PHP - Php - Access Db Coding Issue

Im new to PHP so bare with me.  I created a form for my website.  A person can enter the information and when they hit "submit" all of the information is sent to my email.  for example:   name: mike   state: ca   comment: hi   my problem is this: some of the entered information is sent, while other entered information is not.  I also have a drop down menu that the user can chose from a variety of answers.  how do i use php to get that information sent to my email? If this isnt a clear explanation please forgive me b/c Im not so sure how to explain it.    Any help is appreciated! 

Hey Guys,


I posted a topic titled "Error while executing PHP script for Like/Dislike button" in the forum but am unable to access the topic. The link to the topic is http://www.phpfreaks.com/forums/index.php?topic=353877.new;topicseen#new. Kindly help me as I an unable to locate/search for it. Thank you.

I'm using a wordpress theme which comes with a zoom feature for the product (main image and image gallery thumbnails). 
It currently opens the primary image (and any thumbnail) in a modal window which is quite ugly for a product showcase. 

Code is:

Code: [Select]
    $imgtag = '<img src="'.$src.'"'.$titleattr.' alt="'.$alt.'" width="'.$width_a.'" height="'.$height_a.'" '.$classes.' />';
   
    if (value_is_true($zoom))
    return '<a href="'.ecarturl($img->id,'images').'/'.$img->filename.'" class="'.$zoomfx.'" rel="product-'.$this->id.'">'.$imgtag.'</a>';
I'm trying to implement Cloudzoom (http://www.professorcloud.com/mainsite/cloud-zoom-integration.htm)

I changed the code to:
Code: [Select]
$imgtag = '<a href="'.ecarturl($img->id,'images').'/'.$img->filename.'" class = "cloud-zoom" id="zoom1" rel="adjustX: 10, adjustY:-4, zoomWidth:150, zoomHeight:150, position:\'inside\'"> <img src="'.$src.'"'.$titleattr.' alt="'.$alt.'" width="'.$width_a.'" height="'.$height_a.'" '.$classes.' /></a>';

if (value_is_true($zoom))
return '<a href="'.ecarturl($img->id,'images').'/'.$img->filename.'" class="cloud-zoom-gallery" rel="useZoom: \'zoom1\'">"'.$imgtag.'</a>';
HTML Output:
Code: [Select]
    <div id="main-picture-default">
    <a href="http://www.url.com?siid=9/2-9202.jpg" class = "cloud-zoom" id="zoom1" rel="adjustX: 10, adjustY:-4, zoomWidth:150, zoomHeight:150, position:'inside'"> <img src="http://www.url.com?siid=9&#038;360,450,1,100,2441305929" alt="product-picture" width="360" height="450"  /></a> </div>
    <div id="thumbs">
    <ul id="thumbs-list-default">
   
    <li class="one_third "><a href="http://www.url.com?siid=9/2-9202.jpg" class="cloud-zoom-gallery" rel="useZoom: 'zoom1'">&#8220;<a href="http://www.url.com?siid=9/2-9202.jpg" class = "cloud-zoom" id="zoom1" rel="adjustX: 10, adjustY:-4, zoomWidth:150, zoomHeight:150, position:'inside'"> <img src="http://www.url.com?siid=9&#038;64,64,1,452849676" alt="thumb" width="64" height="64"  class="thumb-picture" /></a></a></li>
    <li class="one_third "><a href="http://www.url.com?siid=17/2-9203.jpg" class="cloud-zoom-gallery" rel="useZoom: 'zoom1'">&#8220;<a href="http://www.url.com?siid=17/2-9203.jpg" class = "cloud-zoom" id="zoom1" rel="adjustX: 10, adjustY:-4, zoomWidth:150, zoomHeight:150, position:'inside'"> <img src="http://www.url.com?siid=17&#038;64,64,1,1330882420" alt="thumb" width="64" height="64"  class="thumb-picture" /></a></a></li>
    </ul>
The primary image zooms just fine. 

The trouble I have now caused is as follows: 

- On hovering the thumbnails, they automatically zoom. They shouldn't. Rather on clicking them it should change the primary image to that image. 
- There is a " on the page above each thumbnail which links to the thumbnail images bigger image, and on click it shows "loading" on the primary image but doesn't actually change the image.

How can I fix my code to work the way the script works he http://www.professorcloud.com/mainsite/cloud-zoom-test.htm, so the thumbnail changes the primary image and the zoom doesn't occur on the thumbnail, only the primary image? 

Thanks!

Note: Would changing the last line `'.$imgtag.'` to `'.ecarturl($img->id,'images').'/'.$img->filename.'` be the fix? Don't want to try it before I get confirmation

Hello, there I'm new at the PHP/MySql matter and so the code I'm going to bring up that I'm having trouble with was written by someone else for me a number of years ago.  It worked just fine until recently and I'm not sure why it just up and stopped working.  Nothing has changed, the database that this code is connected to is still very much the same. 

