PHP - Command Line App To Verify Whether An Email-id Exists Or Not
Hi, suppose I want to write a PHP script that checks whether a valid email address exists or not. There are a number of GUI-based tools to verify this, but is there any command line tool to do the same so that I can use PHP to capture the output?
Similar TutorialsI am making a secure registration for my website and looking for a function that will verify with a user inputted date exists. From my registration html form I am putting a month, day and year , each inputted separately into a single variable: Code: [Select] $bday = $year . "-" . $month . "-" . $day; My birthday input looks like: Code: [Select] <div class=\"Container FormBoxLeft\"> <b>Birthdate:</b> </div> <div class=\"Container FormBoxRight\"> <select name=\"month\"><option value=\"\">-Month-</option> <option value=\"01\">January</option> <option value=\"02\">February</option> <option value=\"03\">March</option> <option value=\"04\">April</option> <option value=\"05\">May</option> <option value=\"06\">June</option> <option value=\"07\">July</option> <option value=\"08\">August</option> <option value=\"09\">September</option> <option value=\"10\">October</option> <option value=\"11\">November</option> <option value=\"12\">December</option> </select> <select name=\"day\"> <option value=\"\"> -Day-</option>'; //Print 31 Days "; for ($x=1; $x<=31; $x++) { echo "<option value='".$x."'"; if(isset($_POST['submit']) && $day == $x) { echo " selected"; } echo ">".$x."</option>\n"; } echo "</select> <input name=\"year\" size=\"2\" maxlength=\"4\" type=\"text\"> So.. What I am asking is.. is there a secure way to check if the date the user inputted exists, or is there a better way to make the form more secure from that part. Upon finding the users birthdate I am also wanting to check if the user is a certain age. Hi all, I'm trying to add a section where it verifies that the email address is active in my register code. My code below is it checking the dnsrr, and if it is not real, I have it die and an error message appears. However, I am getting the error message all the time, whether I am sure the email is working or not. First I declared my email variable ($email), and then after the code below I of course insert the new data in to the database. I'm doing this over my localhost, so is that why it can't verify emails? Or am I setting this up wrong? Code: [Select] <?php $email = trim($_POST['email']); if (False !== strpos($email, '@')) die("Please type in an email address.<br><br><a href=register.php>Continue</a>"); if(!@checkdnsrr($mailDomain,'MX')) die("Not real email address. Please try again.<br><br> <a href=register.php>Continue</a>"); ?> function isValidEmail($email){ return eregi("^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$", $email); } How do I incorporate the code above into my code?? Code: [Select] <?php error_reporting(E_ALL ^ E_NOTICE); ?> <?php // make sure the form has actually been submitted . . . if( strtolower($_SERVER['REQUEST_METHOD']) === 'post' ) { // 1. Create a database connection $connection = mysql_connect("localhost", "root", "maven777"); if(!$connection){ die("Database connection failed: " .mysql_error()); } // 2. Select a database to use $db_select = mysql_select_db("homesloans", $connection); if(!$db_select){ die("Database selection failed: " .mysql_error()); } $radius = ($_POST['radius']); $type = ($_POST['type']); $price = ($_POST['price']); $bedrooms = ($_POST['bedrooms']); $bathrooms = ($_POST['bathrooms']); $parking = ($_POST['parking']); $city = ($_POST['city']); $details = ($_POST['details']); $firstname = ($_POST['firstname']); $lastname = ($_POST['lastname']); $email = ($_POST['email']); $phone = ($_POST['phone']); $query="INSERT INTO leads (leadid, city, radius, type, price, bedrooms, bathrooms, parking, details, firstname, lastname, email, phone) VALUES('NULL', '[$city]', '[$radius]', '[$type]', '[$price]', '[$bedrooms]', '[$bathrooms]', '[$parking]', '[$details]', '[$firstname]', '[$lastname]', '[$email]', '[$phone]')"; mysql_query($query) or die ('Error updating database'); echo "Database Successfully Updated."; // not necessarily. The only way to know for sure is to check that mysql_affected_rows() > 0 } ?> Hi, I'm having a weird issue when I try to run PHP scripts from the command line on my server. I'm trying to just run a very simple script to test it out: #!