PHP - Math Done To Database Query.
The title may not fit but only thing i could think of.
I am pulling data from MSSQL database table.... I need everything from that table but i need to do some basic math funcitons to the resulting data. So the quesiton is should i do the math for this in the SQL query if so how do i pull all fields and do the math in an effcient way. Or should i let php do the math for me after i get all the data i need. If it is better to use php how can i do this in a while loop and get the math result and not a printed equation. Just looking for a few pointers never had to do math before with php Similar TutorialsPlease deal with me for a moment as I try to explain what is occurring. I have created drop down menu that you choose a name and the php/MySQL will run multiple queries to display information regarding the chosen name. The query works great. There is no problem with the query. However when you leave the page, either by navigation or by X'ing out. When you return there are two errors that pop up: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in You can then use the drop down menu and choose a name and it all works great. It is my belief that these errors occur due to how the query was written, as the two queries that have these errors both have math in them. My question is, how do I block these errors from occurring when you return to the page? Here is the query: <?php //Worst Regular Season Record include_once('../other/functions.php'); $con = mysql_connect($hostname, $username, $password) OR DIE ('Unable to connect to database! Please try again later.'); $db = mysql_select_db($dbname, $con); $query = "SELECT win, loss, year, teamname FROM standings, owners WHERE owners.owner_id = standings.owner_id AND win = (SELECT MIN(win) FROM standings) AND standings.owner_id = $thing ORDER BY year"; $result = mysql_query($query); $row = mysql_fetch_array($result); @ mysql_data_seek($result, 0); if(mysql_num_rows($result)>0) { echo "<table CELLPADDING=5 border =1>"; echo "<tr>"; echo "<th align=center colspan=4 > Worst Regular Season Record </th>"; echo "</tr>"; while ($row = mysql_fetch_array($result)) { echo "<tr>"; echo '<td align=center> In '.$row['year'].', the '.$row['teamname'].' had '.$row['win'].' wins, and '.$row['loss'].' losses.</td>'; echo "</tr>"; } } else { } echo "</table>"; mysql_close($con); ?> I don't even know how to explain what I want to do as a subject. >.< Okay, so what I want to do is pull up all the entries in a table, (in this case "horse") for a specific location. Then, I want to pull all the results for that horse from the "result" table. Next, I want to compare each result from that table to a list of if/elseif for points. Finally, I want all the points gathered and totaled and displayed for that horse, and every other horse at that location, in a single page. Here is the coding that I have: Code: [Select] <? ---- connection information is here but removed ----- echo "<table> <tr><td><b>Name</b></td> <td><b>Points</b></td> <td><b>Title</b></td></tr>"; //finds horses at specific location $query = "SELECT * FROM horse WHERE location='DESIRED_LOCATION' ORDER BY name"; $result = mysql_query($query) or die (mysql_error()); while ($row = mysql_fetch_array($result)) { $id = $row['id']; $name = $row['name']; //gathers results based upon the above two pieces of information //the include is shown below as it contains the point info include('includes/points.php'); $query92 = "SELECT * FROM results WHERE MAIN_KEY='$id' OR MAIN_KEY = '$name'"; $result92 = mysql_query($query92) or die (mysql_error()); while($row92 = mysql_fetch_array($result92)) { $place = $row92['place']; echo "<tr><td>$name</td> <td>$points</td> <td>$title</td></tr>"; } } echo "</table>"; ?> and this is the points.php file: Code: [Select] <? if($place === '1st') {$points += 50;} elseif($place === '2nd') {$points += 45;} elseif($place === '3rd') {$points += 40;} elseif($place === '4th') {$points += 35;} elseif($place === '5th') {$points += 30;} elseif($place === '6th') {$points += 25;} elseif($place === '7th') {$points += 20;} elseif($place === '8th') {$points += 15;} elseif($place === '9th') {$points += 10;} elseif($place === '10th') {$points += 10;} elseif($place === 'CH') {$points += 50;} elseif($place === 'RCH') {$points += 40;} elseif($place === 'TT') {$points += 30;} elseif($place === 'T5') {$points += 30;} if($points < 500) {$title = "No Title";} elseif ($points >= 500 && $points < 1000) {$title = "Champion";} elseif ($points >= 1000 && $points < 2500) {$title = "Grand Champion";} elseif ($points >= 2500 && $points < 5000) {$title = "State Champion";} elseif ($points >= 5000 && $points < 8000) {$title = "National Champion";} elseif ($points >= 8000 && $points < 10000) {$title = "World Champion";} elseif ($points >= 10000) {$title = "Hall of Fame";} ?