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PHP - Search Boxes
I am trying to add two search boxes to the below code. I need First Name, Last Name and Skill. I have added the boxes and connected fname (first_name) but am not sure how to link the other two correctly. Can anybody please help? I think it's something to do with the bold red text.
Thanks <h3>Search Contacts Details</h3> <p>You may search either by first or last name</p> <form method="post" action="a.php?go" id="searchform"> <input type="text" name="fname"> <input type="text" name="lname"> <input type="text" name="skill"> <input type="submit" name="submit" value="Search"> </form> <?php if(isset($_POST['submit'])){ if(isset($_GET['go'])){ if(preg_match("/^[ a-zA-Z]+/", $_POST['fname'])){ $fname=$_POST['fname']; //connect to the database $db=mysql_connect ("127.0.0.1", "root", "") or die ('I cannot connect to the database because: ' . mysql_error()); //select the database to use $mydb=mysql_select_db("resource matrix"); //query the database table $sql="SELECT DISTINCT First_Name, Last_Name, l.Resource_ID FROM ((resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID) inner join skill n on ln.Skill_ID = n.Skill_ID) WHERE First_Name LIKE '%" . $fname . "%' OR Last_Name LIKE '%" . $lname ."%' OR Skill_Name LIKE '%" . $skill ."%'"; Similar TutorialsI have a simple (1 table, 14 fields) database. I'm using 9 separate search boxes from my search page : http://www.cinemaposter.com/database.html There are currently 162 entries. Hitting "submit" throws them all out, same with valid input into any box, with the exception of "country" - example : entering "F" gives 20results; "PL" gives 34 results. Here's my code (to simplify, I only went down to the 4th box ('country' - the last and only one giving correct results). I'm one sorry newbie.... please help ! Here's the code : ------------------ <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/1998/REC-html40-19980424/loose.dtd"> <html> <head> <title>Search Results</title> <meta name="generator" content="BBEdit 6.5"> <style type="text/css"> td { color: #000000; font-family: arial; font-size: 10px; } </style> </head> <body> <?php $link = mysql_connect("xxxx", "xxxx", "xxxx") or die("Could not connect"); ///print "Connected successfully<BR>"; mysql_select_db("xxxx") or die("Could not select database"); { $Author = $_POST['Author']; $sql = "SELECT * FROM posters WHERE Author LIKE '%$Author%'"; } { $Title = $_POST['Title']; $sql = "SELECT * FROM posters WHERE Title LIKE '%$Title%'"; } { $Originaltitle =$_POST['Originalitle']; $sql="SELECT * FROM posters WHERE Originaltitle LIKE '%$Originaltitle%'"; } { $Country =$_POST['Country']; $sql="SELECT * FROM posters WHERE Country LIKE '%$Country%'"; } $result = mysql_query ($sql) or die("Query failed : " . mysql_error()); $numrs = mysql_num_rows($result); if ($numrs > 0){ if ($numrs==1){ print ("<p><font face=\"Arial\"><b>There is $numrs record in our database.</B> <BR><BR>"); }elseif($numrs>1){ print ("<p><font face=\"Arial\"><b>There are $numrs records in our database. </B><BR><BR>");//Apparently, he wan't to be able to search again...</b><form method \"POST\" action=\"$PHP_SELF\">Search Again:"); } echo("<a href='javascript:history.go(-1)'>Go Back</a></p>"); print("<P align=center>Click on the column heading links to sort the results.<br><br />"); print ("<TABLE CELLPADDING=\"1\" CELLSPACING=\"2\" BORDER=\"0\">\n"); PRINT ("<TR BGCOLOR=\"#FFFF77\"> <TD COLSPAN=2><P align=center>Author</td> <TD><P align=center>Title</TD> <TD><P align=center>Original Title</TD> <TD><P align=center>Country</TD> <TD><P align=center>Director</TD> <TD><P align=center>Cast</TD> <TD><P align=center>Year</TD> <TD><P align=center>Original Year</TD> <TD><P align=center>Photo</TD> <TD><P align=center>Producer</TD> <TD><P align=center>Circulation</TD> <TD><P align=center>Size</TD> <TD><P align=center>Print type</TD> <TD><P align=center>Remarks</TD></TR>"); $z=1; while ($line = mysql_fetch_array($result)) { $num=$z++; //Note here that I'm assigning the found objects new names (indicated by lowercase) to that php wont get confused..... $auth=$line['Author']; $title=$line['Title']; $originaltitle=$line['Originaltitle']; $country=$line['Country']; $director=$line['Director']; $cast=$line['Cast']; $year=$line['Year']; $originalyear=$line['Originalyear']; $producer=$line['Producer']; $circ=$line['Circulation']; $size=$line['Size']; $print=$line['Print']; $remarks=$line['Remarks']; $pict=$line['Picture']; //Set the formatting $bgcolor = ($i++ & 1) ? '#d3d3d3' : '#c0c0c0'; PRINT("<TR BGCOLOR=$bgcolor> <TD>$num.