PHP - Why Will This Variable: $prodname[$i] Not Insert
Hi - I'm quite confused. I have a variety of variables derived from a post array which all INSERT except for one: $prodname[$i]. Yet it will echo out, and Var_dump shows that it is a string. I have checked the table and the field is a 50 character varchar. If I hard code into my app 'foobar' ( a string ! ) instead of the variable it will insert. Theother variables that I am using will also insert - ok they are floats and ints.
If I remove the $prodname[$i] from my query, the query executes fine with the remaining values, but it fails with it in. Can anyone tell me what I need to do to get this one variable to insert ? I'm using MySQL 5.5 MANY THANKS ! Here is the code: Code: [Select] function confirmed_Order(){ $prodname = $_POST['prodname']; $prodid =$_POST['prodid']; $quantity = $_POST['quantity']; $pricelb = $_POST['pricelb']; $numloops = count($_POST['prodid']); for ($i = 0; $i < $numloops ; $i++) { echo "ProdName".$prodname[$i] . "ProdID".$prodid[$i]."Qunatity".$quantity[$i]. "Pricelb".$pricelb[$i]; // ECHOS FINE var_dump($prodname[$i]); // CONFIRMS IT IS A STRING $sql =" INSERT INTO `confirmedorder` (Prodid, Prodname, pricelb,quantity) VALUES ($prodid[$i], $prodname[$i],$pricelb[$i], $quantity[$i]) "; $this->db->query($sql); } } Similar TutorialsHello, I'm working on a PHP register form, all I want to do, is to be able to insert an extra variable into the database: Code: [Select] // now we insert it into the database $insert = " INSERT INTO users (username, password) VALUES ('".$_POST['username']."', '".$_POST['pass']."') "; $add_member = mysql_query($insert); right, so I have the username and password variable being passed. But I also want to pass a variable into a column called 'weaponAttachments', all I want for this variable to be is 5000. So, in other words, something like this: 5000['weaponAttachments'] Thanks Hello! I was wondering if this could be done... I want to take a variable, and insert it into a URL for a $_GET on a different page? Basically Its a member website, and I want the admin to be able to "accept" or "deny" the application... So i have a page that displays all the applications, and I want it to take him to a different page with all the user's information in detail. Right now it only displays their name, but when the admin presses the link, it takes them to a more detailed page about the applicant, where they can then "accept" or "deny" the application.... Here is what i got so far... Code: [Select] $character_name = "Nightmareinhell"; <a href="admin_evaluate.php?name=$character_name">$character_name</a> Here is the error I get from the code above Quote Parse error: syntax error, unexpected T_STRING in C:\wamp\www\admin_acceptapply.php Thanks to any help!!!! hello can anyone help me how to insert GET variable into mysql <?php $page_title = 'Personal Wellness'; include ('template/header.inc'); include_once('config.php'); $id = $_GET['id']; if(isset($_POST['submit'])) //if submit was pressed { if(strlen($_POST['height'])<1) //if there was no height { print "You did not enter a height."; } else if(strlen($_POST['weight'])<1) //no weight { print "You did not enter a weight."; } else if(strlen($_POST['bodyfat'])<1) //no bodyfat { print "You did not enter a Body Fat Range"; } else if (strlen ($_POST['bodywater'])<1) //no bodywater { print "You did not enter a Body Water Range"; } else if( strlen($_POST['musclemass'])<1) //no musclemass { print "You did not enter a Muscle Mass"; } else if (strlen ($_POST['physiqueratt'])<1) //no physiqueratt { print "You did not enter a Physique Ratings"; } else if (strlen ($_POST['bonemass'])<1) //no bonemass { print "You did not enter a Bone Mass"; } else if (strlen ($_POST['bmr'])<1) //no bmr { print "You did not enter a BMR"; } else if (strlen ($_POST['basalmetabolic'])<1) //no basalmetabolic { print "You did not enter a Basal Metabolic Age"; } else if (strlen ($_POST['visceralfat'])<1) //no visceralfat { print "You did not enter a Visceral Fat"; } else if(strlen($_POST['registrationmonth'] && $_POST['registrationday'] && $_POST['registrationyear'])<1) // no date { print "You did not enter a date of birth"; } else //all fields met { $id=$_GET['id']; $height=$_POST['height']; $weight=$_POST['weight']; $bodyfat=$_POST['bodyfat']; $bodywater=$_POST['bodywater']; $musclemass=$_POST['musclemass']; $physiqueratt=$_POST['physiqueratt']; $bonemass=$_POST['bonemass']; $bmr=$_POST['bmr']; $basalmetabolic=$_POST['basalmetabolic']; $visceralfat=$_POST['visceralfat']; $date=$_POST['registrationyear'] . '-' . $_POST['registrationmonth'] . '-' . $_POST['registrationday']; $insertadmin="INSERT into personalwelness (m_id,height,weight,body_fat,body_water,muscle_mas s,physique_ratt,bone_mass,bmr,basal_metabolic,visc eral_fat,evaluation_date) values ('$id','$height','$weight','$bodyfat','$bodywater','$mus clemass','$physiqueratt','$bonemass','$bmr','$basa lmetabolic','$visceralfat','$date')"; //registering admin in databae echo $insertadmin; $insertadmin2=mysql_query($insertadmin) or die("Could not insert admin"); print "Personal Wellness Successfully Submitted"; } } ?> <form method="post" class="form" action="<?php echo $_SERVER['PHP_SELF'];?>"> <fieldset><legend>Enter Personal Wellness Information in the form below:</legend> <table width="80%" border="0"> <tr> <td width="16%">Height(CM)</td> <td width="2%">:</td> <td width="82%"><label for="height"></label> <input type="text" name="height" id="height" value="<?php if (isset($_POST['height'])) echo $_POST['height'];?>" /></td> </tr> <tr> <td>Weight(KG)</td> <td>:</td> <td><label for="weight"></label> <input type="text" name="weight" id="weight" value="<?php if (isset($_POST['weight'])) echo $_POST['weight'];?>" /></td> </tr> <tr> <td >Body Fat Range</td> <td>:</td> <td><label for="body fat"></label> <input type="text" name="bodyfat" id="bodyfat" value="<?php if (isset($_POST['bodyfat'])) echo $_POST['bodyfat'];?>" ></td> </tr> <tr> <td>Body Water Range(%)</td> <td>:</td> <td><label for="bodywater"></label> <input type="text" name="bodywater" id="bodywater" value="<?php if (isset($_POST['bodywater'])) echo $_POST['bodywater'];?>"/></td> </tr> <tr> <td>Muscle Mass</td> <td>:</td> <td><label for="musclemass"></label> <input type="text" name="musclemass" id="musclemass" value="<?php if (isset($_POST['musclemass'])) echo $_POST['musclemass'];?>"></td> </tr> <tr> <td>Physique Ratings</td> <td>:</td> <td><label for="physiqueratt"></label> <input type="text" name="physiqueratt" id="physiqueratt" value="<?php if (isset($_POST['physiqueratt'])) echo $_POST['physiqueratt'];?>"></td> </tr> <tr> <td>Bone Mass</td> <td>:</td> <td><label for="bonemass"></label> <input type="text" name="bonemass" id="bonemass" value="<?php if (isset($_POST['bonemass'])) echo $_POST['bonemass'];?>" /></td> </tr> <tr> <td>BMR</td> <td>:</td> <td><label for="bmr"></label> <input type="text" name="bmr" id="bmr" value="<?php if (isset($_POST['bmr'])) echo $_POST['bmr'];?>"/></td> </tr> <tr> <td>Basal Metabolic Age</td> <td>:</td> <td><label for="basalmetabolic"></label> <input type="text" name="basalmetabolic" id="basalmetabolic" value="<?php if (isset($_POST['basalmetabolic'])) echo $_POST['basalmetabolic'];?>"></td> </tr> <tr> <td>Visceral Fat</td> <td>:</td> <td><label for="visceralfat"></label> <input type="text" name="visceralfat" id="visceralfat" value="<?php if (isset($_POST['visceralfat'])) echo $_POST['visceralfat'];?>"></td> </tr> <tr> <td>Evaluation Date</td> <td>:</td> <td> <?php echo date_picker("registration")?></td> </tr> </table> </fieldset> <div align="center"><input type="submit" name="submit" value="Submit" /> </div> </form> <?php function date_picker($name, $startyear=NULL, $endyear=NULL) { if($startyear==NULL) $startyear = date("Y")-100; if($endyear==NULL) $endyear=date("Y")+50; $months=array('','January','February','March','Apr il','May', 'June','July','August', 'September','October','November','December'); // Month dropdown $html="<select name=\"".$name."month\">"; for($i=1;$i<=12;$i++) { $html.="<option value='$i'>$months[$i]</option>"; } $html.="</select> "; // Day dropdown $html.="<select name=\"".$name."day\">"; for($i=1;$i<=31;$i++) { $html.="<option $selected value='$i'>$i</option>"; } $html.="</select> "; // Year dropdown $html.="<select name=\"".$name."year\">"; for($i=$startyear;$i<=$endyear;$i++) { $html.="<option value='$i'>$i</option>"; } $html.="</select> "; return $html; } ?> <?php include ('template/footer.inc'); ?