PHP - Image Doesn't Display On Page Php/mysql
Similar TutorialsHey, I'm having problems displaying data from a mysql database properly. Problem page: here It's a bit like a cms, a user fills out a form asking for a page title and the page content, thats then stored in the database and the finished result should be the page title added to the navigation and when clicked displaying the relevant page. I don't know if its possible but I'd like it to be done all on the one page. As you can see on the link I provided, when you click more than one link it displays it on the same page, rather than replacing itself. Can you help with this? Code: <html> <head> <script> function show_content(id){ document.getElementById(id).style.display='block'; } </script> </head> <body> <font face=verdana size=1> <?php include 'dbwire.php'; $query = mysql_query('SELECT * FROM content'); while($results = mysql_fetch_array($query,MYSQL_ASSOC)){ $title = $results['title']; $id = $results['id']; $content = $results['content']; echo "| <a href=\"javascript:void(0);\" onclick=\"show_content($id)\">$title</a> "; echo "<div id=\"$id\" style=\"display:none\">$content</div>"; } ?> <hr> </body> </html> Also, any idea how I should do the navigation? As you can see the more pages added the longer the navigation will get...eventually extending beyond the page width and creating problems. I understand I have problems explaining, if you need more just let me know! Thanks, Drew. Hi, Wonder if someone could help with the problem below. Got a main page that includes a header, footer and a link to a database. I can get the two Includes to work but can't seem to display the database fields in the body of the page. What has me baffled is that it appears to be connecting to the database, (Opening the connection to the database server The connection worked. The link is: Resource id #3) but no text (see below for database text) is appearing on the screen. Yet I'm not getting a "page_not_found" message. I can go to the database in MYSQL console and query it successfully. Read and (hopefully) applied the section Debugging: A Beginner's Guide, but still can't see the problem. Any help greatly appreciated. Bren --------------------CODE FOR MAIN PAGE START------------------- <?php $page_name = $_REQUEST['name']; /*http://localhost/exemples/page.php?name=about_us*/ // Get the body of the page mysql_connect("localhost","root","") or die(mysql_error()); mysql_select_db("test") or die(mysql_error()); $sql = "SELECT * from pages WHERE name='$page_name'"; print "Opening the connection to the database server<br>"; $link = mysql_connect("localhost","root", ""); print "The connection worked. The link is: $link <br>"; /* --------------What is being selected from the database-------------- +----------+------------------------------------------------------------------------+ | name | body | +----------+------------------------------------------------------------------------+ | about_us | <h1>About Us</h1> ACME Toys has been established in 1850 to provide toys | to children all over the world +----------+------------------------------------------------------------------------+ 1 row in set (0.00 sec) ---------------------------------------------------------------------- */ $result = mysql_query($sql) or die(mysql_error() ); // If the page is not found, redirect to a static page if(mysql_num_rows($result) == 0 ) { header("Location: page_not_found.html"); } $row = mysql_fetch_assoc( $result ); $body = stripslashes( $row["body"] ); // Include the header include("c:/wamp/www/exemples/header.php"); // Print the body of the page echo $body; // Include the footer include("c:/wamp/www/exemples/footer.php"); ?> --------------------CODE FOR MAIN PAGE END------------------- Would like to be able to click on a radio button that represents an image. Once selected and submitted, have that image display on another page. I have an idea, but need some guidance. BTW, is using php only doable? Is there a simpler or more elegant way to do this? Thanks all! Hi, I am having an issue with displaying an image that is uploaded in a mysql database. The table format is ----------------------------------------------------------- | id | name | mime | size | data | ----------------------------------------------------------- | 1 | test | image/jpeg| 74857 | BLOB | The data has uploaded fine. I then have the following script on my 'displayimage.php?imgid=1' page... Code: [Select] $id = $_GET['imgid']; $result = mysql_query("SELECT * FROM images WHERE id = '$id'"); while($row = mysql_fetch_array($result)) $size = $row['size']; $mime = $row['mime']; $name = $row['name']; { header("Content-length: $size"); header("Content-type: $mime"); header("Content-Disposition: attachment; filename=$name"); echo $row['data']; However everytime i try to open this page, Firefox or Internet Explorer just ask's me to try and download the file as a php file. Any ideas what is going wrong? Thanks! Matt Code: [Select] $thephoto = $row['thePHOTO']; in mysql thephoto is BLOB file type and stores an image i want to display the image as an avatar, in a while loop. Code: [Select] while($row = mysql_fetch_assoc($query4)) { $id = $row['ID']; $thename = $row['theNAME']; $thephoto = $row['thePHOTO']; } how do i make blob readable and then display as an image? Hi guys, I have a problem. I need to create a page that has a web form to upload an image to a mySQL database and place it in a blob field. Then I need to be able to query the database later to display the image on the site. I've looked around but I just haven't found any examples that can help me. Does anyone know of any good example or can anyone please give me an example? I have nothing so far, just the html web form and database. hi to all.Im currently displaying the images from my upload directory but the image does not display.please help thanks this is my 3 files which is i am using to show data of customer but i am not able to see them their logo image please see them & help me guys i dont know whats wrong in this. these files i uploaded please find attachment to see them. thnx in advanced [attachment deleted by admin] Hi I have tried and tried and tried again to get this to work
in simple terms I have very little knowledge with PHP and even less with mysql
I have a paid subscription and domain in order to learn more and I feel I have made ok progress so far
then I realised how unsafe my current work is;
here is my experience this far
I created a site for a group of voluntary online game hosts where they can posts points from their tournaments in a forum
and some info pages to go with this,
however what I did was create a base template and style sheet and then an admin dashboard linked to individual forms to allow the group admin to edit the info pages they go to my form and enter the desired info and submit this then sends through and action file which posts the text and <BR> to a .txt file,
then the connecting page reads the .txt file using the PHP code of " <? php include ( 'index.txt'); ?>
yes you are seeing this correctly I have allowed a direct edit of text in a .txt file rather silly of me but I didn't realise how unsafe this was until now I guess its a good job I trust that the admin has no knowledge or skills in coding
ok since all this I have created a DB in MySQL on my server,
My server uses PHPMyAdmin I have create a DB named " mnvbcou1_content1 " and a table named " home " with rows " ID " and " home "
what I am trying to do:
I want my page to display the content of the table row home and a form once submitted to send to the table row home
or if needed I can re make this DB if the names are not suitable
I have tried to create the needed coding to make this work but for some reason this just will not work I have already added 2 rows to my table to try and make the page to display the content but it just is not working I got an error every time
so I hope that someone out there is rather patient and is willing to help me learn how to do this correctly and safely,
also this is a closed group website the address to this site is only known by a handful of none programmers I am mainly trying to make this work for my own personal knowledge and server safety please help me
Hi, I am a newbie to this forum and php as well. I have a script which inserts data and image file into mysql database. Now I want to display this image on web page but unable to do it. I tried a lot but couldn't find out any solution. I would appreciate your help. <?php $con = mysql_connect("localhost", "root", "xx"); if(!