PHP - Foreach And Dropdownlist

Hi,
I need to call to this text to add a all with value "blank/empty" or "0" to the dropdownlist code below..
it should be inserted int the first position in the dropdownlist and have a value blank and call to this text from the language files:            
            $searchAll = gettext('_LANGUAGE_SEARCH_ALL',_LANGUAGE_SEARCH_ALL,false,false);
            example is:
            ratestitle=>0 gettext('_LANGUAGE_SEARCH_ALL',_LANGUAGE_SEARCH_ALL,false,false);
            the words it calls is "ALL" when the user selects or leaves the "ALL" in the list the value
             remains empty this allows the search to search everything..
basically im stuck how to get it in the dropdown list as the first default position:
can anyone help?

here is my code://this is a search function which calls to the field rate_title the text from the select box is matched to the database table and the search pages shows the search option is the search is successful.. I have 5 of these types of searches but cant give a broader search option to my users as the values must be selected to search--- i need the option "ALL" to have a "EMPTY" value or no value....
         

if (in_array("ratestitle",$searchOptions)&& $showSearchOptions )
            {
            if (empty($sch->filter['ratestitle']) )
               $selectOption=$output['LANGUAGE_SEARCH_RATESTITLE'];
            else
               $selectOption=$sch->filter['ratestitle'];
            $showButton=true;            
         $query = "SELECT DISTINCT rate_title FROM #__rates_table ORDER BY rate_title ASC";
         $dropDownList ="<select class=\"inputbox\" name=\"ratestitle\">";
         $ratesitles =doSelectSql($query);         
         foreach ($ratesitles as $ratetitle)
            {
            $selected="";
            $rate_title=$ratetitle->rate_title;
            if ($ratetitle==".$sch->filter['ratestitle'].")
               $selected="selected";
            $dropDownList .= "<option ".$selected." value=\"".$rate_title."\">".$rate_title."</option>";
            }
         $dropDownList.="</select>";
         $output['RATESTITLE']=$dropDownList;
            }
               

I'm not sure if the title explains it very well, but here is an image of it. I am trying to figure out how to access the option selected (equal, not equal, etc.), along with its input box, for each column (the checkboxes on the right) selected. The purpose of this is to allow a non-programming administrator user to create a custom query to access information. I can find out which checkboxes are selected no problem, but finding the accompanying drop-down option and input box is difficult for me. How do I do this?

If you have a suggestion on how to change it, I'm very open. Thank you in advance!



Code: [Select]
if(!isset($_POST['submit']))
{
echo "
<form method='post'>
<table>
 <tr>
  <td valign='top'>SELECT</td>
  <td valign='top'>
   <table>";
 
// LIST ALL COLUMNS IN A TABLE
$result = mysql_query("SELECT * FROM table_name") or die(mysql_error());
$rowcount=mysql_num_rows($result);
$y=mysql_num_fields($result);
for ($x=0; $x<$y; $x++)
{ echo "
    <tr>
<td>
  <input type='checkbox' name='fields[]' value='".mysql_field_name($result, $x)."'>".mysql_field_name($result, $x)."
     </td>
</tr>"; }
 
   echo "
   </table>
  </td>
  <td valign='top'>FROM allocations</td>
  <td valign='top'>WHERE</td>
  <td>
   <table>";
   
// LIST ALL COLUMNS IN A TABLE
$result = mysql_query("SELECT * FROM table_name") or die(mysql_error());
$rowcount=mysql_num_rows($result);
$y=mysql_num_fields($result);
for ($x=0; $x<$y; $x++)
{ echo "
    <tr>
<td>
  <input type='checkbox' name='column[]' value='".mysql_field_name($result, $x)."'>".mysql_field_name($result, $x)."
</td>
<td>
  <select name='operator[]'>
          <option value='='>equals</option>
          <option value='<>'>does not equal</option>
          <option value='>'>greater than</option>
          <option value='<'>less than</option>
          <option value='>='>greater than or equal to</option>
          <option value='<='>less than or equal to</option>
          <option value='LIKE'>is like</option>
         </select>
</td>
     <td><input type='text' name='criteria[]'></td>
</tr>"; }

   echo "
   </table>
  </td>
  <td valign='top'><input type='submit' value='Process Query' name='submit' class='submit'></td>
 </tr>
</table>
</form>";
}
else
{
 echo "<b>Fields to edit:</b> ";
foreach ($_POST['fields'] as $fields) {
echo $fields,", ";
}

 echo "<br><br>";
 echo "<b>Columns to query:</b> ";
foreach ($_POST['column'] as $columns) {
echo $columns," HERE IS THE SPOT, ";
}
}