> Hi anyone here know how to insert $GET variable into mysql, i don't know how to put this variable between curly bracket, when i put on top insert query, i got error 'Could not insert admin'...please help Code: [Select] <?php mysql_connect("localhost","root","") or die(mysql_error()); mysql_select_db("healthsystem") or die(msql_error()); [color=red]//GET varibable $id = $_GET['id'];[/color] // file properties $file = $_FILES['image']['tmp_name']; if (!isset($file)) echo "Please select an image"; else { $image = addslashes(file_get_contents($_FILES['image']['tmp_name'])); $image_name = addslashes($_FILES['image']['name']); $image_size = getimagesize($_FILES['image']['tmp_name']); if ($image_size==FALSE) echo "That's not an image."; else { $insert = "INSERT INTO image_tbl(m_id,name,image) VALUES ('$id','$image_name','$image')"; $insert2=mysql_query($insert) or die("Could not insert admin"); print "Personal Wellness Successfully Submitted"; } } ?> I have this link "https://localhost/what/index.php?album=parent%2Fsubalbum&image=1coffee.jpg" Am trying to insert a variable(eid=86) so that it comes before all other variables to read thus "https://localhost/what/index.php?eid=86&album=parent%2Fsubalbum&image=1coffee.jpg" Regards Good evening,
I am working on a program that takes images, and casts them into an associated array, I then want to display thumbnails of those images into a 3 column by 4 row table...
[image][image][image]
[image][image][image]
[image][image][image]
[image][image][image]
(For my visual friends)
here is my current, pardon for the mess, but right now, functionality is more important.
<!DOCTYPE html> <html> <head> <title>Zodiac Gallery</title> </head> <body> <h2 style="text-align:center">Zodiac Gallery</h2> <p>Click a thumbnail image to see enlarged view.</p> <?php $ZodiacArray = array ( "Images/rat.jpg" => "Rat", "Images/ox.jpg" => "Ox", "Images/tiger.jpg" => "Tiger", "Images/rabbit.jpg" => "Rabbit", "Images/dragon.jpg" => "Dragon", "Images/snake.jpg" => "Snake", "Images/horse.jpg" => "Horse", "Images/goat.jpg" => "Goat", "Images/monkey.jpg" => "Monkey", "Images/rooster.jpg" => "Rooster", "Images/dog.jpg" => "Dog", "Images/pig.jpg" => "Pig"); foreach ($ZodiacArray as $image => $zodiac) { echo "<table> <tr> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> </tr> <tr> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> </tr> <tr> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> </tr> <tr> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> <td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td> </tr> </table>"; ?>Help is welcome, thank you. Hello Guys, I want to insert an array variable into the database e.g Code: [Select] foreach($html->find('div[class=PostContent]') as $element) { echo $element; $sq = "INSERT INTO articles(original_text) VALUES ('$element') WHERE article_link='$item_url'"; $result = mysql_query($sql1) or die('Query failed: ' . mysql_error()); } i want to insert the variable $element into the database but i'm not able to do so for some reason! $element contains only a paragraph of text. how can i insert the variable $element? Code: [Select] <?php "INSERT INTO costumers (firstname,lastname,birthdate,product_name,price,details,category,subcategory,city,state,zipcode,country) VALUES('$fname','$lname','$birthday','$itemname','$price','$details','$category','$subcategory','$city','$state','$zipcode','$country')"; ?> What am I missing in the INSERT query above that is not inserting the values of birthday.? I am making a website where writers can share stories. One of the fields is other stories. So I used this code to make it a array with the links in each f the items. $other_split = explode(',', $other_form); $other_int = count($other_split); $x = 0; while ($x>$other_int) { $other_link[$x] = "<a href = '$other_split[$x]'> Chapter $x </a>"; } How can I insert the data in that array into one non array variable. hi ..
hit little snag Ive got html <form name="formx" method="POST" action="connect.php" class='ajaxform'> and about 4 varibles in that form .. now how to properly
query table users so i can find out which prefix correspond with that user
Insert into table "upis" in this case that prefix with 3 variables..
everything in single,.. in this case connect.php file
I know how to do QUERY and INSERT INTO but i don't know how to connect with 2 different tbl or db and do the query and input of data.. every time I put 2 of them together .. never works out..
