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PHP - Displaying An Image From Mysql Database Into Html Table.
Not really sure how to get the images I have stored in MySQL into a html form. I can call-up the text fields from the database but it cannot seem to find the index for the images.
Here is my code:- <?php session_start(); mysql_connect("localhost","root","abc") or die ("Error! Cannot connect to database"); mysql_select_db("theimageworks") or die ("Cannot find database"); $query = "SELECT * FROM jobs"; $result = mysql_query($query) or die (mysql_error()); ?> <?php //display data in html table echo "<table>"; echo "<tr><td>Username</td><td align='center'>Message</td><td>Product Image</td></tr>"; while($row = mysql_fetch_array($result)) { echo "</td><td>"; echo $row['username']; echo "</td><td>"; echo $row['message']; echo "</td></tr>"; echo $row['image']; } echo "</table>"; ?> The error message I get is "Notice: Undefined index: image in....." Thanks in advance! Similar TutorialsSo I have a jobs database with the following columns: id, jobtext, jobdate, and id. This is how it looks right now: http://prahan.com/jobs/display.html.php I have another table called author. In the authorid column in need the results of this query, SELECT name FROM author WHERE id = (SELECT authorid FROM job) , to be displayed for each row. I also want to be able to customize the header title for each column. Thanks in advance! Hi, I'm trying to make a dynamic html table to contain the mysql data that is generated via php. I'm trying to display a user's friends in a table of two columns and however many rows, but can't seem to figure out what is needed to make this work. Here's my code as it stands: Code: [Select] <?php //Begin mysql query $sql = "SELECT * FROM friends WHERE username = '{$_GET['username']}' AND status = 'Active' ORDER BY friends_with ASC"; $result = mysql_query($sql); $count = mysql_num_rows($result); $sql_2 = "SELECT * FROM friends WHERE friends_with = '{$_GET['username']}' AND status = 'Active' ORDER BY username ASC"; $result_2 = mysql_query($sql_2); $count_2 = mysql_num_rows($result_2); while ($row = mysql_fetch_array($result)) { echo $row["friendswith"] . "<br>"; } while ($row_2 = mysql_fetch_array($result_2)) { echo $row_2["username"] . "<br>"; } ?> The above simply outputs all records of a user's friends (their usernames) in alphabetical order. The question of how I'd generate a new row each time a certain amount of columns have been met, however, is beyond me. Anyone know of any helpful resources that may solve my problem? Thanks in advance =) Hello I have an array with data from `mysql` that I would like to output it in a table using twig. The image is an example of want i want to achieve but without any luck. `print_r` of the array data Array ( [Administrator] => Array ( [0] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-View [PermissionId] => 1 ) [1] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-Edit [PermissionId] => 2 ) [2] => Array ( [RoleName] => Administrator [PermissionName] => Catalog-Delete [PermissionId] => 3 ) ) [Moderator] => Array ( [0] => Array ( [RoleName] => Moderator [PermissionName] => Catalog-View [PermissionId] => 1 ) ) ) The `HTML` code:
<table>
<tr>
<thead>
<th>Controller - Action</th>
{% for permission in permissions %}
{% for item in permission %}
<th>{{item.RoleName}}</th>
{% endfor %}
{% endfor %}
</thead>
</tr>
{% for permission in permissions %}
{% for item in permission %}
<tr>
<td>{{item.PermissionName}}</td>
<td>{{item.PermissionId}}</td>
</tr>
{% endfor %}
{% endfor %}
</table>