I am trying to develop a calendar. I have code to determine the number of days for each month. I want to cycle through each day and spit out code for each day. Something like the following:

Code: [Select]
<?php
$month = "December";
$days = 31;

foreach($days){
echo "<div id='day_block'> ".$days." </div>";
}

?>
i think i need to use a counter but don't know how, any help would be awesome!

I'm trying to figure out why its saying Warning: Invalid argument supplied for foreach() in /home/content/y/a/n/yankeefaninkc/html/defiant/efedmanager/forms/booking.php on line 17. I thought I did the foreach loop right so far.


$eventid = $_GET['id'];

$query = "SELECT 
CONCAT_WS(' ', eventnames.eventname, events.label) AS event, 
DATE_FORMAT(events.bookingdate, '%M %d, %Y') AS bookingdate,
    events.nummatches AS nummatches
FROM 
events, eventnames
WHERE  events.event_id = eventnames.id AND events.id = '" . $eventid . "'";
    $result = mysqli_query ( $dbc, $query ); // Run The Query

foreach ($nummatches as $matchnum) {
    echo "Match # $matchnum";
    echo "<select class=dropdown name=matchtype id=matchtype title=Match Type>";
    echo "<option value=0>- Select -</option>";
    $query = 'SELECT id, matchtypename FROM matchtypes';
    $result = mysqli_query ( $dbc, $query ); // Run The Query
    while ( $row = mysqli_fetch_array ( $result, MYSQL_ASSOC ) ) { 
        print "<option value=\"".$row['id']."\">".$row['matchtypename']."</option>\r";
    }
}

Hi guys,

Having a bit of trouble getting this to work. I should say before I start that im a rookie at PHP.

Basically this is the code I have

{counter start=0 print=false name=competcount}
{foreach item=compet from=$person.competition}

<img src="./bargraph/bar.php?value={$person.lineup[$compet.id].titular}&max={$club.matchsplayed[$compet.id].nummatchs}&info" />

The problem lies with the $club array not being defined Code: [Select]
$club.matchsplayed[$competition.id].nummatchs
How do I set up multiple arrays with foreach? Am I even in the right ball park with this?

why does wordpress is using foreach rather than while in listing records?

common
Code: [Select]
while ($products = mysql_fetch_object($rs) {
...
}

but wordpress is using foreach
Code: [Select]
foreach ($posts as $post) {
...
}

which is better? because i'm trying to create my own code for database connection.

today i programmed my own weight calculator.
one thing i am having a problem is with trying to make it so if a weight is over a certain number, then the shipping price will increase by X.
shipping prices are charged in 20000 gram blocks, so if I have something that is 22000 grams then that will be two blocks. what i need to do is something like (this is a big guess)

Quote

$row3 = 50;
$weighttotal = 22000;
if ($weighttotal > 20000) {
   foreach (20000) {
      $row3 += $row3;}
      }
   }
}


can it be done on php??

Hi!

When I echo $m below, it will show all selected options fine.
Instead, I want it to show many I selected.

So if I selected 3 in dropdown, I want it to say I selected 3 instead of showing their values.

      $allmaps=$_POST['maps'];
       foreach ($allmaps as $m) { echo 'm = '.$m.''; }

<select name="maps[]" multiple>'.$maps.'</select>

Hi i am trying to pass values from a cart to a database using foreach.

