|
PHP - Unable To Update
Hello,
I've never really used the update command before for mysql and I'm attempting to use it and struggling a little bit. I'm trying to use mysqli prepared statements.. here's the code that I have thus far: if($query = $database->connection->prepare("UPDATE videos SET comments=?, views=?, uploader=? WHERE title = ?")) { $query->bind_param('iiss', $comments, $views, $uploader, $title); $query->execute(); $result = $query->affected_rows; $query->close(); } For some reason I cannot get this working. I have created a modification page for the administrators to be able change any of the values and wanting to update the database to reflect the changes. When using the MySQL UPDATE command do all of the values have to get changed or modified, or am I able to pass back some of the same values? Like with the above code.. if I only wanted to update the views, would I still be able to just pass in the same values for comments and uploader and it would just replace the values? Similar TutorialsHey guys, Im trying to get a page to update profiles working and have been unsuccessful. Its a basic form with a server.php to process the updates. Server.php
$username = mysqli_real_escape_string($db, $_POST['username']);
$email = mysqli_real_escape_string($db, $_POST['email']);
$password_1 = mysqli_real_escape_string($db, $_POST['password_1']);
$password_2 = mysqli_real_escape_string($db, $_POST['password_2']);
$location = mysqli_real_escape_string($db, $_POST['location']);
$class = mysqli_real_escape_string($db, $_POST['class']);
$id = mysqli_real_escape_string($db, $_POST['id']);
if (empty($username)) { array_push($errors, "Username is required"); }
if (empty($email)) { array_push($errors, "Email is required"); }
if (empty($password_1)) { array_push($errors, "Password is required"); }
if ($password_1 != $password_2) {
array_push($errors, "The two passwords do not match");
}
if (count($errors) == 0) {
$password = password_hash($password_1, PASSWORD_DEFAULT);
$query = "(UPDATE accounts SET password='".$password."', username='".$username."', email='".$email."', role='".$role."', class='".$class."' )";
mysqli_query($db, $query);
$_SESSION['username'] = $username;
$_SESSION['success'] = "Update Successful for user: " . $username;
header('location: index.php');
}
}
update.php
<?php
session_start();
if (!isset($_SESSION['loggedin'])) {
header('Location: ../login.php');
exit();
}
if($_SESSION['class'] == 'user') {
// Jump to user page
header('Location:../user/home.php');
}
?>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1" />
<title>New User Registration</title>
<link rel="stylesheet" type="text/css" href="../css/style.css">
<link href="../css/navbar.css" rel="stylesheet" type="text/css">
</head>
<body>
<?php include "../assets/navbar.php" ?>
<div class="header">
<h2>Update User Info</h2>
</div>
<form method="post" action="server.php" class="form2">
<?php include('errors.php'); ?>
<?php
if (isset($_SESSION['success']) && ! empty($_SESSION['success'])) {
echo "<div class='success'>" . htmlentities($_SESSION['success']) . "</div>";
unset($_SESSION['success']);
}
$id = $_REQUEST['id'];
$username = $_REQUEST['username'];
$location = $_REQUEST['role'];
$email = $_REQUEST['email'];
$password = $_REQUEST['password'];
$class = $_REQUEST['class'];
?>
<div class="input-group">
<input type="hidden" name="id" placeholder="<?php echo $id; ?>" value="<?php echo $id; ?>">
</div>
<div class="input-group">
<input type="text" name="username" placeholder="<?php echo $username; ?>" value="<?php echo $username; ?>">
</div>
<div class="input-group">
<input type="email" name="email" placeholder="Email Address?" value="<?php echo $email; ?>">
</div>
<div class="input-group">
<input list="location" name="location" class="form-control" placeholder="<?php echo $location; ?>" required>
<datalist id="location">
<option value="Manny">
<option value="Nate">
<option value="Jay">
<option value="Imran">
<option value="Sanat">
<option value="Minahan">
</datalist>
</div>
<div class="input-group">
<input list="class" name="class" class="form-control" placeholder="<?php echo $class; ?>" required>
<datalist id="class">
<option value="user">
<option value="admin">
<option value="disabled">
</datalist>
</div>
<div class="input-group">
<input type="password" placeholder="Password" name="password_1">
</div>
<div class="input-group">
<input type="password" placeholder="Confirm Location" name="password_2">
</div>
<div class="input-group">
<button type="submit" class="btn" name="reg_user">Update</button>
