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PHP - Mysql_fetch_assoc() Expects Parameter 1
i get this error
Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\website\viewvideos.php on line 25 Code: [Select] $addviews = $views + 1; $query = mysql_query("UPDATE headlines SET views='$addviews' WHERE id=$viewid"); $rows = mysql_fetch_assoc($query); i dont get whats wrong Similar Tutorialswe did an exercise in IT class it was about how to inject php code in css code we took a template as an example to work on. i injected php code in the page "services.php"as instructed but it didn't work and i keep getting this error : Hello, Im developing simple user registration system with my knowledge.but got this error with this file Code: [Select] <?php //database connection require_once("dbconnection/connect.php"); $success_massage =""; if (isset($_POST['hiddenstudentid'])) $passstudent_id=$_POST['hiddenstudentid']; else $passstudent_id=$_POST['student_id_hidden']; $sql=mysql_query("SELECT * FROM student WHERE StudentID=$passstudent_id"); echo $sql; while ($row=mysql_fetch_assoc($sql)) { $update_nic=$row['NIC']; $update_name=$row['Student_Name']; $update_addr=$row['Address']; $take_bday=$row['Birthday']; echo $take_bday; $update_bday=date('d',strtotime($take_bday)); $update_month=date('m',strtotime($take_bday)); $update_year=date('y',strtotime($take_bday)); $update_tele=$row['Telephone']; $update_email=$row['Email']; } if (isset($_POST['btnupdate'])) { $insert_nic=$_POST['nic_txt']; $insert_name=$_POST['name_txt']; $insert_addr=$_POST['address_txt']; $insert_bday=$_POST['bdate']; $insert_month=$_POST['bmonth']; $insert_year=$_POST['byear']; $insert_tele=$_POST['telephone_txt']; $insert_email=$_POST['email_txt']; $Birthday =date("$insert_year-$insert_month-$insert_bday");//Bday eka $Birthday ta set kereema. $sql="update student set NIC='$insert_nic',Student_Name='$insert_name',Address='$insert_addr',Birthday='$Birthday',Telephone='$insert_tele',Email='$insert_email' where StudentID=$passstudent_id" ; /*(Student_ID,NIC,Student_Name,Address,Birthday,Telephone,Email)values('$student_id','$insert_nic','$insert_name','$insert_addr','$Birthday','$insert_tele','$insert_email')";*/ //echo $sql; $result=mysql_query($sql) or die ("database error"); $success ="Records updated successfully"; $success_massage =$success; header('Location:editdisplay.php'); } if ($_POST['btndelete']=='DELETER') { $delete = "delete from student where StudentID=$passstudent_id"; $result =mysql_query($delete) or die ("data deleting error"); $delete_massage="Record deleted"; //$success_massage = $delete_massage; } if (isset($_POST['btncancel'])) { header ('Location:registration.php'); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script type="text/javascript"> function GetConfirmation() { var res=confirm("Are you sure to delete this Student?"); if(res==true) { var btn=document.getElementById("btndelete"); btn.value="DELETER"; // alert ("YES"); document.editForm.submit(); } } </script> </head> <body> <form id="form1" name="form1" method="post" action=""> <table width="406" border="1"> <tr> <td width="149"> </td> <td width="241">Student Registration</td> </tr> <tr> <td>NIC</td> <td><label for="nic_txt"></label> <input type="text" name="nic_txt" id="nic_txt" value="<?php echo $update_nic ?>" /><input type="hidden" name="student_id_hidden" id="student_id_hidden" value="<?php echo $passstudent_id ?>" /> </td> </tr> <tr> <td>Name</td> <td><label for="name_txt"></label> <input type="text" name="name_txt" id="name_txt" value="<?php echo $update_name ?>" /><span style="color:#F00"><?php echo $massage_name?></span></td> </tr> <tr> <td>Address</td> <td><label for="address_txt"></label> <input type="text" name="address_txt" id="address_txt" value="<?php echo $update_addr ?