OUTPUT: <table> <tbody> <tr></tr> </tbody> <thead> <tr> <th>Controller - Action</th> <th>Administrator</th> <th>Administrator</th> <th>Administrator</th> <th>Moderator</th> </tr> </thead> <tbody> <tr> <td>Catalog-View</td> <td>1</td> </tr> <tr> <td>Catalog-Edit</td> <td>2</td> </tr> <tr> <td>Catalog-Delete</td> <td>3</td> </tr> <tr> <td>Catalog-View</td> <td>1</td> </tr> </tbody> </table> Later Edit MySQL Query: SELECT t3.PermissionName, t1.PermissionId, t2.RoleName FROM tbl_user_role_perm AS t1 INNER JOIN tbl_user_roles AS t2 ON t1.RoleId = t2.RoleId INNER JOIN tbl_user_permissions AS t3 ON t1.PermissionId = t3.PermissionId MySQL Dump: -- Dumping structure for table tbl_user_permissions CREATE TABLE IF NOT EXISTS `tbl_user_permissions` ( `PermissionId` int(11) NOT NULL AUTO_INCREMENT, `PermissionName` varchar(50) NOT NULL, `PermissionDescription` varchar(100) NOT NULL, PRIMARY KEY (`PermissionId`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1; -- Dumping data for table tbl_user_permissions: ~2 rows (approximately) DELETE FROM `tbl_user_permissions`; /*!40000 ALTER TABLE `tbl_user_permissions` DISABLE KEYS */; INSERT INTO `tbl_user_permissions` (`PermissionId`, `PermissionName`, `PermissionDescription`) VALUES (1, 'Catalog->View', 'View Catalog Method'), (2, 'Catalog->Edit', 'Edit Catalog Method'), (3, 'Catalog->Delete', 'Delete Catalog Method'); /*!40000 ALTER TABLE `tbl_user_permissions` ENABLE KEYS */; -- Dumping structure for table tbl_user_role CREATE TABLE IF NOT EXISTS `tbl_user_role` ( `UserRoleId` int(10) NOT NULL AUTO_INCREMENT, `UserId` int(10) NOT NULL, `RoleId` int(10) unsigned NOT NULL, PRIMARY KEY (`UserRoleId`), KEY `FK_tbl_user_role_tbl_user_roles` (`RoleId`), KEY `UserId` (`UserId`) ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1; -- Dumping data for table tbl_user_role: ~2 rows (approximately) DELETE FROM `tbl_user_role`; /*!40000 ALTER TABLE `tbl_user_role` DISABLE KEYS */; INSERT INTO `tbl_user_role` (`UserRoleId`, `UserId`, `RoleId`) VALUES (1, 13, 22), (2, 14, 22); /*!40000 ALTER TABLE `tbl_user_role` ENABLE KEYS */; -- Dumping structure for table tbl_user_roles CREATE TABLE IF NOT EXISTS `tbl_user_roles` ( `RoleId` int(10) unsigned NOT NULL AUTO_INCREMENT, `RoleName` varchar(50) NOT NULL, `CreatedDate` datetime NOT NULL, `ModifiedDate` datetime DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP, PRIMARY KEY (`RoleId`) ) ENGINE=InnoDB AUTO_INCREMENT=29 DEFAULT CHARSET=utf8; -- Dumping data for table tbl_user_roles: ~7 rows (approximately) DELETE FROM `tbl_user_roles`; /*!40000 ALTER TABLE `tbl_user_roles` DISABLE KEYS */; INSERT INTO `tbl_user_roles` (`RoleId`, `RoleName`, `CreatedDate`, `ModifiedDate`) VALUES (22, 'Administrator', '2014-10-28 09:53:08', NULL), (23, 'Moderator', '2014-10-28 09:53:13', NULL), (24, 'Admin', '2014-10-28 12:22:05', '2014-10-28 12:22:06'), (25, 'User', '2014-10-29 15:10:36', '2014-10-29 15:10:37'), (26, 'SuperUser', '2014-10-29 15:10:45', '2014-10-29 15:10:46'), (27, 'Accountant', '2014-10-29 15:10:53', '2014-10-29 15:10:54'), (28, 'God', '2014-10-29 15:11:02', '2014-10-29 15:11:02'); /*!40000 ALTER TABLE `tbl_user_roles` ENABLE KEYS */; -- Dumping structure for table tbl_user_role_perm CREATE TABLE IF NOT EXISTS `tbl_user_role_perm` ( `RoleId` int(10) unsigned NOT NULL, `PermissionId` int(10) unsigned NOT NULL, KEY `RoleId` (`RoleId`), KEY `PermissionId` (`PermissionId`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; -- Dumping data for table tbl_user_role_perm: ~3 rows (approximately) DELETE FROM `tbl_user_role_perm`; /*!40000 ALTER TABLE `tbl_user_role_perm` DISABLE KEYS */; INSERT INTO `tbl_user_role_perm` (`RoleId`, `PermissionId`) VALUES (22, 2), (22, 1), (23, 1), (22, 3); /*!40000 ALTER TABLE `tbl_user_role_perm` ENABLE KEYS */; /*!40101 SET SQL_MODE=IFNULL(@OLD_SQL_MODE, '') */; /*!40014 SET FOREIGN_KEY_CHECKS=IF(@OLD_FOREIGN_KEY_CHECKS IS NULL, 1, @OLD_FOREIGN_KEY_CHECKS) */; /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;Can you help me to make the coding required so that the correct column have the correct permissions? thank you in advance. Hello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
echo '
<tr>
<td>'.$row["id"].'</td>
';
while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) {
echo '
<td>'.$row1["email"].'</td>
';
}
if($row["validity"] == 1) {
echo '<td>'.$row["validity"].' month</td>';
}else{
echo '<td>'.$row["validity"].' months</td>';
}
echo ' <td>'.$row["valid_from"].'</td>
<td>'.$row["valid_to"].'</td>
</tr>';
}
?>