This is my code:
Code: [Select]
$columns = array('order_id', 'order_item_id', 'order_product_name', 'order_product_dimensions', 'order_product_options', 'order_product_quantity', 'order_product_price', 'order_product_subtotal', 'order_product_vat', 'order_product_delivery','order_product_total','order_product_sku','order_product_image_name','order_product_image_type','order_product_image_path','order_product_image_size','order_product_artwork_link','order_product_artwork_name','order_product_artwork_type','order_product_artwork_path','order_product_artwork_size','order_firstname','order_lastname','order_companyname','order_email','order_tel','order_billing_address','order_billing_address2','order_billing_town','order_billing_county','order_billing_postcode','order_shipping_address','order_shipping_address2','order_shipping_town','order_shipping_county','order_shipping_postcode','order_status','order_username');
$data = array_fill_keys($columns, 'NULL');

foreach($data as $key => $value) {

$data[$key] = empty($_POST[$key]) ? 'NULL' : "'".mysql_escape_string($_POST[$key])."'";
$query = "INSERT INTO orders (id, order_created_at, ".implode(", ",$columns).")
VALUES (null, NOW(), ".implode(",",$data).')';

}

Problem is posting 2 or more products into the database.

How do i split the values so it enters each product into the database?

I appear to be having a simple simon day!

my foreach is only displaying the last result in the table as opposed to each row
$num_rows = mysql_num_rows($query);
echo "There are $num_rows records.<br>";

while($row = mysql_fetch_row($query))

foreach ($row as $field)

{ 

echo '<div class="results">';

echo  $field;

echo '<br></div>'; 

}

And the source


Code: [Select]
<link href="../styles/clientbox.css" rel="stylesheet" type="text/css">

<body><br>



<h3>My Services</h3>

<div class="text">

You currently have the following services with us:

</div>

There are 2 records.<br><div class="results">test1<br></div>


</body>

</html>
My table has 2 rows which the 1st one has a package of test and the second a package of test1


Can anyone help?

Thanks

i have a table that echos 10 entries what i want to do is once it echos 5 records it starts a new table. I dont know how to go about this. Could you guys guide me the right way.

Noob question. I've learned so much in the last couple of weeks that I've actually found two ways of doing the same thing!  I was wondering which was the better method, if there is any difference. They are being used to print somewhere between 10 and 200 lines of text.

Either:
$categories_count= (count($categories[1])) -1;
for ($u=0; $u < $categories_count; $u++) {echo "<li>".$categories[1][$u]."</li>";}
Or:
foreach ($categories[1] as $line => $cat)  {echo "<li>".$cat."</li>";};

Hi All,

I essentially am trying to figure out how to print out all of the zip codes that are associated with a search that I am doing, but not list the same zip code more than once.  My current foreach statement is as follows and prints out the zip code for each property that is associated with the search:

<ul>

<?php
foreach($properties as $property) {
?>

      <li><?=$property->$zipcode?></li>

<?php
   }
?>

</ul>

How would I modify this to print out 1 occurrence of each zip code that is in the search, even if, for example 20 properties have the same zip code?

Thanks in advance!

P.S. - Tried using an array to work with it but pretty sure my logic was incorrect when putting it together and couldn't get past the errors.  Anyways, thanks in advance for the help!

Hi can any one help please im still very new but hard trying

The problem is that i only get 1 result back from the database i need it to loop any ideas please
Code: [Select]

$query = mysql_query("SELECT * FROM categorys, sub_categorys WHERE categorys.cat_id = sub_categorys.cat_id");
       
echo "<ul>";
$row[] = mysql_fetch_array($query);
  foreach($row as $category){
                  echo "<li>";
              echo $category['category'];

      foreach($row as $sub_category){
          if($category['cat_id'] == $sub_category["cat_id"]){
      echo "<ul><li>".$sub_category["sub_category"]."</li></ul>";
          }
       }
            echo "</li>";
                }
              echo "</ul>";

    public function update($data, $table, $where) {
        foreach ($data as $column => $value) {
            $sql = "UPDATE $table SET $column = $value WHERE $where";
         print "table: ".$table." column: ".$column." whe ".$where;
            mysql_query($sql) or die(mysql_error());
        }
        return true;
    }


$data:
$data = array(
    "username" => "Jack",
    "email" => "jack.gmail@gmail.com"
);


$db->update($data, "users", 'id=1');

Working on this code that updates a column from a class. Everything is fine except for one issue.

As of right now $column is set to "Jack" which outputs an error, instead of what it should be as "username". I'm sure it's something really simple, so any assistance is appreciated. Any ideas? Problem area is listed in red.