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PHP - Uploaded Images - Thumbnail Sizes?
Upload images - Thumbnail sizes?
Hi all I haven't used php for a while now and I'm really stuck on some code I wrote and now I can't work how to change it. I have this function to upload images and create thumbnails. The thumbnails can be either landscape or portrait and I want them to have the same height. At the moment the portrait thumbnails height is equal to the landscape thumbnail width. The dimensions of the thumbnails are the same but the portrait images are portrait. How can I size the thumbnails so they all have the same height. Thanks in advance for any help or advice on this. Code: [Select] function upload_images(){ $photo_types = array('image/pjpeg'=>'.jpeg','image/jpeg'=>'.jpg','image/gif'=>'.gif','image/.bmp'=>'bmp','image/x-png'=>'.png'); //$number_of_uploads = 5; $image_Dir = "images_1/"; $image_thumb_Dir = $image_Dir . "thumbs/"; $photo_id_arr = array(); $photo_ext_arr = array(); $photo_id_ext_arr = array(); // if(isset($_FILES['images'])){ $image_uploaded = $_FILES['images']; for($i=0; $i<=count($_FILES['images']['name']);$i++){ if(!empty($image_uploaded['name'][$i])){ if(array_key_exists($image_uploaded['type'][$i], $photo_types)){ $file_temp = mysql_prep($image_uploaded['name'][$i]); // $query = "INSERT INTO photos (filename) VALUES ('{$file_temp}')"; $result = mysql_query($query); confirm_query($result); if($result){ $photo_id = mysql_insert_id(); array_push($photo_id_arr, $photo_id); } // $filetype = $image_uploaded['type'][$i]; $ext = $photo_types[$filetype]; array_push($photo_ext_arr, $ext); $dbfile_name = $photo_id . $ext; // $query = "UPDATE photos SET filename = '{$dbfile_name}' WHERE photo_id = '{$photo_id}'"; $result = mysql_query($query); confirm_query($result); // // $stored_image = $image_Dir . $dbfile_name; $stored_thumb = $image_thumb_Dir . $dbfile_name; move_uploaded_file($image_uploaded['tmp_name'][$i], $stored_image ); // $src_image = imagecreatefromjpeg($stored_image); // $src_width = imagesx($src_image); $src_height = imagesy($src_image); $new_width = 900; $new_height = 900; // if($src_width > $src_height){ $img_w = $new_width; $img_h = $src_height*($new_height/$src_width); } if($src_width < $src_height){ $img_w = $src_width*($new_width/$src_height); $img_h = $new_height; } if($src_width == $src_height){ $img_w = $new_width; $img_h = $new_height; } // $mainImg = imagecreatetruecolor($img_w, $img_h); imagecopyresampled($mainImg, $src_image,0,0,0,0,$img_w, $img_h, $src_width, $src_height); imagejpeg($mainImg, $stored_image, 100); imagedestroy($src_image); imagedestroy($mainImg); //*************************** // // // //*************************** $src_image = imagecreatefromjpeg($stored_image); // $src_width = imagesx($src_image); $src_height = imagesy($src_image); $new_width = 85; $new_height = 85; // if($src_width > $src_height){ $thumb_w = $new_width; $thumb_h = $src_height*($new_height/$src_width); } if($src_width < $src_height){ $thumb_w = $src_width*($new_width/$src_height); $thumb_h = $new_height; } if($src_width == $src_height){ $thumb_w = $new_width; $thumb_h = $new_height; } // $thumb = imagecreatetruecolor($thumb_w, $thumb_h); imagecopyresampled($thumb, $src_image,0,0,0,0,$thumb_w, $thumb_h, $src_width, $src_height); imagejpeg($thumb, $stored_thumb, 100); imagedestroy($src_image); imagedestroy($thumb); }else{ //echo "File format not supported."; } } } array_push($photo_id_ext_arr, $photo_id_arr); array_push($photo_id_ext_arr, $photo_ext_arr); return $photo_id_ext_arr; } } Similar TutorialsHi, I have a script that uploads an image to a directory and then saves the fill path to a field in a table for later use. The only problem is people are uploading huge images and then when I produce a catalogue of my listings it takes forever to load because the images are so big. What I am after is an add in script to create an ADDITIONAL image 100 x 75px, I don't really want to change my upload script. Any ideas? Thanks in advace. Here is what I have: Code: [Select] <?php $idir = "../fleet/"; // Path To Images Directory if (isset ($_FILES['fupload'])){ //upload the image to tmp directory $url = $_FILES['fupload']['name']; // Set $url To Equal The Filename For Later Use if ($_FILES['fupload']['type'] == "image/jpg" || $_FILES['fupload']['type'] == "image/jpeg" || $_FILES['fupload']['type'] == "image/pjpeg") { $file_ext = strrchr($_FILES['fupload']['name'], '$account.'); // Get The File Extention In The Format Of , For Instance, .jpg, .gif or .php $copy = copy($_FILES['fupload']['tmp_name'], "$idir" . $_FILES['fupload']['name']); // Move Image From Temporary Location To Perm } } $fleetimage1 = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); //then insert sql code below... ?