Thank you. Hi I have got results being displayed after clicking the search button in a form on my home page but it brings up all the results which is ok but how do I get onlt the results a user searches for for example a location or property type etc as its for a property website The coding is below for the results page Also sorry how do I add a background image to the php page, I tried using css but wouldn't work Code: [Select] <style type="text/css"> body {background-image:url('images/greybgone.png');} </style> <?php mysql_connect ("2up2downhomes.com.mysql", "2up2downhomes_c","mD8GsJKQ") or die (mysql_error()); mysql_select_db ("2up2downhomes_c"); echo $_POST['term']; $sql = mysql_query("select * from properties where typeProperty like '%$term%' or location like '%$term%'"); while ($row = mysql_fetch_array($sql)){ echo 'Type of Property: '.$row['typeProperty']; echo '<br/> Number of Bedrooms: '.$row['bedrooms']; echo '<br/> Number of Bathrooms: '.$row['bathrooms']; echo '<br/> Garden: '.$row['garden']; echo '<br/> Description: '.$row['description']; echo '<br/> Price: '.$row['price']; echo '<br/> Location: '.$row['location']; echo '<br/> Image: '.$row['image']; echo '<br/><br/>'; } ?> Hi, This has been baffling me for a couple hours now and i cant seem to figure it out. I have some code which creates an array and gets info from a mysql database and then displays in a list. This works great but after adding more and more rows to my database the list is now becoming quite large and doesnt look great on my site. Is it possible to split the list into multiple columns of about 25 and if possible once 3 or 4 columns have been created start another column underneath. To help explain i would be looking at a layout as follows: Code: [Select] line 1 line 1 line 1 line 2 line 2 line 2 ... ... ... line 25 line 25 line 25 line 1 line 1 line 1 line 2 line 2 line 2 ... ... ... line 25 line 25 line 25Im guessing there should be some sort of if statement to check how many items are being displayed and to create a new column if necessary. Is this correct? Thanks, Alex Hi, I have a website where users can log on and edit their profile pic, name, biography etc. I was wondering about the correct way to:- Add data to the database through forms (Register.php) Display the data on a page Using mysql escape sting, however, the way I am currently using will display a '\' before any ' symbol. So it's >> it\'s ... Here is a snippet of the code I am using... Code: [Select] //insert data $about1 = mysql_real_escape_string($_POST['about']); //get $query = mysql_query("SELECT * FROM `staff` WHERE username='$username'"); $row = mysql_fetch_array($query); $about = $row['about']; echo $about; Hello I'm trying to set up a user area for my site where it displays the current logged in users ranking and other information in the future.
<?
ini_set('display_errors', 1);
require_once "header.php";
$sql = "SELECT * FROM users WHERE username = ?";
if($stmt = mysqli_prepare($link, $sql)){
mysqli_stmt_bind_param($stmt, 's', $_SESSION['username']);
if(mysqli_stmt_execute($stmt)){
$info = mysqli_fetch_array($stmt);
echo "Current rank:" . $info['rank'];
} else {
echo "Can't find user";
}
}
mysqli_stmt_close($stmt);
?>
That's the code I currently have but it gives me the error "but get an error message of mysqli_fetch_array() expects parameter 1 to be mysqli_result" This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=308347.0 Greetings,
My current code logs into a database, opens a table named randomproverb, randomly selects 1 proverb phrase, and then SHOULD display the proverb in the footer of my web page.
As of right now, the best I can do is get it to display "Array", but not the text proverb... this code below actually causes my whole footer to not even show up.
Please help!
<?php
include("inc_connect.php"); //Connects to the database, does work properly, already tested
$Proverb = "randomproverb";
$SQLproverb = "SELECT * FROM $Proverb ORDER BY RAND() LIMIT 1";
$QueryResult = @mysql_query($SQLproverb, $DBConnect);
while (($Row = mysql_fetch_assoc($QueryResult)) !== FALSE) {
echo "<p style = 'text-align:center'>" . {$Row[proverb]} . "</p>\n";
}
$SQLString = "UPDATE randomproverb SET display_count = display_count + 1 WHERE proverb = $QueryResult[]";
$QueryResult = @mysql_query($SQLstring, $DBConnect);
...
