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PHP - Can Only Update Records Once?
I am really not sure if this is a problem with me (probably is), php or mysql.
I have a calendar that I am adding events to. If I want to edit only the date I can but only once after I make this update I am out. If I attempt to update the time or event title the database is never updated and I am no longer able to update the date. here is the controller for the save. Code: [Select] <?php function eventsave() { $details = $_POST; $this->load->model('eventsmodel'); $this->eventsmodel->eventsave($details,'', TRUE); redirect('/admin/events', 'location'); } ?> I have turned off the redirect to see if I was getting any errors and they seem to be non existent. Here is the model that is used to create a new entry and update a record. Code: [Select] <?php function eventsave($event) { $startdate = explode('-', $event['startdate']); $start = mktime($event['starthour'], $event['startmin'], 0, $startdate['0'], $startdate['1'], $startdate['2']); $end = mktime($event['endhour'], $event['endmin'], 0, $startdate['0'], $startdate['1'], $startdate['2']); $name = $event['name']; if (isset($event['id'])) { // if is true then this is an update not a new event $data = array( 'name' => $name, 'start' => $start, 'end' => $end ); $this->db->where('id', $id); $this->db->update('events', $data); }else{ $this->db->set('name', $name); $this->db->set('start', $start); $this->db->set('end', $end); $this->db->insert('events'); } } ?> I am using code igniter if that helps and the information being submitted by the form looks good. This is the submitted update array and the new event array is just missing the "id" Code: [Select] Array ( [name] => test [startdate] => 05-14-2011 [starthour] => 1 [startmin] => 0 [endhour] => 1 [endmin] => 0 [id] => 54 [saveevent] => save ) Any suggestions would be appreciated. Thank you. Similar TutorialsHi guys, I am trying to UPDATE some records on a mySQL database but can't seem to find out why it is not working. This is my code. Code: [Select] <?php $latitude = $_POST['lat_location']; $longitude = $_POST['long_location']; $unique_ID = $_POST['unique_ID']; include('connect2.php'); $query = mysql_query("SELECT * FROM user_location WHERE unit = '$unique_ID'"); $numrows = mysql_num_rows($query); if ($numrows == 1) { $query2="UPDATE user_location SET lat = '$latitude', long = '$longitude' WHERE unit = '$unique_ID'"; mysql_query($query2); $test = "matches"; } else { mysql_query("INSERT INTO user_location VALUES ('','$unique_ID','$latitude','$longitude')"); $test = "not match"; } echo $test . "<br />"; echo $numrows; ?> The script receives the data via the POST method and assigns it to variables. Then I query the database for one of those variables and check how many results are found. If 0 results are found then a new record is created on the database, but if there is 1 record found then the record that is found has to be UPDATED. When the result is 0 the scripts creates the new record fine, but if the result is 1 it doesn't update. I just can't figure out why. Any help will be greatly appreciated. Thanks in advanced, Hi all, I'm trying to make a query that allows the user to edit the name of a entry in SQL. I believe I have the corect Syntax but I'm not sure if I have the code set up correctly. I am using 2 queries when I think it is possible with one. The first query is used to Pint out results for a certain year and the second to update the names. Code: [Select] $desiredYear = $_POST['year']; $nameEdit = $_POST['edit']; $origName = $_POST['orig']; echo ' The year you have chosen is '.$desiredYear; $describeQuery = "SELECT ID, Name, (SELECT SUM(SalesVolume) as SalesVolume FROM MonthlySales WHERE ProductCode=Products.ID AND Year = '$desiredYear') AS num_sales FROM Products"; $editQuery = "UPDATE Products SET Name = '$nameEdit' WHERE Name ='$origName'"; $results = sqlsrv_query($conn, $describeQuery); echo '<table border="1" BORDERCOLOR=Black>'; echo '<tr><th bgcolor = "LightBlue">Name</th><th bgcolor = "LightBlue" >ID</th> <th bgcolor = "LightBlue" >Sales</th></tr>'; while($row = sqlsrv_fetch_array($results, SQLSRV_FETCH_ASSOC)) { echo '<tr>'; echo '<td >' .$row['Name'].'</td>'; echo '<td>' .$row['ID'].'</td>'; echo '<td>' .$row['num_sales'].'