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PHP - Foreach Giving More Rows Han Expected
Hello, this is my first post in this forum, in fact my first post about php.
I am developing a crud application, but when i am trying to list a set of results it gives me more that the expected Let me explain. if i print_r my array (which i get it from a sql result) it gives me this Array ( => SHR1 [codprod] => SHR1 [1] => REGULAR SERVICE HOUR [proddescription] => REGULAR SERVICE HOUR [2] => 3.00 [qty] => 3.00 [3] => HR Code: [Select] => HR [4] => 45.0000 [price] => 45.0000 [5] => 0.00 [discount] => 0.00 [6] => 135.00 [amount] => 135.00 ) [/li][/list] if I foreach($detailrow as $value){ echo $detailrow['codprod'] . ", " . $detailrow['proddescription'] . ", " . $detailrow['qty'] . ", " . $detailrow['code'] . ", " . $detailrow['price'] . ", " . $detailrow['discount'] . ", " . $detailrow['amount'] . "<br/>"; } It gives me 14 rows with the same info. I run the query in mysql and it gives me only 1 result as expected. I noticed that the 14 rows are the same quantity of items in the array not results but let say columns, i dont know if it has something to do with the results. My questions: Why it is giving me 14 rows instead just one? What is the $value in the foreach function? why can't i just say foreach($myarray)? why the print_r shows me the items array duplicated using the array position and the item name? Thank you for your help!! Similar TutorialsI have a simple foreach loop. The array has four rows in it. Really simple. I have confirmed the data in the array with var_dump. For some reason I cannot fathom, the loop is only processing rows 0 and 2 and is not processing 1 and 3.
Here's the code snippet:
<?php
foreach ($postCals as $key=>$cal){
var_dump($postCals, $cal, $key);
echo '<td style="text-align:right;>' . $cal . "</td>";
}
?>
$postCals has precisely 4 values. Here's the output from this part of the code (in terms of the var_dumps).
array (size=4)0 => string '2.00000' (length=7) 1 => string '2.00000' (length=7) 2 => string '3.20000' (length=7) 3 => string '4.00000' (length=7) string '2.00000' (length=7) int 0 array (size=4) 0 => string '2.00000' (length=7) 1 => string '2.00000' (length=7) 2 => string '3.20000' (length=7) 3 => string '4.00000' (length=7) string '3.20000' (length=7) int 2 That's it. I two other foreach loops identical to this and they run fine! Any ideas? (misc info: php: 5.4.7 running on XAMPP/Windows ) Hi, after banging my head against the wall for a while thinking this would be a simple task, I'm discovering that this is more complicated than I thought. Basically what I have is a link table linking together source_id and subject_id. For each subject there are multiple sources associated with each. I had created a basic listing of sources by subject... no problem. I now need a way of having a form to create an ordered list in a user-specified way. In other words, I can currently order by id or alphabetically (subject name lives on a different table), but I need the option of choosing the order in which they display. I added another row to this table called order_by. No problem again, and I can manage all of this in the database, however I want to create a basic form where I can view sources by subject and then enter a number that I can use for sorting. I started off looping through each of the entries and the database (with a where), and creating a foreach like so (with the subject_id being grabbed via GET from the URL on a previous script) Code: [Select] while($row = mysqli_fetch_array($rs)) { //update row order if (isset($_POST['submit'])) { //get variables, and assign order $subject_id = $_GET['subject_id']; $order_by = $_POST['order_by']; $source_id = $row['source_id']; //echo 'Order by entered as ' . $order_by . '<br />'; foreach ($_POST['order_by'] as $order_by) { $qorder = "UPDATE source_subject set order_by = '$order_by' WHERE source_id = '$source_id' AND subject_id = '$subject_id'"; mysqli_query($dbc, $qorder) or die ('could not insert order'); // echo $subject_id . ', ' . $order_by . ', ' . $source_id; // echo '<br />'; } } else { $subject_id = $_GET['subject_id']; $order_by = $row['order_by']; $source_id = $row['source_id']; } And have the line in the form like so: Code: [Select] echo '<input type="text" id="order_by" name="order_by[]" size="1" value="'. $order_by .'"/> (yes I know I didn't escape the input field... it's all stored in an htaccess protected directory; I will clean it up later once I get it to work) This, of course, results in every source_id getting the same "order_by" no matter what I put into each field. I'm thinking that I need to do some sort of foreach where I go through foreach source_id and have it update the "order_by" field for each one, but I must admit I'm not sure how to go about this (the flaws of being self-taught I suppose; I don't have anyone to go to on this). I'm hoping someone here can help? Thanks a ton in advance This topic has been moved to Application Frameworks. http://www.phpfreaks.com/forums/index.php?topic=355772.0 what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. I have 2 queries that I want to join together to make one row
