PHP - Invoke [

Hello,   I need to create a variable that also has a function when invoked, much like the OOP __invoke magic method, but with a variable rather than a class object.   #1: Is this possible?   Consider the situation:   $parent->child->variable = "test";   I also want to run a SQL query using $parent->child->variable('= 2'); where this function would look like   function $this->variable($params) {    return mysql_query('SELECT FROM `parent`.`child` WHERE `variable`' . $params); }   I already know about safety, etc., so I don't need help on that front. I just need to know if a variable can also be used as a function via its own __invoke magic method or something similar?

hello everybody!

This is just basic script, where i try to modify for the needs. I try to play with it. i want to parse some data. The whole script has  three parts:

1. Fetching
2. parsing
3. storing

i want to put all into one script: Two are allready put together - there all seems to be clear...
So  this thread is one that asks for  the combining two parts of a script - how to invoke a variable between them


What has happened untill now:
1st i need to have a connection to database lets say MySQL. I will suggest to use mysqli instead of mysql.
Well - okay i safe this db.php




$host="localhost"; //database hostname
$username="******"; //database username
$password="******"; //database password
$database="******"; //database name
?>

Now i am going to take a new script and  save this config.php
<?php
require_once('db.php'); //call db.php
$connect=mysqli_connect($host,$username,$password); //connect to mysql through mysqli
if(!$connect){
die("Cannot connect to host, please try later."); //throw error if any problem
}
else
{
$select_db=mysqli_select_db($database); //select database
if(!$select_db){
die("Site Database is down at the moment, Please check later. We will be back shortly."); // error if cannot connect to database or db does not exist
}
}
?>


Now i have to take care for the script, that takes the files (note this is very basic - it is only a proof of concept.
In the real situation i will take cURL since cURL is much much nicer and more elegant and faster etc.


<?php
require_once('config.php'); // call config.php for db connection
$content = file_get_contents("<-here the path to the file goes in-> Position XY! an URL is here ");

var_dump($content);

$pattern = '/<td>(.*?)<\/td>/si';
preg_match_all($pattern,$content,$matches);

foreach ($matches[1] as $match) {
    $match = strip_tags($match);
    $match = trim($match);
    var_dump($match);
$sql = mysqli_query("insert into tablename(contents) values ('$match')");
}

?> 


Note: This is just basic script, where you can modify it for your taste and can play with it.

Question:  If i have stored the URLs that i want to parse in a local file - how do i "call" them in the script.
How do i do the call to file where the URLs (there are more than 2500 URLs that have to be parsed) at the
following position: $content = file_get_contents("<-here the path to the file goes in-> Position XY! an URL is here ");


The folder with the URLs is stored in the same folder as the scripts reside!

Many thanks for all hints and for a starting point!

if i have to write more - or if you need more infos - or if i have to be more concrete, just let me know!


i love to hear from you!
db1

Hi ,

I am tring to call user define function of java which parse xsl & xml and executing it using php but it is giving me following error.
Versions i am using JDK 1.5,Php 5.3,JavaBridge.

Fatal error: Uncaught [[o:Exception]:"java.lang.Exception: Invoke failed: [[o:PhpJBridge]]->XMLXSL((o:String)[o:String], (o:String)[o:String]). Cause: javax.xml.transform.TransformerConfigurationExcep tion: Could not compile stylesheet VM: 1.5.0_18@http://java.sun.com/" at: #-12 com.sun.org.apache.xalan.internal.xsltc.trax.Tran sformerFactoryImpl.newTemplates(Unknown Source) #-11 com.sun.org.apache.xalan.internal.xsltc.trax.Tran sformerFactoryImpl.newTransformer(Unknown Source) #-10 PhpJBridge.XMLXSL(SaxonTest.java:88) #-9 sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) #-8 sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) #-7 sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) #-6 java.lang.reflect.Method.invoke(Unknown Source) #-5 php.java.bridge.JavaBridge.Invoke(JavaBridge.java:1049) #-4 php.java.bridge.Request.handleRequest(Request.java:415) #-3 php.java.bridge.Request.handleRequests(Request.java:491) #-2 php.java.bridge.http.ContextRunner.run(ContextRunner.java:145) #-1 p in http://localhost:8080/EchoServer/java/Java.inc on line 117

I have a PHP file in /var/www/html/ called foobar.php with the following content:

Quote

<?php
shell_exec('/usr/bin/env > /tmp/output');
?>

From the backend I can run php foobar.php.  It works as expected.  When I browse to my website and go to foobar.php, the /tmp/output file does not receive anything.  

I set the permissions of the foobar.php file to different settings.  I set the owner and group of foobar.php and /tmp/output to different values.

I tried modifying the httpd.conf file.  When I placed this stanza in the httpd.conf file

Quote

LoadModule php7_module /usr/lib64/httpd/modules/libphp7.so

I could not restart the httpd service.  I tried using just

Quote

LoadModule php7_module modules/libphp7.so

  But this failed too.  

I thought PHP would interpret the file regardless of how I access it (e.g., via a web page and with the php command from a Linux terminal).  How do I get PHP to invoke a Bash command when someone visits a .php web page?