</td>'; echo '</tr>'; } echo '</table>'; sqlsrv_close($conn); Can somebody help me with this? Thank you I have a problem . I 've been trying for a long time to make an update for php mysql to change the data. but every time I do not manage to make it work with a form. but it works if I only if I put this ($ sql = "UPDATE users SET username = 'value' WHERE id = 10 " ; ) so it only works when I put the value of the id. but I want in an html form to indicate what I want to change and what id goes. but I have tried so long that I do not feel like I so want someone help me. make the same database and same as my records and make the code and test it if it works show me please my database name : web test my table called : users my records are called : id int ( 11) AUTO_INNCREMENT username , varchar ( 255 ) password , varchar ( 255 ) first_name , varchar ( 255 ) last_name , varchar ( 255 ) email, varchar ( 255 ) Age, int ( 11) Look, my update.php is like this now <?php $servername = "localhost"; $username = "root"; $password = "....."; $dbname = "webtest"; $conn = new mysqli($servername, $username, $password, $dbname); if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "UPDATE users SET password='cotton candy' WHERE id=10"; if ($conn->query($sql) === TRUE) { echo "Record updated successfully"; } else { echo "Error updating record: " . $conn->error; } $conn->close(); ?> but now i have still have to go into the php file to change the valeu or the id but i looked on site and youtube how to put it in a simple html form but it still does not work. i want it in a html from. I want that when I enter the ID that the data of the user appears and that I can change any valeu separately. Hi there, Im fairly new at php and mysql but nevertheless im trying to build a web based campaign game for starwars minatures boardgame. Its fairly straightforward and going well.. However ive been thinking about how it will work and have stumbled across a possible problem (because of my limited craft at programming). I want to have a single form that updates all records in the tables, this would simulate an "end of turn" button. Im sure i can do this if doing stuff in the game (e.g. move, create , modify, delete, fleets/ships and auto increment ships hulls simulating repair) if it was done on the same page. However i wanted to to initiate some of these adjustments in their respective pages (fleet.php, planets.php, ships.php etc) and then once the user is happy to click the end turn button somewhere which would update all of these things at the same time.. Is this possible at all??? If anybody could help that would be brilliant. Thank you p.s. if anybody wants a copy of the finished product when its complete, your most welcome. Hi ive been stuck for a while now and i just cant get my head around it so if you could help i'd be well chuffed. I'm trying to update multple rows in a table depending upon the results of another. I have a form that enables me to update a table called fleet. Another table called ships is realted to the fleet table as each ship is in a fleet: fleet ----- Fleetname* Location Detected ships ------ ShipID* Fleetname * Shipname The particular fleet i am editing is parsed as a url parameter. I made a query to search for all the ships that are in the fleet i am editing: Code: [Select] $colname_ShipsInfleet = "-1"; if (isset($_GET['recordID'])) { $colname_ShipsInfleet = (get_magic_quotes_gpc()) ? $_GET['recordID'] : addslashes($_GET['recordID']); } mysql_select_db($database_swb, $swb); $query_ShipsInfleet = sprintf("SELECT * FROM ships WHERE FleetName = %s", GetSQLValueString($colname_ShipsInfleet, "text")); $ShipsInfleet = mysql_query($query_ShipsInfleet, $swb) or die(mysql_error()); $row_ShipsInfleet = mysql_fetch_assoc($ShipsInfleet); $totalRows_ShipsInfleet = mysql_num_rows($ShipsInfleet); It searched the ships WHERE the FleetName (which is the primary key of the fleet table) is parsed as a url parameter. The appropriate ship records that are generated i want to use so a field can be updated. For example im updating a fleet record and and setting the location (Planet Name) to a different value. I want the Ship records that are of that particular fleet to update a field (PlanetName) in ship table when the fleet table is updated. Code: [Select] if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) { $updateSQL = sprintf("UPDATE ships WHERE ShipID = $row_ShipsInfleet['ShipID'] SET PlanetName=%s", GetSQLValueString($_POST['select'], "text")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($updateSQL, $swb) or die(mysql_error()); $updateSQL = sprintf("UPDATE fleet SET PlanetName=%s, Detected=%s, Faction=%s WHERE FleetName=%s", GetSQLValueString($_POST['select'], "text"), GetSQLValueString(isset($_POST['checkbox']) ? "true" : "", "defined","1","0"), GetSQLValueString($_POST['hiddenField2'], "int"), GetSQLValueString($_POST['hiddenField'], "text")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($updateSQL, $swb) or die(mysql_error()); I'm really not sure how to proceed here so please if you can help me out that would be ace. Thank You Hi there, hope have some help. I have a form where a user select time and days of the week (monday, tuesday..) that he is available. The insert script works fine, it insert and the days of week he checked in the table, the only problme is when i try to update each of them.