> Hi everyone!! I have looked into how the upload script works and this is what i have: Code: [Select] <?php if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 20000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file"; } ?> Which is un-tested at the moment, but let's just say for talking sake it worked 100% what elements of this script would i be looking at to display the files uploaded on to another page, in my case my homepage? ive found as to yet, that the uploads have to be stored on a file somewhere on my server, which i've set up. But i thought it would be just as easy to have a field in my table named upload and display it within the table next to the other results? instead i just get whatever the file name is named.jpg. Any help in looking towards the answer? many thanks in advance guys! Hi Everyone, I've been studying the topics at this site and others on ways to count uploaded images; and what I've tried hasn't worked. I have seen this question posed and answered many times and most of the answers are something akin to this: Code: [Select] $count = count($_FILES['userfile'] ['name']); echo "the number of photos is ".$count; The explanation usually states that "count($_FILES['userfile'])" will simply count the number of elements in the array and return 5. But including ['name'] will return the number of files (images) uploaded. I will allow up to five photos to be uploaded (less is OK too) and want to count them in order to iterate through the proper number of loops to filter and process the photos. I've tested both of the above and get 5 (elements) when I count the ['userfile']; but get 0 (zero) when I test "['userfile'] ['name']". Here's the html code: Code: [Select] <!-- html here to input form data --> <label></label><input type="hidden" name="MAX_FILE_SIZE" value="500000000" /><br /> <label for="userfile">Upload photo 1</label> <input type="file" name="userfile1" id="userfile1" /><br /> <label for="userfile">Upload photo 2</label> <input type="file" name="userfile2" id="userfile2" /><br /> <label for="userfile">Upload photo 3</label> <input type="file" name="userfile3" id="userfile3" /><br /> <label for="userfile">Upload photo 4</label> <input type="file" name="userfile4" id="userfile4" /><br /> <label for="userfile">Upload photo 5</label> <input type="file" name="userfile5" id="userfile5" /><br /><br /> <label></label><input type="submit" name="userfile" value="Send Ad" /> </form> I've been testing the uploads with two files (jpg) and have tried to come up with an alternative that can iterate through the file arrays and determine how many photos I have. The code I've been testing is as follows: Code: [Select] $num = 1; $count = 0; while ($num <=5) { foreach ($_FILES['userfile'.$num] as $upload){ if ($upload ['error'] != 4){ } $count ++; } $num++; } echo "the number of photos is ".$count; I'm using "['error'] !=4" because some times people won't have 5 photos to upload. The result I get is 25 or 5 (files) x 5 (elements) for a total of 25. Does anyone know the proper way of doing this? Thanks for you input! Cheers, Rick Hi everyone, I am after a scrpit/function that will get information of an uploaded image, resize it, then display the manipulated image. in my "upload" script, there will be a size limit and a file extension/type limit to: 600 x 200px / jpg, gif, jpeg... this is to keep the script i'm after more simple. As using vector images i'm told is such a complicated problem for me at this time. So... to get the size info/dimensions its like this: Code: [Select] <?php list($width, $height, $type, $attr) = getimagesize("image_name.jpg"); echo "Image width " .$width; echo "<BR>"; echo "Image height " .$height; echo "<BR>"; echo "Image type " .$type; echo "<BR>"; echo "Attribute " .