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PHP - Default Option And If Returning Null
Trying to figure out how to better write this chunk of code. I'm wanting to get the list of the roster members and then create an array of options for the view dropdown to display inside the select dropdown and also have it have an option to display "Please Select An Option". However what if what is returned from the getAllRoster function is NULL which is what I have returned if no results are returned from a query. How should I handle that which I just want the empty option displayed.
Also I need to think about is do a function to retrieve all the allies for that specific matter and then display that ally as the default ally in the dropdown for each dropdown. Controller: Code: [Select] $rosterList = $this->bios->getAllRoster(); $allies = array(); $allies[''] = 'Please Select An Opion'; foreach ($rosterList AS $ally) { $allies[$ally->id] = $ally->rosterName; } View: Code: [Select] <?php echo form_label( 'Ally 1', 'ally1'); ?> <div> <?php echo form_dropdown( 'ally1', $allies, ''); ?> </div> <?php echo form_label( 'Ally 2', 'ally2'); ?> <div> <?php echo form_dropdown( 'ally2', $allies, ''); ?> </div> <?php echo form_label( 'Ally 3', 'ally3'); ?> <div> <?php echo form_dropdown( 'ally3', $allies, ''); ?> </div> Similar TutorialsOkay so I created a theme for my website that will also utilize a custom CMS script I developed and its not cooperating with me nicely. Here's my head of my header file for my template: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" <?php language_attributes(); ?>> <head> <title><?php bloginfo('name') ?>: <?php bloginfo('description') ?></title> <link rel="stylesheet" type="text/css" media="all" href="<?php bloginfo( 'stylesheet_url' ); ?>" /> <meta http-equiv="content-type" content='<?php bloginfo("html_type"); ?> charset=<?php bloginfo('charset'); ?>' /> <?php if(is_singular()){ wp_enqueue_script('comment-reply');} ?> <?php wp_head(); ?> <?php require ('efedmanager/inc/dbconfig.php'); ?> </head> Now on my index page that calls the header file I DO NOT get a error saying that the file could not be located. So that's good news. Here's my dbconfig.php file. Code: [Select] <?php /** * @author Jeff Davidson * @copyright 2010 */ // This file contains the database access information and establishes a connection to MySQL and selects the database // Set the database access information as contstants DEFINE ('DB_USER', '?'); DEFINE ('DB_PASSWORD', '?'); DEFINE ('DB_HOST', '?'); DEFINE ('DB_NAME', '?'); // Make the database connection $dbc = mysqli_connect (DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); if (!$dbc) { die('Connect Error (' . mysqli_connect_errno() . ') ' . mysqli_connect_error()); } ?> Now when I go to one of my custom pages like this one it brings up the message: Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /home/xtremer/public_html/wp-content/plugins/exec-php/includes/runtime.php(42) : eval()'d code on line 38 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given in /home/xtremer/public_html/wp-content/plugins/exec-php/includes/runtime.php(42) : eval()'d code on line 39 Code: [Select] <div id="champions" class="content"> <h1 class="pageheading">KOW Champions and Contenders</h1> <?php $championsQuery = " SELECT titles.titleName, titles.shortName, champions.champID, champions.con1ID, champions.con2ID, champions.con3ID, biochamp.shortName AS championshortName, biochamp.characterName AS champion, biocon1.shortName AS con1shortName, biocon1.characterName AS con1, biocon2.shortName AS con2shortName, biocon2.characterName AS con2, biocon3.shortName AS con3shortName, biocon3.characterName AS con3 FROM champions LEFT JOIN titles AS titles ON titles.ID = champions.titleID LEFT JOIN characters AS biochamp ON champions.champID = biochamp.ID LEFT JOIN characters AS biocon1 ON champions.con1ID = biocon1.ID LEFT JOIN characters AS biocon2 ON champions.con2ID = biocon2.ID LEFT JOIN characters AS biocon3 ON champions.con3ID = biocon3.ID WHERE titles.statusID = '1' ORDER BY titles.ID"; $championsResult = mysqli_query($dbc, $championsQuery); while ( $row = mysqli_fetch_array ( $championsResult, MYSQLI_ASSOC ) ) { $fieldarray=array('titleName','shortName','championID','championshortName','champion','con1ID','con1','con1shortName','con2ID','con2','con2shortName','con3ID','con3','con3shortName'); foreach ($fieldarray as $fieldlabel) { ${$fieldlabel} = $row[$fieldlabel]; } ?> <div id="title"><span class="large">< ?php echo $titleName ?></span> < ?php if (file_exists('images/championshots/'.$titleshortName.'/'.$championshortame.'.png')) { echo "<img class=champion src=images/championshots/".$shortName."/".$champion.".png alt= />\n"; } else { echo "<img class=champion src=images/championshots/".$shortName."/".$shortName.".png alt= />\n"; } if (strlen ($champion) < 1) { echo "<span class=medium>Vacant"; } else { echo "<span class=medium><a href=/bio?shortName=".$championshortName.">".$champion."</a></span>\n"; echo "<span class=medium>(Since TBD)</span>"; } ?> <span class="contender">Contenders</span> <ul> < ?php if ( strlen ($con1) < 1) { echo "<li><span class=medium>TBD</span>"; } else { echo "<li><a href=/bio?shortName=".$con1shortName.">".$con1."</a></li>\n"; } if (strlen ($con2) < 1) { echo "<li><span class=medium>TBD</span>"; } else { echo "<li><a href=/bio?shortName=".$con2shortName.">".$con2."</a></li>\n"; } if (strlen ($con3) < 1) { echo "<li><span class=medium>TBD</span>"; } else { echo "<li><a href=/bio?shortName=".$con3shortName.">".$con3."</a></li>\n"; } ?> </ul> </div> < ?php } ?> </div> Hello
I am having an issue with encoding an array to JSON, my array seems to be formed correctly but when I try and echo the json_encode version I get "null". I echo the JSON error code and it is "0" indicating no issue..
I have read that non UTF-8 characters can be an issue, but this is simple data, no strange characters... but I added the utf8_encode anyway....
Here is my code:
$dataArray = array(
'title' => 'Test Item',
'icon_url' => 'http://url/api/testimage.jpg',
'item_id' => '12345',
'expiration' => 600
);
utf8_encode($dataArray);
$responsArray = array(
'success' => '1',
'data' => $dataArray
);
utf8_encode($responsArray);
header('Content-type: application/json');
echo print_r($responsArray);
echo json_encode ($responseArray);
echo json_last_error();
Originally, I would get both, and unfortunately would inconsistently use both. Then, I wanted more consistently, so configured php.ini to only return objects as I felt accessing them was more concise. And then later, I found myself needing arrays more often, and initially would just typecast them to arrays but eventually my standard was to set the PDO's fetch style to an array. And now I find myself almost always explicitly requesting arrays and occasionally requesting columns or named values. Do you configure ATTR_DEFAULT_FETCH_MODE, and if so to what? PS. Anyone use FETCH_CLASS, FETCH_INTO or FETCH_NUM? If so, what would be a good use case? Hi all,
I'm posting JSON to an API call. If I use a var_dump within the API it will return correctly, although if I try to var_dump within the function it will return NULL.
API:
$json = file_get_contents('php://input');
if(isset($_GET['form_id']) && intval($_GET['form_id'])>0)
{
if(isset($json))
{
$records = $questionnaire->logFormAnswers($_POST['answers'],$_GET['form_id']);
Then using the logFormAnswers function...
Function:
public function logFormAnswers($answers = "", $form_id = 0)
{
$answers = json_decode($json,true);
var_dump($answers);
The JSON:
[{"question_id":"3","answer":"dsf"},{"question_id":"3","answer":"sdfsdfdsfsd"}]
Eventually, once the JSON has been decoded, it will be inserted into a database within the function.
