PHP - Moved: Pass Php Variables From A Php File To A Html File

Hi   I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems. 1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?

for($x = 1;$x<=40;$x++) {
		$lines = file("$filename.html");
        echo $lines[rand(0, count($lines)-1)]."<br>";
        }

I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text  without the html code?P.S file_get_contents doesn't work either have tried that one.     2nd Problem:   As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file?   My code:

if($_POST['submitPasswordIT']){
if ($_POST['passIT']== $password ){
$my_file = file_get_contents("$filename.html");
echo $my_file;
}
else{
echo "You entered wrong password";
}
}

If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that.   

I have a file ("header.html") that predominately has HTML in it.

This may sound silly, but I would like to rename it as a .php file so that when I add comments next to my PHP, my IDE will shade them gray.

I just changed all of my PHP comments from

// Some PHP comment

to

<!-- New and Improved PHP comment -->

only to realize that PHP freaks out and doesn't treat them as comments - like NetBeans falsely does - but treats them as erroneous code.

(Now I have to go back and fix all of my files back to the way they were?!)   

If I could change my file from "header.html" to "header.php" then all of my // Comments would be grayed out in my PHP blocks and make my code easier to read.

To achieve that end, is it okay to rename a file from .html to .php even if most of the content is HTML and only a little is PHP?

(BTW, could you have a file that has 100% html content saved as a .php file and still have it work properly?!)

Thanks,


TomTees

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=347360.0

Right, so I've made a very simple web app that allows....

1.) People to register (adding them to the MySQL database)
2.) Login (providing they're in the database)

I've gotten it all working, but I'm stuck at the last hurdle. If someone logs in using the correct username and password, it takes them to login_success.php. Here I query the database and use "SELECT * FROM Users WHERE Username = '$name'"

I would have thought, that it would have returned that user's entry in the database. But instead I just get a blank page.

Am I right in thinking that's because the contents of the $name variable aren't passed from log.php to login_success.php

If so, how do I fix it?

----------------------------------------------------------------------------------------------------

LOGIN.PHP
Code: [Select]
<?php 
    include_once "Common/header.php";
    session_name("MyLogin");
    $page = (isset($_GET['login']) ? strtolower($_GET['login']) :
    NULL);
    
    if($page == "failed"){
        print $_GET['cause'];
    }

    ?>
<div id="main">
<br /> &nbsp <br />&nbsp <br />
<h2>Sign In</h2>
&nbsp
<form name="form1" method="post" action="log.php?action=login">
    <b>Username:</b> &nbsp<input type="text" name="uname"/><br />&nbsp <br />
  <b>Password:</b>&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp <input type="password" name="pword" /><br />&nbsp <br />
   <input type="submit" value="submit" />
</form>
<?php  include_once "Common/footer.php"; ?>

LOG.PHP
Code: [Select]
<?php 
    session_name("MyLogin");
    session_start();
    
    if($_GET['action'] == "login") {
        $conn = mysql_connect("localhost", "root", "");
        $db = mysql_select_db("test");
        $name = ($_POST['uname']);
        $word = ($_POST['pword']);
        $sql = "SELECT * FROM Users WHERE Username='$name' and Password='$word'";
        $q_user = mysql_query($sql) or die(mysql_error() . ' <br /> in ' . $sql);
        
        if(mysql_num_rows($q_user) == 1){
            $_SESSION['uname'] = $_POST['uname'];
            header("Location: login_success.php");
            exit;
        } else{
            header("Location: login.php?login=failed&cause=".urlencode('Invalid Username or Password'));
            exit;
        }

    } else{
        header("Location: login.php?login=failed&cause=".urlencode('Invalid User'));
        exit;
    }

    
    if(session_is_registered("name") == false) {
        header("Location: login.php");
    }

    ?>

LOGIN_SUCCESS.PHP
Code: [Select]
<?php
include_once "Common/header.php";
    $connect=mysql_connect("localhost", "root", "")or die ("Could not connect to database");
    $data = mysql_query("SELECT * FROM Users WHERE Username ='$name'")  or die(mysql_error());
    Print "<table border cellpadding=3>";
    while($info = mysql_fetch_array( $data ))  {
        Print "<tr>";
        Print "<th>First Name:</th> <td>".$info['First_Name'] . "</td> ";
        Print "<th>Last:</th> <td>".$info['Last_Name'] . " </td></tr>";
    }

    Print "</table>";
    ?>
Login Successful
<?php  include_once "Common/footer.php"; ?>

Hi all

I am having some issues

basically

Code: [Select]
$sftp->put("server.properties",
"allow-nether=".$nether."
level-name=".$lname."");

is not printing the variables. $sftp is part of the phpseclib and the fuction is in the same format as fwrite(), I have tried and failed using fwrite as well! I can echo out the 1st variable correctly, but as soon as I add the second I just get

Code: [Select]
allow-nether=
level-name=

The variables $nether and $lname exist and I have echo'd them to check.

