PHP - Add Up Values In A Column In Excel?
I am trying to find a loop type script that starts at a particular row in a particular column in an excel file and keeps adding values in each row until the last value is reached.
I have searched and am pretty new to loops. can anyone point me in the right direction please? Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
Hi everyone, I got a bit of code off the web and did some tweaking. I want to use it to export data from a mysql table to excel. I do a website for a friend and have been exporting it myself and emailing it to him. However, I thought it'd be easier if I could just direct him to a link so he could get it whenever. Anyway, the code below works pretty well...the only problem being that it exports all data to the first column of the excel file. There are commas between all fields, so it is possible to use the 'text to columns' feature in excel to separate teh data into separate columns. However, if there is a way of fixing the code that would negate the need to have to do this, it would be much appreciated. Here goes: <?php $db = mysql_connect("localhost", "MYUSERNAME", "MYPASSWORD"); mysql_select_db("MYDATABASE",$db); $query="SELECT * FROM MYTABLENAME"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); $csv_output = "firstname,lastname,emailaddress,crew_name_001"; $csv_output .= "\r\n"; $i=0; while ($i < $num) { $id=mysql_result($result,$i,"id"); $firstname = mysql_result($result,$i,"firstname"); $lastname = mysql_result($result,$i,"lastname"); $emailaddress = mysql_result($result,$i,"emailaddress"); $crew_name_001 = mysql_result($result,$i,"crew_name_001"); $csv_output .= "$firstname,$lastname,$emailaddress,$crew_name_001\n"; ++$i; } $mode="xls"; $type="excel"; header("Content-type: text/x-csv"); header("Content-disposition: attachment; filename=".date("d-m-Y")."-export.xls"); print $csv_output; exit; ?> Thanks for your time, Dave Hi there, I am working on a page. That has all the products listed on it. Every product has a Shipping profile associated with it. Whenever a new product is created, we assign a Shipping profile to that new Product. And its product ID is then inserted into the Shipping profile table. Note: One Shipping Profile can have multiple Products under it. The scenario is that when we create the 2nd product and assign Shipping Profile and insert the 2nd product ID to Shipping Profile, the old value gets replaced with the new ProductID. We just need to somehow append the new ProductID to the existing ProductIDs in the Shipping Profile table. We can do an Update query but that will replace the Old Product ID with the new ProductID. Here we just need to append the new Product ID to the Old product ID. eg ............................... Shipping Profile Table| `````````````````` ShippingProfileID ProductID 1 1,4,6 2 3,7 Now at the moment, the ProductID gets stored but it just replaces the Old product ID. We just need to append to the existing IDs Any comments or feedback are always welcomed. Thank you! Hi, I have this form currently setup and is showing the value from the table. <form action="updaterates.php" method="post"> <table width="350"> <tr> <td width="100">7 Nights</td> <td width="100"><input type="text" name="rates1" value="<?php echo ($row['rates1']); ?>" maxlength="3" size="3"></td> </tr> </table> </form> What do I need to do in order for it to update the value in the table... Thanks in advance... Hello, I am trying to add all rows in the same column together. So here is the basic scheme: id l column1 1 l 1 2 l 2 3 l 3 Second table id l variable1 1 l 3 2 l 5 3 l 6 I basically want to add 5+3+6 and set it to a variable named '$total'. Would this be done using while loops? Here is the code I have been messing with. $sql="SELECT column1 from table1 where id='$userid'"; // userid would be set near the top of the page $sql2=mysql_query($sql,$conn); while($rows=mysql_fetch_array($sql2)){ $getid = $rows['column1']; $sql3="SELECT variable1 FROM table2 where id='$getid'"; $sql4=mysql_query($sql3,$conn); while($items=mysql_fetch_array($sql4)){ // Then I'm getting lost... } } Can you at least see what I am trying to do? I'm not even sure if this is the right approach, any help would be appreciated! Hi all, I have a table... id | Name | Downloads | 01 | tom | 5 02 | thomas | 2 03 | tommy | 15 I need a button in my page whcih on submit would resent the 'downloads' column so all values are set to 0, Is this possible and how if it is? Thanks for any advice Hello, I am trying insert the values of csv file into a table. I want to concatenate the values of some columns of csv into one String column of table by delimiting them my commas. $im="INSERT into TB1 (col1, col2 ) values ('$a[2]','$a[3]')"; $b = ""; $b=".'