PHP - Simple Question About Ob_start

Hello, I am an absolute PHP newbie, and I have something which is probably a very stupid question. Nevertheless, I am stuck, despite Google and reading the docs.

Here a very cut down example code:
Code: [Select]
<?php
ob_start();
echo "123\n";
$body = ob_get_flush();
echo "body = ".$body;
?>
I would have expected the output to be
body = 123
It actually is
123
body=123
ie ob_start does indeed buffer the output, but it does not prevent if from getting through.
This happens both on my Mac with 5.3.10, and on my server where I dont know the PHP version (...newbie...)

Any help would be appreciated!

I am trying to use output buffering in the following manner:

Code: [Select]
ob_start("OB_BUFFER");
echo 'Start';
do_stuff_function();
ob_end_clean();
echo 'End';

The problem is that when the output of "do_stuff_function" exceeds 4k the output is automatically flushed and I don't know why (exceeding some limit I suppose). 

So when the output of "do_stuff_function" is less than 4k, I get this:

Code: [Select]
Start
My <4k output here...
End

When "do_stuff_function" exceeds 4k, I end up with this:

Code: [Select]
My > 4k output here...
Start
End

I don't understand why this is.  The docs seem to indicate that the way I am starting the ob_start() function there should be no buffer limit.  Is that not true?

Hi there,
I am trying to create a file using fwrite function, but for something reason all I get is a blank file with no content inside.
Here is the code, go to the bottom where the fwrite function is called:
<?php //Get Nohay Albums function
function GetAlbums($cattype){
    if ((isset($_GET['year']))||(isset($_GET['reciter']))){ //nothing displayed 
    }
    
    else{
        
    $query = "SELECT COUNT(Topic), SUM(Hits) AS totalhits, FileFormat, Speaker, Language, Year, FileType, Cat FROM nauhey WHERE Cat='".addslashes($cattype)."' AND Year='".date('Y')."' GROUP By Speaker, Year";
    $result = mysql_query($query) or die (mysql_error());

//<!------------ Create Cache -------------!>
//folder where cache is saved
$path = "cache/";
//Page name format: FunctionName_Category_Year.html
$pagename = $path."getalbums_".$cattype.".html";
$cacheFile = fopen($pagename, "w");
if ($cacheFile == FALSE){ 
    die ("Unable to create cache file"); }
    
//Get HTML in a variable
$obstart = ob_start();
if ($obstart == FALSE){ 
    die ("Unable to buffer cache content!"); }
//<!------------ Cache closed -------------!>

if ($cattype = strtolower('nauhey')){
    while ($row = mysql_fetch_array($result)){
    echo ("<div class='container'>");
    echo ("<img src=\"http://localhost/HAQMOLAAALI/backed up/haqmolaali/images/".$row['FileFormat'].".gif\">");

    echo ("<b style=\"font-size:10px; color:#000066; position:absolute; margin-left: 500px;\">DOWNLOADS: ".$row['totalhits']."</b>");
    echo (" <a href=\"nohay.php?reciter=".urlencode($row['Speaker'])."&amp;year=".urlencode($row['Year'])."\">".$row['Speaker']." Vol ".$row['Year']."</a> <b style=\"font-size:10px; color:#000000;\">(".strtoupper($row['Language']).")</b>"."\n");
echo ("<div class='small'><b>Year: ".$row['Year']." | Language: ".ucfirst($row['Language'])." | Tracks: ".$row['COUNT(Topic)']."</b></div>");
    echo ("</div>");
    }//while loop closed
        
        }
else {
    while ($row = mysql_fetch_array($result)){
    echo ("<div class='container'>");
    echo ("<img src=\"http://localhost/HAQMOLAAALI/backed up/haqmolaali/images/".$row['FileFormat'].".gif\">");
echo ("<b style=\"font-size:10px; color:#000066; position:absolute; margin-left: 500px;\">DOWNLOADS: ".$row['totalhits']."</b>");
echo (" <a href=\"majlis.php?reciter=".urlencode($row['Speaker'])."&amp;year=".urlencode($row['Year'])."\">".$row['Speaker']." Vol ".$row['Year']."</a> <b style=\"font-size:10px; color:#000000;\">(".strtoupper($row['Language']).")</b>");
echo ("<div class='small'><b>Year: ".$row['Year']." | Language: ".ucfirst($row['Language'])." | Lectures in series: ".$row['COUNT(Topic)']."</b></div>");
    echo ("</div>");
    
