PHP - Upload Issue When Image Exceeds Php Ini Limit

Hi,

I wanted to realize an upload form for a max. file size of 5GB. Don't ask me why, but my friend needs that.
Now I set up a webserver with ISPConfig and this interface provides a lot of features including openbasedir.
Uploading files up to 80MB is no problem but choosing bigger files causes the following errors:

[Mon Sep 12 23:39:03 2011] [warn] [client XX.XX.XXX.XXX] mod_fcgid: stderr: PHP Fatal error:  Allowed memory size of 134217728 bytes exhausted (tried to allocate 97477678 bytes) in Unknown on line 0, referer: hxxp://www.mydomain.com/kontakt-upload.html
[Mon Sep 12 23:39:03 2011] [error] [client XX.XX.XXX.XXX] Premature end of script headers: file-uploader.php, referer: hxxp://www.mydomain.com/kontakt-upload.html
[Mon Sep 12 23:39:03 2011] [warn] [client XX.XX.XXX.XXX] (104)Connection reset by peer: mod_fcgid: error reading data from FastCGI server, referer: hxxp://www.mydomain.com/kontakt-upload.html
[Mon Sep 12 23:39:03 2011] [error] [client XX.XX.XXX.XXX] Premature end of script headers: index.php, referer: hxxp://www.mydomain.com/kontakt-upload.html

As I see the upload get's buffered in the PHP Memory area instead directly to the harddrive.
How could I fix that?

Hello!

I want to make the users in the website able only to upload, for example, 1 GB, so that when a user finishes the 1 GB available for his files, he cannot upload more files.

I know how to set up upload limit for a single file in the upload page, or even globally for anyone to upload. But I would like to know how to make each user has specific capacity, and how it is updated so that if he uploads 0.5 GB he has only 0.5 GB left.

I thought of creating a column in the `users` or something concerning upload limit that I will set it (one GB for example). If I will do that, how will I be able to determine how much he uploaded?

Any help would be appreciated.

Thank you!

I'm trying to add a file size limit to my upload form-code (below)

Unless buffer overflows or breaking out of code to perform a new command are problems that have been solved....

I am trying to figure out the proper PHP method for setting a boundary on a variable within a script. I have this variable $name which is fed a value from $_POST['name'] from a form field. Now this form field is limited in the HTML to accept only 20 characters, but someone could easily edit the form or outgoing post data. So I want to know how to limit the variable size in the script. In other languages it could be something like this: var name(20). So how do I do that in PHP?

How can i edit just one image at on time with a multiple image upload form? I have the images being stored in a folder and the path being stored in MySQL. I also have the files being uploaded with a unique id. My issue is that I want to be able to pass the values of what is already in $name2 $name3 $name4 if I only want to edit $name1. I don't want to have to manually update the 4 images. Here is the PHP:
Code: [Select]
<?php

require_once('storescripts/connect.php');
mysql_select_db($database_phpimage,$phpimage);
$uploadDir = 'upload/';
if(isset($_POST['upload']))
{


foreach ($_FILES as $file)
{

    $fileName = $file['name'];
    $tmpName = $file['tmp_name'];
    $fileSize = $file['size'];
    $fileType = $file['type'];

    if ($fileName != ""){
        $filePath = $uploadDir;
        $fileName = str_replace(" ", "_", $fileName);

        //Split the name into the base name and extension
        $pathInfo = pathinfo($fileName);
        $fileName_base = $pathInfo['fileName'];
        $fileName_ext = $pathInfo['extension'];

        //now we re-assemble the file name, sticking the output of uniqid into it
        //and keep doing this in a loop until we generate a name that 
        //does not already exist (most likely we will get that first try)
        do {
           $fileName = $fileName_base . uniqid() . '.' . $fileName_ext;
        } while (file_exists($filePath.$fileName));

$file_names [] = $fileName;

        $result = move_uploaded_file($tmpName, $filePath.$fileName);
    }


if(!get_magic_quotes_gpc())
{
$fileName = addslashes($fileName);
$filePath = addslashes($filePath);
}
$fileinsert[] = $filePath;
}
}

$mid   = mysql_real_escape_string(trim($_POST['mid']));
$cat   = mysql_real_escape_string(trim($_POST['cat']));
$item  = mysql_real_escape_string(trim($_POST['item']));
$price = mysql_real_escape_string(trim($_POST['price']));
$about = mysql_real_escape_string(trim($_POST['about']));