I guess this is a formatting problem, just cant work it out!

So say I have a file with the contents..

Code: [Select]
; this is a comment
var2 : variable
; another comment
var3 : file.txt


how would I be able to do



<?php

echo $var2; 

?>



That would echo "variable"

and

<?php

$file = file($var3);

?>



So its reading the file to get the variable from the text file and if the line starts with ";" its disregarded..


Thanks

So here is what I have going.

#1 - My weather station software processes a file and enters variables and then uploads it as a php file.
#2 - Currently the station also just uploads every file to the site and enters the data in the html, but I would rather have it only upload this one file and the other pages grab data from it and print it out. I have a few php scrips in there to preform certain functions (if temp <= 32 it echos that data in blue and so on) but would rather make most of it php so I have less files being uploaded every 5 minutes.

This is what the station sends to the web, but I have no idea how to get the other pages to read it and input the variables from it.

Hi, I am trying to create a login system in PHP, but I am not the greatest at PHP so I am using a source code which I found online as I found it to be more secure as it uses things like salted passwords. Anyway I am trying to add more fields to the register system so it adds them to the mysql, the source has a way to do this with arrays, but it is quite complicated so I am just using variables from the original file. There are 2 files: register.php and class.loginsys.php which contains all the functions. At first the query syntax was incorrect so I decided to use the variables created in register.php in the class.loginsys, but now it's giving me an out of memory error:
Fatal error: Allowed memory size of 134217728 bytes exhausted (tried to allocate 28672 bytes) in C:\xampp\htdocs\ls\class.loginsys.php on line 34    Which I am unsure of how to fix. I have tried using different variable names, checking the line, checking the whole register.php file for anything rogue. Here is the code:  Top part of register.php 

<?php
include "config.php";
?>

Config.php: 

<?php
require "class.loginsys.php";
$LS=new LoginSystem();
?>

Then actual register part from register.php: 

<?php
	   	if( isset($_POST['submit']) ){
	   			$firstname2 = $_POST['firstname'];
	   			$lastname2 = $_POST['lastname'];
	    		$user2	 = $_POST['username'];
	    		$sex2 = $_POST['sex'];
	    		$country2 = $_POST['strCountryChoice'];
	    		$email2 = $_POST['email'];
	    		$pass2	 = $_POST['pass'];
	    		$pass3 = $_POST['pass2'];
	    		$birthdate2 = $_POST['birthdate'];
	    		$created2 = date("Y-m-d H:i:s");
	    		//need to add a lot more validation functions.. AKA Check if email exists and username. Password > 5 chars
	    		if( $user2=="" || $email2=="" || $pass2=='' || $pass3=='' || $firstname2=='' || $lastname2=='' || $sex2=='' || $country2=='' || $birthdate2=='' ){
	     			echo "Fields Left Blank","Some Fields were left blank. Please fill up all fields.";
	     			exit;
	    		}
	    		if( !$LS->validEmail($email2) ){
	     			echo "E-Mail Is Not Valid", "The E-Mail you gave is not valid";
	     			exit;
	    		}
	    		if( !ctype_alnum($user2) ){
	     			echo "Invalid Username", "The Username is not valid. Only ALPHANUMERIC characters are allowed and shouldn't exceed 10 characters.";
	     			exit;
	    		}
	    		if($pass2 != $pass3){
		     		echo "Passwords Don't Match","The Passwords you entered didn't match";
	     			exit;
	    		}
   	 		$createAccount2 = $LS->register($user2, $pass2,
	    			array(
	    				"email" 	 => $email2,
	    				"name" 	 => $firstname2,
	    				"lastname" => $lastname2,
	    				"gender" => $sex2,
	    				"country" => $country2,
	    				"DOB" => $birthdate2,
	    				"created" => date("Y-m-d H:i:s") // Just for testing

	    			)
	    		);
			//$createAccount = $LS->register($firstname,$lastname,$user,$sex,$country,$email,$pass,$birthdate,$created);
	    		if($createAccount2 === "exists"){
	     			echo "User Exists.";
	    		}elseif($createAccount2 === true){
	     			echo "Success. Created account.";
	    		}
	   	}
	   	?>

And the function from the class: 

