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PHP - How To Do Yyyy-mm-dd To X, Y, Z
Hi,
In my database, date is stored as in the format of YYYY-MM-DD Something like $date = 2012-04-01 How can I extract this as follows ... $year = 2012 $month = 04 $day = 01 Thanks Similar TutorialsHello Everyone I am working on a website for my favorite hobby. I have created the dynamic pages and they are ready to go. I am having trouble however with the dates. I want all the dates to show up as MM-DD-YYYY. Not sure how to do that with a while loop. I am also trying to figure out how to make the date say "Lost Info" if the date is showing the default.(0000-00-00) Here is my code so far Code: [Select] <?php include('../../includes/config.php'); $sql = 'SELECT id, l_name, f_name, date_sent, date_return, item_return FROM `ttmautos` WHERE `l_name` LIKE \'a%\' AND `category` LIKE \'baseball\' ORDER BY `date_return` DESC'; $link_result = mysql_query($sql, $connection) or die(mysql_error()); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <link rel="stylesheet" type="text/css" href="../../css/reset.css"/> <link rel="stylesheet" type="text/css" href="../../css/top_nav.css"> <link rel="stylesheet" type="text/css" href="../../css/main_layout.css"/> <script src="../../scripts/jquery-1.4.4.js" type="text/javascript"></script> <script src="../../scripts/top_nav.js" type="text/javascript"></script> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Baseball Autographs A</title> </head> <body> <div id="wrapper"> <?php include('../../includes/page/header.php'); ?> <?php include('../../includes/page/top_nav.php'); ?> <?php include('../../includes/page/left_sidebar_autopages.php'); ?> <?php include('../../includes/page/right_sidebar.php'); ?> <div id="content"> <ul class="list_heading"> <li class="title">player name</li> <li>date sent</li> <li>date recievied</li> <li class="return">item recievied</li> </ul> <ul class="list"> <?php while ($link=mysql_fetch_array($link_result)){ echo "<li>$link[f_name] $link[l_name]</li> <li>$link[date_sent]</li> <li>$link[date_return]</li> <li class=\"return\"><a href=\"/auto_pages/baseball/baseball-autographs.php?l_name=$link[l_name]&f_name=$link[f_name]\">$link[item_return]</a></li>"; } if($link[date_sent]=="0000-00-00") { echo "Lost Info"; } if (!($link = mysql_fetch_array($link_result))) { return "Currently our database has no autographs listed for here"; } ?> </ul> </div> <!--END content div--> </div> <!--END wrapper div--> <?php include('../../includes/page/footer.php'); ?> </body> </html> Hello everyone, I am not sure if I am googling this wrong or what. I have several dates in a mysql database that I would like to display in a dynamically made page. Can someone help me or point me in the right direction. I am very unfamiliar with the MySql date function. I would also like to calculate the days that have passed between two different dates. Example would be: 11-27-2011 and 12-15-2011 = # of days yeah... in norway, we use dd.mm.yyyy, but mysql date uses yyyy.mm.dd.. Is there any php lines i can use to rearrange the input dates? And also, rearrange the date when i query the mysql for the dates? guys, im having a problem here... i tried too many ways to convert dates in american format, to brazilian format, but no one is working... how can i do that, to convert it to dd/mm/yyyy (it comes from my db in mysql)... Hi I need to change a uk date dd/mm/yyyy to mysql format yyyy/mm/dd I have a user form where they enter the date in dd/mm/yyyy string format, i want to take that string, and convert it to mysql format yyyy/mm/dd Possible? Ive searched for ages and havent found a solution that works. Is there an easy solution to this? surely there must be Cheers How can I convert a database time to mm/dd/yyyy from yyyy-mm-dd when pulling from database to display, and vice versa when from form to database? How can I get the day of the week from DD/MM/YYYY?? Thanks! hello, i have the following code and it is ok. what im trying to do is convert a 2010-09-20 post from a form and have it read out as Monday September 20, 2010. is this possible? Code: [Select] $dateselected="$_POST[Y]-$_POST[M]-$_POST[D]"; echo "<table border='1'>"; echo "<tr><td width='100%' colspan='4' align='center'>$_POST[M]-$_POST[D]-$_POST[Y]</td></tr>"; I have set up a function to validate user input date in yyyy-mm-dd format taking into account the following possibilities:
the length of the month
February 29th when the year is not a leap year
When I run the code, I do not get any feedback whatsoever, when it should.
This is the code below and I would appreciate your thoughts:
if(!function_exists('checkdate'))
{
function checkdate($date, $checkyear, $currentmonth)
{
if($checkyear == 0)//if it is not a leap year
{
// if current month is february
if($currentmonth == 2)
{
if(!preg_match("/^(20)\d\d[-](0[1-9]|1[012])[-](0[1-9]|1[0-9]|2[0-8])$/", $date))
{
// set error for date field
return ($error = 'Invalid Date!');
}
return ($error = 'valid Date!');
}
// if current months are april, june, september or november
elseif($currentmonth == 4 || $currentmonth == 6 || $currentmonth == 9 || $currentmonth ==11)
{
if(!preg_match("/^(20)\d\d[-](0[1-9]|1[012])[-](0[1-9]|1[0-9]|2[0-8]|3[0])$/", $date))
{
// set error for date field
return ($error = 'Invalid Date!');
}
return ($error = 'valid Date!');
}
else
{
if(!preg_match("/^(20)\d\d[-](0[1-9]|1[012])[-](0[1-9]|[12][0-8]|3[01])$/", $date))
{
// set error for date field
return ($error = 'Invalid Date!');
}
return ($error = 'valid Date!');
}
}
elseif($checkyear == 1)//if it is a leap year
{
// if current month is february
if($currentmonth == 2)
{
if(!preg_match("/^(20)\d\d[-](0[1-9]|1[012])[-](0[1-9]|1[0-9]|2[0-9])$/", $date))
{
// set error for date field
return ($error = 'Invalid Date!');
}
return ($error = 'valid Date!');
}
// if current months are april, june, september or november
elseif($currentmonth == 4 || $currentmonth == 6 || $currentmonth == 9 || $currentmonth ==11)
{
if(!preg_match("/^(20)\d\d[-](0[1-9]|1[012])[-](0[1-9]|1[0-9]|2[0-9]|3[0])$/", $date))
{
// set error for date field
return ($error = 'Invalid Date!');
}
return ($error = 'valid Date!');
}
else
{
if(!preg_match("/^(20)\d\d[-](0[1-9]|1[012])[-](0[1-9]|[12][0-9]|3[01])$/", $date))
{
// set error for date field
return ($error = 'Invalid Date!');
}
return ($error = 'valid Date!');
}
}
}
$todate = getdate();
$currentmonth = $todate['mon'];
$checkyear = date('L');
$date = 2014-02-31;
echo checkdate($date, $checkyear, $currentmonth);
Edited by terungwa, 26 July 2014 - 02:43 PM. Hey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack |
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