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PHP - Create A Form Within A Form By Button Trigger
Hi,
how can i create a form within a form with the click of a button? so that when i click add new item, it brings form fields under the current one. hope my explanation helps thanks Code: [Select] <form id="form1" name="form1" method="post" action=""> <table width="100%" border="0" cellspacing="2" cellpadding="0"> <tr> <td width="22%">Invoice Number </td> <td width="78%"> </td> </tr> <tr> <td>Date Issued </td> <td> </td> </tr> <tr> <td colspan="2"> </td> </tr> <tr> <td colspan="2"><table width="100%" border="0" cellspacing="2" cellpadding="0"> <tr> <td width="10%">Quantity</td> <td width="70%">Description</td> <td width="9%">Taxable</td> <td width="11%">Amnount</td> </tr> <tr> <td valign="top"><input name="textfield" type="text" size="7" /></td> <td valign="top"><textarea name="textfield2" cols="80"></textarea></td> <td valign="top"><input type="checkbox" name="checkbox" value="checkbox" /></td> <td valign="top"><input name="textfield3" type="text" size="12" /></td> </tr> <tr> <td colspan="4"><input type="submit" name="Submit" value="Add New Item" /></td> </tr> </table></td> </tr> <tr> <td colspan="2"> </td> </tr> <tr> <td colspan="2"> </td> </tr> <tr> <td colspan="2"> </td> </tr> </table> </form> Similar TutorialsHello everyone, I am working on a form that is similar to a shopping cart system and I am thinking of creating a button that submits the checked value and saves them to a $_SESSION variable. And also a link that links to a cart.html that takes the values of a $_SESSION variable. I am have trouble figuring what tag/attribute should I use in order to achieve that.
Right now my code attached below submits the checked values to cart.html directly. However I want my submit button to save the checked box to a $_SESSION variable and STAY on the same page. And then I will implement a <a> to link to the cart.php.
I researched a little bit about this subject and I know it's somewhat related to ajax/jquery. I just wanted to know more about it from you guys. I appreciate your attention for reading the post and Thanks!
Below is the form that I currently have:
<form name= "finalForm" method="POST" action="cart.php">
<input type="Submit" name="finalSelected"/>
<?php foreach($FinalName as $key => $item) {?>
<tr>
<td><input type="checkbox" name="fSelected[]" value="<?php echo htmlspecialchars($FinalID[$key])?>" />
<?php echo "$FinalID[$key] & $item";?>
</td>
</tr>
<?php } ;?>
Below is the code for cart.php
<?php
require ('connect_db.php');
if(isset($_POST['finalSelected']))
{
if(!empty($_POST['fSelected']))
{
$chosen = $_POST['fSelected'];
foreach ($chosen as $item)
echo "aID selected: $item </br>";
$delimit = implode(", ", $chosen);
print_r($delimit);
}
}
if(isset($delimit))
{
$cartSQL = "SELECT * from article where aID in ($delimit)";
$cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc));
while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH))
{
$aTitle[] = $row[ 'name' ];
}
}
?>
<table>
<?php if(isset($delimit)) {
$c=0; foreach($aTitle as $item) {?>
<tr>
<td>
<?php echo $aTitle[$c]; $c++;?>
</td>
</tr>
<?php }}?>
</table>
When creating a PHP document we use echo ''; to wrap HTML into PHP, so why does it seem to me that people always say to create a form using PHP you must break it up by using HTML to show the form itself? Is there a way to create the form, and do all that is required using PHP and wrapping PHP around HTML to make it work? I can't imagine its impossible. I am trying to create a form that will be store in-house. This form needs to have a drop-down of keywords. These keywords will cause a snippet of code (pulled from the selection of the keyword) to be placed into a text document one after another. Ex.: I click on "Header" in the list and click Insert Code. This causes Code: [Select] "<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">" to be placed into the text document. I then hit click on "Body" and it creates the Code: [Select] "<body></body" code to appear on the text document below the "Header" code above it. This is basically a text writer that just uses snippets of code as I click on buttons. Almost like this editor above is doing. Is this possible and is it easy/hard? -john i don't know what this would fall under, but it sounds like php..........is there a way to make a form make a new page from a template........like I have a picture page and I can upload pictures from a form with a picture name....and that name turns into a /name.php file? does this make sense? Hey all, I am trying to put a login form on the front pages (index, contact us, about us) of my site. I want the members to put in username and pass, and when they click submit, it takes them to the /members/ area of the site. Right now this is how I have the form. Code: [Select] <form method="POST" action="login.php"> <input type="text" name="username"> <input type="password" name="password"> <input type="submit" value="Login"> </form> I have this, but the members area consist of several pages and not just on location. Code: [Select] if ($_SESSION['authorized'] != true) { header("Location: login_form.php"); exit; } Finally, I am going to create a login.php page that has this in it. Code: [Select] $select_user = mysql_query('select * from users where username = "' . $_POST['username'] . '" and password = "' . md5($_POST['password'] . '"')); if (mysql_num_rows($select_user) != 0) { session_start(); session_register('authorized'); $_SESSION['authorized'] = true; header("Location: protected_content.php"); exit; } else { header("Location: login_form.php"); exit; } So My questions are, How can I make it so they can access the entire /members/ area (directory) and what would I put in the database 'members' when I create it. All members are going to use the same username and pass. So there is only need for 1 query for username and 1 for password. I appreciate anyone help in advance. I am currently looking to have two pages, one with a search form (textbox and button) and output the results (from database table) based on the strings input to another page. how do i achieve this? i just want something very simple nothing too complex and advanced please So completely new here.
