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PHP - Help Needed Calling A Java File
I had Tom Cat Java installed on my Linux sever and I need to call a java file, which isn't working. Someone told me to verify Java is in fact installed on my server using this command:
Code: [Select] echo exec('which java'); but when I run it, nothing displays! The java command I'm trying to run is this: Code: [Select] exec('java -Xmx1024m -jar "/home/account/public_html/java -cp b4a_c2dm.jar anywheresoftware.b4a.c2dm.C2DM send $php_device_id \"test\""'); The .jar file is there. My path to java is: /usr/local/jdk/bin/java Thanks for any help... Similar TutorialsHi How do I turn this: Code: [Select] if($LCname=='Business_solutions'){ $newChild = Business_solutions::find_by_id(1); } In to something like this: Code: [Select] $newChild = $LCname::find_by_id(1); I'm calling lots of class's, and want to make it more dynamic. The 2nd example would be perfect, but that does not work. Is there an alternative? Thanks Hi, I'm a learning PHP developer, and I'm trying to work out how to connect and use an API provided by my goverment to the public. I have no idea how to set it up and test it, and I'm having a really hard time finding any help online.
The documentation mentions using a "simple" cURL request but I have no idea how that works either, and I would like ideally to be able to pull the data and turn into an SQL database where I know how things work a little bit better within PHP.
Many thankss I want to get suggested keywords from yahoo api service. When xml file is empty (no keyword), it gives error. To resolve this problem I used this code: if (file_exists('http://search.yahooapis.com/WebSearchService/V1/relatedSuggestion?appid=YahooDemo&query=Madonna&results=2')) { $xmlmetades = simplexml_load_file('http://search.yahooapis.com/WebSearchService/V1/relatedSuggestion?appid=YahooDemo&query=Madonna&results=2'); } Since it is not a normal .xml file, it is always considered no file, and return nothing. Hi, I wrote this to retrieve a file based on a POST value. For some reason it will not retrieve the file content and display it at all. I get this message: Warning: fopen(18.txt) [function.fopen]: failed to open stream: No such file or directory in /home/content/x/y/z/path/html/includes/different.php The 18 is the correct POST value. So that is a positive There is a file named 18.txt in /home/content/x/y/z/path/html/includes/18.txt Thanks. <?php $id5 = $_POST[id]; //Display Text File $myFile = $id5; $myFile .= ".txt"; $fh = fopen($myFile, 'r'); $theData = fgets($fh); fclose($fh); echo $theData; ?> Hi guys, I hope you may be able to shed some light on a problem I am having. I am fairly new to PHP although do understand bits and peices such as login system. Basically - I have a website with lets say 10 users (more like 500 but that will do for now!) - Each user has their own page wich is password protected. Each month - I want to be able to upload PDF files to the server - which CAN ONLY BE ACCESSED BY THE RELEVANT user. They must not be able to see each others PDF files. To do this I have been advised to have a non-web accessible folder on my server to put the PDF's in and then use PHP to handle the operation. Therefore my path would be: 1/ User logs into page 2/ User clicks the PDF link 3/ PF link goes to PHP page that checks they are logged in and then the PDF they want before delivering to the server. I do actually understand the theory but my PHP is not at the stage where I can just write the code that will handle the operation. I am also very confused over how to access the non-web accessible files! Could anyone please give me an example of the code I will need to use to a) check the user is logged in (I guess I can use the same code I used for the login) and then b) call the relevant PDF and display it? I have been given a path of c:\blahblahblah to access my PDF files but don't even know how to begin implimenting this! Here is the code I use for my login system. Could anyone show me how to adapt it to get what I need? Thank so much for anyone that can help - hopefully I will be in a position to give back one day! -------------------------------------------- if(isset($_SESSION['loggedin'])) { header("Location:" . strtolower($username) . ".php"); if(isset($_POST['submit'])) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $mysql = mysql_query("SELECT * FROM mydb WHERE username = '{$username}' AND password = '{$password}'"); if(mysql_num_rows($mysql) < 1) { die("Password or Username incorrect! Please <a href='login.php'>click here</a> to try again"); } $_SESSION['loggedin'] = "YES"; $_SESSION['username'] = $username; header("Location:" . strtolower($username) . ".php"); AND THEN IN THE HEADER OF THE PAGES <?php session_start(); if(!isset($_SESSION['loggedin'])) { header('Location: /login.php'); } elseif ($_SESSION['username'] . '.php' != basename($_SERVER['SCRIPT_FILENAME']) ) { // Logged in user attempting to view someone else's page header("Location:" . strtolower($_SESSION['username']) . ".php"); exit; } ?> Again - any help would be truly appreciated. I will say now that the last person I asked said "Use the open() function - that'll work!" ...... answers like that are a bit lost on me at the moment and leave me even more confused! Cheers in advance Help! HTML5 Submit button not calling PHD file My HTML: <html> <head> </head> <body> <form action="my.php" method="POST" name="process_form"> <Input type="submit" name="submit" value="Submit" formmethod="post" formaction="my.php"> </form> </body> </html>PHP