$attr; ?> and..... resize something like this: Code: [Select] function get_image_sizes($sourceImageFilePath, $maxResizeWidth, $maxResizeHeight) { // Get width and height of original image $size = getimagesize($sourceImageFilePath); if($size === FALSE) return FALSE; // Error $origWidth = $size[0]; $origHeight = $size[1]; // Change dimensions to fit maximum width and height $resizedWidth = $origWidth; $resizedHeight = $origHeight; if($resizedWidth > $maxResizeWidth) { $aspectRatio = $maxResizeWidth / $resizedWidth; $resizedWidth = round($aspectRatio * $resizedWidth); $resizedHeight = round($aspectRatio * $resizedHeight); } if($resizedHeight > $maxResizeHeight) { $aspectRatio = $maxResizeHeight / $resizedHeight; $resizedWidth = round($aspectRatio * $resizedWidth); $resizedHeight = round($aspectRatio * $resizedHeight); } // Return an array with the original and resized dimensions return array($origWidth, $origHeight, $resizedWidth, $resizedHeight); } // Get dimensions $sizes = get_image_sizes($sourceImageFilePath, $maxResizeWidth, $maxResizeHeight); $origWidth = $sizes[0]; $origHeight = $sizes[1]; $resizedWidth = $sizes[2]; $resizedHeight = $sizes[3]; // Create the resized image $imageOutput = imagecreatetruecolor($resizedWidth, $resizedHeight); if($imageOutput === FALSE) return FALSE; // Error condition // Load the source image $imageSource = imagecreatefromjpeg($sourceImageFilePath); if($imageSource === FALSE) return FALSE; // Error condition $result = imagecopyresampled($imageOutput, $imageSource, 0, 0, 0, 0, $resizedWidth, $resizedHeight, $origWidth, $origHeight); if($result === FALSE) return false; // Error condition // Write out the JPEG file with the highest quality value $result = imagejpeg($imageOutput, $outputPath, 100); if($result === FALSE) return false; // Error condition And.... display is this: Code: [Select] <?php $database="***"; mysql_connect ("***", "***", "***"); @mysql_select_db($database) or die( "Unable to select database"); $result = mysql_query( "SELECT company_name, location, postcode, basicpackage_description, premiumuser_description, upload FROM Companies" ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); print "\n\n\nThere are $num_rows records.<P>"; echo "<table><tr><th>Comppany Name</th><th>Location</th><th>Postcode</th><th>Basic Members</th><th>Upgraded Users</th><th>Company Logo</th></tr><tr><td></td><td></td><td></td><td></td><td></td><td></td></tr>";// store the records into $row array and loop through while ( $row = mysql_fetch_array( $result, MYSQL_ASSOC ) ) { // Print out the contents of the entry echo "<tr><td>{$row['company_name']}</td>"; echo "<td>{$row['location']}</td>"; echo "<td>{$row['postcode']}</td>"; echo "<td>{$row['basicpackage_description']}</td>"; echo "<td>{$row['premiumuser_description']}</td>"; echo "<td><img src=\"http://www.removalspace.com/images/COMPANIES{$row['upload']}\" alt=\"logo\" /></td></tr>";} echo "</table>"; ?> How will all these fit together in one script? any help i'd love it! many thanks in advance I have this script where it uploads the file name to a database plus a few more things. Main Upload form. (img_add.php) <form enctype="multipart/form-data" action="img_add.php" method="POST"> Name: <input type="text" name="name"><br> E-mail: <input type="text" name = "email"><br> Phone: <input type="text" name = "phone"><br> Photo: <input type="file" name="photo"><br> <input type="submit" value="Add"> </form> Uploader. (img_add.php) <?php //This is the directory where images will be saved $target = "mainnewsimg/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $name=$_POST['name']; $email=$_POST['email']; $phone=$_POST['phone']; $pic=($_FILES['photo']['name']); // Connects to your Database mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("chat") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO `images` VALUES ('$name', '$email', '$phone', '$pic')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['photo']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } ?> And the one that views it. (img_view.php) It uses a get function so do it with img_view.php?img=2 <?php mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("chat") or die(mysql_error()) ; //Retrieves data from MySQL $newsid = $_GET['img']; $data = mysql_query("SELECT * FROM `images` WHERE id ='$newsid'") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data Echo "<img src=mainnewsimg/".