|
PHP - Displaying Results Of Many Sql Queries Without Writing Php Code?
am total newbie to programming, apart from knowing SQL, the thing is i have been given a MYSQL database containing various information about kids diseases and a web interface written in php to create reports from the database that can be accessed via the interface. there are almost 25 different variables that need to be computed in the report, i have written sql queries to compute all these values, but i don't know anything about PHP, if i have all these queries isn't there a way for me to combine all these sql queries to be display results on a webpage and come up with this report without writing PHP code?
Thanks for your help very sorry if this is too basic Similar TutorialsHey guys, Having a slight problem with part of the code in my index.php file Code: [Select] mysql_select_db('db_name', $con); $result = mysql_query("SELECT * FROM spy ORDER BY id desc limit 25"); $resulto = mysql_query("SELECT * FROM spy ORDER BY id desc"); $count = mysql_num_rows($resulto); while($row = mysql_fetch_array($result)) { ?> <div class="contentDiv">Someone is looking at <?=$row[title];?> Stats for "<a href="/<?=$row[type];?>/<?=$row[code];?>/<?=$row[city];?>"><?=$row[code];?> <?=$row[city];?></a>"</div> <?}?> </div> <div id="login"></div> <? include("footer.php"); ?> </div> </body> </html> I'm getting the following error when viewing the file Code: [Select] Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in ~path to file/index.php on line 70 Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in ~path to file/index.php on line 71 where lines 70 and 71 are $count = mysql_num_rows($resulto); while($row = mysql_fetch_array($result)) Any ideas on how to fix this? Complete beginner here so just really looking for pointers on where to start. Been doing a bit of bug fixing on one of our sites because the past 3 programmers we've hired have disappeared on us. The big issue I'm looking to solve is the load time of a search. Our website (Love-Rugs) is taking about 6 or 7 seconds to perform a blank search (basically a quick browse) whereas out other site (Little-Persia) takes about a second. It wouldn't be so bad if it was just the initial search but going from one page (only 10 products listed per page) to the next takes the same amount of time. There seems to be an awful lot of queries (around 130-150) on the searches - however - when using some of the search options e.g. type and fabric to refine the search the queries actually stay high but the time to process the results is reduced significantly. I don't really understand why if the queries are still high the search time is much lower unless it's to do with the number of results returned. However this does not explain why Little-Persia (which has far more products on it) takes less time as there would obviously be more results. I realize that without code this isn't easy to answer so I'm just looking to see if someone can point me in the right direction to look at just now. Hello I have a question. I'm trying to perform multiple queries based off the results from a query. Is this possible ? $result = mysql_query("SELECT id FROM sometable"); for each id returned $result1 = mysql_query("SELECT * FROM someothertable WHERE id=result from $result query"); Any help would be GREAT hi I have 2 tables (members & friendship) Members table columns: -------------------------------------------- username | password | email | etc .... -------------------------------------------- Person 1 xxxxxx x@x.com person 2 yyyyyy y@y.com Friendship columns: --------------------------------------- username | friend | status | --------------------------------------- person 1 person 2 friends person 2 person 1 friends person 1 person 3 pending I want to query the friendship table: "SELECT friend FROM friendship WHERE username ='$_SESSION['myusername'];' AND status='friends' " (so its basically getting the user names of anyone who is the logged in users friend) And then use the returned user names to select their data from the members table. Any help much appreciated! ^.^ I need to check if in databaseA (shown below as applicant) it says "PendingGroupA" if yes echo "something" and if not to check databaseB (shown below as comp) for the username and password. Then upon successful username and password entry echo "message B". And if username and password fails to echo "message C". How can I write this correctly? $result=mysql_query("SELECT * FROM comp WHERE username = '$useid' AND pass ='$pass'"); if(mysql_num_rows ($result) == 0) { $login = "&err=Login Failed. Please retry."; echo($login); } elseif { $row = mysql_fetch_array($result); $user=$row['user']; $pass=$row['pass']; $login = "$user=" . $user . "$pass=" . $pass . "&err=Login Successful."; echo($login); } else { $resultA=mysql_query("SELECT * FROM applicant WHERE username = '$useid' AND statusA ='PendingGroupA'"); $peningGA = "&err=Please be patient!"; echo($peningGA); } Hello, Im trying to display some results from mysql database, however none display. Can anyone tell me where im going wrong please? Code: [Select] </head><body> <div id="listhold"> <div class="list"> <a href="Restaurants.html">Restaurants</a><br /> <?php mysql_connect("","",""); mysql_select_db("") or die("Unable to select database"); $result = mysql_query("SELECT name FROM business WHERE type ='restaurant' ORDER BY name"); $number_of_results = mysql_num_rows($result); $results_counter = 0; if ($number_of_results != 0) {while ($array = mysql_fetch_array($result)) $results_counter++; if ($results_counter >= $number_of_results);} ?> </div> I have a PHP while loop that pulls from an SQL database and displays the contents in a table with two columns.