	/* A function to register a user with passing the username, password and optionally any other additional fields. */
	public function register( $id, $password, $other = array() ){
		if( $this->userExists($id) && (isset($other['email']) && $this->userExists($other['email'])) ){
			return "exists";
		}else{
			$randomSalt	= $this->rand_string(20);
			$saltedPass	= hash('sha256', "{$password}{$this->passwordSalt}{$randomSalt}");
			
			if( count($other) == 0 ){
				/* If there is no other fields mentioned, make the default query */
				//old query: ("INSERT INTO `{$this->dbtable}` (`username`, `password`, `password_salt`) VALUES(:username, :password, :passwordSalt)");
				//new query: ("INSERT INTO `{$this->dbtable}` (`username`, 'email' , `password`, `password_salt` , 'name' , 'lastname' , 'gender' , 'country' , 'DOB') VALUES(:username, :email, :pass, :passwordSalt, :firstname, :lastname, :gender, :country, :DOB)");
				$sql = $this->dbh->prepare("INSERT INTO `{$this->dbtable}` (`username`, `password`, `password_salt`) VALUES(:username, :password, :passwordSalt)");
			}else{
				/* if there are other fields to add value to, make the query and bind values according to it */
				//old query: ("INSERT INTO `{$this->dbtable}` (`username`, `password`, `password_salt`, $columns) VALUES(:username, :password, :passwordSalt, :$colVals)");
				//new query: ("INSERT INTO `{$this->dbtable}` (`username`, 'email' , `password`, `password_salt` , 'name' , 'lastname' , 'gender' , 'country' , 'DOB') VALUES(:username, :email, :pass, :passwordSalt, :firstname, :lastname, :gender, :country, :DOB)");
				$keys	 = array_keys($other);
				$columns = implode(",", $keys);
				$colVals = implode(",:", $keys);
			//l= $this->dbh->prepare("INSERT INTO `{$this->dbtable}` (`username`, `password`, `password_salt`, $columns) VALUES(:username, :password, :passwordSalt, :$colVals)");
				//INSERT INTO MyGuests (firstname, lastname, email)cLUES ('John', 'Doe', 'john@example.com')
				$sql = $this->dbh->prepare("INSERT INTO `{$this->dbtable}` (username,email,password,password_salt,name,lastname,created,gender,country,DOB) VALUES ('$username2','$email2','$pass2','$saltedPass','$firstname2','$lastname2','$created2','$gender2','$country2','$birthdate2')");
				print($sql);
				foreach($other as $key => $value){
					$value = htmlspecialchars($value);
					$sql->bindValue(":$key", $value);
				}
			}
			/* Bind the default values */
			$sql->bindValue(":username", $id);
			$sql->bindValue(":password", $saltedPass);
			$sql->bindValue(":passwordSalt", $randomSalt);
			$sql->execute();
			return true;
		}
	}
	

Thanks for your help. I am doing this because for a hobby I am trying to create a browser based game in which I use this login system to login the user to a main page then code all of the other pages myself. I have posted on stackoverflow and someone on their suggested that I should use a framework. If this is the case, can someone point me in the right direction?   Thanks again, if you need any info ask.

So I have a text file "name.txt"

in the text file I have ids and auth keys set up like this

1234564 abcdfhu
3123900 sdkoao

etc

How could I make it to where the ids are $ids and the auth keys are $auth_keys?

I've tried using foreach() but I cant get it

It's been a while since I've dealt with text files and currently I am unable to write the contents of a variable to a text file, only the literal is being written. Should I be de-referencing or is this even possible? Also the problem is compounded by the fact that i also want to write the contents of a class display function into the text file. 

For example:

I am using this code:

Code: [Select]
$myFile = "newuser.txt";
$fh = fopen($myFile, 'r');
$theData = fread($fh, 5);
fclose($fh);
echo $theData;
and it displays:

Code: [Select]
Bob 2 Which I am reading from my newuser.txt file!

Which corresponds to the username bob, and he has the ID of 2.

Now I want to make that linkable like this:

Code: [Select]
<a href=.?act=Profile&id=$IDFROMTEXTFILE(2)>$NAMEFROMTEXTFILE(BOB)</a>

this is possible? If so, Thanks!

I have a php file with a bunch of variables declared.  I now need a function to put data on a separate page that pulls variables from the required page.

So, on the required page, I have a variable set like this:  $qb1 = "John Doe";

The function on the new script is called like this:  getplayer($qb1);

I've tried this without the dollar sign in the function like this: getplayer(qb1); and then adding the $dollar sign in the rest of the function code...but it never populates the sql query correctly.  I'm guessing this is a case for variable variables or something similar, but I don't know how to get the variable value from the required page.  Any ideas?  Thanks.

