PHP - Get Variable Inside Of Function

Im having a problem with getting the quotes correct with this. I can either get the variable to work in the href and img src or in the css. Anyone have any ideas on this. Cuase im really stuck.

This allows the $address and $cos to echo in but not the css variables


<td><?php echo "<a href='planet_profile.php?planet=$address'>
<img src='images/star.jpg' id='$cos' 
style='position:absolute;' left:'$b_x px;' top:'$b_y px;'></a>"; ?></td>


and this allows only the css variables to work


 
<td><?php echo '<a href="planet_profile.php?planet="' . $address . '">
<img src="images/star.jpg" id="' . $cos . '" 
style="position:absolute; left:' . $b_x . 'px; top:' . $b_y . 'px;"></a>'; ?></td>

I'm redoing my login script using functions and a basic switch function checking against a $_GET variable (hope you guys know what I'm talking about).

What I want to do is create two functions:

1 that displays the login form
and 1 that processes the information

The form tag would look like this:
<form action=\"<?php $_SERVER['PHP_SELF']?>?action=process\" method=\"post\">
</form>

Here's my switch statement:
Code: [Select]
<?php

//****************************************
//****************Action******************
//****************************************

switch ($_GET["action"]) {
default:
case "index":
if (!$_SESSION["member"]) {
if (!$timeout) {
display_form();
} else {
echo $timeout_error;
}
} else {
echo "You are already logged in.";
}
break;
case "process":
if (!$_SESSION["member"]) {
if (!$timeout) {
process_form();
} else {
echo $timeout_error;
}
} else {
echo "You are already logged in.";
}
break;
}

?>

This runs as soon as "login.php" loads.

It'll automatically run the commands under case "default" and "index". It'll first check to see if the member's logged in. If not, it'll then check to see if "$timeout" is true ($timeout becomes true if the member has attempted to login 5 times and failed). If not, it'll display the login form, by running "display_form()".

Once the form has been filled and submitted, the commands under case "process" will be performed. Again it will first check to see if the member's logged in. If not, it'll check to see if "$timeout" is true. If not, it'll start validating the forms.

For the validation, I've created a variable called "$errors_found", and scripted one if statement checking to see if the email and password exist. If so, the variables "$rm_field_un" and "$rm_field_pw" become true, as well as "$errors_found".

So, back to submission of the form...

If "$errors_found" is true, display the form (when the form is displayed, there will be an if statement within that says "<?php if ($rm_field_un) { echo "Username is wrong."; } ?>", which will be displayed right underneath the username field and label. Same with the password elements). If "$errors_found" is not true, go ahead and register the member.

Now, here's where I need help, because I'm really confused as to how to accomplish this.

The "display_form()" function will contain a single variable called "$login_form". It will contain a value of the HTML constructed login form, and the function will return the variable.

Remember how I stated in the third paragraph up that I will have <php> statements within the form which would display errors if necessary? Well, how do I put those if statements within the HTML, which is contained within the variable?

If that last question confuses you, allow me to present you with an instance:
Code: [Select]
<?php

function display_form() {
$login_form = "
<form name=\"login_form\" method=\"post\" action=\"<?php $_SERVER['PHP_SELF']?>?action=process\">
Username:
<input type=\"text\">
<?php if ($rm_field_un) { echo "Username is wrong"; } ?>
";

return $login_form;
}

?>

See what I mean?

This code confuses me ALOT. I'm not sure if the <php> tags are needed as it is already contained within existing ones, or what. Can somebody please help me out?

Any and all help is much appreciated. =D

The org variable holds the value of the folder name. The problem is that the header is sending out ".$org." and not the actual value of $org.

Example output url: http://127.0.0.1/application/".$org."/display/trackingboard.php

I want this url if the value is test: http://127.0.0.1/application/test/display/trackingboard.php

Thanks!