/usr/bin/php-cgi -q echo "Hello terminal\n"; And I get the following error in the terminal.. Code: [Select] Error in argument 1, char 3: option not found Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f <file>] php-cgi <file> [args...] When I try taking out the quiet (-q) parameter, I get the following error.. Code: [Select] -bash: ./socket_server.php: /usr/bin/php-cgi^M: bad interpreterNo such file or directory As you can see, in the second example, a rogue "^M" was appended to the end of the first line of my socket_server.php file. What does ^M correlate to? I realize it is a character code for something that can't be represented with an actual character, but I don't know what it is, and I'm not sure why it is being appended to the end of my first line. My assumption is that this is happening in the first example too, which is why I get the "error in argument 1" message, since undoubtedly -q^M is an invalid argument... Any help is greatly appreciated! nethnet Hi.. I have a php file where i have only one line which says header('Location: index.php'); How do i run this php file in the terminal on fedora 14? Thanks, Rohit Hi, I am trying to use php to pass some commands to my linux box.From my webpage I am using the shell_exec function which is working OK but for some administrative tasks in linux I must have root access. As I am sending the commands from the webpage the apache user is used and so I am not allowed to do several tasks. I have also tried to use a bash script to pass the commands but with no result. Any ideas ? hey guys m using STDIN as input stream in php command line my problem is that some time i get this error Warning: fgets(): supplied argument is not a valid stream resource in D:\myquery \test.php on line 16 $number=fgets(STDIN); anyone knows solution I am trying to execute a command line tool, but am having a problem adding a variable to the line. Here is the code Code: [Select] $filename = "devices.txt"; $handle = fopen($filename, 'r'); while (!feof($handle)) { $devices = fgets($handle, 4096); $query = 'ipmitool -I lanplus -H 192.168.1.1 -U admin -P adminpass sdr list'; passthru($query); } flcose($handle); On this line I don't want to have the IP manually added like so. Code: [Select] $query = 'ipmitool -I lanplus -H 192.168.1.1 -U admin -P adminpass sdr list'; Instead I want to be able to insert the $devices variable which contains the values from the text file so it would look something like this: Code: [Select] $query = 'ipmitool -I lanplus -H $devices -U admin -P adminpass sdr list'; Problem is the command line tool does not run this way. How do I properly add the $devices variable so the command line tool ipmitool will run with its value? Thanks, Hi guys, I'm trying to run a php script from command line in linux. I installed xampp for linux a.k.a lampp so typing php /path/to/file.php Just brings up a message saying I need to install php. Whats the correct way to do this? can anyone help me with an overwhelming problem ? I want to use this command in the php curl code. curl -v --data "WSCommunityStringRW?2=1200ve50set&Submit=Submit" http://10.2.3.111/Forms/SnmpCommunityString -u "admin:a1s2d3" --anyauth Hello everyone I have a question? I run a PHP script loads about 200 calls simultaneously on Linux environment, so my question is what is best way to run a command line As an example php-f example.php or make it through the apache example "curl http://localhost/example.php" Thank you woren This topic has been moved to Other Web Server Software. http://www.phpfreaks.com/forums/index.php?topic=350801.0 hello dear php-experts how to testrun a drive with command-line? note: i had several blank screens during the last week does this somewhat have to do with the hard-drive? which tests can be done? All, In my registration script I am trying to check if an email address already exists (yawn I know), and I am stuck. The code highlighted in bold is where I want to check if the email exists (notice that form checking is done above that, including sorting out the email address that the user enters) and if it doesnt insert data into the table. Trouble is that on loading the page it simply states the 'already submitted' error before an email is even entered into the form: Code: [Select] if(isset($_POST['name']) && !empty($_POST['name']) AND isset($_POST['email']) && !empty($_POST['email']) AND ($_POST['password']) && !empty($_POST['password'])){ $name = mysql_escape_string($_POST['name']); // Turn our post into a local variable $email = mysql_escape_string($_POST['email']); $password = mysql_escape_string($_POST['email']);// Turn our post into a local variable } $name = mysql_escape_string($_POST['name']); $email = mysql_escape_string($_POST['email']); $password = mysql_escape_string($_POST['password']); if(!eregi("^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$", $email)){ // Return Error - Invalid Email $msg = 'The email you have entered is invalid, please try again.'; }else{ // Return Success - Valid Email $msg = 'Your account has been made, <br /> please verify it by clicking the activation link that has been sent to your email.'; } $hash = md5( rand(0,1000) ); // Generate random 32 character hash and assign it to a local variable. // Example output: f4552671f8909587cf485ea990207f3b [b]$emailCheck = mysql_query("SELECT email FROM users WHERE email = '".$email."'"); if (mysql_num_rows($emailCheck) > 0) { echo "already submitted"; } else {[/b] // We have a match, activate the account mysql_query("INSERT INTO users (username, password, email, hash) VALUES( '". mysql_escape_string($name) ."', '". mysql_escape_string(md5($password)) ."', '". mysql_escape_string($email) ."', '". mysql_escape_string($hash) ."') ") or die(mysql_error()); Thanks in advance, G So, I'm trying to read a file from a different filepath than the current working directory.