Hello everyone, I'm working on an account update page where users can update their email address, password, or security question/answer as desired. The way I currently have it set up is so that only the information that the user enters will be updated in the database. So if they only enter a new email address, the email field in the database is updated and all other fields are left as is. I'm also trying to set a javascript even handler (onUnload) depending on whether or not anything was updated. When their info is successfully updated, I want to alert the user accordingly, as well as when no information was updated. To do this, I have a variable "$updated" that is set at "false" by default and is supposed to be set to "true" when something is updated and "none" when nothing is updated. The form and mysql commands are working and the correct fields are being updated as expected. The problem that I'm having is the $updated variable is not being set correctly and is ALWAYS being set to "true", even when it is expect to be set to "none." Here's the code that I have: Code: [Select] <?php function safe($value){ return mysql_real_escape_string($value); } $updated = "false"; if (isset($_POST['submit'])) { // If the form has been submitted. $newemail = $_POST['newemail']; $pword1 = $_POST['pword']; $question = safe($_POST['question']); $answer = safe($_POST['answer']); $updated = $_POST['updated']; $pword = md5($pword1); $q = mysql_query("SELECT * FROM `signin` WHERE email = '$newemail'") or die (mysql_error()); $r = mysql_num_rows($q); // Checks to see if anything is in the db. if ($r == 1 && $email == $newemail) { $noemail = "true"; } elseif ($r == 0) { $noemail = "true"; } else { $noemail = "false"; } if ($newemail != "" && $pword1 == "" && $question == "0") { if ($noemail == "true") { mysql_query("UPDATE `signin` SET `email` = '$newemail' WHERE email = '$email'") or die (mysql_error()); $_SESSION['email'] = $newemail; $updated = "true"; } } elseif ($newemail == "" && $pword1 != "" && $question == "0") { mysql_query("UPDATE `signin` SET `pword` = '$pword' WHERE email = '$email'") or die (mysql_error()); $updated = "true"; } elseif ($newemail == "" && $pword1 == "" && $question != "0") { mysql_query("UPDATE `signin` SET `question` = '$question',`answer` = '$answer' WHERE email = '$email'") or die (mysql_error()); $updated = "true"; } elseif ($newemail != "" && $pword1 != "" && $question == "0") { if ($noemail == "true") { mysql_query("UPDATE `signin` SET `email` = '$newemail',`pword` = '$pword' WHERE email = '$email'") or die (mysql_error()); $_SESSION['email'] = $newemail; $updated = "true"; } } elseif ($newemail != "" && $pword1 == "" && $question != "0") { if ($noemail == "true") { mysql_query("UPDATE `signin` SET `email` = '$newemail',`question` = '$question',`answer` = '$answer' WHERE email = '$email'") or die (mysql_error()); $_SESSION['email'] = $newemail; $updated = "true"; } } elseif ($newemail == "" && $pword1 != "" && $question != "0") { mysql_query("UPDATE `signin` SET `pword` = '$pword',`question` = '$question',`answer` = '$answer' WHERE email = '$email'") or die (mysql_error()); $updated = "true"; } elseif ($newemail != "" && $pword1 != "" && $question != "0") { if ($noemail == "true") { mysql_query("UPDATE `signin` SET `email` = '$newemail',`pword` = '$pword',`question` = '$question',`answer` = '$answer' WHERE email = '$email'") or die (mysql_error()); $_SESSION['email'] = $newemail; $updated = "true"; } } else { $updated == "none"; } } ?> //This is where the event handler (onUnload) is set according to what has occurred in the code above <?php if (isset($_POST['submit']) && $updated = "true") { echo "<body onUnload=\"alert('Your information has been successfully updated.')\">"; } elseif (isset($_POST['submit']) && $updated = "false") { echo "<body onUnload=\"alert('There have been no updates made to your account information.')\">"; } else { echo "<body>"; } ?> Can anyone see a problem with this and why the $updated variable is not being set as expected. Any ideas on a better way to accomplish what I want to do? Thanks in advance for anyone's help! Hello I want to check that a variable the user enters is not empty and that it is a string (no numbers). Here is what i have written: Code: [Select] <?php include('css/layout.css.php'); include('css/menu.css'); if (isset($_POST['submit'])) { include('includes/dbconn.php'); if (is_string($_POST['name']) && strlen($_POST['name']) > 0) { $name = mysql_real_escape_string($_POST['name']); } else { echo "Category name must be a word!