</TD> <TD>$auth</td> <TD>$title</TD> <TD>$originaltitle</TD> <TD><P align=center>$country</TD> <TD>$director</TD> <TD>$cast</TD> <TD><P align=center>$year</TD> <TD><P align=center>$originalyear</TD><TD>"); // This is the test to find do we have a picture if ($pict) { // If there is a picture, display it: print ("<P align=center><a href='zdjecie.php?zdj= $pict&autor=$auth&opis=$title&orig=$originaltitle&rok=$year' target='_blank'> <img src=$pict height=\"150\"></a>"); } else { // We don't have a picture, so we print some text instead: print ("<P align=center>no picture available"); } print ("</TD><TD>$producer</TD> <TD><P align=center>$circ</TD> <TD>$size</TD> <TD>$print</TD> <TD>$remarks</TD></TR>"); } PRINT("</TABLE><BR><font face=\"Arial\"><a href=\"javascript:history.go(-1);\">Search Again</a></font>"); }else { print ("<font face=\"Arial\">Sorry, there were no results for your search. <a href=\"javascript:history.go(-1);\">Please try again</a></font>"); } //mysql_close($link); ?> </body> </html> Hello, I had 8 select boxes(dropdowns) in a form. Its like a search kind of implementation in the website. I don't know what the user selects, he may choose different select boxes, any number of select boxes. So, based upon the user selection, I need to generate the data. The data fields to be generated would be almost same. So, How would I know what the user selection is and how many select boxes has been selected and how could I generate different data based upon selected boxes. I had to make a small note abt this, that the data generation fields may change for some of the user select combinations, but most of the result fields would be same. so, can you please help me out, how to do, how to make different combination data generations, because, i had 8 fields, i had to make 8! combinations, that would result in a big code. The result pages is supposed to have pagination like google help me please
I require a page to be added to my website. This page will facilitate a refined search via Google, Bing and Yahoo search engine simultaneously , show the top 5 of each engine. Is this possible using php ? Thank's Hello, Does anyone know a tutorial I can follow to create my own search engine over the items I have in my SQL database? I find a lot of tutorials but they are all 'one word searches' which means if you type two words you will get all results that contain either word (too many hits). If the search engine tutorial displays result with AJAX even better. Thanks for help. df Hello, I'm developing a website that asks the user to submit a keyword for a search. The results should display matches for this keyword, but also show matches for related keywords (in order of relevenace!). I'm planning on building up a library of which search terms users use in the same sessions (e.g. if someone searches for "it jobs" and "php jobs", I'll know the terms are correlated), and I'll also measure the click-through rates of the items on the results list. I've been spending all weekend trying to map out the design for this but it's proving incredibly complicated and I think the solution is likely to be on the internet somewhere already?! Please could someone point me in the right direction if you've come accross this problem before? Thanks a million, Stu I am developing a intranet forum in Php and MySQL and I am using ajax to display searched results on the same page but right now I am using query LIKE text% to search in database which is slower. but I want to make it fast search engin which can parse *,+ and show result. Since I am using ajax i am not able to use free search engin,so if possible pls provide a complete solution I have code to search a database of members, I can search by lastname but having a little problem. I want to be able to search by lastname starting with the first letter. (ie: a or b or c or d and so on). As it is right now I can only search by first letter of last name if I add % to the search (ie: a% b% c%) will give me all members with the last names starting with the approiate letter designation. I'm not sure how to handle this, any help would be appreciated. Thanks. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <center><table cellspacing="10" cellpadding="10" width="750" border="0"> <h4>Search</h4> <form name="search" method="post" action="<?php $PHP_SELF?