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PHP - Another Image Re-sizer Question
Ok I have seen many posts on this script and many people asking question on this site. The script can be found.....
http://www.white-hat-web-design.co.uk/blog/resizing-images-with-php/ However I still can not make it work with what I have got. So here is the problem. First of all I upload the image and save the name to the database. I then pass its ID to the next page to retrieve the image and its path from the database. This is where the script comes in. I then run the image through the script and send you to the success page. Now the image is not being resized! The code is not erroring (even with error reporting on). It would seem the code it just get ignored completely. The image is still there and displays how it was uploaded but the size just hasnt changed. Im asuming Im using it in the correct way. Here is the code after the image has been uploaded. $Fetchq = mysql_query("SELECT * FROM images WHERE imageID ='".$_GET['image']."' ") or die('error stuff here'); $fetched = mysql_fetch_array($Fetchq); $path = "/members/images/members/merseyside/{$fetched['imagename']}"; include('SimpleImage.php'); $image = new SimpleImage(); $image->load('$path'); $image->resize(60,60); $image->save('$path'); $url = "/activity-photos.php?uploaded=true"; header("Location: $url"); Any help would be greatly appreciated as I've had enough of banging my head against this code wall Similar TutorialsI am not sure whether this is an appropriate question for this forum but am hoping it might be. I have an image and intend to create a number of image maps of it so that readers can click on various parts of the image and then get a document coming up inviting them to write their thoughts about that part of the image. I am wondering whether it is possible, once they have written down their thoughts, for what they have written then to be superimposed on the image where the image map is? Thanks. How can I make the image path not have the starting slash for the $path? Currently this... Code: [Select] function getUserAvatar($username) { if (file_exists("{$GLOBALS['path']}/img/${username}.png")) { return "/assets/img/${username}.png"; } else { return "/assets/img/defaultuser.jpg"; } } When path is executed I need it to make /assets/ be assets/ I need to remove the first character from the $path variable. if ($type === 'image/png'){ imagepng($this->img, $path); } OK, I think this is easy, but I just can't seam to get it figured out. I have this piece of code echo '<img src="maps/' . $map . '.jpg" />'; And what I want to do is if that $map is not in the directory I want it to display a standard image that I know is in the directory. So basically I want the alt tag to be a image instead of text. Hello Everybody
I usually work with C#, but I'm doing a website right now and have a question:
I want a picture in my header and when I change the window size the image may not move.
My code so far:
#a1 {
position: relative;
top:-175px; left:0px; width:50px; height:50px;
background-image:url(http://domain.png);
background-repeat:no-repeat;}
</style>
Hope someone can answer this question easyHi guys, Here is what I have so far: http://www.autoshopgarage.com/new-era/generate.php What I am trying to do is instead of having Line 1 and Line 2, I want to just have one big textarea so I don't have to limit the user so much. I did it this way because I want to have two versions of text, the light version and the bold version. Is it possible to have two different fonts with just one textarea of text? Right now I have two functions: Quote ImageTTFText($image, $fontSize, $fontRotation, 435, 80, $color, $font1, wordwrap($first, 18, "\n", true)); ImageTTFText($image, $fontSize, $fontRotation, 485,120, $color_black, $font2, wordwrap($last, 18, "\n", true)); So I would limit that to just 1, and it would automatically wordwrap but what would I put for the $font variable? Is this even possible? I was thinking of just using BBCode so they could type in [b*]Bold Text[/b*] and it would use the Bold version of the font if it sees that. Any help is appreciated. Thanks! Here is the full code: Quote <?php $first = $_GET['first']; $last = $_GET['last']; $font_color = $_GET['color']; header("Content-type: image/png"); $image = imagecreatefrompng ( "banner_blank.png" ); $color_black = imagecolorallocate($image, 0, 0, 0); $color_red = imagecolorallocate($image, 255, 0, 0); if($font_color == "Red") { $color = $color_red; } elseif($font_color == "Black") { $color = $color_black; } $font1 = 'HelveticaNeueLTStd-BdEx.ttf'; $font2 = 'HelveticaNeueLTStd-LtEx.ttf'; $fontSize = "21"; ImageTTFText($image, $fontSize, $fontRotation, 435, 80, $color, $font1, wordwrap($first, 18, "\n", true)); ImageTTFText($image, $fontSize, $fontRotation, 485,120, $color_black, $font2, wordwrap($last, 18, "\n", true)); imagepng ( $image ); imagedestroy ( $image ); ?