|
PHP - Search Buttons With Images
I have a search form which uses an image to perform the search. The search performs correctly however it inserts details of the image in the URL, is this normal?
searchdisplaytest.php?term=red-widget&image.x=50&image.y=23 Can I get rid of the "&image.x=50&image.y=23" Code: [Select] <div class="homepagesearchtext"> <input type="text" name="term" size="20" class="homepagesearch" /> </div> <div class="searchbuttonbox"> <input type="image" name="image" value="Submit" src="http://wwwdomain.com/earch.PNG" alt="Search" name="image" > Similar TutorialsSorry if this should be in the HTML forum but as it is relating to something I am trying to do with php I thought this was the right place! I am creating a search page and one of the columns has only two potential values, 'H' for Home Games and 'A' for Away Games. Using radio buttons I can get the search page to filter correctly but there will also be times, once there are a few more search options on there, when a search would want to show All Games. The current form I have is Code: [Select] <form id="form1" name="form1" method="post" action="fixrestestsearch.php"> <p> <label for="OPP">OPP</label> <input type="text" name="OPP" id="OPP" /> <br /> <label> <input type="radio" name="HA" value="H" id="HA_0" /> Home</label> <br /> <label> <input type="radio" name="HA" value="A" id="HA_1" /> Away</label> <br /> <label> <input type="radio" name="HA" value="" id="HA_2" /> All</label> <br /> <br /> SUB <input type="submit" name="SUB" id="SUB" value="Submit" /> </p> </form> and the query in the results page contains Code: [Select] WHERE team_name='$OPP' AND h_a='$HA' If either the 'Home' or 'Away' buttons are checked everything works fine. If I check the 'All' button nothing is returned as it is looking for blank cells. I have also tried using 'value="*"' but that did not work. Is there anything that I can put as the value of a radio button that would select all records or would it have to be something amended in the query on the results page? Thanks in advance Steve I'm trying to create a database driven poll to allow users to "like" or "dislike" each video on my site. But instead of radio buttons and a submit button I want to use images with jquery handling the submit when a choice is made. I have found 2 tutorials that each accomplish part of what I want. This tutorial has a poll which is perfect because I can pass in a poll id (which will be the same value as my video id) and it will load that video's poll. http://www.webresourcesdepot.com/ajax-poll-script-with-php-mysql-jquery/ This tutorial replaces the radio buttons with images. http://www.weblee.co.uk/2009/05/30/radio-button-replacement-with-style/ I have them both working separately on this page http://aaronhaas.com/poll2/ I can't seem to figure out how to combine the two together. The poll script generates its html inside of a php function. In the code below I have commented out the line ( getPoll(1) ) that calls the function and replaced it with the html it generates to make it easier to see what is going on. Another problem is each form has a different action so both actions somehow need to be combined together into a function. I was hoping someone might want to see if they can combine the two together and post it as a tutorial or demo. Code: [Select] <?php require("inc/db.php"); require("inc/functions.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Ajax Poll Script - Demo</title> <!-- styles and js for poll --> <script src="inc/js/jquery-1.4.2.min.js" type="text/javascript"></script> <script src="inc/js/poll.js" type="text/javascript"></script> <style> body { font-family: Arial, Helvetica, sans-serif; font-size: 1em; } #pollWrap{ width: 550px; margin-left:40px; } #pollWrap h3 { display:none; color:red; font-size: 1em; margin-bottom: 5px; display:none; } #pollWrap ul { margin: 0; padding: 0 0 0 5px; } #pollWrap li { padding: 0; /*overflow:hidden;*/ /*for our lovely friend IE6 to behave nicely*/ font-size: 0.8em; display: inline; } #pollWrap li span { font-size: 0.7em; } .pollChart { margin-left: 25px; height: 10px; width:1px; /*Adding rounded corners to the graphs - Optional - START*/ -moz-border-radius-topright: 4px; -moz-border-radius-bottomright: 4px; -webkit-border-top-right-radius: 4px; -webkit-border-bottom-right-radius: 4px; /*Adding rounded corners to the graphs - Optional - END*/ } #pollSubmit { margin-top: 5px; } #pollMessage { color:#C00; font-size: 0.8em; font-weight: bold; } </style> <!