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PHP - Using An Authcode Stored In A Cookie To Automatically Log A User In.
I am trying to create a remember me checkbox for the login of my CMS.
What I am trying to achieve is that whenever a user logs in with the checkbox ticked and auth code is created and stored in a cookie and also the database under their user info row. When I user closes their browser without logging out and then returns to the CMS a few days later etc I am trying to run some code straight away if they get redirected to the login page. The code will check to see if the auth code cookie exists, if it does it gets checked against the database records, if a match is found then log that user in. If it doesn't do nothing until the user uses the login form. I have written what I though was the perfect solution but it never seems to automatically log the user in, even if they haven't logged out. Some direction in this matter would be very helpful, thank you. I would also like to know if there is a way of using php to stop my session getting cleared by the trash collector after some inactivity? Login.php (I am using PHpass for the password hashing) Code: [Select] <?php include ('functions.php'); ?> <?php get_header('login'); ?> <div id="login-result"> <?php $redirect = htmlspecialchars(mysql_real_escape_string(addslashes($_GET['redirect']))); if(isset($_COOKIE['authcode'])){ connect(); $authcookie = htmlspecialchars(mysql_real_escape_string(addslashes($_COOKIE['authcode']))); $sql = "SELECT uid, username, firstname, lastname, role FROM usersT WHERE authcode='$authcode'"; $result = mysql_query($sql); $count = mysql_num_rows($result); $row = mysql_fetch_array($result); $uid = $row['uid']; $username = $row['username']; $fname = $row['firstname']; $lname = $row['lastname']; $role = $row['role']; if($count==1){ $sql2 = "UPDATE usersT SET status = '1' WHERE uid = '$uid'"; $result2 = mysql_query($sql2); if($result2){ session_register("uid"); session_register("uname"); session_register("ulevel"); $_SESSION["uid"] = $uid; $_SESSION["username"] = $username; $_SESSION["uname"] = $fname; $_SESSION["ufullname"] = $fname . " " .$lname; $_SESSION["urole"] = $role; if(!empty($redirect)) { header( 'Location: '. $redirect ) ; exit(); } else { header( 'Location: index.php' ) ; exit(); } } } } ?> <?php if (isset($_POST['admin_login'])){ if(isset($_POST["username"]) && isset($_POST["password"])){ connect(); $username_p = htmlspecialchars(mysql_real_escape_string(addslashes($_POST["username"]))); $password_p = htmlspecialchars(mysql_real_escape_string(addslashes($_POST["password"]))); if (strlen($password_1) < 73) { //Password hashing $sql3 = "SELECT password FROM usersT WHERE username='$username_p'"; $result3 = mysql_query($sql3); $row3 = mysql_fetch_array($result3); require("inc/password-hash.php"); $hasher = new PasswordHash(8, false); $stored_hash = "*"; $stored_hash = $row3['password']; $check = $hasher->CheckPassword($password_p, $stored_hash); if($check){ $sql4 = "SELECT uid, username, firstname, lastname, role FROM usersT WHERE username='$username_p'"; $result4 = mysql_query($sql4); $row4 = mysql_fetch_array($result4); $uid = $row4['uid']; $username = $row4['username']; $fname = $row4['firstname']; $lname = $row4['lastname']; $role = $row4['role']; $authcode = random(30); $sql5 = "UPDATE usersT SET status = '1', authcode = '$authcode' WHERE uid = '$uid'"; $result5 = mysql_query($sql5); if($result5){ session_register("uid"); session_register("uname"); session_register("ulevel"); $_SESSION["uid"] = $uid; $_SESSION["username"] = $username; $_SESSION["uname"] = $fname; $_SESSION["ufullname"] = $fname . " " .$lname; $_SESSION["urole"] = $role; if(isset($_POST['remember'])) { setcookie("authcode", $authcode, time() + 86400 * 365 * 2); } // Check if the user wants to be remembered. if(!empty($redirect)) { header( 'Location: '. $redirect ) ; exit(); } // Check if the user has been redirected from another page. else { header( 'Location: index.php' ) ; exit(); } } // Check if the users status has been updated. else { echo "<div class=\"error rounded5 shadow\">User status couldn't be updated!</div>"; } } // Check the entered password against the stored hash. else { echo "<div class=\"error rounded5 shadow\">Invalid username or password!</div>"; } } // Checked the character length of the password. else { echo "<div class=\"error rounded5 shadow\">Password must be 72 characters or less!</div>"; } } // Check both fields have been filled in. } // Check the user has submitted the data. ?> </div><!-- / login-results --> <div id="login" class="rounded5 shadow"> <form name="loginform" id="loginform" action="<?php $_SERVER['PHP_SELF']; ?