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PHP - Giving Me A List Of C's And More Then The Amount I Gave It.
So I wrote this piece of code that for the most part works. The problem is two things. One if I print out say $dir[$i] I get 7 directories back. if I try and store that in an array to later be access by some other function I get up to 24+ C's instead of C:/Path...
Code: [Select] public function aisis_get_dir_array($dir){ if(!is_array($dir)){ aisis_get_dir($dir); return; } $count = count($dir); for($i = 0; $i<$count; $i++){ if(!is_dir($dir[$i])){ _e('Specified dir' . $dir[$i] . 'is not a directory.'); } $this->directory_list = $dir[$i]; //store these $handler = opendir($dir[$i]); while($file = readdir($handler)){ if($file != "." && $file != ".."){ $this->files[] = $file; } } } return $this->files; } right under the line: $this->directory_list = $dir[$i]; //store these if You put in echo $dir[$i] you get back directories. How ever down in this function: Code: [Select] public function load_if_extentsion_is_php($dir, $array = false){ $list = array(); $list_dir = array(); if($array == true){ $list = $this->aisis_get_dir_array($dir); $list_dir = $this->directory_list; } else{ $list = $this->aisis_get_dir($dir); } $count = count($list); for($i = 0; $i<$count; $i++){ if($array == true){ $countdir = count($this->directory_list); for($j = 0; $j<$countdir; $j++){ echo $list_dir[$j]; //echo $list_dir[$j]; //echo $list[$i]; } } //if(substr(strrchr($list[$i],'.'),1)=="php"){ //echo $list[$i]; //require_once($dir . $list[$i]); //} } } echoing out: echo $list_dir[$j]; gets you up to 24+ C's instead of the directories that are stored. You can view the whole class at Paste bin - there is an expiry: 12 hours. Essentially you call load_if_extentsion_is_php($dir, $array = false) pass it an array of directories and set the array part to true. To Summarize: If you pass in an array of directories you should get back: a echoed list of directories a echoed list of php files belonging in those directories. Currently you get the later and a series of C's for the first. Why? Similar TutorialsHi, I would like users to be able to send me payments though my website, but where they enter their own amount. I know this can be done using donations, but I do not want the word "donate" or "donations" to appear anywhere in the transaction. Can this be done at all? Heres what i got... function printLB1 (){ $result = mysql_query("SELECT * FROM leaderboards ORDER BY CollegeFootballPoints DESC"); while ($row = mysql_fetch_object($result)) { $leaderboard[] = $row->Username; $leaderboardPoints[] = $row->CollegeFootballPoints; } $num = mysql_num_rows($reault); //I know from here to ................... needs to be in a var or echo or something. <tr> <td>1.</td> //This will auto increment too like i++ but i cna do that myself! <td>echo $leaderboard;</td> <td>echo $leaderboardPoints;</td> </tr> //Here......................................................... } I need to pull a table row per user. But i want to somehow do it once in a function and then ill echo the function into a table after the php stuff is done. Like i want to pull every a table row per user in the function. then display the function below that way i don't have to write a whole extra query and table row per person. If you understand please help if not please let me know where i can explain more. Thanks Hi, Look at this code below: Code: [Select] <?php function outputModule($moduleID, $moduleName, $sessionData) { if(!count($sessionData)) { return false; } $markTotal = 0; $markGrade = 0; $weightSession = 0; $grade = ""; $sessionsHTML = ""; foreach($sessionData as $session) { $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} <strong>Session Mark:</strong> {$session['Mark']}</strong> <strong>Session Weight Contribution</strong> {$session['SessionWeight']}%</p>\n"; $markTotal += round($session['Mark'] / 100 * $session['SessionWeight']); $weightSession += ($session['SessionWeight']); $markGrade = round($markTotal / $weightSession * 100); if ($markGrade >= 70) { $grade = "A"; } else if ($markGrade >= 60 && $markGrade <= 69) { $grade = "B"; } else if ($markGrade >= 50 && $markGrade <= 59) { $grade = "C"; } else if ($markGrade >= 40 && $markGrade <= 49) { $grade = "D"; } else if ($markGrade >= 30 && $markGrade <= 39) { $grade = "E"; } else if ($markGrade >= 0 && $markGrade <= 29) { $grade = "F"; } $moduleHTML = "<p><br><strong>Module:</strong> {$moduleID} - {$moduleName} <strong>Module Mark:</strong> {$markTotal} <strong>Mark Percentage:</strong> {$markGrade} <strong>Grade:</strong> {$grade} </p>\n"; return $moduleHTML . $sessionsHTML; } $output = ""; $studentId = false; $courseId = false; $moduleId = false; while ($row = mysql_fetch_array($result)) { if($studentId != $row['StudentUsername']) { //Student has changed $studentId = $row['StudentUsername']; $output .