?>
the script succesfuly insert image to the database bt, i cant be able to display it on my pages, any help i will appreciate
Attached Files
saveimage.php 1.15KB
2 downloads
images_tbl.php 192bytes
3 downloads Hi, wondering if somebody can tell me where I'm going wrong (I'm new to all of this). I have the following php code which uploads an image file into my database: Code: [Select] //Connect to database include 'Resources/Include/db.inc.php'; $tmp=$_FILES['image']['tmp_name']; //get users IP $ip=$_SERVER['REMOTE_ADDR']; //Don't do anything if file wasn't selected if (!empty($tmp)) { //Copy file to temporary folder copy($tmp, "./temporary/".$ip.""); //open the copied image, ready to encode into text to go into the database $filename1 = "./temporary/".$ip; $fp1 = fopen($filename1, "rb"); //record the image contents into a variable $contents1 = fread($fp1, filesize($filename1)); $contents1 = addslashes($contents1); //close the file fclose($fp1); $ftype = $_FILES['image']['type']; //insert information into the database if(!mysql_query("INSERT INTO LetterImages (Data,Type,LetterID,Page)"." VALUES ( '$contents1', '$ftype',1,1)")){ echo mysql_error(); } //delete the temporary file we made unlink($filename1); } This seems to work ok, as when I go to the LetterImages table there is now an additional row with a file in the blob field. I then have the following code which is supposed to display the image: Code: [Select] $result=mysql_query("SELECT * FROM LetterImages WHERE LetterID=1 AND Page=1"); //fetch data from database $sqldata=mysql_fetch_array($result); $encoded=stripslashes($sqldata['Data']); $ftype=$sqldata['Type']; //tell the browser what type of image to display header("Content-type: $ftype"); //decode and echo the image data echo $encoded; Instead of displaying an image, however, this just displays pages and pages of incomprehensible data. Can anybody tell me where I'm going horribly wrong? I want to display my pictures I stored in Mysql in a 4 column, 2 row table WITH pagination. Here's the code I use to display the data currently: Code: [Select] //your username $username = "username"; //your password $password = "password"; //your mySQL server $host = "host"; //The name of the database your table is in $database = "database"; //connect, but if there is a problem, display an error message telling why there is a problem $conn = mysql_connect($host,$username,$password) or die("Error connecting to Database!<br>" . mysql_error()); //Choose the database from your mySQL server, but if there is a problem, display an error telling why $db = mysql_select_db($database) or die("Cannot select database!<br>" . mysql_error()); // find out how many rows are in the table $sql = "SELECT COUNT(*) FROM myphotos"; $result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR); $r = mysql_fetch_row($result); $numrows = $r[0]; // number of rows to show per page $rowsperpage = 4; // find out total pages $totalpages = ceil($numrows / $rowsperpage); // get the current page or set a default if (isset($_GET['currentpage']) && is_numeric($_GET['currentpage'])) { // cast var as int $currentpage = (int) $_GET['currentpage']; } else { // default page num $currentpage = 1; } // end if // if current page is greater than total pages... if ($currentpage > $totalpages) { // set current page to last page $currentpage = $totalpages; } // end if // if current page is less than first page... if ($currentpage < 1) { // set current page to first page $currentpage = 1; } // end if // the offset of the list, based on current page $offset = ($currentpage - 1) * $rowsperpage; // get the info from the db $sql = "SELECT * FROM myphotos ORDER BY id ASC LIMIT $offset, $rowsperpage"; $result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR); /****** build the pagination links ******/ // range of num links to show $range = 3; // if not on page 1, don't show back links if ($currentpage > 1) { // show << link to go back to page 1 echo "<span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=1'>First</a></span> "; // get previous page num $prevpage = $currentpage - 1; // show < link to go back to 1 page echo " <span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=$prevpage'>Previous</a></span> "; } // end if // loop to show links to range of pages around current page for ($x = ($currentpage - $range); $x < (($currentpage + $range) + 1); $x++) { // if it's a valid page number... if (($x > 0) && ($x <= $totalpages)) { // if we're on current page... if ($x == $currentpage) { // 'highlight' it but don't make a link echo " <span class=\"paginationDown\"><b>$x</b></span> "; // if not current