this is example.. i dont know is this right way to do it .. This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=346503.0 First page adds a new job number, then the order page loaded with the job number id as a get id. Basically there is a while loop in the order page which shows products/services client can order and he chooses what he requires 'one or eight services' (8 in total) and some other variables like date of order and client name etc. Here is the order item code The first sql statement executes fine, but in the second sql query nothing happens $sql="insert into job_order(order_num,order_date,order_customer_id, order_remarks) values(".$_GET['id'].",NOW(),".$_POST['companyBox'].",'".$_POST['remarkBox']."');"; $res=mysql_query($sql); $id=mysql_insert_id(); foreach($_POST as $key => $value) { if(!empty($value)) { $key.' => '.trim(strip_tags($value)); $order="INSERT INTO orderprod (order_num,prod_id,order_amount,teeth_amount) VALUES ('$_GET[id]','$value','$value','$value');"; $orderres=mysql_query($order) or die(mysql_error()); } }?>$sql="insert into job_order(order_num,order_date,order_customer_id, order_remarks) values(".$_GET['id'].",NOW(),".$_POST['companyBox'].",'".$_POST['remarkBox']."');"; $res=mysql_query($sql); $id=mysql_insert_id(); foreach($_POST as $key => $value) { if(!empty($value)) { $key.' => '.trim(strip_tags($value)); $order="INSERT INTO orderprod (order_num,prod_id,order_amount,teeth_amount) VALUES ('$_GET[id]','$value','$value','$value');"; $orderres=mysql_query($order) or die(mysql_error()); } } ?> ============= This is the formI have removed parts which are irrelevant. Please note that dateBox and companyBox are not required to be looping as they are only for first table, echo "<form action=".$config_basedir."./vieworder.php?id=".$_GET['id']." name=form1 method=post>";?><table><tr><td><h4>JOB ORDER</H4></TD><TD></TD></TR><TR><TD>ORDER NUMBER</TD><TD><?PHP ECHO $_GET['id'] ?></td></tr><tr><td>ORDER DATE</td><td><input type=text name=dateBox></td></tr> <tr><td>COMPANY NAME</td><td><?PHP$sql="select * from customers";$res=mysql_query($sql);echo "<select name=companyBox><option value=''>Please select</option>";WHILE($fetch=mysql_fetch_assoc($res)){ echo "<option value='".$fetch['id']."'>".$fetch['cust_name']."</option>";} echo "</select>"; echo "</td></tr>"; ?> </table> <table><tr><th>ITEM</th><th>QUANTITY</th><th>N0. of Teeths</th></tr><tr><?PHP$sql="select * from products";$res=mysql_query($sql); WHILE($fetch=mysql_fetch_assoc($res)){ echo "<td><input type=text name=desBox value='".$fetch['prod_id']."'>".$fetch['prod_name']."</td><td><input type=text name=quantBox></td><td><input type=text name=teethBox></td>";echo "</tr>";}echo "</table>";?>echo "<form action=".$config_basedir."./vieworder.php?id=".$_GET['id']." name=form1 method=post>"; ?> <table> <tr> <td><h4>JOB ORDER</H4></TD><TD></TD> </TR> <TR> <TD>ORDER NUMBER</TD><TD><?PHP ECHO $_GET['id'] ?></td> </tr> <tr> <td>ORDER DATE</td><td><input type=text name=dateBox></td> </tr> <tr> <td>COMPANY NAME</td><td> <?PHP $sql="select * from customers"; $res=mysql_query($sql); echo "<select name=companyBox><option value=''>Please select</option>"; WHILE($fetch=mysql_fetch_assoc($res)){ echo "<option value='".$fetch['id']."'>".$fetch['cust_name']."</option>";} echo "</select>"; echo "</td></tr>"; ?> </table> <table> <tr> <th>ITEM</th><th>QUANTITY</th><th>N0. of Teeths</th> </tr> <tr> <?PHP $sql="select * from products"; $res=mysql_query($sql); WHILE($fetch=mysql_fetch_assoc($res)){ echo "<td><input type=text name=desBox value='".$fetch['prod_id']."'>".$fetch['prod_name']."</td> <td><input type=text name=quantBox></td> <td><input type=text name=teethBox></td>"; echo "</tr>";} echo "</table>"; ?> HERE IS THE IMAGE showing the populated services. http://dubads.com/images/order.jpg Dear Friends, I am alot before doing the mixed content of php and HTML in single variable in PHP.. I could not get the data even though there is not SYNTAX error.. please look my code and advise