$fields = array();
$values = array();
$updateVals = array();
for($i = 0; $i < 4; $i++)
{
    $values[$i] = isset($file_names[$i]) ? mysql_real_escape_string($file_names[$i]) : '';

    if($values[$i] != '') {
        $updateVals[] = 'name' . ($i + 1) . " = '{$values[$i]}'"; 
    }
}
$updateNames = '';
if(count($updateVals))
{
    $updateNames = ", " . implode(', ', $updateVals);
}

$update = "INSERT INTO image
               (mid, cid, item, price, about, name1, name2, name3, name4)
           VALUES
               ('$mid', '$cat', '$item', '$price', '$about', '$values[0]', '$values[1]', '$values[2]', '$values[3]')
           ON DUPLICATE KEY UPDATE
                cid = '$cat', item = '$item', price = '$price', about = '$about' $updateNames";
$result = mysql_query($update) or die (mysql_error());

I am trying to run the following code to upload a file. (WAMP using Win XP). Once I select the file and click submit I get the error: "Forbidden... You don't have permission to access /< on this server." with URL http://localhost/<?=$PHP_SELF?>
Code is below:

<form action="<?=$PHP_SELF?>" method="post" enctype="multipart/form-data">
<br/><br/>
Choose a file to upload:<br/>
<input type="file" name="upload_file">
<br/>
<input type="submit" name="submit" value="submit">
</form>


TIA

Hello
I am facing a rare issue while uploading videos, now the test is on .flv 7 mega and .wmv 5 mega

Not Only the file is not getting uploaded, I cannot even see the tmp_name and ize is 0

I have included:

ini_set("post_max_size", "10M");
ini_set("upload_max_filesize", "10M");

and
<input type="hidden" name="MAX_FILE_SIZE" value="100000" />

This is all locally on the localhost, nothing allows for uploading the video

Many Thanks

Ok, I have this code that is supposed to upload a csv file and save the contents into a specific sql table.  I am getting an error when i hit submit that states the file is empty, meaning the csv file.  I am thinking that the file isn't really being targeted i just don't know how to fix it.  To start i have a php page with a the form and then i have another php page that is included in the form php page.  The functions for submitting the csv info in the text file is located in the include file.  here is the code:

Code: [Select]
$csv = new Quick_CSV_import();

$arr_encodings = $csv->get_encodings(); //take possible encodings list
$arr_encodings["default"] = "[default database encoding]"; //set a default (when the default database encoding should be used)

if(!isset($_POST["encoding"]))
  $_POST["encoding"] = "default"; //set default encoding for the first page show (no POST vars)

if(isset($_POST["Go"]) && ""!=$_POST["Go"]) //form was submitted
{
  $csv->file_name = $HTTP_POST_FILES['file_source']['tmp_name'];
 
  //optional parameters
  $csv->use_csv_header = isset($_POST["use_csv_header"]);
  $csv->field_separate_char = $_POST["field_separate_char"][0];
  $csv->field_enclose_char = $_POST["field_enclose_char"][0];
  $csv->field_escape_char = $_POST["field_escape_char"][0];
  $csv->encoding = $_POST["encoding"];
 
  //start import now
  $csv->import();
}
else
  $_POST["use_csv_header"] = 1;
?>

<tr>
      <td>Source CSV file to import:</td>
      <td rowspan="30" width="10px">&nbsp;</td>
      <td><input type="file" name="file_source" id="file_source" class="edt" value="<?=$file_source?>"></td>
      </tr>
and

Code: [Select]
class Quick_CSV_import
{
  var $table_name = "tbl_product"; //where to import to
  var $file_name; //where to import from
  var $use_csv_header; //use first line of file OR generated columns names
  var $field_separate_char; //character to separate fields
  var $field_enclose_char; //character to enclose fields, which contain separator char into content
  var $field_escape_char;  //char to escape special symbols
  var $error; //error message
  var $arr_csv_columns; //array of columns
  var $table_exists; //flag: does table for import exist
  var $encoding; //encoding table, used to parse the incoming file. Added in 1.5 version
 
  function Quick_CSV_import()
  {
    $this->file_name = $file_name;
    $this->arr_csv_columns = array();
    $this->use_csv_header = true;
    $this->field_separate_char = ",";
    $this->field_enclose_char  = "\"";
    $this->field_escape_char   = "\\";
    $this->table_exists = false;
  }
 
  function import()
  {
    if($this->table_name=="")
      $this->table_name = "temp_".date("d_m_Y_H_i_s");
   