> hello I want query from one table and insert in another table on another domain . each database on one domain name. for example http://www.site.com $con1 and http://www.site1.com $con. can anyone help me? my code is : <?php $dbuser1 = "insert in this database"; $dbpass1 = "insert in this database"; $dbhost1 = "localhost"; $dbname1 = "insert in this database"; // Connecting, selecting database $con1 = mysql_connect($dbhost1, $dbuser1, $dbpass1) or die('Could not connect: ' . mysql_error()); mysql_select_db($dbname1) or die('Could not select database'); $dbuser = "query from this database"; $dbpass = "query from this database"; $dbhost = "localhost"; $dbname = "query from this database"; // Connecting, selecting database $con = mysql_connect($dbhost, $dbuser, $dbpass) or die('Could not connect: ' . mysql_error()); mysql_select_db($dbname) or die('Could not select database'); //query from database $query = mysql_query("SELECT * FROM `second_content` WHERE CHANGED =0 limit 0,1"); while($row=mysql_fetch_array($query)){ $result=$row[0]; $text=$row[1]."</br>Size:(".$row[4].")"; $alias=$row[2]; $link = '<a target="_blank" href='.$row[3].'>Download</a>'; echo $result; } //insert into database mysql_query("SET NAMES 'utf8'", $con1); $query3= " INSERT INTO `jos_content` (`id`, `title`, `alias`, `) VALUES (NULL, '".$result."', '".$alias."', '')"; if (!mysql_query($query3,$con1)) { die('Error: text add' . mysql_error()); } mysql_close($con); mysql_close($con1); ?> Hello All, Trying to write a log-in script using PDO. But have one question. With the below when I query the database and even run a print_r on $RES nothing is outputted? Any ideas? Thanks if (isset($_POST['Submit'])) { $email = $_POST['email']; $password = $_POST['password']; $QUERY = $dbc->prepare("SELECT email, password FROM tbl WHERE email = :email"); $QUERY->bindParam(':email', $email); $QUERY->execute(); $RES = $QUERY->fetchColumn(); echo "Email is:".$RES['email']; echo "PW is: ".$RES['password']; print_r($RES); } I just did a massive hardware/software upgrade - first new computer (a Mac) in 6 1/2 years, first MAMP upgrade in several years, etc. I'm now using these software versions: Apache 2.2.21, PHP 5.3.6, MySQL 5.5.9 Just about everything seems to be working fine except my database connections. I appear to be making a simple mistake, but I can't figure out the solution. I've checked out all sorts of online help pages, but I'm only getting more confused. Rather than ask what the problem is, it might be better to go back to square one and ask how you would write this query from scratch. I pasted my current, somewhat convoluted code below, to give you an idea of how I was doing it. But here's what I'm trying to do: Imagine a website with a static page at World: MySite/World. It displays dynamic pages, like these: MySite/World/France, MySite/World/Spain...just as long as "France" or "Spain" match values stored in a database table (gw_geog). In my query, I represent France, Spain and other place names with the variable $MyURL. So I want to query that database table. If $MyURL = 'Japan' (e.g. MySite/World/Japan), then $result should = 1, fetching a web page. If $result = 0 (e.g. a misspelled URL, like MySite/World/Japax), then it fetches a 404 error page. If $result = 2 or more (e.g. MySite/World/Georgia - the name of a country and a U.S. state), then it fetches a duplicate note. I wrote this script years ago, when I didn't know much about PHP/MySQL (I still don't), and I've upgraded my software, so I need to start fresh. Can anyone tell me how YOU would a script to accomplish this task? Thanks. * * * * * Code: [Select] <?php // DATABASE CONNECTION $conn = mysql_connect("localhost", "Username", "Password"); if (!