PHP - Checkbox Onchange Submit Data Query
Hey phpFreaks, im having some troubles getting my script to work correctly and im also not sure if this issue is in the right section of the forum. but heres what i have going on.
I have a query result that displays a list of images with a checkbox and a couple buttons for edit and delete. everything works fine other than the checkbox stuff. I had it working when i was using a submit button, but i wanted to get rid of that button cuz it was only dealing with the checkboxes. so whats going on when using the checkboxes is that when checked or uncheck it would submit the form. It works to submit but its not submitting any data to the database. heres what i got for code for this section of checkbox. Code: [Select] <?php echo '<form method="post">'; if(isset($_POST['submit'])){ foreach($_POST['id'] as $id){ $value = (isset($_POST['location'][$id]) && $_POST['location'][$id]=="0" ? '0' : '1'); $insert = mysql_query("UPDATE items SET location='$value' WHERE id='$id'") or die('Insert Error: '.mysql_error()); } } $result = mysql_query("SELECT * FROM items") or die("Query Failed: ".mysql_error()); $counter = 0; echo '<div class="specialcontainer">'; while($row = mysql_fetch_array($result)){ list($id, $item_info, $item_img, $price, $sale, $location) = $row; if($location == '0'){ $set_checked = 'checked="checked"'; }else{ $set_checked = ''; } if($counter % 5==0) { echo '</div>'; echo '<div class="specialcontainer">'; } echo '<div class="special"><img src="../images/items/'.$item_img.'" width="130" /><br />'.$item_info.'<br />$'.$price.'<br />$'.$sale.'<br />Slide Show: <input type="checkbox" id='.$id.' value="0" name="location['.$id.']" '.$set_checked.' onchange="this.form.submit()"/><br /><input type="button" value="Edit" name="edit" id="'.$id.'" onclick="window.location.href=\'specials.php?action=edit&id='.$id.'\'"><input type="button" value="Delete" name="Delete" id="'.$id.'" onclick="window.location.href=\'specials.php?action=delete&id='.$id.'\'"><input type="hidden" name="id[]" value='.$id.' /></div>'; $counter++; } echo '</div>'; echo '</form>'; ?> Similar TutorialsThis topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=323252.0 Hi, having problems getting checkboxes to display all reuslts when a user selects more than one check box say in the category section and one in the location section - see page http://www.partyco.co.uk/event-and-party-venues/ - submit to see reults page: I managed to get it to display reults if the user only seletc either a right or left column option OR one of each - BUT not when thet select multiple categories and one location - and ideas how to do this ? putting it into an array perhaps - but how - new to some of this.... here is the code for the reults page: Code: [Select] <?php $location = $_POST[location]; $category = $_POST[category]; ?> <?php $Link = mysql_connect("xxxxxxxxx", "xxxxxxxxx", "xxxxxxxx") or die(mysql_error()); mysql_select_db("xxxxxxxx") or die(mysql_error()); // selects db listings when location not given if (empty($location)) { $query = "SELECT * FROM venues WHERE category = '$category' order by title"; $result = mysql_query($query) or die(mysql_error()); // selects db listings when category not given } elseif(empty($category)) { $query = "SELECT * FROM venues WHERE location = '$location' order by title"; $result = mysql_query($query) or die(mysql_error()); // selects db listings when both given }else { $query = "SELECT * FROM venues WHERE category = '$category' and location = '$location' order by title"; $result = mysql_query($query) or die(mysql_error()); } while($row = mysql_fetch_array($result)){ echo "<div class=\"resultsShort\" style=\"margin-bottom:10px;\">"; echo "<h2 id=\"resultsHeading\">"; echo $row['title']; echo "</h2>"; echo "<p class\"resultspara\">". nl2br($row['description']). "</p>"; echo "<h4 style=\"margin:5px 0 0 0; padding:0;\">Contact details</h4>"; echo "<p class\"resultspara\">". nl2br($row['contact']). "</p>"; echo "<div style=\"float:left; width:124px; height:40px; margin:10px 15px 0 0;\">"; echo "<a href=\"/party-supplier-resources/email-supplier.php?title=". $row['title']. "&email=" . $row['email']. "&location=" . $row['location']. "&category=" . $row['category']. "\" title=\"contact this venue here\">"; echo "<img src=\"/images/email-supplier.jpg\" width=\"124\" align=\"right\" height=\"35\" alt=\"contact this supplier button\" border=\"0\" /></a>"; echo "</div>"; echo "</div>"; } ?