$info['photo'] ."> <br>"; } ?> And my database sql. CREATE TABLE IF NOT EXISTS `images` ( `name` varchar(30) DEFAULT NULL, `email` varchar(30) DEFAULT NULL, `phone` varchar(30) DEFAULT NULL, `photo` varchar(30) DEFAULT NULL, `id` int(11) NOT NULL AUTO_INCREMENT, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; -- -- Dumping data for table `images` -- INSERT INTO `images` (`name`, `email`, `phone`, `photo`, `id`) VALUES ('sdf', 'sdfdsdsf', 'dsffsfsdf', 'arrow_forward_last.gif', 1), ('sadd', 'sadd', 'adsadasdad', 'artbottomshadr.png', 2); The values inside I had to put in manually to test if it worked for the img_view.php Anyways, It doesnt want to upload the images at all, even tho it says it did and gives the message The file ". basename( $_FILES['photo']['name']). " has been uploaded, and your information has been added to the directory I would greatly appreciate some help, I also provided everything so you can try it on your own server too. Please, I need help with resizing uploaded images. Copied below is the code for image upload ( which I tagged "upload.php") Code: [Select] <?php // define a constant for the maximum upload size define ('MAX_FILE_SIZE', 51200); if (array_key_exists('upload', $_POST)) { // define constant for upload folder define('UPLOAD_DIR', 'C:/upload_test/'); // convert the maximum size to KB $max = number_format(MAX_FILE_SIZE/1024, 1).'KB'; // create an array of permitted MIME types $permitted = array('image/gif', 'image/jpeg', 'image/pjpeg', 'image/png'); foreach ($_FILES['image']['name'] as $number => $file) { // replace any spaces in the filename with underscores $file = str_replace(' ', '_', $file); // begin by assuming the file is unacceptable $sizeOK = false; $typeOK = false; // check that file is within the permitted size if ($_FILES['image']['size'][$number] > 0 || $_FILES['image']['size'][$number] <= MAX_FILE_SIZE) { $sizeOK = true; } // check that file is of an permitted MIME type foreach ($permitted as $type) { if ($type == $_FILES['image']['type'][$number]) { $typeOK = true; break; } } if ($sizeOK && $typeOK) { switch($_FILES['image']['error'][$number]) { case 0: // check if a file of the same name has been uploaded // if (!file_exists(UPLOAD_DIR.$file)) { // move the file to the upload folder and rename it $success = move_uploaded_file($_FILES['image']['tmp_name'][$number], UPLOAD_DIR.$file); // } /* else { // get the date and time ini_set('date.timezone', 'Europe/London'); $now = date('Y-m-d-His'); $success = move_uploaded_file($_FILES['image']['tmp_name'][$number], UPLOAD_DIR.$now.$file); }*/ if ($success) { $result[] = "$file uploaded successfully"; } else { $result[] = "Error uploading $file. Please try again."; } break; case 3: $result[] = "Error uploading $file. Please try again."; default: $result[] = "System error uploading $file. Contact webmaster."; } } elseif ($_FILES['image']['error'][$number] == 4) { $result[] = 'No file selected'; } else { $result[] = "$file cannot be uploaded. Maximum size: $max. Acceptable file types: gif, jpg, png."; } } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Multiple file upload</title> </head> <body> <?php // if the form has been submitted, display result if (isset($result)) { echo '<ol>'; foreach ($result as $item) { echo "<strong><li>$item</li></strong>"; } echo '</ol>'; } ?> <form action="" method="post" enctype="multipart/form-data" name="multiUpload" id="multiUpload"> <p> <label for="image1">File 1:</label> <input type="hidden" name="MAX_FILE_SIZE" value="<?php echo MAX_FILE_SIZE; ?>" /> <input type="file" name="image[]" id="image1" /> </p> <p> <label for="image2">File 2:</label> <input type="file" name="image[]" id="image2" /> </p> <p> <input name="upload" type="submit" id="upload" value="Upload files" /> </p> </form> </body> </html> This works fine , except that it only uploads to C:/upload_test instead of the images folder (../img/) Can you please help with the codes for creating thumbnails while retaining the original upload. Thanks hi all I am finishing off the final touches to my PHP postcard script and want to be able to display thumb file types only I have found a script to resize the images but this creates larger ones so i want to be able to switch between the two. <?php // CHANGE PARAMETERS HERE BEGIN $senderName = " Holidays From Home "; // Eg.: John's Postcards $senderEmail = "holidaysfromhome@voluntary.awardspace.co.uk"; // Eg.: john@postcard.com // Change only if you have problems with urls $postcardURL = "http://".