>" /><span style="color:#F00"><?php echo $massage_address?></span></td> </tr> <tr> <td>Birthday</td> <td><label for="bdate"></label> <select name="bdate" id="bdate"> <option selected="selected"><?php echo $update_bday ?></option> <?php for ( $i=1;$i<=31;$i++) {echo '<option>'.$i.'</option>'; } ?> </select> <label for="bmonth"></label> <select name="bmonth" id="bmonth"> <option selected="selected"><?php echo $update_month ?></option> <?php echo '<option>'.'-month-'.'</option>'; for ($b=1;$b<=12;$b++) {echo '<option>'.$b.'</option>'; } ?> </select> <label for="byear"></label> <select name="byear" id="byear" /> <option selected="selected"><?php echo $update_year ?></option> <?php echo '<option>'.'-year-'.'</option>'; for ($b=1960;$b<=2000;$b++) {echo '<option>'.$b.'</option>'; } ?> </select><span style="color:#F00"><?php echo $massage_bday?></span></td> </tr> <tr> <td>Email</td> <td><label for="email_txt"></label> <input type="text" name="email_txt" id="email_txt" value="<?php echo $update_email?>" /></td> </tr> <tr> <td>Telephone</td> <td><label for="telephone_txt"></label> <input type="text" name="telephone_txt" id="telephone_txt" value="<?php echo $update_tele?>"/></td> </tr> <tr> <td> </td> <td><input type="submit" name="btnupdate" id="btnupdate" value="Update" /> <input type="submit" name="btndelete" id="btndelete" value="Delete" onclick="GetConfirmation()" /> <input type="submit" name="btncancel" id="btncancel" value="Cancel" /></td> </tr> </table> <?php echo $success_massage?> </form> </body> </html> got error from these codes in this file Code: [Select] if (isset($_POST['hiddenstudentid'])) $passstudent_id=$_POST['hiddenstudentid']; else $passstudent_id=$_POST['student_id_hidden']; $sql=mysql_query("SELECT * FROM student WHERE StudentID=$passstudent_id"); echo $sql; it is showing this error this this warning error.in here that details from DB will show in form.and im going to edit them from this file. please help me to find the error. i am having problem with this error, could you please help me Code: [Select] function cart () { foreach($_SESSION as $name => $value) { if ($value>0) { if (substr($name, 0, 5) == "cart_") { $productid = substr($name, 5, (strlen($name)-5)); $query = mysql_query("SELECT ProductID, Name, Price FROM product WHERE ProductID = '".mysql_real_escape_string((int)$productid."'")); while ($query_row = mysql_fetch_assoc($query)) { $sub = $query["Price"]*$Value; echo $query["Name"]. ' x ' .$value. ' @ '.$query["Price"]. ' = '.$sub.'<br />'; } } } else { echo "<p>Your Shopping Basket is empty</p>"; } } } Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\xampp\test.php on line 58 line 58 is the where the while loop starts.. what have i done wrong? Code: [Select] $query2 = mysql_query("SELECT student.SID, course.CID FROM student, course WHERE student.SID = `student-course.SID` AND course.CID = `student-course.CID` AND GRADE BETWEEN $beginning AND $grade",$this->connect); while($row = mysql_fetch_assoc($query2)) { $sid = $row['student.SID']; $cid = $row['course.CID']; echo "$sid-$cid"; } Ive been having trouble. Im getting this error: Code: [Select] $select = mysql_query($query1); echo $select; $rows1 = mysqli_fetch_array($dbc, $select); I dont understand whats wrong. Please help, This code is giving me the warning stated in the above given Subject line. And combo box is also not populating. Code: [Select] function populatecombo() { $dropdown = ""; $sqlcmb = "select wardno from wards"; mysql_query($sqlcmb) or die(mysql_error('Unable to query the table')); while($row = mysql_fetch_assoc($sqlcmb)) { $dropdown .