    $this->table_exists = false;
    $this->create_import_table();
   
    if(empty($this->arr_csv_columns))
      $this->get_csv_header_fields();
   
    /* change start. Added in 1.5 version */
    if("" != $this->encoding && "default" != $this->encoding)
      $this->set_encoding();
    /* change end */
   
    if($this->table_exists)
    {
      $sql = "LOAD DATA INFILE '".@mysql_escape_string($this->file_source).
             "' INTO TABLE `".$this-> table_name.
             "` FIELDS TERMINATED BY '".@mysql_escape_string($this->field_separate_char).
             "' OPTIONALLY ENCLOSED BY '".@mysql_escape_string($this->field_enclose_char).
             "' ESCAPED BY '".@mysql_escape_string($this->field_escape_char).
             "' ".
             ($this->use_csv_header ? " IGNORE 1 LINES " : "")
             ."(`".implode("`,`", $this->arr_csv_columns)."`)";
      $res = @mysql_query($sql);
      $this->error = mysql_error();
    }
  }
 
  //returns array of CSV file columns
  function get_csv_header_fields()
  {
    $this->arr_csv_columns = array();
    $fpointer = fopen($file_name, "r");
    if ($fpointer)
    {
      $arr = fgetcsv($fpointer, 10*1024, $this->field_separate_char);
      if(is_array($arr) && !empty($arr))
      {
        if($this->use_csv_header)
        {
          foreach($arr as $val)
            if(trim($val)!="")
              $this->arr_csv_columns[] = $val;
        }
        else
        {
          $i = 1;
          foreach($arr as $val)
            if(trim($val)!="")
              $this->arr_csv_columns[] = "column".$i++;
        }
      }
      unset($arr);
      fclose($fpointer);
    }
    else
      $this->error = "file cannot be opened: ".(""==$this->file_name ? "[empty]" : @mysql_escape_string($this->file_name));
    return $this->arr_csv_columns;
  }
i just can't figure it out.  could anyone help me out?  the error i get says this:  Warning: fopen() [function.fopen]: Filename cannot be empty in /Quick_CSV_import.php on line 83

Hi   I am developing a website for fun to play around with, like a little fun project and am trying to work out how to upload multiple images that stores the filename in the database and the actual file on the server   I have managed to get it working if I upload just one image but can't work it out for multiple images   Can anyone point me in the right direction or advise where I need to adjust for multiple images upload   I know on the html form on the input tag needs to have multiple and then the name in the input tag be image[] but is as far as I get, it's the PHP I get stuck on   The html for the form is below

<form action="private-add-insert.php" method="post" enctype="multipart/form-data">
Car Make: <input type="text" name="make">
Car Model: <input type="text" name="model">
Exterior Colour: <input type="text" name="exteriorcolour">
Engine Size: <input type="text" name="enginesize">
Fuel Type: <input type="text" name="fueltype">
Year Registered: <input type="text" name="yearregistered">
Transmission: <input type="text" name="transmission">
Mileage: <input type="text" name="mileage">
Number of Doors: <input type="text" name="nodoors">
Body Style: <input type="text" name="bodystyle">
Price: <input type="text" name="price">
<br>
<label>Upload Images</label>
<input type="file" name="image[]" multiple/>
<br />
<input type="hidden" name="MAX_FILE_SIZE" value="100000" />
<br />
<input type="submit" value="Submit Listing"> 
</form>

Below is the PHP coding that processes the html form

<?php
ini_set('display_startup_errors',1);
ini_set('display_errors',1);
error_reporting(-1);
?>

<?php
// Start a session for error reporting
session_start();

// Call our connection file
require("includes/conn.php");