> when in a form, I wish to build a conditional that if the response to a radio button is a value of 2 (female), it will display an input requesting for users maiden name. If not 2 goes to the next input statement. Here is code I was experimenting with: <html> <body> <form action="" name="test" method='POST'> <input type="radio" id="sex" value=1 checked><label>Male</label> <input type="radio" id="sex" value=2><label>Femaleale</label> <?php $result = "value"; if ($result == 2) echo "<input type='int' id='gradYear' size='3' required>"; else echo "Not a female!" ?> <input type="submit" value="GO"> </form> </body> </html> The code passes debug, however, Not a Female is displayed. My question is - Can I do this and if so, what value do I test against id='sex' or value. I tried each one but gave the same results. I realize that $_POST[sex] would be used after the submit button is clicked. But this has me stumped. Thanks for the assis in advance. How can i edit just one image at on time with a multiple image upload form? I have the images being stored in a folder and the path being stored in MySQL. I also have the files being uploaded with a unique id. My issue is that I want to be able to pass the values of what is already in $name2 $name3 $name4 if I only want to edit $name1. I don't want to have to manually update the 4 images. Here is the PHP: Code: [Select] <?php require_once('storescripts/connect.php'); mysql_select_db($database_phpimage,$phpimage); $uploadDir = 'upload/'; if(isset($_POST['upload'])) { foreach ($_FILES as $file) { $fileName = $file['name']; $tmpName = $file['tmp_name']; $fileSize = $file['size']; $fileType = $file['type']; if ($fileName != ""){ $filePath = $uploadDir; $fileName = str_replace(" ", "_", $fileName); //Split the name into the base name and extension $pathInfo = pathinfo($fileName); $fileName_base = $pathInfo['fileName']; $fileName_ext = $pathInfo['extension']; //now we re-assemble the file name, sticking the output of uniqid into it //and keep doing this in a loop until we generate a name that //does not already exist (most likely we will get that first try) do { $fileName = $fileName_base . uniqid() . '.' . $fileName_ext; } while (file_exists($filePath.$fileName)); $file_names [] = $fileName; $result = move_uploaded_file($tmpName, $filePath.$fileName); } if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); $filePath = addslashes($filePath); } $fileinsert[] = $filePath; } } $mid = mysql_real_escape_string(trim($_POST['mid'])); $cat = mysql_real_escape_string(trim($_POST['cat'])); $item = mysql_real_escape_string(trim($_POST['item'])); $price = mysql_real_escape_string(trim($_POST['price'])); $about = mysql_real_escape_string(trim($_POST['about'])); $fields = array(); $values = array(); $updateVals = array(); for($i = 0; $i < 4; $i++) { $values[$i] = isset($file_names[$i]) ? mysql_real_escape_string($file_names[$i]) : ''; if($values[$i] != '') { $updateVals[] = 'name' . ($i + 1) . " = '{$values[$i]}'"; } } $updateNames = ''; if(count($updateVals)) { $updateNames = ", " . implode(', ', $updateVals); } $update = "INSERT INTO image (mid, cid, item, price, about, name1, name2, name3, name4) VALUES ('$mid', '$cat', '$item', '$price', '$about', '$values[0]', '$values[1]', '$values[2]', '$values[3]') ON DUPLICATE KEY UPDATE cid = '$cat', item = '$item', price = '$price', about = '$about' $updateNames"; $result = mysql_query($update) or die (mysql_error()); Hi, I've read a lot of places that it's not recommended to store binary files in my db. So instead I'm supposed to upload the image to a directory, and store the link to that directory in database. First, how would I make a form that uploads the picture to the directory (And what kinda directories are we talking?). Secondly, how would I retrieve that link? And I guess I should rename the picture.. I'd appreciate any help, or a good tutorial (Haven't found any myself). The script for creating a new file name for the image:
$validextensions = array("jpeg", "jpg", "png"); //Extensions which are allowed
$ext = explode('.', basename($_FILES['file']['name'][$i]));//explode file name from dot(.)
