PHP - Error When Using File_exists In A While Loop

Hi,


I am trying to verify if the given url exists or not, by using file_exists() function.

It always returns 'FALSE' , according to my understanding it happening because the file to be checked on the given url is located in safe mode.

Could anyone please suggest as to how this could be overcome, by similar function or by using alternative method.

Regards
Abhishek Madhani

I'm working on a WordPress theme and I'm trying to build in a simple if statement which will check if the user has add his own logo into the images folder if he doesn't then the name of the blog will appear as normal text in place of the graphic logo.

This is how it looks like:


<?php

$logo_dir = get_template_directory_uri() . "/images/logo.png";

if (file_exists($logo_dir)) { ?>

<li><img src="<?php bloginfo ('template_directory'); ?>/images/logo.png" alt="<?php bloginfo('description'); ?>" /></li>

<?php } else { ?>

<li id='blog_name'><a href="<?php bloginfo('url'); ?>"><?php bloginfo('name'); ?><font>*</font></a></li>

<?php } ?>




I've echo'd out $logo_dir, the URL is correct, but still for some reason it's seeing it as if there would no file exist. If I turn it around into !file_exists then the graphic logo WILL show up. So it's always seeing it as non-existent.

Any ideas why this could be or am I using this function in a wrong fashion? As far as I've understood the PHP manual, this is the correct way of using it.

My setup: (everything on a local network)
Web server: Ubuntu Server 8.10 -- Workgroup
File server: Windows Server 2008 x64 -- domain
Test server: Win 2000 running WAMP -- domain

I'm trying to run the code snippet below. $file is a file on the File server above. It definitely exists.
Running the code below on the Test server works perfectly. But the file cannot be found when running from the Web server.
$file = '//server/share/file.txt';
if (file_exists($file))
echo 'yay!';
else
echo 'error';

What with the safe mode considerations, I've also tried to add:
ini_set('safe_mode', 'Off'); to no effect. And since file, and fopen similarly not work, I'm pretty sure it's not that either.

The File & Test servers are on the same Windows domain, but that's definitely not the reason. I tried the code on a file on a Linux computer in the Workgroup (where the Web server is) with the same results: Test server works, Web server does not.

Please advise; I'm really lost.

I'm trying to get the data for a single user, but I have a loop error and I don't understand why.  Can someone please clarify where I went wrong?

Code: [Select]
function fetch_user_info_mini_profile_by_uid($uid){
$uid = (int)$uid;

$sql = "SELECT
'${uid}' AS `uid`,
`username` AS username,
`firstname`,
`lastname`,
`accounttype`,
`country`,
`state`,
`city`,
FROM `users`
WHERE `id` = '${uid}'";

$query = mysql_query($sql);

$profile = array();

while (($row = mysql_fetch_assoc($query)) !== false)
{
$profile = array(
'uid' => $row['uid'],
'firstname' => $row['firstname'],
'lastname' => $row['lastname'],
'username' => $row['username'],
'accounttype' => ($row['accounttype'] == '1') ? 'Entreprenuer' : 'Investor',
'country'          => $row['country'],
'state' => $row['state'],
'city' => $row['city'],
'display_name' => ucwords("${row['firstname']} ${row['lastname']}"),
);
}

$profile['avatar'] = getUserAvatar($row['username']);

return $profile;
}

I've got the following and I'm receiving this error:

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/a3839210/public_html/Testing/main.php on line 37

Can anyone tell me what the problem might be?
Thanks very much to anyone who tries to help!

Code: [Select]
<?php
include("db.inc.php");  //connects to database
$result2 = mysql_query("SELECT messid,message,from,read,date FROM messages WHERE id = '$id'");  // line 36
  while ($row2 = mysql_fetch_row($result2)) {  // line 37
  $message = $row2[1];  // line 38
  echo "$message";  // line 39
  }  // line 40
?>

From my old gentoo server I run the following code with success. "/mnt/images" is a cifs mount!
Code: [Select]
<?php
$source = '/mnt/images/1001.jpg';
$target = '/tmp/1001.jpg';

if ( file_exists($source) )
echo "file_exists: TRUE<br/>";
else
echo "file_exists: FALSE<br/>";

if ( is_file($source) )
echo "is_file: TRUE<br/>";
else
echo "is_file: FALSE<br/>";

if ( copy($source, $target) )
echo "copy: TRUE<br/>";
else
echo "copy: FALSE<br/>";

echo "filesize source: ".filesize($source)."<br/>";
echo "filesize target: ".filesize($target)."<br/>";
?>The output is
Quote

file_exists: TRUE
is_file: TRUE
copy: TRUE
filesize source: 4715
filesize target: 4715