<br />"; } if (isset($name)) { echo $name; } else { echo "something"; } } ?> and this is the form i'm getting the data from: Code: [Select] <form action="category_add.php" method="post"> <table class="table-view"> <tr> <td><label for="name">Category Name</label></td> <td><input type="text" name="name" id="name"></td> </tr> <tr> <td><input type="submit" value="Save changes" name="submit" id="submit"></td> </tr> </table> </form> If i enter nothing it works fine, if i enter a string it also works fine, the problem is when i enter 123 in the textbox, i dont get the "Category name must be a word!" as i expected i would. Could someone help me with this one please? Thanks in advance. I wish to find a way to test if multiple sites are up or not. I have been using get_headers but it seems that this does not do what I thought I would. I wish to know if the sites are down or not. Is there another function that can test what state the site is in. i.e. server not found, server issues prevented the page from showing... Using get_headers will still show the site is live even if the server is not found, due to server problems, if any. I'm using PHP 5.2.14 under Windows XP. I'm trying to use ini_set to turn on the 'track_error' configuration option, and it's not working. I make this call, $xxx = ini_set('track_error',"1"); and it returns false. According to the documentation, track_error can be set from any source (including ini_set). What could prevent that from happening? Going back one step, I want to set track_errors so that I can fetch and process the error which occurs when mysql_connect fails. Since it fails, it returns no link, making it impossible to call mysql_errors. Whether ini_set can be made to work or not, is there another, perhaps better way to accomplish this? Hello.
I'm having some issues with a select statement containing ABS().
Here's the select query:
"SELECT gadenavn, husnr, ABS(husnr - $husnr) AS husnr_range, postnr,db, shaping, dsl_node, ctr_node, db_ctr_luftlinje, bynavn FROM `TABLE 1`, Post_numre WHERE `postnr`=`postnummer` AND `gadenavn`=`$vejnavn` AND `postnr`=`$postnr` AND `husnr`>0 ORDER BY husnr_range ASC LIMIT 5"Now lets asume my variable "$husnr" is a value of 15. In my table I have the values for coulmn "husnr": 13,12,11,10,9 What really bugs me is the outcome doing af simple "while loop" is returning the values 12,11,10,9. What happened to 13?! printing the "husnr_range" values shows "3,4,5,6". What puzzles is the row missing, as I only get 4 results, with a "LIMIT 5". Can anyone explain why the last resulst isn't included? I have a form on a page that has checkboxes for a number of entities, including one that is new. I want to determine how many checkboxes were checked for the new entity. The html is:
<div id="new" style="display:block;">Which method(s) of valuation would you like to use for this report?<br /> <input type="checkbox" name="method_code['new'][]" value="EE">Excess Earnings<br /> <input type="checkbox" name="method_code['new'][]" value="DCF">Discounted Cash Flow</div> <div id="75" style="display:none;">Which method(s) of valuation would you like to use for this report?<br /><input type="checkbox" name="method_code['75'][]" value="EE" checked="checked" >Excess Earnings<br /> <input type="checkbox" name="method_code['75'][]" value="DCF" checked="checked" >Discounted Cash Flow</div><div id="79" style="display:none;">Which method(s) of valuation would you like to use for this report?<br /> <input type="checkbox" name="method_code['79'][]" value="EE">Excess Earnings<br /><input type="checkbox" name="method_code['79'][]" value="DCF">Discounted Cash Flow</div> <div id="77" style="display:none;">Which method(s) of valuation would you like to use for this report?<br /> <input type="checkbox" name="method_code['77'][]" value="EE">Excess Earnings<br /> <input type="checkbox" name="method_code['77'][]" value="DCF">Discounted Cash Flow</div>I looked for a method of counting the nuber of checked boxes for a given entity and found So, to count only non-empty: count(array_filter($array));here and here So I implemented that in my code and it doesn't work. I put in the following to debug:
echo '<pre>';
print_r($_POST['method_code']);
echo '</pre>';
echo "arraycount ".count(array_filter($_POST['method_code']['new']));die();
and I get the following output:
Array
(
['new'] => Array
(
[0] => EE
)
['75'] => Array
(
[0] => EE
[1] => DCF
)
['78'] => Array
(
[0] => EE
)
)
arraycount 0
Why is the count 0? I expect that count(array_filter($_POST['method_code']['new'])) would be one since there is one element in that array.