= "<p><strong>Student:</strong> {$row['StudentForename']} {$row['StudentSurname']} ({$row['StudentUsername']})\n"; } if($courseId != $row['CourseId']) { //Course has changed $courseId = $row['CourseId']; $output .= "<br><strong>Course:</strong> {$row['CourseId']} - {$row['CourseName']} <strong>Course Mark</strong> <strong>Grade</strong> <br><strong>Year:</strong> {$row['Year']} </p>\n"; } if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } //Get output for last module $output .= outputModule($moduleId, $moduleName, $sessionsAry); //Display the output echo $output; } } } ?> This code allallows me to make calculations and display a student's course and linked with it the course the modules in the course and linked with modules are all the sessions. It is able to display what marks each student have got for each module and session. Now look at code below, it is able to display modules and in those modules the sessions that link to those modules: Code: [Select] <?php if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } What I want to know is how can I do something similar for course so that it picks out the right modules depending on the course it displays. There maybe some code that needs to be added in the function. Hello Everyone, I am working on a project where I have to go in and grab the names of the fields in a table. I got it to work and for it to show me the field names but it also displays a lot more than what I would like for it to do. I keep getting the following error. It is repeated over my screen like 15 times. Quote Warning: mysql_field_name() [function.mysql-field-name]: Field 5 is invalid for MySQL result index 7 in C:\xampp\htdocs\CMS\admin\includes\get_table.php on line 44 This is the section of code that it is referring to. Line 44 is Quote $tablecolumn .= "<p>" . mysql_field_name($fieldnamesquery_result, $table_field) . "<input type='text' name='" . mysql_field_name($fieldnamesquery_result, $table_field) . "' id='" . mysql_field_name($fieldnamesquery_result, $table_field) . "'/>"; Code: [Select] $tablecolumn = "<form name='insert_table' id='insert_table' action='get_database.php' method='post' > <fieldset> <legend>table information</legend>"; for ($table_field = 2; $table_field < $fieldnamesquery_result; $table_field++) { $tablecolumn .= "<p>" . mysql_field_name($fieldnamesquery_result, $table_field) . "<input type='text' name='" . mysql_field_name($fieldnamesquery_result, $table_field) . "' id='" . mysql_field_name($fieldnamesquery_result, $table_field) . "'/>"; <-----This is line 44 } $tablecolumn .= " <p> <input type='submit' name='submit_info' id='submit_info' /> </p> </fieldset> </form> "; echo $tablecolumn; Hello everyone. I am wondering how can i give different id's to a html form? Code: [Select] <?php ... if ($numrows!=0) { // fetching data from the database to variable while ($row = mysql_fetch_assoc($query)) { $view_jam = $row['jamname']; $view_recipe = $row['jamrecipe']; $view_rating = $row['jamrate']; $view_owner = $row['owner']; $view_comments = $row['comments']; $view_count = $row['count']; $view_id = $row['id']; $view_count2 = $row['count2']; echo "Jam name: <b>" . $view_jam . "</b><br />"; echo "Jam recipe: " . $view_recipe . "<br />"; echo "Owner: " . $view_owner . "<br />"; echo "Comments: " . $view_comments . "<br />"; echo "Jam Rating: " . $view_rating . "<br />"; [b]echo '<form action="main.php?id=jams" method="POST">[/b] Choose rating <input type="text" name="jamrate" /> <input type="submit" name="submit1" value="Rate"> </form><br /><br />'; ... ?>As you can see, the form is inside a loop. I am trying to build a rating system. When there is only one row in a database then everything goes smoothly, but if there are more, then the rating applies to all rows. I suppose i need to give different id's to the form. How? Thank you Error: Code: [Select] No error, Im have trouble Having This Loop Select Only 2 Uploads At a Time. Code: Code: [Select] <?php //porperties $result = mysql_query("SELECT * FROM uploaded"); while($r=mysql_fetch_array($result)) { $link=$r["link"]; $name=$r["name"]; $type=$r["type"]; $size=$r["size"]; $date=$r["date"]; $id=$r["id"]; echo " The File $name Was Currently Updated<br> Size: $size<br> Type: $type<br> Date Updated: $date<br> Link: <a href='$link'>Download</a><br><br> "; } ?