$file_extension = end($ext); //store extensions in the variable
$new_image_name = md5(uniqid()) . "." . $ext[count($ext) - 1];
$target_path = $target_path . $new_image_name;//set the target path with a new name of image
The script creates a new file like:
f6c9b8d9db05366c3504210cded9ddb2.jpgand moves the file to the "uploads" folder. And then the script also creates a thumbnail with the same file name and moves the file to the "thumbs" folder. The issue I am having is that the same ID code could happen again for a different image in the database, thus I would be calling a different original sized image than the thumbnail image. My question is: How to avoid this issue of the same ID code has happened again for a different file. What is the proper way to reference the anchor tag of the thumbnail image to its actual original sized image? With the script I have the thumbnail image would be coming from the "thumbs" folder and the anchor tag would get referenced to the "uploads" folder to get the original sized image. Edited by glassfish, 12 October 2014 - 05:51 AM. After image is drop into container , I want to move copy of the original image to be move when original image dragend within container. I tried but it display copy image each time when original image dragend. can anyone help me?
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Prototype</title>
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<script src="http://d3lp1msu2r81bx.cloudfront.net/kjs/js/lib/kinetic-v4.7.2.min.js"></script>
<script src="http://code.jquery.com/ui/1.9.2/jquery-ui.min.js"></script>
<style>
body{padding:20px;}
#container{
border:solid 1px #ccc;
margin-top: 10px;
width:350px;
height:350px;
}
#toolbar{
width:350px;
height:35px;
border:solid 1px blue;
}
</style>
<script>
$(function(){
var $house=$("#house");
$house.hide();
var $stageContainer=$("#container");
var stageOffset=$stageContainer.offset();
var offsetX=stageOffset.left;
var offsetY=stageOffset.top;
var stage = new Kinetic.Stage({
container: 'container',
width: 350,
height: 350
});
var layer = new Kinetic.Layer();
stage.add(layer);
var image1=new Image();
image1.onload=function(){
$house.show();
}
image1.src="http://vignette1.wikia.nocookie.net/angrybirds/images/b/b6/Small.png/revision/latest?cb=20120501022157";
$house.draggable({
helper:'clone',
});
$house.data("url","house.png"); // key-value pair
$house.data("width","32"); // key-value pair
$house.data("height","33"); // key-value pair
$house.data("image",image1); // key-value pair
$stageContainer.droppable({
drop:dragDrop,
});
function dragDrop(e,ui){
var x=parseInt(ui.offset.left-offsetX);
var y=parseInt(ui.offset.top-offsetY);
var element=ui.draggable;
var data=element.data("url");
var theImage=element.data("image");
var image = new Kinetic.Image({
name:data,
x:x,
y:y,
image:theImage,
draggable: true,
dragBoundFunc: function(pos) {
return {
x: pos.x,
y: this.getAbsolutePosition().y
}
}
});
image.on("dragend", function(e) {
var points = image.getPosition();
var image1 = new Kinetic.Image({
name: data,
id: "imageantry",
x: points.x+65,
y: points.y,
image: theImage,
draggable: false
});
layer.add(image1);
layer.draw();
});
image.on('dblclick', function() {
image.remove();
layer.draw();
});
layer.add(image);
layer.draw();
}
}); // end $(function(){});
</script>
</head>
<body>
<div id="toolbar">
<img id="house" width=32 height=32 src="http://vignette1.wikia.nocookie.net/angrybirds/images/b/b6/Small.png/revision/latest?cb=20120501022157"><br>
</div>
<div id="container"></div>
</body>
</html>
Edited by Biruntha, 08 January 2015 - 10:14 AM. This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=351137.0 Can I get some help or a point in the right direction.
I am trying to create a form that allows me to add, edit and delete records from a database.
I can add, edit and delete if I dont include the image upload code.
If I include the upload code I cant edit records without having to upload the the same image to make the record save to the database.
So I can tell I have got the code processing in the wrong way, thing is I cant seem to see or grasp the flow of this, to make the corrections I need it work.
Any help would be great!