I used this code above, but is not working, instead of updating/inserting days that is selected is inserting multi-records with the same day of the week value.
here it is:
foreach($weekDay as $DaysofWeek){
$sql_days = "UPDATE available SET day_time = '$day_time', week_day = '$DaysofWeek' WHERE user_id = '$id_user'";
$update_availability = mysql_query($sql_days);
}
Hi is it possible to update multiple records of the same table using a single hidden field with a while loop??? For example: Code: [Select] <?php if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) { $updateSQL = sprintf("UPDATE ships SET HealthA=%s WHERE ShipID=%s", GetSQLValueString($_POST['healtha'], "int"), GetSQLValueString($_POST['shipid'], "text")); ?> <input name="healtha" type="hidden" id="healtha" value="<?php echo $row_Ships['HealthA'] + 1; ?>" /> <input name="shipid" type="hidden" id="shipid" value="<?php while($row = mysql_fetch_assoc($Ships)){ echo $row_Ships['ShipID']; }?>" /> If its not possible what else could i do to achieve this please? Thank you I am having trouble showing reports for a given date range. Currently if I specify something like 11/03/2010 to 11/05/2010 I get results for all years within that month and day such as I may get results for 11/03/2008 11/03/2009 11/03/2010 11/04/2008 11/04/2009 11/04/2010 11/05/2008 11/05/2009 11/05/2010. I am using the following code $result = mysql_query("SELECT * FROM report WHERE date>='$date_begin' and date<='$date_end' ORDER BY 'date'",$db); I use the following format in my date feild mm/dd/yyyy My script is finally working as intended, but I want to add some additional data results. I am trying to resolve how I can display a count of ONLY the records updated by my query: // START :: Query to replace matches mysql_query("UPDATE orig_codes_1a AS a JOIN old_and_new_codes_1a AS b ON concat(a.orig_code_1, a.orig_code_2) = concat(b.old_code_1, b.old_code_2) SET a.orig_code_1 = b.new_code_1, a.orig_code_2 = b.new_code_2") or die(mysql_error()); // END :: Query to replace matches In this query I count ALL records selection: // START :: Create query to be displayed as final results of original codes table. $result = mysql_query("SELECT * FROM orig_codes_1a") or die(mysql_error()); I want to display a count on this part of the query: ....concat(a.orig_code_1, a.orig_code_2) = concat(b.old_code_1, b.old_code_2).... Hi i have this simple update form and scrip but somehow it doesnt seem to be update the field on the database can someone help out please. The html form is the second form bellow where the action send to status_update.php HTML FORM Code: [Select] <?php include("../header.html"); ?> <?php include("header_news.html"); extract($_REQUEST,EXTR_SKIP); ?><?php /* print("sfilm_refnum = $sfilm_refnum<BR>"); print("sfilm_addr01 = $sfilm_addr01<BR>"); print("sfilm_postcode = $sfilm_postcode<BR>"); print("Film Client = $fclient<BR>"); */ ?> <form id="search" action="list.php" method="post" name="search"> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td align="right" width="140"></td> <td width="320"><span class="hofblack10"> </span> </td> <td align="center" width="100"><input type="hidden" name="lstart" value="<?php print("$lstart"); ?>" /><input type="hidden" name="lend" value="<?php print("$lend"); ?>" /><input type="hidden" name="lamount" value="<?php print("$lamount"); ?>" /></td> <td align="center" width="100"></td> <td align="right"></td> </tr> </table> </form> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#4050c4"> <tr> <td width="60" class="hofwhite10">action</td> <td width="140"><span class="hofwhite14">DATE</span></td> <td width="80"><span class="hofwhite14">ID</span></td> <td><span class="hofwhite14">News Titile</span></td> <td width="100"><span class="hofwhite14">Status</span></td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table><table width="780" border="0" cellspacing="0" cellpadding="4"><tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> <tr height="0"> <td width="60" height="0"></td> <td width="80" height="0"></td> <td height="0"></td> <td align="right" width="120" height="0"></td> </tr> </table> <?php //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select DATABASE."); $query2="SELECT * FROM news WHERE !