= "\r\n<option value='{$row['wardno']}>'{$row['wardno']}</option>"; } echo $dropdown; } When i try and use this app on my website i get the error, Code: [Select] Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in /home/unionc/public_html/auction/scripts/updateTables.php on line 15 Code: [Select] <?php $now = time(); add_column_if_not_exist("WA_SellPrice", "seller", "VARCHAR( 255 ) NULL"); add_column_if_not_exist("WA_SellPrice", "buyer", "VARCHAR( 255 ) NULL"); add_column_if_not_exist("WA_Players", "canBuy", "INT(11) NOT NULL DEFAULT '0'"); add_column_if_not_exist("WA_Players", "canSell", "INT(11) NOT NULL DEFAULT '0'"); add_column_if_not_exist("WA_Players", "isAdmin", "INT(11) NOT NULL DEFAULT '0'"); add_column_if_not_exist("WA_Auctions", "created", "INT(11) NULL"); function add_column_if_not_exist($table, $column, $column_attr){ $exists = false; $columns = mysql_query("show columns from $table"); while($c = mysql_fetch_assoc($columns)){ if($c['Field'] == $column){ $exists = true; break; } } if(!$exists){ mysql_query("ALTER TABLE `$table` ADD `$column` $column_attr"); } } ?>Please Help! I have a strange error from the code below. I have run the query with the resulting values in PHPMyAdmin and it works fine. The code is: $query = "SELECT * FROM sn_matches WHERE (P1_ID='".$P1_ID."' AND P2_ID='".$P2_ID."') OR (P1_ID='".$P2_ID."' AND P2_ID='".$P1_ID."')"; while($row = mysql_fetch_assoc($query)){ The error is: Quote Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in /customers/ronflorax.com/ronflorax.com/httpd.www/snookerstats/h2h.php on line 21 Line 21 is the one which has mysql_fetch_assoc on it. Any help would be much appreciated! Hi, I'm fairly new to PHP and have run into this problem, I have tried looking through some other peoples solutions to this but don't quite understand them! I have set up a simple news post on a website which works fine, however when I go to edit a post and try to submit it again it comes up with this error: Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in /Users/mdfcows/Sites/atelier/editnews.php on line 61 It still works, i.e. posts it, however I don't quite know what this means, and now I am trying to set it up so that another page can be edited and all I am getting is the same error on the page without any of the other info or PHP coming up! this is the PHP I am using, with the line "while ($row = mysql_fetch_assoc ($result)) {" being line number 61 Code: [Select] <?php require_once('config.php'); $con = mysql_connect(DB_HOST,DB_USER,DB_PASSWORD); if (!$con){ die('Failed to connect to server' . mysql_error()); } mysql_select_db(DB_DATABASE); $ide = $_POST[idf]; $query = "SELECT image,id,title,text FROM news WHERE id = $ide"; $result = mysql_query($query); while ($row = mysql_fetch_assoc ($result)) { $title = htmlentities ($row['title']); $news = nl2br (strip_tags ($row ['text'], '<a><b><i><u>')); $image = $row['image']; echo "<form class ='addform' action='editnews.php' enctype='multipart/form-data' method='post'>"; echo "<input type='hidden' name='ida' value='$ide' />"; echo "<p>Title:<br /><input class='titlefield' type='text' name='title' value='$title' /></p><br />"; echo "<p>News Post:<br /> <textarea name='news' rows='12' cols='50'>$news</textarea></p><br />"; echo "<p>If you uploaded an image with your post you will need to upload it again<br /><input type='hidden' name='MAX_FILE_SIZE' value='20000000' /> <input name='userfile' type='file' value='$image' id='userfile' /></p><br />"; echo "<p><input name='submit' type='submit' value='Submit' /></p>"; echo "</form>"; } if ($_POST['submit']) { mysql_select_db(DB_DATABASE); $upid = $_POST[ida]; $uptitle = $_POST[title]; $upnews = $_POST[news]; $upimage = $_FILES['userfile']['name']; $sql = "UPDATE news SET title = '$uptitle', text = '$upnews', image = '$upimage' WHERE id = '$upid'"; mysql_query($sql); if ($_POST['submit']) { echo "<p class='admintext'>Your post has been Edited - <a href='index.php'>View Latest News Page</a></p><br />"; $name = $_FILES['userfile']['name']; $type = $_FILES['userfile']['type']; $size = $_FILES['userfile']['size']; $tmpname = $_FILES['userfile']['tmp_name']; $ext = substr($name, strrpos($name, '.')); if (strstr($type, "image")) { move_uploaded_file($tmpname, "images/".