>" method="post"> <p> <label for="username">Username<br> <input type="text" name="username" id="username" class="rounded5" value="<?php echo $username_p; ?>" size="20" tabindex="10" /></label> </p> <p> <label for="password">Password<br> <input type="password" name="password" id="password" class="rounded5" value="<?php echo $password_p; ?>" size="20" tabindex="20" maxlength="72" /></label> </p> <p class="submit"> Keep me logged in <input type="checkbox" name="remember" id="remember" <?php if(isset($_COOKIE['remembered'])){ echo "selected=\"selected\""; } ?> /><br /><br /><a href="" class="left">Lost your password?</a> <input type="submit" name="admin_login" id="admin_login" class="btn rounded10 right" value="Log In" tabindex="100" /> </p> <div class="cleaner"></div><!-- / cleaner --> </form> </div><!-- / login--> <?php get_footer('login'); ?> Logout.php Code: [Select] <?php session_start(); include ('functions.php'); connect(); $uid = mysql_real_escape_string($_SESSION['uid']); $sql = "UPDATE usersT SET status = '0', authcode = '' WHERE uid = '$uid'"; $result = mysql_query($sql); if($result) { session_unset(); session_destroy(); setcookie("authcode", $authcode, time() - 86400 * 365 * 2); header("location:" . get_option('home') . "/login.php"); exit(); } else { exit(); } ?> Redirect Code Code: [Select] <?php session_start(); $url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; $uid = $_SESSION['uid']; if (!isset($uid)) { header('location:login.php?redirect='.$url); exit(); die(); } ?> Similar TutorialsOkay, so I have a database with user log on info, and unique ID's. How to I allow the user to save info from a form, and be able to log out and come back and log on to see/edit that info. Thanks! Hi all, I've got a website for an event, each team have their details on a page which are recalled from a SQl database. But I'm wanting to create a password input box for each team, so when they enter the correct password they are taken to a page containing forms where they can edit the team details. Here is the page with the users details on where they anter the password: http://www.wharncliffenetwork.co.uk/wrc/entered/team.php?id=8 I'm not sure how to code it, Can an IF statement be used? Anyone got any pointers? I'f been unsuccessful in finding a tutorial or something similar. Hope that makes sense :S Cheers. Hi there, im hoping someone can help me with this. What i’m trying to do is prevent users from voting twice with cookies, ive tried to set several myself but none of them have worked. Any help would be amazing. Thanks. EDIT: unsure why its formatted this way. how to fix?
<?php include 'functions.php'; // Connect to MySQL $pdo = pdo_connect_mysql(); // If the GET request "id" exists (poll id)... if (isset($_GET['id'])) { // MySQL query that selects the poll records by the GET request "id" $stmt = $pdo->prepare('SELECT * FROM polls WHERE id = ?'); $stmt->execute([$_GET['id']]); // Fetch the record $poll = $stmt->fetch(PDO::FETCH_ASSOC); // Check if the poll record exists with the id specified if ($poll) { // MySQL query that selects all the poll answers $stmt = $pdo->prepare('SELECT * FROM poll_answers WHERE poll_id = ?'); $stmt->execute([$_GET['id']]); // Fetch all the poll anwsers $poll_answers = $stmt->fetchAll(PDO::FETCH_ASSOC); // If the user clicked the "Vote" button... if (isset($_POST['poll_answer'])) { // Update and increase the vote for the answer the user voted for $stmt = $pdo->prepare('UPDATE poll_answers SET votes = votes +1 WHERE id = ?'); $stmt->execute([$_POST['poll_answer']]); // Redirect user to the result page header ('Location: result.php?id=' . $_GET['id']); exit; } } else { die ('Poll with that ID does not exist.'); } } else { die ('No poll ID specified.'); } ?> <?=template_header('Poll Vote')?> <div class="content poll-vote"> <h2><?=$poll['title']?></h2> <p><?=$poll['des']?></p> <form action="vote.php?id=<?=$_GET['id']?>" onSubmit="disable()" method="post"> <?php for ($i = 0; $i < count($poll_answers); $i++): ?> <label> <input type="radio" name="poll_answer" value="<?=$poll_answers[$i]['id']?>"<?=$i == 0 ? ' checked' : ''?>> <?=$poll_answers[$i]['title']?> </label> <?php endfor; ?> <div> <input type="submit" name="submit" value="Vote"> <a href="result.php?id=<?=$poll['id']?>">View Result</a> </div> </form> </div> <?=template_footer()?>
Edited July 1, 2020 by requinix cleaning up post I'm an experienced programmer with several languages (COBOL, REXX, Java, Javascript, etc.) under my belt over many years but I know very little about PHP. I dabbled in it a bit a year or two back and got it to do what I wanted to do but I'm not sure how to do what I currently need.