// Check Connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Select Data Table
$result = mysqli_query($con,"SELECT * FROM Recommendations") or die(mysqli_error);
// Split Data
$mid = ceil(mysqli_num_rows($result)/2);
// Display Content
while ($rows = mysqli_fetch_array($result)) {
$Name = $rows['Name'];
$Author = $rows['Author'];
$Cover = $rows['Link to Cover'];
$Link = $rows['Link to Profile'];
echo "<table><tr><td>
<a href='" . $Link . "' >$Name</a>
<br />
$Author
<br />
<a href='" . $Link . "' ><img src='" . $Cover . "' /></a>
</td>
<td>
<a href='" . $Link . "' >$Name</a>
<br />
$Author
<br />
<a href='" . $Link . "' ><img src='" . $Cover . "' /></a>
</td></tr></table>";
}
?>
I want to be able to display the looped results side by side in columns of two.
Example:
1 2
3 45 6 I've tried using pseudo classes to display only the even and odd results in the different table columns, but honestly have no idea how to do this. I'm new to PHP, so my apologies if the results are really obvious. Thanks in advance! I'm realitivly new to PHP and was hoping somebody could help. I have a mysql database that stores information about books. I am currently using the code below to query the database and extract the 3 most recent entries and showing them in a dynamic list: Code: [Select] $sql = mysql_query("SELECT * FROM products ORDER BY date_added DESC LIMIT 3"); $productCount = mysql_num_rows($sql); if ($productCount > 0) { // ensure a book exists while($row = mysql_fetch_array($sql)){ $id = $row["id"]; $title = $row["title"]; $author = $row["author"]; $price = $row["price"]; $date_added = strftime("%b %d, %Y", strtotime($row["date_added"])); $dynamiclist .= //My table showing the products } } else { $dynamicList = "There are currently no Books listed in this store"; } This works well when showing the most recent books 1 below the other. However, I would like to show these products side by side, horizontally across the page. Can somebody please point me in the right direction? Many thanks I'm trying to create a list that groups information by username. Only part of it is working. The first query ($get_item_sql) is grouping the information perfectly but the second query ($get_sold) is lumping the $item_price and $item_amount_due as one total for each one and outputting the same amounts into every username. I'm stuck on this and would appreciate your help. For example: Username item fees image fees item sales item price total due Jim 2 $0.40 $100.00 $3.00 $3.40 Kelly 5 $1.00 $100.00 $3.00 $4.00 This example shows the columns in red as being the problem where Kelly didn't sell anything so her "item sales" and "item price" should be $0.00 but is carrying Jim's totals into hers. Hope this helps! Thank you! $get_item_sql = mysql_query("SELECT id, username, date, ROUND(price,2) AS price, SUM(item_fee) AS fee, item_fee, SUM(sold) AS sales, SUM(ROUND(price,2)) AS total FROM product WHERE MONTH(date) = MONTH(DATE_ADD(CURDATE(),INTERVAL -1 MONTH)) GROUP BY username" ) or die(mysql_error()); if (mysql_num_rows($get_item_sql) < 1) { //invalid item $display_block .= "<p><em>Invalid item selection.</em></p>"; } else { //valid item, get info while ($item_info = mysql_fetch_array($get_item_sql)) { $item_username = $item_info['username']; $item_date = $item_info['date']; $item_price = $item_info['price']; $item_fee = $item_info['fee']; $image_fees = $item_fee * .20; $item_sold = $item_info['sales']; $get_sold = mysql_query("SELECT SUM(ROUND(price,2)) AS total, SUM(ROUND(sold,2)) AS sales, date, username FROM product WHERE sold = '1' AND MONTH(date) = MONTH(DATE_ADD(CURDATE(),INTERVAL -1 MONTH)) GROUP BY username") or die(mysql_error()); if (mysql_num_rows($get_sold) < 1) { //invalid item $display_block .