-- styles and js for image radio buttons --> <link rel="stylesheet" type="text/css" href="css/radio.css"> <script type="text/javascript" src="js/jquery-1.3.2.min.js"></script> <script type="text/javascript" src="js/radio-demo.js"></script> </head> <body> <div id="greenlight"> <div id="options"> <ul id="list"> <li class="active"><a href="#" class="option1 active" id="link1"><span>Option</span></a></li> <li><a href="#" class="option2" id="link2"><span>Option</span></a></li> </ul> </div> <!-- close options --> <form action="step2.html" method="post" id="radioform"> Green Light: <input name="option1" type="radio" value="option1" id="option1" checked="checked" /><br /> Cancel: <input name="option1" type="radio" value="option2" id="option2" /><br /> </form> <!-- <p><a href="#" class="toggleform">Show Hidden Form Radion Buttons</a></p> --> <?php // getPoll(1); //$pollID ?> <div id="pollWrap"> <form name="pollForm" method="post" action="inc/functions.php?action=vote"> <h3>Poll Question 1</h3> <ul> <li> <input name="pollAnswerID" id="pollRadioButton1" value="1" type="radio"> Answer1 for Poll1 <span id="pollAnswer1"></span> </li> <li class="pollChart pollChart1"></li> <li> <input name="pollAnswerID" id="pollRadioButton2" value="2" type="radio"> Answer2 for Poll1 <span id="pollAnswer2"></span> </li> <li class="pollChart pollChart2"></li> </ul> <input name="pollSubmit" id="pollSubmit" value="Vote" type="submit"> <span id="pollMessage"></span> <img src="ajaxLoader.gif" alt="Ajax Loader" id="pollAjaxLoader"> </form> </div> </div><!-- close greenlight --> </body> </html> I have problem with PHP module for meta search engine, this module takes image results from google and sends it to meta search engine as a result. But it is not working, there is a problem in PHP code witch i have no idea how to find and fix. Code: [Select] <?php class image_google { function image_google() { $this->profile = array( 'site_name' => 'Google', 'site_url' => 'http://www.google.com', 'request_url' => 'http://www.google.com/search?q=$e_qry_str&site=images&tab=wi&start='.(20*($_REQUEST['d']-1)), ); } function parse_results(&$output) { #echo $output; # debug $results = array(); if(preg_match_all('{imgurl=(.*?)&imgrefurl=(.*?)&}is',html_compress(remove_code($output)),$matches,PREG_SET_ORDER)) { $last_match = ''; foreach($matches as $r) { $result = array( 'real_url' => html_decode($r[2]), 'follow_url' => html_decode($r[1]), 'image_url' => html_decode($r[1]), 'title' => html_decode($r[1]), 'description' => html_decode($r[1]), ); array_push($results,$result); $last_match = &$r[0]; } if($last_match) { $offset = strpos($output,$last_match)+strlen($last_match); $output = substr($output,$offset); } } #var_export($results); # debug return $results; } } ?> The result pages is supposed to have pagination like google help me please
I require a page to be added to my website. This page will facilitate a refined search via Google, Bing and Yahoo search engine simultaneously , show the top 5 of each engine. Is this possible using php ? Thank's Hello, Does anyone know a tutorial I can follow to create my own search engine over the items I have in my SQL database? I find a lot of tutorials but they are all 'one word searches' which means if you type two words you will get all results that contain either word (too many hits). If the search engine tutorial displays result with AJAX even better. Thanks for help. df Friends, I want to extract the Search Keyword from the URL, a visitor came from. I am using a PHP CMS and want to show the Keyword on my Blog. So if they search "abcd" from google, i want to extract "abcd" and echo on my blog. Here is the coding i could got hold of, but its not working, not echoing anything <?php function pk_stt2_function_get_delimiter($ref) { $search_engines = array('google.com' => 'q', 'go.google.com' => 'q', 'images.google.com' => 'q', 'video.google.com' => 'q', 'news.google.com' => 'q', 'blogsearch.google.com' => 'q', 'maps.google.com' => 'q', 'local.google.com' => 'q', 'search.yahoo.com' => 'p', 'search.msn.com' => 'q', 'bing.com' => 'q', 'msxml.excite.com' => 'qkw', 'search.lycos.com' => 'query', 'alltheweb.com' => 'q', 'search.aol.com' => 'query', 'search.iwon.com' => 'searchfor', 'ask.com' => 'q', 'ask.co.uk' => 'ask', 'search.cometsystems.com' => 'qry', 'hotbot.com' => 'query', 'overture.com' => 'Keywords', 'metacrawler.com' => 'qkw', 'search.netscape.com' => 'query', 'looksmart.com' => 'key', 'dpxml.webcrawler.com' => 'qkw', 'search.earthlink.net' => 'q', 'search.viewpoint.com' => 'k', 'mamma.com' => 'query'); $delim = false; if (isset($search_engines[$ref])) { $delim = $search_engines[$ref]; } else { if (strpos('ref:'.$ref,'google')) $delim = "q"; elseif (strpos('ref:'.$ref,'search.atomz.')) $delim = "sp-q"; elseif (strpos('ref:'.$ref,'search.msn.')) $delim = "q"; elseif (strpos('ref:'.