I've created a database that has 4 fields full_name, company, email and serial_no with 2 sample records.
I would like to create a form with those fields, so the data I enter into the form when I press submit it goes into the database. Config File:
<?php
$mysqli = new mysqli('localhost', 'username', 'pass', 'database_name');
if($mysqli->connect_error)
{
echo $mysqli->connect_error;
}
?>
Index.php
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Add Record Form</title>
</head>
<body>
<form action="insert.php" method="post">
<p>
<label for="Fullname">Fullname:</label>
<input type="text" name="full_name" id="Fullname">
</p>
<p>
<label for="Company">Company:</label>
<input type="text" name="Company" id="Company">
</p>
<p>
<label for="emailAddress">Email Address:</label>
<input type="text" name="email" id="emailAddress">
</p>
<p>
<label for="Serial">Serial:</label>
<input type="text" name="Serial" id="Serial">
</p>
<input type="submit" value="Submit">
</form>
</body>
</html>
Insert.php
<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
$link = mysqli_connect("localhost", "username", "pass", "database_name");
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Escape user inputs for security
$full_name = mysqli_real_escape_string($link, $_REQUEST['full_name']);
$company = mysqli_real_escape_string($link, $_REQUEST['company']);
$email = mysqli_real_escape_string($link, $_REQUEST['email']);
$serial_no = mysqli_real_escape_string($link, $_REQUEST['serial_no']);
// Attempt insert query execution
$sql = "INSERT INTO licjwe(full_name, company, email, serial_no) VALUES ('$full_name', '$company', '$email', '$serial_no')";
if(mysqli_query($link, $sql)){
echo "Records added successfully.";
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($link);
?>
This is the error I am getting:
ERROR: Could not able to execute INSERT INTO database_name(full_name, company, email, serial_no) VALUES ('test', '', 'email@home.com', ''). Table 'table_name' doesn't exist
Not sure what I am doing.
Basically I want to have the form so I can enter the data, once its been entered, it lets me know its been successfully updated, then loads the page again.
Please help. Where have I gone wrong?