A bit of context: I have designed a website where the user can choose between various page styles; each style invokes different CSS to give them a different visual experience of the site. They can select the style they want via View/Style in Internet Exploder and View/Page Style in Firefox but that preference is only remembered as long as they're on that page. As soon as they move to another page on the site, they have to choose the alternate style again or live with the default style. I want them to be able to select that preference ONCE, the store it in a cookie specifically for them, then keep using that style every time they visit the site. (Naturally, I want them to be able to change the style and then remember the new style as well.) There will be many visitors and each will want that same capability. I currently don't require any login to the site. (I'm toying with password-protecting some of the site down the road but that's not a factor in this page style thing that I'm talking about here.
Now, my questions.
I've found a variety of short articles describing how to use setCookie() to create the cookie (and delete it later) and getCookie() or the newer echo $_COOKIE["name"] to determine the cookie value. However, I am NOT seeing anything that says where I put the code to set and/or read the code within my web pages. I would really appreciate an explanation of that! I expect to write short fragments of php code to do those jobs which I will then imbed within my web pages via SSI (Server Side Includes). Is that reasonable or is there a better way?
Also:
1. When the user clicks on the desired Style in the View/Style menu, how do I detect what choice they made?
2. Should the name of the cookie be something like "pageStyle" or should it be something that uniquely identifies the user so that the right cookie is retrieved when the come back? If the latter, what value should I use and how should I obtain it? I assume that something unique about the user obtained from their headers is far better than displaying a dialog and asking them for some unique identifier.
I'd rather stay away from Javascript in any of this functionality since I can't rely on it being turned on.
One quick aside while I'm here. Does anyone know how to change the page style if visitors use Google Chrome or Opera? I can't even FIND options for changing the page style in my copies of those two browsers and both are current versions. Do they not support differing page styles at all or do they just hide the technique to choose the style very effectively?
--
Henry
wrote a stored procedure this morning and i don’t know how to get the values out of it through a class function in php or phpmyadmin. here is what i wrote :
public function totalProcedures($friend_name,$session_id)
{ /* *query to fetch stored procedure */
try {
//executing the stored procedure
$sql_sp="CALL timeline (:friend, :session,@updates, @group_posts)";
$stmt_sp= $this->_db->prepare($sql_sp);
$stmt_sp->bindValue(":friend",$friend_name);
$stmt_sp->bindValue(":session",$session_id);
$stmt_sp->execute();
$rows=$stmt_sp->fetch(PDO::FETCH_ASSOC);
$stmt_sp->closeCursor(); // closing the stored procedure
//trying to get values from OUT parameters.
$stmt_sp_2=$this->_db->prepare("select @updates,@group_posts");
$stmt_sp_2->execute();
return $stmt_sp_2->fetch(PDO::FETCH_ASSOC);
} catch (PDOException $ei)
{
echo $ei->getMessage(); }
}
can someone helpme how to get results. here is the storedprocedu DELIMITER $$ CREATE DEFINER=`root`@`localhost` PROCEDURE `timeline`(IN `friend` VARCHAR(255), IN `session_id` VARCHAR(255), OUT `updates` VARCHAR(62555), OUT `group_posts` VARCHAR(62555)) BEGIN select * FROM updates where author in (friend,session_id) order by time desc limit 5; select * FROM group_posts where author_gp in (friend,session_id) order by pdate desc limit 5; END$$ DELIMITER ; i get the result in php myadmin as follows:
how do i do this inside a php class function.
