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PHP - Display Today's Date With Php
I'm looking for a simple little code to display today's date, month, day, year and countdown to 365 days. Can anyone please help.
Similar TutorialsHi, I have a job listing website which displays the closing date of applications using: $expired_date (This displays a date such as 31st December 2019) I am trying to show a countdown/number of days left until the closing date. I have put this together, but I can't get it to show the number of days.
<?php
$expired_date = get_post_meta( $post->ID, '_job_expires', true );
$hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true );
if(empty($hide_expiration )) {
if(!empty($expired_date)) { ?>
<span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span>
<?php
$datetime1 = new DateTime($expired_date);
$datetime2 = date('d');
$interval = $datetime1->diff($datetime2);
echo $interval->d;
?>
<?php }
}
?>
Can anyone help me with what I have wrong? Many thanks (continuing from topic title) So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date. How could I go about doing this easily? I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after. Cheers Denno Hi guys, I'm putting together a small event system where I want the user to add his own date and time into a textfield (I'll probably make this a series of drop-downs/a date picker later). This is then stored as a timestamp - "0000-00-00 00:00:00" which displays fine until I try to echo it out as a UK date in this format - jS F Y, which just gives today's date but not the inputted date. Here's the code I have right now: Code: [Select] $result = mysql_query("SELECT * FROM stuff.events ORDER BY eventdate ASC"); echo "<br />"; echo mysql_result($result, $i, 'eventvenue'); echo ", "; $dt = new DateTime($eventdate); echo $dt->format("jS F Y"); In my mysql table eventdate is set up as follows: field - eventdate type - timestamp length/values - blank default - current_timestamp collation - blank attributes - on update CURRENT_TIMESTAMP null - blank auto_increment - blank Any help as to why this could be happening would be much appreciated, thanks. Is there a way of getting today's date (in European format - day-month-year) into the body of an email sent via phpmailer? Many thanks. is it possible to do something like Code: [Select] $today = date("Y-m-d"); $result = mysql_query("SELECT * FROM staff where date = '.$today.' "); also, is it normal for the first entry in the database not to be displayed? i have 6 entries in a table and only 2-6 are shown. when i changed the id for 1 to 7, it only displayed 3-7. still shows all records in the database... any idea how i go about this? Code: [Select] $date= date('y-m-d'); $query=mysql_query("SELECT * FROM listing WHERE date >= $date") or die (mysql_error()); Hey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack Hi... Good day! I have table that has a field from_date and to_date. Now I just want to know if how can I display as table format the dates between from_date to_date. Like this from_date: 2011-12-16 to_date: 2011-12-31 I want to display it: 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 // table format. Thank you Hey guys, How would I go about subtracting Today from a previous day to find the difference? For example, I want to subtract TODAY from a previous date in my database, to determine if the difference is greater than 1 day. Any ideas? I tried doing the subraction in TIMESTAMPS, but when I convert the date back to Y-m-d H:i:s, I got some weird year and time. Hi, I have the following table: ID picName description date 1 Us Time.jpg A couple watching the sunset at Ballintoy Harbour 2011-02-04 2 Pic.jpg This is the house on Castle Island taken in fog. 2011-02-03 3 catblack.jpg Pic of a cat 2011-02-05 I am trying to display th picName that belongs to the highest date but only know how to display all pictures. Can anybody help me? Here is what I have: <?php include("db.inc"); $cxn = mysqli_connect($host,$user,$password,$dbname) or die ("couldn't connect to server"); /* Select */ $query = "SELECT * FROM pictures"; $result = mysqli_query($cxn,$query) or die ("Couldn't execute query."); while($row = mysqli_fetch_assoc($result)) { echo "<tr><td colspan=2> </td> <td><img src='./images/{$row['picName']}' border='0' width='500' height='400' /><p></td></tr>\n"; } ?> I made the basic function to count the number of left count and right count. However now i need to display then number of additions to a tree according to their joining date. I stuck here. can someone please show me the logic to do this ? I know i need to use UNION for sql because date of joining and tree structure are in different tables. Sql tables- Member table -(doj is date of join) Tree table- Basic Code- Code: [Select] <?php function tree_count($node) //Function to calculate count;$node is first lchild or first rchild. { $sql = "SELECT lchild,rchild FROM tree WHERE parent = '".$node."'" ; // $sql = "SELECT lchild,rchild FROM tree WHERE parent = '".$node."' should i do something like this ? // UNION SELECT member_id FROM member WHERE id_sponsor=".$node." AND doj BETWEEN '".$from."' AND '".$to."'" ; $execsql = mysql_query($sql); $array = mysql_fetch_array($execsql); if(!empty($array['lchild'])) { $count += tree_count($array['lchild']); } if(!empty($array['rchild'])) { $count += tree_count($array['rchild']); } $totalcount = 1 + $count; return $totalcount; } ?> I have a posting system worked out, as well as my database configured to my linking.. But as of right now, my posts are posted from oldest to newest, having users scroll down or go to the next page to see the most recent post.
