PHP - Converting To Php - Copy Text To Your Clipboard
I found this "https://github.com/mojombo/clippy" Clippy into our site which uses php.
The example is written in Rails (Ruby). https://github.com/mojombo/clippy#readme Can anyone help me convert that into php? Here is my attempt but not getting any results. <? if ( ! function_exists('clipit')) { function clipit($var = 'Copy me please') { $clippy_url = '/resources/flash/clippy.swf'; $clippy = <<< EOD <object classid="clsid:d27cdb6e-ae6d-11cf-96b8-444553540000" width="110" height="14" id="clippy" > <param name="movie" value="$clippy_url"/> <param name="allowScriptAccess" value="always" /> <param name="quality" value="high" /> <param name="scale" value="noscale" /> <param NAME="FlashVars" value="text=$var"> <param name="bgcolor" value="#FFFFFF"> <embed src="$clippy_url" width="110" height="14" name="clippy" quality="high" allowScriptAccess="always" type="application/x-shockwave-flash" pluginspage="http://www.macromedia.com/go/getflashplayer" FlashVars="text=$var" bgcolor="#FFFFFF" /> </object> EOD; return $clippy; } } ?> Thanks Similar TutorialsHi my dear expert friends here, Can help me with this problem as stated above? Problem details: I need to copy a table from HTML and paste it to Lotus Approach. But when i copy a fraction(1 1/8) from HTML and paste it , it become 1.125. Below picture show the output when i copy and pasted to excel file, it look like window will auto change a fraction become a floating value when copy from a HTML: 22.jpg 29KB 0 downloads this is what i want it to copy and paste it as a text file. 11.jpg 19.98KB 0 downloads Any kind experts can please help me? Thank you~ Hi, I'm working on zend frame and im beginner. I have to copy text from textarea through javascript and when i press ctrl + v it should paste. And im working in linux machine. Looking for help. Please respond as soon as possible. Thanks in advance Shastry Hi guys, I am wirting a script to upload an image file, but I get the error: copy() [function.copy]: Filename cannot be empty in Obviouly it has something to do with the copy() function - (copy($HTTP_POST_FILES['product_img']['tmp_name'], $path)) I think it is not copying from my temp folder or something. Can anyone help me out? Code is: Code: [Select] //IMAGE FILE $file_name = $_FILES['product_img']['name']; echo '<p>File Name:' . $file_name . '</p>'; //IMAGE UPLOAD // random 4 digit to add to file name $random_digit=rand(0000,9999); //combine random digit to file name to create new file name //use dot (.) to combile these two variables $new_image_name = $random_digit.$file_name; echo $new_image_name; //SET DESINATION FOLDER $path= "uploads/".$new_image_name; echo '<p>Path:' . $path . '</p>'; if($product_img !=none) { if(copy($HTTP_POST_FILES['product_img']['tmp_name'], $path)) { echo "Successful<BR/>"; echo "File Name :".$new_file_name."<BR/>"; echo "File Size :".$HTTP_POST_FILES['product_img']['size']."<BR/>"; echo "File Type :".$HTTP_POST_FILES['product_img']['type']."<BR/>"; } else { echo "Image upload Error<BR/>"; } } Any help would be greatly appreciated! Thanks Ok I am designing a php upload that will take a image file from a form and change the name of the file to the productnumber also recieved from the form. I had it working the otherday now it says Warning: copy() [function.copy]: open_basedir restriction in effect File() is not within the allowed path(s): (/home:/tmp:/usr) addpro.php on line 51. my files are attached.... note that $pnum is the product number gotten from my form and image is the image being uploaded gotten from the form also. The thing is it worked the other day but now it don't is it a change to the server ( I dont run the server) or did I mess up my code since then? I really need a code that will do this two time over once for a small image being put into a folder called small and once for a folder called large both images being uploaded and being changed to $pnum.ext so they will both be displayed when being called out by the product number. but I can work on that after I get this one working. line 51 is $copied = copy($_FILES['image']['tmp_name'], $newname); I came across the PHP clone method. Does this clone first level fields and methods or does it also do deep copying e.g. copying references to those fields. For example, a field may be an array. Does it make a copy of the actual array or does it refer to the same array position in memory, so if the original changes, then the copy's changes as well?