CALL timeline('shan2batman','aboutthecreator', @updates, @group_posts);
Often times I need to convert between PHP Arrays, MySQL, XML, JSON sqlite etc. Lately I've been just building PHP arrays with all the data. Its a big hassle though when theres a lot of data. I'm thinking I should have one central location that I store data in, then export to other formats from there, but I dont know what that central location should be. I like MySQL because I'm used to it. Sometimes its not an option though, like if I need to make a really light script, I dont want the hassle of connecting to MySQL. Would XML be the best place to store data, then from the XML file I can convert it to whatever format I want?
I'm working on a project and cannot figure out why one piece of code works in one project but not in this one. Code: [Select] $username = "voltageme5"; $result = $mysqli->query("call usernameCheck($username)"); returns string(43) "Unknown column 'voltageme5' in 'field list'" Here is the stored routine: Code: [Select] CREATE PROCEDURE `database`.`table` (IN memUsername varchar(45)) BEGIN select count(*) as total from members where username = memUsername; END Whats weird is that in the PHP code if i replace the variable with a string, it works. It's only with the variable in the call that it errors out like that. I'm new to this stored procedure thing so I'm sure I'm missing something stupid. The path to a image is stored in a variable and I need to display this image in the email. Can someone help me. This is my current attempt and nothing is happening. But the variable passes the URL correctly. Code: [Select] <TABLE BORDER='0'> <TR> <TD align='left' width='370'><img src='".$dis_logoimg."' width='370' height='86' /></TD> </TR> </TABLE> Hi Everyone, I have this php page that runs couple of MS SQL stored procedures to fetch me values from SQL Server, however I have run into a problem where not more then 2 stored procedures are executed at same time. For instance below mentioned code only fetches me values for 1st and 2nd SP's. If I need values from the 3rd stored procedure then I would have to comment either one of the first two stored procedure. Can someone please tell me what is that I am doing wrong. I am relatively new to PHP, so please be gentle. Any help would be highly appreciated. Thanks.
<?php
if($conn = mssql_connect('host', 'user', 'pass')) echo 'Connected to SQLEXPRESS<BR>';
if(mssql_select_db("database",$conn)) echo 'Selected DB: SomeDatabase<BR>';
$variable1=something;
$sql_statement = mssql_init("stored_procedure1 '$variable1'", $conn);
$result=mssql_execute($sql_statement);
$x=0;
while ($row = mssql_fetch_assoc($result))
{
$column2[$x]= $row['column2'];
$column1= $row['column1'];
$x++; }
echo "Value 1: $column1 </br>";
echo "Value 2: $column2[0] </br>";
echo "Value 3: $column2[1] </br>";
echo "Value 4: $column2[2] </br>";
echo "Value 5: $column2[3] </br>";
echo "Value 6: $column2[4] </br>";
echo "Value 7: $column2[5] </br>";
mssql_free_statement($sql_statement);
$sql_statement = mssql_init("stored_procedure2 '$variable1'", $conn);
$result=mssql_execute($sql_statement);
$x=0;
while ($row = mssql_fetch_assoc($result))
{
$someval1[$x]= $row['somecolumn1'];
$someval2[$x]= $row['somecolumn2'];
$someval3= $row['somecolumn3'];
$someval4= $row['somecolumn4'];
$someval5= $row['somecolumn5'];
$someval6= $row['somecolumn6'];
$x++; }
echo "Something1: $someval1[0]</br>";
echo "Something2: $someval3 </br>";
echo "Something3: $someval2[0] </br>";
echo "Something4: $someval4 </br>";
echo "Something5: $someval6 </br>";
echo "Something6: $someval5 </br>";
mssql_free_statement($sql_statement);
$sql_statement = mssql_init("stored_procedure3 '$variable1'", $conn);
$result=mssql_execute($sql_statement);
$x=0;
while ($row = mssql_fetch_assoc($result))
{
$somevaluecheck= $row['somecolumncheck'];
$x++; }
echo "SomethingCheck: $somevaluecheck </br>";
mssql_free_statement($sql_statement);
?>