= "<p><em>Invalid item selection.</em></p>"; } else { //valid item, get info while ($item_sold2 = mysql_fetch_array($get_sold)) { $item_sales = $item_sold2['total']; $item_price = ($item_sold2['total']) * .03; $item_amount_due = $image_fees + $item_price; $content .= "<form action=\"add_artist.php\" method=\"post\"><table class=\"anotherfont\" width=\"670\" border=\"0\"> <tr><td width=\"201\">{$item_username}</td> <td width=\"109\">{$item_fee}</td> <td width=\"109\">{$image_fees}</td> <td width=\"109\"> {$item_sales}</td> <td width=\"109\"> {$item_price}</td> <td width=\"109\"><input name=\"balance_due\" type=\"text\" value=\"{$item_amount_due}\" /></td> </tr><br /></table></form>"; } } } } Dear all, I am new in this forum. This is my code $query = " SELECT webdb.id, webdb.writer, writer.picLoc, webdb.title FROM webdb, writer WHERE webdb.writer=writer.name and category = 'Researchworks' and language = 'Farsi' ORDER BY writer DESC"; $resultaat = mysql_query($query, $LinkID); $column_count = mysql_num_fields($resultaat) or die (mysql_error()."<br>Couldn't execute query: $SQLquery"); $counter=1; echo "<table border=\"0\" width=\"700\" border color=white><tr>"; while ($row = mysql_fetch_row($resultaat)) { if ($author !== $row[1]) { $author = $row[1]; echo "<td align=right width=220 valign=top style=\"margin: 5px; float: right border-bottom-color:#000; border-left-color:#000;\">"; echo "<img width=\"50\" height=\"80\" src=\"admin/writers/$row[2]\" border =\"0\"><br>".$row[1]."<br>"; echo "<a href=\"poems.php?writer=$row[1]\">".$row[3]."</a><br>"; echo "</td>"; if($counter%3==0) { echo"</tr><tr>"; } $counter++; } } echo"</tr></table>"; i have authors with different articles on a certain topic. What i want is, displaying the name of the author only once and all his titles under his name. I also want a dynamic table where i display three authors in each row and soon as there a fourth author a new row must start. My problem now is is the title is also being filtered and i can only display one title. Thanks in advance Alright so I'm attempting to save config data via php. Bellow is the code I currently have, however I'm afraid that when I "flip the switch" and use it that it will error out because of the <?php and ?> tags inside of it... Ideas, suggestions? $config = '../includes/config.php'; $fh = fopen($config, 'w'); $data = ' <?php $dbhost = "'.$database_host.'"; $dbuser = "'.$database_username.'"; $dbpass = "'.$database_password.'"; $dbname = "'.$database_name.'"; $key = "'.$site_key.'"; $cron_key = "'.$database_cron_key.'"; ?> '; fwrite($fh, $data); fclose($fh); Hi everyone. I'm stuck on the following query. I need to display all the fields listed below on a page, but linked via communications.CommID. I'd appreciate any assistance you can provide. thank you. Code: [Select] <?php $result = mysql_query("SELECT records.NameFirst_1, records.NameLast_1, records.CompanyName, records.CompanyBranch, records.CompanyReferenceNumber, records.CaseOwnerSelect, communications.ConversionType, communications.Contact, communications.ContactFrom, communications.CommID, communications.ContactPosition, communications.ContactTelephone, communications.ContactEmail, communications.ContactFax, communications.CallDate, communications.CallTime, communications.ActionTextField FROM records INNER JOIN communications ON records.IDNumber = '$IDNumber'") or die(mysql_error()); $row = mysql_fetch_array($result); ?