$_SERVER["HTTP_HOST"].$_SERVER["SCRIPT_NAME"]; // CHANGE PARAMETERS HERE END $result = 0; $msg = ""; $msg1 = ""; $pic = ""; function displayPhotos() //edit photos and change image sizes { global $pic; $columns = 5; $act = 0; $act1 = 0; $sel = 0; // Open the actual directory if($handle = opendir("thumbs")) { // Read all file from the actual directory while($file = readdir($handle)) { if(!is_dir($file)) { if(isset($pic[1])) { if($pic[1] == $act1){$sel = "checked";} else{$sel = "unchecked";} } if($act == 0){echo "<tr>";} echo "<td align='center'><img src='thumbs/$file' alt='postcard' BORDER =1 /><br/><input type='radio' name='selimg' value='$file,$act1' $sel/></td>"; //displays the images $act++; $act1++; if($act == $columns){$act = 0;echo "</tr>";} } } echo "</tr>"; } } ?> my thumbnail images all end in (_th.jpg) and my large files all end in (.jpg). I am really stuck any help would be much appreciated Right now users log in and upload an image to the website. I want every image that is uploaded to be watermarked with a particular logo. Is this possible? Any hints or tips will be appreciated. Thank you. Hi all, Could someone help me add a thumbnail script to the below that works on scaling it down to 200px x 133px. I guess it is not that hard. <?php $destination='aircraft/'.$reg."1.jpg"; $temp_file = $_FILES['image']['tmp_name']; move_uploaded_file($temp_file,$destination); ?> Thanks Is it better to store uploaded images as 'content' in the database? (like he http://www.techsupportforum.com/forums/f49/tutorial-upload-files-to-database-176804.html).. Or just as a regular file which is referenced in the database..? Hi all, I am creating a thumbnail from an uploaded image (in this case a company logo). The problem is that the thumbnail image is poor quality and not fit to display on the website! I have attached the uploaded image and then then generated thumbnail, so you can see how much it is degrading. I always want the thumb to be the same size, which is 129pxx44px. I have included the thumb generation part of my script below: // This is declared at the start of the script $tdir = "images/agencylogos/thumbs/"; $twidth = "129"; $theight = "44"; // This is the actual part of the script that does the resizing $simg = imagecreatefromjpeg($newname); $currwidth = imagesx($simg); $currheight = imagesy($simg); if ($currheight > $currwidth) { $zoom = $twidth / $currheight; $newheight = $theight; $newwidth = $currwidth * $zoom; } else { $zoom = $twidth / $currwidth; $newwidth = $twidth; $newheight = $currheight * $zoom; } $dimg = imagecreate($newwidth, $newheight); imagetruecolortopalette($simg, false, 256); $palsize = ImageColorsTotal($simg); imagecopyresized($dimg, $simg, 0, 0, 0, 0, $newwidth, $newheight, $currwidth, $currheight); // Copy Resized Image To The New Image (So We Can Save It) imagejpeg($dimg, "$tdir" . $image_name, 100); imagedestroy($simg); imagedestroy($dimg); Can anyone see any ways of improving this script so that it would make the thumb image better quality? Many thanks, Greens85 Hi, this is what I want to get working: each time I add an entry, it is displayed in a nice html table, and each entry listed in this html table has an UPDATE link that allows the user to update the Price and Description field of the corresponding table in my database. I have also included an upload element which whenever a user chooses an image, it will replace the default fileUploadIcon.jpg with this. Please see the index.php and bellUpdateForm.php below respectively Code: [Select] //index.php <table border="border"> <?php require 'bellConnect.inc.php'; $curImage; $imgIndx=-1;//iniitally $result=mysql_query("SELECT ID, Name, Manufacturer, Price, Description, SimSupport FROM bellProducts"); $indx=0;//***HOW DO I MAKE THIS SHARED SO THAT EACH ENTRY ADDED HAS AN INCREMENTED index appended to end of its name attribute //phpinfo(); //print "Val of \$counter so far: ".