page... } else { // make it a link echo " <span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=$x'>$x</a></span> "; } // end else } // end if } // end for // if not on last page, show forward and last page links if ($currentpage != $totalpages) { // get next page $nextpage = $currentpage + 1; // echo forward link for next page echo " <span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=$nextpage'>Next</a></span> "; // echo forward link for lastpage echo " <span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=$totalpages'>Last</a></span><br> "; } // end if /****** end build pagination links ******/ // while there are rows to be fetched... while ($list = mysql_fetch_assoc($result)) { extract ($list); // echo data $url = $list['url'];; $title = $list['title']; $description = $list['description']; echo("$title<br><a rel=\"example_group\" title=\"$description\" href=\"$url\"><img src=\"$url\" alt=\"\" width=\"\" height=\"\" class=\"gallery_images\" /></a>"); } // end while /****** build the pagination links ******/ // range of num links to show $range = 3; // if not on page 1, don't show back links if ($currentpage > 1) { // show << link to go back to page 1 echo "<span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=1'>First</a></span> "; // get previous page num $prevpage = $currentpage - 1; // show < link to go back to 1 page echo " <span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=$prevpage'>Previous</a></span> "; } // end if // loop to show links to range of pages around current page for ($x = ($currentpage - $range); $x < (($currentpage + $range) + 1); $x++) { // if it's a valid page number... if (($x > 0) && ($x <= $totalpages)) { // if we're on current page... if ($x == $currentpage) { // 'highlight' it but don't make a link echo " <span class=\"paginationDown\"><b>$x</b></span> "; // if not current page... } else { // make it a link echo " <span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=$x'>$x</a></span> "; } // end else } // end if } // end for // if not on last page, show forward and last page links if ($currentpage != $totalpages) { // get next page $nextpage = $currentpage + 1; // echo forward link for next page echo " <span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=$nextpage'>Next</a></span> "; // echo forward link for lastpage echo " <span class=\"pagination\"><a href='{$_SERVER['PHP_SELF']}?currentpage=$totalpages'>Last</a></span><br>"; } // end if /****** end build pagination links ******/ The above code just displays the pictures vertically. Here's this code live: http://www.djsmiley.net/gallery/albums/my_photos.php (you can't view the page in IE) Now how would I make it so that the first 8 images in the database display in a 4x2 table, etc.? Hi, I am trying to array a mysql tables data into a php table. Not having luck... <?php include('dbconnect.php') ?> <?php // Make a MySQL Connection $query = "SELECT * FROM cars"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo $row['CarName']. " - ". $row['CarTitle']; echo "<br />"; echo "<TABLE CELLPADDING=0 CELLSPACING=0 WIDTH=100%>"; echo "<TR />"; echo "<TD />"; echo $row['CarName'].; echo "</TD>"; echo "<TD />"; echo $row['CarTitle'].; echo "</TD>"; echo "</TR>"; echo "</TABLE>"; } ?> Error says: Parse error: syntax error, unexpected ';' in /home/wormste1/public_html/tilburywebdesign/shop/FTPServers/barryottley/viewcars.php on line 69 echo </TD /> is line 69. Please help Ian Now I am trying to display the images from my table and I have almost got it working, except for one small thing --- it seems to be displaying all the records, but instead of displaying the right image for each record, it's displaying the same image across all the records. Can anyone tell me what I have done wrong? Code: [Select] this is the gallery <?php $dbhost = 'localhost'; $dbuser = 'webdes17_lizkula'; $dbpass = 'minimoon'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'webdes17_jewelry'; mysql_select_db($dbname); $all_records = "SELECT * FROM gallery"; $all_records_res = mysql_query($all_records); $image = mysql_result($all_records_res, 0, 'image'); while($nt=mysql_fetch_array($all_records_res)){ echo "<img src=http://www.webdesignsbyliz.com/wdbl_wordpress/wp-content/themes/twentyten_2/upload/$image>"; } ?