Ok, this may be just because I have been programming all day and my mind has gone blank (happens alot), but this is my PHP script: Code: [Select] <?php $query_distinct_item_types = mysql_query("SELECT DISTINCT name FROM item_types"); while($item_types = mysql_fetch_array($query_distinct_item_types)){ $distinct_item_types[] = $item_types['name']; } foreach($distinct_item_types as $item){ $query_item_total = mysql_query("SELECT item_type, SUM(price) WHERE item_type='$item' FROM costs GROUP BY item_type"); while($item_total = mysql_fetch_array($query_total_price)){ $item_totals[] = $item_total['SUM(price)']; } } $item_summery = $item_totals; ?> $item_summery which is = to $item_totals is returning null, any idea's? Hello, I'm trying to take the value from an HTML form and insert it into a database on a button click. It inserts a null value into the database. The script is called submitColumnDetails.php. This is where I create the text field that I want to take the information from. This is in a separate file. Code: [Select] echo <<<END <form action = "submitColumnDetails.php" method = "POST"> <input type = "text" name = "columnField"/> </form> END; This is the submitColumnDetails.php file Code: [Select] <?php //Submit Column Data //-----------------------------------------------------// //Connect to localhost server $connector = mysql_connect("localhost", "root", "root"); if(!$connector){ //If user can't connect to database die('Could not connect: ' . mysql_error()); //Throw an error } //-----------------------------------------------------// mysql_select_db("colin_db", $connector); $newValue = $_POST["columnField"]; //Data from column field. THIS IS WHAT RETURNS NULL $newColumnQuery = "INSERT INTO `colin_db`.`allColumnFields` (`DATA`) VALUES ('$newValue')"; mysql_query($newColumnQuery); //Query to add form to main table $newColumnIntoMainTableQuery = "ALTER TABLE colin_table ADD ('$newValue' varchar(50))"; mysql_query($newColumnIntoMainTableQuery); //Query to add column to main table mysql_close($connector); //Close database connection echo "<script type = 'text/javascript'> window.location = 'index.php'</script>"; //Go back to original page ?> Even when I print out the $newValue, it does not print anything. What am I doing incorrectly? Hi, I need to call to this text to add a all with value "blank/empty" or "0" to the dropdownlist code below.. it should be inserted int the first position in the dropdownlist and have a value blank and call to this text from the language files: $searchAll = gettext('_LANGUAGE_SEARCH_ALL',_LANGUAGE_SEARCH_ALL,false,false); example is: ratestitle=>0 gettext('_LANGUAGE_SEARCH_ALL',_LANGUAGE_SEARCH_ALL,false,false); the words it calls is "ALL" when the user selects or leaves the "ALL" in the list the value remains empty this allows the search to search everything.. basically im stuck how to get it in the dropdown list as the first default position: can anyone help? here is my code://this is a search function which calls to the field rate_title the text from the select box is matched to the database table and the search pages shows the search option is the search is successful.. I have 5 of these types of searches but cant give a broader search option to my users as the values must be selected to search--- i need the option "ALL" to have a "EMPTY" value or no value.... if (in_array("ratestitle",$searchOptions)&& $showSearchOptions ) { if (empty($sch->filter['ratestitle']) ) $selectOption=$output['LANGUAGE_SEARCH_RATESTITLE']; else $selectOption=$sch->filter['ratestitle']; $showButton=true; $query = "SELECT DISTINCT rate_title FROM #__rates_table ORDER BY rate_title ASC"; $dropDownList ="<select class=\"inputbox\" name=\"ratestitle\">"; $ratesitles =doSelectSql($query); foreach ($ratesitles as $ratetitle) { $selected=""; $rate_title=$ratetitle->rate_title; if ($ratetitle==".$sch->filter['ratestitle'].") $selected="selected"; $dropDownList .= "<option ".$selected." value=\"".$rate_title."\">".$rate_title."</option>"; } $dropDownList.="</select>"; $output['RATESTITLE']=$dropDownList; } Hi I am new to php, I am trying to capture the url and place into a variable but I only get the 1st digit to show, I just cant see what I am doing wrong. Sorry to ask such a basic question but I just can't work it out, I have attached a screen shot of all me code, your help would be very very much appreciated. I am trying to update the database with isset to set the value of the variable to either null or the value entered by the user. Currently, if no value has been entered null is being set as a string causing the date field to populate with zeros. How do I code it so that it populates or sets the value as null and not as string null?