> Hi I have got results being displayed after clicking the search button in a form on my home page but it brings up all the results which is ok but how do I get onlt the results a user searches for for example a location or property type etc as its for a property website The coding is below for the results page Also sorry how do I add a background image to the php page, I tried using css but wouldn't work Code: [Select] <style type="text/css"> body {background-image:url('images/greybgone.png');} </style> <?php mysql_connect ("2up2downhomes.com.mysql", "2up2downhomes_c","mD8GsJKQ") or die (mysql_error()); mysql_select_db ("2up2downhomes_c"); echo $_POST['term']; $sql = mysql_query("select * from properties where typeProperty like '%$term%' or location like '%$term%'"); while ($row = mysql_fetch_array($sql)){ echo 'Type of Property: '.$row['typeProperty']; echo '<br/> Number of Bedrooms: '.$row['bedrooms']; echo '<br/> Number of Bathrooms: '.$row['bathrooms']; echo '<br/> Garden: '.$row['garden']; echo '<br/> Description: '.$row['description']; echo '<br/> Price: '.$row['price']; echo '<br/> Location: '.$row['location']; echo '<br/> Image: '.$row['image']; echo '<br/><br/>'; } ?> Hello Everyone was wondering if I could get some help with the following code? I am querying a database for results of listings that are in a database these listings are displayed on the page in a form. I am wanting each listing to be on a different page. Below is my code. Code: [Select] $lim=1; if (!isset($s) || $s < 1 || !is_numeric($s)) { $s = 1; } $start = ($s - 1) * $lim; $sql = "select id,bussimg,imagewidth,imageheight,email,usridm,company,businesscategory,address1,address2,state,city,zip,website,email,repname,description,phonenumber,country,status from $approvecheckbusinesses where usridm='$user_id'"; $result=db_query($sql); $countpages = $sql; $sql = $sql . " order by id asc limit $start, $lim"; $result=db_query($sql); $pages = ceil(mysql_num_rows(mysql_query($countpages)) / $lim); $result=db_query($sql); for ($i = 0; $i < mysql_num_rows($result); $i++) { $Listid= mysql_result($result, $i, "id"); $usridm= mysql_result($result, $i, "usridm"); $CompanyName= mysql_result($result, $i, "company"); $realname= mysql_result($result, $i, "repname"); $email= mysql_result($result, $i, "email"); $BusinessCategory= mysql_result($result, $i, "businesscategory"); $status= mysql_result($result, $i, "status"); echo ("FORM IS TO BE DISPLAYED HERE"); } if ($pages > 1) { echo("<p align=left style='font-size: 85% color=white'>"); for ($i = 1; $i <= $pages; $i++) { echo("["); if ($i == $s) {echo("<b>");} else {echo("<a id=home_offerLink href='index.html?EditMemberListing&user_id=$user_id&s=$i'>");} echo("Page $i"); if ($i == $s) {echo("</b>");} else {echo("</a>");} echo("] "); } echo("</p>") Page Numbers here using the above code.. The problem I seem to be running into is that it only displats the first record. The page numbers show up page 1 page 3 page 2 and three are blank there is no mysql error or anything for some reason I only get that first result out of three I'm trying to pull results from a database based on where the user is located based upon the variables $usr_lat & $usr_lng, and search for by a radius of x amount of miles/km (need to make it optional). I can't seem to find exactly what I'm looking for on google so I thought I'd asked here. Any help would be appreciated.