>"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="lname">Last Name</option> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <?php // check to see if anything is posted if (isset($_POST['find'])) {$find = $_POST['find'];} if (isset($_POST['searching'])) {$searching = $_POST['searching'];} if (isset($_POST['field'])) {$field = $_POST['field'];} //This is only displayed if they have submitted the form if (isset($searching) && $searching=="yes") { echo "<h4>Results</h4><p>"; // If they did not enter a search term we give them an error if (empty($find)) { echo "<p>You forgot to enter a search term"; exit; } // Otherwise we connect to our Database mysql_connect("localhost", "root", "1910") or die(mysql_error()); mysql_select_db("cmc_member") or die(mysql_error()); // We preform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); // Now we search for our search term, in the field the user specified $results = mysql_query("SELECT * FROM members WHERE upper($field) LIKE'$find'"); // And we display the results if($results && mysql_num_rows($results) > 0) { $i = 0; $max_columns = 3; while($row = mysql_fetch_array($results)) { // make the variables easy to deal with extract($row); // open row if counter is zero if($i == 0) echo "<tr>"; // make sure we have a valid product ALIGN='CENTER' if($fname != "" && $fname != null) echo "<td ALIGN='CENTER'><FONT COLOR='red'><b>$fname $lname</b></FONT><br> $address <br> $city $state $zip <br>$phone<br><a href=\"mailto: $email\">$email</a><br></td>"; // increment counter - if counter = max columns, reset counter and close row if(++$i == $max_columns) { echo "</tr>"; $i=0; } // end if } // end while } // end if results // clean up table - makes your code valid! if($i < $max_columns) { for($j=$i; $j<$max_columns;$j++) echo "<td> </td>"; } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches = mysql_num_rows($results); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> </tr> </table></center> </body> </html> Hello. I am working on a php script for searching a database table. I am really new to this, so I used the this tutorial http://www.phpfreaks.com/tutorial/simple-sql-search I managed to get all the things working the way I wanted, except one important and crucial thing. Let me explain. My table consist of three columns, like this: ID(bigint20) title(text) link (varchar255) ============================= ID1 title1 link-1 ID2 title2 link-2 etc... Like I said, I managed to make the script display results for a search query based on the title. Want I want it to do more, but I can't seem to find the right resource to learn how, is to place a "Download" button under each search result with its corresponding link from the table. Here is the code I used. <?php $dbHost = 'localhost'; // localhost will be used in most cases // set these to your mysql database username and password. $dbUser = 'user'; $dbPass = 'pass'; $dbDatabase = 'db'; // the database you put the table into. $con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error()); mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error()); // Set up our error check and result check array $error = array(); $results = array(); // First check if a form was submitted. // Since this is a search we will use $_GET if (isset($_GET['search'])) { $searchTerms = trim($_GET['search']); $searchTerms = strip_tags($searchTerms); // remove any html/javascript. if (strlen($searchTerms) < 3) { $error[] = "Search terms must be longer than 3 characters."; }else { $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection. } // If there are no errors, lets get the search going. if (count($error) < 1) { $searchSQL = "SELECT title, link FROM db WHERE title LIKE '%{$searchTermDB}%'"; $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided {$searchTerms} yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; } } } } function removeEmpty($var) { return (!empty($var)); } ?> <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?> <form method="GET" action="search?" name="searchForm"> Search for title: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" /> <input type="submit" name="submit" value="Search" /> </form> <?php echo (count($results) > 0)?"Rezultate lucrari de licenta sau disertatie pentru {$searchTerms} :<br /><br />" . implode("", $results):""; ?