Hey everyone, I am looking to create an advanced contact form but need someone to point me in the right direction. I need to create a customer service form and would like it to contain the usual fields e.g. Name, Email etc. but also want to include a drop down field which has a couple of options e.g. Sales Enquiry, Order Status etc. Once one of those options has been selected e.g. Order Status, I then want a further section of the form to appear where the user can input data such as their order number, order date etc. Does anyone have any ideas on how to achieve this or know of any demos/scripts which they think might help. I am trying to create a very basic "forum"/comments section and I want to know how to have a page be automatically created once the form is submitted. I have found the code: Code: [Select] <?php function wwwcopy($link,$file) { $fp = @fopen($link,"r"); while(!feof($fp)) { $cont.= fread($fp,1024); } fclose($fp); $fp2 = @fopen($file,"w"); fwrite($fp2,$cont); fclose($fp2); } //Example on using this function //wwwcopy("http://www.domain.com/list.php?member=sample", "sample.html"); //Another example //wwwcopy("http://www.domain.com/list.php?member=sample2", "sample2.html"); ?> I am using post for my forum (not even sure how get would handle the comments section). How can I use this (or tweak it)? The variables I am passing are $User, $Email, $Title, $Comments, $Date. Would I still use it the same? ie: wwwcopy("http://www.domain.com/forum/new-post.php?User=$User&Email=$Email&Title=$Title&Comments=$Comments&Date=$Date", "X.php");? Also, the value for X is up in the air. I've considered using the auto increment id(index) number from the mySQL database this is saved in. Hi, I have a page with a long list of names (c1000) each with an id. On that page I would like to have a form into which i put the id number, when the form is submitted it will take me to the anchor point for that id. The question I have is, how, when i press submit and reload the page, how can I then have that form input as a anchor in the url that will then take me to the place I want to go on the list when the page loads. I can do it manually no problem by adding the hash tag and id to the url myselft it takes me there but It's a pain to do this every time. I would like to use a form. Is this possible? any help appreciated. Thanks i have my form with 5 fields that are not required to be filled out. Code: [Select] <input class="inputbg" type="text" name="MAC[]" /> <input class="inputbg" type="text" name="MAC[]" /> <input class="inputbg" type="text" name="MAC[]" /> <input class="inputbg" type="text" name="MAC[]" /> <input class="inputbg" type="text" name="MAC[]" /> On my process page I want to remove all of the empty index's that did not have data entered. I am new to sending array data via POST do I need to do anything else other then what is below? Code: [Select] foreach($MAC as $key => $value) { if($value == "") { unset($MAC[$key]); } } $mac_addresses = array_values($MAC); if(empty($mac_addresses)){ $error = "You did not enter any MAC adresses."; $valid = "false"; } Hello fellow PHP Freaks Is there a way to assign mysql access privileges using a php script? Maybe when your registering a user and assign them a role, depending on the role, they get certain privileges on the db... I need help. Thank you in advance. Ok, I need this button here to be a link to /admin.php?edit&id=$userid. I cant get anything after the edit to work. please help: Code: [Select] echo "<form action='admin.php?edit&id=' method='get'><INPUT TYPE='submit' name='submit' VALUE='Edit'></form>\n"; echo "</td><td>";I am pretty sure that this is not complete, but I cant seem to figure it out for some reason... Hi People. I am building a logbook application and have a form field where the user will enter a date. However, I would like to simplify it for the user and give them a button which would add "todays" date into the box for them. Please could someone tell me the code to do so. The date format in my DB is YYYY-MM-DD. The form would also need to take input from the user if they were adding info from a different day instead of today. Thanks in advance. Code: [Select] <input type="text" name="date" id="date" size = "25"/> </label> <input type="submit" name="today" id="today" value="Add Today" /> So I posted something like this a while ago but i didn't get any particularly good answers so I redid it. this is what I have now. It takes clicking the reply three times before it changes changes the form but then after that initial session of reply button clicks it only takes two which is what I want. This is the last thing on my forum (at least till I find some other bug :p) and I need it fixed but I can't figure it out. IT\t wouldn't be a huge issue but the thing is that the first reply you make someone would fill it all in and then press reply then they would lose all their stuff and have to start over before it was submitted, Help please! thanks! Code: [Select] <form action="<?php if ($_SESSION['logged_in'] == '1') { if ((isset($_POST['reply_to_thread'])) && ($_SESSION['reply_has_been_clicked'] != '1')) { echo $this_thread_path; } elseif ((isset($_POST['reply_to_thread'])) && ($_SESSION['reply_has_been_clicked'] == '1')) { $_SESSION['reply_has_been_clicked'] = '0'; $_SESSION['came_from_a_page'] = '1'; echo 'thread_redirect.php'; }}?