$con) { die('Could not connect:' .mysql_error()); } mysql_select_db("yyy",$con); $memberid = '$_POST[memberid]'; $fname = '$_POST[fname]'; $lname = '$_POST[lname]'; $gender= '$_POST[gender]'; $add1 = '$_POST[add1]'; $add2 = '$_POST[add2]'; $city = '$_POST[city]'; $state = '$_POST[state]'; $zip = '$_POST[zip]'; $country = '$_POST[country]'; $photo1 = '$_FILES[image][name]'; echo "$photo1"; //if ($memberid= $_GET['memberid']){ $query="select memberid,fname,lname,gender,add1,add2,city,state,zip,country,photo1 from vadhuvar_member where memberid =(select max(memberid)from vadhuvar_member)"; $result=mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_assoc($result)) { $memberid = $row['memberid']; $fname = $row['fname']; $lname = $row['lname']; $gender = $row['gender']; $add1 = $row['add1']; $add2 = $row['add2']; $city = $row['city']; $state = $row['state']; $zip = $row['zip']; $country = $row['country']; //$photo1=chunk_split(base64_encode($photo1)); $photo1 = $row['photo1']; //echo base64_encode($photo1); echo "Name:$fname $lname<br>"; //echo "Name:$_POST[fname]$_POST[lname]<br>"; echo "Gender:$gender<br>"; echo "Address:$add1 $add2<br>"; echo "$city $state $zip<br>"; echo "$country<br>"; //echo "<img src=".upload/$photo1 ." alt="" width="200" height="300" /><br />"; } //} ?> <!--img src="<?php echo '.upload/$_FILES[image][name]?memberid=$row[memberid]'?>"alt="" width="200" height="300"/-->; <?php echo "<img src=". upload/$row[photo1]" alt="" width="200" height="300">";?> <!--img src="<?php echo ".\upload\$photo1" ?>" alt="" width="200" height="300"/-->; <? set_magic_quotes_runtime(1); // turn back on ?> Thanks Smita This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=348417.0 I wrote the page below to display a member's area of a website. The page is a mix of html and php code. the first part of is a block of php, which authenticates the user and displays the header. The middle part is a block of html which contains the bulk of the page. Embedded in this block of html are two sections of php, the first of which is supposed to display a user uploaded picture, enclosed in div tags, and the second of which, prints out the user's first name, from the database. The end of the script is a line of php that displays the footer. Now the page displays correctly when the section of php that contains the select query for displaying the picture(starting line 104) is omitted. But once I include that section, all i see is a blank page. Why is that section of php problematic? What can be done to fix it? Here is the data for the full page. Thanks for any help. <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //authenticate user require('auth.php'); //define title define('TITLE' , 'Members'); require ('header.html'); //need the header ?> <div id="main" style="background-color: #FFFFFF; height:71%; width:101%; border:0px none none; margin:auto; "> <!-- --> <div id="main_left" style="float:left; height:100%; width:20%; border:0px none none;"> <!--opens main left--> <div id="main_left_top" style="float:left; position:relative;bottom:5px;right:5px; height:31.25%; width:100%; background-color: #FFFFFF; border:1px solid #c0c0c0; margin:1px;"> <!--opens main left top--> </div> <!-- closes main left top--> <div id="main_left_center" style="float:left; background-color: #FFFFFF; height:33%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left center--> <div id="main_left_bottom" style="float:left; background-color: #FFFFFF; height:33%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left bottom--> </div> <!-- closes main left--> <div id="main_center" class="content_text" style="float:left; height:100%; width:58%; background-color: #FFFFFF; border:1px solid #c0c0c0;"> <!--opens main center--> <div id="image_box" style="float:left; background-color: #c0c0c0; height:150px; width:140px; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); $query = "SELECT* FROM images WHERE member_id ='{$_SESSION['id']}' AND cartegoty 'main' "; $result = mysql_query($query); $result_data = mysql_fetch_array($result); header("Content-type: image/jpeg") ; echo $result_data['image']; ?> </div> <a href="upload_image_page.php">click here to uplaod a picture</a> <h1>Welcome <?php echo ucfirst($_SESSION['firstname']);?></h1> <a href="member_profile.php">My Profile</a> | <a href="logout.php">Logout</a> <p>This is a password protected area only accessible to members. </p> <a href="blog_entries.php">Add to Hahap Tok Library</a> </div> <!-- closes main center--> <div id="main_right" style="float:left; background-color: #FFFFFF; height:100%; width:20%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> <div id="main_right_top" style="float:left; background-color: #FFFFFF; height:33%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left top--> <div id="main_right_center" style="float:left; background-color: #FFFFFF; height:33%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left center--> <div id="main_right_bottom" style="float:left; background-color: #FFFFFF; height:34%; width:100%; border-color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; "> <!