I have some simple PHP like this :
<?php $input_map = "readfile.php"; $map_contents = file_get_contents($input_map); echo $map_contents."<br />\n"; ?>And this'll work fine because it's in the same directory but if I try to set $input_map = "/home/...", the browser will return an empty string. This script will work from the command line though. So how do I get file_get_contents() to read from the server's file structure instead of just the working directory? Edit : For example, this will not work through the browser : <?php $input_map = "/home/..."; $map_contents = file_get_contents($input_map); echo $map_contents."<br />\n"; var_dump($map_contents); ?> Edited by MutantJohn, 21 January 2015 - 06:35 PM. I would like to update the DB when a service ends and thought about doing so in the destructor, but I did not make much progress. Then tried using pcntl_signal(), but also didn't get far. Is doing so possible? Thanks /usr/lib/systemd/system/test123.service [Unit] Description=bla After=syslog.target [Service] ExecStart=/usr/bin/php /var/www/testing/__destruct.php [Install] WantedBy=multi-user.target
/var/www/testing/__destruct.php <?php ini_set('display_errors', 1); pcntl_signal(SIGTERM, function() { syslog(LOG_INFO, 'Caught SIGTERM'); die; }); pcntl_signal(SIGHUP, function() { syslog(LOG_INFO, 'Caught SIGHUP'); die; }); pcntl_signal(SIGUSR1, function() { syslog(LOG_INFO, 'Caught SIGUSR1'); die; }); pcntl_signal(SIGINT, function() { syslog(LOG_INFO, 'Caught SIGINT'); die; }); pcntl_signal(SIGABRT , function() { syslog(LOG_INFO, 'Caught SIGABRT '); die; }); /* pcntl_signal(SIGSTOP , function() { syslog(LOG_INFO, 'Caught SIGSTOP '); die; }); */ /* pcntl_signal(SIGKILL , function() { syslog(LOG_INFO, 'Caught SIGKILL '); die; }); */ class Bla { private $bla; public function __construct($bla) { syslog(LOG_INFO, '__construct'); $this->bla = $bla; } public function __destruct() { syslog(LOG_INFO, '__destruct'); } public function start() { $counter=0; $counter2=0; while(true) { $counter++; if($counter>10000000) { $counter2++; $counter=0; syslog(LOG_INFO, '.'); } if($counter2>5) { die('all done!'); } } } } $bla = new Bla('hello'); $bla->start();
Hello all
I'm new to this forum. I've been struggling on this problem for a few days now.
I’m writing a script to automatically push code to a git server. exec(‘git config user.name "’ . $userName . ‘"’); exec(‘git config user.email "’ . $userEmail . ‘"’); exec('git checkout -b ’ . $branch); exec(‘git add --all’); exec(‘git commit -m "’ . $message . ‘"’); exec('git push origin ’ . $branch);
When running the last command, the script stops and asks for a user name, then a password. I tried other forums, searching the net. I'm frustrated...
Thanks in advance. Hey, so I'm trying to check the database if the user and email already exists when registering. <?php include_once('includes/config.php'); if(isset($_POST['submit'])) { $username = $_POST['username'] ? trim($_POST['username']) : null; $password = md5($_POST['password']) ? trim($_POST['password']) : null;; $email = ($_POST['email']); $message = ""; if(empty($username) || empty($password) || empty($email)) { $message = "All fields required"; } else { $sql = "SELECT COUNT(username) AS userNum FROM users WHERE username = :username"; $sql = "SELECT COUNT(email) AS emailNum FROM users WHERE email = :email"; $stmt = $db->prepare($sql); $stmt->bindValue(':username', $username); $stmt->execute(); $row = $stmt->fetch(PDO::FETCH_ASSOC); if($row['userNum'] >0) { die("That username already exists!"); } elseif($row['emailNum'] > 0) { die("That email already exists!"); } $sql = "INSERT INTO users (username, password, email) VALUES (:username, :password, :email)"; $stmt = $db->prepare($sql); $stmt->bindValue(':username', $username); $stmt->bindValue(':password', $password); $stmt->bindValue(':email', $email); $result = $stmt->execute(); if($result) { $message = "Registration was successful"; } } } ?> If I remove this line " $sql = "SELECT COUNT(email) AS emailNum FROM users WHERE email = :email"; the code works but only checks the username. How can I check both? Hi Guys, I'm using the following code to write emails to a .txt file: // Write the email to file $leadsFile = "leads/emails.txt"; $fh = fopen($leadsFile, 'a') or die ("can't open leads file!"); $writeData = "$conEM\r\n"; fwrite($fh, $writeData); fclose($fh); which works great, but i can't figure out how to NOT write an email to the .txt file if it's already on it, i'm not using a database for a change i'm stumped lol thanks for any help guys Graham Hi all, In the process of moving websites off an old win 2008 server and onto a new win 2016 server. I discovered that dns_get_record is failing on the new server. I made a simple test page: $dnsrecs = dns_get_record('google.com'); When i call this as a webpage, it comes back with dns query failed. It comes back instantly, so it's not like it's timing out. But, if i just call the webpage from the command line, it comes back with the dns record. Why would dns_get_record fail when used in a webpage, but work from the command line? I can make outside connections since I was able to send an email to an smtp server. I thought maybe this is a permission issue, but seems odd I'd be able to send an email using php but not do a dns query. Oh, and I have two versions of php installed on this server - 5.4.10 and 7.4.9. The old version is a direct copy from the 2008 server. 7.4.9 is a clean install. Both of them behave the same way. webpage fails, command line works. Also, nslookup works. I also tried switching to using google's name server, but it had no effect on anything. Anyone have any suggestions? |