PHP - Basic Preg_replace Help

Hi,

I'm kind of new to PHP and very new to Regular Expressions and I was wondering if someone could help run through this code snippet from a callback function in a Joomla plugin called Affliates Feed.

So far I have this
is passed a pointer to variable item (I understand this is effectively the same as passing the variable but a lot less CPU intensive.
Creates an array with keys and values

Now the for loop I am stuck with, I understand the interation through the array. But what is preg_replace returning and why pass it back that way hasn't it already done its job?

Can any one help? And please feel free to be as basic as possible :help:

Thanks,
Adam


Code: [Select]
function gardening(&$item) {
   #renaming categories, not the most efficient use for example strtolower first, and use only lowercase in the rename array
   $rename=array(
      ' Gardening?' => '',
      'Climber Plants' => 'Climbing Plants',
      'Seeds.*Bulbs' => 'Seeds Bulbs',
      'Plant protection' => 'Horticultural goods',
      'Garden structures' => 'Garden buildings',);
   foreach ( $rename as $k => $v ) {
      list($item['menu_1'],$item['menu_2'])=preg_replace("#$k#",$v,array($item['menu_1'],$item['menu_2']));
   }
   $item['menu_1']=ucfirst(strtolower($item['menu_1']));
   $item['menu_2']=ucfirst(strtolower($item['menu_2']));
   $item['menu_3']=ucfirst(strtolower($item['menu_3']));
   $item['menu_4']=ucfirst(strtolower($item['menu_4']));
}

Hello ppl,
I have this website link http://www.somesite.com/anotherpage/yetotherpage.html what i want to make is using preg_replace that the final result will be www.somesite.com

Hi everyone,

how do i add and ampersand symbol into preg_replace

preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/"

where do i place the symbol? &

im trying to do a complex(i think) prg replace but i keep getting the error:

Code: [Select]
Failed evaluating code: $lang->showing-1,1
the code i am trying to replace is:

Code: [Select]
<asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]>
and the preg_replace is:

Code: [Select]
$content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content);
its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)".

So the output would be showing 1 of 1.

Anyone know where im going wrong?

I am trying to pull out the image HTML tag but its not working as expected.
Here is what I am doing
   $removeimagetag='/<a href/';
   $replacwith = "illegal";
$_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']);

in the 'descr' there is a <a href="http://s635.photobucket.com......
When it post it does not strip out the <a href
So the image is displayed.

I tried a modified version to test to see if it work that looked like this.

   $removeimagetag='/goofy/';
   $replacwith = "illegal";
$_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']);

When the word goofy appears in the text then its replaced with the word illegal,

Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed"  rather than just the part in the front...the <a href.

Any help you can be will be greatly appreciated.

Code: [Select]
$str = preg_replace('/('.$word.')/i', '<em>\1</em>', $str);

how come this doesn't work when $word = 'http://www.google.com', or any other URL?

hi all

why this code doesn't work?


$string = "some words here, 12654124";
$pieces = explode(",", $string);
for ($i=0; $i<=1; $i++){
  $pieces[0] = preg_replace("/[^A-Za-z ]$/", "text to be replace", $pieces[0]); 
  echo $pieces[0] . "<br>";
}

It returns:
Code: [Select]
some words here
some words here
The right result would be:

"text to be replace, 12654124"

How come preg_replace won't traverse multiple lines?   <?php $str = '

Hey, I am trying to write a sort of replace function where {user:1} is converted into a set of information from a database using preg_replace. So I have created the following preg_replace:

$patterns = array();
$patterns[1] = '/\{user:([0-9]+)\}/';

$replacements = array();
$replacements[1] = UserCredit('$1');

ksort($patterns);
ksort($replacements);

$content_show = preg_replace($patterns, $replacements, $content);

echo $content_show;


and then the function UserCredit which is just above that on the page:

function UserCredit($user_id) {
require 'connect.php';
$user_lookup = mysql_query("SELECT * FROM prop_users WHERE ID = '$user_id'");
while($row = mysql_fetch_array($user_lookup)) {
$user_name = $row['full_name'];
$user_file = $row['credit_file'];
$user_url = $row['link_url'];
$user_url_alt = $row['link_alt'];
}
if(mysql_num_rows($user_lookup)==0){
  die("An error has occured, Sorry for any Inconvenience Caused! User ID=".$user_id);
}
require 'close.php';
$output = "<li class=\"clearfix\"><div class=\"credimg\"><img src=\"".$user_file."\" width=\"75px\" height=\"75px\" alt=\"".$user_name."\" /></div><p><strong><a href=\"".$user_url."\" title=\"".$user_url_alt."\">".$user_name."</a></strong><br /><em>Writing / Code</em></p></li>";
return $output;
}


I have tested the function and it works when I echo UserCredit('1');

And the preg_replace works at simply extracting the value for the user.