--opens the white content area--> </div> <!-- closes main left bottom--> </div> <!-- closes main right--> </div> <!-- closes main--> <?php require('footer.html'); ?> My code: Code: [Select] <?php $username = $_SESSION['loggedin']; $extract_user_rank = mysql_query("SELECT `rank` FROM users WHERE username='$username'"); if($extract_user_rank['rank'] > 0) { echo "<a href='control_panel.php'>Admin Control Panel</a>"; } else { //return nothing } ?> I have my rank in the database set to 1. Why doesn't it output the ACP link? I have a problem with the three special characters in the Danish language: æ, ø and å. I have created a database with a simple table manually within phpMyAdmin, and I have added contents, which is text with the letters mentioned. Everythings looks correct in here. But when I get the content of the database written out via a php document, these three letters are replaced with a box sign. In phpMyAdmin I chose "utf8_danish_ci" as collation. And here is the code of the php document writing out the content of the database table, named "lille_tabel", with the password written with stars.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <?php $server = "localhost"; $brugernavn = "root"; $kodeord = "************"; $db = "lille"; mysql_connect($server,$brugernavn,$kodeord) or die(mysql_error()); echo "Forbundet til MySQL server<br/>"; mysql_select_db($db) or die(mysql_error()); echo "Forbundet til Databasen<br/>"; $data = mysql_query("SELECT * FROM lilletabel") or die(mysql_error()); while ($info = mysql_fetch_array($data)) { echo "ID: ".$info['id']."<br/>"; echo "Navn: ".$info['navn']."<br/>"; echo "Tekst: ".$info['tekst']."<br/>"."<br/>"; } ?> </body> </html>By the way: I use Dreamweaver. I hope someone have suggestions to pinpoint the problem ... Regards, Erik ONE of my SESSION values isn't remaining after login while others do. This works fine on my localhost, it's on the live site that there is a problem and it just started yesterday. Before that it worked great. Out of the four SESSIONs made I can only echo three values on other pages, member id the most important doesn't transfered to other pages Notes: all these files are in the same folder, there is a SESSION started for the member id on the login page, you can see that it is used in the redirect below and the redirect works fine with the redirect going to the correct page " $home/member/index.php?user=$id_mem " Here is the login page // Here's the basic login page info <?php # login.php session_start(); ob_start() ...connect to db & header called... ...Form validation..... if ($e && $p) { // If everything's OK. // Query the database: $q = "SELECT id_mem, display_name, mem_group FROM sn_members WHERE (email='$e' AND password=SHA1('$p')) AND active IS NULL"; $r = mysqli_query ($dbc, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); // or die("Error: ".mysqli_error($dbc)); if (@mysqli_num_rows($r) == 1) { // If a match was made. // Register the values & redirect: // Give SELECTED elements a session $_SESSION = mysqli_fetch_array ($r, MYSQLI_ASSOC); $_SESSION['agent'] = md5($_SERVER['HTTP_USER_AGENT']); mysqli_free_result($r); // Update db for last login $id_mem = $_SESSION['id_mem']; // <<< SESSION member id has a value here because it's used in the redirect below $ip = $_SERVER['REMOTE_ADDR']; // Get ip address of person logging in $q = "UPDATE sn_members SET last_login = Now(), ip = '$ip' WHERE id_mem = '$id_mem' LIMIT 1"; $r = mysqli_query ($dbc, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); header("Location: $home/member/index.php?user=$id_mem"); exit(); // Quit the script. } ?> Here is the main page that a user would be redirect to above <?php // /member/ all member info is through this folder session_start(); ob_start(); if (isset($_GET['user']) && is_numeric($_GET['user'])) { $user = $_GET['user']; $user = $user; if ($user < 0) { header("Location: $home/index.php"); exit(); } } if ((!isset($_SESSION['id_mem'])) && (!isset($_SESSION['agent']) OR ($_SESSION['agent'] != md5($_SERVER['HTTP_USER_AGENT'])))){ // If not a logged in member redirect header("Location: $home/index.php"); exit(); // Quit the script. } ?> Thanks in advance for the help SJ My Php Buddies, I have mysql tbl columns these:
id: Now, I want to display their row data by excluded a few columns. Want to exclude these columns: date_&_time account_activation_code account_activation_status id_verification_video_file_url password
So, the User's (eg. your's) homepage inside his account should display labels like these where labels match the column names but the underscores are removed and each words' first chars CAPITALISED:
Id: 1
For your convenience only PART 1 works. Need help on Part 2 My attempted code:
PART 1 <?php // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } // Query to get columns from table $query = $conn->query("SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA = 'members' AND TABLE_NAME = 'users'"); while($row = $query->fetch_assoc()){ $result[] = $row; } // Array of all column names $columnArr = array_column($result, 'COLUMN_NAME'); foreach ($columnArr as $value) { echo "<b>$value</b>: ";?><br><?php } ?> PART 2 <?php //Display User Account Details echo "<h3>User: <a href=\"user.php?user=$user\">$user</a> Details</h3>";?><br> <?php $excluded_columns = array("date_&_time","account_activation_code","account_activation_status","id_verification_video_file_url","password"); foreach ($excluded_columns as $value2) { echo "Excluded Column: <b>$value2</b><br>"; } foreach ($columnArr as $value) { if($value != "$value2") { $label = str_replace("_"," ","$value"); $label = ucwords("$label"); //echo "<b>$label</b>: "; echo "$_SESSION[$value]";?><br><?php echo "<b>$label</b>: "; echo "${$value}";?><br><?php } } ?> PROBLEM: Columns from the excluded list still get displayed. Edited November 19, 2018 by phpsaneI am writing a code for a page which will get certain information from database into fields and update edited information. I can get information from database, but cannot update the edited information to database. Please, Can anyone help me ? Code: [Select] <? session_start(); include("includes/connection.php"); include("includes/config.php"); $sqlsettings = "SELECT * from admin"; $resultsettings = mysql_query($sqlsettings); $rowsettings = @mysql_fetch_array($resultsettings); if ($_SESSION['MyAccount']=='') { $_SESSION['MyAccount'] = "MyAccount"; header('LOCATION: login.php'); exit(); } $msg=''; if($_POST['continue'] == "true") { $AddedDate = $_POST['AddedDate']; $sqlUpdate = "UPDATE buyer_career SET CareerTitle='".mysql_real_escape_string($_POST['CareerTitle'])."', CareerDescription='".mysql_real_escape_string($_POST['CareerDescription'])."', ExpiryDate='".mysql_real_escape_string($_POST['ExpiryDate'])."', where BuyerCareerID=".$_POST['BuyerCareerID']; $result=mysql_query($sqlUpdate); header("Location:buyers_career.php?msg=Buying Lead has been updated successfully"); exit(); } ?> <? //retreiving data from selling leads $sqlBuyingLead="select * from buyer,buyer_career where buyer.BuyerID=buyer_career.BuyerID and BuyerCareerID=".$_GET['BuyerCareerID']; $resultBuyingLead=mysql_query($sqlBuyingLead); $buying_row=@mysql_fetch_array($resultBuyingLead); ?> <form name="PostNewCareer" method="post" action="edit_buyer_career.php" enctype="multipart/form-data" onSubmit="return validate(this);"> <input type="text" name="CareerTitle" style="width: 400px" class="basicPoint" id="CareerTitle" value="<?=$buying_row['CareerTitle']?>" /> <input type="hidden" name="AddedDate" value="<?=$buying_row['AddedDate']?>"> <input type="text" name="CareerVacancies" style="width: 400px" class="basicPoint" id="CareerVacancies" value="<?=$buying_row['CareerVacancies']?>"/> <input type="hidden" name="continue" value="true"> <input type="hidden" name="BuyerCareerID" id="BuyerCareerID" value="<?=$_GET['BuyerCareerID']?>"/> <input type="submit" value="Update Buying Lead" name="submitButton" /> Hello, My current server setup :
PHP version: 7.1.4
From what I read, in order to have MySQL return native datatypes (as opposed to just strings) : Now, I do have mysqlnd, but a simple PDO Prepared statement still returns me all strings, even though some columns are set as INT, VARCHAR, DATETIME, etc.. $stmt = $pdo->prepare("SELECT * FROM tbl_users WHERE id=1"); $stmt->execute(); $user = $stmt->fetch(); var_dump($user); OUTPUT: array(13) { ["id"]=> string(1) "1" ["is_admin"]=> string(1) "1" ["is_active"]=> string(1) "1" ["username"]=> string(5) "jdoe" ... }
I'm not sure what to look for to resolve this issue if I want it to return INT as INT and not STRING, etc. Does having `extension_loaded('mysqlnd') == true`, make my system automatically use this native mysql driver? How can I tell ? Could this be a version problem perhaps?