$a[6]'."||".'$a[7]'."||".'$a[8]'."||".'$a[9]'."; $im1=$im+"UPDATE TB1 set latlng=.'$aline'."; mysql_query($im1) OR die(mysql_error()); I need to enter the value of $a[6] till $a[9] into a string column with delimiters and insert into the column col3 of TB1 with value as $a[4]. I am stuck up here could anyone help me with this issue. Hi, I have downloads that are available for users. They can click the links to download the file. Once they do this, I have a query that updates the number of downloads that file has received. I need to create a query that adds up all the rows Total Downloads. So for example: i have 3 rows: Name - Total Downloads First - 2 Second - 23 Third - 7 Using the query for these rows would give me an amount of 32. Any idea how to do this? I don't want to have to create a new column to find the total number of downloads. Any other ways? I need some help and hopefully will respond. I'm trying to put some information to the second row of the excel sheet once extracted. Can somebody help me with this script? I'm trying to move the address line to the second row. Thanks. Hello, i am currently getting an Microsoft Excel formatted text file whose save type is .Txt from a URL.I used to open it and will change the save type as excel file. Please suggest whether we can do this with php code. currently my code is like this, <? php copy("http://www.faa.gov/airports/airport_safety/airportdata_5010/menu/emergencyplanexport.cfm?Region=&District=&State=&County=&City=LAS%20VEGAS&Use=&Certification=","./contactsexport.xls"); ?> where as the contactsexport.xls type is .Txt which i need it in .xls Thanks in Advance. PHP script return 20 UL LIST values like, < ul >
A < /ul > How to display UL LIST into row wise 5 columns like
A B C D My Php Buddies, I have mysql tbl columns these:
id: Now, I want to display their row data by excluded a few columns. Want to exclude these columns: date_&_time account_activation_code account_activation_status id_verification_video_file_url password
So, the User's (eg. your's) homepage inside his account should display labels like these where labels match the column names but the underscores are removed and each words' first chars CAPITALISED:
Id: 1
For your convenience only PART 1 works. Need help on Part 2 My attempted code:
PART 1 <?php // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } // Query to get columns from table $query = $conn->query("SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = 'members' AND TABLE_NAME = 'users'"); while($row = $query->fetch_assoc()){ $result[] = $row; } // Array of all column names $columnArr = array_column($result, 'COLUMN_NAME'); foreach ($columnArr as $value) { echo "<b>$value</b>: ";?><br><?php } ?> PART 2 <?php //Display User Account Details echo "<h3>User: <a href=\"user.php?user=$user\">$user</a> Details</h3>";?><br> <?php $excluded_columns = array("date_&_time","account_activation_code","account_activation_status","id_verification_video_file_url","password"); foreach ($excluded_columns as $value2) { echo "Excluded Column: <b>$value2</b><br>"; } foreach ($columnArr as $value) { if($value != "$value2") { $label = str_replace("_"," ","$value"); $label = ucwords("$label"); //echo "<b>$label</b>: "; echo "$_SESSION[$value]";?><br><?php echo "<b>$label</b>: "; echo "${$value}";?><br><?php } } ?> PROBLEM: Columns from the excluded list still get displayed. Edited November 19, 2018 by phpsaneDear All Members here is my table data.. (4 Columns/1row in mysql table)
id order_no order_date miles How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.