Code: [Select] <?php $result = mysql_query("SELECT * FROM FamilyTbl INNER JOIN PeopleTbl ON (FamilyTbl.Name_ID = PeopleTbl.NameID) WHERE FamilyTbl.House_ID = '$address' ORDER BY NameLast, NameFirst ") OR die(mysql_error()); WHILE ($row = mysql_fetch_array($result) ) { echo $row[NameLast]. ", ". $row[NamePrefix]. " ". $row[NameFirst]. " ". $row[NameMiddle]. $row[NameSuffix]. " "; } ?> OK, some of these queries return A LOT of names. I'd like to be able to display them in columns in a table like so: Code: [Select] Charne, Mr. Michael Glanger, Mrs. Karin Kling, Mr. Wayne Charne, Mrs. Suzette Glanger, Mr. Trevor Lazarow, Mrs. Fiona Charney, Mrs. Linda Jochelson, Mrs. Barbara Lazarow, Mr. Mark Charney, Mr. Norman Jochelson, Mr. Neil Norton, Mr. Charles Cohen, Mr. Brendan Karlan, Mr. Dennis Norton, Mrs. Jodi Cohen, Mrs. Joanna Karlan, Mrs. Helen Roy, Mr. Michael Flekser, Mrs. Jean Kling, Mrs. Danielle Roy, Mrs. Nicki Frysh, Dr. Howard Kling, Mrs. Melanie Tsafrir, Mrs. Lauren Frysh, Mrs. Sandra Kling, Mr. Nevil Tsafrir, Mr. Thomer That way it reads top to bottom THEN left to right. math-wise, it's simple to set up: Code: [Select] $num_results = number_of_$results; $numcols = 3; $numrows = trunc($numresults/numcols); <table> for row_loop=1 to numrows <tr> for col_loop = 1 to numcols <td> echo result(col_loop-1)*(numrows)+row_loop </td> next col_loop </tr> next row_loop </table> Anyone want to give this a shot? Revraz already directed me to http://www.phpfreaks.com/forums/index.php/topic,95426.0.html but that displayed the data from left to right then up to down like so: Code: [Select] Charne, Mr. Michael Charne, Mrs. Suzette Charney, Mrs. Linda Charney, Mr. Norman Cohen, Mr. Brendan Cohen, Mrs. Joanna Flekser, Mrs. Jean Frysh, Dr. Howard Frysh, Mrs. Sandra Glanger, Mrs. Karin Glanger, Mr. Trevor Jochelson, Mrs. Barbara Jochelson, Mr. Neil Karlan, Mr. Dennis Karlan, Mrs. Helen Kling, Mrs. Danielle Kling, Mrs. Melanie Kling, Mr. Nevil Kling, Mr. Wayne Lazarow, Mrs. Fiona Lazarow, Mr. Mark Norton, Mr. Charles Norton, Mrs. Jodi Roy, Mr. Michael Roy, Mrs. Nicki Tsafrir, Mrs. Lauren Tsafrir, Mr. Thomer It's a good temp solution, but if anyone is good with for loops, I'd appreciate the help, thanks! -Dave Hi, fairly new to PHP over the last couple weeks. Been having a problem with certain queries. I have a database with football results, games, teams etc. I can filter these using drop down and that's all well and good. The problem I'm having is displaying the data via gameweek. I've been asked to display the table like so - Gameweek1 will display week1 teams, results etc. Gameweek2 will display week2... and so on.
I can manage to do this in a drop down. But I've been asked to display this using links like "Previous, 1, 2, 3 Next". I've tried pagination but I couldn't figure it out. Can anyone point me in the right direction? If I need a GET() method, how would I go about coding that so it will be used in a link(s)? Been searching and searching to find an answer but to no avail...
//Database connection etc...
$gameweek = "SELECT * FROM games WHERE gameweek= 1";
//if(isset($_GET['gameweek']))
//{
// $gameweek = $_GET['gameweek'];
//
//}
//....
$result=mysqli_query($connection, "select * from games WHERE gameweek= 1");
//Print table and table headings...
mysqli_close($connection);
?>
<a href="http://weeks.php?gameweek=2">Week 2</a>
<a href="http://weeks.phpgameweek=3">Week 3</a>
</body>
</html>
I would like assistance in displaying a company name in my web search results.