I have an avatar upload script. The uploading and moving of the image file to the correct directory works fine, but the displaying of the image causes problems. This is the code that is supposed to display the avatar. // _DISPLAY_ avatar - START $query2 = "SELECT * FROM user WHERE user_id = '$dbuser_id'"; $row2 = mysqli_query ($dbc, $query2) or die (mysqli_error($dbc)); $assoc2 = mysqli_fetch_assoc ($row2); $target = AVATAR_UPLOADPATH; $avatar_name = $target . $assoc2['avatar']; if (is_file($assoc2['avatar'])) { echo "<img src='$avatar_name' alt='Avatar' /><br /><br />"; } else { echo "is not a regular file"; } // END The avatar column in the MySQL database says: image.jpg So there's a regular file. What I want to accomplish: I want the script to check if there's an avatar in the database, if NOT, then it should say: "no avatar uploaded yet." But as it is now it's telling me that there's no regular file even if there is, as I said the avatar column has an entry saying: image.jpg. Should I use if !empty instead? The strange thing is it used to work, now for some reason it suddenly doesn't. EDIT: With !empty it works, am I using the is_file function incorrectly? I have only one result being displayed in a select query result whereas I'm expecting 4 results in an array. This is my code below. $sq2="SELECT course FROM course_reg WHERE userid=?";
$stm =$conn->prepare($sq2);
$stm->bind_param("s",$logged);
$stm->execute ();
$return2= $stm->get_result();
$r2 = $return2->fetch_all();
//print_r($r2);
foreach($r2 as $course){
foreach($course as $courses){
echo $courses;
}
}
If I do print_r($r2); it comes out with array containing all the possible results. When i loop through the array to get individual result, it only comes out with a single result. I.e CME211 I would be glad if you can help me figure where the issue is. Thanks!!!