> <?php include("../include/shareLinks.php"); ?> <div id="popupContact"> <a id="popupContactClose" title="close this window">close x</a> <h1>Supplier Directory Enquiry Form</h1> <?php include("../include/enquiryform.php"); ?> </div> <div id="backgroundPopup"></div> <?php mysql_close ($Link); ?> Any help appreciated! Aaron MOD EDIT: [code] . . . [/code] BBCode tags added. How can I make my on change in the form pass through the year thats been selected, then use that in the second query? Code: [Select] <select name="mySelect" onchange=""> <?php $result= mysql_query('SELECT DISTINCT Year FROM MonthlySales'); ?> <?php while($row= mysql_fetch_assoc($result)) { ?> <option value="<?php echo htmlspecialchars($row['Year']);?>"> <?php echo htmlspecialchars($row['Year']); ?> </option> <?php } ?> </select> <?php $query="SELECT * FROM MonthlySales WHERE Year = PASS YEAR SELECTED VARIABLE TO THIS BIT HERE"; $results = mysql_query ( $query, $conn); Hello: I have a SELECT dropdown menu that works like this: Code: [Select] <?php $states_arr = array('AL'=>"Alabama",'AK'=>"Alaska",'AZ'=>"Arizona",'AR'=>"Arkansas",'CA'=>"California",'CO'=>"Colorado",'CT'=>"Connecticut",'DE'=>"Delaware",'DC'=>"District Of Columbia",'FL'=>"Florida",'GA'=>"Georgia",'HI'=>"Hawaii",'ID'=>"Idaho",'IL'=>"Illinois", 'IN'=>"Indiana", 'IA'=>"Iowa", 'KS'=>"Kansas",'KY'=>"Kentucky",'LA'=>"Louisiana",'ME'=>"Maine",'MD'=>"Maryland", 'MA'=>"Massachusetts",'MI'=>"Michigan",'MN'=>"Minnesota",'MS'=>"Mississippi",'MO'=>"Missouri",'MT'=>"Montana",'NE'=>"Nebraska",'NV'=>"Nevada",'NH'=>"New Hampshire",'NJ'=>"New Jersey",'NM'=>"New Mexico",'NY'=>"New York",'NC'=>"North Carolina",'ND'=>"North Dakota",'OH'=>"Ohio",'OK'=>"Oklahoma", 'OR'=>"Oregon",'PA'=>"Pennsylvania",'RI'=>"Rhode Island",'SC'=>"South Carolina",'SD'=>"South Dakota",'TN'=>"Tennessee",'TX'=>"Texas",'UT'=>"Utah",'VT'=>"Vermont",'VA'=>"Virginia",'WA'=>"Washington",'WV'=>"West Virginia",'WI'=>"Wisconsin",'WY'=>"Wyoming"); function showOptionsDrop($array){ $string = ''; foreach($array as $k => $v){ $string .= '<option value="'.$k.'"'.$s.'>'.$v.'</option>'."\n"; } return $string; } ?> <form> <select name="states"> <option value="0">Choose a state</option> <?php echo showOptionsDrop($states_arr); ?> </select> </form> I would like to show all the towns/zipcodes for each individual state with an "onchange" from the SELECT menu. The table is called "zip_codes" and the City/Zip Codes are called "city" and "zip" What I would like to do is display them as links, so a user can click into each town and either create a new entry (a restaurant) or update an existing entry. What would be the best approach for this? I appreciate the help. Hello, first time poster.. I've looked the web over for a long time and can't figure this one out. - Below is basic code that successfully checks MySQL for a match and displays result. I was debugging and forced the "height" and "width" to be 24 and 36 to make sure that wasn't the problem. That's good.. - I'd like to give the user ability to select width and height from a form.. and have it do an onchange this.form.submit so the form can be changing as fields are altered (thus the onchange interaction) - In a normal coding environment I've done this numerous times with no "Page cannot be displayed" problems. It would simply change one select-option value at a time til they get down the form and click submit... but in WordPress I'm having trouble making even ONE single onchange work! - I've implemented the plugins they offer which allows you to "copy+paste" your php code directly into their wysiwyg editor. That works with basic tests like my first bullet point above. - I've copied and pasted the wordpress url (including the little ?page_id=123) into the form "action" url... that didn't work... tried forcing it into an <option value=""> tag.. didn't work. I'm just not sure. I've obviously put xx's in place of private info.. Why does this form