Below is my code:
<html>
<head></head>
<body>
<?php if (!isset($_POST['q'])) { ?>
<img src="/wvb-logo-slogen.png" border="0" />
<h2>Search</h2>
<form method="post" action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>">
<input type="text" name="q" size="30" />
</form>
<?php } else { ?>
<img src="/wvb-logo-slogen.png" border="0" />
<h2>Search Results</h2>
<?php
try {
// create object
// $swish = new Swish('/usr/local/apache/htdocs/swish/index.swish-e');
$swish = new Swish('/var/www/html/pdf2/index.swish-e');
// get and run query from command-line
$queryStr = htmlentities($_POST['q']);
$result = $swish->query($queryStr);
?>
Found <?php echo $result->hits; ?> match(es) for '<?php echo $queryStr; ?>'.
<?php
// iterate over result set
// print details for each match
while($r = $result->nextResult()) {
?>
<p>
<?php echo $r->swishreccount; ?>
<strong>
<a href="<?php echo '/pdf2', ltrim($r->swishdocpath, '.') ; ?>">
<?php echo $r->swishdocpath; ?>
</a>
</strong> (sco <?php echo $r->swishrank; ?>) <br/>
<?php echo $r->swishdocpath; ?><br />
<?php
//Split a filename by .
$filenames = explode(".", $r->swishdocpath);
//get 3 chars from $filenames to $country
$country = substr($filenames[1],1,3);
echo 'Country name: '.$country."<br />";
//$filenames[2] = explode(".", $r->swishdocpath);
$year = substr($filenames[2],0,4);
echo 'Year: '.$year;
//$filenames = explode(".", $r->swishdocpath);
$wvbnumber = substr($filenames[1],1,12);
echo 'WVB Number: '.$wvbnumber;
?>
</p>
<?php
}
} catch (Exception $e) {
die('ERROR: ' . $e->getMessage());
}
}
?>
</body>
</html>
As you can see I am able now display the WVB number, country name and year. But my question to anyone is how would I display the company name that it corresponds to?The names of the company are located in a .csv file called active_colist.csv and it is under the /var/www/html directory. This is what my /var/www/html directory looks like: [root@zeus wvbadmin]# cd /var/www/html [root@zeus html]# ls -l total 2140 -rw-r--r--. 1 root root 2110323 May 14 23:39 active_colist.csv -rw-r--r--. 1 root root 6678 Apr 30 13:25 favicon.ico -rw-r--r--. 1 root root 17256 May 5 16:02 h1 -rw-r--r--. 1 root root 113 Apr 29 16:45 hello.php -rw-r--r--. 1 root root 19 Apr 24 23:53 info.php drwxr-xr-x. 2 root root 12288 May 12 15:30 pdf2 lrwxrwxrwx. 1 root root 20 May 5 15:46 pdf3 -> /home/wvbadmin/pdf3/ -rw-r--r--. 1 root root 1227 May 6 16:33 pdfsearch2.php -rw-r--r--. 1 root root 1204 May 6 15:13 pdfsearch3.php -rw-r--r--. 1 root root 1625 May 19 23:27 pdfsearch.php -rw-r--r--. 1 root root 1838 Apr 30 13:10 search.php -rw-r--r--. 1 root root 10077 May 12 11:38 wvb-logo-slogen.png What is in the .csv file is the first 12 characters that correspond to the company name. What PHP code would I use to grab the first 12 characters of search results match them up with what is in the .csv file and display the proper company name? This is what is inside of the .csv file: WVB_NUMBER,PRIMARY_SHORT_COMPANY_NAME,CURR_ISO_CNTRY_OF_INCORP "AIA000030001","THE NATIONAL BANK OF ANGUILLA","AIA" "AIA000030003","ANGUILLA ELECTRICITY COMPANY","AIA" "AIA000030005","KMT-HANSA","AIA" "ALB000040001","BURSE E TIRANES","ALB" "ANT000020000","RORENTO","ANT" "ANT000030001","INTRUM JUSTITIA","SWE" "ANT000030002","ORTHOFIX INTERNATIONAL","ANT" "ANT000030004","HAL TRUST","ANT" "ARE000030001","MASHREQBANK","ARE" "ARE000030002","COMMERCIAL BANK OF DUBAI","ARE" Any assistance would be greatly appreciated. |
|||||||