The only problem is that I can't figure a way for the preg_replace to carry the value of $1 into the function it just literally carries "$1"

Is there something obvious that I am missing or am I going around this the wrong way?

i'm having trouble in combining the 2 preg_replace into 1.
basically i have a string witch strange chars, first i remove all except alphanumeric chars and the remaining string has 1 or 2 spaces and i replace them with dash.
Code: [Select]
strtolower(preg_replace('/\s+/', '-', preg_replace("/[^0-9a-zA-Z]/i", ' ',$a['item'])));

Hello.
Im working on a function:
  Code: [Select]
function image_vote_img_replace($content) {
preg_match_all('/<img[^>]+>/i',$content, $result, PREG_PATTERN_ORDER);
foreach ($result[0] as $img_oryg) {
$result = '<div class="test">'.$img_oryg.'</div>';
$content = preg_replace( $img_oryg, $result , $content );

}
return $content;
}
It gets as input content from CMS. It supposed to add overlaping div to each <img src="xxxx" /> so it looks like: <div class="test"><img src="xxxx" /></div>.
But instead i get:
<<div class="test"><img src="xxxx" /></div>>
with additional < and > at beginning and end.

I thin ,that it might be first regexp problem, but in second hand - entire img is extracted properly...

Thanks in advice.
Martin.

Okay, i know there are lots of these questions out there and tons of ways to do this. I do have it working to replace URLs with <a href="URLs">URLs</a> but now i need some help detecting <a href=""></a> so the preg_replace will not double up the code and mess up the link.

here is my code so far.
Code: [Select]
<?php
echo 'COMMENTS<br /><br />';
  while($rows = mysql_fetch_array($comres)){
  list($comid, $menu_title, $post_id, $comdate, $comname, $comment) = $rows;
  $comment = nl2br($comment);
  $comment = preg_replace('/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/', '<a href="$0" target="_new">$0</a>', $comment);
  $comment = str_replace("&acute;", "'", $comment);
  $comdate = date("g:ia - M j, Y",strtotime("$comdate"));
  echo 'User: '.$comname.'<font color="#B20303"> - '.$comdate.'</font><br />';
  echo '&nbsp;&nbsp; - '.$comment.'<br /><br />';
  }
?>

so with this code, if someone commented a link like this

http://example.com

it will turn it this

<a href="http://example.com" target="_new">http://example.com</a>

but now if someone knew some basic HTML coding, and they used this

<a href="http://example.com">Example.com</a>

it will look like this...

<a href=<a href="http://example.com" target="_new">http://example.com</a>>Example.com</a>

$titleurl = preg_replace('/[^a-zA-Z0-9_ -%]/', '-', $d);
$titleurl = preg_replace('/[ ]/', '-', $titleurl);


How do you add to this to replace

---- with -
--- with -
-- with -

and remove quotes?

How do you remove a - if it's at the very end of $titleurl. For example, replace My-iPhone- with My-iPhone

Hi there!

I'm trying to use preg_replace to include/get content a php file with dynamic variable


$txt = "Bla bla bla bla bla [gls]12[/gls] bla bla bla";
$txt = preg_replace("#\[gls\](.*?)\[/gls\]#si",file_get_contents('shipping.php?id=\\1'),$txt);


..and it doesn't work. I can not get ID. When I do like that
$txt = preg_replace("#\[gls\](.*?)\[/gls\]#si","My Id is - \\1"),$txt);

i see it, but not when I'm using file_get_contents function.

Thanks in advance for help.

Hi,

I have a link like this:

<a href="myword.php" title="myword">some other text myword blah foo</a>

OK now I need to replace myword with newword, but only in the anchor text. So myword in the href or title should not be changed, only matches found inside the anchor text!

I tried using str_replace but obviously this just matched all occurances. So I guess preg_replace is the way to go here but it is far too advanced for me and I cannot get my head around all the different symbols.

Here is some example code:


$html = '<a href="myword.php" title="myword">some other text myword blah foo</a>';
$new = 'newword'
$html = preg_replace(//unsure here!);


I just don't know how to work regex  OT: Did you find it easy/difficult to learn? Thanks to any help