> Couldn't Think of a Good name For this,Sorry Code: [Select] ${$payment['amount']} using the $ next to it doesn't work I am using itinside double quotes, any way I can get that dollar sign right next to it? This for people buying stuff off my forum i want the amount to show right by the $ dollar sign And im working inside double quotes only What I can Do: Code: [Select] function createDir($path = '/path/to/root/') What I Need To Do: Something like this Code: [Select] $server_root = $_SERVER['DOCUMENT_ROOT']; function createDir($path = $server_root) Or This Code: [Select] function createDir($path = $_SERVER['DOCUMENT_ROOT']) Code: [Select] $Rep = htmlspecialchars($_GET["Rep"]); echo $Rep; The above will print "John Doe & Assoc." (without the quotes) Code: [Select] $result = mysql_query("SELECT RepName FROM Reps WHERE Repname = '".$Rep."'"); $repcount = mysql_num_rows($result); echo $repcount; The above code prints "0" If I delete the first block of code and replace it with Code: [Select] $Rep = "John Doe & Assoc." The second block of code will then return a "1" as it should. Why is one returning a 0 and one returning a 1 when the text in $Rep appears to be identical in both cases? This problem only appears to be occurring when the $Rep value contains an &. All, I'm getting the following error when I work with a class: Parse error: syntax error, unexpected T_STRING, expecting T_OLD_FUNCTION or T_FUNCTION or T_VAR or '}' in /webspace/httpdocs/offers/form_key.php on line 5 The complete code for this is class is: <?php class Form_Key { protected $oldKey; public function __construct() { // Ensure we have an available session if ( NULL == session_id() ) { session_start(); } // Grab our former key for validation if ( isset( $_SESSION['form_key'] ) ) { $this->oldKey = $_SESSION['form_key']; } // Assign the new key $_SESSION['form_key'] = md5( uniqid( mt_rand(), TRUE ) ); } public function isValid() { return 'POST' == $_SERVER['REQUEST_METHOD'] && isset( $_POST['form_key'] ) && '' != trim( $_POST['form_key'] ) && '' != trim( $this->oldKey ) && $_POST['form_key'] === $this->oldKey; } public function getKey() { return $_SESSION['form_key']; } public function getOldKey() { return $this->oldKey; } public function render() { return '<input type="hidden" name="form_key" value="' . $_SESSION['form_key'] . '" />'; } public function __toString() { return $this->render(); } } ?> The line that is giving the issue is this line: protected $oldKey; Is it ok just to remove this line?? If I comment it out it gives me the same message but for line 7, which is this one: public function __construct() Anyone have any ideas? Thanks in advance. My code looks as follows: include('connectvars.php'); /* REGISTER FORM */ // check if submit button has been clicked if (isset($_POST['submit_signup'])) { // process and assign variables after post submit button has been clicked $user_email = strip_tags(trim($_POST['email'])); $firstname = strip_tags(trim($_POST['firstname'])); $lastname = strip_tags(trim($_POST['lastname'])); $nickname = strip_tags(trim($_POST['nickname'])); $password = $_POST['password']; $repassword = $_POST['repassword']; $dob = $_POST['dob']; $find_us_question = strip_tags(trim($_POST['find_us_question'])); // connect to database $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $check_query = "SELECT * FROM users WHERE nickname = '$nickname'"; $check_connect = mysqli_query($dbc, $check_query); $check_count = mysqli_num_rows($check_connect); echo $check_count; die(); It's a register (sign up) page, and it's the beginning of the script, the rest of the script is just checking if all fields are a empty and if the input is in the allowed character length etc. I could it off at die(); because the rest doesn't matter. I want the script to check if the username already exists in the database, so I want mysqli_num_rows to tell me how many rows are already there with the same username, and then I want to continue doing an if statement saying if ($check_count != 0) { echo "Username already exists!" } But the mysqli_num_rows doesn't even print out how many rows there are availible, it gives me an error saying: Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in... The num_rows function worked in the login script the same way, but for some reason it's not working in the register script. Any ideas, what I'm doing wrong? For testing purposes I just want it to print me "1" when I'm entering a username that's already in the database. Hi all, Here's the code I'm using, after opening an IMAP stream to an inbox. The code previous to this opens the inbox, grabs the emails and iterates through them. This bit is checking an individual mail for attachments. Code: [Select] <?php $structure = imap_fetchstructure($mbox, $email_number); $parts = $structure->parts; $fpos=2; for($i = 1; $i < count($parts); $i++) { $message["pid"][$i] = ($i); $part = $parts[$i]; if($part->disposition == 'ATTACHMENT') { // Save the attachment locally to the server // Find the file extension // Save the attachment to DB code here $fpos+=1; } } ?