if(isset ($_POST["submit"])){
Do something;
Do something;
} else {
Do something;
Do something;
}
I click the button and nothing happens. What am I missing? Hi guys <?php sleep(00); $handle = fopen("http://www.myurl.com/?bla=bla=bla" , "r"); fclose($handle); ?> How do i prevent this from outputing to a file on my server. I only need the url to be accessed to add a new row of data to my DB. Any Ideas? Regards Mark Hi. I have text files in the directory that contain rapidshare.com links. Now what I need to do is take them one by one and check links inside them one by one using rapidshare API. Everything works fine apart from one thing. It reads files and deletes the ones containing dead links but the problem is that it only deletes the file if ALL links are dead, but not when only one link is dead or some of them. Code: Code: [Select] <?php function rs_check($url){ if (!$url) return false; $files_pattern= '/\/files\/([^\/]*)\//'; $filename_pattern= '/\/files\/.*\/(.*)/'; preg_match($files_pattern, $url, $matches_id); preg_match($filename_pattern, $url, $matches_name); $res= file_get_contents("http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=checkfiles_v1&files={$matches_id[1]}&filenames={$matches_name[1]}"); list($fId,$fName,$fSize,$fServerId,$fStatus,$fShortHost,$fmd5) =explode(',',$res); return ($fStatus==1 || $fStatus==2); } $directory = "download/"; $linksfiles = glob("" . $directory . "*.txt"); foreach($linksfiles as $linkfile) { $lf = file_get_contents($linkfile); $purefilename = str_replace($directory, "" , $linkfile); if($purefilename != "5100c00fdb545e12e8cb4f9c5f69ec21.txt"){ if(rs_check($lf) != 1){ unlink($directory . $purefilename); echo("<br />"); } } } ?> Hi! I hope somebody can help me what im do wrong. i have checked that the data from the file is in $source_file but nothing imports to the database Code: [Select] <?php include('config.php'); include('opendb.php'); if(isset($_POST['upload'])) { $source_file = @$_POST['userfile']; //$source_file = fopen('http://localhost/test/upload/test.csv', 'r'); $target_table = 'foretag'; function csv_file_to_mysql_table($source_file, $target_table, $max_line_length=10000) { if (($handle = fopen("$source_file", "r")) !== FALSE) { $columns = fgetcsv($handle, $max_line_length, ","); foreach ($columns as $column) { $column = str_replace(".","",$column); } $insert_query_prefix = "INSERT INTO $target_table (".join(",",$columns).")\nVALUES"; while (($data = fgetcsv($handle, $max_line_length, ";")) !== FALSE) { while (count($data)<count($columns)) array_push($data, NULL); $query = "$insert_query_prefix (".join(",",quote_all_array($data)).");"; mysql_query($query); } fclose($handle); } } function quote_all_array($values) { foreach ($values as $key=>$value) if (is_array($value)) $values[$key] = quote_all_array($value); else $values[$key] = quote_all($value); return $values; } function quote_all($value) { if (is_null($value)) return "NULL"; $value = "'" . mysql_real_escape_string($value) . "'"; return $value; } } include('closedb.php'); echo "<br>done<br>"; ?> I have purchased a ad manager type script and have put so much work in to the site but i cannot get the cron file to execute properly due to errors. The makers of the script arent answering my emails so I am left to find the answer myself im hoping some experts can shine a light on this for me
I have the cron running once daily as required
the error messages are as follows:
/home2/net2you/public_html/2xx.co.uk/include/CronStats.php: line 1: ?php: No such file or directory /home2/net2you/public_html/2xx.co.uk/include/CronStats.php: line 2: syntax error near unexpected token `;' /home2/net2you/public_html/2xx.co.uk/include/CronStats.php: line 2: `ob_start();' I have installed the script on two different hosts and get the exact same errors. any help would be much appriciated the contents of the cron file are below ______________________________________________ <?php Is there a way I can readily stream-process a compressed XML file in PHP? Something like this NON WORKING example: Code: [Select] $reader = new XMLReader(); $reader->open(bzopen($planet_file,"r")); while ($reader->read()) { ... See also http://php.net/manual/en/xmlreader.open.php Hello, I am having some issues with a project I am working on. I am calling a php file on another server using Code: [Select] <script type="text/javascript" src="http://www.website.com/test/file.php"></script> I