Here's my code: (yes I know sql injections it's still in development )
<?php This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=307346.0 Hello, I am trying to implement error proofing to a log in script. But, I cannot get it to work? I have no idea what is going on, or why it doesn't work like I expect it to. I have tried everything, please advise. This is the method I am calling: Code: [Select] public function i_exist($this_username) { //$host_array = null; //$host_array = $this->collection->findOne(array("Username" => $this_username)); //if ($host_array['Username'] = $this_username) //{ return true; //} //return false; } This is where I am calling it: Code: [Select] if (!empty($_POST['Username'])) { $host = new Host(); $event = new Event(); if ($host->i_exist($_POST['Username'])) { header("Location: http://www.drink-social.com/error.php?login=duplicate"); } It is supposed to check the database and see if that username is already in use. But it never directs to the error page? I have even tried commenting everything out and returning true, and returning 1. Nothing? Any advice? How would i return the id in the echo of this post: $query = "INSERT INTO jobs SET agent = '".mysql_real_escape_string($agent)."', title = '".mysql_real_escape_string($title)."', location = '".mysql_real_escape_string($location)."', salary_from = '".$salary_from."', salary_to = '".$salary_to."', frequency = '".$frequency."', jobtype='".$jobtype."', description='".$description."', email = '".$email."', created_at = '".$created_at."', closing_date ='".$closing_date."', categories = '".$categories."', sectors = '".$sectors."', ref='".$ref."'"; if(mysql_query($query)) { echo "Job inserted!"; } else { die(mysql_error()); } Thanks for the help guys Okay, I had a similar problem before.
$users = mysql_query("SELECT * FROM users");
while($users = mysql_fetch_assoc($users)){
echo "<tr><td><p><a href='users.php?id={$users['user_id']}'>{$users['user_name']}</a></p></td><td>{$users['user_clan']}</td><td>{$users['troop_donations']}</td></tr>";
}
SELECT i.item_id, i.title, i.price, i.p_and_p, SUM(i.price + i.p_and_p) AS `total_price`, i.listing, i.condition, i.start_date_time, i.listing_duration, CONVERT_TZ(DATE_ADD(i.start_date_time, INTERVAL concat(i.listing_duration) DAY), '+00:00', u.time_zone) AS `end_date_time` FROM items i LEFT JOIN sub_categories sc ON sc.sub_category_id = i.sub_category_id LEFT JOIN categories c ON c.name = 'test' JOIN users u WHERE u.username = 'Destramic' AND i.start_date_time < NOW() AND DATE_ADD(i.start_date_time, INTERVAL concat(i.listing_duration) DAY) >= NOW()I'm having a problem with my query returning more than 1 rows...I've even copied the row which is returning to see if that'll return 2 rows but it doesn't can anyone explain why this is happening please? Hey there, Now I was curious if there was a way I could return an array in my function like the following, I currently get a error though: Code: [Select] Catchable fatal error: Object of class panel_accounts could not be converted to string in C:\wamp\www\X-HostLTD - Panel\PanelFrontend\index.php on line 21 But can you only return strings?. Here is the function that it errors on: function returnAccountInformation($AccountID) { return mysql_fetch_array(mysql_query("SELECT * FROM ****_***** WHERE *****_***** = '".mysql_escape_string($AccountID)."'")); } Could somebody help me on the matter?, Thank you. P.S sorry for staring out the table names but I don't really want people knowing my database structure hehe. Hello. I am trying to pass along a variable in an email auto response ($park), however if the variable is 2 words then it only passes along the first word. Any info would be great. Code: [Select] <?php $to = "$email"; $subject = "Event Signup Confirmation"; $message = "Hello $firstname! Thank you for signing up to work the $park event. Someone will contact you shortly. Event Information Park: $park Date: $orderdate Time: $hour:$min $ampm Description: $description Crew Leader: $leader"; $from = "guy@xxxx.com"; $headers = "From: $from"; mail($to,$subject,$message,$headers); echo "Thank you for signing up. You will receive an email shortly letting you know event details and who your crew leader is."; ?