(news_status='deleted')"; $result2 = mysql_query($query2) or die("Couldn't execute QUERY - Select NEWS Qty"); $fqty = mysql_num_rows($result2); //SELECT or FIND the same USERNAME $query3="SELECT * FROM news WHERE !(news_status='deleted') ORDER BY news_id DESC"; $result3 = mysql_query($query3) or die("Couldn't execute QUERY - Select NEWS"); while ($row = mysql_fetch_array($result3)) { $news_id = $row['news_id']; $news_title = $row['news_title']; $news_story = $row['news_story']; $news_image = $row['news_image']; $news_image_caption = $row['news_image_caption']; $news_image_link = $row['news_image_link']; $news_date_day = $row['news_date_day']; $news_date_month = $row['news_date_month']; $news_date_year = $row['news_date_year']; $news_status = $row['news_status']; $news_website = $row['news_website']; $news_date_created = $row['news_date_created']; $news_date_modified = $row['news_date_modified']; ?> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td width="60"><span class="hofblack10"> <?php if($news_status=="deleted"){ print("<a class='hifblack10'>deleted</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>edit</a>"); } ?> </span></td> <td width="140"><span class="titlegrey12"> <?php if(!$news_date_day) { echo "00"; } else{ echo $news_date_day; } echo "/"; if(!$news_date_month) { echo "00"; }else{ echo $news_date_month; } echo "/"; if(!$news_date_year) { echo "0000"; }else{ echo $news_date_year; } ?> </span></td> <td width="80"><span class="titlegrey12"><?php print("$news_id"); ?></span> </td> <td><?php if($news_status=="deleted") { print("<class='hofblack10'>$news_title</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>$news_title</a>"); } ?></td> <td width="100"> <form id="list_update" action="status_update.php" method="post" name="list_update"> <select name="newnstatus" size="1"> <option <?php if($row['news_status'] == "") { print("selected"); } ?> selected="selected" value="">Status...</option> <option <?php if($row['news_status'] == "on") { print("selected"); } ?> value="on">On</option> <option <?php if($row['news_status'] == "off") { print("selected"); } ?> value="off">Off</option> <option <?php if($row['news_status'] == "deleted") { print("selected"); } ?> value="deleted">Delete</option> </select> <input type="hidden" name="nstatus" value="<?php echo $row[news_status]; ?>" /> <input type="hidden" name="id" value="<?php echo $row[news_id]; ?>" /> <input type="submit" name="update" value="update" /> </form> </td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table> <?php } mysql_close($connection);//}?> <table width="780" border="0" cellspacing="0" cellpadding="4"> <tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> </table><?php // include("list_navigation.html"); ?> <?php include("../footer.html"); ?> </div></body></html> The action script php Code: [Select] <?php /* echo "fstatus: ".$fstatus."<BR>"; echo "id: ".$id."<BR>"; echo "fclient: ".$fclient."<BR>"; echo "newfstatus: ".$newfstatus."<BR>";*/ //set the date of agreement $timestamp = date('l jS \of F Y h:i:s A'); //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select FILMS DATABASE."); // All appears well, so enter into database $query= "UPDATE news SET news_status = '$newnstatus' WHERE news_id='$id'"; $result = mysql_query($query) or die("could not execute query - Update FILMS Record to DB"); //setup an email to the Admin @ hof, w/o attachment $emailto="xx@xxx.co.uk"; $emailfrom="no-reply@xxxx.co.uk"; $emailsubject="xx Record Updated"; $emailmessage="Hello Registrar\n\n"; $emailmessage.="News ID: ".$id."\n"; $emailmessage.="Updated on: ".$timestamp."\n\n"; $emailmessage.="Status was: ".$nstatus."\n"; $emailmessage.="Status now: ".$newfnstatus."\n"; $emailmessage.="Thank you,\n\n"; $emailmessage.="Web Site ROBOT\n"; $emailmessage.="(Administrator)\n"; $emailmessage.="xxx.co.uk | xxx.biz\n"; $emailmessage.="----------------------------------------------\n"; $emailmessage.="e. http://www.xxx.co.uk/contact.php\n"; $emailmessage.="w. http://www.xxx.co.uk\n"; $emailheader="From: xxx.co.uk<$emailfrom>"; $emailheader .= 'Cc: xxx@xxx.co.uk'."\r\n"; $emailheader .= 'Bcc: xxx@xxxxx.co.uk'."