$name); } } } ?> Any help would be much appreciated! Thank you Martin I am trying to create a simple voting form. Everything goes well until I submit and then I get a Warning: mysqli_error() expects exactly 1 parameter, 0 given on line 79 error. I am assuming it is not pulling the ID correctly but as I am new to php and mysqli I cannot exactly say if it the way the code is written or if I am calling the parameter incorrectly in the query. Again I am new to to this so please be gentle. Below is my code. It pulls the drop down list correctly and echo's correctly but I believe my post query to be a little out of wack. Could someone point me in the correct direction? It would be very appreciated.
<form action="businesstype_update.php" method="post">
<?php
if(isset($_POST['voteall'])){
$vote_lg = "update membertest where id={$row_lg['id']} set vote=vote+1";
$run_lg = mysqli_query($con, $vote_lg) or die(mysqli_error());
}
$result_lg = mysqli_query($con, "SELECT id, business FROM membertest WHERE businesstype='large'");
echo "Vote for large business of the year! <SELECT name='business'>\n";
echo "<option>Select a large business</option>";
while($row_lg = $result_lg->fetch_assoc()) {
echo "<option value='{$row_lg['id']}'>{$row_lg['business']}</option>\n";
}
echo "</select></br></br>\n";
echo "<input type='submit' name='voteall' value='voteall'>";
$result_lg->close();
$con->close();
May I know what does this mean, this is the code which they are referring to. I have tried troubleshooting, still could not find the cause, appreciate if anyone can help? Thanks Warning: mysqli_error() expects exactly 1 parameter, 0 given in D:\inetpub\vhosts\championtutor.com\httpdocs\inc\elements\t_reg_post1.php on line 204 /**INSERT into tutor_musical_background table**/ foreach($musics as $music) { $query6 = "INSERT INTO tutor_musical_background (tutor_id, musical_instrument_id) VALUES ('$tutor_id', '$music')"; $results6 = mysqli_query($dbc, $query6) or die(mysqli_error()); Hi all, I have received this error, and I could clearly recall I did not actually change any content in the file. May I know how should I debug it? Thanks Warning: mysqli_error() expects exactly 1 parameter, 0 given in D:\inetpub\vhosts\abc.com\httpdocs\inc\php\tutor\t_reg_post1.php on line 163 Hi I'm having a bit of bother with my login. I created a login using this tutorial http://www.phpeasystep.com/phptu/6.html and it works perfectly. So i have attempted to change it to meet my own database. So basically i've changed the database, table names etc to meet my own. I haven't changed any other lines. When i run it i get an error message: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\checklogin.php on line 26 The code is below: Code: [Select] <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="final year project"; // Database name $tbl_name="tbl_user"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // username and password sent from form $mem_username=$_POST['mem_username']; $mem_password=$_POST['mem_password']; // To protect MySQL injection (more detail about MySQL injection) $mem_username = stripslashes($mem_username); $mem_password = stripslashes($mem_password); $mem_username = mysql_real_escape_string($mem_username); $mem_password = mysql_real_escape_string($mem_password); $sql="SELECT * FROM $tbl_name WHERE username='$mem_username' and password='$mem_password'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $mem_username and $mem_password, table row must be 1 row if($count==1){ // Register $mem_username, $mem_password and redirect to file "login_success.php" session_register("mem_username"); session_register("mem_password"); header("location:login_success.php"); } else { echo "Wrong Username or Password"; } ?