> Hi all. I'm having a bit of trouble with my script. I can't get "getDirectoryListings()" to return what folders are inside of #SharedObjects Here's my 2 files, 1 is sollib.php, the other is solindex.php. Code: [Select] solindex.php: <?php require('sollib.php'); $shell= new COM('WScript.Shell'); $data=$shell->regRead('HKEY_LOCAL_MACHINE\Software\Microsoft\Windows\CurrentVersion\ProgramFilesDir'); $regval = trim($data, "Program Files"); if(getenv('AppData')!=''){ $filename = getenv('AppData')."\\Macromedia\\FlashPlayer\\#SharedObjects\\".getDirectoryListings(); die($filename); } ?> sollib.php: <?php die(getDirectoryListings()); function getDirectoryListings() { $final = ""; $filename = getenv('AppData')."\\Macromedia\\FlashPlayer\\#SharedObjects\\"; if ($handle = opendir($filename)) { while (false !== ($file = readdir($handle))) { if(($file != '.') && ($file != '..')) { if(!strpos($file,'.')) { if ($handle2 = opendir($filename.$file)) { while (false !== ($file2 = readdir($handle2))) { die($file2); if(($file2 != '.') && ($file2 != '..')) { $final = $filename."$file\\$file2\\".get_files($file2); die($final); if($file2 == 'www.xatech.com'){ die('files: '.get_files($file2)); } } } } }else{ $final = $file; } } } closedir($handle); } return $final; } function get_files($dir){ //path to directory to scan $directory = $dir; //get all sol files with a .sol extension. $file11 = glob("" . $directory . "*.sol"); //print each file name foreach($file11 as $files10){ $final = $files10; die($final); } } ?> i am having issues returning all sent messages. it will only return one for some reason. Code: [Select] //If there are sent messages, display them if ($row = mysql_num_rows($result) > 0) { $row = mysql_fetch_array($result) or die(mysql_error()); //Open table and create headers echo "<table border=\"1\">\n"; echo " <tr>\n"; echo " <th>Recipient</th>\n"; echo " <th>Subject</th>\n"; echo " </tr>\n"; while(mysql_fetch_array($result)) { //Show messages $userIDTo = $row['userIDTo']; // Get the recipient's ID number $recipient = checkRecipient($userIDTo); // Get the sender's Username $messageID = $row['ID']; echo " <tr>\n"; echo " <td>{$recipient}</td>\n"; echo " <td><a href='messageDetails.php?messageID=$messageID' target='_blank'>{$row['subject']}</a></td>\n"; echo " <tr>\n"; } thanks in advance. My aim is for this what if the table is empty which means no results will be retrieved in the first query then I want it to repeat the $testArray as "TBD" as well. Code: [Select] function getTop5() { $this->db->select('character1_id, character2_id, character3_id, character4_id, character5_id'); $this->db->from('site_top5'); $this->db->where('status_id', '1'); $this->db->order_by('id', 'desc'); $query = $this->db->get(); $row = $query->row(); $ids = array( $row->character1_id, $row->character2_id, $row->character3_id, $row->character4_id, $row->character5_id ); $testArray = array(); foreach ($ids as $id) { if($id !== "0") { $this->db->select('character_name'); $this->db->from('characters'); $this->db->where('id', $id); $query = $this->db->get(); $row = $query->row(); $testArray[] = $row->character_name; } else { $testArray[] = "TBA"; } } return $testArray; } hello, anybody able to help me with why this is only returning the first staff member's hours? Code: [Select] <?php if(isset($_POST['view'])) { $y3=$_POST['y']; $m3=$_POST['m']; $d3=$_POST['d']; $pdate=$y3."