Here is the form add.php code
<?php require_once ("dbconnection.php");
$id="";
$venue_name="";
$address="";
$city="";
$post_code="";
$country_code="";
$url="";
$email="";
$description="";
$img_url="";
$tags="";
if(isset($_GET['id'])){
$id = $_GET['id'];
$sqlLoader="Select from venue where id=?";
$resLoader=$db->prepare($sqlLoader);
$resLoader->execute(array($id));
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Add Venue Page</title>
<link href='http://fonts.googleapis.com/css?family=Droid+Sans' rel='stylesheet' type='text/css'>
<link rel="stylesheet" href="//maxcdn.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css">
<script src="//maxcdn.bootstrapcdn.com/bootstrap/3.2.0/js/bootstrap.min.js"></script>
</head>
<body>
<div class="container">
<?php
$sqladd="Select * from venue where id=?";
$resadd=$db->prepare($sqladd);
$resadd->execute(array($id));
while($rowadd = $resadd->fetch(PDO::FETCH_ASSOC)){
$v_id=$rowadd['id'];
$venue_name=$rowadd['venue_name'];
$address=$rowadd['address'];
$city=$rowadd['city'];
$post_code=$rowadd['post_code'];
$country_code=$rowadd['country_code'];
$url=$rowadd['url'];
$email=$rowadd['email'];
$description=$rowadd['description'];
$img_url=$rowadd['img_url'];
$tags=$rowadd['tags'];
}
?>
<h1 class="edit-venue-title">Add Venue:</h1>
<form role="form" enctype="multipart/form-data" method="post" name="formVenue" action="save.php">
<input type="hidden" name="id" value="<?php echo $id; ?>"/>
<div class="form-group">
<input class="form-control" type="hidden" name="id" value="<?php echo $id; ?>"/>
<p><strong>ID:</strong> <?php echo $id; ?></p>
<strong>Venue Name: *</strong>
<input class="form-control" type="text" name="venue_name" value="<?php echo $venue_name; ?>"/><br/>
<br/>
<strong>Address: *</strong>
<input class="form-control" type="text" name="address" value="<?php echo $address; ?>"/><br/>
<br/>
<strong>City: *</strong>
<input class="form-control" type="text" name="city" value="<?php echo $city; ?>"/><br/>
<br/>
<strong>Post Code: *</strong>
<input class="form-control" type="text" name="post_code" value="<?php echo $post_code; ?>"/><br/>
<br/>
<strong>Country Code: *</strong>
<input class="form-control" type="text" name="country_code" value="<?php echo $country_code; ?>"/><br/>
<br/>
<strong>URL: *</strong>
<input class="form-control" type="text" name="url" value="<?php echo $url; ?>"/><br/>
<br/>
<strong>Email: *</strong>
<input class="form-control" type="email" name="email" value="<?php echo $email; ?>"/><br/>
<br/>
<strong>Description: *</strong>
<textarea class="form-control" type="text" name="description" rows ="7" value=""><?php echo $description; ?></textarea><br/>
<br/>
<strong>Image Upload: *</strong>
<input class="form-control" type="file" name="image" value="<?php echo $img_url; ?>"/>
<small>File sizes 300kb's and below 500px height and width.<br/><strong>Image is required or data will not save.</strong></small> <br/><br/>
<strong>Tags: *</strong>
<input class="form-control" type="text" name="tags" value="<?php echo $tags; ?>"/><small>comma seperated vales only, e.g. soul,hip-hop,reggae</small><br/>
<br/>
<p>* Required</p>
<br/>
<input class="btn btn-primary" type="submit" name="submit" value="Save">
</div>
</form>
</div>
</body>
</html>
Here is the save.php code
<?php
error_reporting(E_ALL);
ini_set("display_errors", 1);
include ("dbconnection.php");
$venue_name=$_POST['venue_name'];
$address=$_POST['address'];
$city=$_POST['city'];
$post_code=$_POST['post_code'];
$country_code=$_POST['country_code'];
$url=$_POST['url'];
$email=$_POST['email'];
$description=$_POST['description'];
$tags=$_POST['tags'];
$id=$_POST['id'];
if(is_uploaded_file($_FILES['image']['tmp_name'])){
$folder = "images/hs-venues/";
$file = basename( $_FILES['image']['name']);
$full_path = $folder.$file;
if(move_uploaded_file($_FILES['image']['tmp_name'], $full_path)) {
//echo "succesful upload, we have an image!";
var_dump($_POST);
if($id==null){
$sql="INSERT INTO venue(venue_name,address,city,post_code,country_code,url,email,description,img_url,tags)values(:venue_name,:address,:city,:post_code,:country_code,:url,:email,:description,:img_url,:tags)";
$qry=$db->prepare($sql);
$qry->execute(array(':venue_name'=>$venue_name,':address'=>$address,':city'=>$city,':post_code'=>$post_code,':country_code'=>$country_code,':url'=>$url,':email'=>$email,':description'=>$description,':img_url'=>$full_path,':tags'=>$tags));
}else{
$sql="UPDATE venue SET venue_name=?, address=?, city=?, post_code=?, country_code=?, url=?, email=?, description=?, img_url=?, tags=? where id=?";
$qry=$db->prepare($sql);
$qry->execute(array($venue_name, $address, $city, $post_code, $country_code, $url, $email, $description, $full_path, $tags, $id));
}
if($success){
var_dump($_POST);
echo "<script language='javascript' type='text/javascript'>alert('Successfully Saved!')</script>";
echo "<script language='javascript' type='text/javascript'>window.open('index.php','_self')</script>";
}
else{
var_dump($_POST);
echo "<script language='javascript' type='text/javascript'>alert('Successfully Saved!')</script>";
echo "<script language='javascript' type='text/javascript'>window.open('index.php','_self')</script>";
}
} //if uploaded
else{
var_dump($_POST);
echo "<script language='javascript' type='text/javascript'>alert('Upload Recieved but Processed Failed!')</script>";
echo "<script language='javascript' type='text/javascript'>window.open('index.php','_self')</script>";
}
} //move uploaded
else{
var_dump($_POST);
echo "<script language='javascript' type='text/javascript'>alert('Successfully Updated.')</script>";
echo "<script language='javascript' type='text/javascript'>window.open('index.php','_self')</script>";
}
?>
Thanks in advance!