> Line 26 is $count=mysql_num_rows($result); I'm baffled as to why the test database worked. I tried another test database but got the same error. baffled.com Hope someone can help MOD EDIT: [code] . . . [/code] tags added. I keep getting this error when I run the following code: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\vitamin-k-tracker\my-meal-planner.php on line 29 Code: [Select] <?php include 'top.php'; ?> <?php if (!loggedin()) {//1 if start header('Location: need-to-log-in-mmp.php'); }//1 if end ?> <title>My Meal Planner - Vitamin K Tracker</title> </head> <div id="container"> <?php include 'header.php'; ?> <?php include 'nav.php'; ?> <?php //do sql query to return the foods and nutrients that a person added to their que // // we're doing a left join between the foods and user foods table connected by the id $queryc = "SELECT `foods.id`, `foods.name`, `foods.source`, `users_foods.food_id` FROM `foods` LEFT JOIN users_foods ON foods.id=users_foods.food_id"; $query_runc = mysql_query($queryc); //error on the line below: while ($rowc = mysql_fetch_array($query_runc)){ echo 'ok'; } ?> <div id="content-container"> <div id="content_for_site"> <h2>My Meal Planner</h2> <br /> My Meal Que: <br /> <ul> <form> <li><input type="checkbox" name="meal_one" value="meal_one" /> Meal One</li> How many servings will you have? <input type="text" name="meal_one_servings"><br /><br /> <li><input type="checkbox" name="food_one" value="food_one" /> Food One</li> How many servings will you have? <input type="text" name="meal_one_servings"> </form> </ul> <input type="submit" value="delete" name="delete"><br /> <input type="submit" value="add to calendar" name="add_to_calendar"> <br /><br /> <a href="create-a-meal.php">Create A Meal & add to your Meal Que</a><br /> <a href="find-a-meal.php">Find a Meal or Food to Add to your Meal Que</a> </div> <div id="clear"></div> <?php include 'footer.php'; ?> </div> </div> Hello im geting this error what im ding wrong? Code: [Select] PHP Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /home/admincom/public_html/tsue/library/plugins/movie_plugin.php on line 7 line 7 is: while ($row = mysqli_fetch_array($sql)) { code he Code: [Select] $query = mysqli_connect(MYSQL_HOST, MYSQL_USER, MYSQL_PASS, MYSQL_DB); $sql = mysqli_query($query, "SELECT `membername`, `filename`, `tid`, `info_hash`, `name`, `description`, `cid`, `size`, `added`, `leechers`, `seeders`, `times_completed`, `owner`, `options`, `nfo`, `sticky`, `flags`, `mtime`, `ctime`, `download_multiplier`, `upload_multiplier` FROM `tsue_members`, `tsue_torrents`, `tsue_attachments` WHERE `memberid`='owner' AND `content_type`='torrent_images' AND `content_id` = `tid` LIMIT 0, 10"); while ($row = mysqli_fetch_array($sql)) { $movie_plugin_row = ''; $uploader = $row['membername']; $description= $row['description']; $dydis= $row['size']; $name= $row['name']; $leechers= $row['leechers']; $owner= $row['owner']; $filename= $row['filename']; $nunx= $row['tid']; $seeders= $row['seeders']; eval("\$movie_plugin_row = \"".$TSUE['TSUE_Template']->LoadTemplate('movie_plugin_row')."\";"); $movie_plugin .