</div>
</form>
</body>
</html>
When I process the update it gives me a success message but the data in the table is not updated at all. Any suggestions on what im doing wrong here? Hi i have this simple update form and scrip but somehow it doesnt seem to be update the field on the database can someone help out please. The html form is the second form bellow where the action send to status_update.php HTML FORM Code: [Select] <?php include("../header.html"); ?> <?php include("header_news.html"); extract($_REQUEST,EXTR_SKIP); ?><?php /* print("sfilm_refnum = $sfilm_refnum<BR>"); print("sfilm_addr01 = $sfilm_addr01<BR>"); print("sfilm_postcode = $sfilm_postcode<BR>"); print("Film Client = $fclient<BR>"); */ ?> <form id="search" action="list.php" method="post" name="search"> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td align="right" width="140"></td> <td width="320"><span class="hofblack10"> </span> </td> <td align="center" width="100"><input type="hidden" name="lstart" value="<?php print("$lstart"); ?>" /><input type="hidden" name="lend" value="<?php print("$lend"); ?>" /><input type="hidden" name="lamount" value="<?php print("$lamount"); ?>" /></td> <td align="center" width="100"></td> <td align="right"></td> </tr> </table> </form> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#4050c4"> <tr> <td width="60" class="hofwhite10">action</td> <td width="140"><span class="hofwhite14">DATE</span></td> <td width="80"><span class="hofwhite14">ID</span></td> <td><span class="hofwhite14">News Titile</span></td> <td width="100"><span class="hofwhite14">Status</span></td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table><table width="780" border="0" cellspacing="0" cellpadding="4"><tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> <tr height="0"> <td width="60" height="0"></td> <td width="80" height="0"></td> <td height="0"></td> <td align="right" width="120" height="0"></td> </tr> </table> <?php //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select DATABASE."); $query2="SELECT * FROM news WHERE !(news_status='deleted')"; $result2 = mysql_query($query2) or die("Couldn't execute QUERY - Select NEWS Qty"); $fqty = mysql_num_rows($result2); //SELECT or FIND the same USERNAME $query3="SELECT * FROM news WHERE !(news_status='deleted') ORDER BY news_id DESC"; $result3 = mysql_query($query3) or die("Couldn't execute QUERY - Select NEWS"); while ($row = mysql_fetch_array($result3)) { $news_id = $row['news_id']; $news_title = $row['news_title']; $news_story = $row['news_story']; $news_image = $row['news_image']; $news_image_caption = $row['news_image_caption']; $news_image_link = $row['news_image_link']; $news_date_day = $row['news_date_day']; $news_date_month = $row['news_date_month']; $news_date_year = $row['news_date_year']; $news_status = $row['news_status']; $news_website = $row['news_website']; $news_date_created = $row['news_date_created']; $news_date_modified = $row['news_date_modified']; ?> <table width="780" border="0" cellspacing="0" cellpadding="4" bgcolor="#eeeeee"> <tr> <td width="60"><span class="hofblack10"> <?php if($news_status=="deleted"){ print("<a class='hifblack10'>deleted</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>edit</a>"); } ?> </span></td> <td width="140"><span class="titlegrey12"> <?php if(!$news_date_day) { echo "00"; } else{ echo $news_date_day; } echo "/"; if(!$news_date_month) { echo "00"; }else{ echo $news_date_month; } echo "/"; if(!$news_date_year) { echo "0000"; }else{ echo $news_date_year; } ?> </span></td> <td width="80"><span class="titlegrey12"><?php print("$news_id"); ?></span> </td> <td><?php if($news_status=="deleted") { print("<class='hofblack10'>$news_title</span>"); }ELSE{ print("<a class='blueul' href='edit.php?id=$news_id'>$news_title</a>"); } ?></td> <td width="100"> <form id="list_update" action="status_update.php" method="post" name="list_update"> <select name="newnstatus" size="1"> <option <?php if($row['news_status'] == "") { print("selected"); } ?> selected="selected" value="">Status...</option> <option <?php if($row['news_status'] == "on") { print("selected"); } ?> value="on">On</option> <option <?php if($row['news_status'] == "off") { print("selected"); } ?> value="off">Off</option> <option <?php if($row['news_status'] == "deleted") { print("selected"); } ?> value="deleted">Delete</option> </select> <input type="hidden" name="nstatus" value="<?php echo $row[news_status]; ?>" /> <input type="hidden" name="id" value="<?php echo $row[news_id]; ?