PHP - Function Call(passing An Argument)

I think this is a simple question, but I'm just starting out and can't figure out how to do this exactly.

I'm making a demo site for a flower shop. The structure is as such (only listing the particular files in question - once this is done, the rest will be easy)

index.php -> inc_show_colors.php -> showColors.php

The index is to be standard through the site, loading include files into a main content area.  Clicking on a link loads inc_by_color.php (index.php -> index.php?page=by_color )

From there, one of the four colors is selected.

showColors.php contains switch statements for each color. I want to load showColors.php into the main content window when a color is selected, and I need to have it work for all four colors. I'm not sure how to do this, as you can't pass a variable to an include from what I understand.

What's the easiest way to go about this? Keep in mind this is an intro class and "best practices" are not necessary yet, just the simplest solution to get it working.

 I want each of these colors to link to another include file, which will load in its place in index.php.


index.php:
Code: [Select]
<div id="maincontent">
<?php
if (isset($_GET['page'])) {
switch ($_GET['page']) {
case 'by_color':
include('includes/inc_by_color.php');
break;
case 'by_type':
include('includes/inc_by_type.php');
break;
case 'by_occasion':
include('includes/inc_by_occasion.php');
break;
case 'view_cart':
include('includes/inc_view_cart.php');
break;
case 'payment_options':
include('includes/inc_payment_options.php');
break;

case 'home_page':
default:
include('includes/inc_home.php');
break;
}
}
else 
include('includes/inc_home.php');

?>
</div>

inc_by_color.php:
The first link I tried doing in the way I thought would work, but it doesn't. It can't find the include file.
The second one works, kind of - but it just loads the page by itself, not into the maincontent div in index.php.
Code: [Select]
<h1>Flowers Categorized by Color</h1>
<div class="picdivcontainer">
<div class="picdiv"><a href="index.php?page=red"><img src="images/image.png" width="90" height="90" alt="Red Flowers" />
  <p>Red</a></p></div>
<div class="picdiv"><a href="showColors.php?color=white"><img src="images/image.png" width="90" height="90" alt="White Flowers" /></a>
  <p><a href="showColors.php?color=white">White</a></p></div>
</div>

and showColors.php:
Code: [Select]
if (isset($_GET['color'])) {
switch ($_GET['color']) {
case 'red':
$result = mysql_query("SELECT * FROM flowers WHERE color='red'") or die(mysql_error());
while($row = mysql_fetch_array( $result )) {
// Set and trim strings and show the resulting flowers from query
$flowername = $row['name'];
$flowerimage = $row['image'];
$image_path = "images/";
$flowername = str_replace('_', ' ', $flowername);
$flowername = ucwords($flowername);
?> <div class="picdiv"><p><?php echo $flowername."<br />";
$flowerimage = str_replace(' ', '_', $flowerimage);
echo "<img src='images/" . $row['image'] . "' />";
?></p></div> <?php
} 
break;
I realize that showColors.php is probably a really messy way of doing this, but I just need to get it functioning ASAP for now.

This topic has been moved to Other Libraries and Frameworks.

http://www.phpfreaks.com/forums/index.php?topic=319682.0

I can call the following function successfully as a single php program

  // Acknowledge and clear the orders
   function ack($client, $merchant, $id) {
         $docs = array('string' => $id);
         $params = array('merchant' => $merchant, 'documentIdentifierArray' => $docs);
         $result = $client->call('postDocumentDownloadAck', $params);
         return $result;
         }
with

   $result = ack($t, $merchant,'2779540483');

successful output

    [documentDownloadAckProcessingStatus] => _SUCCESSFUL_
    [documentID] => 2779540483

I'm trying to figure out how to call this function as an object from another program.

Trying the following gives error  ***Call to a member function call() on a non-object***

  function postDocumentDownloadAck($t, $merchant, $id) {
     $this->error = null;
     $docs = array('string' => $this->id);
     $params = array('merchant' => $this->merchant, 'documentIdentifierArray' => $docs);

 **  I've tried the following which does nothing
     $result = $this->soap->call('postDocumentDownloadAck', $params);

** I've tried the following   -  which gives error "Call to a member function call() on a non-object"
     $result = $this->t->soap->call('postDocumentDownloadAck', $params);

     if($this->soap->fault) {
        $this->error = $result;
        return false;
     }

     return $result;
  }


***

calling program snippet for above function
   $merchant= array( "merchant"=> $merchantid, "merchantName" => $merchantname, "email"=> $login, "password"=> $password);
   $t = new AmazonMerchantAPI($merchantid, $merchantname, $login, $password);
   $documentlist= $t->GetAllPendingDocumentInfo('_GET_ORDERS_DATA_');
   $docid = $documentlist['MerchantDocumentInfo'][$i]['documentID'];
   $docs = array('string' => $docid);
   $ackorders = $t->postDocumentDownloadAck($t, $merchant,$docs);

Any ideas of what I'm doing wrong are greatly appreciated.

hi there,

i am fairly new to OOPs in php, i get an error when i declare the argument type (as object) in a function and pass the same type (object).



class eBlast {
       public static function getEmail(object $result) {
           return $result->email;
       }
}

$r = mysql_fetch_object($query);
eBlast::getEmail($r);

echo gettype($r); // outputs: object



error is :

Code: [Select]
Catchable fatal error: Argument 1 passed to eBlast::getEmail() must be an instance of object, instance of stdClass given, called in C:\wamp\www\integra\client\pl_eblast\admin\send_emails.php on line 145 and defined in C:\wamp\www\integra\client\pl_eblast\app\app.eBlast.php on line 8
if i remove the type declaration in the function it works, but just would like to know why it shows error when pass the same type, also isnt mysql_fetch_object is the instance of stdclass?

thanks in advance!

Im getting a warning with in_array.I have used if() inside for loop to check if value has already been printed or not. If not it will print and save the value in $done[].Can someone please point me out my mistake that i am getting a warning.

Code: [Select]
<?php
             for($i=0;$i<=$count;$i++)
                {   
                    $count_final = explode("_", $result[$i]);
                   if (in_array($count_final[0],$done)) 
                    {  //Line 480
                    echo "<tr>";
                    echo"<td>$count_final[0]</td>";
                    $templ = $count_final[0]."_left";
                    $tempr = $count_final[0]."_right";
                    $cleft = $count_middle[$templ];
                    $cright = $count_middle[$tempr];
                    echo"<td>$cright</td>";  
                    echo"<td>$cleft</td>";
                    echo "</tr>"; 
                    $done[] = $count_final[0];
                   }
                }    
?> Code: [Select]
Warning: in_array() [function.in-array]: Wrong datatype for second argument in C:\Users\\Desktop\yyy.php on line 480