PHP - Preg_replace

Hi,

I'm kind of new to PHP and very new to Regular Expressions and I was wondering if someone could help run through this code snippet from a callback function in a Joomla plugin called Affliates Feed.

So far I have this
is passed a pointer to variable item (I understand this is effectively the same as passing the variable but a lot less CPU intensive.
Creates an array with keys and values

Now the for loop I am stuck with, I understand the interation through the array. But what is preg_replace returning and why pass it back that way hasn't it already done its job?

Can any one help? And please feel free to be as basic as possible :help:

Thanks,
Adam


Code: [Select]
function gardening(&$item) {
   #renaming categories, not the most efficient use for example strtolower first, and use only lowercase in the rename array
   $rename=array(
      ' Gardening?' => '',
      'Climber Plants' => 'Climbing Plants',
      'Seeds.*Bulbs' => 'Seeds Bulbs',
      'Plant protection' => 'Horticultural goods',
      'Garden structures' => 'Garden buildings',);
   foreach ( $rename as $k => $v ) {
      list($item['menu_1'],$item['menu_2'])=preg_replace("#$k#",$v,array($item['menu_1'],$item['menu_2']));
   }
   $item['menu_1']=ucfirst(strtolower($item['menu_1']));
   $item['menu_2']=ucfirst(strtolower($item['menu_2']));
   $item['menu_3']=ucfirst(strtolower($item['menu_3']));
   $item['menu_4']=ucfirst(strtolower($item['menu_4']));
}

Hi there!

I need to echo some text from a database table, this text should be linked to a url stored in the same database. I am trying to do this with preg_replace but I am terrible at it! I keep getting this error:

Warning: Wrong parameter count for preg_replace()

while($row = mysql_fetch_array( $result ))
 {

$reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";

echo preg_replace ($reg_exUrl, $row['title');


Any suggestion?

Thanks

I'm trying to search a string for all occurences of a pattern, then append text after that pattern.  The example is:   SUM("foo") as "bar"   and have it display as:   SUM("foo") over() as "bar"   The "SUM" could be any SQL aggregate and be case insensitive.  So For bonus points, let's say the valid aggregates are  array('SUM', 'MAX', 'MIN', 'AVG').  My plan right now is to figure it out for SUM, then loop it replacing the aggregate.   This is what I have so far... and it is not working.   $l= 'SUM("foo") as "bar"'; $l=preg_replace('/([^"]+")/','\0 over()',$l);   Thanks,   Ryan

im trying to do a complex(i think) prg replace but i keep getting the error:

Code: [Select]
Failed evaluating code: $lang->showing-1,1
the code i am trying to replace is:

Code: [Select]
<asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]>
and the preg_replace is:

Code: [Select]
$content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content);
its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)".

So the output would be showing 1 of 1.

Anyone know where im going wrong?

i'm having trouble in combining the 2 preg_replace into 1.
basically i have a string witch strange chars, first i remove all except alphanumeric chars and the remaining string has 1 or 2 spaces and i replace them with dash.
Code: [Select]
strtolower(preg_replace('/\s+/', '-', preg_replace("/[^0-9a-zA-Z]/i", ' ',$a['item'])));

Okay, i know there are lots of these questions out there and tons of ways to do this. I do have it working to replace URLs with <a href="URLs">URLs</a> but now i need some help detecting <a href=""></a> so the preg_replace will not double up the code and mess up the link.

here is my code so far.
Code: [Select]
<?php
echo 'COMMENTS<br /><br />';
  while($rows = mysql_fetch_array($comres)){
  list($comid, $menu_title, $post_id, $comdate, $comname, $comment) = $rows;
  $comment = nl2br($comment);
  $comment = preg_replace('/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/', '<a href="$0" target="_new">$0</a>', $comment);
  $comment = str_replace("&acute;", "'", $comment);
  $comdate = date("g:ia - M j, Y",strtotime("$comdate"));
  echo 'User: '.$comname.'<font color="#B20303"> - '.$comdate.'</font><br />';
  echo '&nbsp;&nbsp; - '.$comment.'<br /><br />';
  }
?>

so with this code, if someone commented a link like this

http://example.com

it will turn it this

<a href="http://example.com" target="_new">http://example.com</a>

but now if someone knew some basic HTML coding, and they used this

<a href="http://example.com">Example.com</a>

it will look like this...