>" method='post'> <?php if ($_SESSION['logged_in'] == '1') { if ((isset($_POST['reply_to_thread'])) && ($_SESSION['reply_has_been_clicked'] != '1')) { echo '<textarea name="reply_body" cols="75" rows="10" style="resize:none; onKeyUp="limitText(this.form.reply_body,this.form.countdown,5000); onKeyDown="limitText(this.form.reply_body,this.form.countdown,5000);">Enter your reply here...</textarea><br><br><font size="1">(Maximum characters: 5000)<br> You have <input readonly type="text" name="countdown" size="3" value="5000"> characters left.</font><br>'; $_SESSION['reply_has_been_clicked'] = '1'; } } ?> <input type='submit' name='reply_to_thread' value="Reply"> <?php if (isset($_POST['reply_to_thread'])) { if ($_SESSION['logged_in'] != '1') { echo 'You need to be logged in!'; } } ?> </form> This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=347219.0 Ok my question is, when they hit the "Play!" button, then I want the php code below to pop up. Like... i think I would use the GET method, but I'm not sure still. I don't think that really matters what method you use, but how do I say IF they click on the "Play" button, then lead them to this code so they can start playing the game. I'm entering this into the database, but I'm just trying to get this code first. I already know how to make it lead to the database and whatnot. <?php session_start(); include("logincheck.php"); ?> <?php include_once("header.php"); ?> <br> Welcome to the Six Dice game. <br><br><b>Instructions</b>: You play this game by randomly rolling a dice. If you land on 1-5, you earn 0 rp. If you land on a 6, you earn 500rp! The game is free so why not give it a shot? <br>You may only play this game 25 times a day! <br><br><form action="sixdice.php?roll" method="post"> <input type="submit" name="playsix" value="Play!" /> </form> <?php if(isset($_POST['playsix'])); $dice = rand(1,6); echo "You rolled a<br /><b>{$dice}</b>\n"; $winnings = "500"; if($dice == 6) { include("haha.php"); $cxn = mysqli_connect($dbhost,$dbuser,$dbpassword,$dbdatabase); $username = $cxn->real_escape_string($_SESSION['username']); $sql = "UPDATE `Member` SET `rp` = rp+$winnings WHERE `username` = '$username'"; mysqli_query($cxn,$sql); }?> <FORM ACTION="sixdice.php" METHOD="post"> <INPUT TYPE="submit" VALUE="Roll Again!" /> </FORM> <?php include_once("footer.php"); ?> Hello everyone, I have a page with a short form with just a password field and a submit button. I also have php code setting variables depending on whether or not the password is correct. When the password is entered and the submit button is CLICKED, everything works as it should. However, when the password is entered and the ENTER button is pushed to submit the form, the form is reset and nothing else happens. Also, this only happens in I.E., it works fine with Firefox. I have plenty of other forms that I use in the same manner but they all work whether the submit button is clicked or the enter button is pushed to submit, regardless of what browser is used. The idea is to have this window close (it's opened as a pop-up) and the main window load the next page. Again, it works perfectly as long as the submit button is clicked but not if the enter button is pushed. Not sure if it has something to do with my php code or what. Any ideas on how to fix this? Here's my code: Code: [Select] <?php if (isset($_POST['submit'])) { $pword = md5($_POST['pword']); $q = mysql_query("SELECT * FROM `accounts` WHERE acct_number = '$acct' AND pword = '$pword'") or die (mysql_error()); $r = mysql_num_rows($q); // Checks to see if anything is in the db. if ($r == 1) { $student = "true"; } else { $student = "false"; } } else { $student = "unknown"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Student Verification...</title> </head> <!-- <body> tag is in PHP --> <?php if ($student == "true") { echo "<body onunload=\"opener.location=('signup.php?acct1=$acct')\">"; } else { echo "<body>"; } if ($student == "true") { echo "<div align='center'>"; echo "<p><font size='+2'>Passcode Correct!</font></p>"; echo "</div>"; echo "<div align='justify'>"; echo "<p>You will now be directed to the signup page.</p>"; echo "</div>"; echo "<div align='center'>"; echo "<p>Thank you.</p>"; echo "<input type='button' value='Continue to Signup...' onClick='window.close()'>"; echo "</div>"; echo "<meta http-equiv=\"REFRESH\" content=\"20;url=close.php\">"; } elseif ($student == "unknown") { echo "<div align='center'>"; echo "<table width='325' height='175' border='0' cellspacing='0' cellpadding='0'>"; echo "<tr>"; echo "<td width='325' align='center' valign='middle'>"; echo "<p><font size='+1'><strong>Welcome!