$htmlcontent .=" <tr> <td colspan=\"8\">".$details."></td> </tr>"; for($k=0;$k<count($reg_years[$details]);$k++) { $year = (int)($reg_years[$details][$k]); $singlecount[$year] = array_filter($result[$details],function($details1) use ($year){ return ($details1['reg_year'] == $year && $details1['bench_type'] == 1); }); $divisioncount[$year] = array_filter($result[$details],function($details2) use ($year){ return ($details2['reg_year'] == $year && $details2['bench_type'] == 2); }); $fullcount[$year] = array_filter($result[$details],function($details3) use ($year){ return ($details3['reg_year'] == $year && $details3['bench_type'] >= 3); }); $rpcount[$year] = array_filter($result[$details],function($rp) use ($year){ return ($rp['reg_year'] == $year && $rp['bench_type'] == 'RP'); }); $mjccount[$year] = array_filter($result[$details],function($mjc) use ($year){ return ($mjc['reg_year'] == $year && $mjc['bench_type'] == 'MJC'); }); $cocount[$year] = array_filter($result[$details],function($co) use ($year){ return ($co['reg_year'] == $year && $co['bench_type'] == 'X'); }); $total = 0; $total = (int)(count($singlecount[$year])+count($divisioncount[$year])+count($fullcount[$year])+count($rpcount[$year])+count($mjccount[$year])+count($cocount[$year])); $htmlcontent .=" <tr> <td>".$year."</td> <td align=\"center\"> if(count($singlecount[$year])>0) { echo (count($singlecount[$year])); } else { echo "-"; } </td> <td align=\"center\"> if(count($divisioncount[$year])>0) { ".count($divisioncount[$year])." } else { "-" } </td> <td align=\"center\"> if (count($fullcount[$year]) > 0) { echo (count($fullcount[$year])); } else { echo "-"; } </td > < td align =\"center\"> if(count($rpcount[$year])>0) { echo (count($rpcount[$year])); } else { echo " - "; } </td> <td align=\"center\"> if(count($mjccount[$year])>0) { echo (count($mjccount[$year])); } else { echo " - "; } </td> <td align=\"center\"> if(count($cocount[$year])>0) { echo (count($cocount[$year])); } else { echo " - "; } </td> <td align=\"center\"> echo $total; </td> </tr>"; } } $htmlcontent .= "</tbody></table>"; $mpdf = new \Mpdf\Mpdf(); $mpdf->WriteHTML($htmlcontent); $mpdf->Output(); Waiting for FAST reply
Thanks Anes I have a form that users input user name, password, and email... all writes to csv fine. My problem is I need to concatenate a a string with a variable and some html code will preserving the html when written to the csv.. I need the csv to be this username,password,email,user,category,text with http://sub.domain..com/splash/,something,something here's what i have Code: [Select] <?php if($_POST['formSubmit'] == "Submit") $varUserName = $_POST['username']; $varPW = $_POST['PW']; $varEmail = $_POST['email']; { $fs = fopen("testcsv.csv","a"); fputcsv($fs, array($varUserName,$varPW,$varEmail,"user","title",",category","some text '<a href="http://$varUserName.url.com/splash/>site.com</a>',)); fclose($fs); exit; } ?> and of course I'm getting Parse error: syntax error, unexpected T_STRING, expecting ')' on line 9 I need a help in the following : I have an admin page from where the admin attaches an gif image.This attached image should be shown to the user as a scrolling image. The code for the scrolling image is done through javascript. So my actual problem is getting the name of the attached gif image to the javascript array which is used for scrolling horizontally. Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; I'm missing something here. I have a form, and when the submit is pressed, the relevant post data inserts into table one, then I want the last insert id to insert along with other form data into a second table. The first table's still inserting fine, but I can't get that second one to do anything. It leapfrogs over the query and doesn't give an error. EDIT: I forgot to add an error: I get: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'usage, why VALUES ('14', '', '123', '','1234', '', '')' at line 1 query:INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('test 14', 'asdfa', 'asdf', 'adf','asdf', '', '', '', '123', '', '') Code: [Select] if (empty($errors)) { require_once ('dbconnectionfile.php'); $query = "INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('$description12', '$sn', '$description4', '$cne','$description5', '$description6', '$description7', '$description8', '$description9', '$description10', '$description11')"; $result = @mysql_query ($query); if ($result) { $who_donated=mysql_insert_id(); $query2 = "INSERT INTO tbl_donation (donor_id, donor_expyear, donor_cvv, donor_cardtype, donor_authorization, amount, usage, why) VALUES ('$who_donated', '$donate2', '$donate3', '$donate4','$donate5', '$donate6', '$donate7')"; $result2 = @mysql_query ($query2); if ($result2) {echo "Info was added to both tables! yay!";} echo "table one filled. Table two was not."; echo $who_donated; //header ("Location: http://www.twigzy.com/add_plant.php?var1=$plant_id"); exit(); } else { echo 'system error. No donation added'; Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! |