$counter; //NB: print table headings if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { //$counter+=1; print "<table border='border'>"; print "<tr> <th>ID</th> <th>Image</th> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> <th colspan=2 align='center'>Modify</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { //extract($row); //if($indx<sizeof($bellProductsArray)) //{ "<tr align='center'> <td>$row[ID]</td> <td>"; if($_POST['upload']) print "<img src=".$_FILES['image']['name'].">"; else print "<img src='fileUploadIcon.jpg' name='image' /> </td> <td> $row[Name] </td> <td> $row[Manufacturer] </td> <td> $$row[Price]</td> <td align='left'>$row[Description]</td> <td>$row[SimSupport]</td> <td><a href='bellUpdateForm.php?ID=$row[ID]'>UPDATE</a></td> <td><a href='bellDeleteForm.php?ID=$row[ID]' name='delete'>DELETE</a></td> </tr>"; //}//END INNER IF $indx++; }//END WHILE }//END BIG IF ?> </table> </body> </html> Code: [Select] //bellUpdateForm.php <?php require 'bellConnect.inc.php'; if($_GET && !$_POST)//this is to make sure that the current entry is selected BUT the updated info NOT submitted yet { if(isset($_GET['ID'])) { $ID=$_GET['ID']; $result=mysql_query("SELECT * FROM bellProducts WHERE ID=$ID"); $row=mysql_fetch_assoc($result); //store the one entry that will be updated print "You are currently updating item: <strong>$row[Manufacturer] $row[Name] </strong> <br /><br />"; "<form action='bellUpdate.php' method='post'> <label> Price:<input type='text' value='$row[Price]' name='price' id='price'></input> </label> <label> Description: <textarea cols='60' rows='3' name='description' id='description'> $row[Description] </textarea> </label> <div> <input type='submit' value='Update entry' name='update' id='update' /> <input type='hidden' value=$row[ID] name='id' /> </div> <input type='reset' value='Reset entry' />"; print "</form>"; }//END INNER IF }//END BIG IF ?> <form method='post' action='index.php' enctype='multipart/form-data' name='uploadImage' id='uploadImage'> <p> <label>Upload image</label> <input type='file' name='image' id='image' /> </p> <p> <input type='submit' value='Upload this' name='upload' id='upload' /> </p> </form> <?php if(array_key_exists('upload', $_POST)) { // define constant for upload folder define('UPLOAD_DIR', 'C:\wamp\www'); // move the file to the upload folder and rename it move_uploaded_file($_FILES['image']['tmp_name'], ! UPLOAD_DIR.$_FILES['image']['name']); } ?> </body> </html> I have a script that I am trying to transfer one file from a remote server to my local server and save it. The files can be quite large. I have successfully backed up around 200 MB... But, anything over that seems to fail with a strange error... I was hoping for a little guidance... here is my code and error/warning that I get: PHP Code: function remote_capture($tmp_url, $filename) { $r_handle = fopen($tmp_url, "rb"); $d_handle = fopen($filename, 'w'); if($r_handle&&$d_handle) { while(($buffer = fgets($r_handle)) !== false) { fputs($d_handle, $buffer); } fclose($r_handle); fclose($d_handle); return true; } else { return false; } } Warning Message: Warning: file_get_contents(URL_OF_MY_SCRIPT_HAS_BEEN_REMOTED) [function.file-get-contents]: failed to open stream: HTTP request failed! in /path/on/my/local/server/to/script on line 298 Hi Guys I'm building a shopping cart based on the http://www.phpwebcommerce.com/ free tutorial. I'm getting stuck on adding sizes to the product options. what I need: Mens - available in Medium Large and XLarge Womens - available in Small Medium and Large Baby - available in 6, 12, 18 and 24 months I've created arrays to hold the sizing options: Code: [Select] $catAlias = (isset($_GET['a']) && $_GET['a'] != '') ? $_GET['a'] : 0; $product = getProductDetail($pdId, $catId, $catAlias); // populate the arrays $size_m = array("medium", "large", "x-large"); $size_w = array("small", "medium", "large"); $size_b = array("6 months", "12 months", "18 months", "24 months"); // create dropdown function createDropdown($arr, $frm) { echo '<select name="'.$frm.'" id="'.$frm.'"><option value="">Select one</option>'; foreach ($arr as $key => $value) { echo '<option value="'.$value.'">'.$value.'