> I'm guessing I have the $image variable in the wrong place, but when I tried placing it within the while statement, the page never loaded, and instead acted like it was loading forever. What am I doing wrong? Here is the link to the page so you can see what is happening: http://webdesignsbyliz.com/wdbl_wordpress/test-submit/ I just can't get anything right today! Now I am trying to have a list of images, and when the user clicks on the image, the next page will display the image along with other fields for that record. I am sending the id through the hyperlink to the next page, and I have echoed it to ensure it's comign through, but I cannot get anythign to display ont he next page. What am I doin wrong? Here is the link to the page. If you click on one of the images, you 'll see that the next page is empty: http://webdesignsbyliz.com/wdbl_wordpress/test-submit/ Here is my code: Code: [Select] this is the gallery <?php $dbhost = 'localhost'; $dbuser = 'user'; $dbpass = 'pass'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'jewelry'; mysql_select_db($dbname); $all_records = "SELECT * FROM gallery"; $all_records_res = mysql_query($all_records); $image = mysql_result($all_records_res, 0, 'image'); $id = mysql_result($all_records_res, 0, 'id'); while($nt=mysql_fetch_array($all_records_res)){ echo "<a href=http://webdesignsbyliz.com/wdbl_wordpress/test-display/?id=" .$nt['id']." ><img src=http://www.webdesignsbyliz.com/wdbl_wordpress/wp-content/themes/twentyten_2/upload/".$nt['image']." width=133 height=86></a>"; } ?> display page: Code: [Select] <?php $id = $_GET['id']; $dbhost = 'localhost'; $dbuser = 'user'; $dbpass = 'pass'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'jewelry'; mysql_select_db($dbname); $all_records = "SELECT * FROM gallery WHERE id = $_GET[id]"; $all_records_res = mysql_query($all_records); $image = mysql_result($all_records_res, 0, 'image'); $id = mysql_result($all_records_res, 0, 'id'); while($nt=mysql_fetch_array($all_records_res)){ echo "<img src=http://www.webdesignsbyliz.com/wdbl_wordpress/wp-content/themes/twentyten_2/upload/".$nt['image']." width=133 height=86></a>"; } ?> What an I doing wrong this time?? :-( Ok, I got someone to help me fix this but he had no idea what the error was... I have 2 tables, one called points and the other called members. In members i have got: id name In points i have got: id memberid promo I have the following code: Code: [Select] <?php $con = mysql_connect("localhost","slay2day_User","slay2day"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("slay2day_database",$con); $sqlquery="SELECT Sum(points.promo) AS score, members.name, members.id = points.memberid Order By members.name ASC"; $result=mysql_query($sqlquery,$con); while ($row = mysql_fetch_array($result)) { //get data $id = $row['id']; $name = $row['name']; $score = $row['score']; echo "<b>Name:</b> $name<br />"; echo "<b>Points: </b> $score<br />" ; echo "<b>Rank: </b>"; if ($name == 'Kcroto1'): echo 'The Awesome Leader'; else: if ($points >= '50'): echo 'General'; elseif ($points >= '20'): echo 'Captain!'; elseif ($points >= '10'): echo 'lieutenant'; elseif ($points >= '5'): echo 'Sergeant'; elseif ($points >= '2'): echo 'Corporal'; else: echo 'Recruit'; endif; endif; echo '<br /><br />'; } ?> I am getting the following error when i do the query in mysql: Code: [Select] #1109 - Unknown table 'points' in field list And when i open the webpage i get the following error: Code: [Select] Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/slay2day/public_html/points/members.php on line 18 Please Help me? For the last few days I have been trying to work out why my code does not update the MySQL database table. Having tried several variation I have the below but cannot see anything wrong. The rest of the program produces the correct results (displaying what is currently on the table) showing it is connecting to the correct table but altering the table is not working. Any help greatly appreciated. The few lines in question a Code: [Select] // Update the profile data in the database if (!$error) { if (!empty($name)&& !empty($phone) && !empty($address1) && !empty($address2)) { // Only set the picture column if there is a new picture if (!empty($new_picture)) { //if (!empty($postcode)){ $query = "UPDATE antique SET name = '$name', phone = '$phone', address1 = '$address1', address2 = '$address2', postcode = '$postcode', " . " email = '$email', webadd = '$webadd', picture = '$new_picture', username = '" . $_SESSION['username'] . "' WHERE name = '" . $row['name'] ."'"; }} else { $query = "UPDATE antique SET name = '$name', phone = '$phone', address1 = '$address1', address2 = '$address2', postcode = '$postcode', " . " email = '$email', webadd = '$webadd', username = '" . $_SESSION['username'] . "' WHERE name = '" . $row['name'] ."'"; } mysqli_query($dbc, $query) or die("<br>Query $query<br>Failed with error: " . mysqli_error($dbc) . '<br>On line: ' . __LINE__); The whole program is below Code: [Select] <?php error_reporting(E_ALL); session_start(); ?