Much thanks! Pat
I am using this PHP code with a MySQL query. PHP parses the PHP fine, but the MySQL query is not having any effect on the database. Can anyone see an error in my code? I can't. $query = "UPDATE `products` set `id` = '".$_POST['id']."' where `id` = '".$_POST['id']."'"; MOD EDIT: Changed PHP manual link tags to [php] . . . [/php] tags. I have a site with a members area that uses sessions. I migrated my DB from MySQL 4 to 5. Now my login page does not work. Please help. Member Login Page: Code: [Select] <?php session_name ('name'); ini_set ('session.use_cookies', 0); session_start(); ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link href="css/style.css" rel="stylesheet" type="text/css" /> <script type="text/javascript" src="js/swfobject/swfobject.js"></script> <script type="text/javascript"> var flashvars = {}; flashvars.xml = "config.xml"; flashvars.font = "font.swf"; var attributes = {}; attributes.wmode = "transparent"; attributes.id = "slider"; swfobject.embedSWF("cu3er.swf", "cu3er-container", "960", "400", "9", "expressInstall.swf", flashvars, attributes); </script> <link href="css/menu.css" rel="stylesheet" type="text/css" /> <style type="text/css"> #apDiv1 { position:absolute; left:592px; top:75px; width:552px; height:53px; z-index:1; } a:visited { color: #5D4580; } a:hover { color: #FFF; } a:active { color: #5D4580; } </style> </head> <body> <div class="main"> <div class="blok_header"> <div class="header"> <div class="rss"><strong>P</strong></div> <div class="clr"></div> <div class="logo"><a href="index.html"><img src="images/logo.jpg" width="211" height="88" border="0" alt="" class="one" /></a></div> <div class="menu"> <ul id="css3menu"> <li class="topfirst"><a href="index.html" title="Home">Home</a></li> <li><a href="#" title=""><span>Omega Psi Phi</span></a> <ul> <li><a href="founders.html" title="Fraternity Founders">Fraternity Founders</a></li> <li><a href="omegahistory.html" title="Fraternity History">Fraternity History</a></li> <li><a href="programs.html" title="Mandated Programs">Mandated Programs</a></li> <li><a href="links.html" title="Links">Links</a></li> </ul> </li> <li><a href="#" title="Phi Gamma Chapter"><span>Phi Gamma Chapter</span></a> <ul> <li><a href="history.html" title="Phi Gamma History">Phi Gamma History</a></li> <li><a href="lineage.html" title="Phi Gamma Lineage">Phi Gamma Lineage</a></li> <li><a href="dedication.html" title="Dedication">Dedication</a></li> <li><a href="calendar.html" title="Calendar">Calendar</a></li> <li><a href="photogallery.html" title="Photo Gallery">Photo Gallery</a></li> <li><a href="members/login.php" title="Member Login">Member Login</a></li> <li><a href="roster.html" title="Chapter Roster">Chapter Roster</a></li> </ul> </li> <li><a href="members/login.php" title="Member Login">Member Login</a></li> <li class="toplast"><a href="contact.html" title="Contact Info.">Contact Info.</a></li> </ul> </div> </div> <div class="clr"></div> <div class="body"> <div class="body_bg"> <h2>Member's Only </h2> <?php if ($_SESSION['membername'] != null) { // print "<META HTTP-EQUIV='Refresh' content='0;URL=updatemember.php'>"; echo "You are already logged in. Please wait to be redirected to the members page, or <a href=\"members.php\">click here</a> if you are not automatically redirected. User name for the session is ".$_SESSION['username'].", the member name is ".$_SESSION['membername']; print "<META HTTP-EQUIV='Refresh' content='5;URL=members.php'>"; //header("Location: members.php"); //exit; } else { ?