This was generated through phpFormGenerator, but I'm getting the following warning message when a file is not uploaded. I didn't set it as a required field. "Warning: copy() [function.copy]: Filename cannot be empty ..." If it possible to skip this check since it's not supposed to be required to upload a file? I'm simply trying to make a contact form that emails basic information with the added option of attaching a file/picture. Code: [Select] <?php include("global.inc.php"); $errors=0; $error="The following errors occured while processing your form input.<ul>"; pt_register('POST','FullName'); pt_register('POST','Email'); pt_register('POST','Phone'); pt_register('POST','QuestionsorComments'); $QuestionsorComments=preg_replace("/(\015\012)|(\015)|(\012)/"," <br />", $QuestionsorComments);$AttachPictureforQuote=$HTTP_POST_FILES['AttachPictureforQuote']; pt_register('POST','Howdidyoufindus'); if($FullName=="" || $Email=="" ){ $errors=1; $error.="<li>You did not enter one or more of the required fields. Please go back and try again."; } if($HTTP_POST_FILES['AttachPictureforQuote']['tmp_name']==""){ } else if(!is_uploaded_file($HTTP_POST_FILES['AttachPictureforQuote']['tmp_name'])){ $error.="<li>The file, ".$HTTP_POST_FILES['AttachPictureforQuote']['name'].", was not uploaded!"; $errors=1; } if(!eregi("^[a-z0-9]+([_\\.-][a-z0-9]+)*" ."@"."([a-z0-9]+([\.-][a-z0-9]+)*)+"."\\.[a-z]{2,}"."$",$Email)){ $error.="<li>Invalid email address entered"; $errors=1; } if($errors==1) echo $error; else{ $image_part = date("h_i_s")."_".$HTTP_POST_FILES['AttachPictureforQuote']['name']; $image_list[4] = $image_part; copy($HTTP_POST_FILES['AttachPictureforQuote']['tmp_name'], "files/".$image_part); $where_form_is="http".($HTTP_SERVER_VARS["HTTPS"]=="on"?"s":"")."://".$SERVER_NAME.strrev(strstr(strrev($PHP_SELF),"/")); $message="Full Name: ".$FullName." Email: ".$Email." Phone: ".$Phone." Questions or Comments: ".$QuestionsorComments." Attach Picture for Quote: ".$where_form_is."files/".$image_list[4]." How did you find us: ".$Howdidyoufindus." "; $message = stripslashes($message); mail("webmaster@gmail.com","Form Submitted at your website",$message,"From: phpFormGenerator"); ?> <!-- This is the content of the Thank you page, be careful while changing it --> <h2>Thank you!</h2> <table width=50%> <tr><td>Full Name: </td><td> <?php echo $FullName; ?> </td></tr> <tr><td>Email: </td><td> <?php echo $Email; ?> </td></tr> <tr><td>Phone: </td><td> <?php echo $Phone; ?> </td></tr> <tr><td>Questions or Comments: </td><td> <?php echo $QuestionsorComments; ?> </td></tr> <tr><td>Attach Picture for Quote: </td><td> <?php echo $AttachPictureforQuote; ?> </td></tr> <tr><td>How did you find us: </td><td> <?php echo $Howdidyoufindus; ?> </td></tr> </table> <!-- Do not change anything below this line --> <?php } ?> Thanks for your time and any help you can provide! This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=350182.0 Hello, i am currently getting an Microsoft Excel formatted text file whose save type is .Txt from a URL.I used to open it and will change the save type as excel file. Please suggest whether we can do this with php code. currently my code is like this, <? php copy("http://www.faa.gov/airports/airport_safety/airportdata_5010/menu/emergencyplanexport.cfm?Region=&District=&State=&County=&City=LAS%20VEGAS&Use=&Certification=","./contactsexport.xls"); ?> where as the contactsexport.xls type is .Txt which i need it in .xls Thanks in Advance. Hello everyone, so I made this script that creates directories via "a hack around" cPanel, on my own server, in order to create directories via my own software, but I also need to copy files from one directory into that newly created directory... Therein lies the problem... I created a script a few years ago that worked, but for the life of me I can't remember how I enabled myself to be able to use the copy function of php... Anybody know? hey people i cant get copy() to work. im working on an online server and trying to copy a file into directories i just created. i read about fopen() having to be enabled if both source and destination files are urls, and fopen is enabled and both files are urls (and on the same server). the directories get created but the file doesnt get copied. the directories have permission 777. could it be that when i call the copy function the directories