> $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; I would like the results to be displayed like this Results for SearchItem: Result 1 Download | Other link Result 2 Download | Other link etc.... or something like this. So, how do I add the data from the link row into a text(Dowload), within an <a href> tag (well, at least I guess it would go this way) ? My first tries (fueled by my lack of knowledge) where things like $results[] = "{$row['title']}<br /> <a href="{$row['link']}">Download</a> <br /> "; but I keep getting lots of errors, and then I don't know much about arrays and stuff (except basic notions); So there it is. I am really stuck and can't seem to find any workaround for this. Any suggestions? (examples, documentation, anything would do, really) Thanks, Radu Hi all How do I modify the below code to search multiple tables in mySQL database? $query = "select * from store_items where description like \"%$trimmed%\" or title like \"%$trimmed%\" or dimensions like \"%$trimmed%\" order by id ASC"; $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); It is for a search function and I need it to search another table called 'about_text' and 'faq_text' Thanks Pete Friends, I want to extract the Search Keyword from the URL, a visitor came from. I am using a PHP CMS and want to show the Keyword on my Blog. So if they search "abcd" from google, i want to extract "abcd" and echo on my blog. Here is the coding i could got hold of, but its not working, not echoing anything <?php function pk_stt2_function_get_delimiter($ref) { $search_engines = array('google.com' => 'q', 'go.google.com' => 'q', 'images.google.com' => 'q', 'video.google.com' => 'q', 'news.google.com' => 'q', 'blogsearch.google.com' => 'q', 'maps.google.com' => 'q', 'local.google.com' => 'q', 'search.yahoo.com' => 'p', 'search.msn.com' => 'q', 'bing.com' => 'q', 'msxml.excite.com' => 'qkw', 'search.lycos.com' => 'query', 'alltheweb.com' => 'q', 'search.aol.com' => 'query', 'search.iwon.com' => 'searchfor', 'ask.com' => 'q', 'ask.co.uk' => 'ask', 'search.cometsystems.com' => 'qry', 'hotbot.com' => 'query', 'overture.com' => 'Keywords', 'metacrawler.com' => 'qkw', 'search.netscape.com' => 'query', 'looksmart.com' => 'key', 'dpxml.webcrawler.com' => 'qkw', 'search.earthlink.net' => 'q', 'search.viewpoint.com' => 'k', 'mamma.com' => 'query'); $delim = false; if (isset($search_engines[$ref])) { $delim = $search_engines[$ref]; } else { if (strpos('ref:'.$ref,'google')) $delim = "q"; elseif (strpos('ref:'.$ref,'search.atomz.')) $delim = "sp-q"; elseif (strpos('ref:'.$ref,'search.msn.')) $delim = "q"; elseif (strpos('ref:'.$ref,'search.yahoo.')) $delim = "p"; elseif (preg_match('/home\.bellsouth\.net\/s\/s\.dll/i', $ref)) $delim = "bellsouth"; } return $delim; } /** * retrieve the search terms from search engine query * */ function pk_stt2_function_get_terms($d) { $terms = null; $query_array = array(); $query_terms = null; $query = explode($d.'=', $_SERVER['HTTP_REFERER']); $query = explode('&', $query[1]); $query = urldecode($query[0]); $query = str_replace("'", '', $query); $query = str_replace('"', '', $query); $query_array = preg_split('/[\s,\+\.]+/',$query); $query_terms = implode(' ', $query_array); $terms = htmlspecialchars(urldecode(trim($query_terms))); return $terms; } /** * get the referer * */ function pk_stt2_function_get_referer() { if (!isset($_SERVER['HTTP_REFERER']) || ($_SERVER['HTTP_REFERER'] == '')) return false; $referer_info = parse_url($_SERVER['HTTP_REFERER']); $referer = $referer_info['host']; if(substr($referer, 0, 4) == 'www.') $referer = substr($referer, 4); return $referer; } $referer = pk_stt2_function_get_referer(); if (!$referer) return false; $delimiter = pk_stt2_function_get_delimiter($referer); if( $delimiter ){ $term = pk_stt2_function_get_terms($delimiter); } echo $term; ?> May someone help? Natasha T Hello All, Hi all Im looking to do a "SIMPLE" search on a databse usign php. I want to have a drop down box like so : <select name="Lowest"> <option>0</option> <option>100</option> <option>200</option> </select> this is for the prices i want 2 of these so that the first will be the lowest price and the second will be the higher price Then i will make a query to SELECT * WHERE ( i dont know how to call the results from the select box here to display the whole tabled results ) any help please thnax Hi I have 3 drop down boxes and I want my boxes to go to another page when I select them and click go. For example if I click western cape I want it to give me all the resorts in western cape and if I click western cape and beaches I want it to give me all the resorts that are in the western cape that are next to beaches. I have been able to populate the drop down boxes with information and it can go to another page but it doesn't give me the information I want. This is my drop down boxes code Code: [Select] <script type="text/javascript"> function showGo(){ var region_id = $("#region_id").val(); var lifestyle_id = $("#lifestyle_id").val(); var resort_facility_id = $("#resort_facility_id").val(); if((region_id != 'false') || (lifestyle_id != 'false') || (resort_facility_id != 'false')){ $("#destinationSearchButton").css('display', 'block'); }else{ $("#destinationSearchButton").css('display', 'none'); } </script> <form action="/pages/search/" method="post"> <select class="formSelect" name="region_id" id="region_id" size="1" tabindex="1" onchange="showGo()"> <option label="Region"> <?php $regions_model = new regions_model('regions'); $regions = $regions_model -> get_all(); foreach($regions as $region){ $name = $region['name']; $id =$region['id']; $select = "SELECT $id, $name FROM regions"; echo "<option value='$id'>$name</option>"; } ?> </option> </select> <select class="formSelect" name="lifestyle_id" id="lifestyle_id" size="1" tabindex="2" onchange="showGo()"> <option label="lifestyle"> <?php $lifestyles_model = new lifestyles_model('lifestyles'); $lifestyles = $lifestyles_model -> get_all(); foreach($lifestyles as $lifestyle){ $name = $lifestyle['name']; $id = $lifestyle['id']; $select = "SELECT $name FROM lifestyles"; echo "<option name='$id'>$name</option>"; } ?> </option> </select> <select class="formSelect" name="resort_facility_id" id="resort_facility_id" size="1" tabindex="3" onchange="showGo()"> <option label="Facilities & Amenities"> <?php $resort_facilities_model = new resort_facilities_model('resort_facilities'); $resort_facilities= $resort_facilities_model -> get_all(); foreach($resort_facilities as $resort_facility){ $name = $resort_facility['name']; $id = $resort_facility['id']; $select = "SELECT $name FROM resort_failities"; echo "<option name='$id'>$name</option>"; } ?> </option> </select> <input class="formInputButton" type="submit" name="submitButtonName" id="destinationSearchButton" value="Go" tabindex="4"/ style="display: none;" /> </form> </div> Thank you Hi, im new to php and got a simple query. i have built a web gallery and i want to add keywords to pictures, ive built the interface and mysql statements so it lists all possible keywords and creates a tick box for the user to use. ive created a table to join the image id's to my keyword id's as its going to be a many to many relationship, ive also built the sql statement below to select the highlighted image, but im not sure how i can join the looping of all keywords to generate the tick boxes and then to loop again to populate the tickboxes that are saved within the DB - if that makes sense?? SELECT * FROM images,img_key,keywords where img_key.img_id=images.id and keywords.id=img_key.key_id and images.id='2' Im having a problem in popup box.. i made a checkbox in a loop.. then after a success loop ive set a code for a popupbox. Code: [Select] echo '<script type="text/javascript"> {alert("Rejected!");} </script>'; But when a user checked 2 check boxes.. it would also popup a 2 popup box.. How can i make my code only popup once even if it selects multiple checkboxes? I want to know how to display results from mysql database by filling in a form. but i have found a tutorial which shows typing in a text box which displays results. if i follow this tutorial will it help me to understand and create php coding to display results for my form? Need some help I have 2 tables in a database and I need to search the first table and use the results from that search, to search another table, can this be done? and if it can how would you recommend that I go about it? Thanks For Your Help Guys! I have a form that contains radio buttons and when it is submitted the content of the form are added to a database. I was wondering how you get the values of radio boxes when submitting the form. I have the following radio buttons and when submitting I use "$_POST['article_type']" but this doesn't seem to work. Thanks for any help. <label>PDF Article</label><input name="article_type" value="pdf" type="radio" /> <label>Video Webcast</label><input name="article_type" value="webcast" type="radio" /> <label>Podcast</label><input name="article_type" value="podcast" type="radio" /> Hi There, Is there any way that I can get a select box to auto-select the value from a SQL query? For example, if I have a select box like this: Dave,Jon,Simon,Fred And a select statement that brings back the value of Fred then the select box (in HTML) would: <select name='people'><option>Dave</option><option>Jon</option><option>Simon</option><option selected='selected'>Fred</option></select> Same as if the name was Dave, or Simon etc etc. Hope that makes sense? Cheers Matt |
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