How would I "flip" that around and make my posts start from newest to oldest by its date/time (Which is stored in the database)?
Thanks!
I have a simple mysql database holding information about an image upload including its 'name' and 'date uploaded' [current_timestamp()] to a folder 'image' I then display it into a table using the php ‘foreach’ facility. I want the date to be displayed in the ‘dd/mm/yyyy’ format. not the default yyyy/mm/dd. Here is the relevant code
<?php
$conn = mysqli_connect("localhost", "root", "", "dbname");
$results = mysqli_query($conn, "SELECT * FROM tablename");
$image = mysqli_fetch_all($results, MYSQLI_ASSOC);
?>
<?php foreach ($image as $user): ?>
<td><p>NAME</p><?php echo $user['name']; ?></td>
<td><p>COMMENT</p><?php echo $user['comment']; ?></td>
<td><p>DATE</p><?php echo $user['date']; ?></td>
What do I need to do? THANKS- Warren I would like to know the best practice to achieve the following: I have a list of dates related to live events for performing artists. When someone views the web page that contains a section to display the dates, I would only want to show the dates from today into the future and not show any dates from the past. What is the best way to accomplish this? Thanks in advance... Hi I am trying to add a field to a database that is 4 days from the date the record is added, but it is not adding a value Code: [Select] $end_date=strtotime("+ 4 days"); $add_vehicle_sql=mysql_query("INSERT INTO `tbl_auction_lot`(`cust_id`,`reserve`,`make`,`model`,`spec`,`fuel`,`doors`,`mot_date`,`fns`,`fos`,`rns`,`ros`,`condition`,`reg_no`,`service_history`,`sale_type`,`status`,`keepers`,`gearbox`,`emissions`,`colour`,`date_first_reg`,`date_manufacture`,`bhp`,`engine_size`,`end_date`) VALUES ('$seller_id','$reserve','$make','$model','$body_style','$fuel_type','$no_of_doors','$mot','$fns','$fos','$rns','$ros','$vehicle_condition','$vrm','$service_history','auction','$status','$prev_keepers','$gearbox','$emissions','$colour','$date_reg','$date_man','$bhp','$engine_size','$end_date')") or die(mysql_error()); What am I doing wrong and what is there a better way to achieve the desired result. Hello, In my Mysql database, it has a datetime field. and I have created a $today = date('Y-m-d H:i:s'); <- today's date and time How do I write a query to run in PHP in order to get all today's items by comparing datetime field and $today? Thanks! This topic has been moved to PHP Freelancing. http://www.phpfreaks.com/forums/index.php?topic=333553.0 Hello, i'm trying to get the number of users that registered today and the number of users that registered yersterday (seperate), i've got this field in mysql: 'registertime' which stores data in this format 2011-11-14 14:53:49 also i have the field 'time' in the same format that updates everytime the user logs in. Now previously i wanted to find out users online in last 24 hours, the code i used for that is this: Code: [Select] $query = "SELECT COUNT(*) as Anzahl FROM customers WHERE country = 'de' AND time BETWEEN DATE_SUB( NOW(), INTERVAL 24 HOUR ) and NOW() "; $queryerg = mysql_query($query) OR die(mysql_error()); while($row = mysql_fetch_array($queryerg)){ $customers_on_de_24 = $row[0]; } How could i edit that to select the count just by date and ignore the time (hours minutes seconds) ? Hi All, Newbie here.
I run a website using xmb forums software as a base login script to connect to my database and created my own crude and simple pages for adding and displaying the data learning as I went. Over the years with recent upgrades of php versions its now virtually useless and unsecure code. I archive a lot of news articles but have had trouble pasting text that includes apostrophe's and special characters, but managed to fix that using addslashes() now. Can someone suggest a tutorial or a way to rebuild my site from scratch or something I can use as a template to connect to my pages ?. |
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