$conn) { echo "Unable to connect to DB: " . mysql_error(); exit; } if (!mysql_select_db("db_general")) { echo "Unable to select db_general: " . mysql_error(); exit; } // DATABASE QUERY $sql = " SELECT COUNT(URL) FROM gw_geog WHERE URL = '$MyURL' "; $sql_result = mysql_query($sql,$conn); $result = $sql_result; // DO SOMETHING WITH THE RESULTS switch ($result) { case 1: echo "\n"; include_once($BaseINC."/$MyPHP/inc/B/DB2/Child/World.php"); include_once($BaseINC."/$MyPHP/inc/B/Child2.php"); include_once($BaseINC."/$MyPHP/inc/D/Child.php"); echo "\n"; break; case 0: include_once($BaseINC."/404.php"); break; default: // More than one results, as in Georgia (state and republic) include_once($_SERVER['DOCUMENT_ROOT']."/Dupe.php"); echo "\n"; break; } ?> Hello All, This is my first post. I have tried getting some help on the PHP channel in IRC but people there always point you to a reference page. I need actual help and example with my code. Possible someone to show/highlight what I did wrong and then show me the correction. First, my code is supposed to create a form. The form (server_select.php) is a pre-populated form that has a drop down box that queries a table from the database. The form then sends the info to get_disk.php page to post the results of the users selected query options. Here is how it's supposed to work: User goes to webpage.tld/index.php. They click on "Select Server Details" page (server_select.php). A form gets loaded User then has to select from the drop down menu's: server, date range from and to and then hit submit User gets sent to get_disk.php The get_disk.php is supposed to show them all of the following info from their selected server and date range: hostname, device name, device size, current usage, remaining size, percentage used, mount point, time stamp. All of that is supposed to show when they user hits submit. Issue: My submit page seems to work but my "get_disk.php" page doesn't seem to know how to query the database correctly. Attached are both of my files. Can someone tell me why my query on the get_disk.php page is not working and how I get it to display my requested info, please? Is it possible to query my database and display results from a varible that changes each time from a users search? I know how to get results from a variable like a field name and display them but i was wondering if for example; the user searches for criteria and gets the result there looking for (postcode); they then click that result in the browser and are redirected to another page with lots more information.(company_name and location). There result from the original search would be different each time but i would like to know if i could take that result and display all other fields in my table associated with that one result. ***Freelistings*** id company_name location postcode 1 Dave's Storage London PO Box1 2 Steve's Trucks Birmingham WS12 3 3 Sue's Tyres Manchester M14 6 4 Paul's Birmingham WS11 7 ***Basicpackge*** id company_name location postcode 1 Storage Ltd London LN12 5TW 2 Fran's Grit Birmingham WS5 37 3 Raj Walls Manchester M14 60 4 Paul's Light's Birmingham WS12 17 ***Premiumuser*** id company_name location postcode 1 Name1 Location1 PC1 2 Name2 Location2 PC2 3 Name3 Location3 PC3 4 Name4 Location4 PC4 I'm sure this can be done, i'm just getting stuck on how to treat the user's search result. Currently it's called '%$var%'. Can i use: $query = "(SELECT company_name, location FROM freelistings WHERE company_name, location like '%$var%') UNION (SELECT company_name, location FROM basicpackage WHERE company_name, location like '%$var%') UNION (SELECT company_name, location FROM premiumuser WHERE company_name, location like '%$var%') ORDER BY postcode"; So that would be looking at all three tables, getting the details from each field that is associated with that (result) postcode. I hope i have given enough information to explain my problem i'm having. for me quite a tough one? any help would be appreciated, thanks guys in advance! I'm having a problem with adding icon/avatar to my database..this is a submit form where I just submit the avatar url. I don't know how to change the submit link from avatar_add.php?mode=submit to index.php?mode=submit&x=avatar_add. http://www.graphics.allmerk-noplay.com/index.php?x=avatar_add Code: [Select] <?php $host =""; // host name $user =""; // user $pass =""; // password $dbase =""; // database name // connect to the server mysql_connect("$host","$user","$pass"); // and select the database mysql_select_db($dbase); $mode=$_GET["mode"]; // get the mode $QUERY_STRING = 'x=avatar_add'; if(!isset($mode) || empty($mode)) // if mode is empty, switch to case index { $mode='index'; } switch($mode) { case 'index'; // displays the form ?