$ref,'search.yahoo.')) $delim = "p"; elseif (preg_match('/home\.bellsouth\.net\/s\/s\.dll/i', $ref)) $delim = "bellsouth"; } return $delim; } /** * retrieve the search terms from search engine query * */ function pk_stt2_function_get_terms($d) { $terms = null; $query_array = array(); $query_terms = null; $query = explode($d.'=', $_SERVER['HTTP_REFERER']); $query = explode('&', $query[1]); $query = urldecode($query[0]); $query = str_replace("'", '', $query); $query = str_replace('"', '', $query); $query_array = preg_split('/[\s,\+\.]+/',$query); $query_terms = implode(' ', $query_array); $terms = htmlspecialchars(urldecode(trim($query_terms))); return $terms; } /** * get the referer * */ function pk_stt2_function_get_referer() { if (!isset($_SERVER['HTTP_REFERER']) || ($_SERVER['HTTP_REFERER'] == '')) return false; $referer_info = parse_url($_SERVER['HTTP_REFERER']); $referer = $referer_info['host']; if(substr($referer, 0, 4) == 'www.') $referer = substr($referer, 4); return $referer; } $referer = pk_stt2_function_get_referer(); if (!$referer) return false; $delimiter = pk_stt2_function_get_delimiter($referer); if( $delimiter ){ $term = pk_stt2_function_get_terms($delimiter); } echo $term; ?> May someone help? Natasha T Hi all How do I modify the below code to search multiple tables in mySQL database? $query = "select * from store_items where description like \"%$trimmed%\" or title like \"%$trimmed%\" or dimensions like \"%$trimmed%\" order by id ASC"; $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); It is for a search function and I need it to search another table called 'about_text' and 'faq_text' Thanks Pete Hello. I am working on a php script for searching a database table. I am really new to this, so I used the this tutorial http://www.phpfreaks.com/tutorial/simple-sql-search I managed to get all the things working the way I wanted, except one important and crucial thing. Let me explain. My table consist of three columns, like this: ID(bigint20) title(text) link (varchar255) ============================= ID1 title1 link-1 ID2 title2 link-2 etc... Like I said, I managed to make the script display results for a search query based on the title. Want I want it to do more, but I can't seem to find the right resource to learn how, is to place a "Download" button under each search result with its corresponding link from the table. Here is the code I used. <?php $dbHost = 'localhost'; // localhost will be used in most cases // set these to your mysql database username and password. $dbUser = 'user'; $dbPass = 'pass'; $dbDatabase = 'db'; // the database you put the table into. $con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error()); mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error()); // Set up our error check and result check array $error = array(); $results = array(); // First check if a form was submitted. // Since this is a search we will use $_GET if (isset($_GET['search'])) { $searchTerms = trim($_GET['search']); $searchTerms = strip_tags($searchTerms); // remove any html/javascript. if (strlen($searchTerms) < 3) { $error[] = "Search terms must be longer than 3 characters."; }else { $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection. } // If there are no errors, lets get the search going. if (count($error) < 1) { $searchSQL = "SELECT title, link FROM db WHERE title LIKE '%{$searchTermDB}%'"; $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided {$searchTerms} yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; } } } } function removeEmpty($var) { return (!empty($var)); } ?> <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?> <form method="GET" action="search?" name="searchForm"> Search for title: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" /> <input type="submit" name="submit" value="Search" /> </form> <?php echo (count($results) > 0)?"Rezultate lucrari de licenta sau disertatie pentru {$searchTerms} :<br /><br />" . implode("", $results):""; ?> $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; I would like the results to be displayed like this Results for SearchItem: Result 1 Download | Other link Result 2 Download | Other link etc.... or something like this. So, how do I add the data from the link row into a text(Dowload), within an <a href> tag (well, at least I guess it would go this way) ? My first tries (fueled by my lack of knowledge) where things like $results[] = "{$row['title']}<br /> <a href="{$row['link']}">Download</a> <br /> "; but I keep getting lots of errors, and then I don't know much about arrays and stuff (except basic notions); So there it is. I am really stuck and can't seem to find any workaround for this. Any