Hey guys, I have been banging my head against a wall here with this. I am saving my sessions in my database via session_set_save_handler(). So let me walk you through what I have here, what works, and what the issue seems to be. basically, the problem is the $_SESSION array is empty on page load. common.php: I have the open / close / read / write / destroy / and gc functions. These all work properly as when i use a session variable it stores into the database and i can see all of the information in there.. inside of common.php i have session_start().. I am positive that the session_start() is running becasue common.php is included into index.php and i tried adding session_start() to index.php again and i got an E_NOTICE saying the session already began. (yes, for the read function i am returning a string... i included that below). for the table itself, i have set the session_data as both text and blob, same issue with both. index.php: includes common.php. I know it's included as other aspects of the file are included and work properly. if i call var_dump($_SESSION) i get an empty array. and i prited out the session_id() and it matched my session id in the database. and the values that are stored in there are correct. i have for example: count|i:0 now with that value actually in the database and when calling session_id() and i get the ID that matches in the table. so i will get an E_NOTICE of an undefined index.. i was trying something like: if(!isset($_SESSION['count'])) $_SESSION['count'] = 0; else $_SESSION['count']++; echo $_SESSION['count']; Everytime the page is reloaded, count is reset to 0.. I can tell that it is reset to 0 as the expired time changes in the database after every load of the page (which is part of the write function). I double checked that it wasn't a problem for some reason with the ++ by adding in a variable that sets to 1 when in the if, and 0 if in the else, and it always outputs a 1. i have included here my read function since that apparently is the issue.. function sess_read($sess_id) { global $DB; $sql = "SELECT `session_data` FROM `sessions` WHERE session_id = '".$sess_id."' AND session_agent = '".$_SERVER["HTTP_USER_AGENT"]."' AND session_expire > '".time()."';"; $query = $DB->query($sql); if($DB->num_rows($query) > 0) { $r = $DB->fetch($query); return settype($r['session_data'], 'string'); } return ''; } I tried also with removing the agent and expire check to see if it was an issue there but same problem. I probably have missed something really dumb but i can't for the life of me figure it out and I have googled around for a similar issue. The actual output of the page is correct.. all of the HTML and CSS information loads properly.. no errors are reported (and i have E_ALL on). Thanks I am writting a php function that uses mysql to get user data - pretty common, right Well, my issue is that I need to run a check in my file system. Users profile pictures are stored in my image directory as .png's. I need to have my function check that directory and if an image matches their id, then return their information. I only want the user data if they have an image uploaded. Here is my current function: Code: [Select] function fetch_users_login($limit) { $limit = $limit(int); $sql = "SELECT `users`.`id`, `users`.`firstname`, `users`.`lastname`, `users`.`username`, `user_privacy`.`avatar` FROM `users` LEFT JOIN `user_privacy` ON `users`.`id` = `user_privacy`.`uid` WHERE `users`.`status` > 2 AND `user_privacy`.`avatar` = 1 ORDER BY `users`.`id` DESC LIMIT 0, {$limit}"; $result = mysql_query($sql) or die(mysql_error()); $users = array(); $i = 0; while(($row = mysql_fetch_assoc($result)) !== false) { $users[$i] = array( 'id' => $row['id'], 'firstname' => $row['firstname'], 'lastname' => $row['lastname'], ); $users[$i]['avatar'] = getUserAvatar($row['username']); $i++; } return $users; } I am trying to make a setup file for a website I'm developing, and am having the database tables and stored procedures created automatically. However, I'm having issue getting the stored procedures to be created. Here is my code: Code: [Select] $db->Q(" DELIMITER $$ CREATE PROCEDURE `Database`.