(5 Columns in mysql table) id order_no order_date state miles 310 001 02-15-2020 MI 108.53 310 001 02-15-2020 Oh 194.57 310 001 02-15-2020 PA 182.22
310 001 02-15-2020 WA 238.57 ------------------my php code -----------
<?php
if(isset($_POST["add"]))
$miles = explode("\r\n", $_POST["miles"]);
$query = $dbh->prepare($sql);
$lastInsertId = $dbh->lastInsertId(); if($query->execute()) {
$sql = "update tis_invoice set flag='1' where order_no=:order_no"; $query->execute();
} ----------------- my form code ------------------
<?php -- Can any one help how to correct my code..present nothing inserted on table
Thank You Edited February 8, 2020 by karthicbabuHi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
I need to parse xls files (Microsoft Excel). The option to tell the users who will be uploading the files to convert it to a more friendly format like XML or CSV is not an option (I know its unfortunately, though I have to make it so it parses those formats as well (fun is)). Users must be able to just save the file, and upload it as is. below is a link to a example xls file. So I am looking to see if there's anything native to php that will allow me to open and read xls formatted files quickly and efficiently and work with the values independently on a per row per column basis when outputting them. Or if there's a recommended library/class I can use that someone here can suggest. My biggest issue is I am on a time crunch so I need something I can work with quickly and efficiently all around. Any samples would be greatly appreciated. http://mtpdev.com/dev/xls-reader/sample.xls Hi All, I am trying to export a table into excel and it is working, kind of.. I'm trying to import data that has commas in it. Unfortunately, it looks like this "PHP to CVS" process is comma delimited. How can I get around that, while having the data in the correct columns? Here is my code: Code: [Select] $file = 'Notes_Export'; $csv_output = ''; $sql = "SHOW COLUMNS FROM prop_notes WHERE Field IN ('note', 'created_by', 'created_on', 'updated_by', 'updated_on')"; $result = mysqli_query($connect, $sql); $i = 0; if (mysqli_num_rows($result) > 0) { while ($row = mysqli_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $sql = "SELECT note, created_by, created_on, updated_by, updated_on FROM prop_notes"; $values = mysqli_query($connect, $sql); while($rowr = mysqli_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= $rowr[$j].", "; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d_H-i",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); // header( "Content-disposition: filename=".$filename.".csv"); header("Content-disposition: attachment; filename=".$filename.".csv"); print $csv_output; exit; I need a way of parsing Excel files.. both xls and xlsx in what seems to be various formats.. the concept of the way the expected sheets are to come in is with 2 tabs first tab row one column one will be a single value.. second tab will be any number of values only 2 columns though. I had found one parser class that I could use but it was very limiting and for some reason didn't work when I saved a fresh file... whats the best class, or way of handling an excel file? is there anything out there freely avaliable to work with thats kept upto date? or that works? Hi I have a script which references a DB and then produces an XML output saved as XLS to then open in Excel. This works an absolute dream in my dev environment using IE7 and in live using Firefox. However my entire audience uses IE7 and this is where it breaks in the live environment. For some reason, I cannot get the download to work. I get a windows pop-up with an error on it - see attached. If you need to see code, let me know which bit of code could possibly cause this, i.e. headers etc. I've not posted code as there's loads of it and I can't understand why it works in dev in IE 7 but not in live, and works in Firefox in live. Hi I have a database set up using MySQL and want to be able to query this and then export to Excel using PHP. I've had a look around on the web but a lot of what I'm reading is going over my head. I don't have PEAR so can't use the ready made stuff. Basically, I want to be able to query the database, then export the arrays to an excel file and a pop up to appear asking the user to open / save / cancel (standard pop-up) Anyone know of any good places to start looking for the information for this? Sorry, I'm new to all this so any help / pointers would be greatly appreciated. Cheers Hi all, I'm a first time poster here and I would really appreciate some guidance with my latest php challenge! I've spent the entire day googling and reading and to be honest I think I'm really over my head and need the assistance of someone experienced to advise the best way to go! I have a multi dimensional array that looks like (see below); the array is created by CodeIgniter's database library (the rows returned from a select query) but I think this is a generic PHP question as opposed to having anything to do with CI because it related to working with arrays. I'm wondering how I might go about searching the array below for the key problem_id and a value equal to a variable which I would provide. Then, when it finds an array with a the matching key and variable, it outputs the other values in that part of the array too. For example, using the sample data below. How would you recommend that I search the array for all the arrays that have the key problem_id and the value 3 and then have it output the value of the key problem_update_date and the value of the key problem_update_text. Then keep searching to find the next occurrence? Thanks in advance, as above, I've been searching really hard for the answer and believe i'm over my head! Output of print_r($updates); CI_DB_mysql_result Object ( [conn_id] => Resource id #30 [result_id] => Resource id #35 [result_array] => Array ( ) [result_object] => Array ( ) [current_row] => 0 [num_rows] => 5 [row_data] => ) Output of print_r($updates->result_array()); Array ( [0] => Array ( [problem_update_id] => 1 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Some details about a paricular issue [problem_update_active] => 1 ) [1] => Array ( [problem_update_id] => 4 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Another update about the problem with an ID of 3 [problem_update_active] => 1 ) [2] => Array ( [problem_update_id] => 5 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of four [problem_update_active] => 1 ) [3] => Array ( [problem_update_id] => 6 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of 6 [problem_update_active] => 1 ) [4] => Array ( [problem_update_id] => 7 [problem_id] => 3 [problem_update_date] => 2010-10-12 [problem_update_text] => Some new update about the problem with the ID of 3 [problem_update_active] => 1 ) ) |