</option>'; } echo '</select>'; } and can call them into a dropdown depending on the department alias Code: [Select] <p>Choose your Size: <?php if ($catAlias == "mens-tees") { createDropdown($size_m, 'frmsize');} elseif ($catAlias == "womens-tees") { createDropdown($size_w, 'frmsize');} elseif ($catAlias == "inkababy") { createDropdown($size_b, 'frmsize');} ?> </p> The resulting HTML looks like this: Code: [Select] <p>Choose your Size: <select name="frmsize" id="frmsize"><option value="">Select one</option><option value="medium">medium</option><option value="large">large</option><option value="x-large">x-large</option></select></p> - so far so good. I'm struggling to find a way to pass the chosen size (frmsize) to the mini-cart and cart pages to store as an order. I've been Googling for days, reading through O'Reilly PHP, MYSQL book and haven't been getting anywhere. The flow is: Choose size click buy now > All detail are pass through getCartcontents function to mini-cart (shown in sidebar) and cart > details then passed through to checkout. Where do I store the chosen size variable for each t-shirt? How do i declare that this one is for product X in mens size or product X in womens size Would really appreciate some advice, I just can't get my head around the concept of where the chosen size goes and how to pass it to the cart(s). Thanks I have an existing PHP array ($products) with various fields in it.... id / title / description / link / image link etc. etc. as per requirements for a Google Products feed (https://support.google.com/merchants/answer/7052112). My issue is that, for clothing, Google want a separate record for each size available. My array includes the "size" field as a comma separated list e.g. 6,8,10,12,14 or XS,S,M,L,XL etc. etc. So before creating the feed (a text file, which is currently outputting fine except for the size field issue) I need to duplicate each id where there's more than 1 size in that field, for each size, and then manipulate the fields a little so that (ignoring all the duplicated fields that would remain unchanged) instead of the single record : -
id size item group id I'd have 11 records, item group id would be what the id is, the size appended to the id, and the size field only one (in sequence of those from the original), so: - id size item group id
52-6 6 52 That's just one product....there are quite a lot, each with multiple sizes, but all in the same format within the $products array. As always, any help / pointers / solutions much appreciated! At the moment I have been uploading files to my server using <input type='files'> and binary encrytion. I would like to have more controll over the files tmp_name. is there a way to assing it befor hand? Hello, I have a form for uploading CV files into a CV database. Once the files are uploaded to their directory (e.g. www.jobsboard.com/cvdatabase/) please could someone tell me how to restrict access to users? e.g. once a user logs into their userpanel they should be able to click on a hyperlink to download a CV e.g. (www.jobsboard.com/cvdatabase/CV1.doc) but a user who isn't logged in shouldn't be able to access www.jobsboard.com/cvdatabase/CV1.doc Please could you tell me whether this is possible? Many thanks, Stu I want to resize both width and height of the thumb pic this is the php code <?php $id_member=$_SESSION['rid']; if(!empty($foto1_name)) { $nama_file=$foto1_name; $anton->sekur_upload($nama_file); if($valid) { $abpath = "conf/i/"; @copy($foto1, $abpath."/".$foto1_name); $abang_dom=$abpath."/".$foto1_name; list($width, $height) = getimagesize($abang_dom); if($width>200) { make_thumb("$abpath/$foto1_name","conf/i/thumb/$foto1_name",200); } else { $tujuan="conf/i/thumb/".$foto1_name; rename($abang_dom, $tujuan); } } $foto_old_name=$foto1_name; $foto1_name=$id_member."_".$foto1_name; $foto1_name=strtolower($foto1_name); $foto1_name=str_replace(' ', '', $foto1_name); $asal1="conf/i/".$foto_old_name; $asal2="conf/i/thumb/".$foto_old_name; $tujuan1="conf/i/".$foto1_name; $tujuan2="conf/i/thumb/".$foto1_name; rename($asal1, $tujuan1); rename($asal2, $tujuan2); } I want to set the size to 100 x 100, which part of the code that I need to edit? Any one know a tutorial for an easy to use thumbnail script which I can use with pictures stored in mysql database. |
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