PHP - How To Pass A Variable Into An Object?

I work with a large codebase and I have this situation come up fairly often:   the legacy class has large objects such as:

$design->motor->dimensions->a;
$design->motor->dimensions->bd;
$design->specifications->weight;
$design->data->height;
//etc

When I create a new class, that class sometimes operates on the specific data, so say:

class MyClass
{
    public function compute($weight, $height, $a)
    {
        //stuff
    }
}

//and I call this for example as such:
(new MyClass())->compute($design->specifications->weight, $design->data->height, $design->motor->dimensions->a);

CONS:  Potential issue:  if design specs change and I need to change things parameters in "compute" function, I need to "re-key" the variables I pass to the function, and adjust things accordinly in MyClass as wel. PROS:  only the exact data is being passed, and this data can come from anywhere it is viable, so in effect the function is fairly well separated, I think.   Alternative option for me is to pass the entire design object, i.e

class MyClass
{
    public function compute(&$design) //can also be done via DI through a setter or constructor.
    {
         print $design->specifications->weight;
         print ($design->data->height + $design->motor->dimensions->a);
        //stuff
    }
}

(new MyClass())->compute($design);

PROS:  In this case when things change internally in which variables are needed and how things are computed, I only need to change the code in compute function of the class itself. CONS:  MyClass now needs to be aware of how $design object is constructed.   When it comes to this parameter passing, and Dependency Injection like this in general, does Computer Science advocate a preference on this issue?  Do I pass the entire object, or do I pass only the bits and pieces I need?

so I need some help passing these variable from this page to final.php.  how do I pass these arrays?  I know if it were singled....not arrayed, I could use hidden fields in a form and echo them out....but these are multiples....not singled.  The form way is prefered.....but it doesn't have to be.  I just need these passed to the page where I am going to process them.  I am not good at working with arrays.  Thanks in advance

Code: [Select]
<?php
include_once("connect.php");
session_start();

 
 




 
foreach($_POST["product"] AS $key => $val) {
$product = $val;
$month = $_POST['month'][$key];
$day = $_POST['day'][$key];
$year = $_POST['year'][$key];
$date = $_POST['date'][$key];
$price = $_POST['price'][$key];
$qty = $_POST['qty'][$key];
$id = $_POST['id'][$key];
$total = $_POST['total'][$key];
$academy = $_POST['academy'][$key];
$priceunit = $price * $qty;


}

?>

Hi guys,

I need your help, I have got a problem with the if statement. When I don't insert the pass function in the url like this:

Code: [Select]
http://www.mysite.com/myscript.php?image=myimagelocation&strings=mystrings&user=test

I will get this on my php page:

Code: [Select]
PASSWORD are missing

Code: [Select]
<?php
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbusername');
    define('DB_PASSWORD', 'mydbpass');
    define('DB_DATABASE', 'mydbname');
       
    $errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
  die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
    $image = clean($_GET['image']);
    $strings = clean($_GET['strings']);
    $username = clean($_GET['user']);
    $pass = clean($_GET['pass']);


    if($username == '' && $pass) {
  $errmsg_arr[] = 'username are missing';
  $errflag = true;
     }elseif($username && $pass =='') {
  $errmsg_arr[] = 'PASSWORD are missing';
  $errflag = true;
    }
    if($username == '' && $pass == '') {
  $errmsg_arr[] = 'username or password missing';
  $errflag = true;
    }

    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {

 
$insert = array();
if(isset($_GET['image'])) {
    $insert[] = 'image = \'' . clean($_GET['image']) . '\'';
}
if(isset($_GET['strings'])) {
    $insert[] = 'strings = \'' . clean($_GET['strings']) . '\'';
}
if(isset($_GET['user'])) {
    $insert[] = 'user = \'' . clean($_GET['user']) .'\'';
}
if(isset($_GET['pass'])) {
    $insert[] = 'pass = \'' . clean($_GET['pass']) . '\'';
}



if (count($insert)>0) {
   $names = implode(',',$insert);

$required_fields = array('image', 'strings', 'user');

if($image && $strings && $username) {
  echo "working 1";
} elseif($username && $pass) {
  echo "working 2";
  }
 }
}
?>

Do anyone know how to fix this?

I have researched all over forums from past day. Not getting correct solution. I have 2 textboxes and a button. First box is to enter value and i will click button, i need to get the value.   Here is the code, that works without input box 1   In this code i want to modify my web address, at the end after ky= i want add my first textbox value, then click event and output in second textbox, let me know where i messed.  

<script type="text/javascript">
function Assign() 
{
<?php
$html = file_get_contents("http://geoportaal.maaamet.ee/url/xgis-ky.php?ky=79401:006:0812" );
preg_match_all('(<li.*?>.*?</li>)', $html, $matches);
$one=$matches[0][0];


?>
document.getElementById("OutputField").value = "<?=$one?>";
}
</script>




<input id="InputField" type="text" style="width:200px"/>
<input type="submit" value="Assign Value" onclick="Assign()"/>
<input id="OutputField" type="text" style="width:200px"/>

Hello

I'm using a form to collect user data (is a Cognito form) it is displayed on vacation rental properties pages, so it collects user´s email, in date, out date, etc.
However since my site https://www.bariloche.esp.br/hoteis/hosteria-no-centro-vista-ao-lago uses the same form for several properties, when someone submits, I get the information but I dont know if it comes from here https://www.bariloche.esp.br/hoteis/hosteria-no-centro-vista-ao-lago or https://www.bariloche.esp.br/hoteis/hotel-com-praia-de-lago-ha1 or any other property page.

in the cognito form I have one text hidden field called REF, 

I wonder how to do in order to use the same form and be able to identify where the info comes from. 

I thougt that if I could put the page url into the REF variable, the problem would be solved, but I'm not sure if that is possible and how to do it.

It is?

If not: is it possible to handle that ?