PHP - Help!!!! Delete A Selected <option> From Dropdown-list Populated By A Mysql-db

I have a form that contains 3 text fields and 7 populated lists (that are dependent on the choice of the previous lists).  When I post the information to MySQL and to my processing page, it posts the table "ids" instead of the selected option. 

Here's the php code for the form:

<form action="gccsuccess_form.php" method="post" enctype="multipart/form-data" name="gcc" id="gcc">
  <table width="700" border="0" align="center" cellpadding="3" cellspacing="3">
    <tr>
      <td><label for="date">Today's Date:</label>
 <input type="text" name="date" id="date"></td>
      <td>&nbsp;</td>
    </tr>
    <tr>
      <td>Week Number:
       <select name="week" size="1" id="week">
         <option value="0" selected>Week 0 - 3/26 - 4/1</option>
         <option value="1">Week 1 - 4/2 - 4/8</option>
         <option value="2">Week 2 - 4/9 - 4/15</option>
         <option value="3">Week 3 - 4/16 - 4/22</option>
         <option value="4">Week 4 - 4/23 - 4/29</option>
         <option value="5">Week 5 - 4/30 - 5/6</option>
         <option value="6">Week 6 - 5/7 - 5/13</option>
      </select></td>
      <td><label for="location"></label>
      </td>
    </tr>
    <tr>
      <td>Location:
        <select id='locations' name='location'>
      </select></td>
      <td>&nbsp;</td>
    </tr>
    <tr>
      <td><label for="label8">Team Name</label>
<select id='team_names' name='team_name'>
</select></td>
      <td>&nbsp;</td>
    </tr>
    <tr>
      <td><em>*Please enter each team member's first and last name:</em></td>
      <td>&nbsp;</td>
    </tr>
    <tr>
      <td><label for="mem_1"> Team <strong>Captain:</strong></label>
        <select id='team_members 1' name='capt'>
        </select></td>
      <td><label for="label4"><strong>Steps:</strong></label>
        <input type="text" name="steps_1" id="steps_1"></td>
    </tr>
    <tr>
      <td><label for="mem_2">Team Member #2 <strong>Name: 
        <select id='team_members 2' name='mem_2'>
        </select>
      </strong></label></td>
      <td><label for="label5"><strong>Steps:</strong></label>
        <input type="text" name="steps_2" id="steps_2"></td>
    </tr>
    <tr>
      <td><label for="mem_3">Team Member #3 <strong>Name:
            <select id='team_members 3' name='mem_3'>
        </select>
      </strong></label></td>
      <td><label for="label6"><strong>Steps:</strong></label>
        <input type="text" name="steps_3" id="steps_3"></td>
    </tr>
    <tr>
      <td><label for="mem_4">Team Member #4<strong> Name</strong>:
        <select id='team_members 4' name='mem_4'>
        </select>
      </label></td>
      <td><label for="label7"><strong>Steps:</strong></label>
        <input type="text" name="steps_4" id="steps_4"></td>
    </tr>
    <tr>
      <td><label for="label">Team Member #5<strong> Name</strong>:
        <select id='team_members 5' name='mem_5'>
        </select>
      </label></td>
      <td><label for="label7"><strong>Steps:</strong></label>
          <input type="text" name="steps_5" id="steps_5"></td>
    </tr>
    <tr>
      <td>&nbsp;</td>
      <td>&nbsp;</td>
    </tr>
    <tr>
      <td>&nbsp;</td>
      <td><em>* Maximum steps for each team member per week is <strong>105,000. </strong></em></td>
    </tr>
    <tr>
      <td>&nbsp;</td>
      <td><input type="submit" name="Submit Form" id="Submit Form" value="Submit"></td>
    </tr>
  </table>
  <label></label>
  <div align="center"><br>
    If you have questions about the competition or reporting please contact KC   WELLNESS, INC&nbsp;toll free at <SPAN id="lw_1237248942_0">877-634-1412.</SPAN><br>
    <br>
  </div>
</form>


And here's the code for the page it is posted in:

<?php
      
      $date = $_POST['date'];
      $week = $_POST['week'];
      $location = $_POST['location'];
      $team_name = $_POST['team_name'];
      $capt = $_POST['capt'];
      $mem_2 = $_POST['mem_2'];
      $mem_3 = $_POST['mem_3'];
      $mem_4 = $_POST['mem_4'];
      $mem_5 = $_POST['mem_5'];
      $steps_1= $_POST['steps_1'];
      $steps_2= $_POST['steps_2'];
      $steps_3= $_POST['steps_3'];
      $steps_4 = $_POST['steps_4'];
      $steps_5 = $_POST['steps_5'];
      
      mysql_connect("mysql1.myregisteredsite.com", "49200_kandace", "Leonardo56")
      or die(mysql_error());
      mysql_select_db("49200_GCC") or die(mysql_error());
      mysql_query("INSERT INTO `walkathon` VALUES ('$date', '$week', '$location', '$team_name', '$capt','$mem_2','$mem_3',  '$mem_4', '$mem_5', '$steps_1','$steps_2', '$steps_3','$steps_4', '$steps_5' )"); 