aren't yet available on the server? i am copying the file in the same code block as 'create folders', right after. any pointers? So my hosting server does not allow fopen anymore, so I was wondering if anyone had an alternative to copying a file from a remote server via a URL to a local folder? Any alternatives is apprecited. I have a DB with 10 fields Records are entered under a date There can be 1 to 30 records for a given date I need to copy all records of a given date with the 10 fields of each... Into the same DB only changing the original date to a new date Sounds easy, but so far I haven't been able to make it work. Any nudge in the right directiion would be much appreciated. hey, can some one provide a code to help me copy a folder called contents with files in it to another folder called items cheers Hello, im new to php and I would appreciate help with this one.... Error code is Warning: copy() expects parameter 1 to be string, array given in /path/to/file/http.class.php on line 143 Error block Code: [Select] if (count($_FILES) > 0) { foreach ($_FILES as $name => $file) { if ($file['tmp_name']) { $newfile=dirname(__FILE__).'/../cache/'.$file['name']; $newfiles[]=$newfile; copy ($file['tmp_name'],$newfile); if ($file['tmp_name']) $this->post[$name]='@'.$newfile; } } } Line 143 Code: [Select] copy ($file['tmp_name'],$newfile); Hello freaks, I am currently creating a member system that will place a default handle image into a newly registered members file. I have used the mkdir function create the directory successfully based on the members ID, but I can't get the copy function to work. Code: Code: [Select] mkdir("memberFiles/$memberID", 0755); $old = 'images/defaultlogo.jpg'; $new = 'memberFiles/$memberID/logo.jpg'; copy($old, $new); Error Message: Warning: copy(memberFiles/$memberID/logo.jpg) [function.copy]: failed to open stream: No such file or directory Lastly, this folder is created to store members files. hi i made my very first array, and its working great now i want to have another array wich does the same thing, but on another category, it shows gold silver and bronze logos, but now i want to give leaders of other categorys also those logos, but different ones so i thought i change from $array[$snipergameid][$x] = $sniperleaders[playerid]; (part of the code in a while loop) into $array2[$snipergameid][$x] = $sniperleaders[playerid]; (part of the code in a while loop) and i do the same for the result checker loops but that doesnt work so how do i copy an entire arrray, and give it another name to match it with the correct while loop checker? Hi Guys, I am trying to use htmlentities and htmlspecialchars to convert a ampersand (&) to the html markup eqivalant (&) to no avail. any ideas ? htmlentities("this is & that"); Would someone please take a look at this. I am trying to use a form to allow users to answer yes or no with radio buttons, and then print it out on another page. I can only get the script to print the number 1 no matter which button is selected. When I check the database the number 1 is recorded no matter which button is selected. In the top of the input form I have Code: [Select] <input type='hidden' name='electricity' value='0'>In the body of the input form I have Code: [Select] Electricity <input type='radio' name='electricity' value='0'>no <input type='radio' name='electricity' value='1'>yesAnd on the output page I have Code: [Select] $electricity = $row['electricity']; if ($electricity == 1) { $answer = "YES"; } else { $answer = "NO"; }and Code: [Select] echo $row['electricity'];I have been over and over this and can not discover my error. Thank you for looking. xml file: Code: [Select] <PRICES> <PRICE> <WIC>HDE0AAFGRBOX</WIC> <STOCK>100+</STOCK> <MY_PRICE>219.00</MY_PRICE> </PRICE> </PRICES>php file: Code: [Select] <? $filexml='stock.xml'; if (file_exists($filexml)) { $xml = simplexml_load_file($filexml); $f = fopen('stock.csv', 'w'); foreach($xml->PRICES->PRICE as $price) { fputcsv($f, get_object_vars($price),',','"'); } fclose($f); } ?> Error: Warning: Invalid argument supplied for foreach() in C:\xampp\htdocs\stock.php on line 6 Please help with this. Hi All, I am trying to "echo" a result from a SQL query, that returns a size in KB, but I want this to read in MB or GB - can PHP change this for me, or is it something I need to do in SQL? Cheers Matt |