</strong></font></p>"; echo "<p>Please enter the school passcode.</p>"; echo "<form name='form' method='POST' action='schoolpw.php'>"; echo "<p><input type='password' name='pword' size='30' maxlength='20' /></p>"; echo "<input type='submit' name='submit' id='submit' value='Submit' /> "; echo "<input type='button' name='cancel' value='Cancel' onClick='window.close()' />"; echo "</form>"; echo "</p>"; echo "</td>"; echo "</tr>"; echo "</table>"; echo "</div>"; } elseif ($student == "false") { echo "<div align='center'>"; echo "<table width='325' height='175' border='0' cellspacing='0' cellpadding='0'>"; echo "<tr>"; echo "<td width='325' align='center' valign='middle'>"; echo "<p><font size='+1'><strong>Welcome!</strong></font></p>"; echo "<p><font color='#FF0000'>Incorrect Passcode! Please try again.</font></p>"; echo "<form name='form' method='POST' action='schoolpw.php'>"; echo "<p><input type='password' name='pword' size='30' maxlength='20' /></p>"; echo "<input type='submit' name='submit' value='Submit' /> "; echo "<input type='button' name='cancel' value='Cancel' onClick='window.close()' />"; echo "</form>"; echo "</p>"; echo "</td>"; echo "</tr>"; echo "</table>"; echo "</div>"; } ?> </body> </html> Hey guys! I've looked through this code over and over today, and I still haven;t found where my error is. Here is my entire code: Code: [Select] <?php session_start(); include("config536.php"); ?> <html> <head> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <?php if(!isset($_SESSION['username'])) { echo "<banner></banner><nav>$shownavbar</nav><ubar><a href=login.php>Login</a> or <a href=register.php>Register</a></ubar><content><center><font size=6>Error!</font><br><br>You are not Logged In! Please <a href=login.php>Login</a> or <a href=register.php>Register</a> to Continue!</center></content>"; } if(isset($_SESSION['username'])) { echo "<nav>$shownavbar</nav><ubar>$ubear</ubar><content><center><font size=6>Quest Agency</font><br><br>"; $startjob = $_POST['submit']; $jobq = "SELECT * FROM jobs WHERE username='$showusername'"; $job = mysql_query($jobq); $jobnr = mysql_num_rows($job); if($jobnr == "0") { ?> <form action="<?php echo "$PHP_SELF"; ?>" method="POST"> <input type="submit" name="submit" value="Start Job"></form> <?php } if(isset($startjob)) { $initemidq = "SELECT * FROM items ORDER BY RAND() LIMIT 1"; $initemid = mysql_query($initemidq); while($ir = mysql_fetch_array($initemid)) { $ids = $ir['itemid']; } mysql_query("INSERT INTO jobs (username, item, time, completed) VALUES ('$showusername', '$ids', 'None', 'No')"); $wegq = "SELECT * FROM items WHERE itemid='$ids'"; $weg = mysql_query($wegq); while($wg = mysql_fetch_array($weg)) { $im = $wg['image']; $nm = $wg['name']; $id = $wg['itemid']; } $_SESSION['theid'] = $id; $yeshere = $_SESSION['theid']; echo "<font color=green>Success! You have started this Job!</font><br><br>Please bring me this item: <b>$nm</b><br><br><img src=/images/items/$im><br><br><br>"; } if($jobnr == "1") { $yeshere = $_SESSION['theid']; $finish = $_POST['finish']; $quit = $_POST['quit']; $okgq = "SELECT * FROM items WHERE itemid='$yeshere'"; $ok = mysql_query($okgq); while($ya = mysql_fetch_array($ok)) { $okname = $ya['name']; $okid = $ya['itemid']; $okimage = $ya['image']; } $yeshere = $_SESSION['theid']; echo "Where is my <b>$okname</b>?<br><br><img src=/images/items/$okimage><br><br><br>"; ?> <form action="<?php echo "$PHP_SELF"; ?>" method="POST"> <input type="submit" name="finish" value="I have the Item"><br><br> <input type="submit" name="quit" value="Quit"></form> <?php } } if(isset($finish)) { $yeshere = $_SESSION['theid']; $cinq = "SELECT * FROM uitems WHERE theitemid='$_SESSION[theid]'"; $cin = mysql_query($cinq); $connr = mysql_num_rows($cin); if($connr != "0") { mysql_query("DELETE FROM uitems WHERE username='$showusername' AND theitemid='$yeshere' LIMIT 1"); mysql_query("UPDATE users SET jobs=jobs+1 WHERE username='$showusername'"); mysql_query("UPDATE users SET credits=credits+320 WHERE username='$showusername'"); mysql_query("DELETE FROM jobs WHERE username='$showusername'"); echo "<font color=green>Success! You have completed this job! You have been given <b>320</b> credits as an award. Thank You!</font>"; } else { echo "<font color=red>Error! You do not have my item!</font>"; } if(isset($quit)) { mysql_query("DELETE FROM jobs WHERE username='$showusername'"); echo "<font color=green>Success! You have quit this quest.</font>"; } $yeshere = $_SESSION['theid']; } ?> The variable for the button is: $quit = $_post and I want the quit button to work. Does anybody know why it will not work? Thank you in advance! |
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