`Procedure_Name`(in sp_uid mediumint(20) unsigned, in sp_user varchar(15), in sp_pass varchar(20), in sp_email varchar(30)) BEGIN Insert Into Table Values (sp_uid, sp_user, md5(sp_pass), sp_email, '1', '1', '0'); Select true; END$$ "); Assume that the "$db->Q()" works just fine, as I'm having issues no where else with it. This automatically connects to the database and runs a query with whatever is inside the "()". The tables are being created just fine, but no stored procedures are being created. I've tried everything I can think of, and googled my question many different ways without finding an answer or work-through. Does anyone know what I am doing wrong? Thanks in advance. Hey Guys, I have got 3 chained select boxes working. Basically what you do is check for a region with the country, then once you pick a region, you select a club within that region. Once you have selected the club, you can then choose a team from within that club. Screenshot: Attchment As part of this chained select boxes's, a user can register. Although, the user has to FIRST check if the TEAM has already been registered in the database. I have taken a screenshot of my database, which shows the regions, clubs, and teams from the chained select boxes. What i want to do now is be able to check if a TEAM is already registered in the database. So as you can see in the database, the team 'NPOB, Senior As' has already been taken. Database Screenshot: Attachment *** How do i check if a user has been registered to one of the teams? And if there is not a registered user to that team, they can then register it. Here is my code: <?php include"database.php"; ?> <script type="text/javascript"> /* Triple Combo Script Credit By Philip M: http://www.codingforums.com/member.php?u=186 Visit http://javascriptkit.com for this and over 400+ other scripts */ var categories = []; categories["startList"] = ["Taranaki","Auckland"] // Regions + Clubs categories["Taranaki"] = ["NPOB","Tukapa"]; categories["Auckland"] = ["Marist","Takapuna"]; // Clubs + Teams within that Club categories["NPOB"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Tukapa"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Marist"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Takapuna"] = ["Senior As","Senior Bs","Colts U21s"]; var nLists = 3; // number of select lists in the set function fillSelect(currCat,currList){ var step = Number(currList.name.replace(/\D/g,"")); for (i=step; i<nLists+1; i++) { document.forms['tripleplay']['List'+i].length = 1; document.forms['tripleplay']['List'+i].selectedIndex = 0; } var nCat = categories[currCat]; for (each in nCat) { var nOption = document.createElement('option'); var nData = document.createTextNode(nCat[each]); nOption.setAttribute('value',nCat[each]); nOption.appendChild(nData); currList.appendChild(nOption); } } // function getValue(L3, L2, L1) { // alert("Your selection was:- \n" + L1 + "\n" + L2 + "\n" + L3); // } function init() { fillSelect('startList',document.forms['tripleplay']['List1']) } navigator.appName == "Microsoft Internet Explorer" ? attachEvent('onload', init, false) : addEventListener('load', init, false); </script> <form name="tripleplay" action="testingdropdown.php" method="post"> <select name='List1' onchange="fillSelect(this.value,this.form['List2'])"> <option selected>Choose Region</option> </select><br /><br /> <select name='List2' onchange="fillSelect(this.value,this.form['List3'])"> <option selected>Choose Club </option> </select><br /><br /> <select name='List3' onchange="getValue(this.value, this.form['List2'].value, this.form['List1'].value)"> <option selected >Choose Team </option> </select> <input type="submit" name="tripleplay" value="Register"> </form> <?php if (isset($_POST['tripleplay'])) { $region = addslashes(strip_tags($_POST['List1'])); $club = addslashes(strip_tags($_POST['List2'])); $team = addslashes(strip_tags($_POST['List3'])); $email = 'email'; $check = mysql_query("SELECT * FROM managers WHERE email='$email'"); if ($email == '') { echo "You can register that club"; } else { echo "Sorry that team has already been registered"; } } ?> hey guys i have this code FILE NAME "index.php" Code: [Select] <?php // make a connection to the database mysql_connect ("localhost", "root", "vertrigo") or die ('Error: I Failed To Connect To The Database ' . mysql_error()); mysql_select_db ("test"); // Get Data $query = mysql_query("SELECT * FROM TestTable"); // display the data and loop while ($row = mysql_fetch_array($query)) { echo "<br /> ID: ".$row['ID']."<br /> First Name: ".$row['FName']."<br /> Last Name: ".$row['LName']."<br /> Contact Number: ".