> <form name="admin" method="post" action="userlogon.php"> <table width="891" border="0" cellspacing="5" cellpadding="5"> <tr> <td height="80" colspan="2" align="left"><p>Please enter you username and password. Don't remember your password, <u><strong><a href="password.php">click here</a></strong></u><strong><a href="password.php"></a></strong>.</td> <td width="360" rowspan="5" align="center" valign="middle"><img src="images/login_image.jpg" width="239" height="314" /></td> </tr> <tr> <td width="257" height="38" align="right"><p><strong>Username:</strong></td> <td width="224" align="left"><input type="text" name="username"></td> </tr> <tr> <td height="38" align="right"><p><strong>Password:</strong></td> <td align="left"><input type="password" name="password"></td> </tr> <tr> <td height="34"> </td> <td align="left"><input type="submit" class="yellowbutton" name="submit" value="Sign In"></td> </tr> <tr> <td colspan="2"><p>To register for a username and password with Phi Gamma, please <u><strong><a href="register.php">click here</a></strong></u><strong><a href="password.php"></a></strong>.</td> </tr> </table> </form> <?php } ?> <p> </p> <div class="clr"></div> </div> <div class="clr"></div> </div> </div> <div class="footer"> <div class="footer_resize"> <p class="center"> <a href="index.html">Home</a> | <a href="contact.html">Contact</a> </p> <div class="clr"></div> </div> <div class="clr"></div> </div> </body> </html> After the credentials are entered the user is returned back to the login page and NOT the member's page. This is the userlogon.php page: Code: [Select] <?php $link = mysql_connect('localhost:/tmp/mysql5.sock', 'dbuser', 'dbpw'); if (!$link) { die('Could not connect: ' . mysql_error()); } //mysql_close($link); if (!mysql_select_db('db_name', $link)) { echo 'Could not select database'; exit; } $username = $HTTP_POST_VARS["username"]; $password = $HTTP_POST_VARS["password"]; $member_id = ''; $role = ''; $firstname = ''; // Formulate Query // This is the best way to perform a SQL query // For more examples, see mysql_real_escape_string() $query = sprintf("SELECT users.member_id, users.username, users.password, users.role, FROM users join members on users.member_id = members.member_id WHERE users.username ='%s' AND users.password='%s'", mysql_real_escape_string($username), mysql_real_escape_string($password)); // Perform Query $result = mysql_query($query); // Check result // This shows the actual query sent to MySQL, and the error. Useful for debugging. if (!$result) { $message = 'Invalid query: ' . mysql_error() . "\n"; $message .= 'Whole query: ' . $query; die($message); } // Use result // Attempting to print $result won't allow access to information in the resource // One of the mysql result functions must be used // See also mysql_result(), mysql_fetch_array(), mysql_fetch_row(), etc. while ($row = mysql_fetch_assoc($result)) { $member_id = $row['member_id']; $username = $row['username']; $role = $row['role']; } if ($member_id != ''){ session_start(); $_SESSION['membername'] = $username; $_SESSION['username'] = $username; $_SESSION['memberid'] = $member_id; $_SESSION['role'] = $role; print "<META HTTP-EQUIV='Refresh' content='0;URL=members.php'>"; } else { print "<META HTTP-EQUIV='Refresh' content='0;URL=memberlogin.php'>"; } // Free the resources associated with the result set // This is done automatically at the end of the script mysql_free_result($result); ?> It worked fine before the migration??? Anyone know where the problem is? |