> <form method="post" action="avatar_add.php?mode=submit"> Avatar URL:<br> <input type="text" name="avatar_url" size="30"><br><br> <input type="submit" value="Submit"> <?php break; case 'submit'; // form processing mode $avatar_url=$_POST["avatar_url"]; // check for empty fields if(empty($avatar_url)) { echo "Error! Please go back and fill in all the required fields!"; // if you have a footer include, insert it before the die statement die; // stops the script from executing the rest of the code } // let's get the date in YYYY-MM-DD format $date = date("Y-m-d"); $query="INSERT into icons_db (id,avatar_url) VALUES ('','$avatar_url')"; $result=mysql_query($query) or die ("Couldnot execute query: $query." . mysql_error()); if($result) // if mysql query successful { echo "Thank you! The avatar has been added to or database."; } break; } ?> Working on a website directory that includes ratings for listed companies. Trying to obtain information from database that would put some companies in a higher category than others. Or at least, I believe that is the approach I should be taking.
There are a few tricky issues.
1. Ratings are their own custom posts but are attached to company pages (parents)
2. Rating values I need to obtain are meta keys (1. total number of ratings & 2. rating average of EACH)
3. Ratings are based on four criteria which are summed and averaged for each rating submitted. As a result, values are rarely single digits such as 4 or 5 but include decimals rounded to 1 place (e.g. 4.8 or 3.5)
Additional info:
Ratings are based on 5-star system (out of 5)
Higher category would be business that achieved at least 10 ratings of 4 or more
Any help appreciated.
in database, I have faced error where query does not responded properly
it was showing the error message that "too much query, user cannot execute more query"....
when I increased the limit, it works for sometime and after sometime, it again generates the error , my question here is:
"why the error is occurring ?"
"what is the correct way to improve the execution of multiple queries at single instance ??? "
Hi guys, i am currently working on a project that queries an inventory database through the use of radio buttons, for example; If the first button FOR THE Item(HAMMERS)is clicked, the output should be the name of the item, the number sold and the total profit(calculations) into a table. the way i have it now, when io click on the radio button my output comes back as the results for all the items in the table, i want it to display only the information about hammers, then only about each individual item when the corresponding radio button is clicked. any help would be greatly appreciated!!! So I'm creating a website for bar deals... I've tried for hours trying to get the url to take in more than one parameter with no luck, I don't know if my database isn't setup correctly or something but the url would look like this http://www.site.com/?id=1&day=Monday and when those parameters are passed the deals for that id and day are then posted in the content area I'm pretty much stumped. I feel like it's much easier than I am making it. My database looks like: ID Name Monday Tuesday Wednesday -> and so on 1 Bar1 MondayDeal TuesdayDeal WednesdayDeal 2 Bar2 MondayDeal -> and so on Hi I'm using a couple of queries to search a database. This works well but is slow as I'm cascading/nesting the queries.. Below is an example of what I mean... (LDAP queries) Code: Code: [Select] <? $dn = "cn=user"; $filter="(objectclass=user)"; $justthese = array('cn','telephone','guid','ID','email'); $sr=ldap_search($ds, $dn, $filter, $justthese); $info = ldap_get_entries($ds, $sr); for ($n=0; $n<$info['count']; $n++) { $cn = $info[$n]['cn'][0]; $email = $info[$n]['email'][0]; $id= $info[$n]['id'][0]; $dn = "cn=Device"; $filter="(objectclass=device)(userid=$id)"; $justthese = array('cn','system','guid','ID','userid'); $sr=ldap_search($ds, $dn, $filter, $justthese); $info = ldap_get_entries($ds, $sr); for ($n=0; $n<$info['count']; $n++) { $system = $info[$n]['system'][0]; $userid = $info[$n]['userid'][0]; } } ?