>" /> <input type="submit" name="update" value="update" /> </form> </td> </tr> <tr height="0"> <td bgcolor="white" width="60"></td> <td bgcolor="white" width="140" height="0"></td> <td bgcolor="white" width="80" height="0"></td> <td bgcolor="white" height="0"></td> <td bgcolor="white" width="100" height="0"></td> </tr> </table> <?php } mysql_close($connection);//}?> <table width="780" border="0" cellspacing="0" cellpadding="4"> <tr> <td width="60"></td> <td width="80"></td> <td><a class="blueullrg" href="add.php">Add News</a></td> <td align="right" width="120"></td> </tr> </table><?php // include("list_navigation.html"); ?> <?php include("../footer.html"); ?> </div></body></html> The action script php Code: [Select] <?php /* echo "fstatus: ".$fstatus."<BR>"; echo "id: ".$id."<BR>"; echo "fclient: ".$fclient."<BR>"; echo "newfstatus: ".$newfstatus."<BR>";*/ //set the date of agreement $timestamp = date('l jS \of F Y h:i:s A'); //get the DB connection variables include("../../../includes/config.php"); //connect to DB $connection = @mysql_connect($db_address,$db_username,$db_password) or die("Couldn't CONNECT."); $db = @mysql_select_db($db_name, $connection) or die("Couldn't select FILMS DATABASE."); // All appears well, so enter into database $query= "UPDATE news SET news_status = '$newnstatus' WHERE news_id='$id'"; $result = mysql_query($query) or die("could not execute query - Update FILMS Record to DB"); //setup an email to the Admin @ hof, w/o attachment $emailto="xx@xxx.co.uk"; $emailfrom="no-reply@xxxx.co.uk"; $emailsubject="xx Record Updated"; $emailmessage="Hello Registrar\n\n"; $emailmessage.="News ID: ".$id."\n"; $emailmessage.="Updated on: ".$timestamp."\n\n"; $emailmessage.="Status was: ".$nstatus."\n"; $emailmessage.="Status now: ".$newfnstatus."\n"; $emailmessage.="Thank you,\n\n"; $emailmessage.="Web Site ROBOT\n"; $emailmessage.="(Administrator)\n"; $emailmessage.="xxx.co.uk | xxx.biz\n"; $emailmessage.="----------------------------------------------\n"; $emailmessage.="e. http://www.xxx.co.uk/contact.php\n"; $emailmessage.="w. http://www.xxx.co.uk\n"; $emailheader="From: xxx.co.uk<$emailfrom>"; $emailheader .= 'Cc: xxx@xxx.co.uk'."\r\n"; $emailheader .= 'Bcc: xxx@xxxxx.co.uk'."\r\n"; $ok=mail($emailto,$emailsubject,$emailmessage,$emailheader); mysql_close($connection); if ($ok) { header("Location: list.php"); /* Redirect browser */ exit; } else { $errmsg="There was a problem, please try later or telephone us direct."; $errsta="1"; include("edit_error.html"); //echo "<p>Mail could not be sent. Sorry!</p>"; exit; } ?> Thanks in advance Can anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; what Im basically trying to do is just like a phpmyadmin function... you select rows you want to update with a checkbox and then it takes you to a page where the rows that are clicked are shown in forms so that you can view and edit info in them... and then have 1 submit button to update them all at once. As the title says I need help with multiple update system.. Can't really get it to work at all >.< Here's some code: $selectt = mysql_query("SELECT * FROM exercises WHERE user='" . $_SESSION["user"] . "' AND exname='" . $_GET["edit"] . "'"); echo '<form method="POST" action="exercises.php?edited">'; echo '<div id="newexx">'; while($raw = mysql_fetch_array($selectt)) { echo '<input type="text" name="up[' . $raw["id"] . ']" value="' . $raw["swe"] . '">'; echo '<input type="text" name="up1[' . $raw["id"] . ']" value="' . $raw["eng"] . '"><br>'; echo '<input type="hidden" name="id[' . $raw["id"] . ']">'; } echo '</div>'; echo '<input type="submit" value="Update Exercise">'; echo '</form>'; if(isset($_GET["edited"])) { $swe = $_POST["up"]; $eng = $_POST["up1"]; $id = $_POST["id"]; foreach($id as $value => $index) { $update = "UPDATE exercises SET swe='".$swe."', eng='".$eng."' WHERE id='".$index."'"; mysql_query($update); } Would be thankful for reply! Hi Guys, I want my UPDATE function from the code below to only update those fields that are NOT empty - if they are empty on submit then do not update or change any values from that field. I know that sounds odd, but with my file fields, when I submit to change something else at a later date it will overwrite the photo, download1,2 & 3 values and as a result I loose my files from the mysql table. Cheers, S <?php include('config.php'); if (isset($_GET['Ter']) ) { $ter = (int) $_GET['Ter']; if (isset($_POST['submitted'])) { //Photo & Document Upload Upload $timestamp_photo = time(); $timestamp_download1 = time(); $timestamp_download2 = time(); $timestamp_download3 = time(); //This is the directory where the files will be saved //Photos $photo_target = "images/"; $photo_target = $photo_target .