I am trying to load all rows from a table in a database into a table on a webpage. I cannot understand why the following code does not work: Code: [Select] <?php ... echo "You are currently in a fleet. The details of the fleet are below.<br>"; $fleetName = $_SESSION['charFleetName']; $sqlFleetDetails = "SELECT * FROM `$fleetName`"; $queryFleetDetails = mysql_query($sqlFleetDetails); echo "<table>"; echo "<tr>"; echo "<th>Pilot</th>"; echo "<th>Ship</th>"; echo "<th>Type</th>"; echo "</tr>"; while($rowFleetDetails = mysql_fetch_array($queryFleetDetails)) { $charId = $rowFleetDetails['charId']; $charName = $rowFleetDetails['charName']; $shipHull = $rowFleetDetails['shipHull']; $shipType = $rowFleetDetails['shipType']; echo "<tr>"; echo "<td><a href=\"#\" onClick=\"CCPEVE.showInfo{1377, " . $charId . "}>" . $charName . "</a></td>"; echo "<td>" . $shipHull . "</td>"; if($shipType == 1) echo "<td>Logistics</td>"; if($shipType == 2) echo "<td>DPS Boat</td>"; if($shipType == 3) echo "<td>Sniper 120Km+</td>"; if($shipType == 4) echo "<td>Off-grid Booster</td>"; echo "</tr>"; } echo "</table><br>"; I originally had the $rowFleetDetails['charId'] and others in the echo instead of loading them into variables then echoing the variables but changed it to see if that was working, neither is. If I add an extra line outside of the while loop to echo the output of the array then the information is displayed fine, so I know that the information is being transferred from the table into the array correctly, but why is it not outputting properly in the While loop? Hello everyone. I am wondering how can i give different id's to a html form? Code: [Select] <?php ... if ($numrows!=0) { // fetching data from the database to variable while ($row = mysql_fetch_assoc($query)) { $view_jam = $row['jamname']; $view_recipe = $row['jamrecipe']; $view_rating = $row['jamrate']; $view_owner = $row['owner']; $view_comments = $row['comments']; $view_count = $row['count']; $view_id = $row['id']; $view_count2 = $row['count2']; echo "Jam name: <b>" . $view_jam . "</b><br />"; echo "Jam recipe: " . $view_recipe . "<br />"; echo "Owner: " . $view_owner . "<br />"; echo "Comments: " . $view_comments . "<br />"; echo "Jam Rating: " . $view_rating . "<br />"; [b]echo '<form action="main.php?id=jams" method="POST">[/b] Choose rating <input type="text" name="jamrate" /> <input type="submit" name="submit1" value="Rate"> </form><br /><br />'; ... ?>As you can see, the form is inside a loop. I am trying to build a rating system. When there is only one row in a database then everything goes smoothly, but if there are more, then the rating applies to all rows. I suppose i need to give different id's to the form. How? Thank you Hello Everyone, I am working on a project where I have to go in and grab the names of the fields in a table. I got it to work and for it to show me the field names but it also displays a lot more than what I would like for it to do. I keep getting the following error. It is repeated over my screen like 15 times. Quote Warning: mysql_field_name() [function.mysql-field-name]: Field 5 is invalid for MySQL result index 7 in C:\xampp\htdocs\CMS\admin\includes\get_table.php on line 44 This is the section of code that it is referring to. Line 44 is Quote $tablecolumn .= "<p>" . mysql_field_name($fieldnamesquery_result, $table_field) . "<input type='text' name='" . mysql_field_name($fieldnamesquery_result, $table_field) . "' id='" . mysql_field_name($fieldnamesquery_result, $table_field) . "'/>"; Code: [Select] $tablecolumn = "<form name='insert_table' id='insert_table' action='get_database.php' method='post' > <fieldset> <legend>table information</legend>"; for ($table_field = 2; $table_field < $fieldnamesquery_result; $table_field++) { $tablecolumn .= "<p>" . mysql_field_name($fieldnamesquery_result, $table_field) . "<input type='text' name='" . mysql_field_name($fieldnamesquery_result, $table_field) . "' id='" . mysql_field_name($fieldnamesquery_result, $table_field) . "'/>"; <-----This is line 44 } $tablecolumn .