The problem I am having is trying to login via the Login name and Password.  As I said before this code worked just fine up to a few days ago and the person that wrote this out for me has long since disappeared into the ether and I would really love to get this back up and working again, I just don't know where to begin. 

Now the problem, once from the login it gets me far enough to the "Login Success. Forwarding to tools..." that takes all who have access to tools to this next stage and that's when the trouble hit, with the information in and it sits and then come back "No password provided"  so its basically not gettting the information from the database itself.  Or something.  So yes, if someone see something small, or an update in code or something, would be great.  Otherwise... just have to give up on this.  Be my luck the other PHP code that I have for the other various things - I run an online Roleplaying site requires people to submit character sheets, then to be able to view sheets, edit certain part of the sheets and this particular project is for the Storytellers to update those sheets - has decided to say um, I'm done working now.   

My webprovider offers the following if this is needed information wise:
MySQL version 5.0.90-community
PHP version 5.2.13

Thanks much for taking the moment to look this over, I'll try to provide as much detail I can if anyone post any further inquiry on this odd problem of mines.

<?PHP
if( !isset($pass) ){ die("No password provided"); }
if( $pass == "" ){ die("No password provided"); }
$sql = "SELECT * FROM stlogin WHERE id='$ID'";
mysql_connect("localhost", "USERNAME", "PASSWORD");
$rs = mysql_db_query("primevil_database",$sql);
while ($row = mysql_fetch_object($rs)){ 
$password1 = $row->pass;
$login = $row->login;
$access = $row->access;
}
if( $password1 == $pass ){  }
else{ die("Password not matched"); }
?>
<?PHP
if($access >= 2){
echo "Welcome $login. <BR>";
}
if($access == 3){
echo "<strong><font color=\"#FF0000\">ST Level Access</font></strong><BR>";
}
if($access == 2){
echo "<strong><font color=\"#FF0000\">Assistant ST Level Access</font></strong><BR>";
}
if($access == 4){
echo "<strong><font color=\"#FF0000\">Admin Level Access</font></strong><BR><a href=\"deletechar.php?ID=$ID&pass=$pass\">Delete Character.</a><br>";
}
if($access == 3 | $access == 4){
echo "<a href=\"editchar.php?ID=$ID&pass=$pass\">Edit Character.</a><br>";
}
if($access == 2 | $access == 3 | $access == 4){
echo "<a href=\"searchchar.php?ID=$ID&pass=$pass\">Search Character.</a><br><a href=\"viewchar.php?ID=$ID&pass=$pass\">View Character.</a>";
}
?>

I'm developing my own CMS with a few functions and wanted to know how things are looking right now because I can't find a board for strickly CODING CRITIQUE so I put it in this board. There isn't a whole lot to go through. I know there is something wrong with my issets line but other than that just a general critique of how its shaping up?

manager.php

<?php
        session_start();

        require "dbconfig.php";
        require "functions.php";

        if ((isset($_POST['username'])) && (isset($_POST['password'])))
        {
                $username = $_POST{'username'};
                $password = SHA1($_POST{'password'});
                validate($username, $password);
        }
        elseif ((!(isset('username'))) && (!(isset('password'))))
        {
                require_once "login.php";
        }
        
        $username = stripslashes($username);
        $password = stripslashes($password);
        $username = mysql_real_escape_string($username);
        $password = mysql_real_escape_string($password);
        
        $sql="SELECT * FROM dbusers WHERE username='$username' and password='$password'";
        $result = mysql_query($sql);
?>




functions.php

<?php

// This page defines functions used by the login/logout process

function validate($username, $password)
{
    
}

?>


login.php

<?php
include_once ("globals.php");
?>

<html>
<head>
<title><?php echo $shortsitename; ?> EW Manager</title>
<link rel="stylesheet" type="text/css" href="<?php echo "$stylesheet"; ?>" />
</head>
<body>

<p id="backtosite"><a href="#" title="Are you lost?">&larr;&nbsp;Back to <?php echo $fedname ?></a></p>

<div id="login">
    <h1><?php echo $shortsitename; ?> Manager</h1>
    <form id="loginform" action="" method="POST">
        <p><label>Username<br /><input type="text" name="username" id="user_login" class="input" size="15"  /></label></p>
        <p><label>Password<br /><input type="password" name="password" id="user_pass" class="input" size="15" /></label></p>
        <p class="forgetmenot"><label><input name="rememberme" type="checkbox" id="rememberme" />&nbsp;Remember Me</label></p>
        <p class="submit">
        <input type="submit" value="Login" class="button-primary" />
        </p>
    </form>
</div>

</body></html>