PHP - How Do I Store 3 Values In An Array?
I want to store...
- questionID - questionNo - questionText ...in one array? How do I do that?! Debbie Similar Tutorialsi'm trying to get all the results from a query search into an array and them have another query search the results from that array againts a different table to get the right results. Here is my code: Code: [Select] $name = $_GET['name']; //lets say $name = 'california' $get_state = mysql_query("SELECT * FROM locations WHERE state LIKE '$name'") or die(mysql_error()); $num_states = mysql_num_rows($get_state); $location_array = array(); $i = 0; while($state = mysql_fetch_assoc($get_state)){ $location_array[$i][] = $state['id']; $i++; } $get_buildings = mysql_query("SELECT * FROM points WHERE location_id='".implode(",", $location_array)."' ORDER BY name ASC") or die(mysql_error()); However i can't get any results. I tried outputing the array by imploding it and all i got was "array, array, array, array," I hope someone here can help me out. I am pulling 5 addresses and I am wanting to store these 5 addresses in columns in a separate table. On the query string I put LIMIT 5. How can I store the results of each of the 5 loops into columns in a separate table? The columns are A1(for name), A2(for address), A3 (for city), A4 (for state), A5 (for zip), A6 (for phone), A7 (for miles), .... then I also have B1-B7, C1-C7, D1-D7, and E1-E7. I am basically wanting to store up to 5 addresses in an array and then update them into a mysql table. Code: [Select] foreach ($zips as $key => $value) { $result = mysql_query("SELECT State FROM extreme WHERE Zip = '$key' AND Type='store' AND `InStore` <> 'NO' LIMIT 5", $db); $num_rows = mysql_num_rows($result); while($myrow = mysql_fetch_array ($result)) { $Dealer=$myrow['Dealer']; $Address=$myrow['Address']; $City=$myrow['City']; $State=$myrow['State']; $Zip=$myrow['Zip']; $Phone=$myrow['Phone']; $Miles = $value; } } Hello, I have a variable called $Price, We are getting it through Mysql Database using While loop. We getting the data from database in ordered by ID. Now then i have requirement to store that data into Low to High form ... Like we are receiving $price lke unordered form .. 50 14 35 25 00 145 52 Here i just want to store it in Low to high form like 00, 14,25,35 ... and so on .. Please suggest me the appropriate code. While($myrow=mysql_fetch_array($result, MYSQL_ASSOC)) { some codes return value $price. // want to store in array } $array($price) // here want to store in Low to high with key value. This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=327616.0 hi i am trying to make a payroll calculator script that takes employee info, calculates pay, displays submitted info in a table, stores info in an array, and updates the array when new info is submitted. i have most of these accomplished, i am having trouble with the "store into an array, and update the array when new info is submitted" parts of the project. i am still not very fluent in php so there may be easier ways to achieve what i have so far. any pointers would be a great help, this part has got me stumped. Hi, I have this form which will create a checkbox list using data from my database and also determin if a checkbox had been checked before and check if it had. <form style="text-align:center" name="PrefRestaurant" id="PrefRestaurant" action="preferances_check.php" method="post"><table align="center"> <?php checkbox(id, name, restaurants, id); ?></table> <input type="submit" name="Prefer" id="Prefer" value="Επιλογή"/></form> function checkbox($intIdField, $strNameField, $strTableName, $strOrderField, $strMethod="asc") { $strQuery = "select $intIdField, $strNameField from $strTableName order by $strOrderField $strMethod"; $rsrcResult = mysql_query($strQuery); while ($arrayRow = mysql_fetch_assoc($rsrcResult)) { $testqry = "SELECT * FROM user_restaurant WHERE user_id = $_SESSION[UserId] AND restaurant_id = $arrayRow[id]"; $rsltestqry = mysql_query($testqry); $numrows = mysql_num_rows($rsltestqry); if ($numrows == 1) { echo "<tr align=\"left\"><td><input type=\"checkbox\" name=\"restaurant[]\" value=\"$arrayRow[id]\" checked/>$arrayRow[name]</td></tr>"; } else{ echo "<tr align=\"left\"><td><input type=\"checkbox\" name=\"restaurant[]\" value=\"$arrayRow[id]\" />$arrayRow[name]</td></tr>"; } } } Now the part which I can't get to work is when I'm trying to store the new values in my database. When I click the submit button I clear my database of any row that is related to the currently loggedin user and I want to store his new preferences (checked cheboxes). I've read that only the cheked checkboxes' values are POSTed so I did this (preferances_check.php) foreach($_POST['restaurant'] as $value) { $query="INSERT INTO user_restaurant VALUES ('$_SESSION[UserId]','$value')"; } But it is not working, nothing gets written in my table Could someone please enlighten me on this? Thnks! hey i am using a MySql database and i need to create a dynamic HTML table with one of its columns as checkboxes.so i have to create multiple checkboxes.but these checkbox values are to be stored in a mysql table and then later retrieved when form reloads.and depending on previous state when form was submitted, the newly created