$row['CNumber']."<br />";} ?> <form method="post" action="update.php"> <table border="1" align="center"> <tr> <td align="right" width="220">ID: </td> <td align="left" width="220"> <input type="text" name="ID" size="30" /></td> </tr> <tr> <td align="right" width="220">First Name: </td> <td align="left" width="220"> <input type="text" name="FName" size="30" /></td> </tr> <tr> <td align="right" width="220">Last Name: </td> <td align="left" width="220"> <input type="text" name="LName" size="30" /></td> </tr> <tr> <td align="right" width="220">Contact Number: </td> <td align="left" width="220"> <input type="text" name="CNumber" size="30" /></td> </tr> <tr> <td align="right" width="220"><input type="reset" value="Reset" /> </td> <td align="left" width="220"> <input type="submit" value="Update Database" /></td> </tr> </table> </form> and i also have this code FILE NAME "update.php" Code: [Select] <?php $ID = $_POST['ID']; $FName = $_POST['FName']; $LName = $_POST['LName']; $CNumber = $_POST['CNumber']; mysql_connect ("localhost", "root", "vertrigo") or die ('Error: I Failed To Connect To The Database ' . mysql_error()); mysql_select_db ("test"); $query="INSERT INTO testtable (ID, FName, LName, CNumber)VALUES ('".$ID."','".$FName."', '".$LName."', '".$CNumber."')"; mysql_query($query) or die ('Error Updating Database'); echo "Database Updated Sucsessfully With: ".$ID." ".$FName." ".$LName." ".$CNumber ; ?> ok so the script is working like a charm its sending the data to the database as i want it to. the problem i have is that i want to be able to update the info that is already on the database lets say i want to change a phone/contact number i have typed the ID number into the ID text field and the same first and last name into there correct boxes and then typed in the new phone number i then click submit and i get the error ""Error Updating Database"" i have looked all over the forum and net to see what i have done wrong to not allow this code to update can anyone help me out here please im quite new to the php language and could really do with some pointers thanks Steve Hello, Here's my system. Once a user is successfully logged in, a new instance of a User class is created. The constructor of this class grabs the details of the logged-in user from a database and stores them inside properties in the User class. The problem is, obviously I'd want to access these properties from any page I require them to be able to display user data, so I looked into storing the User object in a Session. When I tried implementing this, I ran into a bunch of errors and I couldn't figure it out. Here's an example: After a user has logged in, I had the following code: Code: [Select] $_SESSION['user'] = new User($this->username); I was under the impression that this assigns a user object to a session. But it's not working as I receive this error: Quote Notice: Undefined index: user in ../v2/admin/index.php on line 18 Then on the page I want to display the name of the current user logged-in, I had this code: Code: [Select] $_SESSION['user']->get_Name(); But then I get this error: Quote Fatal error: Call to a member function get_IP() on a non-object in ../v2/admin/index.php on line 18 Can tell me what I have to do, to make this work? Thanks. I have a PHP page that offers various information from a single text file. This text file is encrypted on the server HD. Upon initial entry into the page, the user enters an encryption/decryption KEY and the encrypted file is decrypted to clear text and it is available for viewing. I have some parameters that I store in PHP session variables. I do this since various subsequent actions by the user will require these parameters. The code is written and the whole process seems to work well. Since the info in these session variables is sensitive, I need to understand WHERE they are stored. I know that it is a file on the HD, but after hours of reading the PHP Manual on sessions, I am not finding where (HD directory) that storage is. I have a typical shared hosting account for my web site. Mostly I want to discover is, are the session variables in y User/file hierarchy, or are they stored in a system area where the PHP is installed. Whew. Sorry this was so long.