// Check to see if the type of file uploaded is a valid image type
function is_valid_type($file)
{
	// This is an array that holds all the valid image MIME types
	$valid_types = array("image/jpg", "image/jpeg", "image/bmp", "image/gif", "image/png");

	if (in_array($file['type'], $valid_types))
		return 1;
	return 0;
}

// Just a short function that prints out the contents of an array in a manner that's easy to read
// I used this function during debugging but it serves no purpose at run time for this example
function showContents($array)
{
	echo "<pre>";
	print_r($array);
	echo "</pre>";
}

// Set some constants

// This variable is the path to the image folder where all the images are going to be stored
// Note that there is a trailing forward slash
$TARGET_PATH = "private-listing-images/";

// Get our POSTed variables
$make = $_POST['make'];
$model = $_POST['model'];
$exteriorcolour = $_POST['exteriorcolour'];
$enginesize = $_POST['enginesize'];
$fueltype = $_POST['fueltype'];
$yearregistered = $_POST['yearregistered'];
$transmission = $_POST['transmission'];
$mileage = $_POST['mileage'];
$nodoors = $_POST['nodoors'];
$bodystyle = $_POST['bodystyle'];
$price = $_POST['price'];
$image = $_FILES['image'];

// Sanitize our inputs
$make = mysql_real_escape_string($make);
$model = mysql_real_escape_string($model);
$exteriorcolour = mysql_real_escape_string($exteriorcolour);
$enginesize = mysql_real_escape_string($enginesize);
$fueltype = mysql_real_escape_string($fueltype);
$yearregistered = mysql_real_escape_string($yearregistered);
$transmission = mysql_real_escape_string($transmission);
$mileage = mysql_real_escape_string($mileage);
$nodoors = mysql_real_escape_string($nodoors);
$bodystyle = mysql_real_escape_string($bodystyle);
$price = mysql_real_escape_string($price);
$image['name'] = mysql_real_escape_string($image['name']);

// Build our target path full string.  This is where the file will be moved do
// i.e.  images/picture.jpg
$TARGET_PATH .= $image['name'];

// Check to make sure that our file is actually an image
// You check the file type instead of the extension because the extension can easily be faked
if (!is_valid_type($image))
{
	$_SESSION['error'] = "You must upload a jpeg, gif, bmp or png";
	header("Location: private-add-listing.php");
	exit;
}

// Lets attempt to move the file from its temporary directory to its new home
if (move_uploaded_file($image['tmp_name'], $TARGET_PATH))
{
	
	// NOTE: This is where a lot of people make mistakes.
	// We are *not* putting the image into the database; we are putting a reference to the file's location on the server
	$sql = "insert into privatelistings (make, model, exteriorcolour, enginesize, fueltype, yearregistered, transmission, mileage, nodoors, bodystyle, price, filename) values ('$make', '$model', '$exteriorcolour', '$enginesize', '$fueltype', '$yearregistered', '$transmission', '$mileage', '$nodoors', '$bodystyle', '$price', '" . $image['name'] . "')";
	$result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error());
	header("Location: private-add-listing-successfully.php?msg=Listing Added successfully");
	exit;
}
else
{
	// A common cause of file moving failures is because of bad permissions on the directory attempting to be written to
	// Make sure you chmod the directory to be writeable
	$_SESSION['error'] = "Could not upload file.  Check read/write persmissions on the directory";
	header("Location: private-add-listing.php");
	exit;
}
?>

I know the coding needs updating to mysqli and prevent sql injections but want to get it working first and then will do them parts   Thank you in advance   Kind regards   Ian

Hello

I am having problems uploading an image through a HTML form. I want the image to be uploaded to the server and the image name to be written to the mysql database.

Below is the code I am using:
Code: [Select]
<?php
if (isset($_POST['add'])){
   
   echo "<br /> add value is true";
      $name = $_POST['name'];   
      $description = $_POST['description'];   
      $price = $_POST['price'];
      $category_id = $_POST['category_name'];
      $image = $_FILES['image']['name'];   
      
      //file path of the image upload
      $filepath = "../images/";
      //mew name for the image upload
      $newimagename = $name;
      //new width for the image
      $newwidth = 100;
      //new height for the image
      $newheight = 100;
      
      include('../includes/image-upload.php');
      
      
      mysql_query("INSERT INTO item (item_name, item_description, item_price, item_image)
      VALUES ('$name','$description','$price','$image')"); ?>

Here is the image-upload.php file code:

Code: [Select]
<?php

//assigns the file to the image
$image =$_FILES["image"]["name"];
$uploadedfile =$_FILES["image"]["tmp_name"];

if ($image) {
   //retrieves the extension type from image upload
   $extension = getextension($image);
   //converts extension to lowercase
   $extension = strtolower($extension);
   
   //create image from uploaded file type
   if($extension=="jpg" || $extension=="jpeg") {
      $uploadedfile = $_FILES['image']['tmp_name'];
      $src = imagecreatefromjpeg($uploadedfile);
   }else if($extension=="png") {
      $uploadedfile = $_FILES['image']['tmp_name'];
      $src = imagecreatefrompng($uploadedfile);
   }else{
      $src = imagecreatefromgif($uploadedfile);
   }
   
   //creates a list of the width and height of the image
   list($width,$height)=getimagesize($uploadedfile);
   
   //adds color to the image
   $tmp = imagecreatetruecolor($newwidth,$newheight);
   
   //create image
   imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height);
   
   //set file name
   $filename = $filepath.$newimagename.".".$extension;
   $imagename = $newimagename.".".$extension;
   //uploads new file with name to the chosen directory
   imagejpeg($tmp,$filename,100);
   
   //empty variables
   imagedestroy($src);
   imagedestroy($tmp);
   
}


?>
Any help would be appreciated, fairly new to all this!

Thanks!!!

I have a working image upload script that uploads, renames the file and adds filename to the database.

is it possible to include some sort of image resize code? if so can anyone point me in the right direction or better still show some example code and explain how it works etc.

below is my working code:

Code: [Select]
<?php
$rand = mt_rand(1,9999999);
$member_id = $_SESSION['SESS_MEMBER_ID'];
$caption = $_POST["caption"];

if(isset($_FILES['uploaded']['name']))
{
$allowed_filetypes = array('.jpg','.gif','.bmp','.png','.jpeg');
$max_filesize = 524288; // Maximum filesize in BYTES (currently 0.5MB) 
    $fileName = basename($_FILES['uploaded']['name']);
$errors = array();
$target = "gallery/";
$fileBaseName = substr($fileName, 0, strripos($fileName, '.'));

   // Get the extension from the filename.
   $ext = substr($fileName, strpos($fileName,'.'), strlen($fileName)-1); 
 
   //$newFileName = md5($fileBaseName) . $ext;
   $newFileName = $target . $rand . "_" . $member_id.$ext;
   
   // Check if filename already exists
   if(file_exists("gallery/" . $newFileName)) 
    {
     $errors[] = "The file you attempted to upload already exists, please try again.";
    }
   // Check if the filetype is allowed.
   if(!in_array($ext,$allowed_filetypes))
    {
         $errors[] = "The file you attempted to upload is not allowed.";
    }
    
// Now check the filesize.
   if(!filesize($_FILES['uploaded']['tmp_name']) > $max_filesize)
    {
         $errors[] = "The file you attempted to upload is too large.";
    }
  
    // Check if we can upload to the specified path.
   if(!is_writable($target))
    {
         $errors[] = "You cannot upload to the specified directory, please CHMOD it to 777.";
    }
 
    //Here we check that no validation errors have occured.
    if(count($errors)==0)
    {

//Try to upload it.
        if(!move_uploaded_file($_FILES['uploaded']['tmp_name'], $newFileName))
        {
            $errors[] = "Sorry, there was a problem uploading your file.";
        }
    }
    //Lets INSERT database information here
    if(count($errors)==0)
    {
$result = mysql_query("INSERT INTO `gallery` (`image`, `memberid`, `caption`) VALUES ('$newFileName', '$member_id', '$caption')")
    or die (mysql_error()); 

}
    //If no errors show confirmation message
    if(count($errors)==0)
    {
         echo "<div class='notification success png_bg'>
<a href='#' class='close'><img src='img/cross_grey_small.png' title='Close this notification' alt='close' /></a>
<div>
Image has been uploaded.<br>\n
</div>
</div>";


//echo "The file {$fileName} has been uploaded";
echo "<br>\n";
echo "<a href='gallery.php'>Go Back</a>\n";