checkboxes have to be checked in the same manner.so how do i store multiple checkbox values in my table and also how do i retrieve them? please help. Hello all, I have an error handler that I need to append messages to (First name not right, Last name not right, etc) I'm using a session array to handle all error messages titled GORB. How come this code won't work? $_SESSION['GORB']['message'][] = "First name wrong"; $_SESSION['GORB']['message'][] = "Last name wrong"; How can I get it to work? I already have the handler output written and functioning fine, I just need to get it to loop over an array of errors instead of just one. hello, um i got a form that stored an array of variables upon users clicks. it submits to another page fine as an array and i can print them using if(!empty($_POST['langSpoken'])) { echo "\n<p><strong>You selected the following LangSpoken:</strong></p>\n<ul>"; foreach($langSpoken as $lang) { // exclude any items with chars we don't want, just in case someone is playing if(!preg_match('/^[-A-Z0-9\., ]+$/iD', $lang)) continue; // print the lang echo "\n\t<li>" . htmlspecialchars($lang) . "</li>"; } echo "\n</ul>"; } else { echo "\n<p>No items selected</p>"; } it prints a list a of array like english spanish but i need to store each one in one variable so i can store in a database is there a way? thanks Hi, I'm trying to store the first+lastname from my mysql user datababase into arrays like this: // Fill up array with names $a[]="Anna"; $a[]="Brittany"; $a[]="Cinderella"; $a[]="Diana"; $a[]="Eva"; $a[]="Fiona"; $a[]="Gunda"; $a[]="Hege"; $a[]="Inga"; $a[]="Johanna"; $a[]="Kitty"; $a[]="Linda"; $a[]="Nina"; $a[]="Ophelia"; $a[]="Petunia"; $a[]="Amanda"; $a[]="Raquel"; $a[]="Cindy"; $a[]="Doris"; $a[]="Eve"; $a[]="Evita"; $a[]="Sunniva"; $a[]="Tove"; $a[]="Unni"; $a[]="Violet"; Hello, I'm trying to store the match I get in $result to a variable so that I can easily compare its other values against other values. Here is my code.. //loop through new orders array foreach ( $orders as $order ) { //compare job number and line item against database information for a match if ( array_search ( $order[ 'job_number' ], array_column ( $result, 'job_number' ) ) !== false && array_search ( $order[ 'line_item' ], array_column ( $result, 'line_item' ) ) !== false ) { $db_match = key($result); echo '<br><br>'.$db_match.'<br><br>'; echo 'Job: ' . $order['job_number'] . '/Line Item: ' . $order['line_item'] . ' was found<br>'; //new order which doesn't exist in database } else { echo 'Job: ' . $order['job_number'] . '/Line Item: ' . $order['line_item'] . ' was not found<br>'; } } When I do $db_match = key($result); I get 0 each time and when I do: $db_match = array_search ( $order[ 'job_number' ], array_column ( $result, 'job_number' ) ) !== false && array_search ( $order[ 'line_item' ], array_column ( $result, 'line_item' ) ) !== false; I get 1 each time...which I assume is the number of matches which meet that criteria instead of the array key I found a match on. Edited May 8, 2020 by mongoose00318Hi all, I'm a first time poster here and I would really appreciate some guidance with my latest php challenge! I've spent the entire day googling and reading and to be honest I think I'm really over my head and need the assistance of someone experienced to advise the best way to go! I have a multi dimensional array that looks like (see below); the array is created by CodeIgniter's database library (the rows returned from a select query) but I think this is a generic PHP question as opposed to having anything to do with CI because it related to working with arrays. I'm wondering how I might go about searching the array below for the key problem_id and a value equal to a variable which I would provide. Then, when it finds an array with a the matching key and variable, it outputs the other values in that part of the array too. For example, using the sample data below. How would you recommend that I search the array for all the arrays that have the key problem_id and the value 3 and then have it output the value of the key problem_update_date and the value of the key problem_update_text. Then keep searching to find the next occurrence? Thanks in advance, as above, I've been searching really hard for the answer and believe i'm over my head! Output of print_r($updates); CI_DB_mysql_result Object ( [conn_id] => Resource id #30 [result_id] => Resource id #35 [result_array] => Array ( ) [result_object] => Array ( ) [current_row] => 0 [num_rows] => 5 [row_data] => ) Output of print_r($updates->result_array()); Array ( [0] => Array ( [problem_update_id] => 1 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Some details about a paricular issue [problem_update_active] => 1 ) [1] => Array ( [problem_update_id] => 4 [problem_id] => 3 [problem_update_date] => 2010-10-01 [problem_update_text] => Another update about the problem with an ID of 3 [problem_update_active] => 1 ) [2] => Array ( [problem_update_id] => 5 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of four [problem_update_active] => 1 ) [3] => Array ( [problem_update_id] => 6 [problem_id] => 4 [problem_update_date] => 2010-10-12 [problem_update_text] => An update about the problem with an ID of 6 [problem_update_active] => 