$timestamp_photo. basename( $_FILES['photo']['name']); //Documents $download_target = "documents/"; $download_target1 = $download_target .$timestamp_download1. basename( $_FILES['download1']['name']); $download_target2 = $download_target .$timestamp_download2. basename( $_FILES['download2']['name']); $download_target3 = $download_target .$timestamp_download3. basename( $_FILES['download3']['name']); //This gets all the other information from the form $photo = ($_FILES['photo']['name']); $download1 = ($_FILES['download1']['name']); $download2 = ($_FILES['download2']['name']); $download3 = ($_FILES['download3']['name']); //Pause Photo/Document Upload foreach($_POST AS $key => $value) { $_POST[$key] = mysql_real_escape_string($value); } $sql= "UPDATE `ter` SET `Ter` = '{$_POST['Ter']}' , `BranchName` = '{$_POST['BranchName']}' , `BranchAddress` = '{$_POST['BranchAddress']}' , `BranchTel` = '{$_POST['BranchTel']}' , `BranchEmail` = '{$_POST['BranchEmail']}' , `BranchLink` = '{$_POST['BranchLink']}' , `Theme` = '{$_POST['Theme']}' , `LocalInfo` = '{$_POST['LocalInfo']}' , `BranchInfo` = '{$_POST['BranchInfo']}' , `photo` = '$timestamp_photo{$_FILES['photo']['name']}' , `download1` = '$timestamp_download1{$_FILES['download1']['name']}' , `download1name` = '{$_POST['download1name']}' , `download2` = '$timestamp_download2{$_FILES['download2']['name']}' , `download2name` = '{$_POST['download2name']}' , `download3` = '$timestamp_download3{$_FILES['download3']['name']}' , `download3name` = '{$_POST['download3name']}' WHERE `Ter` = '$ter' "; mysql_query($sql) or die(mysql_error()); //Unpause Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $photo_target)) { echo "<br />The file ".$timestamp_photo. basename( $_FILES['photo']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download1']['tmp_name'], $download_target1)) { echo "<br />The file ".$timestamp_download1. basename( $_FILES['download1']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download2']['tmp_name'], $download_target2)) { echo "<br />The file ".$timestamp_download2. basename( $_FILES['download2']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload //Writes the photo to the server if(move_uploaded_file($_FILES['download3']['tmp_name'], $download_target3)) { echo "<br />The file ".$timestamp_download3. basename( $_FILES['download3']['name']). " has been uploaded. <br />"; } else { echo ""; } //End of Photo/Document Upload echo (mysql_affected_rows()) ? "<br />Edited Branch.<br />" : "<br />Nothing changed. <br />"; } $row = mysql_fetch_array ( mysql_query("SELECT * FROM `ter` WHERE `Ter` = '$ter' ")); ?> Good morning. I am looking fo some help with an update script to update all rows in a table. This is what I have for a form and all looks well. form.php <?php // run the query and put the results in an array variable called $result $result = mysql_query("SELECT * FROM table ORDER BY 'id', 'title', 'text', 'number'"); print "<form method='post' action='update.php'> <table width='100%' border='0' cellspacing='1' cellpadding='1'><tr> <td align='center'><strong>ID</strong></td> <td align='center'><strong>Title</strong></td> <td align='center'><strong>text</strong></td> <td align='center'><strong>Number</strong></td> </tr>\n"; // start a loop to print all of the courses with their book information // the mysql_fetch_array function puts each record into an array. each time it is called, it moves the array counter up until there are no more records left while ($Update = mysql_fetch_array($result)) { // start displaying the info; the most important part is to make the name an array (notice bookinfo[$i]) print "<td align='center'><p>{$Update['id']}</p></td>\n"; print "<td align='center'><input type='text' name='title' value='{$Update['title']}' /></td>"; print "<td align='center'><input type='text' size='40' name='text' value='{$Update['text']}' /></td>\n"; print "<td align='center'><input type='text' size='40' name='number' value='{$Update['number']}' /></td>\n"; print "</tr>\n"; // add 1 to the count, close the loop, close the form, and the mysql connection } print "<tr> <td colspan='4' align='center'><input type='submit' value='submit' />"; print "</td> </tr> </table> </td> </tr> </form> </table>"; print "</tr>\n"; ?