give me Page Cannot Be Displayed in WordPress every time? It won't do anything no matter how simple.. using onchange.. Code.. $con = mysql_connect("xxxx.xxxxxxx.com","xxxxxx","xxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("xxxxxx", $con); $myprodwidth=24; $myprodheight=36; $result = mysql_query("SELECT * FROM product_sizes WHERE prodwidth='$myprodwidth' and prodheight='$myprodheight'"); while($row = mysql_fetch_array($result)) { echo $row['prodprice']; } mysql_close($con); <form method="post" action=""> <select name="myheight" onchange="this.form.submit();"> <option selected="selected" value="">select height</option> <option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">36</option> <option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">48</option> </select> Say there is a complex opt in process where people start to enter their data but certain questions stop them where they close out of the page. They already entered their data and I feel there is a way to grab it and post it to mysql even though they do not click submit.
How would this be done?
A super simple example (proof of concept) or a link to a tutorial would be very useful.
Edited by brentman, 23 September 2014 - 10:42 AM. i have an html form which is a "post" on it i have an array of checkboxes and a sumbit button, once button is clicked i go to another page where i handle those boxes checked the problem now is if NO checkboxes are checked and i hit the submit...i get errors on the other page my code: foreach($product_names as $product_row) { ?> <tr> <td > </td><td width='200px'><?php echo $product_row->getName(); ?></td> <td width='200px'><input type="checkbox" name="graphic[]" value="<?php echo $product_row->getId();?>" /></td> <td width='200px'><input type="checkbox" name="text[]" value="<?php echo $product_row->getId();?>" /></td> </tr> <?php } ?> </table> <table> <tr> <td> <input type='submit' name='submit' value='Submit'> <?php if ( (isset($graphic)) || (isset($text) )) { echo "checkboxes checked"; //show submit button } else { //hide submit botton and echo "no boxes check"; } ?> the above is NOT working please help???? Which languages do I need to make this happen? And I am unsure of how to incorporate PHP within a javascript query and what jQuery functions I will need. I have been having a bit of difficultly understanding how to submit a single checkbox values for a list of names and saving it in a MySQL database. The way it is meant to work is that a list of names from a table (Table1) is produced on the screen through a query. I have a checkbox that appears beside each individual name and if I tick the box I want it to save the value '1' to the database, otherwise the value remains as zero. When I tick the necessary boxes I wish to save it to another table (Table2, it is separate from Table1). The name and value needs to be saved to it. The problems that arises is how do I save the checkbox value for each individual name? Will I need to use a checkbox array or can I treat each name as independent? Hopefully you understand what I mean. After a few days of searching and running across a problem what is almost like mine on these forums (cant seem to find the link now) where the person was looking to search a database using checkboxes. What I am trying to do is use a list of checkboxes (http://www.animeseason.com/anime-list/categories/) exactly like this link and search my table which has the genres as columns. I am new to PHP and don't really have a starting point. I have taken a bunch of examples and came up with this. My HTML form with a list of all my checkboxes. Code: [Select] <form method="post" ACTION = "php/do_search.php"> <ul class="cat_col"> <li><input type="checkbox" name="cat_check[]" value="1"> <a href="#Action">Action</a></li> <li><input type="checkbox" name="cat_check[]" value="2"> <a href="#Adventure">Adventure</a></li> <li><input type="checkbox" name="cat_check[]" value="3"> <a href="#Comedy">Comedy</a></li> <li><input type="checkbox" name="cat_check[]" value="4"> <a href="#Demons">Demons</a></li> <li><input type="checkbox" name="cat_check[]" value="5"> <a href="#Drama">Drama</a></li> <li><input type="checkbox" name="cat_check[]" value="6"> <a