> I'm sure there's a better way of writing this... that will make it faster. Thanks I have a test database set up that I am working on. Right now, just some names like so firstName lastName companyName I have used phpmyadmin to insert names in the database. Right now just three names are inserted. One first and last name, one first name and one company name I am getting the results back in an associative array. How can I echo out the information with the break tag, or one field at a time? if I use a break tag, then the loop adds in extra blank lines when it gets to the first name and it's null. Can I test for null values and do it that way? I am a beginner so I have no idea what I am doing. Code: [Select] $result = $mysql->query("select * from names") or die($mysql->error); if($result){ while($row = $result->fetch_assoc()){ $name = $row['firstName']; $lastName = $row['lastName']; $company = $row['companyName']; echo $name . " "; echo $lastName . " "; echo $company . " "; } } Hi I have created a Database class that uses the singleton method. I have a query method within this class so i would call this to return an array of results. What i need to know is what would be the best way to use this returned array Database Class: Code: [Select] <?php class Database { private static $dbInstance; private $hostname; private $username; private $password; private $database; private function __construct() { $this->hostname = 'localhost'; $this->username = 'user'; $this->password = 'pass'; $this->database = 'test'; mysql_connect($this->hostname, $this->username, $this->password); mysql_select_db($this->database); } public static function getDBInstance() { if (!self::$dbInstance) { self::$dbInstance = new Database(); } return self::$dbInstance; } public function query($q) { return mysql_query($q); } } ?> Person Class: Code: [Select] <?php require_once('Database.php'); class person { public function getName($id) { $con = Database::getDBInstance(); $query = $con->query("select name from data where id = ".$id); $result = mysql_fetch_assoc($query); echo $result['name']; } } ?> Index page: Code: [Select] <?php require_once('person.php'); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <?php $person = new person(); $person->getName(1); echo "<br />"; $person->getName(2); ?> </body> </html> Hi, I am trying to store a sql query in a database, but every time I try to read it, it shows all the code as text. eg just print ' . $parts_row['part_number'] . ' Here is the code on the page: $parts_sql = "SELECT * FROM parts WHERE part_cat = " . $category_row['cat_id'] . " ORDER BY CAST(part_a AS DECIMAL(10,2))"; $parts_result = mysql_query($parts_sql); if(!$parts_result) { echo '<tr><td>The parts could not be displayed, please try again later.</tr></td></table>'; } else { while($parts_row = mysql_fetch_array($parts_result)) { $pageformat_sql = "SELECT * FROM category_pages WHERE catpage_number = " . $category_row['cat_page'] . ""; $pageformat_result = mysql_query($pageformat_sql); if(!$pageformat_result) { echo 'Error'; } else { while($pageformat_row = mysql_fetch_assoc($pageformat_result)) { $data = $pageformat_row['catpage_table']; echo '<table class="table2 centre" style="width:750px"> ' . $pageformat_row['catpage_tabletitle'] . '' . $data . ''; } } }}And this is what is stored in the database table: <tr> <td class="cell left">' . $parts_row['part_number'] . '</td> <td class="cell centre">' . $parts_row['part_a'] . ' mm</td> <td class="cell centre">' . $parts_row['part_b'] . ' mm</td> <td class="cell centre">' . $parts_row['part_c'] . ' mm</td> <td class="cell centre">' . $parts_row['part_d'] . ' mm</td> <td class="cell centre">' . $parts_row['part_e'] . ' mm</td> <td class="cell centre">' . $parts_row['part_imped100'] . '</td> <td class="cell centre"><a href="datasheets/' . $parts_row['part_datasheet'] . '.pdf"><img border="0" src="images/pdf.jpg" alt="Download"</a></td></tr>I would be very grateful to anyone who can help me with this. Last Christmas my wife bought me a book on html and css because I said that I have always wanted to write a website. Over the last 10 months I have really enjoyed learning web design and have progressed to try and learn php and using myPHPadmin databases.