><br /><br /> My question is. How do I update this info into the database with the proper info. ie. Update.php? I created this code to upload a member's main picture on his member page on website. I'll only include the query part of the code since that's what is relevant to my problem. The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page. If a picture already exists, then the script replaces the old picture with the new one upon upload. But for whatever reason I don't understand, when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select] $query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"; $result = @mysql_query($query); $num = @mysql_num_rows($result); if ($num> 0) { //Update the image $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); $_SESSION['error'] = "File updated successfully."; //really should be session success message. header("Location: member.php"); exit; } else { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')"; $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error()); $_SESSION['error'] = "File uploaded succussfully."; //really should be session success message. header("Location: member.php"); } So can anyone tell me what the problem is? Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup? Appreciate your responses in advance. I'm new to PHP and I was able to figure out how to populate data from my database into my text fields. I am trying to add the update information to the same php file; however, I am now receiving errors within the data I was able to populate,
Notice: Undefined variable: stmt in C:\xampp\htdocs\Cust_App\update.php on line 47 and errors with the Update statement
Notice: Undefined variable: stmtupdate in C:\xampp\htdocs\Cust_App\update.php on line 96 I had defined the customerID variable above in the code, but it isn't being captured from here. I tried setting up this query like the one which gathered the data, but I'm off by a little bit. I would like the option to be able to update all fields. Any help is appreciated. I'm trying to learn as I may get asked to update other forms in the future. (new boss asks a lot)
<?php
require_once('database.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<!-- the head section -->
<head>
<title>My Guitar Shop</title>
<link rel="stylesheet" type="text/css" href="main.css" />
</head>
<!-- the body section -->
<body>
<div id="page">
<div id="header">
<h1>SportsPro Technical Support</h1>
<p>Sports management software for the sports enthusiast.</p></h1>
</div>
<div id="main">
<h1>View/Update Customer</h1>
<form action="update.php" method="get" >
<?php
if(isset($_GET['customerID'])) {
$customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT);
$sql = "SELECT * FROM customers WHERE customerID =$customerID ";
$stmt = $db->query($sql);
}
?>
<div id="content">
<!-- display a table of products -->
<h2>Customers</h2>
<form method = "edit">
<?php foreach ($stmt as $cust) { ?>
<div>
<label>First Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['firstName']; ?>">
</div><br>
<div>
<label>Last Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['lastName']; ?>">
</div><br>
<div>
<label>Address</label>
<input type="text" name="address" class ="form-control" value ="<?php echo $cust['address']; ?>">
</div><br>
<div>
<label>City</label>
<input type="text" name="city" class ="form-control" value ="<?php echo $cust['city']; ?>">
</div><br>
<div>
<label>State</label>
<input type="text" name="state" class ="form-control" value ="<?php echo $cust['state']; ?>">
</div><br>
<div>
<label>Country</label>
<input type="text" name="countryCode" class ="form-control" value ="<?php echo $cust['countryCode']; ?>">
</div><br>
<div>
<label>Zip Code</label>
<input type="text" name="postalCode" class ="form-control" value ="<?php echo $cust['postalCode']; ?>">
</div><br>
<div>
<label>Email </label>
<input type="text" name="email" class ="form-control" value ="<?php echo $cust['email']; ?>">
</div><br>
<div>
<label>Phone Number </label>
<input type="text" name="phone" class ="form-control" value ="<?php echo $cust['phone']; ?>">
</div><br>
<div>
<label>Password </label>
<input type="text" name="password" class ="form-control" value ="<?php echo $cust['password']; ?>">
</div><br>
<div>
<?php }
?>
<input type="Submit" name="Update_Data" value="Update Data"></input>
<?php
$sql2 = "UPDATE customers SET firstName = ". $stmtupdate['firstName']." WHERE customerID =$customerID ";
$stmtupdate = $db->query($sql2);
?>
</div>
</div>
<div id="footer">
<p>
© <?php echo date("Y"); ?> SportsPro, Inc.
