PHP - Moved: Insert Select
This topic has been moved to MySQL Help.
http://www.phpfreaks.com/forums/index.php?topic=357712.0 Similar TutorialsHi, I would like to do the following in PHP using a MySQL database, but not sure how. select a, b,c etc.. from mailbox where id = X then insert id,a,b,c etc.. into problem When I select, I will be calling the id So I would like it to get data from mailbox and then insert it into problem. How would I go about doing this? Thanks for any help you can give me Hello. I have a simple enough code that takes information from one table and drops it into another. This is great, but I have 2a new complexities that I have been unable to code correctly. A. 'lastname', 'firstname' on table1 need to be combined into 'name' How & Where do I combine these strings and then pass them? Code: [Select] <?php include('dbconfig.php'); // Make a MySQL Connection mysql_connect("localhost", "$user", "$password") or die(mysql_error()); mysql_select_db("$database") or die(mysql_error()); $result = mysql_query( "INSERT INTO table2 (lastname, firstname, email) SELECT lastname, firstname, email FROM table1 WHERE email='someemail@gmail.com' ") or die(mysql_error()); ?> Hi,
I'm really at a loss here.
I have queried a table to get an option list, which returns what I expect but I need to then add it to some current code instead of the fixed option list presented.
The syntax is beyond me.
Please see attached.
Any pointers would be great.
Attached Files
OptionList.txt 1.61KB
7 downloads I have tried several attempts and can get data to select and using echo display it, however, I need to take this data and insert it into the database in a separate table. I have the following which does hafl the job, can I get some pointers on the rest. I have looked everywhere and not found a solution, at all. // Selects the data I need <?php mysql_connect("PRIVATE INFO","PRIVATE INFO","PRIVATE INFO") or die("Could not connect: " . mysql_error()); mysql_select_db("wpdb"); $result = mysql_query("SELECT ID FROM wp_posts WHERE post_title LIKE '%future%' AND post_status = 'publish' OR post_title LIKE '%option%' AND post_content LIKE '%fundamental%' AND post_status = 'publish' ORDER BY post_date DESC"); while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { echo $row['ID']; echo "<br />";}; ?> Thought maybe something like the following would work, but am at a loss: INSERT INTO wp_term_relationships (object_id, term_taxonomy_id, term_order) SELECT ID FROM wp_posts WHERE post_title LIKE '%future%' AND post_status = 'publish' OR post_title LIKE '%option%' AND post_content LIKE '%fundamental%' AND post_status = 'publish' ORDER BY post_date DESC while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) VALUES ($row['ID'], '25', '0') Well, I made this yesterday then realised, I need to check is it exists... I got this but when I go to accept the application and the member exists in the table it enters it anyway... Code: [Select] <?php $member=$_POST['memberid']; $status=$_POST['Status']; $con = mysql_connect("host","user","pass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("a2186214_hbclan",$con); $sql="UPDATE application SET Status = '$status' WHERE ID = '$member'"; $sql1="INSERT INTO table_members(name) SELECT application.Name FROM application WHERE application.ID = '$member'"; if ($status == 'ACCEPTED') { if(mysql_num_rows(mysql_query("SELECT name FROM table_members WHERE name = '$member'"))) { if(mysql_query($sql, $con) or die(mysql_error())) { echo 'Status Changed.<br /><a href="../applications.php">Return To Members List</a>'; } else { die('Could not submit: ' . mysql_error()); } } else { if(mysql_query($sql, $con) or die(mysql_error())) { if(mysql_query($sql1, $con) or die(mysql_error())) { echo 'Status Changed.<br /><a href="../applications.php">Return To Members List</a>'; } } else { die('Could not submit: ' . mysql_error()); } } } else { if(mysql_query($sql, $con) or die(mysql_error())) { echo 'Status Changed.<br /><a href="../applications.php">Return To Members List</a>'; } else { die('Could not submit: ' . mysql_error()); } } mysql_close($con); ?> could anyone please help me with the code which is i have already displayed data as a multi select list but now i need to select one or more from them and insert into another database table. would be appreciate your help. thanx I am simply trying to insert a value generated from an array in a while loop, but it seems the value is not global and I can't pass it as I like. I did some research on this, but could not find an answer that solved my issue... Here is my select box code which is working perfect: <select name="city"> <?php $sql = "SELECT id, city_name FROM cities ". "ORDER BY city_name"; $results_set = (mysqli_query($cxn, $sql)) or die("Was not able to produce the result set!"); while($row = mysqli_fetch_array($results_set)) { echo "<option value=$row[id]>$row[city_name]</option>"; } ?> </select> Are any variables defined in a while loop global to the while loop only? Here is my SQL which you can see my $row[id] being passed thru field city_id... The value is being generated as supposed to based on value like: value="1", value="2" etc.. for the select options for each city name. So the values are there... But I CANNOT get that numerical id to pass to the database when submitting my form. Any ideas for a workaround to get this value passing as normal? if (isset($_POST['addPosting'])) { $query = "INSERT INTO Postings (id, city_id, title, description) VALUES ('','$row[id]','$_POST[title]','$_POST[description]')"; This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=309473.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=315743.0 This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=350408.0 This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=344267.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=308768.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=354933.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=352154.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=319161.0 This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=346503.0 Amazingly, PHP Coding Help != JavaScript Help. 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