Here's the code:

	<?php
	function getplayer($position)
{ // start function
	//$new_position = "$" . $position;
$new_position = $position;
	
$file = "their.php";
require "$file";
//echo $qb1;    this displays the name John Doe...as $qb1 is declared in the required file
	
$db_select_their = "bschultz_their";
	$servername = "localhost";
$username = "user";
$password = "pass";
$dbname = "db_name";
	// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}
	$sql = "SELECT * FROM (select number as position_number, name as position_name, pronunciation as position_pronunciation, pos as position_pos, height as position_height, weight as position_weight, year as position_year, city as position_city, state as position_state, notes as position_notes FROM $db_select_their WHERE name = '$new_position') as position";
	//$sql = "SELECT * FROM bschultz_their WHERE name = $new_position";
   
echo $sql; //exit;        
/*
this displays this text...   SELECT * FROM (select number as position_number, name as position_name, pronunciation as position_pronunciation, pos as position_pos, height as position_height, weight as position_weight, year as position_year, city as  position_city, state as position_state, notes as position_notes FROM bschultz_their WHERE name = '') as position

The name is empty
*/
	$result = $conn->query($sql);
	if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        echo "#: " . $position_number . " - Name: " . $position_name . "";
    }
} else {
    echo "0 results";
}
	} // end function
	
getplayer("${$qb1}");
$conn->close();
?>

Edited September 8, 2019 by bschultz

Hello all,

I am trying to create a PHP CLi Script that will help me setup new config and server files / directories for every new web project i get instead of me having to manually create everything with each project. The script accepts the project name, and y/n for whether i want to create subdomains for css, jss and image files. After it has that, it must create a new http config file under sites-available (in Linux), by pasting the config file text.

Problem : If I output regular text to the file, it displays exactly in the format that I write the string variable. But when I use a printf, or try to use variables directly in the config text, it starts formatting the text in the config file in a strange way. I just want the variables to just be replaced and the text to appear in the exact format below. The text displays perfectly as i typed below in the config file if I don't use any variables.


$subDomainConfig .=
'<VirtualHost *:80>
ServerAdmin webmaster@%1$s
ServerName  %1$s.%2$s
ServerAlias %1$s.%2$s

# Indexes + Directory Root.
DirectoryIndex index.html index.php
DocumentRoot /var/www/%2$s/public_html/

# CGI Directory
ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/
<Location /cgi-bin>
Options +ExecCGI
</Location>


# Logfiles
ErrorLog  /var/www/%2$s/logs/apache/error.log
CustomLog /var/www/%2$s/logs/apache/access.log combined
</VirtualHost>
'.PHP_EOL;
$httpConfigFileText = sprintf($subDomainConfig, $subDomain, $shortProjectName);


The above code outputs text in this way in the file :

<VirtualHost *:80>
   ServerAdmin webmaster@images
   ServerName  images.mysite

   ServerAlias images.mysite


   # Indexes + Directory Root.
   DirectoryIndex index.html index.php
   DocumentRoot /var/www/mysite
/public_html/

   # CGI Directory
   ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/
   <Location /cgi-bin>
      Options +ExecCGI
   </Location>


   # Logfiles
   ErrorLog  /var/www/mysite
/logs/apache/error.log
   CustomLog /var/www/mysite
/logs/apache/access.log combined
</VirtualHost>   

PLEASE HELP! 
I need help I am a new php user, and am trying to understand how to read a .txt file into an array then to retrieve the index of the array at will.
Code: [Select]
<?php 
//echo $myfile = fopen("ArrayTestFile.txt", "r") . "File exists: " or die("File does not exist or you lack permission to open it! ");
//echo "The contents of the file is " . file_get_contents("ArrayTestFile.txt") . "<br />";
$fh = fopen("ArrayTestFile.txt", 'r+') or die("Failure");
$array = array(); //creation of array
$num = fgets($fh);// recursive call variable $num fgets(.txt line) 
for ($i = 0; $i <= 5; $i++) //for loop loads first 5 of .txt
   {
    $array["i"] = $num; //loads each line of .txt into the array at the loops index.
    echo "Line " . $i . " of the array is " . $array["i"]; // displays the contents of the array in a print message 
   }
?>
Thank you.

MOD EDIT: code tags added.

Hello. Trying to learn MVC better by creating my own little framework to understand how it works.

Things were going OK til now.

I have a base class:

<?php

/**
 * Base class most classes will extend from.
 * Simply put, this class just has methods that
 * most, if not all, classes will need.
 */

class Application {

public function includer($path) {

if (is_readable($path) == true) {
include_once($path);
} else {
die("404 not found =[");
}
}




}
?>


So the above method 'includer' just sees if a file exists/is readable and if so, include it.

Here's where I am using said method.


class Index extends Application {

function __construct($method = 'view') {
// load the index model
include(ROOT . '/app/models/model.index.php');

// Invoke requested method.
$this->$method();
}

public function view() {

$name = 'Smith';
$this->includer(ROOT . '/app/views/view.index.php'); # Problem here, i think
}


}


view.index.php just contains
<?php echo $name; ?>


All that is called from the index page, with this line of code
Application::includer($controller_path);


Now, in line
$this->includer(ROOT . '/app/views/view.index.php'); # Problem here, i think

If i get rid of $this->includer, the script will work and say 'Smith'.

If i have $this->includer(...) or parent::includer(...), it doesn't work.

why?