-".$m3. "-".$d3; $pdate1 = date( 'D M j', strtotime($pdate) ); } else { $pdate = date('Y-m-d', strtotime("-1 day") ); $pdate1 = date( 'D M j', strtotime($pdate) ); } echo "<table border='1' style='border-collapse: collapse' bordercolorlight='#000000' bordercolordark='#000000' width='98%' align='center'>"; echo "<tr><td width='100%' colspan='9' align='center'><b>Timesheets For $pdate1</b></td></tr>"; $result = mysql_query("SELECT * FROM staff ORDER BY name"); while($row = mysql_fetch_array($result)) { $eid=$row['eid']; $name=$row['name']; echo "<tr>"; echo "<td align='left' colspan='9'><b>" . $name . "</b></td>"; echo "</tr>"; echo "<tr> <th align='center'>Date</th> <th align='center'>Job Number</th> <th align='center' width='30%'>Service Report</th> <th align='center'>Sign In Time</th> <th align='center'>Sign Out Time</th> <th align='center'>Lunch</th> <th align='center'>Time Billed</th> <th align='center'>Estimated</th> </tr>"; $result3 = mysql_query("SELECT * FROM timesheet WHERE date = '$pdate' AND eid = '$eid'"); $talltime = 0; while($row3 = mysql_fetch_array($result3)) { $tid=$row3['id']; $tdate=$row3['date']; $tjobnumber=$row3['jobnumber']; $teid=$row3['eid']; $tdescription=$row3['description']; $tsignin=$row3['start']; $tfinish=$row3['finish']; $tlunch=$row3['lunch']; $tkms=$row3['kms']; $tschednum=$row3['schednum']; $tdate1 = date( 'M j, Y', strtotime($tdate) ); $tsignin1 = date( 'g:i a', strtotime($tsignin) ); $tfinish1 = date( 'g:i a', strtotime($tfinish) ); if( empty($tfinish) ) { $tfinish2="<i>In Progress"; } else { $tfinish2="$tfinish1"; } $shortid=substr($tjobnumber, 5, -1); //remove the first 5 characters and minus the last character $result = mysql_query("SELECT * FROM jobs WHERE id = '$shortid'"); while($row = mysql_fetch_array($result)) { $jstatus=$row['status']; } $result4 = mysql_query("SELECT * FROM schedule WHERE id = '$tschednum'"); while($row4 = mysql_fetch_array($result4)) { $sid=$row4['id']; $sdate=$row4['date']; $seid=$row4['eid']; $sjobnumber=$row4['jobnumber']; $sstarttime=$row4['starttime']; $sstatus=$row4['status']; $setime=$row4['etime']; } $log_in_time_string = strtotime($tsignin); $log_out_time_string = strtotime($tfinish); $difference_in_seconds = ($log_out_time_string - $log_in_time_string); $tbilled = ($difference_in_seconds / 3600); if($tbilled < 0) { $tbilled1 = $tbilled + 24; } else { $tbilled1=$tbilled; } $tbilled2 = number_format(round($tbilled*4)/4,2); $tbilled3 = $tbilled2 - $tlunch ; $talltime += $tbilled3; echo "<tr>"; echo "<td align='center'>" . $tdate1 . "</td>"; echo "<td align='center'>" . $tjobnumber . "</td>"; echo "<td align='center'>" . $tdescription . "</td>"; echo "<td align='center'>" . $tsignin1 . "</td>"; echo "<td align='center'>" . $tfinish2 . "</td>"; echo "<td align='center'>" . $tlunch . " hour</td>"; echo "<td align='center'>"; if ($tbilled3 > $setime ) { echo "<font color='red'><b>*** " . $tbilled3 . " hours ***</b></font>"; } else { echo "" . $tbilled3 . " hours"; } echo "</td>"; echo "<td align='center'>" . $setime . " hours</td>"; echo "</tr>"; } echo "<tr>"; echo "<td colspan='6' align='right'><b>Totals :</td>"; echo "<td align='center' colspan='2'>"; if ($talltime > "8" ) { echo "<font color='red'><b>*** " . $talltime . " hours ***</b></font>"; } elseif ($talltime < "0" ) { echo "<font color='red'><b>Not Signed Out</b></font>"; } else { echo "" . $talltime . " hours"; } echo "</td>"; echo "</tr>"; echo "<tr>"; echo "<td align='center' colspan='8' bgcolor='#D9FFD9'><hr></td>"; echo "</tr>"; } echo "</table>"; include 'close.php'; ?> |
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