1 ) [4] => Array ( [problem_update_id] => 7 [problem_id] => 3 [problem_update_date] => 2010-10-12 [problem_update_text] => Some new update about the problem with the ID of 3 [problem_update_active] => 1 ) ) Hi there I have a MySQL database table that has multiple records which look like (1, Which of these are your favorite color(s)?, Red||Blue||Orange||Green, question-type1 ) I have written some PHP code in extracting that data into a HTML form. (The above data looks like a question with multiple options (radio buttons/checkboxes) below it). Below is what I'm trying to achieve: When the action is Submit: store the question number, user responses of the options , time stamp and user name into a new database table. I came to know that passing arrays will do the job, but I got stuck in the middle. Please see the attached documents that has the code. TIA [attachment deleted by admin] The Script:
<form method="post" action="<?php echo $_SERVER['PHP_SELF'] ?>"> <input type="text" name="hashtags" /> <input type="submit" name="submit" /> </form> <?php include("connect.php"); ?> <?php if(isset($_POST['submit'])){ $hashtags = explode(", ", $_POST['hashtags']); for($i= 0; $i < count($hashtags); $i++){ $tqs = "SELECT `id` FROM `hashtags_two` WHERE `hashtags` = '" . $hashtags[$i] . "'"; $tqr = mysqli_query($dbc, $tqs) or die(mysqli_error($dbc)); } $fetch_array = array(); while($row = mysqli_fetch_array($tqr)){ $fetch_array[] = $row['id']; } }Hey, sorry for these fundamental array questions lately, I am not going to ask much more when it comes to this. The hashtags come from the submit form (separated by commas) and get stored inside an array with the "explode()" function. The script should select the ID numbers of the hashtags from the table. With the script above only the last row gets inserted into $fetch_array inside the while loop. When the $fetch_array variable is printed on screen then only one ID number can be seen inside the array: Array ( [0] => 24 )How can I have the other ID numbers too? hello dear php-experts,
well i want to do some data-saving in the next few days. i have some data amount to store in a mysql-db.
well i am pretty sure this is a easy question for php-freaks
the question is: from plain-text to mysql-db: how to store a triple / array? how to store this data into a mysql-db have a dataset of 10 000 lines: {'data_1': 'data_2', 'data_3': 'data_4', 'data_5': 'data_6', 'data_7': 'data_8'} how to store this dataset into the mysql db ? love to hear from you greetings Hi I have a results page from a MySQL query and I have implemented pagination to present data in chunks of 25 per page in a table view (each row => 1 entry). My problem is that next to each data row, I have a selection checkbox, and if the user clicks on it, he can download the selected entries. This thing worked OK before I employed paginated view, when I presented all data in one page. Now, if I select e.g. 2 entries in page 1, then I jump to page 12 and select another 2 entries, if I click on the "Retrieve" button, I get only the last 2 entries (from the last page visited). How can I solve this problem? With JS? Can I use PHP only? Hi, I want to store files to variable array using glob() like $files[0] = xyz.txt $files[1] = pqr.txt . . . $files[n] = nfile.txt I know how to list files from directory using glob() Code: [Select] <?php foreach (glob("*.txt") as $filename) { echo "$filename size " . filesize($filename) . "\n"; } ?> How can I do that ? Hi there, Basic question, but I can't seem to find a page in the PHP docs that answers (though I'm sure such a one exists, I just can't seem to think up the right search terms - anyway) My question is: is there a short-hand way to use a value from an associative array as the key in another associative array? So for example, given this array: $the_array = array(0 => array('name': 'the_name', 'value' : 'the_value'), 1 => etc....); then this kind of foreach loop doesn't work Code: [Select] $new_data = array(); foreach($the_array as $element){ $new_data[$element['name']] = $element['value']; } Obviously I can just save out the values, like $name = $element['name'] --- but I was just wondering if there was a more efficient way to do it? Cheers, PS. I tried encapsulating with {} - i.e. $new_data[{$element['name']}] --- but that also fails. I have mysql select query shown below retrieving data from a database:
$sql = " SELECT student, sum( test_score ) as score FROM test INNER JOIN level ON test.level_id = level.level_id GROUP BY student" $result = $mysqli->query($sql, MYSQLI_STORE_RESULT); if($result) { while ($row = $result->fetch_array(MYSQLI_ASSOC)) { var_dump($row); } }On inspection of the retrieved array with var_dump(), i have these result below: array (size=2) 'John' => string 'English' (length=2) 'Score' => string '20' (length=3) array (size=2) 'Mary' => string 'Math' (length=3) 'Score' => string '35' (length=3) array (size=2) 'Samuel' => string 'Physics' (length=3) 'Score' => string '5' (length=3)How do I get at and print out the highest score from this set of array values within this context. I tried this echo max($row['count']) but i understandably got this feedback: Warning: max(): When only one parameter is given, it must be an array Thanks. |