die('readChatOnload');
}

//READ CHAT LOOP
function readChatLoop()
{
die('readChatLoop');
}

}


I don't understand why this is happening.

Thanks

Hi all,

I am looking a developing a script that instead of using something like mysite.com/showproduct.php?id=1 I would like it to appear as mysite.com/php-editor

Is their a simple way of doing this? I would still need to pull info from a database so the page would still need to be dynamic, I just want it to appear static!

I am used to using the get id function of php, what would the workaround be? would the id be hidden from the url but still usable in a query?

I have had a look at the apache mod_rewrite, but quite frankly, I dont understand it!

Cheers

Morning,

I'm working on a web site using a switch to separate different calls from a MySQL database.  My style looks like this:


<?php

switch ($_GET['page']) {
     case 'news':
           echo ("NEWS HERE"); }
           break;
     case 'schedule';
          echo ("SCHEDULE HERE"); }
          break;
     default:
          echo ("MAIN PAGE HERE");
     break;
}


What I am trying to do, is specify that if the page is news, there can be an additional variable for id.  I attempted before and after the break; for the news case, to make a new switch, but it isn't taking.  I've looked around online, but can't find any information about this.  Can anyone offer a hand?

Is their something I can do in PHP (like some sort of function/config/array etc...) which would make the following process easier (examples appreciated)...

I have an .htaccess file where im rewriting urls to seo friendly ones...now in the PHP script is their something I can place for urls are meant to be displayed/linked (like some sort of placeholder) which makes it easier for me to modify the urls within the PHP script, without constantly editing countless php sourcecode to just change the url?

Example scenario:

Say I had a php file (called submit.php):

<?php
echo 'Hey!
Thanks for submiting the form, <a href="submit.php?form">click here</a> to go back!';
?>

and my rewrite rule for submit.php?form was: /form

How would I easily change the url within submit.php without editing submit.php directly?