Thank you, How can I run php code that is stored in a database? I have my pages created by grabbing the contents of a pageBody mySQL table cell, but some pages require further php to be able to display correctly. For example, I have a players page, which will list all players, and some information about them. The players and information is all saved in a players table in my database (separate to the pages table where pageBody is stored). I use simple php to grab all the players and format all of their information so it can be displayed on the page. This is the flow of information that I would like: User clicks on players page browser loads content page (this is a template page), and grabs the pageid from $_GET browser then reads pages table in database to get the pageBody associated with the pageid The pageBody will contain more php, which will run the players script to retrieve the list, and display Doing it the above way will make it much easier to extend the website to include more types of pages that has to run additional php scripts. The only way I can think of this working is by doing this: user clicks on players page browser loads content page, grabs pageid from $_GET browser checks the pageid for the one associated with players (hard coded into the php script) browser then loads the players.php script instead of going to the database This above way means that I will need to edit the index.php page everytime I add a new list type (example, coaches, volunteers etc). Anyone have any suggestions? I know my question is long, but I was finding it hard to explain it in an easy to understand way, but I'm still not sure if I have :S. Cheers Denno Hi Guys, I have a webpage which has subsequent pages stored in a database e.g. index.php?id=1 The problem being, is that id=1 has it's data pulled from a database. This was fine & dandy until I started to insert PHP...I am trying to get the below to executre <?php $rater_id=1; $rater_item_name='Rate This'; include("rater.php");?> However nothing shows & nothing happens, I know eval can be used but have not been succesfull in implementing this, can someone please help! sorry if i have posted this in the wrong place, wasnt sure wether to post here or mysql. I have made a php calendar, and i am now wanting it to show if there is an event on that day and if so show it in a tool tip. the tool tip is populated by what is in the title="" of the link so i need my events to be shown in there. I have figured out how to show the event but now i am stuck on how to show all events if there is more than one one that day, how i have set it seems to only the second event, probably as the second variable overwrote the first variable. this is the code i have at the minute .............. $result = mysql_query("SELECT * FROM events WHERE day='$day_num' AND month='$fullmonth' AND year='$year'") or die(mysql_error()); $rows= mysql_num_rows($result); if ($rows !="false"){ while($rowout = mysql_fetch_array($result)) { $todayis = $rowout['day'] ."-". $rowout['month'] ."-". $rowout['year'] ."<br>"; $title= $rowout['event'] ."<br><br>";} $firstl = "<a href='' title='". $todayis . $title ."'>"; $lastl = "</a>";} else {$firstl = ""; $lastl = "";} then to display the day and links ................. Code: [Select] <td><? echo $firstl; ?><? print $day_num; ?><? echo $lastl; ?></td> could some one be so kind and help me write it so that it displays all events? here is a link to the calendar, incase its needed. http://www.scripttesting.htmlstig.com/calendar/index.php Many thanks Carl Hi Everyone, I have a program that generates 200 unique images keeping the first image static in each run.The images keep scrolling on to the screen pause for 3 seconds and scroll off I'm able to generated all 200 unique images without repetition, everything is working well except for the lase two images the last two images are scrolling on to the screen but are not been displayed in the database, Moreover The last image is a duplicate of 197th image.I don't know what is happening..... Here is MY code.......... <?php session_start(); $sid = $_SESSION['id']; $_SESSION['imageDispCnt'] = 0; $myQuery = "SELECT * from image"; $conn = mysql_connect("localhost","User","Passwd"); mysql_select_db("database_Name",$conn); $result = mysql_query($myQuery); $img =Array(); $id =Array(); $i =0; $imagepath = 'http://localhost/images/'; while ($row = mysql_fetch_array($result)) { $img[$i] = $imagepath.$row['img_name']; $id[$i] = $row['imageid']; $i = $i + 1; } ?> </head> <script language="JavaScript1.2"> var scrollerwidth='800px'; var scrollerheight='600px'; var scrollerbgcolor='white'; var pausebetweenimages=3200; var s; var sec; var d; var j; var imgid; var milisec = 0; var seconds = 0; var flag = 1; var ses_id = '<?php echo $sid;?>'; var count = 0; var i = 0; var imgname; var imgid; var k =0; var slideimages=new Array(); var img_id = new Array(); var index; <?php $l =0; $count = array(); $j = rand(0,199); while($l < 200) { while(in_array($j, $count)) { $j = rand(0,199); } $count[$l] = $j; $l++; }?> <?php $k = 0; for($k = 0;$k<count($count);$k++){ ?> index = <?php echo $k;?>; <?php $indx = $count[$k];?> if(index == 0){ slideimages[0] = '<img src="http://localhost/images/hbag044.jpg" name="r_img" id="0"/>'; img_id[0] = '<input type="hidden" value="0" id="imgId" />'; } else if(index > 0) { slideimages[<?php echo $k?>] = '<img src="<?php echo $img[$indx]?>" name="r_img" id="<?php echo $id[$indx]?>"/>'; img_id[<?php echo $k?>] = '<input type="hidden" value="<?php echo $id[$indx]?>" id="imgId" />'; } <?php } ?> Can Any one plese help me Appreciate your help... 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