suggestions? (examples, documentation, anything would do, really) Thanks, Radu Hello, I'm developing a website that asks the user to submit a keyword for a search. The results should display matches for this keyword, but also show matches for related keywords (in order of relevenace!). I'm planning on building up a library of which search terms users use in the same sessions (e.g. if someone searches for "it jobs" and "php jobs", I'll know the terms are correlated), and I'll also measure the click-through rates of the items on the results list. I've been spending all weekend trying to map out the design for this but it's proving incredibly complicated and I think the solution is likely to be on the internet somewhere already?! Please could someone point me in the right direction if you've come accross this problem before? Thanks a million, Stu I have code to search a database of members, I can search by lastname but having a little problem. I want to be able to search by lastname starting with the first letter. (ie: a or b or c or d and so on). As it is right now I can only search by first letter of last name if I add % to the search (ie: a% b% c%) will give me all members with the last names starting with the approiate letter designation. I'm not sure how to handle this, any help would be appreciated. Thanks. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <center><table cellspacing="10" cellpadding="10" width="750" border="0"> <h4>Search</h4> <form name="search" method="post" action="<?php $PHP_SELF?>"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="lname">Last Name</option> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <?php // check to see if anything is posted if (isset($_POST['find'])) {$find = $_POST['find'];} if (isset($_POST['searching'])) {$searching = $_POST['searching'];} if (isset($_POST['field'])) {$field = $_POST['field'];} //This is only displayed if they have submitted the form if (isset($searching) && $searching=="yes") { echo "<h4>Results</h4><p>"; // If they did not enter a search term we give them an error if (empty($find)) { echo "<p>You forgot to enter a search term"; exit; } // Otherwise we connect to our Database mysql_connect("localhost", "root", "1910") or die(mysql_error()); mysql_select_db("cmc_member") or die(mysql_error()); // We preform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); // Now we search for our search term, in the field the user specified $results = mysql_query("SELECT * FROM members WHERE upper($field) LIKE'$find'"); // And we display the results if($results && mysql_num_rows($results) > 0) { $i = 0; $max_columns = 3; while($row = mysql_fetch_array($results)) { // make the variables easy to deal with extract($row); // open row if counter is zero if($i == 0) echo "<tr>"; // make sure we have a valid product ALIGN='CENTER' if($fname != "" && $fname != null) echo "<td ALIGN='CENTER'><FONT COLOR='red'><b>$fname $lname</b></FONT><br> $address <br> $city $state $zip <br>$phone<br><a href=\"mailto: $email\">$email</a><br></td>"; // increment counter - if counter = max columns, reset counter and close row if(++$i == $max_columns) { echo "</tr>"; $i=0; } // end if } // end while } // end if results // clean up table - makes your code valid! if($i < $max_columns) { for($j=$i; $j<$max_columns;$j++) echo "<td> </td>"; } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches = mysql_num_rows($results); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> </tr> </table></center> </body> </html> I am developing a intranet forum in Php and MySQL and I am using ajax to display searched results on the same page but right now I am using query LIKE text% to search in database which is slower. but I want to make it fast search engin which can parse *,+ and show result. Since I am using ajax i am not able to use free search engin,so if possible pls provide a complete solution Hello All, I have this script from http://lampload.com/...,view.download/ (I am not using a database) I can upload images fine, I can view files, but I want to delete them. When I press the delete button, nothing happens
http://www.jayg.co.u...oad_gallery.php
<form>
<?php $dir = dirname(__FILENAME__)."/images/gallery" ; $files1 = scandir($dir); foreach($files1 as $file){ if(strlen($file) >=3){ $foil = strstr($file, 'jpg'); // As of PHP 5.3.0 $foil = $file; $pos = strpos($file, 'css'); if ($foil==true){ echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />'; echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host //echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/ $file' /><br/>"; } } }?> <input type="submit" name="mysubmit2" value="Delete"> </form>
any ideas please?