When I try this on my newly installed CentOS machine I get
Quote

file_exists: FALSE
is_file: FALSE

Warning: copy(/mnt/images/1001.jpg) [function.copy]: failed to open stream: Permission denied in /var/www/html/filetest.php on line 16
copy: FALSE

Warning: filesize() [function.filesize]: stat failed for /mnt/images/1001.jpg in /var/www/html/filetest.php on line 21
filesize source:

Warning: filesize() [function.filesize]: stat failed for /tmp/1001.jpg in /var/www/html/filetest.php on line 22
filesize target:

Every function fails. Then I found that when I disable SELinux with "echo 0 > /selinux/enforce" file_exists() and copy() works.
Quote

file_exists: TRUE
is_file: FALSE
copy: TRUE

Warning: filesize() [function.filesize]: stat failed for /mnt/images/1001.jpg in /var/www/html/filetest.php on line 21
filesize source:
filesize target: 4715

But is_file() and filesize() still doesn't work. They all work when I run them on local files so it is somewhat related to the cifs mount.
What could be the problem here?

Hi ppl

got code problem cant get it show users avatar & blank avatar at same time not that good at
php ppl.

avatar box page

Code: [Select]
<style type="text/css">
#name_area{height:20px; padding:3px;};
</style>
<script language="javascript">
<!--
function member_change(id){
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);
if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
?>
document.getElementById('<?php echo mysql_result($allgames, $i, 'game_id'); ?>').style.display = "none";
<?php
$i++;
}
}
?>
document.getElementById(id).style.display = "block";
}
function show_name(name){

document.getElementById('name_area').innerHTML = name;
}
function hide_name(){
document.getElementById('name_area').innerHTML = '';
}
//-->
</script>

<div style="text-align:left;">
Choose Squad: <select name="D1" onchange="member_change(this.options[this.selectedIndex].value)" class="standardforms">
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);

if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
$game = mysql_result($allgames, $i, 'game_title');
$members_total2 = mysql_num_rows(mysql_query("SELECT * FROM members WHERE game = '$game'"));

if($members_total2!=0)
{
?>
<option value="<?php echo mysql_result($allgames, $i, 'game_id'); ?>"><?php echo mysql_result($allgames, $i, 'game_title'); ?></option>
<?php
}
$i++;
}
}
?>
</select><br /><br />
</div>
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);
if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
$game = mysql_result($allgames, $i, 'game_title');
$members = mysql_query("SELECT * FROM members WHERE game = '$game'");
$members_total = @mysql_num_rows($members);

if($allgames_total!=0)
{
?>
<div id="<?php echo mysql_result($allgames, $i, 'game_id'); ?>" style="display: block; text-align:left;">
<?php

if($members_total!=0)
{
$d=0;
while($d<$members_total)
{

?>
<a href="index.php?page=members&amp;id=<?php echo mysql_result($members, $d, 'id'); ?>"><img onmouseover="show_name('<?php echo mysql_result($members, $d, 'username'); ?>')" onmouseout="hide_name()" src="user/<?php

  echo mysql_result($members, $d, 'avatar_link');

$filename = 'avatar_link';

if (file_exists($filename)) {
     echo "avatar_link";
} else {
     echo "avatars/blank.jpg";
}


?>" width="50" height="50" alt="<?php echo mysql_result($members, $d, 'username'); ?>" title="<?php echo mysql_result($members, $d, 'username'); ?>"/></a>
<?php
$d++;
}
}
}
echo "</div>";
$i++;
}
}
?>
<div id="name_area"></div>

PHP Warning:  file_exists() expects parameter 1 to be string, array given in /home/mysite/public_html/display.mysite.com/wp-content/themes/mytheme/form.php on line 9

PHP Warning:  file_exists() expects parameter 1 to be string, array given in /home/mysite/public_html/display.mysite.com/wp-content/themes/mytheme/form.php on line 13

I have a form that is having some issues and in the error log I see a bunch of these warnings. What is wrong with this??   I numbered the offending lines below (lines 9 & 13)   Thanks for any help on this.

function CheckExistance($VUrl)

{

/*9*/    if ( file_exists($VUrl) )

        echo $VUrl;

/*13*/    elseif ( file_exists(str_replace('www.display.mysite.com','www.display.com', $VUrl)) )

        echo str_replace('www.display.mysite.com','www.mysite.com', $VUrl);

    else

        echo str_replace('www.mysite.com','www.display.mysite.com', $VUrl);

}

Edited by damion, 02 July 2014 - 06:01 PM.