Edited by hankmoody, 12 August 2014 - 05:15 PM. Hello, Five images will be displayed inside a division. There will be a previous and next button/link. If someone click the next button the next image will be added in that div and the first image will be gone from that div. The previous button/link will do the same thing. Is it possible with php? I am confused if it's a javascript or ajax question. Thanks. Hello I am having problems uploading an image through a HTML form. I want the image to be uploaded to the server and the image name to be written to the mysql database. Below is the code I am using: Code: [Select] <?php if (isset($_POST['add'])){ echo "<br /> add value is true"; $name = $_POST['name']; $description = $_POST['description']; $price = $_POST['price']; $category_id = $_POST['category_name']; $image = $_FILES['image']['name']; //file path of the image upload $filepath = "../images/"; //mew name for the image upload $newimagename = $name; //new width for the image $newwidth = 100; //new height for the image $newheight = 100; include('../includes/image-upload.php'); mysql_query("INSERT INTO item (item_name, item_description, item_price, item_image) VALUES ('$name','$description','$price','$image')"); ?> Here is the image-upload.php file code: Code: [Select] <?php //assigns the file to the image $image =$_FILES["image"]["name"]; $uploadedfile =$_FILES["image"]["tmp_name"]; if ($image) { //retrieves the extension type from image upload $extension = getextension($image); //converts extension to lowercase $extension = strtolower($extension); //create image from uploaded file type if($extension=="jpg" || $extension=="jpeg") { $uploadedfile = $_FILES['image']['tmp_name']; $src = imagecreatefromjpeg($uploadedfile); }else if($extension=="png") { $uploadedfile = $_FILES['image']['tmp_name']; $src = imagecreatefrompng($uploadedfile); }else{ $src = imagecreatefromgif($uploadedfile); } //creates a list of the width and height of the image list($width,$height)=getimagesize($uploadedfile); //adds color to the image $tmp = imagecreatetruecolor($newwidth,$newheight); //create image imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height); //set file name $filename = $filepath.$newimagename.".".$extension; $imagename = $newimagename.".".$extension; //uploads new file with name to the chosen directory imagejpeg($tmp,$filename,100); //empty variables imagedestroy($src); imagedestroy($tmp); } ?> Any help would be appreciated, fairly new to all this! Thanks!!! Hello, I've had success creating a cool vanity QR code with rounded edges for my organization by generating a standard QR code, then applying a noise -> median effect in Photoshop to get the edges rounded among some other effects. Photoshop is great, but I want to automate this. I found a great PHP library to generate QR codes. The part I don't get is the rounding of the hard edges. I've seen other sites do it like this one. So far google searches are yielding rounded corner tutorials. Any thoughts on how to do this with GD or ImageMagic? Best regards, Chris Would like to be able to click on a radio button that represents an image. Once selected and submitted, have that image display on another page. I have an idea, but need some guidance. BTW, is using php only doable? Is there a simpler or more elegant way to do this? Thanks all! Hey guys, I am making a quotes siggy, code: <?php /** * @author Jragon * @copyright 2010 */ $textfile = "quotes.txt"; $quotes = array(); if (file_exists($textfile)) { $quotes = explode("\n", file_get_contents($textfile)); srand((float)microtime() * 10000000); $string = $quotes[array_rand($quotes)]; $string = wordwrap($string, 100, "\n", true); text_to_image($string, 800); } else { $string = "Sig file