</p>
</div>
</div><!-- end page -->
</body>
</html>
Code: [Select] <?php function checking_out() { $conn = db_connect(); $nickname=$_SESSION['valid_user']; $query="select sum(price) from preorders where name='".$nickname."'"; $result = $conn->query($query); if ($result) { echo '<h1>'.$result.'</h1>'; } } ?> This is not working, there is no result in the browser, any idea ? Hi all,
I am not sure why my header is not displaying the header image after using the CSS
I have a png file that repeats horizotally.
Please help
<!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title>Wikigets The online store</title> <style type="text/css"> body { margin:0 px;} #pageTop { background: url(style/headerline1.png); height:110 px; } </style> </head> <body> <div id="pageTop"> </div> <div id="pageMiddle"></div> <div id="pageBottom"></div> </body> </html> headerline1.png 2.82KB 0 downloads headerline1.png 2.82KB 0 downloads I get the unable to jump to row zero mysql error. Code: [Select] function is_admin($uid, $cid) { $uid = (int)$uid; $cid = (int)$cid; $sql = "SELECT `users`.`id` AS `uid`, `companies`.`companyid` AS `cid`, `companies`.`adminid` AS `aid` FROM `companies` LEFT JOIN `users` ON `users`.`id` = companies.adminid WHERE `users`.`id` = {$uid} AND `companies`.`companyid` = {$cid}"; $user = mysql_query($sql); return (mysql_result($user, 0) == '1') ? true : false; } First of all, here's what i want it to look:' I just want that the related image must align towards left, and its information is just in front of it. But, what my code does is place the image on above line, and the information on the link below. Here's how it looks with my code. I will be able to make the changes with the File Information. The PHP which is being used is: 1. To fetch if preview is available: Code: [Select] $pre = ''; if ($prew==0) { if ($ext == 'bmp') $pre = 'Impossible Preview <br>'; if ($ext == 'gif' or $ext == 'jpeg' or $ext == 'jpg' or $ext == 'png' or $ext == 'JPG' or $ext == 'GIF' or $ext == 'PNG'or $ext == 'JPEG') $pre = '<img style="align:left;margin: 1px;" src="im.php?bab=1&id='.$file_info['id'].'" alt=""/>'; }2. To insert the preview image: Code: [Select] if($pre!=NULL) echo '<div class="block">'.$pre.'</div>'; 3. And finally the code to fetch file information: Code: [Select] echo '<div class="fileName"><a href="load.php?id='.$file_info[id].'"><font color="red">'.$file_info['name'].''.$extension.'</font></a>|'; if($ext =='txt') { echo '<a href="read.php?id='.$file_info['id'].'&id2='.$id.'"><font color="red">Read</font></a>';} echo $new_info.''; if(!empty($file_info['fastabout'])) echo str_replace("\n", '<br>',$file_info['fastabout']); echo '</div>'; echo '<tr><div class="t_block">'.$ico.'<a href="view.php?id='.$file_info[id].'"><strong>File Info</strong></a></div></tr></td>'; I just can't figure out what to insert with the code. I think it must be some table formatting (TR/TD), but because I'm a noob with PHP, I failed in all my attempts. Please, if anyone could help me out! Hi all, Newbie here, i am having a problem to get my images to show which are stored in mysql database as a mediumblob. I get id number to print in table ut am just getting empty square with red cross in where my image should be. Is my code incorrect or is it something else? Appreciate your help with this. I have included both of the pages codes i am using. Thanks Tony image2.php <?php include("common.php"); error_reporting(E_ALL); $link = mysql_connect(host,username,password) or die("Could not connect: " . mysql_error()); mysql_select_db(db) or die(mysql_error()); $sql = "SELECT id FROM photos"; $result = mysql_query("$sql") or die("Invalid query: " . mysql_error()); ?> <table border="1"><tr><td>id</td><td>image</td></tr> <?php while($row=mysql_fetch_assoc($result)){ print '<tr><td>'.$row['id'].'</td><td>'; print '<img src="image1.php?id='.$row['id'].'height="75" width="100"">'; } echo '</td></tr></table>' ?> image1.php <?php ob_start(); include("common.php"); mysql_connect(host,username,password) or die(mysql_error()); mysql_select_db(db) or die(mysql_error()); $query = mysql_query("SELECT imgage FROM photos WHERE id={$_GET['image_id']}"; $row = mysql_fetch_array($query); $content = $row['image']; header('Content-type: image/jpg'); echo $content; } ob_end_flush(); ?