\r\n"; $ok=mail($emailto,$emailsubject,$emailmessage,$emailheader); mysql_close($connection); if ($ok) { header("Location: list.php"); /* Redirect browser */ exit; } else { $errmsg="There was a problem, please try later or telephone us direct."; $errsta="1"; include("edit_error.html"); //echo "<p>Mail could not be sent. Sorry!</p>"; exit; } ?> Thanks in advance Can anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. I created this code to upload a member's main picture on his member page on website. I'll only include the query part of the code since that's what is relevant to my problem. The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page. If a picture already exists, then the script replaces the old picture with the new one upon upload. But for whatever reason I don't understand, when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select] $query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"; $result = @mysql_query($query); $num = @mysql_num_rows($result); if ($num> 0) { //Update the image $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); $_SESSION['error'] = "File updated successfully."; //really should be session success message. header("Location: member.php"); exit; } else { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); $_SESSION['error'] = "File uploaded succussfully."; //really should be session success message. header("Location: member.php"); } So can anyone tell me what the problem is? Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup? Appreciate your responses in advance. Good morning. I am looking fo some help with an update script to update all rows in a table. This is what I have for a form and all looks well. form.php <?php // run the query and put the results in an array variable called $result $result = mysql_query("SELECT * FROM table ORDER BY 'id', 'title', 'text', 'number'"); print "<form method='post' action='update.php'> <table width='100%' border='0' cellspacing='1' cellpadding='1'><tr> <td align='center'><strong>ID</strong></td> <td align='center'><strong>Title</strong></td> <td align='center'><strong>text</strong></td> <td align='center'><strong>Number</strong></td> </tr>\n"; // start a loop to print all of the courses with their book information // the mysql_fetch_array function puts each record into an array. each time it is called, it moves the array counter up until there are no more records left while ($Update = mysql_fetch_array($result)) { // start displaying the info; the most important part is to make the name an array (notice bookinfo[$i]) print "<td align='center'><p>{$Update['id']}</p></td>\n"; print "<td align='center'><input type='text' name='title' value='{$Update['title']}' /></td>"; print "<td align='center'><input type='text' size='40' name='text' value='{$Update['text']}' /></td>\n"; print "<td align='center'><input type='text' size='40' name='number' value='{$Update['number']}' /></td>\n"; print "</tr>\n"; // add 1 to the count, close the loop, close the form, and the mysql connection } print "<tr> <td colspan='4' align='center'><input type='submit' value='submit' />"; print "</td> </tr> </table> </td> </tr> </form> </table>"; print "</tr>\n"; ?><br /><br /> My question is. How do I update this info into the database with the proper info. ie. Update.php? As the title says I need help with multiple update system.. Can't really get it to work at all >.< Here's some code: $selectt = mysql_query("SELECT * FROM exercises WHERE user='" . $_SESSION["user"] . "' AND exname='" . $_GET["edit"] . "'"); echo '<form method="POST" action="exercises.php?edited">'; echo '<div id="newexx">'; while($raw = mysql_fetch_array($selectt)) { echo '<input type="text" name="up[' . $raw["id"] . ']" value="' . $raw["swe"] . '">'; echo '<input type="text" name="up1[' . $raw["id"] . ']" value="' . $raw["eng"] . '"><br>'; echo '<input type="hidden" name="id[' . $raw["id"] . ']">'; } echo '</div>'; echo '<input type="submit" value="Update Exercise">'; echo '</form>'; if(isset($_GET["edited"])) { $swe = $_POST["up"]; $eng = $_POST["up1"]; $id = $_POST["id"]; foreach($id as $value => $index) { $update = "UPDATE exercises SET swe='".$swe."', eng='".$eng."' WHERE id='".