> When I run the script, I get a load of the following reply: Notice: Undefined property: stdClass::$parts in /var/www/html/site/public_html/cron/cron_email_import.php on line XXX Would this mean that there are no actual attachments in the email being processed? Has anyone ever dealt with this function before? All input appreciated. WoolyG Okay, I have a healing spell that allows people to regain stats when it's cast. But, how do I limit it so that they can't go over their maxhp? Here's what I have so far: $db->execute("UPDATE `users` SET `hp`=?, `mp`=?, `energy`=? WHERE `id`=?", array($player->hp + $healspell, $player->mp - $spell['mp'], $player->energy - $spell['energy'], $player->id)); What do I need to do in this to tell it to limit it to the maxhp but never going over it? $healspell is a random number, so it is quite possible to go over the maxhp at the moment. Thank you! If I knew what to call it I could have searched it. So I will just explain. I have a form that is pulling from a database to build the following. echo <input name='$row[id]' type='text' id='$row[id]' size=2>; This will build a page that has this <input name='22' type='text' id='22' size=2> <input name='54' type='text' id='54' size=2> This part works great. The problem is when I try to add it to the database. How can I insert variables that I don't know the names of? They will be something like $_POST[22] $_POST[54] and so on. I hope someone can understand my jibberish. I am sure there is a WAY better way to do this. Hi All, Im new to this forum but think its going to be a regular location for me for quite a while. Im very very new to php and the guy that was doing code for me is not responding to emails, so i thought id have a go myself...lol at the moment im going through the trial and error phase while learning. I have edited some of the code he has put on the site to create a new look. the original page: http://www.ridersguide.co.uk/county_accommodation.php?county=4; the one im trying:http://www.ridersguide.co.uk/county_accommodation2.php?county=4; The new bit is to add a preview of the text for the page. echo $row[ad_text]; the code above brings up all the text but i only want to show the first 4 or 5 lines. Is this possible in php? Any help appreciated Neil I have a field in my database called description. How can I echo out only 500 out of the 2000 max characters? Like for example: Code: [Select] $query = mysql_query("SELECT description FROM `servers` ORDER BY votes DESC LIMIT 5"); If I were to echo out the value of description for the database, how can I only echo out the first 500 characters? Hey quick question on my homepage there is a featured content section, which is populated from my DB some of the posts are really long so I would like to limit the amount of text. how can I do this? also is there a way to make sure if does not cut a word in half? thanks Hi, I have a database where I store times with the Now(); function. What I want is: When the viewer looks at the post, instead of it saying: Posted: 2010-11-14 19:08:14, I want it to say posted: x hours ago, Posted: x days ago, etc. Any help with this would be appreciated! Hi,
I have a text area field on one of my forms in order for people to post articles, however, it doesn't work when I try and post HTML through it. It works if I post normal text. Also, PHP won't give me an error, it just doesn't insert it?
<?php
if ($_POST['add']) {
$title = addslashes($_POST['title']);
$image = htmlspecialchars($_POST['image']);
$source = mysql_real_escape_string($_POST['source']);
$active = $_POST['active'];
$feature = $_POST['feature'];
$cat_id = $_POST['cat_id'];
$content = htmlspecialchars($_POST['content']);
$months = array(
"",
"January",
"February",
"March",
"April",
"May",
"June",
"July",
"August",
"September",
"October",
"November",
"December"
);
$date = date('d', time()) . ' ' . $months[date('n', time())] . ' ' . date('Y', time());
if ($title == NULL || $image == NULL || $content == NULL) {
echo '<br /><br /><center>Please, fill all inputs</center><br /><br />';
} else {
$add = "INSERT INTO `news` cat_id='$cat_id', title='$title', image='$image', content='$content', date='$date', author='".$user['admin']."', authorid='".$user['id']."', source='$source', active='$active', twitter='".$user['twitter']."', featured='$feature'" or die(mysql_error());
$sql = mysql_query($add);
$addgrowl = "INSERT INTO `growl` (toid, message) VALUES ('$id', 'Your article is now online!')";
$sql = mysql_query($addgrowl);
echo '<script type="text/javascript">
window.location = "articles.php"
</script>
';
}
}
?>
Help :-(
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