> Hello....I am using ajax,jquery with php to insert data in db.....but the script is not working. form.html: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <style type="text/css"> label{ display:block; } </style> <script type="text/javascript" src="jquery-1.5.min.js"> </script> <script type="text/javascript"> $(function() { $('#submit').click(function(){ $('#container').append('<img src="ajax-loader.gif" id="loading" alt="image" />'); var name=$('#name').val(); var email=$('#email').val(); var d=$('#d').val(); var m=$('#m').val(); var y=$('#y').val(); var add=$('#add').val(); var phone=$('#phone').val(); $.ajax({ url: 'process.php', type: 'POST', data: 'name=' + name + '&email=' + email + '&d=' + d + '&m=' + m + '&y=' + y + '&add=' + add + '&phone=' + phone, success: function(result){ $('#response').remove(); $('#container').append('<p id="response">' + result + '</p>'); $('#loading').fadeOut(500,function(){ $(this).remove(); }); } }); return false; }); }); </script> </head> <body> <h2>User Registeration</h2> <form action="process.php" method="POST"> <div id="container"> Name:<br> <input type="text" name="name" id="name" /><br> Email:<br> <input type="text" name="email" id="email" /><br> Date Of Birth:<br> <input type="text" id="d" name="d" size="2" /> <input type="text" id="m" name="m" size="2" /> <input type="text" id="y" name="y" size="4" /><br> Address:<br> <input type="text" id="add" name="add" /><br> Phone:<br> <input type="text" id="phone" name="phone" /><br> <input type="submit" name="submit" id="submit" value="GO!" /> </div> </form> </body> </html> process.php My db id named "jquery" and table is "tab" Code: [Select] <?php $conns=mysql_connect("localhost","root",""); if(!$conns) echo "error in connection"; mysql_select_db("jquery", $conns); $name=$_POST['name']; $email=$_POST['email']; $m=$_POST['m']; $d=$_POST['d']; $y=$_POST['y']; $add=$_POST['add']; $phone=$_POST['phone']; echo $name,"<br>"; echo $email,"<br>"; echo $m, "<br>"; echo $d,"<br>"; echo $y,"<br>"; echo $add, "<br>"; echo $phone,"<br>"; $query="INSERT INTO tab (name,email,d,m,y,add,phone) VALUES ('$name',$email','$d','$m','$y','$add','$phone')"; if(!mysql_query($query,$conns)) echo "Error"; else echo "DATA inserted"; ?> The output shown is: pulkit pulkit@gmail.com 1 26 1991 lucknow 987576787 Error For some values i entered. ==> MySQL version 5.0.91-community So once upon a time I was working on a CMS. I worked on it for 3 months, had to wipe my computer - but didn't worry about it because I backed up the files on a flash drive... which got smushed by some boxes when I moved <.< awesome -.- Anyway, a year later (ie: today), I've decided to start again from scratch. For me - for whatever reason - the simplest things always seem to give me the most trouble. I decided to start with a "user" table - naturally - and began working on the first page: user_view.php and added an include file that connects to the database (connectDB.php). Since I started today, everything is simple - no design elements yet - just good 'ol code. The View Users Page is simply a page that grabs all the rows from Table: users and prints the information to the screen, as if you were viewing a Members page on a forum. This Page works fine. No complaints, does everything I need it to, prints all the rows and cols from Table Users. Then I created the Edit User Page. When I did this a year ago, and I wanted to print out all the data from the table, I used the while loop. When I wanted to only grab certain variables from a table, I just created a new set of variables, as show below. Using the same method from a year ago, I started working on printing various data to the screen (such as "Welcome $username"). 5 minutes of typing... refresh page... nada. So I stripped away just about every tag but the essentials and it still wouldn't work Code: [Select] <?php ... $userID = 3; $sql = "SELECT * FROM users WHERE userID='$userID'"; $result = mysql_query($sql); $rows = mysql_fetch_row($result); echo $rows['username']; ... ?