      Print "Thank you for your entry. <br>
      Report summary: <br/><br/>";    
      
         echo "<strong> Date: </strong>   {$date} 
         <br/> <br/><strong> Week: </strong>   {$week}
         <br/> <br/><strong> Location: </strong>  {$location}
         <br/> <br/><strong> Team Name: </strong>   {$team_name}
         <br/> <br/><strong> Team Captain: </strong>  {$capt} / <strong> Steps: </strong> {$steps_1} 
         <br /> <br/><strong> Team Member 2 Name: </strong>  {$mem_2} / <strong> Steps: </strong> {$steps_2} 
         <br /> <br/><strong> Team Member 3 Name: </strong>  {$mem_3} / <strong> Steps: </strong> {$steps_3}
         <br /> <br/><strong> Team Member 4 Name: </strong>  {$mem_4} / <strong> Steps: </strong> {$steps_4}
         <br /> <br/><strong> Team Member 5 Name: </strong>  {$mem_5} / <strong> Steps: </strong> {$steps_5}"
         
               ?>

How do I get the processing page to echo the selected option instead of the id?

Hi,  I'm a php newbie, with some mysql experience. I have a mysql database as follows:
Database=watch, Table=events - fields id, reportno, sdate, comments

What I need is:
1. A dropdown list to display reportno from mysql database.
2. Depending on which reportno I choose, I'd like to open a popup(or separate) page to display the stored information.

Tks in advance for any help

I'm just attempting to learn how PHP handles things and I can't quite wrap my head around how to apply Selected to the final Option and show the Traits for the Character based on the Selected Option.

I understand this might need POST, if it does, I would appreciate a bit of help on how I would set this up as POST since I didn't think a drop down required a submit button.

Code: [Select]
$character= array (array(Name=>"Barry","Class"=>"Fighter",Level=>1,Str=>10,Dex=>10,"Int"=>10),array(Name=>"Lindehar","Class"=>"Ranger",Level=>1,Str=>10,Dex=>10,"Int"=>10),array(Name=>"Verelden","Class"=>"Mage",Level=>1,Str=>10,Dex=>10,"Int"=>10));

print "Select a Character:<br /><select>";
foreach($character as $array_num)
{
foreach($array_num as $char_trait=>$trait_value)
{
if($char_trait==Name)
{
$selected_value="";
$generated_chars="<option selected=".$selected_value." value='".$char_trait."'>".$char_trait.": ".$trait_value."</option>";
print $generated_chars;
if($selected_value=/".$char_trait.": Barry"/")
{
foreach($char_trait=="Barry")
{
print "<h4>".$char_trait.": ".$trait_value."</h4>";
}
}
}


}
}
print "</select><p />";

mysql.php
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("ckeditor",$con);
?>
---------------------------------------------------------
add.php
<?php
include("mysql.php");


if(isset($_POST["button2"]))
{
$sql="INSERT INTO cktext (section)
VALUES
('$_POST[select2]')";

if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }

?>

-----------------------------------------------------------------
home.php

<form id="form1" name="form1" method="post" action="add.php">
<tr>
    <td>Section:</td>
    <td><select name="select2" id="select2">
     <option selected="selected" value="MALE">Male</option>
  <option selected="" value="FEMAIL">FEMAIL</option>
    </select></td>
  </tr>
<input type="submit" name="button2" id="button2" value="Upload" />
  </form>

In DATABASE :- cktext table attribute "section" is varchar type.

BUT IT RETURN ME BLANK OUTPUT.

Hi, basically, here's the deal:
I have a lit of checkboxes that are added by the admin (there's an unlimited amount, just depends on how many are added). Then, those are put in a form, in which the user picks whichever ones need to be chosen and those values get sent to a MySQL table.

Here's the code that displays the checkboxes

Code: [Select]
<?php
$sql="SELECT * FROM category ORDER BY categoryID ASC";
$result=mysql_query($sql); 

while($row=mysql_fetch_array($result)){
    echo "<input type='checkbox' id='". $row['categoryName'] ."' name='licensed[]' value='" . $row['categoryID'] ."' /><label for='". $row['categoryName'] ."'><br>" . $row['categoryName'] ."</label><br>";
}
?>
What I'm making now, is an edit form where whichever checkboxes were checked, will show up checked in the edit form. But I'm not really sure how to go about this, since there is only one actual input tag in the code, I can't select the different ones.

I also have this SQL query which selects whichever boxes were inputted into the DB

Code: [Select]
$sql2="SELECT * FROM category, categoryInfo WHERE category.categoryID = categoryInfo.categoryID AND categoryInfo.parentID = $parentID";
$result2=mysql_query($sql2);
Where $parentID is the ID of whichever form you're editing.

But yes, I'm basically not really sure how to go about this and would like some help figuring this out

Thanks for your time