<a href=<a href="http://example.com" target="_new">http://example.com</a>>Example.com</a>

Hi guys, this is what im trying to achieve, im trying to remove the links to the current page for all my web pages with a single script, like for example, if i am on a home page, then the home page hyperlink is disabled, and if i am on a about us page the hyperlink for about us is disabled, i have went through many forums and posts but the more i read the more confused i get, however i came up with a method of my own with many bits of code i've read about everywhere.

firstly, the script collects the current url of the page(i dont need https or any sub direct, its just for example index.php)
then it stores the page name, index.php into a variable say - $current
Then a menu.php which is the navigation file is loaded and heres the part i cant get to work, i would like to match find that <a href="index.php"> index </a> and replace that with <a> index </>
so that the link to the current page is disabled..i tried using preg_replace but failed miserably and opted to use str_replace

Heres the code:

<?php
//the function below gets the current page url or file
//i got this off webcheatsheet - http://www.webcheatsheet.com/PHP/get_current_page_url.php
function getPage(){
 return substr($_SERVER["SCRIPT_NAME"],strrpos($_SERVER["SCRIPT_NAME"],"/")+1);
}

//store the current url or the file name into a variable
$current = getPage();

echo "The current page name is ".$current;
$menu=file_get_contents("menu.php");

$string = "<a>"+$current+"</a>";
$link = "<a href="+ current +"> ";
//i could not get preg_replace to work or come up with an effective regular expression
//which is why i use str_replace instead.
$menu=str_replace("" , $string, $menu);

echo $menu;

?>

Hi there!

I'm trying to use preg_replace to include/get content a php file with dynamic variable


$txt = "Bla bla bla bla bla [gls]12[/gls] bla bla bla";
$txt = preg_replace("#\[gls\](.*?)\[/gls\]#si",file_get_contents('shipping.php?id=\\1'),$txt);


..and it doesn't work. I can not get ID. When I do like that
$txt = preg_replace("#\[gls\](.*?)\[/gls\]#si","My Id is - \\1"),$txt);

i see it, but not when I'm using file_get_contents function.

Thanks in advance for help.

Hi,

I have a link like this:

<a href="myword.php" title="myword">some other text myword blah foo</a>

OK now I need to replace myword with newword, but only in the anchor text. So myword in the href or title should not be changed, only matches found inside the anchor text!

I tried using str_replace but obviously this just matched all occurances. So I guess preg_replace is the way to go here but it is far too advanced for me and I cannot get my head around all the different symbols.

Here is some example code:


$html = '<a href="myword.php" title="myword">some other text myword blah foo</a>';
$new = 'newword'
$html = preg_replace(//unsure here!);


I just don't know how to work regex  OT: Did you find it easy/difficult to learn? Thanks to any help

i want to remove any links which get pulled  out in my general information query.

Code: [Select]
$general_info = $row['general_info'];
$general= preg_replace('/<a href="([^<]*)">([^<]*)<\/a>/', '', $general_info);

echo '<h2>General Information : <img src="images/mag.png"></h2>';
echo '<div id="featurecontent">';
echo '<p>'. ucfirst($general).'</p>';
echo '</div>';
But the above code doesnt seem to be stripping out links.

Can anyone see what i am doing wrong.

Kind Regards

Dean

how is it possible to allow someone to do paragraphs when using preg_replace? would someone show a few good examples of hows its done?

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=347057.0

I had this code but now I need to change it to newer preg_replace function
Can someone help me to do it please?

Here is the code:

    $newString = ereg_replace("[[:alpha:]]+://[^<>[:space:]]+[[:alnum:]/]","<a href=\"\\0\" target=\"_blank\">\\0</a>", $originalString);

Thanks in advance.

Quote

Hi Guys,
I have a small issue with doing a preg_replace on a string.
Here is the string I wish to use preg_replace on




Code: [Select]
<?php
$mystring = "This is my test string that has {['site_info']} and some more stuff {['taste']} then nothing"
?>

Quote

I want to do a preg_replace and replace {['site_info']} with  $stuff['major']['site_info'] through the string

Quote

I want to replace the placeholder with real variables from the array
Any help would be great

This topic has been moved to PHP Regex.

http://www.phpfreaks.com/forums/index.php?topic=350441.0