> <?php require_once('appvars.php'); require_once('connectvars1.php'); // Connect to the database $dbc = mysqli_connect(DB_Host, DB_User, DB_Password, DB_Name); if (!isset($_GET['user_id'])) { $query = "SELECT * FROM antique WHERE user_id = '" . $_SESSION['user_id'] . "'"; } else { $query = "SELECT * FROM antique WHERE user_id = '" . $_GET['user_id'] . "'"; } $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { // The user row was found so display the user data $row = mysqli_fetch_array($data); echo '<table>'; if (!empty($row['name'])) { echo '<tr><td class="label">Name:</td><td>' . $row['name'] . '</td></tr>'; } if (!empty($row['phone'])) { echo '<tr><td class="label">Phone:</td><td>' . $row['phone'] . ' </td></tr>'; } if (!empty($row['address1'])) { echo '<tr><td class="label">Address1:</td><td>' . $row['address1'] . ' </td></tr>'; } if (!empty($row['address2'])) { echo '<tr><td class="label">Address2:</td><td>' . $row['address2'] . ' </td></tr>'; } if (!empty($row['postcode'])) { echo '<tr><td class="label">Postcode:</td><td>' . $row['postcode'] . ' </td></tr>'; } if (!empty($row['webadd'])) { echo '<tr><td class="label">Web address:</td><td>' . $row['webadd'] . ' </td></tr>'; } if (!empty($row['email'])) { echo '<tr><td class="label">Email:</td><td>' . $row['email'] . ' </td></tr>'; } if (!empty($row['username'])) { echo '<tr><td class="label">Username:</td><td>' . $row['username'] . ' </td></tr>'; } if (!empty($row['user_id'])) { echo '<tr><td class="label">User ID:</td><td>' . $row['user_id'] . ' </td></tr>'; } echo '</table>'; //echo '<class = "label">USER ID: ' . $_SESSION['user_id'] . ''; if (!isset($_GET['postcode']) || ($_SESSION['postcode'] == $_GET['postcode'])) { echo '<p>Would you like to <a href="index5.php">Go to Homepage</a>?</p>'; } } // End of check for a single row of user results else { echo '<p class="error">There was a bit of a problem accessing your profile.</p>'; } ?> <hr> <?php require_once('appvars.php'); require_once('connectvars1.php'); // Make sure the user is logged in before going any further. if (!isset($_SESSION['user_id'])) { echo '<p class="login">Please <a href="login1.php">log in</a> to access this page.</p>'; exit(); } // Connect to the database $dbc = mysqli_connect(DB_Host, DB_User, DB_Password, DB_Name); if (isset($_POST['submit'])) { // Grab the profile data from the POST $name = mysqli_real_escape_string($dbc, trim($_POST['name'])); $phone = mysqli_real_escape_string($dbc, trim($_POST['phone'])); $address1 = mysqli_real_escape_string($dbc, trim($_POST['address1'])); $address2 = mysqli_real_escape_string($dbc, trim($_POST['address2'])); $postcode = mysqli_real_escape_string($dbc, trim($_POST['postcode'])); $webadd = mysqli_real_escape_string($dbc, trim($_POST['webadd'])); $email = mysqli_real_escape_string($dbc, trim($_POST['email'])); $old_picture = mysqli_real_escape_string($dbc, trim($_POST['old_picture'])); $new_picture = mysqli_real_escape_string($dbc, trim($_FILES['new_picture']['name'])); $new_picture_type = $_FILES['new_picture']['type']; $new_picture_size = $_FILES['new_picture']['size']; $username = mysqli_real_escape_string($dbc, trim($_POST['username'])); $user_id = mysqli_real_escape_string($dbc, trim($_POST['user_id'])); if (!empty($_FILES['new_picture']['tmp_name'])) {list($new_picture_width, $new_picture_height) = getimagesize($_FILES['new_picture']['tmp_name']); } //list($new_picture_width, $new_picture_height) = getimagesize($_FILES['new_picture']['tmp_name']); $error = false; // Validate and move the uploaded picture file, if necessary if (!empty($new_picture)) { if ((($new_picture_type == 'image/gif') || ($new_picture_type == 'image/jpeg') || ($new_picture_type == 'image/pjpeg') || ($new_picture_type == 'image/png')) && ($new_picture_size > 0) && ($new_picture_size <= MM_MAXFILESIZE) && ($new_picture_width <= MM_MAXIMGWIDTH) && ($new_picture_height <= MM_MAXIMGHEIGHT)) { if ($_FILES['new_picture']['error'] == 0) { // Move the file to the target upload folder $target = MM_UPLOADPATH . basename($new_picture); if (move_uploaded_file($_FILES['new_picture']['tmp_name'], $target)) { // The new picture file move was successful, now make sure any old picture is deleted if (!empty($old_picture) && ($old_picture != $new_picture)) { } } else { // The new picture file move failed, so delete the temporary file and set the error flag @unlink($_FILES['new_picture']['tmp_name']); $error = true; echo '<p class="error">Sorry, there was a problem uploading your picture.