I have a syntax error.  I'm not sure what I'm missing.   Parse error: syntax error, unexpected ';', expecting ')'

Code: [Select]
$information = array(

$i = 0;
while ($i = count($actions))
{
array($actions[$i], $action_details[$i])
$i++;
}
);

Hi there, just trying to make my while loop for echoing data look better but ive now got an error:
Parse error: syntax error, unexpected T_STRING in /home/a9855336/public_html/261/cadetinfo.php on line 48
and im not sure what ive done wrong here is my code, line 48 is marked

<?php
$fldtextArea_name = str_replace("<br>", "\n", $fldtextArea_name);
//connect to the databas
mysql_connect("m*******","a********_root","n*********");
mysql_select_db("m***********");

//add the email to from @valiantflight.co.uk
$from = $from."@valiantflight.co.uk";

//query database and pull email addresses    

$result = mysql_query("SELECT * FROM mail");
while ($row = mysql_fetch_array($result))
{
?>
48 <div id="rightleft"><?php echo('Name:'. $row['Name'] .'); ?></div><div id="rightright"><?php echo('Email:'. $row['Email'] .'<br>'); ?></div>

<?php
}
?> 
Any help would be very appriciated,

Thanks,


Blink359

*delurk! It had to happen sooner or later!*

OK, I am totally and utterly stumped. I have this script:

$this->clear_cache ($this->cache_dir, $this->cache_time);

if ($this->cache_time > 0) {
$current_page = $_SERVER ['REQUEST_URI'];
$current_page_encoded = base64_encode($current_page);
$current_page_path = $this->cache_dir . $current_page_encoded;

 if (file_exists($current_page_path)) { // see if there is still a file with the name of the current request URI after cache cleared
                $content = file_get_contents ($current_page_path);

return $content;
                } 
         }

Basically, it is for checking if there is a cached version of the page before running the rest of the script, using the REQUEST_URI as the identifier. So it calls a function to clear the cache, which works fine (and I've tried just deleting the cache files manually anyway).

Then it checks if we are even caching, i.e. if cache time is greater than 0. Then it uses the BASE64-encoded REQUEST_URI (under which name the file would have been cached previously) to check if a file with that name still exists in the cache dir, and if so loads it. Now, this works perfectly with a url like:

mysite/myscript/mysubpage

But when the page has parameters, like:

mysite/myscript/mysubpage?search=widgets

the file_exists function returns TRUE, even though the directory is empty. I did do a clearstatcache(); but it made no difference and anyway, it wouldn't explain why the URI with query string would fail while the regular one would not. And even if something is wrong with my code elsewhere, the fact is it is returning TRUE for a non-existent file.

Can someone prevent my slide into insanity?!

I get the error:
Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in D:\mypubspace.com\wwwroot\phpsite\pubs.php on line 95

Code: [Select]
$towns  = "SELECT DISTINCT rsTown, COUNT(PubID) As PubCount FROM pubs GROUP BY rsTown  ORDER BY rsTown ASC";
$townresult = mysql_query($towns) or die(mysql_error().'<br>SQL: ' . $towns);


echo <<<EOF
<form name="form3" method="post" action="">
<select name="menu2" onChange="MM_jumpMenu('parent',this,0)" class="textbox">
<option value="">Please choose a town!</option>
while($row1 = mysql_fetch_array($townresult)){
<option value="pubs_norm1.asp?rsTown='$row1['RSTOWN'];'">
Pubs and bars in $row1['RSTOWN']; ($row1['RSTOWN'];)</option>
}
</select>
</form>
EOF;

Please help

hi i am trying to fetch all my data from table here is the code

function premiumview($cn,$table)
	{
		$table=mysqli_real_escape_string($cn,$table);
		$result=$cn->query("select * from $table");
		if($result->num_rows >0)
		{
			while($f=$result->fetch_all(MYSQL_ASSOC))
			{
				$result[]=$f;
			}
			return $result;
		}
		else
		{
			return $result=$cn->error;
		}
	}

and the error is   Fatal error: Cannot use object of type mysqli_result as array ( in while loop line )   What i am doing wrong?

Hi all

My code give this:

<b>Warning</b>:  file_exists(): open_basedir restriction in effect. File(/tmp) is not within the allowed path(s): (/home/clients/........

I get the tmp folder and check for its existanse and whether it is writeable

$t=sys_get_temp_dir();
writelog("t=$t");
if(file_exists($t)) writelog("t1=YES"); else writelog("t1=NO");
if(is_writable($t)) writelog("t2=YES"); else writelog("t2=NO");

Both gives no which is fine, I can process that. I do it to avoid the output above, but I still get that.

How should I check for allowed paths?

This runs on several systems where I cannot access php.ini or other system stuff.