href="#Ecchi">Ecchi</a></li> <li><input type="checkbox" name="cat_check[]" value="7"> <a href="#Fantasy">Fantasy</a></li> <li><input type="checkbox" name="cat_check[]" value="8"> <a href="#Harem">Harem</a></li> <li><input type="checkbox" name="cat_check[]" value="9"> <a href="#Horror">Horror</a></li> <li><input type="checkbox" name="cat_check[]" value="10"> <a href="#Magic">Magic</a></li> <li><input type="checkbox" name="cat_check[]" value="11"> <a href="#Martial Arts">Martial Arts</a></li> <li><input type="checkbox" name="cat_check[]" value="12"> <a href="#Mecha">Mecha</a></li> <li><input type="checkbox" name="cat_check[]" value="13"> <a href="#Music">Music</a></li> </ul> <ul class="cat_col"> <li><input type="checkbox" name="cat_check[]" value="14"> <a href="#Mystery">Mystery</a></li> <li><input type="checkbox" name="cat_check[]" value="15"> <a href="#Ninja">Ninja</a></li> <li><input type="checkbox" name="cat_check[]" value="16"> <a href="#Parody">Parody</a></li> <li><input type="checkbox" name="cat_check[]" value="17"> <a href="#Psychological">Psychological</a></li> <li><input type="checkbox" name="cat_check[]" value="18"> <a href="#Reverse Harem">Reverse Harem</a></li> <li><input type="checkbox" name="cat_check[]" value="19"> <a href="#Romance">Romance</a></li> <li><input type="checkbox" name="cat_check[]" value="20"> <a href="#Samurai">Samurai</a></li> <li><input type="checkbox" name="cat_check[]" value="21"> <a href="#School Life">School Life</a></li> <li><input type="checkbox" name="cat_check[]" value="22"> <a href="#Science Fiction">Science Fiction</a></li> <li><input type="checkbox" name="cat_check[]" value="23"> <a href="#Seinen">Seinen</a></li> <li><input type="checkbox" name="cat_check[]" value="24"> <a href="#Shoujo">Shoujo</a></li> <li><input type="checkbox" name="cat_check[]" value="25"> <a href="#Shounen">Shounen</a></li> <li><input type="checkbox" name="cat_check[]" value="26"> <a href="#Slapstick">Slapstick</a></li> </ul> <ul class="cat_col"> <li><input type="checkbox" name="cat_check[]" value="27"> <a href="#Slice of Life">Slice of Life</a></li> <li><input type="checkbox" name="cat_check[]" value="28"> <a href="#Sports">Sports</a></li> <li><input type="checkbox" name="cat_check[]" value="29"> <a href="#Supernatural">Supernatural</a></li> <li><input type="checkbox" name="cat_check[]" value="30"> <a href="#Thriller">Thriller</a></li> <li><input type="checkbox" name="cat_check[]" value="31"> <a href="#Tragedy">Tragedy</a></li> <li><input type="checkbox" name="cat_check[]" value="32"> <a href="#Vampire">Vampire</a></li> </ul> <ul class="cat_col"> <li><input type="checkbox" name="cat_check[]" value="33"> <a href="#Movie">Movie</a></li> <li><input type="checkbox" name="cat_check[]" value="34"> <a href="#OVA">OVA</a></li> <li><input type="checkbox" name="cat_check[]" value="35"> <a href="#Top Rated">Top Rated</a></li> <li><input type="checkbox" name="cat_check[]" value="36"> <a href="#Currently Airing">Currently Airing</a></li> <li><input type="checkbox" name="cat_check[]" value="37"> <a href="#Ended">Ended</a></li> <li><input type="checkbox" name="cat_check[]" value="38"> <a href="#Ongoing">Ongoing</a></li> </ul> <div id="submit_btn_pos"> <input type="submit" name="search" value="Lets Make Magic" class="submit_btn"> <> </form> My PHP script that right now seems to do nothing. Code: [Select] <?php //if we got something through $_POST if (isset($_POST['cat_check'])) { $con = mysql_connect("localhost","USERNAME","PASSWORD") or die("Connection error"); mysql_select_db("DATABASENAME")or die("database doesn't exist"); // sanitize user input $cleanData = array(); foreach($_POST['cat_check'] as $_comp) { //$cleanData = mysql_real_escape_query($_comp); } // Build query $compStr = implode("'), ('", $cleanData); $sql = "SELECT anime_name WHERE $_comp='1'"; } ?> My database has a layout of "Name of show, (every genere listed above)". Thanks for any help. I was just wondering if it's possible to run a query on data that has been returned from a previous query? For example, if I do Code: [Select] $sql = 'My query'; $rs = mysql_query($sql, $mysql_conn); Is it then possible to run a second query on this data such as Code: [Select] $sql = 'My query'; $secondrs = mysql_query($sql, $rs, $mysql_conn); Thanks for any help i have checkbox in a table and want to put the value as the id in the database then when i press submit it displays all the row data for each checkbox Hi, I want to pull data from db, where sometimes all rows and sometimes rows matching given "username". Here is my code:
//Grab Username of who's Browsing History needs to be searched. if (isset($_GET['followee_username']) && !empty($_GET['followee_username'])) { $followee_username = $_GET['followee_username']; if($followee_username != "followee_all" OR "Followee_All") { $query = "SELECT * FROM browsing_histories WHERE username = \"$followee_username\""; $query_type = "followee_username"; $followed_word = "$followee_username"; $follower_username = "$user"; echo "$followee_username"; } else { $query = "SELECT * FROM browsing_histories"; $query_type = "followee_all"; $followed_word = "followee_all"; $follower_username = "$user"; echo "all"; } }
When I specify a "username" in the query via the url: browsing_histories_v1.php?followee_username=requinix&page_number=1 I see result as I should. So far so good.
Now, when I specify "all" as username then I see no results. Why ? All records from the tbl should be pulled! browsing_histories_v1.php?followee_username=all&page_number=1 This query shouldv'e worked:
$query = "SELECT * FROM browsing_histories";
i want to insert only whats checked to db:) but everything get posted for now i came upwith a for loop but thats for inserting all data not only whats checked any one know a good way to do this? Hi. I want to put data from these checkboxes (example): Jan (value = jan) Chris (value = chris) Tom (value = 50) Jon (unchecked) Put janchris50 to the database after finding correct row with user ID, which is user_id for this example. Then, the user goes to another page and he should see this: Jan (checked) Chris (checked) Tom (checked) Jon (unchecked) In other words - page should get the information from the database and check the checkboxes that appears to be checked in the database. By the way, it should rewrite the row each time, as the user can modify it. Thanks. Hello all I am working on creating a basic ordering form that allow the user to use check-boxes to select certain products and than return a total back to them. I am having a hard time figuring out the php code to gather and calculate things. What I dont quite understand is how to pass the data properly so my $sum calculation actually knows what the values are... In my html doc I have my checkboxes as follows: //formatted in tables <input type = "checkbox" name = "eight100wattreg" size ="40" /> <input type = "checkbox" name = "four100wattreg" size ="40" /> //etc.... and in my php doc: <?php> //get form values $four100wattreg = $_POST["four100wattreg"]; $eight100wattreg = $_POST["eight100wattreg"]; $four100wattlong = $_POST["four100wattlong"]; $eight100wattlong = $_POST["eigth100wattlong"]; $payment = $_POST["payment"]; //set lightbulb values $four100wattreg=2.39; $eight100wattreg=2.39; $four100wattlong=2.39; $eight100wattlong=2.39; //calculate costs if (isset($_POST['four100wattreg']) { //checkbox is checked $four100wattreg = $_POST['four100wattreg']; } else if (!isset($_POST['checkbox']) { //checkbox not checked $four100wattreg = 0; } $sum = $four100wattreg + $eight100wattreg + $four100wattlong + $eigth100wattlong; ?> <?php> echo "Your total is: '$sum' <br />"; ?> I also attached the files if someone wants to look at them in they're entirety. Any advice would be greatly appreciated, but please keep in mind I am a php beginner and am still learning. Thanks, Charlie helo does anyone know how to display data from db in checkbox form? i have been searching for days and still cannot find answer that i can understand. i hope someone can help me. i really am lost. any help is much appreciated Hey I have checkbox and when the user tick one or more box these should be stored as 0 or 1 but since its while loop, I am not sure how to work that out. So far I have <html> <?php session_start(); include '../Database/connection.php'; $Value24 = mysql_real_escape_string(trim($_POST['myselect'])); $_SESSION['smodule'] = $Value24; ?