    }
        }
        
//<!------------ Cache Code -------------!>
$cacheContent = ob_get_contents();
//Write to cache file
fwrite ($cacheFile, $cacheContent) or die ("Cannot write cache content to file!");
fclose ($cacheFile);
ob_flush();
ob_end_clean();
//<!------------ Cache Closed-------------!>
    
    }
}

GetAlbums("nauhey");
?>

When I execute the function, I get my self-made error "Cannot write cache content to file!". Help would be much appreciated. Thank you.

This topic has been moved to PHP Applications.

http://www.phpfreaks.com/forums/index.php?topic=355260.0

I've seen this,
Code: [Select]
<?php } ?>
in a lot of scripts at the very end of the script. What does this piece of code do?

hello all I'm VERY new to php and I just have a simple question

how do I bold the output text of this string

echo $row['name']."<BR>";

what does the # symbol do in php(e.x index.php?cat=1#privacy)? How can i use it? From what i 've seen you use it for changing a whole div without reloading the page like tabs..

Hi.  I have an ID in md5 format but in the database its not.  I pass the md5 ID to a page and then I am trying to load the correct record via a look up in the database of that ID.  Im wondering is this code possible?



<?php $query = mysql_query("SELECT * FROM table WHERE ".md5(tableID)." = $ID"); ?>



Thanks

if someone can help me out with this, its quite simple but I can't seem to get it to work..

Basically, this is the code I have for now, the issue is if I have 0 product or items, I don't want the sorting option to show up on the page,    from the code below, what line can I add tosay that if there is no products in a category, not to show the SORT feature.

thanks in advance if anyone can help.


{if isset($orderby) AND isset($orderway)}
<!-- Sort products -->
{if isset($smarty.get.id_category) && $smarty.get.id_category}
   {assign var='request' value=$link->getPaginationLink('category', $category, false, true)}
{elseif isset($smarty.get.id_manufacturer) && $smarty.get.id_manufacturer}
   {assign var='request' value=$link->getPaginationLink('manufacturer', $manufacturer, false, true)}
{elseif isset($smarty.get.id_supplier) && $smarty.get.id_supplier}
   {assign var='request' value=$link->getPaginationLink('supplier', $supplier, false, true)}
{else}
   {assign var='request' value=$link->getPaginationLink(false, false, false, true)}
{/if}
<form id="productsSortForm" action="{$request|escape:'htmlall':'UTF-8'}">
   <select id="selectPrductSort" onchange="document.location.href = $(this).val();">
      <option value="{$link->addSortDetails($request, $orderbydefault, $orderwaydefault)|escape:'htmlall':'UTF-8'}" {if $orderby eq $orderbydefault}selected="selected"{/if}>{l s='--'}</option>
      {if !$PS_CATALOG_MODE}
      <option value="{$link->addSortDetails($request, 'price', 'asc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'price' AND $orderway eq 'asc'}selected="selected"{/if}>{l s='Price: lowest first'}</option>
      <option value="{$link->addSortDetails($request, 'price', 'desc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'price' AND $orderway eq 'desc'}selected="selected"{/if}>{l s='Price: highest first'}</option>
      {/if}
      <option value="{$link->addSortDetails($request, 'name', 'asc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'name' AND $orderway eq 'asc'}selected="selected"{/if}>{l s='Product Name: A to Z'}</option>
      <option value="{$link->addSortDetails($request, 'name', 'desc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'name' AND $orderway eq 'desc'}selected="selected"{/if}>{l s='Product Name: Z to A'}</option>
      {if !$PS_CATALOG_MODE}
      <option value="{$link->addSortDetails($request, 'quantity', 'desc')|escape:'htmlall':'UTF-8'}" {if $orderby eq 'quantity' AND $orderway eq 'desc'}selected="selected"{/if}>{l s='In-stock first'}</option>
      {/if}
   </select>
   <label for="selectPrductSort">{l s='Sort by'}</label>
</form>
<!-- /Sort products -->
{/if}

Hi, I'm working on a product page and I got it to list all the products in one column of a table, but when I add a second column it just duplicates the first column.  What do I need to change? 