I am now trying to write a private message function. I've got a members database and a conversation database. I am trying to filter out whether a private message is 'read' or 'unread', but whatever I try it is still listing all messages under both options. I've spent 48 hours staring at this bit of code. Can anyone see what I have done wrong? The relevant (and self-explanatory) fields from my members database a id username member_first_name member_last_name The relevant fields from my conversation database a id id2 (always set as '1' to count messages in a conversation) member1 (the initial sender of the first message) member2 (the initial recipient of the first message) read1 (member1 has read this message default to yes when message sent and to no when message received) read2 (member2 has read this message default to yes when message sent and to no when message received) removed1 (member1 has deleted this message from their record) removed2 (member2 has deleted this message from their record) time (timestamp) <?php $query1 = DB::getInstance()->query("SELECT c1.id, c1.title, c1.time, c1.removed1, c1.removed2, count(c2.id) AS reps, m.id as memberid, m.username m.member_first_name, m.member_last_name FROM conversation as c1, conversation as c2, members as m WHERE ((c1.member1='{$logid}' AND c1.read1='No' AND c1.removed1='No' AND m.id=c1.member2) OR (c1.member2='{$logid}' AND c1.read2='No' AND c1.removed2='No' AND m.id=c1.member1)) AND c1.id2='1' AND c2.id=c1.id GROUP BY c1.id ORDER BY c1.id DESC"); $query2 = DB::getInstance()->query("SELECT c1.id, c1.title, c1.time, c1.removed1, c1.removed2, count(c2.id) as reps, m.id as memberid, m.username, m.member_first_name, m.member_last_name FROM conversation as c1, conversation as c2, members as m WHERE ((c1.member1='{$logid}' AND c1.read1='Yes' AND c1.removed1='No' AND m.id=c1.member2) OR (c1.member2='{$logid}' AND c1.read2='Yes' AND c1.removed2='No' AND m.id=c1.member1)) AND c1.id2='1' AND c2.id=c1.id GROUP BY c1.id ORDER BY c1.id DESC"); ?> UNREAD MESSAGES (<?php echo intval($query1->count()); ?>) <br> READ MESSAGES (<?php echo intval($query2->count()); ?>)I've tried running through things in a logical path: UNREAD MESSAGES member1 = logged in user read1 = No removed1 = No members.id = member2 OR member2 = logged in user read2 = No removed2 = No members.id = member1 READ MESSAGES member1 = logged in user read1 = Yes removed1 = No members.id = member2 OR member2 = logged in user read2 = Yes removed2 = No members.id = member1 I can't understand how if 'read1 = yes and the logged in user is member1, why they are being counted in the unread list. Can anyone see what I have done wrong? Edited by MartynLearnsPHP, 15 November 2014 - 08:05 AM. Can someone please double check my search query to make sure it is the minimum and most efficient coding. My goal is an exact match search of field1 from my database table and list field1, field2, field3, field4 and field5 if the part number is in the database or no results if it is not. The query works as is but I have a feeling it could be done more efficiently or professionally and minimum work for my poor little server. Thanks in advance. Code: [Select] <?php //connect to the database include("./databaseconnect.php"); //get query $q=$_GET['q']; //convert query to uppercase & remove all spaces and special charactars $q=strtoupper(preg_replace("/[^A-Za-z0-9]/","",$q)); //if blank query if ($q == "") { echo "You did not enter a search term"; } else { //exact match only query $query = "SELECT * FROM ".$dbtable." WHERE field1 like \"$q\""; $result = mysql_query($query); //if query returns no results if(mysql_num_rows($result)==0) { echo "<span class=\"noresults\">There were no results for your search</span>"; //display database results } else { while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { echo "<span class=\'results\'>SEARCH RESULTS</span><br /> <span class=\'list\'>Part Number: ".