have the correct type header in my php file and the php outputs JS. example Code: [Select] echo "document.write(\"some stuff\");"; that kind of thing happens alot I also have it outputting a few JS functions, example Code: [Select] echo 'function dostuff(){ stuff }'; the problem I am having is when I add the JS call to the page that calls the php it does nothing I am using document.ready I am not really sure where to go from here, I know php well enough to do anything I need but I do not know JS at all I can not post the actual source code, I know that would be much easier to troubleshoot this but this is something I just can not do. Also this needs to be done this way, I need to call to php files on another server so they can do some stuff and then use JS to change some things on another page on another server. This is a content locker, a lot like CPALead and things like that. What am I missing? Any help is greatly appreciated I am trying to call a javascript function from a php script. This is the approach I'm using. I have an alert in the function, just to confirm the function executes. Code: [Select] echo "<script type='text/javascript' src='http://localhost/Project/JScript/File.js'>"; echo "<script type='text/javascript'>functionName();</script>"; Is this the correct approach? This is probably a quick one. I am pretty new to OOP, in fact somewhat a novice. I am working a lot more with objects lately as my previous "flat" php experience doesn't allow me to create clean and expandable applications. Of course though, questions will always pop up (that's what you guys are for?) One concept I am having trouble understanding, is the method to call a class. What is the difference between?: Code: [Select] <?php $cat = new class(); ?> and just simply: Code: [Select] <?php new class(); ?> Both appear to have the same output from my small amount of practice, but the first way seems strange to me. Being that I am very new to OO PHP, the first way looks like it is just defining a var. But in reality it is calling the class and running it? This seems very backwards to me and I am having a hell of a time understanding it. I am aware that the first way seems to be the "proper" way, but just can't fathom it. Could someone explain this to me a little further? thanks much, i have a constructor Quote public function __construct(){ // check if any action related to this page was generated if(isset($_GET['action'])){ $this->action = ucwords($_GET['action']) . '()'; self::{$this->maction}; } //code to generate the list of all the systems users $user = new userDAO; $this->results = $user->fetchAll(); } if action is present in the querystring, eg. delete, it would be stored into $this->action as Delete(). Similarly, if the action was edit, it would be stored as Edit(). My intent is to call the method named Delete() or Edit() depending upon which action was generated. I have defined the methods in the same class. Once i assign the current action to the $this->action, i want to call the method without explicitly specifying the method name.... here i have tried self::$this->action.... i even tried $this->action only but its not working? i think the string stored in the self::$this->action is not being interpolated? or....sth. i dont know. pls help out guys How can i call a specific row when ever a like. example : Code: [Select] $record = mysql_query("select * from table_name"); ($getValue= mysql_fetch_row($record) //i'm not sure what should i use. should i use mysql_fetch_array, mysql_ fetch_ assoc, mysql_ fetch_ object, mysql_ field_ name and etc. print $getValue[$column_name][0]; 0 = value 1st row in the database/table_name 1 = value 2nd row in the database/table_name 2 = value 3rd row in the database/table_name ...... .... ...... ..... etc. is there a code i can do except from using sql_fetch_array then loop and put in into a multidimensional array? I have a PHP config file called config.php. inside the file is simular to this: Quote <?php class JConfig { var $offline = '0'; var $editor = 'tinymce'; var $list_limit = '20'; } ?> From another file, i have included config.php, but how do I call $editor to get "tinymce"? Thanks Hi, I'm currently in the process of making my first website. The problem is that I'm trying to change the language the website will be in by pressing a button that will call the setlocale() function. But I can't seem to get it to work. From what I read on the internet you can't use php in javascript because it's serverside. But I can't really think of an alternative way of doing this. Any sugestions? This is my code btw for what it's worth. Code: [Select] <form action="SetLangEN()" > <input type="image" src="../images/ENflag.jpg" alt= "EN" width="20px" height="15px" onclick="SetLangEN()" /> </form> </form> </div> <script type="text/javascript"> function SetLangEN() { <?php setlocale(LC_ALL, "en_US"); ?> } </script> |
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