> <body> <form action="Test_Completed.php" method="post"> <?php $query = mysql_query(" SELECT * FROM Test WHERE Tes_ID = '{$_SESSION['smodule']}' "); while( $query1 = mysql_fetch_array($query) ) { echo "Test Name: {$query1['Tes_Name']}"; } ?> <br> <?php $query = mysql_query(" SELECT * FROM User WHERE Use_ID = '{$_SESSION['ssubject']}' "); while( $query1 = mysql_fetch_array($query) ) { echo "User Name: {$query1['Use_Name']}"; } ?> <br> <?PHP include '../Database/take_an_exam.php'; $intNumber = 1; while($info = mysql_fetch_array( $sql )) { echo "$intNumber, {$info['Que_Question']} <br />\n"; echo "<input type=\"checkbox\" name=\"choice1[]\" value=\"{$info['Que_Choice1']}\" /> "; echo "{$info['Que_Choice1']} <br />\n"; echo "<input type=\"checkbox\" name=\"choice2[]\" value=\"{$info['Que_Choice2']}\" /> "; echo "{$info['Que_Choice2']} <br />\n"; echo "<input type=\"checkbox\" name=\"choice3[]\" value=\"{$info['Que_Choice3']}\" /> "; echo "{$info['Que_Choice3']} <br />\n"; echo "<input type=\"checkbox\" name=\"choice4[]\" value=\"{$info['Que_Choice4']}\" /> "; echo "{$info['Que_Choice4']} <br />\n"; $intNumber++; } ?> <input type="submit" value="submit"/> </body> </html> </body> </html> <?PHP $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Examination", $con); //Get & clean value from POST data $choice1 = mysql_real_escape_string(trim($_POST['choice1'])); $choice2 = mysql_real_escape_string(trim($_POST['choice2'])); $choice3 = mysql_real_escape_string(trim($_POST['choice3'])); $choice4 = mysql_real_escape_string(trim($_POST['choice4'])); $user = mysql_real_escape_string(trim($_SESSION['username1'])); //Create and run INSERT query $query = "INSERT INTO Answer (`Ans_Answer1`, `Ans_Answer2`, `Ans_Answer3`, `Ans_Answer4`, `Que_ID`, `Use_ID`) VALUES ('{$choice1}', '{$choice2}', '{$choice3}', '{$choice4}', '{$query1}', '{$user}')"; $result = mysql_query($query) or die (mysql_error()); $_SESSION['Ans_ID'] = mysql_insert_id(); header("location:check.php"); ?> I've been poking around online for about a day now trying to find a good way to do the following: I have an "order" I'm reading in from a MySQL database (not completely relevant, but just fyi). And, for this order there are a number of "parts" (automotive parts) that have been ordered. For each part there is data pertaining to the quantity of parts that have been ordered and the number of parts that have been allocated (based on our inventory) and then a third column that has the number of parts still in that order that are still to be allocated at a future date. Basically, I'm displaying this data in a form with each row having a checkbox to the far left. What I want to do is allow the user to check any number of check boxes. If a check box is checked the form should submit all of the input text boxes for that row (the user can update the quantities) that I talked about in the second paragraph for that "part" (each part is displayed in a row and has a checkbox). Unfortunately, most of the examples I found for checkboxes in a form submit a specific value (like a number of a letter). I need the form to submit the values that are in the textboxes. So basically, I'm thinking I need the page to update a PHP object whenever the value of a textbox is changed and then when the user clicks a button it will send the php object for each checked row through GET or POST. But, how would I get it to onchange update a PHP object (the PHP object would need to be a 2-D array where the first index allows you to select the part and the second index allows you to select which quantity you will change). I'm thinking I would need to call a script from the onchange like: onchange="somePHPfunction(partNumberIndex, whichQuantityI'mChanging, currentValueOfThatQuantity)" but of course that would require me to embed some php inside the onchange call since the partNumberIndex and whichQuantity are PHP variables.. Any ideas on how to do this sort of thing? Or any ideas on how to do this differently? I'm trying to avoid javascript because it would place a javascript constraint on the users. But, maybe there's no other way to do this sort of thing? Any help would be greatly appreciated! |