= $movie_plugin_row; } I have tired to search this up but get nothing back.. :@ This error is on line 18 on line 18 is Code: [Select] if (mysql_num_rows($result) == 1) { Quote Notice: Undefined variable: result in C:\xampp\htdocs\Exam_Online\Staff_login\Staff_login_process.php on line 18 Warning: mysql_num_rows() expects parameter 1 to be resource, null given in C:\xampp\htdocs\Exam_Online\Staff_login\Staff_login_process.php on line 18 Wrong Username or Password This is the error message. Code: [Select] if (mysql_num_rows($result) == 1) { // Set username session variable $_SESSION['ID'] = $_POST['ID']; header("location:Staff_Menu.php"); } else { echo"Wrong Username or Password"; } Hi guys, I have an error msg here, "Warning: mysqli_error() expects exactly 1 parameter, 0 given in D:\inetpub\vhosts\championtutor.com\httpdocs\tutor_registration3.php on line 598". I have highlighted the error line in red, do you guys have any idea what went wrong? Thanks <?php $dbc = mysqli_connect('localhost', '111', '111', '111') or die(mysqli_error()); $query = "SELECT sl.subject_level_id, sl.level_id, sl.subject_id, tl.name AS level_name, ts.name AS subject_name " . "FROM tutor_subject_level AS sl " . "INNER JOIN tutor_level AS tl USING (level_id) " . "INNER JOIN tutor_subject AS ts USING (subject_id) "; $sql = mysqli_query($dbc, $query) or die(mysqli_error()); echo'<table><tr>'; // Start your table outside the loop... and your first row $count = 0; // Start your counter while($data = mysqli_fetch_array($sql)) { /* Check to see whether or not this is a *new* row If it is, then end the previous and start the next and restart the counter. */ if ($count % 5 == 0) { echo "</tr><tr>"; $count = 0; } echo '<td><input name="subject_level[]" type="checkbox" id="'.$data['subject_level_id'].'" value="'.$data['subject_level_id'].'"/>'; echo '<label for="'.$data['subject_name'].'">'.$data['subject_name'].'</label></td>'; $count++; //Increment the count } echo '</tr></table><br/><br/>'; //Close your last row and your table, outside the loop ?> My brain isn't working... I am trying to get this Prepared Statement to pull Events from my database and display them, but get this error... Quote Warning: mysqli_stmt_bind_param() expects parameter 1 to be mysqli_stmt, boolean given in /Users/user1/Documents/DEV/++htdocs/01_MyProject/events_9.php on line 30 Here is my code... Code: [Select] <?php // Initialize a session. session_start(); // Access Constants. require_once('config/config.inc.php'); // Initialize variables. $eventExists = FALSE; // Connect to the database. require_once(ROOT . 'private/mysqli_connect.php'); // ******************** // Build Event Query * // ******************** $id=1; // Build query. $q = 'SELECT id, name, location, date FROM show WHERE id=?'; // Prepare statement. $stmt = mysqli_prepare($dbc, $q); // Bind variable. mysqli_stmt_bind_param($stmt, 'i', $id); (The last line above is Line 30.) Debbie I'm an extreme newbie and have this current error on my site. The error states: Warning: mktime() expects parameter 4 to be long, string given in featured_product.php on line 75 <?php for ($i = 0; $i < $num_rows; $i++) { $id = mysql_result($result,$i,"id"); $title = mysql_result($result,$i,"title"); $featured = mysql_result($result,$i,"featured"); $feature_date = mysql_result($result,$i,"feature_date"); $feature_date_arr = explode("-",$feature_date); $feat_date = mktime(0,0,0,$feature_date_arr[0],$feature_date_arr[1],2000+$feature_date_arr[2]); if ( ($feat_date+($featured*24*60*60))<time() ) { $db2->query("UPDATE product_catalog SET featured = 0 WHERE id='$id'"); $featured = 0; } else { $featured = 1; $db2->query("UPDATE product_catalog SET featured = 1 WHERE id='$id'"); } ?> Any ideas on how to correct this? Thanks! |
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