</p>'; } } } else { // The new picture file is not valid, so delete the temporary file and set the error flag @unlink($_FILES['new_picture']['tmp_name']); $error = true; echo '<p class="error">Your picture must be a GIF, JPEG, or PNG image file no greater than ' . (MM_MAXFILESIZE / 1024) . ' KB and ' . MM_MAXIMGWIDTH . 'x' . MM_MAXIMGHEIGHT . ' pixels in size.</p>'; } } $error = false; // Update the profile data in the database if (!$error) { if (!empty($name)&& !empty($phone) && !empty($address1) && !empty($address2)) { // Only set the picture column if there is a new picture if (!empty($new_picture)) { //if (!empty($postcode)){ $query = "UPDATE antique SET name = '$name', phone = '$phone', address1 = '$address1', address2 = '$address2', postcode = '$postcode', " . " email = '$email', webadd = '$webadd', picture = '$new_picture', username = '" . $_SESSION['username'] . "' WHERE name = '" . $row['name'] ."'"; }} else { $query = "UPDATE antique SET name = '$name', phone = '$phone', address1 = '$address1', address2 = '$address2', postcode = '$postcode', " . " email = '$email', webadd = '$webadd', username = '" . $_SESSION['username'] . "' WHERE name = '" . $row['name'] ."'"; } mysqli_query($dbc, $query) or die("<br>Query $query<br>Failed with error: " . mysqli_error($dbc) . '<br>On line: ' . __LINE__); // Confirm success with the user echo '<p>Your profile has been successfully updated. Would you like to <a href="viewprofile4.php">view your profile</a>?</p>'; mysqli_close($dbc); exit(); } else { echo '<p class="error">You must enter all of the profile data (the picture is optional).</p>'; } } // End of check for form submission else { // Grab the profile data from the database $query="SELECT * FROM antique WHERE user_id= '" . $row['user_id'] . "'"; $data = mysqli_query($dbc, $query); $row = mysqli_fetch_array($data); if ($row != NULL) { $name = $row['name']; $phone = $row['phone']; $address1 = $row['address1']; $address2 = $row['address2']; $postcode = $row['postcode']; $email = $row['email']; $webadd = $row['webadd']; $old_picture = $row['picture']; $username = $_SESSION['username']; $user_id = $row['user_id']; } else { echo '<p class="error">There was a problem accessing your profile.</p>'; } } mysqli_close($dbc); ?> <form enctype="multipart/form-data" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="hidden" name="MAX_FILE_SIZE" value="<?php echo MM_MAXFILESIZE; ?>" /> <fieldset> <legend>Personal Information</legend> <label for="name">Name:</label> <input type="text" id="name" name="name" value="<?php if (!empty($name)) echo $name; ?>" /><br /> <label for="phone">Phone:</label> <input type="text" id="phone" name="phone" value="<?php if (!empty($phone)) echo $phone; ?>" /><br /> <label for="address1">Address1:</label> <input type="text" id="address1" name="address1" value="<?php if (!empty($address1)) echo $address1; ?>" /><br /> <label for="address2">Address2:</label> <input type="text" id="address2" name="address2" value="<?php if (!empty($address2)) echo $address2; ?>" /><br /> <label for="postcode">Postcode:</label> <input type="text" id="postcode" name="postcode" value="<?php if (!empty($postcode)) echo $postcode; ?>" /><br /> <label for="email">Email:</label> <input type="text" id="email" name="email" value="<?php if (!empty($email)) { echo $email; } else { echo 'No email entered';} ?>" /><br /> <label for="webadd">Web address:</label> <input type="text" id="webadd" name="webadd" value="<?php if (!empty($webadd)) { echo $webadd; } else { echo 'No web address entered';} ?>" /><br /> <input type="hidden" name="old_picture" value="<?php if (!empty($old_picture)) echo $old_picture; ?>" /> <label for="new_picture">Pictu </label> <input type="file" id="new_picture" name="new_picture" /> <?php if (!empty($old_picture)) { echo '<img class="profile" src="' . MM_UPLOADPATH . $old_picture . '" alt="Profile Picture" style: height=100px;" />'; } ?> <br /> <label for="username">Username:</label> <input type="text" id="username" name="username" value="<?php if (!empty($username)) echo $username; ?>" /><br /> <label for="user_id">User ID:</label> <input type="text" id="user_id" name="user_id" value="<?php echo '' . $row['user_id'] . '' ; ?>" /><br /> </fieldset> <input type="submit" value="Save Profile" name="submit" /> </form> <?php echo('<p class="login">You are logged in as ' . $_SESSION['username'] . '. <a href="logout3.php">Log out</a>.</p>'); echo '<class = "label">USER ID: ' . $row['user_id'] . ''; ?> <p><a href="index.php">Return to homepage</a></p> <?php require_once('footer.php'); ?> </body> </html> Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero |
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