thanks
I want to know how to display results from mysql database by filling in a form. but i have found a tutorial which shows typing in a text box which displays results. if i follow this tutorial will it help me to understand and create php coding to display results for my form? Need some help I have 2 tables in a database and I need to search the first table and use the results from that search, to search another table, can this be done? and if it can how would you recommend that I go about it? Thanks For Your Help Guys! Hi all, I was just wondering if it possible to execute a php-script when someone presses a button without the page to reload or is this done with javascript. So for instance a calculator. I would be more than pleased to hear and if possible even a short example. All i know is to work with a form method but as far as I know that requires the page to reload. thanks! I'm totally naive to php coding and i'm trying to modify my website which was written for me by someone else in php. So i'm kind of shooting in the dark - but my modification really isn't that difficult... here goes. I already have a form set up allowing the user to select values from drop down menus. To this I want to add a further selection from a choice of 4 radio buttons. This is the coding I've used (i've stripped it down to basics for simplicity) it's inserted between the 'form' tags <input type=radio name="choice" value="FP"> Front Print<br> <input type=radio name="choice" value="BP"> Back Print<br> <input type=radio name="choice" value="PP"> Pocket Print<br> <input type=radio name="choice" value="CP"> Custom Print<br> Ok - this part displays ok and seems to function as expected. The form 'Action' sends the user to another php page so i need to access these values on a different page. This is where I'm running blind. I just want a simple 'if' statement to set a variable based on the value of the radio buttons. So something that looks like this.... if (choice[1].checked=true) {$printchoice = "Front Print";} if (choice[2].checked=true) {$printchoice = "Back Print";} if (choice[3].checked=true) {$printchoice = "Pocket Print";} if (choice[4].checked=true) {$printchoice = "Custom Print";} This part doesn't work - i've tried various combinations but i'm just taking wild guesses. Any help would be much appreciated - thanks Hi i'm making a new website based on PHP. I bumped on a problem now... The problem is that I have a loop where i get all records out of my sql database and get them into a form. Every record has a differend form with a button to. Every button then has a unique ID. Now i tried everyting i could think of to get the value out of a button when a button is clicked. But nothing worked... here is the part of the code where everything is for the form and the POST. Code: [Select] while($record = mysql_fetch_object($result)){ $id = $record->id; echo"<form action='home.php' method='post'>"; echo"<b>name:</b>".$record->name." <b>Price: </b>".$record->price.""; echo'<input type="hidden" name="id" value='.$id.'>'; echo"<input type='submit' value='Buy' /><br />"; echo"</form>"; } if($_POST) { $ID = intval($_POST['id']); $query1 = "SELECT price FROM items WHERE id = ".$ID.""; $result1 = mysql_query($query1); list($cost) = mysql_fetch_row($result1); $gold = getStat('gc',$userID); if($gold > $cost) { setStat('gc',$userID,($gold - $cost)); $queryw = "INSERT INTO users_inventory(item_id,user_id, quantity) VALUES ('".$ID."','".$userID."','1')"; $resultw = mysql_query($queryw); } else { echo"You can't afford this weapons."; } } The only thing that doesn't seem to work is this part Code: [Select] $ID = intval($_POST['id']); is always gives me this error: Notice: Undefined index: id in shop.php on line 26 Please help me out here i have no idea what to do from here on... Hello guys. I am learning PHP little by little and am writing a VERY basic quiz. For functionality in the future I want to be able to change questions and answers in one "included" php doc. The problem i am having with my current code is that I would like to place a variable in the "value" definition on the radio input. I am unable to do this I guess. Any suggestions to accomplish the same thing? Sorry for my horrible code, this is the first thing I have written from scratch. The form page: Code: [Select] <?php include ("test.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Untitled Document</title> </head> <body> <h2><? print $q1; ?></h2> <form method="post" action="test.php"> <input type="radio" name="q1answered" value="Basketball"/> <?php print $q1ans[0]; ?> <input type="radio" name="q1answered" value="Football"/> <?php print $q1ans[1]; ?> <br /><br /> <input type="submit" value="Submit Your Answer!" name="submit" /> </form> </body> </html> The php Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Untitled Document</title> </head> <body> <?php //Enter all questions below $q1 = "What is your favorite Sport?"; $q2 = "What is your favorite hobby?"; //End Questions //Enter Asnwer choices for each question $q1ans = array("Basketball", "Football"); //End Answers //All question defined variables here to make grading easier $qbank = array ($q1, $q2,); if (isset($_POST["submit"])) { $choice = $_POST["q1answered"]; if ($choice == $q1ans[0]){ print "Your Favorite Sport is $q1ans[0]."; } else { print "Your Favorite Sport is $q1ans[1]."; } } ?> </body> </html> Thanks! |
|||||||