non-existant..."; } function text_to_image($text, $image_width, $colour = array(0, 244, 34), $background = array(0, 0, 0)) { $font = 5; $line_height = 15; $padding = 2; $text = wordwrap($text, ($image_width/10)); $lines = explode("\n", $text); $image = imagecreate($image_width, ((count($lines) * $line_height)) + ($padding * 2)); $background = imagecolorallocate($image, $background[48], $background[44], $background[44]); $colour = imagecolorallocate($image, $colour[0], $colour[1], $colour[2]); imagefill($image, 0, 0, $background); $i = $padding; foreach ($lines as $line) { imagestring($image, $font, $padding, $i, trim($line), $colour); $i += $line_height; } header("Content-type: image/jpeg"); imagejpeg($image); imagedestroy($image); exit; } ?> What i want it to do is have the lines the same legnth, and when a quote is smaller the image to shrink. Thanks jragon hello friends, while clicking the form all the information goes to database, I have one image upload field, when cliking the submit button, i would like 'image name' to go in database and file to go in /upload folder, i have tried this for hours and gave up, if anyone help me in this, i would be very greatful This resizer works fine except I would like it to save the original image AND the thumbnail. Right now its only saving the cropped thumbnail. It's seems simple enough but I've tried several different ways but can't get it to work. :( I would appreciate your help. :) define( 'DESIRED_IMAGE_WIDTH', 150 ); define( 'DESIRED_IMAGE_HEIGHT', 150 ); $source_path = $_FILES[ 'thumb' ][ 'tmp_name' ]; $timestamp = time(); $target = "image_files/".$imagename; move_uploaded_file($source, $target); // // Add file validation code here // list( $source_width, $source_height, $source_type ) = getimagesize( $source_path ); switch ( $source_type ) { case IMAGETYPE_GIF: $source_gdim = imagecreatefromgif( $source_path ); break; case IMAGETYPE_JPEG: $source_gdim = imagecreatefromjpeg( $source_path ); break; case IMAGETYPE_PNG: $source_gdim = imagecreatefrompng( $source_path ); break; } $source_aspect_ratio = $source_width / $source_height; $desired_aspect_ratio = DESIRED_IMAGE_WIDTH / DESIRED_IMAGE_HEIGHT; if ( $source_aspect_ratio > $desired_aspect_ratio ) { // // Triggered when source image is wider // $temp_height = DESIRED_IMAGE_HEIGHT; $temp_width = ( int ) ( DESIRED_IMAGE_HEIGHT * $source_aspect_ratio ); } else { // // Triggered otherwise (i.e. source image is similar or taller) // $temp_width = DESIRED_IMAGE_WIDTH; $temp_height = ( int ) ( DESIRED_IMAGE_WIDTH / $source_aspect_ratio ); } // // Resize the image into a temporary GD image // $temp_gdim = imagecreatetruecolor( $temp_width, $temp_height ); imagecopyresampled( $temp_gdim, $source_gdim, 0, 0, 0, 0, $temp_width, $temp_height, $source_width, $source_height ); // // Copy cropped region from temporary image into the desired GD image // $x0 = ( $temp_width - DESIRED_IMAGE_WIDTH ) / 2; $y0 = ( $temp_height - DESIRED_IMAGE_HEIGHT ) / 2; $desired_gdim = imagecreatetruecolor( DESIRED_IMAGE_WIDTH, DESIRED_IMAGE_HEIGHT ); imagecopy( $desired_gdim, $temp_gdim, 0, 0, $x0, $y0, DESIRED_IMAGE_WIDTH, DESIRED_IMAGE_HEIGHT ); // // Render the image // Alternatively, you can save the image in file-system or database // header( 'Content-type: image/jpeg' ); imagejpeg( $desired_gdim, "image_files/" . $timestamp . $_FILES["thumb"]["name"] ); Hi, I have some images that I want to resize to a square dimention (40px 40px). However, not all image are square, so when they are resized, they lose their ration and look squashed. Is there a way I can display just a part of the original image, say 40px x 40px on the top middle of each image? I hope that makes sense |
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