$row['field1']."<br /> Manufacturer: ".$row['field2']."<br /> Cost per unit: ".$row['field3']."<br /> Warehouse Location: ".$row['field4']."<br /> Quantity Available: ".$row['field5']."<br /> Notes: ".$row['field6']."<br /> </span>"; } } } ?> Hello all, Trying to figure out how to display database results so that they are numbered (for editing and deletion purposes). I want to be able to edit the message text and update the database information with the UPDATE command, but have not gotten that far yet. Current problem is that I am returning no results. Here is my script: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>My Profile</title> <link href="loginmodule.css" rel="stylesheet" type="text/css" /> </head> <body> <h1>My Profile </h1> <a href="member-index.php">Home</a> | <a href="member-profile.php">My Profile</a> | Update Posts | <a href="logout.php">Logout</a> <br /><br /> <?php $subject = $_POST['subject']; $message_text = $_POST['message_text']; //Connect to mysql server $link = mysql_connect('XXXXXX', 'XXXXXX', 'XXXXXX'); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db('ryan_iframe'); if(!$db) { die("Unable to select database"); } // validate incoming values $subject = (isset($_GET['subject'])) ? (int)$_GET['subject'] : 0; $message_text = (isset($_GET['message_text'])) ? (int)$_GET['message_text'] : 0; ob_start(); $id = $_GET['SUBJECT']; $query = sprintf( " SELECT SUBJECT, MSG_TEXT, UNIX_TIMESTAMP(MSG_DATE) AS MSG_DATE FROM FORUM_MESSAGE WHERE SUBJECT = '$id' ORDER BY MSG_DATE DESC", DB_DATABASE, DB_DATABASE, $subject, $subject); $result = mysql_query($query) or die(mysql_error()); $num = mysql_numrows($result); mysql_close(); $i = 0; while ($i < $num) { $subject = mysql_result($result, $i, "SUBJECT"); $message_text = mysql_result($result, $i, "MSG_TEXT"); echo '<div style="width: 400px;padding:20px;">'; echo '<table border=0 width="400px">'; echo '<tr>'; echo '<td style="vertical-align:top;width:auto;">'; echo 'Date: '; echo '</td>'; echo '<td style="vertical-align:top;width:320px;">'; echo date('F d, Y', $row['MSG_DATE']) . '</td>'; echo '</tr>'; echo '<tr>'; echo '<td style="vertical-align:top;width:auto;">'; echo 'Subject: '; echo '</td>'; echo '<td style="vertical-align:top;width:320px;">'; echo '<div>' . htmlspecialchars($row['SUBJECT']) . '</div>'; echo '</td>'; echo '</tr>'; echo '<tr>'; echo '<td style="vertical-align:top;width:auto;">'; echo 'Message: '; echo '</td>'; echo '<td style="vertical-align:top;width:320px;">'; echo '<div>' . htmlspecialchars($row['MSG_TEXT']) . '</div>'; echo '</td>'; echo '</tr>'; echo '<tr>'; echo '<td style="vertical-align:top;width:auto;">'; echo '</td>'; echo '<td style="vertical-align:top;width:320px;text-align:center;">'; echo '<form method="post">'; echo '<input type="hidden" name="update" value="true" />'; echo '<input type="submit" value="Update" />'; echo ' '; echo '<input type="hidden" name="delete" value="true" />'; echo '<input type="submit" value="Delete" />'; echo '</form>'; echo '</td>'; echo '</tr>'; echo '</table>'; echo '<br />'; echo '<hr />'; echo '</div>'; ++$i; } ?> </body> </html> Thanks in advance. Ryan I'm trying to get a nickname system working for a little project, but I've run into a problem. This code that I wrote here gets the users nickname from their username: Code: (php) [Select] $user = $_GET['user']; @mysql_select_db("db") or die( "Unable to select database"); $query = mysql_query("SELECT `nickname` FROM `info` WHERE `username`='$user'"); WHILE($rows = mysql_fetch_array($query)): $nickname = $rows['nickname']; echo $nickname; endwhile; ?> But the problem is, if the user doesn't have a nickname then it just turns up blank. How can I check if the output of $nickname is blank and if it is then just return their normal name ($user) Thanks Oh, and how to you format php code to look like php code on these forums? |