Code: [Select]
$org = "test";
header('Location: ../application/".$org."/display/trackingboard.php');

how can you increase the page number in the following line until $status returns an empty result?

curl_setopt($ch, CURLOPT_HTTPHEADER, array("Accept: application/xml", "Authorization: xxxxxxxxxxxxx:xxxxxxxxxxxxxxxx", "Page: 2"));

I'm trying to build a math game.

But I'm having trouble trying to make a variable calculate that contains an operator.

Example:


$c1_op = "+";
$a1_num_user = $_POST['a1_num'];
$e1_num_user = $_POST['e3_num'];

$row_1 = $a1_num_user . $c1_op . $e1_num_user;
echo "result: " . $row_1;



If I now input a 10 and a 2 I will get echo'd out:

result: 10+2

It's not calculating. When I don't use any quotation marks then I will get the error "unexpected ;".

I need the operator inside a variable, it's the nature of the math game, any idea how I can make it work so it calculates?

Hi Everyone,

I have built a website utilizing a PHP abstract Webpage class to create the pages. When creating another class that inherits from Webpage class I rewrite abstract functions, etc. where needed. When instantiating an object of the extended classes I pass the constructor the $page_title, $css_file, $meta_data, $keywords, etc., etc.. I am able to pass html markup in a string variable to a class level "Setter" function  to populate a "main area" of the website and all works perfectly.

However, I have a contact form which I send the "Submit Message" button click to a PHP function that takes care of making sure the form fields are not empty, then sends email and returns a success message back to the calling page, if they are empty, the function returns what fields are empty(required). If the page includes empty and populated fields I want to put the populated fields into session variables so that I may populate the fields when the user is taken back to the page and display to the user the required fields that were empty(this functionality is already within the function).

This brings me to my question(see code below for reference):

Seeing that I am populating a variable with a string it seems I cannot use an if statement, echo or the like, my IDE gives me errors. How may I insert an if statement where needed to populate the empty form fields?
Code: [Select]
include('../php_functions/functions.php');//for the chechData() function

$error_message = NULL;

if(isset($_POST['submit']))
{
    $error_message = checkData($_POST, 'Renovation & Consulting');
}
$main_content =
'<form method="post" action="">
    <fieldset id="contactform">
        <legend>Renovations &amp; Consultations</legend>'.

        [color=red]//placing a variable here works fine![/color]
            $error_message
       
            .'<div class="row_div">
                <div class="label_div">
                    <label>First Name:</label>
                </div>
                <div class="input_div">
                    <input name="First Name" type="text" maxlength="50" size="50" value="'.[color=red]if(session variable not empty) echo it here;.'"[/color] />
                </div>
            </div>
            <div class="row_div">
                <input name="submit" type="submit" value="Send Message" />
            </div>
      </fieldset>
</form>';

Thanks for any and all responses.

Chuck

Hi,
The array shown below is causing problems. I know this for sure because when I comment the array out the script runs. Is it: 'pswrd1'=>SHA1('$_POST['pswrd1']') inside the array causing the script not to run?? All help will be greatly appreciated.

$register_data =
array('username'=>$_POST['username'], 'first_name'=>$_POST['first_name'], 'last_name'=>$_POST['last_name'], 'address'=>$_POST['address'], 'postcode'=>$_POST['postcode'], 'country'=>$_POST['country'], 'e_mail'=>$_POST['e_mail'], 'pswrd1'=>SHA1('$_POST['pswrd1']'), 'phone_no'=>$_POST['phone_no']);

I am echoing a variable that is an array.  I want to change the first part of the variable but don't know how to manipulte names inside the ['brackets']
Code: [Select]

echo $row['v1_name']);?>



lets say I have a value called $var = v1.  How do I substitute that like this:
Code: [Select]
echo $row[$var.'_name']);?>
I know the above doesnt work, but thats what i want it to do :-)

Trying to figure out how to make it so name is a link to the profile when its echo
anyone know how to do this?