Code: [Select]
<?php
require_once("functions.php"); 
?> 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<style type="text/css">
td {
border-top-style: solid;
border-right-style: solid;
border-bottom-style: solid;
border-left-style: solid;
border-top-color: #30C;
border-right-color: #30C;
border-bottom-color: #30C;
border-left-color: #30C;
}
</style>
</head>

<body>
<form action="" method="post" name="catalog">
<?php 

DatabaseConnection();  

  $query = "SELECT * FROM treats";
        $result_set = mysql_query($query) or die(mysql_error());

        $output = "<table>";
        while ($row = mysql_fetch_array($result_set))
        {
            $output .= (" 
<tr>
<td width=\"400px\">" . $row['product_title']."<br /> ".$row['product_Description']."<br />" .$row['price'] . "<br />  Quantity: <input name=\"quantity\" type=\"text\" size=\"2\" /> </td>  
<td width=\"400px\">" . $row['product_title']."<br /> ".$row['product_Description']."<br />" .$row['price'] . "<br />  Quantity: <input name=\"quantity\" type=\"text\" size=\"2\" /> </td>  
</tr>
");
        }
        $output .= "</table>";
        echo $output;
?>   
</form>
</body>
</html>

Hello everyone! I am a new user and I have a simple question. How do I set a password for a user to log in to my site with PHP? I have no MySQL database just a iOS code/host app. I know this isn’t secure but only me and my friends are on the site. Any help is appreciated. 

I'm teaching myself php and mysql -- and my coding is a little rough.   But what i'm trying to do is display information from a mysql table in another table on a website.  I can do this just fine simply displaying the table, but i want a little something different.  I am only displaying one column of the table, instead of displaying it all in one column, i want to display the information in 5 columns.  for example.....  the table from mysql has names scott, john, james, mary, simon.  with the code I have i can make it display like this:
                                                                                         scott scott scott scott scott
                                                                                         john john john john john
                                                                                         james james james james james
                                                                                         mary mary mary mary mary
                                                                                         simon simon simon simon simon
i want it to diplay like this:
                                                                                          scott john james mary simon
                                                                                          new names will continue down

here is my code:

<?php

require ("connectigb.php");


$result = mysql_query ("SELECT pledgeName FROM pledgewall");

$fields_num = mysql_num_fields($result);


echo "<center> <h1>TSA It Gets Better Pledge Wall</h1>";
echo "<table border='1' align='center' style='width:960px;'><tr>";


while($row = mysql_fetch_row($result))
{
    echo "<tr>";

    // $row is array... foreach( .. ) puts every element
    // of $row to $cell variable
    foreach($row as $cell)
      if ($cell != "") {
for ($j=0; $j<5; $j++) {
        echo "<td>$cell</td>";
   }
   }

    echo "</tr>\n";

}
mysql_free_result($result);
echo "</table></center>";
?>

any ideas on what i can do here, i'm sure this is a simply fix.  i just haven't come across it yet.  thanks for the help in advance.

I can't figure out why im getting an error with this code.

if ($notif = mysql_query("SELECT * FROM notifications_1 WHERE recieverid='". $_SESSION['id']."' ORDER BY read ASC, id DESC") or die (mysql_error())); {

Code: [Select]
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'read ASC, id DESC' at line 1

Hello to everyone

I would like to ask for this simple question.. Im trying to put if and else condition on my php code. However this condition is not working..

Code: [Select]
if($file == #3#){
echo "No results found";
}else{ echo "results has been found"; }
This variable $file is the result after i used an API.. If the API does not see any results they would return #3# as the result. This means they returned a transaction code of 3 which you can see here http://developer.textapp.net/WebService/TransactionCodes.aspx means that there was nothing to return.

The condition does not function well even if i make 3 or #3# as part of the condition. Can you help me guys?

thanks

Lets say I have:

$var=5;

What would an output look like to get me:

1<br>
2<br>
3<br>
4<br>
5<br>

Im at a complete loss!


Thanks!