$index."'"; mysql_query($update); } Would be thankful for reply! Hi Guys, I want my UPDATE function from the code below to only update those fields that are NOT empty - if they are empty on submit then do not update or change any values from that field. I know that sounds odd, but with my file fields, when I submit to change something else at a later date it will overwrite the photo, download1,2 & 3 values and as a result I loose my files from the mysql table. Cheers, S <?php include('config.php'); if (isset($_GET['Ter']) ) { $ter = (int) $_GET['Ter']; if (isset($_POST['submitted'])) { //Photo & Document Upload Upload $timestamp_photo = time(); $timestamp_download1 = time(); $timestamp_download2 = time(); $timestamp_download3 = time(); //This is the directory where the files will be saved //Photos $photo_target = "images/"; $photo_target = $photo_target .$timestamp_photo. basename( $_FILES['photo']['name']); //Documents $download_target = "documents/"; $download_target1 = $download_target .$timestamp_download1. basename( $_FILES['download1']['name']); $download_target2 = $download_target .$timestamp_download2. basename( $_FILES['download2']['name']); $download_target3 = $download_target .$timestamp_download3. basename( $_FILES['download3']['name']); //This gets all the other information from the form $photo = ($_FILES['photo']['name']); $download1 = ($_FILES['download1']['name']); $download2 = ($_FILES['download2']['name']); $download3 = ($_FILES['download3']['name']); //Pause Photo/Document Upload foreach($_POST AS $key => $value) { $_POST[$key] = mysql_real_escape_string($value); } $sql= "UPDATE `ter` SET `Ter` = '{$_POST['Ter']}' , `BranchName` = '{$_POST['BranchName']}' , `BranchAddress` = '{$_POST['BranchAddress']}' , `BranchTel` = '{$_POST['BranchTel']}' , `BranchEmail` = '{$_POST['BranchEmail']}' , `BranchLink` = '{$_POST['BranchLink']}' , `Theme` = '{$_POST['Theme']}' , `LocalInfo` = '{$_POST['LocalInfo']}' , `BranchInfo` = '{$_POST['BranchInfo']}' , `photo` = '$timestamp_photo{$_FILES['photo']['name']}' , `download1` = '$timestamp_download1{$_FILES['download1']['name']}' , `download1name` = '{$_POST['download1name']}' , `download2` = '$timestamp_download2{$_FILES['download2']['name']}' , `download2name` = '{$_POST['download2name']}' , `download3` = '$timestamp_download3{$_FILES['download3']['name']}' , `download3name` = '{$_POST['download3name']}' WHERE `Ter` = '$ter' "; mysql_query($sql) or die(mysql_error()); //Unpause Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $photo_target)) { echo "<br />The file ".$timestamp_photo. basename( $_FILES['photo']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download1']['tmp_name'], $download_target1)) { echo "<br />The file ".$timestamp_download1. basename( $_FILES['download1']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download2']['tmp_name'], $download_target2)) { echo "<br />The file ".$timestamp_download2. basename( $_FILES['download2']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download3']['tmp_name'], $download_target3)) { echo "<br />The file ".$timestamp_download3. basename( $_FILES['download3']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload echo (mysql_affected_rows()) ? "<br />Edited Branch.<br />" : "<br />Nothing changed. <br />"; } $row = mysql_fetch_array ( mysql_query("SELECT * FROM `ter` WHERE `Ter` = '$ter' ")); ?> I'm new to PHP and I was able to figure out how to populate data from my database into my text fields. I am trying to add the update information to the same php file; however, I am now receiving errors within the data I was able to populate,
Notice: Undefined variable: stmt in C:\xampp\htdocs\Cust_App\update.php on line 47 and errors with the Update statement
Notice: Undefined variable: stmtupdate in C:\xampp\htdocs\Cust_App\update.php on line 96 I had defined the customerID variable above in the code, but it isn't being captured from here. I tried setting up this query like the one which gathered the data, but I'm off by a little bit. I would like the option to be able to update all fields. Any help is appreciated. I'm trying to learn as I may get asked to update other forms in the future. (new boss asks a lot)
<?php
require_once('database.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<!-- the head section -->
<head>