> Normally, this would just grab the username from a row in Table users where the userID = 3 But instead - it does nothing. I just see a blank page. It's a simple 5 lines of code and it's like "im just gonna do w.e the fk i wanna do mmmk thxforplaying" PS: Keep in mind there is nothing wrong with the connection to the database, and as already stated I'm able to print ALL values from the Users Table using this same method: Code: [Select] <?php ... $user_sql = "SELECT * FROM users ORDER BY username ASC"; $user_result = mysql_query($user_sql); while ( $user_rows = mysql_fetch_array($user_result) ) ... ?> In the given code below I am getting this error Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\samples\getcustomers.php on line 20 WHY? Code: [Select] <?php $value = $_GET["q"]; $con = mysql_connect('localhost', 'root', ''); //db_connect(); if (!$con) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db("ajaxDb",$con); $sql = "SELECT * FROM 'cutomers' WHERE Name = '".$value."'"; // echo $sql; $result = mysql_query($sql); echo "<table border='1'> <tr> <th>Name</th> <th>Address</th> <th>Country</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['Name'] . "</td>"; echo "<td>" . $row['Address'] . "</td>"; echo "<td>" . $row['Country'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Hello. I am coding a remember me feature. Everything is working, except i am being logged in using cookies even when i want to use a session. To login using a cookie i must select the checkbox, for sessions i must leave it blank. Here is my code, if someone could spot a mistake i would be really grateful. Login page Code: [Select] <?php ob_start(); // starting session... session_start(); // requiring connection... require("functions.php"); // assigning variables... $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $submit = mysql_real_escape_string($_POST['submit']); $rememberme = $_POST['rememberme']; // querying database... $query = mysql_query("SELECT * FROM users WHERE username = '$username'"); $numrows = mysql_num_rows($query); if ($numrows != 0) { while ($row = mysql_fetch_assoc($query)) { $db_username = $row['username']; $db_password = $row['password']; } } // verifying login details... if ($submit) { if (!empty($username) && !empty($password)) { if ($username == $db_username && $password == $db_password) { if ($rememberme = "on") { setcookie("username", $username, time() + 7200); header('Location: tablets.php'); } else { $_SESSION['username'] = $db_username; $url = $_SESSION['origin'] ? $_SESSION['origin'] : "main.php"; unset($_SESSION['origin']); header('Location: ' . $url); exit; } } else { echo "Incorrect login details"; } } else { echo "You must type in username and password"; } } ob_end_flush(); ?> Login form Code: [Select] <?php session_start(); require("connect.php"); if (isset($_SESSION['username']) || isset($_COOKIE['username'])) { header('Location: main.php'); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>Login</title> <link rel="stylesheet" type="text/css" href="form.css" /> </head> <body> <form method="post" action="login.php"> <div class="box"> <h1>Login</h1> <label> <span>Username</span> <input type="text" class="input_text" name="username" id="name" /> </label> <label> <span>Password</span> <input type="password" class="input_text" name="password" id="password" /> </label> <input type="checkbox" name="rememberme" /> <label> <input type="submit" class="button" value="Login" name="submit" /> </label> </div> </form> </body> </html> Hi guys, Currently my result displayed a 'comma' at the end Lower Primary English, Math, Science, Chinese, How do I remove the comma which is bold in red? Thank you so much My code Code: [Select] while($row3 = mysqli_fetch_array($data3)) { if ($row3['level_id'] == 2) { echo ''.$row3['subject_name'].', '; } } Hey guys, After my php script a HTML code follows. But i can't edit the HTML code because it isn't recognised. It does show up, however i can't edit it. Problem: Unable to edit HTML code below php scripts Code: <?php function createNewFile($name,$mail,$subject,$comments,$count,$date,$other="",$up="0") { global $settings; $header=implode('',file('header.txt')); $footer=implode('',file('footer.txt')); $content=' ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <html> <head> <title>'.$subject.'</title> <meta content="text/html; charset=windows-1250"> Thanks in advance |
|||||||