   }
    else
    {
        //show error message
        echo "<div class='notification attention png_bg'>
<a href='#' class='close'><img src='img/cross_grey_small.png' title='Close this notification' alt='close' /></a>
<div>
Sorry your file was not uploaded due to the following errors:<br>\n
</div>
</div>";
//echo "Sorry your file was not uploaded due to the following errors:<br>\n";
        echo "<ul>\n";
        foreach($errors as $error)
        {
            echo "<li>{$error}</li>\n";
        }
        echo "</ul>\n";
echo "<br>\n";
echo "<a href='gallery.php'>Go Back</a>\n";
    }
    
}
else
{
    //Show the form
echo "Use the following form below to add a new image to your gallery;<br /><br />\n";
    echo "<form enctype='multipart/form-data' action='' method='POST'>\n";
    echo "Please choose a file:<br /><input class='text' name='uploaded' type='file' /><br />\n";
echo "Image Caption:<br /><input class='text' name='caption' type='text' value='' /><br /><br />\n";
    echo "<input class='Button' type='submit' value='Upload' />\n";
    echo "</form>\n";

}
?>
Many thanks to phpfreaks again.

hello friends,

while clicking the form all the information goes to database, I have one image upload field,
when cliking the submit button, i would like 'image name' to go in database and file to go in
/upload folder, i have tried this for hours and gave up,

if anyone help me in this, i would be very greatful

I need code for upload images for php as well as to edit that image

Hi,

Im rather new to php and really unable to get the above to work. Everything works apart from the image being resized. File is uploaded, and the image name is printed into the SQL database. But i cant for the life of me get the image to go to 300x200? If you could help me i would be very grateful

My code for the form processing page is attached. Ive put a few line breaks into the code as to where i think is the issue. I just cant seem to resize the image. Does the image resize need to come before the part it writes the image to the server or can this be done afterwards? Please help.

P.S - Thanks in advance

Hi everybody, I have similar problem like member vikaspa in this thread:

http://www.phpfreaks.com/forums/index.php?topic=279531.msg1323820#msg1323820

Have great site, but this image rewriting makes me crazy...today someone upload  in some thread 1.jpg for example...after 3 days someone uploads diferent image and also called it 1.jpg, and overwrites this earlier one. Nonsense.

Please help me with my code, what to add where, to prevent rewriting and instead that, to rename upload internally (without notifying the user)...for example 1_1.jpg.

Here is my code:

Code: [Select]
if ($fdata['forum_attach'] && checkgroup($fdata['forum_attach'])) {
$attach = $_FILES['attach'];
if ($attach['name'] != "" && !empty($attach['name']) && is_uploaded_file($attach['tmp_name'])) {
$attachname = stripfilename(substr($attach['name'], 0, strrpos($attach['name'], ".")));
$attachext = strtolower(strrchr($attach['name'],"."));
if (preg_match("/^[-0-9A-Z_\[\]]+$/i", $attachname) && $attach['size'] <= $settings['attachmax']) {
$attachtypes = explode(",", $settings['attachtypes']);
if (in_array($attachext, $attachtypes)) {
$attachname .= $attachext;
move_uploaded_file($attach['tmp_name'], FORUM."attachments/".$attachname);
chmod(FORUM."attachments/".$attachname,0644);
if (in_array($attachext, $imagetypes) && (!@getimagesize(FORUM."attachments/".$attachname) || !@verify_image(FORUM."attachments/".$attachname))) {
unlink(FORUM."attachments/".$attachname);
$error = 1;
}
if (!$error) { $result = dbquery("INSERT INTO ".DB_FORUM_ATTACHMENTS." (thread_id, post_id, attach_name, attach_ext, attach_size) VALUES ('".$thread_id."', '".$post_id."', '$attachname', '$attachext', '".$attach['size']."')"); }
} else {
@unlink($attach['tmp_name']);
$error = 1;
}
} else {
@unlink($attach['tmp_name']);
$error = 2;
} 


Member Little guy wrote:

$tmp_name = $_FILES["pictures"]["tmp_name"];
$tmp_new_name = $_FILES["pictures"]["name"];
$path_parts = pathinfo($tmp_new_name);
$new_name = $path_parts['filename'] . time() . $path_parts['extension'];
$uploads_dir = '/uploads';
move_uploaded_file($tmp_name, "$uploads_dir/$new_name");

But I'm completely noob for coding and don't know where to put that in my forum code. Please help.

Thanx in advance, sorry for longer thread, and for my english. Regards.