= " <p> <input type='submit' name='submit_info' id='submit_info' /> </p> </fieldset> </form> "; echo $tablecolumn; Hello guys, I devised the code block below, to retrieve all US zip codes that are located within a specified radius from the user's own zip code. So basically, the user selects a maximum distance option from a form element (not shown here)which is appended to the variable $distance. What the code below does is as follows: The longitude and latitude corresponding to the user's zip code are retrieved in the first query. Then in the second query, the longitudes and latitudes corresponding to every zip code in the database are retrieved. In the ensuing while loop, a distance calculation is made between the user's zip and every other zip using the longitudes and latitudes and if that distance falls within the selected $distance, that particular zip code is listed in a defined array called $range. Now everything works fine up to this point as tested. The problem is with the very last line. I try to implode the $range array into a string with the same name, separating the array elements with commas (,). Then when I print out the resulting string, I get the list of desired zip codes but not separated by commas. For example: 9001190015900179003490037900439004790048900569006 19006290301 9030190301 90302 Well when I use a foreach loop as follows: foreach ($range as $r) {echo $r.",";} the $range array behaves like any normal array yielding: 90011,90015,90017,90034,90037,90043,90047,90048,90056,90061,90062,90301 ,90301,90301 ,90302, So why in the world is the implode function not working? Here is my code. //Retrieve the zip codes within range. // Connect to the database. require('config.php'); //Retrieve longitude and latitude of logged in member. $query = "SELECT* FROM members INNER JOIN zip_codes ON members.zip = zip_codes.zip WHERE members.member_id = '{$_SESSION['id']}'"; $result = mysql_query($query); $row = mysql_fetch_assoc($result); $my_lon = $row['lon']; $my_lat = $row['lat']; //Query all longitudes and latitudes in database. $query2 = "SELECT* FROM zip_codes INNER JOIN members ON members.zip = zip_codes.zip "; $result2 = mysql_query($query2); while ($row2 = mysql_fetch_assoc($result2)) { //Define array to hold zips found within range. $range = array(); if((rad2deg(acos(sin(deg2rad($my_lat))*sin(deg2rad($row2['lat'])) +cos (deg2rad($my_lat)) * cos (deg2rad($row2['lat'])) * cos(deg2rad($my_lon - $row2['lon'])) ) ) )*69.09 <= $distance ) { $range[] = $row2['zip']; } //Implode the range arrary. $range = implode(',' , $range); echo $range; }//End of while loop. I cannot get this INSERT to work. Not records are being added to the sys_city_dev table. No query errors are being thrown. I am simply trying to add ALL records from all_illinois to sys_city_dev and Mid should have be add as 11 in all inserts. city_name of course will be field city_name from all_illinois. Here is my code: $query = "SELECT * FROM all_illinois"; if ($results = mysqli_query($cxn, $query)) { $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($rows = mysqli_fetch_array($results)) { echo $rows['city_name'] . "<br />"; $mid_id = '11'; $insert_city_query = "INSERT INTO sys_city_dev (ID, Mid, cityName, forder, disdplay, cid) VALUES (' ','" . $mid_id . "','" . $rows['city_name'] . "', '', '','')"; if (!$insert_city_query) exit(mysql_error()); } } } Here is my insert table structure and 5 records dump: -- -- Table structure for table `sys_city_dev` -- CREATE TABLE IF NOT EXISTS `sys_city_dev` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `Mid` int(11) NOT NULL DEFAULT '0', `cityName` varchar(30) NOT NULL DEFAULT '', `forder` int(4) NOT NULL DEFAULT '0', `disdplay` int(4) NOT NULL DEFAULT '0', `cid` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=113970 ; -- -- Dumping data for table `sys_city_dev` -- INSERT INTO `sys_city_dev` (`ID`, `Mid`, `cityName`, `forder`, `disdplay`, `cid`) VALUES (84010, 1, 'Dothan', 0, 0, 0), (84011, 1, 'Alabaster', 0, 0, 0), (84012, 1, 'Birmingham', 0, 0, 0), (84013, 2, 'Flagstaff', 0, 0, 0), (84014, 1, 'Auburn', 0, 0, 0); And the all_illinois dump w/ 5 records: -- -- Table structure for table `all_illinois` -- CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; -- -- Dumping data for table `all_illinois` -- INSERT INTO `all_illinois` (`state_id`, `city_name`) VALUES ('135', 'Abingdon'), ('135', 'Adair'), ('135', 'Addieville'), ('135', 'Addison'), ('135', 'Adrian'); Hi all,
Wondered if anyone could assist?
On the following website the footer is not displaying as expected and cannot see why:
http://www.urxltd.com/index.php
Any other pages on the website show the footer correctly.
Thanks.
I am doing some study on using time() and date() and i just wrote this simple for loop to add one day to each iteration with +$i and its echoing the unix timestamp as opposed to the correctly formated date as it should be based on my code. Anyone have any idea why this is not working as expected? for($i=0; $i < 50; $i++) { echo $time = time()+$i . "<br />"; // add a day on each iteration echo date('y-m-d', $time) . "<br />"; // should echo 10-12-02, 10-12-03, 10-12-04, etc.. } what am i doing wrong here? arrgggg! maybe its too late for this s$%^#! |
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