im at a huge stand still


Code: [Select]
<?php 

                                                $sql = "SELECT name FROM users WHERE DATE_SUB(NOW(),INTERVAL 5 MINUTE) <= lastactive ORDER BY id ASC"; 
$query = mysql_query($sql) or die(mysql_error());
$count = mysql_num_rows($query);
$i = 1;
while($row = mysql_fetch_object($query)) {
 $online_name = htmlspecialchars($row->name);


   echo '<a href="Inbox.php">"'[$goauld]'</a>"'; ?>

I want to define a function instead of repeating query in all my php pages. I call a function by passing an $id value and from that function i have to get all the info related to that id, like name, description and uom.    I am trying to do this, but i dont know how to get these values seperately.   here is my function  

function items($item_id)
{
$details = array(); 
$result = mysql_query("select item_id, name, uom, description from items where item_id=".$item_id."") or die (mysql_error());
while($row = mysql_fetch_array($result))
{
$details[] = array((stripslashes($row['name'])), (stripslashes($row['uom'])), (stripslashes($row['description'])));
}
return $details;
}

and i call my function like this

$info = items($id);

Can somebody guide me in this    

I tried these below,
Code: [Select]
class Site extends Controller
{
  function Site()
 {
    public $data = Array();
 }
}

but it fail?

Thanks in advanced.

I have a function that get's a quick single item from a query:

function gimme($sql) { 
global $mysqli; 
global $mytable; 
global $sid; 
$query = "SELECT ".$sql." FROM ".$mytable." WHERE sid = ".$sid; $result = $mysqli->query($query); 
$value = $result->fetch_array(MYSQLI_NUM); 
$$sql = is_array($value) ? $value[0] : ""; 
return $$sql; // this is what I've tried so far 
$result->close(); 
}

It works great as:

echo(gimme("name"));

Then I realized that I could use that as a variable ('$name' in this case) elsewhere. However, I can't figure out how get that new, variable variable 'outside' of the function.  As such,

echo($name);

isn't working outside the function.  Is there a way to return a variable variable?  In other words, is there a way to make a function that creates a variable variable that will available outside of the function?

 

Thanks

 

I have included language file and function file in my index.php

include 'includes/functions.php';
include 'languages/english.php';

english.php contains

<?php
$lang['success']['a'] = 'Settings have been updated.';
$lang['error']['b'] = 'Database error. Please try again later!';

.................................
?>

functions.php

<?php
function testFunction($id, $settings, $db){
	
	$query = 'UPDATE table_name SET a = a + :a WHERE id = :id';
	$update = $db->prepare($query);
	$update->bindParam(':a', $settings['a'], PDO::PARAM_INT); 
	$update->bindParam(':id', $id, PDO::PARAM_INT);  
	$success = $update->execute();
	
	if($success){
		print $lang['success']['a'];
	}else{
		print $lang['error']['b'];
	}
	
}

.................................................

?>

Now if i print testFunction(); i got Undefined variable: lang in .............  If i include 'languages/english.php'; in testFunction() then everything works. Any other way to make $lang working without including language file in testFunction(). (Sorry for my  bad english)

print testfunction(2, $settings, $db);

Hi,
I'm an novice/intermediate PHP prgogrammer, so excuse me if this is a stupid question.

I have one php program that consist of a few functions. Inside the function taht is the starting point I pickup a few entries from a MYSQL database, and display those in my html page.

I wish to dynamically put a link on those entries that makes it possible for the users to click those entries an get directed to other functions inside this very same PHP program WITH a parameter. The parameters that should accompany the url/link into the selected function to be able to select apropriate records from the mysql tables.

Any hints and tips for this would be highly appreciated!

Kind Regsrds,

Terje Hvidsten.

Hey

Before I start playing around with some code I want to know if it is possible to call a function inside a while loop that will call echo a some stuff then return to the loop it got called by?

thanks