<title>My Guitar Shop</title>
<link rel="stylesheet" type="text/css" href="main.css" />
</head>
<!-- the body section -->
<body>
<div id="page">
<div id="header">
<h1>SportsPro Technical Support</h1>
<p>Sports management software for the sports enthusiast.</p></h1>
</div>
<div id="main">
<h1>View/Update Customer</h1>
<form action="update.php" method="get" >
<?php
if(isset($_GET['customerID'])) {
$customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT);
$sql = "SELECT * FROM customers WHERE customerID =$customerID ";
$stmt = $db->query($sql);
}
?>
<div id="content">
<!-- display a table of products -->
<h2>Customers</h2>
<form method = "edit">
<?php foreach ($stmt as $cust) { ?>
<div>
<label>First Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['firstName']; ?>">
</div><br>
<div>
<label>Last Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['lastName']; ?>">
</div><br>
<div>
<label>Address</label>
<input type="text" name="address" class ="form-control" value ="<?php echo $cust['address']; ?>">
</div><br>
<div>
<label>City</label>
<input type="text" name="city" class ="form-control" value ="<?php echo $cust['city']; ?>">
</div><br>
<div>
<label>State</label>
<input type="text" name="state" class ="form-control" value ="<?php echo $cust['state']; ?>">
</div><br>
<div>
<label>Country</label>
<input type="text" name="countryCode" class ="form-control" value ="<?php echo $cust['countryCode']; ?>">
</div><br>
<div>
<label>Zip Code</label>
<input type="text" name="postalCode" class ="form-control" value ="<?php echo $cust['postalCode']; ?>">
</div><br>
<div>
<label>Email </label>
<input type="text" name="email" class ="form-control" value ="<?php echo $cust['email']; ?>">
</div><br>
<div>
<label>Phone Number </label>
<input type="text" name="phone" class ="form-control" value ="<?php echo $cust['phone']; ?>">
</div><br>
<div>
<label>Password </label>
<input type="text" name="password" class ="form-control" value ="<?php echo $cust['password']; ?>">
</div><br>
<div>
<?php }
?>
<input type="Submit" name="Update_Data" value="Update Data"></input>
<?php
$sql2 = "UPDATE customers SET firstName = ". $stmtupdate['firstName']." WHERE customerID =$customerID ";
$stmtupdate = $db->query($sql2);
?>
</div>
</div>
<div id="footer">
<p>
© <?php echo date("Y"); ?> SportsPro, Inc.
</p>
</div>
</div><!-- end page -->
</body>
</html>
I am have a query with a limit of 3 i want it to echo the first two in one li class and the 3 in another li class. This is what i have, but i know the logic is not right, but i cant figure it out Code: [Select] </div> <?php echo "<ul class='services-list'>"; //echo "<li class='bubble'>"; $i = 1; foreach ($rows_class as $record_class ){ ?> <li class="bubble"><a href="viewclass.php?class_id=<?php echo base64_encode($record_class[class_id]) ?>" /><h6 class="title"><img src="./images/services/picture-services.png" class="picture" alt="logo" /><? echo $record_class[class_title]; ?></h6></a><p><?php $string = $record_class['description']; echo substr(strip_tags($string), 0, 200); ?></p> <?php if( $i % 2 === 0 && $record_class !== end($rows_class) ) { echo "</li>\n<li class='bubble last'>\n";?> <?php } elseif ( $record_class === end($rows_class) ) { echo "</li>\n "; } $i++; } ?> </ul> Howdy, The following code wil geenrate a dynamic pull-down list based on column values. Can someone help me tweak it so that is will NOT display a duplicate record value. That is, if the sponsors values in the table were Hart, Michaels, Michaels, Morella ...it would only display Hart, Michaels, Morella in the pull-down menu. <form name="form0"> <? $result = @mysql_query("select distinct sponsor from table ORDER BY sponsor ASC"); if (mysql_num_rows($result) > 0) { print "<select name=\"link\">"; ?> <option <?php if(empty($_GET['sponsor'])){ echo "selected=\"selected\""; } ?> value="<? echo "$page_name" ?>">SELECT A SPONSOR</option> <? while ($row = mysql_fetch_array($result)) { print "<option "; if($_GET['sponsor'] == $row['sponsor'] ){ echo "selected=\"selected\""; } print " value=\"index?sponsor=" . $row['sponsor'] . "\">" . $row['sponsor'] . "</option>\n"; } print "</select>"; } ?> </form> Thank you. ~Wayne |
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