PHP - Max(`date`) Not To Exceed 2 Days Into The Future

Hi, I am trying to get the number of days between the current date and a date in the future specified by column 'end_date'. The code I have seems to be working but it displays the number of days as a negative number, how do I change this to be a positive number? I have tried simply changing $days = $now - $end_date; to $days = $end_date - $now; but that doesn't work as I thought it would! Thanks in advance..

Code: [Select]
$now = time();
      $end_date = strtotime($row['end_date']);
      $days = $now - $end_date;
      echo floor($days/(60*60*24));

Hi,

I have a job listing website which displays the closing date of applications using:

$expired_date

(This displays a date such as 31st December 2019)

I am trying to show a countdown/number of days left until the closing date.

I have put this together, but I can't get it to show the number of days.

                    <?php 
                    $expired_date = get_post_meta( $post->ID, '_job_expires', true );
                    $hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true );
                    if(empty($hide_expiration )) {
                        if(!empty($expired_date)) { ?>
                                <span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span>
                    
                    <?php
                                        $datetime1 = new DateTime($expired_date);
                                        $datetime2 = date('d');
                                        $interval = $datetime1->diff($datetime2);
                                        echo $interval->d;

                     ?>
                        <?php }
                    } 
                    ?>

Can anyone help me with what I have wrong?

Many thanks

Hi, I am using this function to output a list of dates for every friday over the next 12months. This is working fine.

Code: [Select]
[php]
//function
function nextWeeksDay($date_begin,$nbrweek)
{
$nextweek=array();
for($i = 1; $i <= $nbrweek; $i++)  { // 52 week in one year of course
$nextweek[$i]=date('Y-m-d', strtotime('+'.$i.' week',$date_begin));
}
return $nextweek;
}
/// end function
/// example of a select date
// var
$date_begin=strtotime('this Friday');
$nbrweek=52;
// call function
$result=nextWeeksDay($date_begin,$nbrweek);
// Insert
//$date1=date('Y-m-d', $date_begin);
for($i = 1; $i <= $nbrweek; $i++)  {
//$date=$result[$i];
echo $result[$i]."<br/>";
}

[/php]
My problem is that when I alter the code to try and get the date for every second Friday for the next year the script freezes.

Code: [Select]
[php]
//function
function nextWeeksDay($date_begin,$nbrweek)
{
$nextweek=array();
for($i = 2; $i <= $nbrweek; $i+2)  { // 52 week in one year of course
$nextweek[$i]=date('Y-m-d', strtotime('+'.$i.' week',$date_begin));
}
return $nextweek;
}
/// end function
/// example of a select date
// var
$date_begin=strtotime('this Friday');
$nbrweek=52;
// call function
$result=nextWeeksDay($date_begin,$nbrweek);
// Insert
//$date1=date('Y-m-d', $date_begin);
for($i = 2; $i <= $nbrweek; $i+2)  {
//$date=$result[$i];
echo $result[$i]."<br/>";
}

[/php]
I really don't understand why??  Does anyone know why?

Thanks

Hi,

I want to calculate the future month, i have used following code to calculate the date
$date = date('Y-m-d',strtotime(date("Y-m-d", strtotime('2010-01-31')) . " +3 month"));

It gives me 2010-03-03

But i need to get 2010-02-28

OR just month is enough like 2010-02

Thank you
Nikhil

I want to set a never expire date, so I figured I would set the date 99 years into the future.  No dice.  After trial and error, it appears you can only make it 25 years into futu

date("Y-m-d",strtotime("+25 years"));

I wonder if it is the absolute date, or the number 25.  If it is the maximum date (i.e. nothing after 2035) then I will have a problem with this code next year!